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  • FULLTEXT Irrelevant results

    - by Imran Omar Bukhsh
    Just came across this issue using the fulltext search of mysql. I have like 250 records ( long articles like stuff ) and am using the fulltext MATCH AGAINST IN BOOLEAN MODE. Now if I search for a keyword e.g. 'Samsung' and if this keyword is present in ALL the records then it returns all the 250 records which it should ( of course without `IN BOOLEAN MODE it would return nothing as the keyword is present in more than 50% of the records ). Now the problem is that in some articles the keyword 'Samsung' occurs once and in others a couple of times, but MYSQL is giving a score of 1 to all the records returned, even those which have 'Samsung' like 15 times in them.

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  • SQLite3 - select date range not working

    - by iFloh
    yet anotherone that gives me grief. In a SQLite3 DB Select I query for a date range specified in (NSDate *)fromDate to (NSDate *)toDate const char *sql = "SELECT * FROM A, B WHERE A.key = B.key AND A.date between ? and ?"; After opening the DB I run the query in Objective-C as follows: NSDateFormatter *tmpDatFmt = [[[NSDateFormatter alloc] init] autorelease]; [tmpDatFmt setDateFormat:@"dd-MM-yyyy"]; sqlite3_stmt *stmt; if(sqlite3_prepare_v2(db, sql, -1, &stmt, NULL) == SQLITE_OK) { NSLog(@"From %s to %s;", [[tmpDatFmt stringFromDate:fromDate] UTF8String], [[tmpDatFmt stringFromDate:toDate] UTF8String]); sqlite3_bind_text(stmt, 1, [[tmpDatFmt stringFromDate:fromDate] UTF8String], -1, SQLITE_STATIC); // first '?' sqlite3_bind_text(stmt, 2, [[tmpDatFmt stringFromDate:toDate] UTF8String], -1, SQLITE_STATIC); // second '?' while(sqlite3_step(stmt) == SQLITE_ROW) { NSLog(@"Success");} In the database I have several records that match the date range: 12-04-2010 = in seconds 1271059200 13-04-2010 = in seconds 1271145600 13-04-2010 = in seconds 1271152800 14-04-2010 = in seconds 1271267100 When I run it the first NSLog shows From 2010-04-01 to 2010-04-30 my problem is the records are not selected (no "Success" shows in the log) and I don't understand why. earlier I had miscalculated the dates 2 days later as 14-04-2010 = in seconds 1271232000 15-04-2010 = in seconds 1271318400 15-04-2010 = in seconds 1271325600 16-04-2010 = in seconds 1271439936 These dates worked fine (4 x "Success in the log). I am puzzled ...

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  • Looping Through Database Query

    - by DrakeNET
    I am creating a very simple script. The purpose of the script is to pull a question from the database and display all answers associated with that particular question. We are dealing with two tables here and there is a foreign key from the question database to the answer database so answers are associated with questions. Hope that is enough explanation. Here is my code. I was wondering if this is the most efficient way to complete this or is there an easier way? <html> <head> <title>Advise Me</title> <head> <body> <h1>Today's Question</h1> <?php //Establish connection to database require_once('config.php'); require_once('open_connection.php'); //Pull the "active" question from the database $todays_question = mysql_query("SELECT name, question FROM approvedQuestions WHERE status = active") or die(mysql_error()); //Variable to hold $todays_question aQID $questionID = mysql_query("SELECT commentID FROM approvedQuestions WHERE status = active") or die(mysql_error()); //Print today's question echo $todays_question; //Print comments associated with today's question $sql = "SELECT commentID FROM approvedQuestions WHERE status = active"; $result_set = mysql_query($sql); $result_num = mysql_numrows($result_set); for ($a = 0; $a < $result_num; $a++) { echo $sql; } ?> </body> </html>

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  • mysql_connect() doesn't work when run by apache; works from command line.

    - by Skeeter
    Hi, I have a strange issue. I'm trying to write a simple php webpage on my server, but mysql_connect() doesn't connect to any server, either local or otherwise. Here's where it gets strange. If I take the same php script and run it from the commandline, the script works. phpinfo() indicates that both the file (being run by apache) and the commandline (run as root) are calling the same version of php, mysql is loaded, and the php.ini is the same. Furthermore, I'm running a MediaWiki installation on this same server, and it's using the mysqld installed locally and works just fine, so I'm completely at a loss as to why the code isn't working. The error I receive on runtime: Can't connect to MySQL server on 'xxx.xxx.xxx.xxx' (13) (The IP is x'd out for the privacy of the owner of the server I'm connecting to)

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  • TV Guide script - getting current date programmes to show

    - by whitstone86
    This is part of my TV guide script: //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, episode, airdate, expiration, setreminder FROM mediumonair where airdate >= now()"); The episodes show up, so there are no issues there. However, it's getting the database to find data that's the issue. If I add a record for a programme that airs today this should show: Medium showing on TV4 8:30pm "Episode" Set Reminder Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder but this shows instead: Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder I almost have the SQL working; just not sure what the right code is here, to avoid the second mistake showing - as the record (which indicates a show currently airing) does not seem to work at present. Please can anyone help me with this? Thanks

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  • Tracking Votes and only allowing 1 vote per member

    - by MikeAdams
    What I'm trying to do is count the votes when someone votes on a "page". I think I lost myself trying to figure out how to track when a member votes or not. I can't seem to get the code to tell when a member has voted. //Generate code ID $useXID = intval($_GET['id']); $useXrank = $_GET['rank']; //if($useXrank!=null && $useXID!=null) { $rankcheck = mysql_query('SELECT member_id,code_id FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'" AND WHERE code_id="'.$useXID.'"'); if(!mysql_fetch_array($rankcheck) && $useXrank=="up"){ $rankset = mysql_query('SELECT * FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'"'); $ranksetfetch = mysql_fetch_array($rankset); $rankit = htmlentities($ranksetfetch['ranking']); $rankit+="1"; mysql_query("INSERT INTO code_votes (member_id,code_id) VALUES ('$_MEMBERINFO_ID','$useXID')") or die(mysql_error()); mysql_query("UPDATE code SET ranking = '".$rankit."' WHERE ID = '".$useXID."'"); } elseif(!mysql_fetch_array($rankcheck) && $useXrank=="down"){ $rankset = mysql_query('SELECT * FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'"'); $ranksetfetch = mysql_fetch_array($rankset); $rankit = htmlentities($ranksetfetch['ranking']); $rankit-="1"; mysql_query("INSERT INTO code_votes (member_id,code_id) VALUES ('$_MEMBERINFO_ID','$useXID')") or die(mysql_error()); mysql_query("UPDATE code SET ranking = '".$rankit."' WHERE ID = '".$useXID."'"); } // hide vote links since already voted elseif(mysql_fetch_array($rankcheck)){$voted="true";} //}

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  • Why is Zend Framework (Zend_Db_table) rejecting this SQL Query?

    - by Michael T. Smith
    I'm working on a simple JOIN of two tables (urls and companies). I am using this query call: print $this->_db->select()->from(array('u' => 'urls'), array('id', 'url', 'company_id')) ->join(array('c' => 'companies'), 'u.company_id = c.id'); which is out putting this query: SELECT `u`.`id`, `u`.`url`, `u`.`company_id`, `c`.* FROM `urls` AS `u` INNER JOIN `companies` AS `c` ON u.company_id = c.id Now, I'd prefer the c.* to not actually appear, but either way it doesn't matter. ZF dies with this error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1" but I can run that query perfectly fine in my MySQL CLI. Any ideas how to fix up this query?

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  • How to find intersect rows when condition depend on some columns in one table

    - by user3695637
    Table subscribe subscriber | subscribeto (columns) 1 | 5 1 | 6 1 | 7 1 | 8 1 | 9 1 | 10 2 | 5 2 | 6 2 | 7 There are two users that have id 1 and 2. They subscribe to various user and I inserted these data to table subscribe. Column subscriber indicates who is subscriber and column subscribeto indicates who they've subscribe to. From the above table can conclude that; user id=1 subscribed to 6 users user id=2 subscribed to 3 users I want to find manual of subscription (like Facebook is manual friends) user 1 subscribe to user 5,6,7,8,9,10 user 2 subscribe to user 5,6,7 So, Manual subscription of user 1 and 2 are: 5,6,7 And I'm trying to create SQL statement.. I give you user table for my SQL statement and I think we can use only subscribe table but I can't figure out. Table user userid (columns) 1 2 3 ... ... SQL "select * from user where (select count( 1 ) from subscribe where subscriber = '1' and subscribeto = user.userid) and (select count( 1 ) from subscribe where subscriber = '2' and subscribeto = user.userid);" This SQL can work correctly, but it very slow for thousands of columns. Please provide better SQL for me, Thanks.

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  • Explanation of NSMutableURLRequest : setHTTPMethod

    - by kkmoslehpour
    I am new to objective c programming. I am currently trying to insert data into mysql database. I have read a couple links on this and could not find the exact answer I am looking for. Here is what I am trying to do: I have my app that user inputs a name in a text field and once the press the add button, it makes a connection to my php file and my php file does the rest of the work (using POST method) and adds the name to the mysql dataase. I have seen a lot of people use NSMutableURLRequest : setHTTPMethod :POST`` in their code (in my case my php file does that and I don't haveNSMutableURLRequest` included in my code and it works perfectly fine.) My questions are: Are there any benefits of including NSMutableURLRequest in your code when you can just call your php code to take care of the POST for you? What does NSMutableURLRequest exactly do and which way is more efficient?

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  • How can I handle this kind of exceptions (in Doctrine)

    - by ppavlovic
    Can you tell me how can I handle this kind of exceptions: Fatal error: Uncaught exception 'Doctrine_Connection_Exception' with message 'PDO Connection Error: SQLSTATE[HY000] [2013] Lost connection to MySQL server at 'reading initial communication packet', system error: 110' in ... It happens when connection with MySQL is lost during query. I need to handle this exception so I can show 500 error page so the crawlers do not cache page, and to redirect user to appropriate "Try again" page. P.S. I have a lot's of code, so I can not go trough all code to put try/catch block. I need something simple and yet effective.

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  • SQL most popular

    - by Brae
    I have a mysql table with items in relation to their order. CREATE DATABASE IF NOT EXISTS `sqltest`; USE `sqltest`; DROP TABLE IF EXISTS `testdata`; CREATE TABLE `testdata` ( `orderID` varchar(10) DEFAULT NULL, `itemID` varchar(10) DEFAULT NULL, `qtyOrdered` int(10) DEFAULT NULL, `sellingPrice` decimal(10,2) DEFAULT NULL ) INSERT INTO `testdata`(`orderID`,`itemID`,`qtyOrdered`,`sellingPrice`) values ('1','a',1,'7.00'),('1','b',2,'8.00'),('1','c',3,'3.00'),('2','a',1,'7.00'),('2','c',4,'3.00'); Intended Result: A = (1+1)2 B = 2 C = (2+4)6 <- most popular How do I add up all the qty's for each item and result the highest one? It should be fairly strait forward but I'm new to SQL and I can't work this one out :S Solution needs to be mysql and or php. I guess there needs to be some sort of temporary tally variable for each item ID, but that seems like it could get messy with too many items.

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  • Same Data Appear only once.

    - by friendishan
    I have the following code which produces following output:- <? $tablaes = mysql_query("SELECT * FROM members where id='$order[user_id]'"); $user = mysql_fetch_array($tablaes); $idsd=$user['id']; $rPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'"); $hdPaid = mysql_fetch_array($rPaid); $sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'"); while ($hPaid = mysql_fetch_array($sPaid)) { ?> <td><?=$user['username']?></td> <td><?=$hPaid['total']?></td> <? } ?> </tr> It appears like this http://dl.dropbox.com/u/14384295/darrenan.jpg I want same data to appear only once.. Like Username: Vegas and price with him only once.

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  • How to "redefine search" or correct "misspelling" from the database

    - by From.ME.to.YOU
    Hello i want to add new feature to the search in my website. i'm using PHP and MYSQL. mysql database containing a table to the items that the user will search for, for each item there is a "keyword" column that's comma separated keywords "EXAMPLE: cat,dog,horse". after the user search in my website i want to get the words that are let me say "85%" similar to his search keyword, this is for redefine search. and for misspelling i want a service or something that provide if the keyword is correct or misspelled so i get some corrections and check if those exists in the database and then give those corrections to user to change his search keyword. i'm not asking for a solution here ... but if you can direct me in a one way or another that will be great Thanks guys Cheers

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  • MySql - JSON data not showing in html

    - by Ramzie
    I'm trying to create a drop down list from a MySql. The php is successfully fetching the data from the MySql. But my problem is the data is not showing on the drop down list in my HTML page? json_mysql_data2.php header("Content-Type: application/json"); require_once("con.php"); $i=0; $jsonData = array(); foreach ($conn_db->query("SELECT customerID FROM customers WHERE furniture='33' ") as $result){ $i++; $jsonData["article".$i]=$result['customerID']; } echo json_encode($jsonData); myJS.js $(document).ready(function(){ var ddlist = document.getElementById("ddlist"); var hr = new XMLHttpRequest(); hr.open("GET", "json_mysql_data2.php", true); hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); hr.onreadystatechange = function() { if(hr.readyState == 4 && hr.status == 200) { var d = JSON.parse(hr.responseText); for(var o in d){ if(d[o].title){ ddlist.innerHTML += '</option><option value='+d[o].title+'</option>'; } } } } hr.send("null"); ddlist.innerHTML = "Loading Customer ID...."; }); html <script src="myJS.js" type="text/javascript"></script> </head> <body> <div class="dlist"> Customer ID: <select id='EmpLst' name="dwlist" onchange='document.getElementById("val1").value = this.value;'><option value="">SELECT STUDENT ID</option> <div id="ddlist"></div> </select> </div>

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  • Implementing set operations in TSQL

    - by dotneteer
    SQL excels at operating on dataset. In this post, I will discuss how to implement basic set operations in transact SQL (TSQL). The operations that I am going to discuss are union, intersection and complement (subtraction).   Union Intersection Complement (subtraction) Implementing set operations using union, intersect and except We can use TSQL keywords union, intersect and except to implement set operations. Since we are in an election year, I will use voter records of propositions as an example. We create the following table and insert 6 records into the table. declare @votes table (VoterId int, PropId int) insert into @votes values (1, 30) insert into @votes values (2, 30) insert into @votes values (3, 30) insert into @votes values (4, 30) insert into @votes values (4, 31) insert into @votes values (5, 31) Voters 1, 2, 3 and 4 voted for proposition 30 and voters 4 and 5 voted for proposition 31. The following TSQL statement implements union using the union keyword. The union returns voters who voted for either proposition 30 or 31. select VoterId from @votes where PropId = 30 union select VoterId from @votes where PropId = 31 The following TSQL statement implements intersection using the intersect keyword. The intersection will return voters who voted only for both proposition 30 and 31. select VoterId from @votes where PropId = 30 intersect select VoterId from @votes where PropId = 31 The following TSQL statement implements complement using the except keyword. The complement will return voters who voted for proposition 30 but not 31. select VoterId from @votes where PropId = 30 except select VoterId from @votes where PropId = 31 Implementing set operations using join An alternative way to implement set operation in TSQL is to use full outer join, inner join and left outer join. The following TSQL statement implements union using full outer join. select Coalesce(A.VoterId, B.VoterId) from (select VoterId from @votes where PropId = 30) A full outer join (select VoterId from @votes where PropId = 31) B on A.VoterId = B.VoterId The following TSQL statement implements intersection using inner join. select Coalesce(A.VoterId, B.VoterId) from (select VoterId from @votes where PropId = 30) A inner join (select VoterId from @votes where PropId = 31) B on A.VoterId = B.VoterId The following TSQL statement implements complement using left outer join. select Coalesce(A.VoterId, B.VoterId) from (select VoterId from @votes where PropId = 30) A left outer join (select VoterId from @votes where PropId = 31) B on A.VoterId = B.VoterId where B.VoterId is null Which one to choose? To choose which technique to use, just keep two things in mind: The union, intersect and except technique treats an entire record as a member. The join technique allows the member to be specified in the “on” clause. However, it is necessary to use Coalesce function to project sets on the two sides of the join into a single set.

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • Having a problem inserting a foreign key data into a table using a PHP form

    - by Gideon
    I am newbee with PHP and MySQL and need help... I have two tables (Staff and Position) in the database. The Staff table (StaffId, Name, PositionID (fk)). The Position table is populated with different positions (Manager, Supervisor, and so on). The two tables are linked with a PositionID foreign key in the Staff table. I have a staff registration form with textfields asking for the relevant attributes and a dynamically populated drop down list to choose the position. I need to insert the user's entry into the staff table along with the selected position. However, when inserting the data, I get the following error (Cannot add or update a child row: a foreign key constraint fails). How do I insert the position selected by the user into the staff table? Here is some of my code... ... echo "<tr>"; echo "<td>"; echo "*Position:"; echo "</td>"; echo "<td>"; //dynamically populate the staff position drop down list from the position table $position="SELECT PositionId, PositionName FROM Position ORDER BY PositionId"; $exeposition = mysql_query ($position) or die (mysql_error()); echo "<select name=position value=''>Select Position</option>"; while($positionarray=mysql_fetch_array($exeposition)) { echo "<option value=$positionarray[PositionId]>$positionarray[PositionName]</option>"; } echo "</select>"; echo "</td>"; echo "</tr>" //the form is processed with the code below $FirstName = $_POST['firstname']; $LastName = $_POST['lastname']; $Address = $_POST['address']; $City = $_POST['city']; $PostCode = $_POST['postcode']; $Country = $_POST['country']; $Email = $_POST['email']; $Password = $_POST['password']; $ConfirmPass = $_POST['confirmpass']; $Mobile = $_POST['mobile']; $NI = $_POST['nationalinsurance']; $PositionId = $_POST[$positionarray['PositionId']]; //format the dob for the database $dobpart = explode("/", $_POST['dob']); $formatdob = $dobpart[2]."-".$dobpart[1]."-".$dobpart[0]; $DOB = date("Y-m-d", strtotime($formatdob)); $newReg = "INSERT INTO Staff (FirstName, LastName, Address, City, PostCode, Country, Email, Password, Mobile, DOB, NI, PositionId) VALUES ('".$FirstName."', '".$LastName."', '".$Address."', '".$City."', '".$PostCode."', '".$Country."', '".$Email."', '".$Password."', ".$Mobile.", '".$DOB."', '".$NI."', '".$PostionId."')"; Your time and help is surely appreciated.

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  • PHP-How to Pass Multiple Value In Form Field

    - by Tall boY
    hi i have a php based sorting method with drop down menu to sort no of rows, it is working fine. i have another sorting links to sort id & title, it is also working fine. but together they are not working fine. what happens is that when i sort(say by title) using links, result gets sorted by title, then if i sort rows using drop down menu rows get sorted but result gets back to default of id sort. sorting codes for id & tite is if ($orderby == 'title' && $sortby == 'asc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=title&sort=asc'>title-asc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=title&sort=asc'>title-asc:</a></li> ";} if ($orderby == 'title' && $sortby == 'desc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=title&sort=desc'>title-desc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=title&sort=desc'>title-desc:</a></li> ";} if ($orderby == 'id' && $sortby == 'asc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=id&sort=asc'>id-asc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=id&sort=asc'>id-asc:</a></li> ";} if ($orderby == 'id' && $sortby == 'desc') {echo " <li id='scurrent'><a href='?rpp=$rowsperpage&order=id&sort=desc'>id-desc:</a></li> ";} else {echo " <li><a href='?rpp=$rowsperpage&order=id&sort=desc'>id-desc:</a></li> ";} ?> sorting codes for rows is <form action="is-test.php" method="get"> <select name="rpp" onchange="this.form.submit()"> <option value="10" <?php if ($rowsperpage == 10) echo 'selected="selected"' ?>>10</option> <option value="20" <?php if ($rowsperpage == 20) echo 'selected="selected"' ?>>20</option> <option value="30" <?php if ($rowsperpage == 30) echo 'selected="selected"' ?>>30</option> </select> </form> this method passes only rows per page(rpp) into url. i want it to pass order, sort& rpp. is there a way around to pass multiple values in form fields like this. <form action="is-test.php" method="get"> <select name="rpp, order, sort" onchange="this.form.submit()"> <option value="10, $orderby, $sortby" <?php if ($rowsperpage == 10) echo 'selected="selected"' ?>>10</option> <option value="20, $orderby, $sortby" <?php if ($rowsperpage == 20) echo 'selected="selected"' ?>>20</option> <option value="30, $orderby, $sortby" <?php if ($rowsperpage == 30) echo 'selected="selected"' ?>>30</option> </select> </form> this may seem silly but it just to give you an idea of what i am trying to implement,(i am very new to php) please suggest any way to make this work. thanks

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