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  • SEO for Computer Software Engineering Topics

    - by Michael Aaron Safyan
    I'm currently trying to SEO my development and coding search custom search engine as well my website that has a variety of coding and development resources. I would like to increase the number of links to my website, but I don't want to simply generate spam. What are some places that I should submit my website, where the content would be considered relevant rather than just spam? Thanks.

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  • To run two CGIs simultaneously

    - by Punit
    On my form onbutton submit following events takes place: 1) CGI is called which uploads the file 2) Javascript/Ajax function is called which opens a request for another CGI and is supposed to receive updated values from there. However, it seems that the CGI with which Ajax is communicating is not responding to Ajax requests. My question is that is it possible to run two CGIs simultaneously?

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  • Not allowing characters after Space. Mysql Insert With PHP

    - by Jake
    Ok so I think this is easy but I dont know (I'm a novice to PHP and MySQL). I have a select that is getting data from a table in the database. I am simply taking whatever options the user selects and putting it into a separate table with a php mysql insert statement. But I am having a problem. When I hit submit, everything is submitted properly except for any select options that have spaces don't submit after the first space. For example if the option was COMPUTER REPAIR, all that would get sent is COMPUTER. I will post code if needed, and any help would be greatly appreciated. Thanks! Ok here is my select code: <?php include("./config.php"); $query="SELECT id,name FROM category_names ORDER BY name"; $result = mysql_query ($query); echo"<div style='overflow:auto;width:100%'><label>Categories (Pick three that describe your business)</label><br/><select name='select1'><option value='0'>Please Select A Category</option>"; // printing the list box select command while($catinfo=mysql_fetch_array($result)){//Array or records stored in $nt echo "<option>$catinfo[name]</option><br/> "; } echo"</select></div>"; ?> And here is my insert code ( Just to let you know its got everything not just the select!) ?php require("./config.php"); $companyname = mysql_real_escape_string(addslashes(trim($_REQUEST['name']))); $phone = mysql_real_escape_string(addslashes($_REQUEST['phone'])); $zipcode = mysql_real_escape_string(addslashes($_REQUEST['zipcode'])); $city = mysql_real_escape_string(addslashes($_REQUEST['city'])); $description = mysql_real_escape_string(addslashes($_REQUEST['description'])); $website = mysql_real_escape_string(addslashes($_REQUEST['website'])); $address = mysql_real_escape_string(addslashes($_REQUEST['address'])); $other = mysql_real_escape_string(addslashes($_REQUEST['other'])); $payment = mysql_real_escape_string(addslashes($_REQUEST['payment'])); $products = mysql_real_escape_string(addslashes($_REQUEST['products'])); $email = mysql_real_escape_string(addslashes($_REQUEST['email'])); $select1 = mysql_real_escape_string(addslashes($_REQUEST['select1'])); $select2 = mysql_real_escape_string(addslashes($_REQUEST['select2'])); $select3 = mysql_real_escape_string(addslashes($_REQUEST['select3'])); $save=$_POST['save']; if(!empty($save)){ $sql="INSERT INTO gj (name, phone, city, zipcode, description, dateadded, website, address1, other2, payment_options, Products, email,cat1,cat2,cat3) VALUES ('$companyname','$phone','$city','$zipcode','$description',curdate(),'$website','$address','$other','$payment','$products','$email','$select1','$select2','$select3')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "<br/><h2><font color='green' style='font-size:15px'>1 business added</font></h2>"; mysql_close($link); } ?>

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  • how to upload a audio file using REST webservice in Google App Engine for Java

    - by sathya
    Am using google app engine with eclipse IDE and trying to upload a audio file. I used the File Upload in Google App Engine For Java and can able to upload the file successfully. Now am planning to use REST web service for it. I had analyzed in developers.google but i failed. Can anyone suggest me how to implement REST Web services in google app engine using Eclipse. The code google provided is shown below, // file Upload.java public class Upload extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException { Map<String, BlobKey> blobs = blobstoreService.getUploadedBlobs(req); BlobKey blobKey = blobs.get("myFile"); if (blobKey == null) { res.sendRedirect("/"); } else { res.sendRedirect("/serve?blob-key=" + blobKey.getKeyString()); }}} // file Serve.java public class Serve extends HttpServlet { private BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException { BlobKey blobKey = new BlobKey(req.getParameter("blob-key")); blobstoreService.serve(blobKey, res); }} // file index.jsp <%@ page import="com.google.appengine.api.blobstore.BlobstoreServiceFactory" %> <%@ page import="com.google.appengine.api.blobstore.BlobstoreService" %> <% BlobstoreService blobstoreService = BlobstoreServiceFactory.getBlobstoreService(); %> <form action="<%= blobstoreService.createUploadUrl("/upload") %>" method="post" enctype="multipart/form-data"> <input type="file" name="myFile"> <input type="submit" value="Submit"> </form> // web.xml <servlet> <servlet-name>Upload</servlet-name> <servlet-class>Upload</servlet-class> </servlet> <servlet> <servlet-name>Serve</servlet-name> <servlet-class>Serve</servlet-class> </servlet> <servlet-mapping> <servlet-name>Upload</servlet-name> <url-pattern>/upload</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Serve</servlet-name> <url-pattern>/serve</url-pattern> </servlet-mapping> Now how to provide a rest web service for the above code. Kindly suggest me an idea.

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  • What does the MVC Controller.UpdateModel<T>(T) actually try to do?

    - by unanswered
    When I submit my MVC Page I get an IvalidOperationException from System.Web.Mvc Controller object in the UpdateModel method. the MSDN documentation states that this method does the following: Updates the specified model instance using values from the controller's current value provider. Is the value provider referencing the current Request object? Or where exactly does it get the values that it is using to update the model? And what specifically does the UpdateModel method check and what does it 'mean' when it says that The model of type 'abcXYZ' was not successfully updated Thanks

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  • jquery function call with parameters

    - by Kaushik Gopal
    Hi a newb question: I have a table with a bunch of buttons like so: <tr class="hr-table-cell" > <td>REcord 1</td> <td> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(222445,704);" /> </td> </tr> <tr class="hr-table-cell" > <td>REcord 1</td> <td align="center" class="hr-table-bottom-blue-border" valign="middle"> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(237760,776);" /> </td> </tr> I have my jquery like so: <script type="text/javascript"> // JQUERY stuff $(document).ready(function(){ function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } }); This doesn't seem to work.I thought this means, the function is ready only after the dom is ready. After the dom is ready and i click the button, why is not recognizing the function declaration within the .ready() function? However if i use the function directly: <script type="text/javascript"> function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } This works. I want to get my fundamentals straight here... If i do the declaration without the .ready() , does that mean i'm using plain vanilla jscript? If i were to do this with the document.ready - the usual jquery declaration way, what would i have to change to make it work? I understand there are much better ways to do this like binding with buttons etc, but I want to know why this particular way doesn't seem to be working. Thanks. Cheers. K

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  • Can MySQL reasonably perform queries on billions of rows?

    - by haxney
    I am planning on storing scans from a mass spectrometer in a MySQL database and would like to know whether storing and analyzing this amount of data is remotely feasible. I know performance varies wildly depending on the environment, but I'm looking for the rough order of magnitude: will queries take 5 days or 5 milliseconds? Input format Each input file contains a single run of the spectrometer; each run is comprised of a set of scans, and each scan has an ordered array of datapoints. There is a bit of metadata, but the majority of the file is comprised of arrays 32- or 64-bit ints or floats. Host system |----------------+-------------------------------| | OS | Windows 2008 64-bit | | MySQL version | 5.5.24 (x86_64) | | CPU | 2x Xeon E5420 (8 cores total) | | RAM | 8GB | | SSD filesystem | 500 GiB | | HDD RAID | 12 TiB | |----------------+-------------------------------| There are some other services running on the server using negligible processor time. File statistics |------------------+--------------| | number of files | ~16,000 | | total size | 1.3 TiB | | min size | 0 bytes | | max size | 12 GiB | | mean | 800 MiB | | median | 500 MiB | | total datapoints | ~200 billion | |------------------+--------------| The total number of datapoints is a very rough estimate. Proposed schema I'm planning on doing things "right" (i.e. normalizing the data like crazy) and so would have a runs table, a spectra table with a foreign key to runs, and a datapoints table with a foreign key to spectra. The 200 Billion datapoint question I am going to be analyzing across multiple spectra and possibly even multiple runs, resulting in queries which could touch millions of rows. Assuming I index everything properly (which is a topic for another question) and am not trying to shuffle hundreds of MiB across the network, is it remotely plausible for MySQL to handle this? UPDATE: additional info The scan data will be coming from files in the XML-based mzML format. The meat of this format is in the <binaryDataArrayList> elements where the data is stored. Each scan produces = 2 <binaryDataArray> elements which, taken together, form a 2-dimensional (or more) array of the form [[123.456, 234.567, ...], ...]. These data are write-once, so update performance and transaction safety are not concerns. My naïve plan for a database schema is: runs table | column name | type | |-------------+-------------| | id | PRIMARY KEY | | start_time | TIMESTAMP | | name | VARCHAR | |-------------+-------------| spectra table | column name | type | |----------------+-------------| | id | PRIMARY KEY | | name | VARCHAR | | index | INT | | spectrum_type | INT | | representation | INT | | run_id | FOREIGN KEY | |----------------+-------------| datapoints table | column name | type | |-------------+-------------| | id | PRIMARY KEY | | spectrum_id | FOREIGN KEY | | mz | DOUBLE | | num_counts | DOUBLE | | index | INT | |-------------+-------------| Is this reasonable?

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  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • How to handle when SSRS does not automatically update fields based on database query?

    - by badpanda
    So I am trying to change the number of fields in my dataset in SSRS and the refresh button is not picking up the added field from the SQL server. The query is definitely returning the correct data, as I have double checked in the server engine itself. Also, I have tried manually adding the field using the SSRS menu, but as soon as I execute it disappears. Any suggestions or similar experiences?

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  • php how to open new tab or new window

    - by dpaksp
    in php my task here is before user downloads a file i have display a form thr where i can get details of user i.e form1...on click on submit button it will go to next php file where it process some logic...from thr i have open new tab or new window in that i have display my file or any thing ....how to do thank u

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  • JRadio Menu buttons - JAVA

    - by user337465
    I have a relatively easy question. I have to create a java GUI to do math based calculations. I have to have a menu item that will double the variable that I am doing calculations with. For example variable = 1 if radio button = selected{ variable = variable * 2 } So, how would I achieve the if statement there? thankyou

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  • SAS on OS X any way to run without working within virtual machine?

    - by user309284
    I would like to edit and submit SAS code from emacs (aquamacs) on OS X to SAS running on Vista (through Parallels). Any idea how to do this? I like to do everything through one place and it is really annoying to work within the windows emulator. I have run SAS from a linux server through aquamacs but wonder if something similar can be done locally. Any ideas?

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  • SDL_GL_SwapBuffers Segfault

    - by RyanG
    I'm getting a segfault that GDB says is coming from SDL_GL_SwapBuffers. However, I can't imagine why. The SDL documentation mentions no specific pre-conditions for calling swapBuffers except that double buffering be allowed. Is this an option I have to turn on while initializing OpenGL or is this a hardware capability thing? My code: http://pastie.org/859721 (Ignore the unused variables, strange comments and other things. I haven't prettied this up at all. :P)

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  • PHP syntax error “unexpected $end”

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • Uploading photo from my website, and send it via email.

    - by Sohail
    Hello everybody, I have a form, which gathers some Information of my visitor, and when they submit the Information, it will send it to my desired email. now I need another input "file" that they can even attach their photo and send along with it to my email not on my server, I have no Idea how can I do that, I would appreciate any helps.

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  • Fixing Floating Point Error

    - by HannesNZ
    I have some code that gets the leading value (non-zero) of a Double using normal math instead of String Math... For Example: 0.020 would return 2 3.12 would return 3 1000 should return 1 The code I have at the moment is: LeadingValue := Trunc(ResultValue * Power(10, -(Floor(Log10(ResultValue))))) However when ResultValue is 1000 then LeadingValue ends up as 0. What can I do to fix this problem I'm assuming is being caused by floating point errors? Thanks.

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  • Writing " to a file in bash.

    - by S1syphus
    Simply I need to write "echo" t${count} = "$"t${count}" To a text file, including all the So the output would be something like: echo " t1 = $t1" With " as they are. So I have tried: count=1 saveIFS="$IFS" IFS=$'\n' array=($(<TEST.txt)) IFS="$saveIFS" for i in "${array[@]}" do echo "echo" t${count} = "$"t${count}"" (( count++ )) done >> long1.txt And variations on this such as: echo "echo" """"" t${count} = "$"t${count}"" But I guess the wrapping in double " is only for variables. Ideas?

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