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  • Where I can download

    - by Sorrybyenglish
    Where I can download source codes of sites on clear OOP without Frameworks or Cms? For best studying system of OPP and with perfect code where should I focus my coding style? I can learning only on examples of code whatever but i dont need script I need all site code entirely with Database data and with setting up Apache. Thanks everyone. Sorry by my English )) P.S can you advice to me what Projects with advantages? Exactly ;p

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  • How would you show a file with CURL? [PHP]

    - by Kyle
    There is an epic lack of php CURL love on the internet for beginners like me. I was wondering how to use CURL to download & display an ICS file (They're plain text to me...) in my php code. Unless Fopen is 1,000 times easier, I'd like to stick with CURL for this one.

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  • A first look at SQL Server 2012 Availability Group Wait Statistics

    If you are trouble-shooting an AlwaysOn Availability Group topology, a study of the wait statistics will give a pointer to many of the causes of problems. Although several wait types are documented, there is nothing like practical experiment to familiarize yourself with new wait stats, and Joe Sack demonstrates a way of testing the sort of waits generated by an availability group under various circumstances.

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  • Why doesn't SSIS ftp task receive file?

    - by Mark
    I'm running an FTP task inside of SSIS to receive a file and the task executes successfully yet no file is returned to the local folder that I specified. Where did the file go? How can I make the FTP task download a file to the location that I need it at?

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  • Gracefully Dealing with Deadlocks

    - by Derek Dieter
    In some situations, deadlocks may need to be dealt with not by changing the source of the deadlock, but by changing handling the deadlock gracefully. An example of this may be an external subscription that runs on a schedule deadlocking with another process. If the subscription deadlocks then it would be ok to [...]

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  • Restoring a Publisher Database in SQL Server

    Introduction Restoring any database is a critical task which will be  complicated by the database to be  restored being a publisher database. For the purposes of this article, I will assume familiarity with the different types ... [Read Full Article]

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  • In SQL, why is "select *, count(*) from sentGifts group by whenSent;" ok, but when "*" and "count(*)

    - by Jian Lin
    In SQL, using the table: mysql> select * from sentGifts; +--------+------------+--------+------+---------------------+--------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | +--------+------------+--------+------+---------------------+--------+ | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | | 2 | 2010-04-24 | 123 | 4568 | 2010-04-24 01:56:04 | 100 | | 3 | 2010-04-24 | 123 | NULL | NULL | 1 | | 4 | 2010-04-24 | NULL | 111 | 2010-04-24 03:10:42 | 2 | | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | | 6 | 2010-04-24 | 11 | 222 | 2010-04-24 03:54:49 | 6 | | 7 | 2010-04-24 | 1 | 2 | 2010-04-24 03:58:45 | 6 | +--------+------------+--------+------+---------------------+--------+ 7 rows in set (0.00 sec) The following is OK: mysql> select *, count(*) from sentGifts group by whenSent; +--------+------------+--------+------+---------------------+--------+----------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | count(*) | +--------+------------+--------+------+---------------------+--------+----------+ | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | 1 | | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | 6 | +--------+------------+--------+------+---------------------+--------+----------+ 2 rows in set (0.00 sec) But suppose we want the count(*) to appear as the first column: mysql> select count(*), * from sentGifts group by whenSent; ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '* from sentGifts group by whenSent' at line 1 it gave an error. Why is it so and what is a way to fix it? I realized that this is ok: mysql> select count(*), whenSent from sentGifts group by whenSent; +----------+------------+ | count(*) | whenSent | +----------+------------+ | 1 | 2010-03-03 | | 6 | 2010-04-24 | +----------+------------+ 2 rows in set (0.00 sec) but what about the one above that gave an error? thanks.

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  • Reliable Storage Systems for SQL Server

    By validating the IO path before commissioning the production database system, and performing ongoing validation through page checksums and DBCC checks, you can hopefully avoid data corruption altogether, or at least nip it in the bud. If corruption occurs, then you have to take the right decisions fast to deal with it. Rod Colledge explains how a pessimistic mindset can be an advantage

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  • Download files with NSURL

    - by Ishwar
    I am trying to download a list of files from a ftp server using: NSURL *ftpUrl = [NSURL URLWithString:@"ftp://xxx:[email protected]"]; I HAVE to use FTP, so please do not recommend an alternative. I want to know how to get the list of files from the root directory and also navigate inside folders (of FTP server). P.S: I do not think external library would be required to accomplish such an easy task, but if I must, any recommendations would be appreciated. Thank You :)

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  • SQL: Getting the full record with the highest count.

    - by sqlnoob
    I'm trying to write sql that produces the desired result from the data below. data: ID Num Opt1 Opt2 Opt3 Count 1 A A E 1 1 A B J 4 2 A A E 9 3 B A F 1 3 B C K 14 4 A A M 3 5 B D G 5 6 C C E 13 6 C C M 1 desired result: ID Num Opt1 Opt2 Opt3 Count 1 A B J 4 2 A A E 9 3 B C K 14 4 A A M 3 5 B D G 5 6 C C E 13 Essentially I want, for each ID Num, the full record with the highest count. I tried doing a group by, but if I group by Opt1, Opt2, Opt3, this doesn't work because it returns the highest count for each (ID Num, Opt2, Opt3, Opt4) combination which is not what I want. If I only group by ID Num, I can get the max for each ID Num but I lose the information as to which (Opt1, Opt2, Opt3) combination gives this count. I feel like I've done this before, but I don't often work with sql and I can't remember how. Is there an easy way to do this?

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