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• How to display a border-bottom only if table cells are not empty (CSS)

  - by Polarpro

  Hey there, I've got a Filemaker calculation that generates an HTML page with several tables. If the calculation results in values for certain fields the result would be <table> <tr><td>Example value 1</td></tr> <tr><td>Example value 2</td></tr> ... </table> If the calculation finds no values to be displayed, the result would simply be <table> </table> In the first case, I want to the table to display a border at the bottom (or any other horizontal line); in the second case, I don't want to display a border at the bottom. I cannot find a way to get this done using a CSS... Thanks in adavance :-)

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• Quicktabs with AJAX Views

  - by Primus202

  I'm working in Drupal 7 with the quicktabs and views modules. I have a great looking tabbed set of tables filled with data. However, despite all the views having AJAX turned on, trying to do a column sort (or use the pager I imagine though currently there is not enough content to require one) causes the page to reload with a new URL instead of simply reloading the view in question. I found on Drupal some fixes for this problem but all seem to be in Drupal 6. Anyone have a patch for 7?

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• fastest way to perform string search in general and in python

  - by Rkz

  My task is to search for a string or a pattern in a list of documents that are very short (say 200 characters long). However, say there are 1 million documents of such time. What is the most efficient way to perform this search?. I was thinking of tokenizing each document and putting the words in hashtable with words as key and document number as value, there by creating a bag of words. Then perform the word search and retrieve the list of documents that contained this word. From what I can see is this operation will take O(n) operations. Is there any other way? may be without using hash-tables?. Also, is there a python library or third party package that can perform efficient searches?

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• How do i use SQL Server 2008? With Visual Studios?

  - by acidzombie24

  Its a two part question. How do i use SQL Server 2008? With Visual Studios? I started up a dummy project and with server explorer i tried with create new sql server database and add connection using my computer name (it came from a dropdown) as the server location. When i tried to create the database 'TestDB1' i got an error. I dont understand why. Its a fresh install and i have restarted the comp a few times since then. I havent messed with visual studios or the servers or even the control options to disable anything that would have been automatic. So whats with this? -edit- My goals are 1) create a database. 2) Be able to see all the database that exist on the server 3) execute sql queries in the ide 4) be able to browse tables. I dont need all of these but as many possible would be nice.

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• error defining foreign key PhpMyAdmin

  - by Ngounou lassale

  I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

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• Show the specific field on mysql table based on active date

  - by mrjimoy_05

  Suppose that I have 3 tables: A) Table UsrHeader ----------------- UsrID | UsrName ----------------- 1 | Abc 2 | Bcd B) Table UsrDetail ------------------------------- UsrID | UsrLoc | Date ------------------------------- 1 | LocA | 10 Aug 2012 1 | LocB | 15 Aug 2012 2 | LocA | 10 Aug 2012 C) Table Trx ----------------------------- TrxID | TrxDate | UsrID ----------------------------- 1 | 10 Aug 2012 | 1 2 | 16 Aug 2012 | 1 3 | 11 Aug 2012 | 2 What I want to do is to show the table like: --------------------------------------- TrxID | TrxDate | UsrID | UsrLoc --------------------------------------- 1 | 10 Aug 2012 | 1 | LocA 2 | 16 Aug 2012 | 1 | LocB 3 | 11 Aug 2012 | 2 | LocA Notice that there is one user but different location. That's based on the UsrDetail table that the user on a specified date has moved to another location. So, it should be show the user specific location on that date on every transaction. I have try this code but it is no luck: SELECT trx.TrxID, trx.TrxDate, trx.UsrID, User.UsrName, User.UsrLoc FROM trx INNER JOIN ( SELECT UsrHeader.UsrID, UsrHeader.UsrName, UserDetail.UsrLoc FROM UsrHeader INNER JOIN ( SELECT UsrDetail.UsrID, UsrDetail.UsrLoc, UsrDetail.Date FROM UsrDetail ) AS UserDetail ON UserDetail.UsrID = UsrHeader.UsrID ) AS User ON User.UsrID = trx.UsrID AND trx.TrxDate >= User.Date How to do that? Thanks..

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• Expanded securityadmin

  - by user80652

  I'm aware that sysadmin is documented as the server role necessary for creating logins (SQL/Windows-integrated); nevertheless, I'm tasked to find out if there's any other server role (built-in or otherwise) that can be used. To be specific, I'm looking to setup one or two logins with access to create logins, create [database] users, assign users to [database] roles. Potentially reset passwords, but most of the logins are Windows-integrated and it's not necessary. Cannot have access to data at all, nor can these logins have rights to update tables nor create/update roles. Seems my only options so far are to set these 2 logins with securityadmin server role and for the specific databases, configure with db_securityadmin and db_accessadmin... but this configuration doesn't allow for creating logins.

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• many-to-many relationship in CI (not using ORM)

  - by Ross

  I'm implementing a categories system in my CI app and trying to work out the best way of working with many to many relationships. I'm not using an ORM at this stage, but could use say Doctrine if necessary. Each entry may have multiple categories. I have three tables (simplified) Entries: entryID, entryName Categories: categoryID, categoryname Entry_Category: entryID, categoryID my CI code returns a record set like this: entryID, entryName, categoryID, categoryName but, as expected with Many-to-Many relationships, each "entry" is repeated for each "category". What would the best way to "group" the categories so that when I output the results, I am left with something like: Entry Name Appears in Category: Foo, Bar rather than: Entry Name Appears in Category: Foo Entry Name Appears in Category: Bar I believe the option is to track if the post ID matches a previous entry, and if so, store the respective category, and output it as one, rather than several, but am unsure of how to do this in CI. thanks for any pointers (I appreciate this is may be a vague/complex question without a better knowledge of the system).

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• Traversing ORM relationships returns duplicate results

  - by NKing253

  I have 4 tables -- store, catalog_galleries, catalog_images, and catalog_financials. When I traverse the relationship from store --> catalog_galleries --> catalog_images in other words: store.getCatalogGallery().getCatalogImages() I get duplicate records. Does anyone know what could be the cause of this? Any suggestions on where to look? The store table has a OneToOne relationship with catalog_galleries which in turn has a OneToMany relationship with catalog_images and an eager fetch type. The store table also has a OneToMany relationship with catalog_financials.

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• Count, inner join

  - by Urosh

  I have two tables: DRIVER (Driver_Id,First name,Last name,...) PARTICIPANT IN CAR ACCIDENT (Participant_Id,Driver_Id-foreign key,responsibility-yes or no,...) Now, I need to find out which driver participated in accident where responsibility is 'YES', and how many times. I did this: Select Driver_ID, COUNT (Participant.Driver_ID)as 'Number of accidents' from Participant in car accident where responsibility='YES' group by Driver_ID order by COUNT (Participant.Driver_ID) desc But, I need to add drivers first and last name from the first table(using inner join, I suppose). I don't know how, because it is not contained in either an aggregate function or the GROUP BY clause. Please help :)

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• Fill data gaps without UNION

  - by Dave Jarvis

  Problem There are data gaps that need to be filled, possibly using PARTITION BY. Query Statement The select statement reads as follows: SELECT count( r.incident_id ) AS incident_tally, r.severity_cd, r.incident_typ_cd FROM report_vw r GROUP BY r.severity_cd, r.incident_typ_cd ORDER BY r.severity_cd, r.incident_typ_cd Code Tables The severity codes and incident type codes are from: severity_vw incident_type_vw Actual Result Data 36 0 ENVIRONMENT 1 1 DISASTER 27 1 ENVIRONMENT 4 2 SAFETY 1 3 SAFETY Required Result Data 36 0 ENVIRONMENT 0 0 DISASTER 0 0 SAFETY 27 1 ENVIRONMENT 0 1 DISASTER 0 1 SAFETY 0 2 ENVIRONMENT 0 2 DISASTER 4 2 SAFETY 0 3 ENVIRONMENT 0 3 DISASTER 1 3 SAFETY Any ideas how to use PARTITION BY (or JOINs) to fill in the zero counts?

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• PHP Booking timeslot

  - by boyee007

  Im developing a php booking system based on timeslot for daily basis. Ive set up 4 database tables! Bookslot (which store all the ids - id_bookslot, id_user, id_timeslot) Timeslot (store all the times on 15 minutes gap ex: 09:00, 09:15, 09:30, etc) Therapist (store all therapist details) User (store all the members detail) ID_BOOKSLOT ID_USER ID_THERAPIST ID_TIMESLOT 1 10 1 1 (09:00) 2 11 2 1 (09:00) 3 12 3 2 (09:15) 4 15 3 1 (09:00) Now, my issue is, it keep showing repeation for timeslot when i want echoing the data for example: thera a thera b thera c ------------------------------------------------- 09:00 BOOKED available available 09:00 available BOOKED available 09:00 available available BOOKED 09:15 available BOOKED available as you can see, 09:00 showing three times, and i want something like below thera a thera b thera c ------------------------------------------------- 09:00 BOOKED BOOKED BOOKED 09:15 available BOOKED available There might be something wrong with joining the table or else. The code to join the table $mysqli->query("SELECT * FROM bookslot RIGHT JOIN timeslot ON bookslot.id_timeslot = timeslot.id_timeslot LEFT JOIN therapist ON bookslot.id_therapist = therapist.id_therapist" if anyone have the solution for this system, please help me out and i appriciate it much!

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• How to return result set based on other rows

  - by understack

  I've 2 tables - packages and items. Items table contains all items belonging to the packages along with location information. Like this: Packages table id, name, type(enum{general,special}) 1, name1, general 2, name2, special Items table id, package_id, location 1, 1, America 2, 1, Africa 3, 1, Europe 4, 2, Europe Question: I want to find all 'special' packages belonging to a location and if no special package is found then it should return 'general' packages belonging to same location. So, for 'Europe' : package 2 should be returned since it is special package (Though package 1 also belongs to Europe but not required since its a general package) for 'America' : package 1 should be returned since there are no special packages

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• Questions regarding databases MS Access [on hold]

  - by user2977751

  Good day! I am using MS Access 2007. I was wondering, how can I link a specific item on a table to another item in another table? For example, if I search for a particular product, all the suppliers of that product will be displayed. I want to connect my supply field to different suppliers field in different tables so that when I search for a particular supply, all the suppliers for that supply will be shown. And if it is also possible to link the records into a pre-set template in excel. THANKS!

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• Delete rows out of table that is innerjoined and unioned with 2 others

  - by jonathan

  We have 3 tables (table1, table2, table3), and I need to delete all the rows from table1 that have the same ID in table2 OR table3. To see a list of all of these rows I have this code: ( select table2.ID, table2.name_first, table2.name_last, table2.Collected from table2 inner join table1 on table1.ID = table2.ID where table2.Collected = 'Y' ) union ( select table3.ID, table3.name_first, table3.name_last, table3.Collected from table3 inner join table1 on table1.ID = table3.ID where table3.Collected = 'Y' ) I get back about 200 rows. How do I delete them from table1? I don't have a way to test if my query will work, so I'm nervous about modifying something I found online and potentially deleting data (we do have backups, but I'd rather not test out their integrity). TIA!

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• MySQL: Select remaining rows

  - by Bjork24

  I've searched everywhere for this, but I can't seem to find a solution. Perhaps I'm using the wrong terms. Either way, I'm turning to good ol' trusty S.O. to help my find the answer. I have two tables, we'll call them 'tools' and 'installs' tools = id, name, version installs = id, tool_id, user_id The 'tools' table records available tools, which are then installed by a user and recorded in the 'installs' table. Selecting the installed tools are simple enough: SELECT tools.name FROM tools LEFT JOIN installs ON tools.id = installs.tool_id WHERE user_id = 99 ; How do I select the remaining tools -- the ones that have yet to be installed by user #99? I'm sorry if this is painfully obvious, but I just can't seem to figure it out! Thanks for the help!

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• Concurrency handling

  - by Lijo

  Hi, Suppose, I am about to start a project using ASP.NET and SQL Server 2005. I have to design the concurrency requirement for this application. I am planning to add a TimeStamp column in each table. While updating the tables I will check that the TimeStamp column is same, as it was selected. Will this approach be suffice? Or is there any shortcomings for this approach under any circumstances? Please advice. Thanks Lijo

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• Normalization two types of customers into one table

  - by JDewzy

  I am trying to model a sales situation where you can sell to a person or to a business with a contact person. I cannot figure out the proper way to do this. It seems like 2 tables would be incorrect. But how do I model a Customer table that can be a business or a person? Would I just have a boolean for "business" and an additional "business_name" field that would default to Null. But then I have to do an if/then on the columns and that seems like poor design. Any advice, direction, or links is appreciated.

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• how to join on varchar(32) and binary(16) columns in sybase?

  - by Paul Sanwald

  I want to join two tables on a UUID. table A's UUID is represented as varchar(32). table B's UUID is represented as binary(16). what's the best way to join a varchar to a binary column? I've tried using some sybase functions for this, but I'm getting different results and unsure of why: select hextobigint('0x000036ca4c4c11d88b8dcd1344cdb512') 3948051912944290701 select convert(bigint,0x000036ca4c4c11d88b8dcd1344cdb512) -2877434794219274240 what am I missing about convert and hextobigint? I must be misundstanding at least one of these functions. thanks for your help!

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• PHP "You have () new comments on your clip", how?

  - by user292516

  Hello. I want to do a function to my users, so on index.php there is e.g: You have 2 new comments on your clip How should i do this? I mean i want ideas to do this the easiest way. Table for the videos is member_videos, and tables for the comment is member_videocomments, a comment inside the table is connected by their "videoID", which is the id of the column in member_videos. Should i do the classic, making a field, which all is 0, until it has been seen by the user its 1 or what should i do.

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• MySQL query to find the most popular value in a column joined by another value in a second table

  - by Budove

  I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

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• Merge Join component sorted outputs [SSIS]

  - by jamiet

  One question that I have been asked a few times of late in regard to performance tuning SSIS data flows is this: Why isn’t the Merge Join output sorted (i.e.IsSorted=True)? This is a fair question. After all both of the Merge Join inputs are sorted, hence why wouldn’t the output be sorted as well? Well here’s a little secret, the Merge Join output IS sorted! There’s a caveat though – it is only under certain circumstances and SSIS itself doesn’t do a good job of informing you of it. Let’s take a look at an example. Here we have a dataflow that consumes data from the [AdventureWorks2008].[Sales].[SalesOrderHeader] & [AdventureWorks2008].[Sales].[SalesOrderDetail] tables then joins them using a Merge Join component: Let’s take a look inside the editor of the Merge Join: We are joining on the [SalesOrderId] field (which is what the two inputs just happen to be sorted upon). We are also putting [SalesOrderHeader].[SalesOrderId] into the output. Believe it or not the output from this Merge Join component is sorted (i.e. has IsSorted=True) but unfortunately the Merge Join component does not have an Advanced Editor hence it is hidden away from us. There are a couple of ways to prove to you that is the case; I could open up the package XML inside the .dtsx file and show you the metadata but there is an easier way than that – I can attach a Sort component to the output. Take a look: Notice that the Sort component is attempting to sort on the [SalesOrderId] column. This gives us the following warning: Validation warning. DFT Get raw data: {992B7C9A-35AD-47B9-A0B0-637F7DDF93EB}: The data is already sorted as specified so the transform can be removed. The warning proves that the output from the Merge Join is sorted! It must be noted that the Merge Join output will only have IsSorted=True if at least one of the join columns is included in the output. So there you go, the Merge Join component can indeed produce a sorted output and that’s very useful in order to avoid unnecessary expensive Sort operations downstream. Hope this is useful to someone out there! @Jamiet  P.S. Thank you to Bob Bojanic on the SSIS product team who pointed this out to me!

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• SQL SERVER – World Shapefile Download and Upload to Database – Spatial Database

  - by pinaldave

  During my recent, training I was asked by a student if I know a place where he can download spatial files for all the countries around the world, as well as if there is a way to upload shape files to a database. Here is a quick tutorial for it. VDS Technologies has all the spatial files for every location for free. You can download the spatial file from here. If you cannot find the spatial file you are looking for, please leave a comment here, and I will send you the necessary details. Unzip the file to a folder and it will have the following content. Then, download Shape2SQL tool from SharpGIS. This is one of the best tools available to convert shapefiles to SQL tables. Afterwards, run the .exe file. When the file is run for the first time, it will ask for the database properties. Provide your database details. Select the appropriate shape files and the tool will fill up the essential details automatically. If you do not want to create the index on the column, uncheck the box beside it. The screenshot below is simply explains the procedure. You also have to be careful regarding your data, whether that is GEOMETRY or GEOGRAPHY. In this example,  it is GEOMETRY data. Click “Upload to Database”. It will show you the uploading process. Once the shape file is uploaded, close the application and open SQL Server Management Studio (SSMS). Run the following code in SSMS Query Editor. USE Spatial GO SELECT * FROM dbo.world GO This will show the complete map of world after you click on Spatial Results in Spatial Tab. In Spatial Results Set, the Zoom feature is available. From the Select label column, choose the country name in order to show the country name overlaying the country borders. Let me know if this tutorial is helpful enough. I am planning to write a few more posts about this later. Note: Please note that the images displayed here do not reflect the original political boundaries. These data are pretty old and can probably draw incorrect maps as well. I have personally spotted several parts of the map where some countries are located a little bit inaccurately. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Add-On, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Spatial, SQL Tips and Tricks, SQL Utility, T SQL, Technology

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• Using DEBUG Mode in Oracle SQL Developer to Log SQL

  - by thatjeffsmith

  Curious how we’re getting the data you see in SQL Developer when you click on something? While many of the dialogs provide a ‘SQL’ panel that shows you the SQL ABOUT to be generated, I’d rather see the SQL AS it’s executed. True, you could set a TRACE or fire up a Monitor Sessions report, but both of those solutions leave me hungry for more. Did you know that SQL Developer has a ‘debug’ mode? It slows the tool down a bit and spits out a lot of information you don’t care about, but it ALSO shows you ALL the SQL that is sent to the database, as you click around the tool! See ALL the SQL that SQL Developer sends to the database on your behalf Enable DEBUG Mode When you see the splash screen as SQL Developer fires up, frantically hit Up, Up, Down, Down, Left, Right, Left, Right, B, A, SELECT, Start. Wait, wrong game. No, all you need to do is go to your SQL Developer directory and navigate down to the ‘bin’ directory. In that directory, find the ‘sqldeveloper.conf’ file. Install Directory - sqldeveloper - bin - sqldeveloper.conf Open it with a text editor. Find this line IncludeConfFile sqldeveloper-nondebug.conf And replace it with this line IncludeConfFile sqldeveloper-debug.conf Save the file. Start up SQL Developer. Observe the Logging Page – Log Panel for the SQL There’s going to be more than just SQL here. You’ll actually see a LOT of other information. If you’re having general problems with the tool and you want to see the nitty-gritty of what’s going on, then this is a good place to satisfy your curiosity and might help us diagnose your issue if you post to the forums or open a ticket with My Oracle Support. You’ll find ‘INFO’ entries that look a little something like this - This is the query used to populate your Tables list in the connection tree. You can double-click on the sql text and get a pop-up window that’s much easier to read. See all that typing we’re saving you? I don’t recommend running in DEBUG mode all the time. Capturing this information and displaying it is more expensive than not doing so. And it provides a lot of information you don’t normally need to see. But when you DO want to know what’s going on and why, this is an excellent way of getting that information. When you’re ready to go back to ‘normal’ mode, just close SQL Developer, go back to your .conf file, and add the ‘nondebug’ bit back.

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• SQL Developer Database Diff – Compare Objects From Multiple Schemas

  - by thatjeffsmith

  Ever wonder why Database Diff isn’t called Schema Diff? One reason is because SQL Developer allows you select objects from more than one schema in the ‘Source’ connection for the compare. Simply use the ‘More’ dialog view and select as many tables from as many different schemas as you require Now, before you get around to testing this – as you should never believe what I say, trust but verify – two things you need to know: I’m using SQL Developer version 3.2 On the initial screen you need to use the ‘Maintain’ option Maintain tells SQL Developer to use the schema designation in the source connection to find the same corresponding object in the destination schema. Choose ‘maintain’ if you want to compare objects in the same schema in the destination but don’t have the user login for that schema. So after you’ve selected your databases, your diff preferences, and your objects – you’re ready to perform the compare and review your results. The DIFF Report Notice the highlighted text, SQL Developer is ‘maintaining’ the Schema context from the two databases. Short and sweet. That’s pretty much all there is to doing a compare with SQL Developer with multiple schemas involved. You may have noticed in some posts lately that my editor screenshots had a ‘green screen’ look and feel to them. What’s with the black background in your editors? In the SQL Developer preferences, you can set your editor color schemes. I started with the ‘Twilight’ scheme (team Jacob in case you’re wondering) and then customized it further by going with a default green font color. You could go pretty crazy in here, and I’m assuming 90% of you could care less and will just stick with the original. But for those of you who are particular about your IDE styling – go crazy! SQL Developer Editor Display Preferences

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