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  • random quote generator with php, ajax and mysql

    - by fusion
    i've tried using this code and this to make a random quote generator, but it doesn't display anything. my questions are: what is wrong with my code? in the above tut, the quote is generated on a button click, i'd like a random quote to be displayed every 30 mins automatically. how do i do this? //////////////////////// quote.html: <!DOCTYPE html> <script src="ajax.js" type="text/javascript"></script> <body> <!–create the div for the quotes land–> <div id="quote"><strong>this</strong></div> <div><a style="cursor:pointer" onclick="run_query();">Next quote …</a></div> </body> </html> ///////////////////// quote.php: <?php include 'config.php'; // 'text' is the name of your table that contains // the information you want to pull from $rowcount = mysql_query("select count(*) as rows from quotes"); // Gets the total number of items pulled from database. while ($row = mysql_fetch_assoc($rowcount)) { $max = $row["rows"]; } // Selects an item's index at random $rand = rand(1,$max)-1; $result = mysql_query("select * from quotes limit $rand, 1"); $row = mysql_fetch_array($result); $randomOutput = $row['storedText']; echo '<p>' . $randomOutput . '</p>'; //////////// ajax.js: var xmlHttp function run_query() { xmlHttp=GetXmlHttpObject(); if (xmlHttp==null) { alert ("This browser does not support HTTP Request"); return; } // end if var url="quote.php"; xmlHttp.onreadystatechange=stateChanged; xmlHttp.open("GET",url,true); xmlHttp.send(null); } //end function function stateChanged(){ if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete"){ document.getElementById("quote").innerHTML=xmlHttp.responseText; } //end if } //end function function GetXmlHttpObject() { var xmlHttp=null; try { // For these browsers: Firefox, Opera 8.0+, Safari xmlHttp=new XMLHttpRequest(); }catch (e){ //For Internet Explorer try{ xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); } } return xmlHttp; } //end function

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  • Getting the responseText from XMLHttpRequest-Object

    - by Sammy46
    I wrote a cgi-script with c++ to return the query-string back to the requesting ajax object. I also write the query-string in a file in order to see if the cgi script works correctly. But when I ask in the html document for the response Text to be shown in a messagebox i get a blank message. here is my code: js: <script type = "text/javascript"> var XMLHttp; if(navigator.appName == "Microsoft Internet Explorer") { XMLHttp = new ActiveXObject("Microsoft.XMLHTTP"); } else { XMLHttp = new XMLHttpRequest(); } function getresponse () { XMLHttp.open ("GET", "http://localhost/cgi-bin/AJAXTest?" + "fname=" + document.getElementById('fname').value + "&sname=" + document.getElementById('sname').value,true); XMLHttp.send(null); } XMLHttp.onreadystatechange=function(){ if(XMLHttp.readyState == 4) { document.getElementById('response_area').innerHTML += XMLHttp.readyState; var x= XMLHttp.responseText alert(x) } } </script> First Names(s)<input onkeydown = "javascript: getresponse ()" id="fname" name="name"> <br> Surname<input onkeydown = "javascript: getresponse();" id="sname"> <div id = "response_area"> </div> C++: int main() { QFile log("log.txt"); if(!log.open(QIODevice::WriteOnly | QIODevice::Text)) { return 1; } QTextStream outLog(&log); QString QUERY_STRING= getenv("QUERY_STRING"); //if(QUERY_STRING!=NULL) //{ cout<<"Content-type: text/plain\n\n" <<"The Query String is: " << QUERY_STRING.toStdString()<< "\n"; outLog<<"Content-type: text/plain\n\n" <<"The Query String is: " <<QUERY_STRING<<endl; //} return 0; } I'm happy about every advice what to do! EDIT: the output to my logfile works just fine: Content-type: text/plain The Query String is: fname=hello&sname=world I just noticed that if i open it with IE8 i get the query-string. But only on the first "keydown" after that IE does nothing.

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  • A two player game over the intranet..

    - by Santwana
    Hi everybody.. I am a student of 3rd year engineering and only a novice in my programming skills. I need some help with my project.. I wish to develop a two player game to be played over the network (Intranet). I want to develop a simple website with a few html pages for this.My ideas for the project run as follows: 1.People can log in from different systems and check who ever is online on the network currently. the page also shows who is playing with whom. 2.If a person is interested in playing with a player who is currently online, he sends a request of which the other player is somehow notified( using a message or an alert on his profile page..) 3.If the player accepts the request, a game is started. This is exactly where I am clueless.. How can I make them play the game? I need to develop a turn based game with two players, eg chessboard.. how can I do this? The game has to be played live.. and it is time tracked. i need your help with coding the above.. the other features i wish to include are: 4.The game could not be abruptly terminated by any one if the users.The request to terminate the game should be sent to the other player first and only if he accepts can the game be terminated. Whoever wins the game would get a plus 10 on their credit and if he terminated he gets a minus 10. The credits remains constant even if he loses but the success percentage is reduced. 6.The player with highest winning percentage is projected as the player of the week on the home page and he can post a challenge to all others.. I only have an intermediate knowledge of core java and know the basics of Swing and Awt. I am not at all familiar with networking in java right now. I have 5 to 6 weeks of time for developing the project but I hope to learn the things before I start my project. i would prefer to use a lan to illustrate the project and I know only java,jsp,oracle,html and bit of xml to develop my proj. Also I wish to know if I can code this within 6 weeks, would it be too difficult or complicated? Please spare some time to tell me. Please.. please.. I need your suggestions and help.. thank you so much..

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  • jQuery - Form input return confirm to delete

    - by bruno
    hello guys. I struggled a lot before posting here :) now, I want to replace my default javascript confirmation for deleting a file. I saw a lot of examples here, but no example with form input. Now I have his form: <form action="delete.php" method="post"> <input type="hidden" name="id" value="<{$pid}>" /> <input type="hidden" name="picture" value="<{$lang_del_pic}>" /> <input type="image" src="<{xoImgUrl}>img/del-icon.gif" width="16" height="16" align="bottom" border="0" alt="Delete media" name="pictured" value="<{$lang_del_pic}>" onclick="javascript: return confirm('<{$lang_confirm_del}>');" /> </form> Now, I did everything, I have this div: <div id="dialog-confirm" title="Empty the recycle bin?"> <p><span class="ui-icon ui-icon-alert" style="float:left; margin:0 7px 20px 0;"></span>These items will be permanently deleted and cannot be recovered. Are you sure?</p> </div> this javascript: <script type="text/javascript"> $(document).ready(function() { $("#dialog").dialog({ autoOpen: false, modal: true }); }); $(".confirmLink").click(function(e) { e.preventDefault(); var targetUrl = $(this).attr("href"); $("#dialog").dialog({ buttons : { "Confirm" : function() { window.location.href = targetUrl; }, "Cancel" : function() { $(this).dialog("close"); } } }); $("#dialog").dialog("open"); }); </script> and this new form: <form name="dialog-confirm" id="dialog-confirm" method="post"> <input type="hidden" name="id" value="<{$pid}>" /> <input type="hidden" name="picture" value="<{$lang_del_pic}>" /> <input type="image" src="<{xoImgUrl}>img/del-icon.gif" width="16" height="16" align="bottom" border="0" alt="Delete media" name="pictured" value="" id="opener" /> </form> On press, I call successfuly the jQuery modal diolog, and everything works, but somehow, when I press 'delete all' the script tells me - "the script is called without the necessary parameters" Now I guess I am failig to send the pic ID to be deleted with the jQuery, .. but do not know how to fix it. Any ideas ?

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  • What do I need to distribute (keys, certs) for Python w/ SSL-socket connection?

    - by fandingo
    I'm trying to write a generic server-client application that will be able to exchange data amongst servers. I've read over quite a few OpenSSL documents, and I have successfully setup my own CA and created a cert (and private key) for testing purposes. I'm stuck with Python 2.3, so I can't use the standard "ssl" library. Instead, I'm stuck with PyOpenSSL, which doesn't seem bad, but there aren't many documents out there about it. My question isn't really about getting it working. I'm more confused about the certificates and where they need to go. Here are my two programs that do work: Server: #!/bin/env python from OpenSSL import SSL import socket import pickle def verify_cb(conn, cert, errnum, depth, ok): print('Got cert: %s' % cert.get_subject()) return ok ctx = SSL.Context(SSL.TLSv1_METHOD) ctx.set_verify(SSL.VERIFY_PEER|SSL.VERIFY_FAIL_IF_NO_PEER_CERT, verify_cb) # ?????? ctx.use_privatekey_file('./Dmgr-key.pem') ctx.use_certificate_file('Dmgr-cert.pem') # ?????? ctx.load_verify_locations('./CAcert.pem') server = SSL.Connection(ctx, socket.socket(socket.AF_INET, socket.SOCK_STREAM)) server.bind(('', 50000)) server.listen(3) a, b = server.accept() c = a.recv(1024) print(c) Client: from OpenSSL import SSL import socket import pickle def verify_cb(conn, cert, errnum, depth, ok): print('Got cert: %s' % cert.get_subject()) return ok ctx = SSL.Context(SSL.TLSv1_METHOD) ctx.set_verify(SSL.VERIFY_PEER, verify_cb) # ?????????? ctx.use_privatekey_file('/home/justin/code/work/CA/private/Dmgr-key.pem') ctx.use_certificate_file('/home/justin/code/work/CA/Dmgr-cert.pem') # ????????? ctx.load_verify_locations('/home/justin/code/work/CA/CAcert.pem') sock = SSL.Connection(ctx, socket.socket(socket.AF_INET, socket.SOCK_STREAM)) sock.connect(('10.0.0.3', 50000)) a = Tester(2, 2) b = pickle.dumps(a) sock.send("Hello, world") sock.flush() sock.send(b) sock.shutdown() sock.close() I found this information from ftp://ftp.pbone.net/mirror/ftp.pld-linux.org/dists/2.0/PLD/i586/PLD/RPMS/python-pyOpenSSL-examples-0.6-2.i586.rpm which contains some example scripts. As you might gather, I don't fully understand the sections between the " # ????????." I don't get why the certificate and private key are needed on both the client and server. I'm not sure where each should go, but shouldn't I only need to distribute one part of the key (probably the public part)? It undermines the purpose of having asymmetric keys if you still need both on each server, right? I tried alternating removing either the pkey or cert on either box, and I get the following error no matter which I remove: OpenSSL.SSL.Error: [('SSL routines', 'SSL3_READ_BYTES', 'sslv3 alert handshake failure'), ('SSL routines', 'SSL3_WRITE_BYTES', 'ssl handshake failure')] Could someone explain if this is the expected behavior for SSL. Do I really need to distribute the private key and public cert to all my clients? I'm trying to avoid any huge security problems, and leaking private keys would tend to be a big one... Thanks for the help!

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  • Can I use this Ajax script to communicate and exchange data between client and server?

    - by lala
    This block of code is for client.html (it is located in this www.client.com/client.html) - client side. The I have the code below that goes something like this: ajaxRequest.open("GET", "http://www.server.com/ajax.php", true); This is how I call the file ajax.php located in the server. Unfortunately I have no luck at all. It cannot connect to the server I'm calling. BTW, the ips /test site I've been using are all no restrictions, and is accessible to all. However, I tried to simulate by putting both client.html and ajax.php in same site and it works well. So my question is does this script works only if you are in same site? or does it work also in client-server scenario? What else do I have to do in order to make this work? //client.html <script language="javascript" type="text/javascript"> <!-- //Browser Support Code function ajaxFunction(){ var ajaxRequest; // The variable that makes Ajax possible! try{ // Opera 8.0+, Firefox, Safari ajaxRequest = new XMLHttpRequest(); } catch (e){ // Internet Explorer Browsers try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser broke!"); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState == 4){ document.myForm.time.value = ajaxRequest.responseText; } } ajaxRequest.open("GET", "http://www.server.com/ajax.php", true); ajaxRequest.send(null); } //--> </script> <form name='myForm'> Name: <input type='text' onChange="ajaxFunction();" name='username' /> <br /> Time: <input type='text' name='time' /> </form> </body> </html> // ajax.php <?php echo date("H:i:s"); ?>

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  • Changing the title of jQuery-UI dialog-box with in another dialog-box's function...

    - by Brian Ojeda
    Why doesn't doesn't the second jQuery-UI dialog box title change when popped. The first dialog box I change the title of the box with using the following .attr("title", "Confirm") -- it change the title of the first box to 'Confirm', like it should have. Now when the second box pops up it should change the title to 'Message' since did the same thing for the second box -- .attr("title", "Message"). Right? But it doesnt. It keep the title from before. However, the message change like it should have. I have tested in IE8, Chrome, and FF3.6. <div id="dialog-confirm" title=""></div> <-- This is the html before jQuery functions. Javascript / jQuery $('#userDelete').click(function() { $(function() { var dialogIcon = "<span class=\"ui-icon ui-icon-alert\"></span>"; var dialogMessage = dialogIcon + "Are you sure you want to delete?"; $("#dialog-confirm").attr("title", "Confirm").html(dialogMessage).dialog({ resizable: false, height: 125, width: 300, modal: true, buttons: { 'Delete': function() { $(this).dialog('close'); $.post('user_ajax.php', {action: 'delete', aId: $('[name=aId]').val() }, function(data) { if(data.success){ var dialogIcon = "<span class=\"ui-icon ui-icon-info\"></span>"; var dialogMessage = dialogIcon + data.message; $('#dialog-confirm').attr("title", "Message"); $('#dialog-confirm').html(dialogMessage); $('#dialog-confirm').dialog({ resizable: false, height: 125, width: 300, modal: true, buttons: { 'Okay': function() { $(this).dialog('close'); var url = $_httpaddress + "admin/index.php" $(location).attr('href',url); } // End of Okay Button Function } //--- End of Dialog Button Script });//--- End of Dialog Function } else { $_messageConsole.slideDown(); $_messageConsole.html(data.message); } }, 'json'); }, //--- End of Delete Button Function 'Cancel': function() { $(this).dialog('close'); } //--- End of Cancel Button Function } //--- End of Dialog Button Script }); //--- End of Dialog Script }); //--- End of Dialog Function return false; }); Thank you for you assistant, if you choose to help.

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  • jQuery - Save to SQL via PHP

    - by Kenny Bones
    This is probably easy for you guys, but I can't understand it. I want to save the filename of an image to it's own row in the SQL base. Basically, I log on to the site where I have my own userID. And each user has its own column for background images. And the user can choose his own image if he wants to. So basically, when the user clicks on the image he wants, a jquery click event occurs and an ajax call is made to a php file which is supposed to take care of the actual update. The row for each user always exist so there's only an update of the data that's necessary. First, I collect the filename of the css property 'background-image' and split it so I get only the filename. I then store that filename in a variable I call 'filename' which is then passed on to this jQuery snippet: $.ajax({ url: 'save_to_db.php', data: filename, dataType:'Text', type: 'POST', success: function(data) { // Just for testing purposes. alert('Background changed to: ' + data); } }); And this is the php: <?php require("dbconnect.php") ?> <?php $uploadstring = ($_POST['filename']); mysql_query("UPDATE brukere SET brukerBakgrunn = $uploadstring WHERE brukerID=" .$_SESSION['id'] .""; mysql_close(); ?> Basically, each user has their own ID and this is called 'brukerID' The table everything is in is called 'brukere' and the column I'm supposed to update is the one called 'brukerBakgrunn' When I just run the javascript snippet, I get this message box in return where it says: Background changed to: Parse error: syntax error, unexpected ';' in /var/www/clients/client2/web8/web/save_to_db.php on line 8 I actualle get this messagebox twice, not sure why. Line 8 in 'save_to_db.php' is this one: mysql_query("UPDATE brukere SET brukerBakgrunn = $uploadstring WHERE brukerID=" .$_SESSION['id'] .""; Not sure if you need to see db_connect.php as well. I can add that later if you need to see it. So what am I missing here?

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  • Fill 4 input with one textarea

    - by Patrice Poliquin
    I have a question for the community. My problem is that I have 4 input files with a maxlength of 60 caracters for a total of 240 caracters. Because the "backend" of the customer's system, it need to be 4 differents inputs max to be inserted and they say it is not user-friendly to fill 4 fields. My solution I want to make a textarea and when you fill it, il complete the 4 fields. [input text #1] max60 [input text #2] max60 [input text #3] max60 [input text #4] max60 [textarea max 240] What I am trying to do is to make by javascript/jQuery to fill up the four field while typing in. At the moment, here is my code. $(document).ready(function() { // My text area $("#inf_notes").bind('keydown', function () { var maxLength = 240; if ($(this).val().length <= 60) { // The first 60 caracters $('#inf_notes_1').val($(this).val()); } if ($(this).val().length > 60 && $(this).val().length <= 120) { // If more then 60, fill the second field $('#inf_notes_2').val($(this).val()); } // If 121 - 180 ... // If 181 - 240 ... if($(this).val().length == 240) { $(this).val($(this).val().substring(0, maxLength)); $('.alert_textarea').show(); // Simple alert else { $('.alert_textarea').hide(); } }); }); It actually works for the first one, but I would like to have some feedbacks to help me complete the script to fill the 3 nexts. Any guess to complete it? -- EDIT #1 I found a way that could maybe work! When the first input is completly filled, it will jump to the next field with a .focus() $(".inf_notes").bind('keydown', function () { var notes1 = $('#inf_notes_1').val(); var notes2 = $('#inf_notes_2').val(); var notes3 = $('#inf_notes_3').val(); if (notes1.length == 60) { $('#inf_notes_2').focus(); } if (notes2.length == 60) { $('#inf_notes_3').focus(); } if (notes3.length == 60) { $('#inf_notes_4').focus(); } });

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  • ASP.NET MVC 3 NOT showing appropriate view, action called using jquery

    - by TunAntun
    I have a small problem. My action is : public ViewResult SearchForRooms(int HotelDDL) { List<Room> roomsInHotel = bl.ReturnRoomsPerHotel(HotelDDL); return View(roomsInHotel); } Here is the jquery that is calling the action: <script type="text/javascript" language="javascript"> $(document).ready(function () { $("#HotelDDL").change(function () { var text = $("#HotelDDL option:selected").text(); var value = $("#HotelDDL option:selected").val(); alert("Selected text=" + text + " Selected value= " + value); $.post("/Home/SearchForRooms", { HotelDDL: $("#HotelDDL option:selected").val() }); }); }); </script> And finally, here is the View that should be called: @model IEnumerable<RoomReservation.Entities.Entities.Room> @{ ViewBag.Title = "Search"; } <h2>Result</h2> <table> <tr> <th> City </th> <th> Hotel </th> <th> Room label </th> <th> Number of beds </th> <th> Price per night </th> <th></th> </tr> @foreach (var item in Model) { <tr> <td> @Html.DisplayFor(modelitem=>item.Hotel.City.Name) </td> <td> @Html.DisplayFor(modelItem => item.Hotel.Name) </td> <td> @Html.DisplayFor(modelItem => item.Name) </td> <td> @Html.DisplayFor(modelItem => item.NumberOfBeds) </td> <td> @Html.DisplayFor(modelItem => item.PricePerNight) </td> </tr> } </table> Everthing is working ok (databse return all rooms correctly) except final view rendering. I have tried Phil's tool but it doesn't give me any suspicious hints: RouteDebug.RouteDebugger.RewriteRoutesForTesting(RouteTable.Routes); So, why is it not showing after jscript send it's post method to SearchForRooms()? Thank you P.S. If you need any other piece of code please just say so.

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  • Hoe to convert a JSON array of paths to images stored on a server into a javaScript array to display them? Using AJAX

    - by MichaelF
    I need for html file/ ajax code to take the JSON message and store the PATHS as a javaScript array. Then my buildImage function can display the first image in the array. I'm new to AJAX and believe my misunderstanding lies within the converting of the JSON to Javascript. I'm confused also about if my code creates a JSON array or object or either. I might need also to download a library to my app to understand JSON? Below is a PHP file loading the paths of the images. I believe json ecode is converting the PHP Array in a Json message. <?php include("mysqlconnect.php"); $select_query = "SELECT `ImagesPath` FROM `offerstbl` ORDER by `ImagesId` DESC"; $sql = mysql_query($select_query) or die(mysql_error()); $data = array(); while($row = mysql_fetch_array($sql,MYSQL_BOTH)){ $data[] = $row['ImagesPath']; } echo $images = json_encode($data); ?> Below is the script in is going to be loaded on an Cordova app. <!DOCTYPE html> <html> <head> <link rel="stylesheet" href="css/styles.css"> <link rel="stylesheet" href="css/cascading.css"> <script> function importJson(str) { // console.log(typeof xmlhttp.responseText); if (str=="") { document.getElementById("content").innerHTML=""; return; } if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else { // code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { //var images = JSON.parse(xmlhttp.responseText); document.getElementById("content").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","http://server/content.php"); xmlhttp.send(); } function buildImage(src) { var img = document.createElement('img') img.src = src alert("1"); document.getElementById('content').appendChild(img); } for (var i = 0; i < images.length; i++) { buildImage(images[i]); } </script> </head> <body onload= "importJson();"> <div class="contents" id="content" ></div> <img src="img/logo.png" height="10px" width="10px" onload= "buildImage();"> </body>

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  • I am having trouble using jquery to submit a form. It was working before

    - by noah
    When a user clicks a link it uses jquery ajax to submit a form to go to paypal. Not working for some reason. Really appreciate any help... LINK TO CLICK I put this in an href for onClick: javascript:go_paypal(); CODE TO EXECUTE ON CLICK function go_paypal() { data = 'req_paypal=1'; $.blockUI({ message: '<h1> Going to Paypal...</h1>',css:{background:'#000'} }); $.ajax({ type: "POST", url: "index.php", data: data, success: function(data) { $("#paypal_form").html(data); $("#payPalForm").submit(); } , error: function() {$.unblockUI(); alert('Unable to communicate to server.'); } }); return false; } CODE TO GO ON SUBMIT if(isset($_POST['req_paypal']) && $_POST['req_paypal'] == 1 ) { $sql = 'INSERT INTO `transactions` (id,type,ip,time,ammount,status) VALUES (NULL,1,\''.$_SERVER['REMOTE_ADDR'].'\',\''.time().'\',\''.$global['paypal_prod_amount'].'\',0) '; echo $sql; mysql_query($sql); $id = mysql_insert_id(); $html = ' <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post" id="payPalForm"> <input type="hidden" name="item_number" value="One Year of Imgur Pro"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="no_note" value="1"> <input type="hidden" name="business" value="'.$global['paypal_email'].'"> <input type="hidden" name="custom" value="'.base64_encode($id).'"> <input type="hidden" name="currency_code" value="USD"> <input type="hidden" name="return" value="'.$global['paypal_return'].'"> <input name="item_name" type="hidden" id="item_name" value="One Year of Imgur Pro" > <input name="amount" type="hidden" id="amount" value="'.$global['paypal_prod_amount'].'" > </form> '; echo $html;exit; }

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  • JQuery Ajax Updating MySQL Database, But Not Running Success Function

    - by myrmidon16
    I am currently using the JQuery ajax function to call an exterior PHP file, in which I select and add data in a database. Once this is done, I run a success function in JavaScript. What's weird is that the database is updating successfully when ajax is called, however the success function is not running. Here is my code: <!DOCTYPE html> <head> <script type="text/javascript" src="jquery-1.6.4.js"></script> </head> <body> <div onclick="addtask();" style="width:400px; height:200px; background:#000000;"></div> <script> function addtask() { var tid = (Math.floor(Math.random() * 3)) + 1; var tsk = (Math.floor(Math.random() * 10)) + 1; if(tsk !== 1) { $.ajax({ type: "POST", url: "taskcheck.php", dataType: "json", data: {taskid:tid}, success: function(task) {alert(task.name);} }); } } </script> </body> </html> And the PHP file: session_start(); $connect = mysql_connect('x', 'x', 'x') or die('Not Connecting'); mysql_select_db('x') or die ('No Database Selected'); $task = $_REQUEST['taskid']; $uid = $_SESSION['user_id']; $q = "SELECT task_id, taskname FROM tasks WHERE task_id=" .$task. " LIMIT 1"; $gettask = mysql_fetch_assoc(mysql_query($q)); $q = "INSERT INTO user_tasks (ut_id, user_id, task_id, taskstatus, taskactive) VALUES (null, " .$uid. ", '{$gettask['task_id']}', 0, 1)"; $puttask = mysql_fetch_assoc(mysql_query($q)); $json = array( "name" => $gettask['taskname'] ); $output = json_encode($json); echo $output; Let me know if you have any questions or comments, thanks.

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  • Jquery ajax using asp.net does not work on IE9 during the 2nd call of the function?

    - by randelramirez1
    I have gridview that is loaded from another aspx page after an ajax call, the problem is it works on chrome/firefox/safari but using ie9 the ajax call would work fine during the first call but when i try to call the function again it throws an 304 status on the network tab of ie9 dev tool and the gridview is not refreshed. Here is the jquery code: <%@ Page Language="C#" AutoEventWireup="true" CodeFile="LoadCoursesGridViewHere.aspx.cs" Inherits="CoursesGridView" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> <script src="Scripts/jquery-1.8.2.js" type="text/javascript"></script> </head> <body> <form id="form1" runat="server"> <div id="Gridview-container"> <asp:GridView ID="GridView1" runat="server"> </asp:GridView> </div> <asp:TextBox ID="TextBox1" runat="server" ViewStateMode="Disabled"></asp:TextBox> <%-- <asp:Button Text="text" ID="btn" OnClientClick=" __doPostBack('UpdatePanel1', '')" runat="server" />--%> <input type="button" id="btn" value="insert"/> </form> <script type="text/javascript"> $("#btn").click(function () { var a = $("#TextBox1").val(); $.ajax({ url: 'WebService.asmx/insert', data: "{ 'name': '" + a + "' }", contentType: "application/json; charset=utf-8", type: "POST", success: function () { // alert('insert was performed.'); $("#Gridview-container").empty(); $("#Gridview-container").load("GridViewCourses.aspx #GridView1"); } }); }); </script> </body> </html> What happen is that after click the button it will insert the textbox value in the database through the webservice 'insert' and then reload the gridview that is placed inside a different aspx page. The problem is that when I ran it on IE9 during the 1st insert everything works properly but the succeeding inserts does reload the gridview and I noticed that it says '304' on the network tab of ie9 dev tool.

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  • dialog.show() crashes my application, why?

    - by user1739462
    I'm new in adroid. I like to do things when the color reach a value. I like (for example) show the alert if r is bigger than 30, but the application go in crash. Thank for very simple answares. public class MainActivity extends Activity { private AlertDialog dialog; private AlertDialog.Builder builder; private BackgroundColors view; public class BackgroundColors extends SurfaceView implements Runnable { public int grand=0; public int step=0; private boolean flip=true; private Thread thread; private boolean running; private SurfaceHolder holder; public BackgroundColors(Context context) { super(context); } Inside this loop while running is true. is impossible to show dialogs ?? public void run() { int r = 0; while (running){ if (holder.getSurface().isValid()){ Canvas canvas = holder.lockCanvas(); if (r > 250) r = 0; r += 10; if (r>30 && flip){ flip=false; // ********************************* dialog.show(); // ********************************* // CRASH !! } try { Thread.sleep(300); } catch(InterruptedException e) { e.printStackTrace(); } canvas.drawARGB(255, r, 255, 255); holder.unlockCanvasAndPost(canvas); } } } public void start() { running = true; thread = new Thread(this); holder = this.getHolder(); thread.start(); } public void stop() { running = false; boolean retry = true; while (retry){ try { thread.join(); retry = false; } catch(InterruptedException e) { retry = true; } } } public boolean onTouchEvent(MotionEvent e){ dialog.show(); return false; } protected void onSizeChanged(int xNew, int yNew, int xOld, int yOld){ super.onSizeChanged(xNew, yNew, xOld, yOld); grand = xNew; step =grand/15; } } public void onCreate(Bundle b) { super.onCreate(b); view = new BackgroundColors(this); this.setContentView(view); builder = new AlertDialog.Builder(this); builder.setMessage("ciao"); builder.setPositiveButton("OK", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int which) { Log.d("Basic", "It worked"); } }); dialog = builder.create(); } public void onPause(){ super.onPause(); view.stop(); } public void onResume(){ super.onResume(); view.start(); } }

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  • JavaScript (via Greasemonkey) failing to set "title" attributes on <a> tags

    - by rjray
    I have the following (fairly) simple JavaScript snippet that I have wired into Greasemonkey. It goes through a page, looks for <a> tags whose href points to tinyurl.com, and adds a "title" attribute that identifies the true destination of the link. Much of the important code comes from an older (unsupported) Greasemonkey script that quits working when the inner component that held the XPath implementation changed. My script: (function() { var providers = new Array(); providers['tinyurl.com'] = function(link, fragment) { // This is mostly taken from the (broken due to XPath component // issues) tinyurl_popup_preview script. link.title = "Loading..."; GM_xmlhttpRequest({ method: 'GET', url: 'http://preview.tinyurl.com/' + fragment, onload: function(res) { var re = res.responseText.match("<blockquote><b>(.+)</b></blockquote>"); if (re) { link.title = re[1].replace(/\<br \/\>/g, "").replace(/&amp;/g, "&"); } else { link.title = "Parsing failed..."; } }, onerror: function() { link.title = "Connection failed..."; } }); }; var uriPattern = /(tinyurl\.com)\/([a-zA-Z0-9]+)/; var aTags = document.getElementsByTagName("a"); for (i = 0; i < aTags.length; i++) { var data = aTags[i].href.match(uriPattern); if (data != null && data.length > 1 && data[2] != "preview") { var source = data[1]; var fragment = data[2]; var link = aTags[i]; aTags[i].addEventListener("mouseover", function() { if (link.title == "") { (providers[source])(link, fragment); } }, false); } } })(); (The reason the "providers" associative array is set up the way it is, is so that I can expand this to cover other URL-shortening services as well.) I have verified that all the various branches of code are being reached correctly, in cases where the link being examined does and does not match the pattern. What isn't happening, is any change to the "title" attribute of the anchor tags. I've watched this via Firebug, thrown alert() calls in left and right, and it just never changes. In a previous iteration all expressions of the form: link.title = "..."; had originally been: link.setAttribute("title", "..."); That didn't work, either. I'm no newbie to JavaScript OR Greasemonkey, but this one has me stumped!

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  • Replacing div html() by echoing PHP - how to?

    - by Jared
    Hello, I have a multiple product elements that get their class and ID from PHP: $product1["codename"] = "product-1"; $product1["short"] = "Great Product 1"; $product2["codename"] = "product-2"; $product2["short"] = "Great Product 2"; <div class="leftMenuProductButton" id="'. $product1["codename"].'" >'. $product1["short"].'</div> <div class="leftMenuProductButton" id="'. $product2["codename"].'" >'. $product2["short"].'</div> These display as: <div class="leftMenuProductButton" id="product-1" > Great Product 1</div> <div class="leftMenuProductButton" id="product-2" > Great Product 2</div> In the page, I have an element that I want to replace the HTML: <div id="productPopupTop"> //Replace this content </div> Using jquery, I have tried the following: $( '.leftMenuProductButton' ).hover ( function () { var swapNAME = $(this).attr("id"); //gets the ID, #product-1, #product-2 etc. This works. $("#productPopupTop").html(' <? echo $' + swapNAME + '["short"] ?>'); //This is supposed to get something like <? echo $product-1["short"] ?> This doesn't appear to work. }, function () { //this is just here for later }); If I try to do an alert('<? echo $' + swapNAME + '["short"] ?>'); it will literally display something like <? echo $product-1["short"] ?> Please note that both the Javascript and the PHP are externally linked in a PHP file (index.php <<< (js.js, products.php) QUESTION: How do I replace the HTML() of #productPopupTop with the ["short"] of a product? If I should use Ajax, how would I code this?

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  • index seems to be out of sync for jquery .keydown and .click methods

    - by Growler
    I'd like to navigate images using both keyboard and mouse (clicking left and right arrow images). I'm using Jquery to do this, but the shared imgIndex seems to be off from the .keydown function and the .click function... Whenever .keydown function -- or ++ the imgIndex, isn't that changed index also used in the click function? So shouldn't they always be on the same index? keydown function: <script type="text/javascript"> var imgArray = [<?php echo implode(',', getImages($site)) ?>]; $(document).ready(function() { var img = document.getElementById("showimg"); img.src = imgArray[<?php echo $imgid ?>]; var imgIndex = <?php echo $imgid ?>; alert(imgIndex); $(document).keydown(function (e) { var key = e.which; var rightarrow = 39; var leftarrow = 37; var random = 82; if (key == rightarrow) { imgIndex++; if (imgIndex > imgArray.length-1) { imgIndex = 0; } img.src = imgArray[imgIndex]; } if (key == leftarrow) { if (imgIndex == 0) { imgIndex = imgArray.length; } img.src = imgArray[--imgIndex]; } }); click function: Connected to left and right clickable images $("#next").click(function() { imgIndex++; if (imgIndex > imgArray.length-1) { imgIndex = 0; } img.src = imgArray[imgIndex]; }); $("#prev").click(function() { if (imgIndex == 0) { imgIndex = imgArray.length; } img.src = imgArray[--imgIndex]; }); }); Just so you have some visibility into the getImages php function: <?php function getImages($siteParam) { include 'dbconnect.php'; if ($siteParam == 'artwork') { $table = "artwork"; } else { $table = "comics"; } $catResult = $mysqli->query("SELECT id, title, path, thumb, views, catidFK FROM $table"); $img = array(); while($row = $catResult->fetch_assoc()) { $img[] = "'" . $row['path'] . "'"; } return $img; } ?> Much appreciated! Snapshot of where the script is on "view image.php"

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  • How does Page.IsValid work?

    - by Lijo
    I have following code with a RequiredFieldValidator. The EnableClientScript property is set as "false" in the validation control. Also I have disabled script in browser. I am NOT using Page.IsValid in code behind. Still, when I submit without any value in textbox I will get error message. From comments of @Dai, I came to know that this can be an issue, if there is any code in Page_Load that is executed in a postback. There will be no validation errors thrown. (However, for button click handler, there is no need to check Page.IsValid) if (Page.IsPostBack) { string value = txtEmpName.Text; txtEmpName.Text = value + "Appended"; } QUESTION Why the server side validation does not happen before Page_Load? Why it works fine when I use Page.IsValid? UPDATE It seems like, we need to add If(Page.IsValid) in button click also if we are using a Custom Validator with server side validation. Refer CustomValidator not working well. Note: Client side validation question is present here: Whether to use Page_IsValid or Page_ClientValidate() (for Client Side Events) MARKUP <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> <script type="text/javascript"> alert('haiii'); </script> </head> <body> <form id="form1" runat="server"> <div> <asp:ValidationSummary runat="server" ID="vsumAll" DisplayMode="BulletList" CssClass="validationsummary" ValidationGroup="ButtonClick" /> <asp:TextBox ID="txtEmpName" runat="server"></asp:TextBox> <asp:RequiredFieldValidator ID="valEmpName" runat="server" ControlToValidate="txtEmpName" EnableClientScript="false" ErrorMessage="RequiredFieldValidator" Text="*" Display="Dynamic" ValidationGroup="ButtonClick"></asp:RequiredFieldValidator> <asp:Button ID="Button1" runat="server" onclick="Button1_Click" Text="Button" ValidationGroup="ButtonClick" /> </div> </form> </body> </html> CODE BEHIND protected void Button1_Click(object sender, EventArgs e) { string value = txtEmpName.Text; SubmitEmployee(value); } References: Should I always call Page.IsValid? ASP.NET Validation Controls – Important Points, Tips and Tricks CustomValidator not working well

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  • Select options not showing in IE

    - by donkapone
    I have a dynamically generated select with some options and it shows the options fine in normal browsers, but its empty options in IE. Here's the generated HTML: <select name="0" id="custom_0" style="border-bottom: #c0cedb 1px solid; border-left: #c0cedb 1px solid; background-color: #ededed; width: 280px; font-size: 0.87em; border-top: #c0cedb 1px solid; border-right: #c0cedb 1px solid"> <option id="1000" value="0" name="00">1x2GB ECC DDRIII 2GB ECC DDRIII</option> <option id="1001" value="10" name="01">2x2GB ECC DDRIII 4GB ECC DDRIII (+10.00 €)</option> </select> I can't really show you the javascript, since there's so much of it and I would be able to make it simple just for a demo. Maybe you had some of you would've had a similar experience and could figure this one out. Thanks I've added some javascript: $('#custom_order').append('<tr id="custom_'+category+'_row"><td'+padding+'>'+header+'<select id="custom_'+category+'" name="'+category+'" style="background-color:#EDEDED;border:1px solid #C0CEDB;width:280px;font-size:0.87em"></select>'+plusspan+'</td></tr>'); for (var i=0;i<components[category]['value'].length;i++){ $('#custom_'+category).append('<option id="'+components[category]['value'][i]['id']+'" value="'+components[category]['value'][i]['price']+'"></option>'); removals(category,i); dependencies(category,i); selectInput(category); } getDiff(category); getDiff() function adds the values to the options with html() function. The weird thing is, if I alert the html of the option just after the getDiff() function, it shows the value filled out. And it I put the getDiff() function in the for loop where the options are generated, it fills the values and shows them in IE, just not the last one. I'm calling getDiff() outside the loop for optimization, and since I can add the values later after all the options are generated. Well at least I thought I could, since it works on Firefox and Chrome.

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  • Submitting form in php file accessed by Ajax?

    - by dronnoc
    Hi people, I am trying to figure out how to submit a form in a page being accessed by Ajax? here are some code snippets to help demonstrate what i am trying to say. HTML BODY - THIS IS WHAT THE USER WILL SEE. <html> <head> <script language="javascript" src="linktoajaxfile.js"> </head> <body onLoad="gotoPage(0)"> <div id="fillThis"> </div> </body> </html> AJAX FILE var xmlhttp function gotoPage(phase) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Your browser does not support AJAX!"); return; } var url="pageofstuffce.php"; url=url+"?stg="+phase; url=url+"&sid="+Math.random(); xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } function stateChanged() { if (xmlhttp.readyState==4) { document.getElementById("fillThis").innerHTML=xmlhttp.responseText; } } function GetXmlHttpObject() { if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari return new XMLHttpRequest(); } if (window.ActiveXObject) { // code for IE6, IE5 return new ActiveXObject("Microsoft.XMLHTTP"); } return null; } PAGE OF DATA <?php $stage = $_GET['stg']; if($stage == 0) { echo '<a onClick="gotoPage(1)">click me</a>'; } elseif($stage == 1) { <form> <input type="text" name="name"> <input type="submit" name="submit"> </form> } elseif(somehow can reach here) { show data from form. } ?> Can anyone perhaps help me get past the form and display the data in the same page? Also, i have looked around, and i don't think anything around has what i need... correct me if i'm wrong though :) Thanks in advance, and i hope i didn't put in too much detail :) Dronnoc EDIT Forgot to mention what I've tried; I have tried submitting the form to itself (same file) and that destroyed the ajax link, and opened the page. i have also tried just having the button move the page onto another step, but the $_POST variable is empty... i am at a loss, so does anyone else have any ideas?

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  • jquery .find to get the text in a <li>

    - by Chris
    So I have a series of 2 nested ul's. When you click on the text (which is in an a tag) in the li, my page makes that editable and adds a save button. clicking the save button needs to give me back the new text inside that li and the id of that li. The id is not a problem. I'm trying to use jQuery's .find to select that anchor tag (which is successful) but i can't seem to get the text from it. Here is an example of the first list and it's sublists. <ul class='lists'> <li class='list1'> <a class='a list' id='list1'> List 1 Name</a> <img id='savelist1id' onClick="SaveName(this.parentNode.id)" src='save.jpg'> <ul class='list1subs'> <li class='sub1'> <a class='a sub' id='sub1id'> Sub 1 Name</a> <img id='savesub1id' onClick="SaveName(this.parentNode.id)" src='save.jpg'> </li> <li class='sub3'> <a class='a sub' id='sub2id'> Sub 2 Name</a> <img id='savesub2id' onClick="SaveName(this.parentNode.id)" src='save.jpg'> </li> <li class='sub2'> <a class='a sub' id='sub3id'> Sub 3 Name</a> <img id='savesub3id' onClick="SaveName(this.parentNode.id)" src='save.jpg'> </li> </ul> </li> </ul> Here's the code for identifying which save button you clicked. function SaveName(parentid){ $('li').find('a').each(function(){ if (this.id == parentid){ alert(this.id+' '+this.text) } } }); I am wanting this.text to show me the text inside the anchor tags. Help, please?

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  • jqgrid modify data returned from ajax call before display in table

    - by user954211
    I have to display some data that I receive from the server as json object like this {"rowndx":"0","rows":"25","rowstotal":"100","rowsdata":[ ["00","DEVICE001","T0_IHOME","1","***","1","10"], ["01","DEVICE002","NO_DEVICE","1","***","1","10"], ["02","DEVICE003","NO_DEVICE","0","***","1","10"], ..... Before displaying the received data in a table I would like to make changes where necessary adding units to the numbers or replacing the numbers with words (eg 0 -OFF 1- ON) To do this I have associated at the ajax option "success" my encoding function. In this case, however, remains always visible the message "Loading ..." and no other action is permitted. I moved my re-encoding procedure to the "complete" ajax option and this time it seems to work. But I did not understand what was my mistake and I do not know if my procedure can work. This is my table ajax configuration url : "devtbl.json", mtype : "POST", datatype : "json", postData : ...... ajaxGridOptions: { type : 'post', contentType: 'application/json', async : false, complete : DEVparse_serverdata, error : function() { alert('Something bad happened. Stopping');}, }, jsonReader : { root : "tablerows", page : "currentpage", total : "totalpages", records : "totalrecords", cell : "", id : "0", userdata : "userdata", repeatitems : true }, and my coding function function DEVparse_serverdata(js , textStatus) { var jsontablereply = {} ; var rowsxpage_int = parseInt(UB.rowsxpage.DEVtable) ; var jsonreply = jQuery.parseJSON(js.responseText) ; jsontablereply.currentpage = "" + (1 + (parseInt(jsonreply.rowndx) / rowsxpage_int)); jsontablereply.totalpages = "" + parseInt((parseInt(jsonreply.rowstotal) + (rowsxpage_int-1)) / rowsxpage_int) ; jsontablereply.totalrecords = jsonreply.rowstotal; jsontablereply.tablerows = [] ; $.each(jsonreply.rowsdata, function(ndx, row) { var rowarray = [] ; rowarray[0] = row[0] ; rowarray[1] = row[1] ; rowarray[2] = row[2] ; rowarray[3] = row[3] ; rowarray[4] = row[4] ; switch (row[2]) { case "NO_DEVICE": rowarray[5] = "***" ; break ; case "T0_IHOME": rowarray[5] = "T=" + row[5] + "°C" ; break ; } jsontablereply.tablerows[ndx] = rowarray ; }) ; // each jQuery("#DEVtbl")[0].addJSONData(jsontablereply); } (I am a beginner with Jquery my coding style is poor)

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  • PHP uploads and checking

    - by user147685
    Hi all, I want to update/insert file by using upload box to the database but before that it will check for the file type thats only pdf can be upload. Somthing wrong with the codes and i dont know what..Please help here are part of my updates codes: $id=$rs['id']; $qry = "SELECT a.faillampiran FROM {$CFG->prefix}ptk_lampiran a, {$CFG->prefix}ptk b WHERE a.ptkid=$id and b.id=$id"; $sql = get_records_sql($qry); if($_POST['check']){ $ext = pathinfo($faillampiran,PATHINFO_EXTENSION); $err = "Upload Only PDF File. "; if ($ext =='pdf'){ $qry="UPDATE {$CFG->prefix}ptk_lampiran SET faillampiran='".$faillampiran."' WHERE ptkid='".$_GET['id']."'"; $sql=mysql_query($qry); $qry = "SELECT a.faillampiran FROM {$CFG->prefix}ptk_lampiran a, {$CFG->prefix}ptk b WHERE b.id = '".$rs[id]."' AND a.ptkid = '".$rs[id]."' "; $sql = get_records_sql($qry); foreach($sql as $rs){ ?> <?=basename($rs->faillampiran); ?><br> <? } ?> <tr><td></td><td></td><td> <input type="file" size="50" name="faillampiran" alt="faillampiran" value= "<?=$faillampiran;?>" /> <input type="submit" name="edit" value="Muat naik fail ini" /><br /> </td></tr> } else { echo "<script>alert('$err')</script>"; } } else { foreach($sql as $rs){ ?> <?=basename($rs->faillampiran); ?><br> <? } ?> <input type="file" size="50" name="faillampiran" alt="faillampiran" value= "<?=$faillampiran;?>" /> <input type="submit" name="edit" value="Muat naik fail ini" /><br /> <?} Sori bout the messiness of the codes, im still a beginner in this languages. thx

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  • Why is the data I am printing not in a table format

    - by udaya
    Hi This is my program .when i submit the print button i can print the datas but they are not aligned in the table formatthe format in which i need the print to be...How can i print in the correct format <html> <head> <script type="text/javascript" src="http://jqueryjs.googlecode.com/files/jquery-1.3.1.min.js" > </script> <script type="text/javascript"> function PrintElem(elem) { //alert('ddd'); Popup($(elem).text()); } function Popup(data) { var mywindow = window.open('', 'mydiv', 'height=400,width=600'); mywindow.document.write('<html><head><title>my div</title>'); /*optional stylesheet*/ //mywindow.document.write('<link rel="stylesheet" href="main.css" type="text/css" />'); mywindow.document.write('</head><body >'); mywindow.document.write(data); mywindow.document.write('</body></html>'); mywindow.document.close(); mywindow.print(); return true; } </script> </head> <body> <div id="mydiv"> <table width="200" border="1"> <tr> <td>sss</td> <td>sssss;</td> <td>snssbsp;</td> </tr> <tr> <td>ssss;</td> <td>sssnbsp;</td> <td>snbsp;</td> </tr> <tr> <td>snbsp;</td> <td>snbsp;</td> <td>snbsp;</td> </tr> </table> </div> <input type="button" value="Print Div" onClick="PrintElem('#mydiv')" /> </body> </html>

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