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  • iPad web app: Prevent input focus AFTER ajax call

    - by Mike Barwick
    So I've read around and can't for the life of me figure out of to solve my issue effectively. In short, I have a web app built for the iPad - which works as it should. However, I have an Ajax form which also submits as it should. But, after the callback and I clear/reset my form, the "iPad" automatically focuses on an input and opens the keyboard again. This is far from ideal. I managed to hack my way around it, but it's still not perfect. The code below is run on my ajax callback, which works - except there's still a flash of the keyboard quickly opening and closing. Note, my code won't work unless I use setTimeout. Also, from my understanding, document.activeElement.blur(); only works when there's a click event, so I triggered one via js. IN OTHER WORDS, HOW DO I PREVENT THE KEYBOARD FROM REOPENING AFTER AJAX CALL ON WEB APP? PS: Ajax call works fine and doesn't open the keyboard in Safari on the iPad, just web app mode. Here's my code: hideKeyboard: function () { // iOS web app only, iPad IS_IPAD = navigator.userAgent.match(/iPad/i) != null; if (IS_IPAD) { $(window).one('click', function () { document.activeElement.blur(); }); setTimeout(function () { $(window).trigger('click'); }, 500); } } Maybe it's related to how I'm clearing my forms, so here's that code. Note, all inputs have tabindex="-1" as well. clearForm: function () { // text, textarea, etc $('#campaign-form-wrap > form')[0].reset(); // checkboxes $('input[type="checkbox"]').removeAttr('checked'); $('#campaign-form-wrap > form span.custom.checkbox').removeClass('checked'); // radio inputs $('input[type="radio"]').removeAttr('checked'); $('#campaign-form-wrap > form span.custom.radio').removeClass('checked'); // selects $('form.custom .user-generated-field select').each(function () { var selection = $(this).find('option:first').text(), labelFor = $(this).attr('name'), label = $('[for="' + labelFor + '"]'); label.find('.selection-choice').html(selection); }); optin.hideKeyboard(); }

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  • A two player game over the intranet..

    - by Santwana
    Hi everybody.. I am a student of 3rd year engineering and only a novice in my programming skills. I need some help with my project.. I wish to develop a two player game to be played over the network (Intranet). I want to develop a simple website with a few html pages for this.My ideas for the project run as follows: 1.People can log in from different systems and check who ever is online on the network currently. the page also shows who is playing with whom. 2.If a person is interested in playing with a player who is currently online, he sends a request of which the other player is somehow notified( using a message or an alert on his profile page..) 3.If the player accepts the request, a game is started. This is exactly where I am clueless.. How can I make them play the game? I need to develop a turn based game with two players, eg chessboard.. how can I do this? The game has to be played live.. and it is time tracked. i need your help with coding the above.. the other features i wish to include are: 4.The game could not be abruptly terminated by any one if the users.The request to terminate the game should be sent to the other player first and only if he accepts can the game be terminated. Whoever wins the game would get a plus 10 on their credit and if he terminated he gets a minus 10. The credits remains constant even if he loses but the success percentage is reduced. 6.The player with highest winning percentage is projected as the player of the week on the home page and he can post a challenge to all others.. I only have an intermediate knowledge of core java and know the basics of Swing and Awt. I am not at all familiar with networking in java right now. I have 5 to 6 weeks of time for developing the project but I hope to learn the things before I start my project. i would prefer to use a lan to illustrate the project and I know only java,jsp,oracle,html and bit of xml to develop my proj. Also I wish to know if I can code this within 6 weeks, would it be too difficult or complicated? Please spare some time to tell me. Please.. please.. I need your suggestions and help.. thank you so much..

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  • How to use sound and images in a Java applet?

    - by Click Upvote
    Question 1: How should I structure my project so the sound and images files can be loaded most easily? Right now, I have the folder: C:\java\pacman with the sub-directory C:\java\pacman\src containing all the code, and C:\java\pacman\assets containing the images and .wav files. Is this the best structure or should I put the assets somewhere else? Question 2: What's the best way to refer to the images/sounds without using the full path e.g C:\java\pacman\assets\something.png to them? If I use the getCodeBase() function it seems to refer to the C:\java\pacman\bin instead of C:\java\pacman\. I want to use such a function/class which would work automatically when i compile the applet in a jar as well as right now when I test the applet through eclipse. Question 3: How should I load the images/sounds? This is what I'm using now: 1) For general images: import java.awt.Image; public Image getImg(String file) { //imgDir in this case is a hardcoded string containing //"C:\\java\\pacman\\assets\\" file=imgDir + file; return new ImageIcon(file).getImage(); } The images returned from this function are used in the drawImage method of the Graphics class in the paint method of the applet. 2) For a buffered image, which is used to get subImages and load sprites from a sprite sheet: public BufferedImage getSheet() throws IOException { return ImageIO.read(new File(img.getPath("pacman-sprites.png"))); } Later: public void loadSprites() { BufferedImage sheet; try { sheet=getSheet(); redGhost.setNormalImg(sheet.getSubimage(0, 60, 20, 20)); redGhost.setUpImg(sheet.getSubimage(0, 60, 20, 20)); redGhost.setDownImg(sheet.getSubimage(30, 60, 20, 20)); redGhost.setLeftImg(sheet.getSubimage(30, 60, 20, 20)); redGhost.setRightImg(sheet.getSubimage(60, 60, 20, 20)); } catch (IOException e) { System.out.println("Couldnt open file!"); System.out.println(e.getLocalizedMessage()); } } 3) For sound files: import sun.audio.*; import java.io.*; public synchronized void play() { try { InputStream in = new FileInputStream(filename); AudioStream as = new AudioStream(in); AudioPlayer.player.start(as); } catch (IOException e) { e.printStackTrace(); } }

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  • RIM blackberry Record 3GP video

    - by pankaj_shukla
    Hi All, I am writing an application that can record a 3GP video. I have tried both MMAPI and Invoke API. But have following issues. Using MMAPI: 1. When I record to stream, It records video in RIMM streaming format. when I try to play this video player gives error "Unsupported media format.". 2. When I record to a file. It will create a file of size 0. Using Invoke API: 1. In MMS mode it does not allow to record a video more than 30 seconds. 2. In Normal mode size of the file is very large. 3. Once I invoke camera application I do not have any control on application. Here is my source code: _player = javax.microedition.media.Manager .createPlayer("capture://video?encoding=video/3gpp&mode=mms"); // I have tried every encoding returns from System.getProperty("video.encodings") method _player.realize(); _videoControl = (VideoControl) _player.getControl("VideoControl"); _recordControl = (RecordControl) _player.getControl("RecordControl"); _volumeControl = (VolumeControl) _player.getControl("VolumeControl"); String videoPath = System.getProperty("fileconn.dir.videos"); if (videoPath == null) { videoPath = "file:///store/home/user/videos/"; } _recordControl.setRecordLocation(videoPath + "RecordedVideo.3gp"); _player.addPlayerListener(this); Field videoField = (Field) _videoControl.initDisplayMode( VideoControl.USE_GUI_PRIMITIVE, "net.rim.device.api.ui.Field"); _videoControl.setVisible(true); add(videoField); _player.start(); ON start menu item Selection: try { _recordControl.startRecord(); } catch (Exception e) { _player.close(); showAlert(e.getClass() + " " + e.getMessage()); } On stop menuItem selection: try { _recordControl.commit(); } catch (Exception e) { _player.close(); showAlert(e.getClass() + " " + e.getMessage()); } Please let me if I am doing something wrong. Thanks, Pankaj

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  • How to manipulate file paths intelligently in .Net 3.5?

    - by Hamish Grubijan
    Scenario: I am maintaining a function which helps with an install - copies files from PathPart1/pending_install/PathPart2/fileName to PathPart1/PathPart2/fileName. It seems that String.Replace() and Path.Combine() do not play well together. The code is below. I added this section: // The behavior of Path.Combine is weird. See: // http://stackoverflow.com/questions/53102/why-does-path-combine-not-properly-concatenate-filenames-that-start-with-path-dir while (strDestFile.StartsWith(@"\")) { strDestFile = strDestFile.Substring(1); // Remove any leading backslashes } Debug.Assert(!Path.IsPathRooted(strDestFile), "This will make the Path.Combine(,) fail)."); in order to take care of a bug (code is sensitive to a constant @"pending_install\" vs @"pending_install" which I did not like and changed (long story, but there was a good opportunity for constant reuse). Now the whole function: //You want to uncompress only the files downloaded. Not every file in the dest directory. private void UncompressFiles() { string strSrcDir = _application.Client.TempDir; ArrayList arrFiles = new ArrayList(); GetAllCompressedFiles(ref arrFiles, strSrcDir); IEnumerator enumer = arrFiles.GetEnumerator(); while (enumer.MoveNext()) { string strDestFile = enumer.Current.ToString().Replace(_application.Client.TempDir, String.Empty); // The behavior of Path.Combine is weird. See: // http://stackoverflow.com/questions/53102/why-does-path-combine-not-properly-concatenate-filenames-that-start-with-path-dir while (strDestFile.StartsWith(@"\"")) { strDestFile = strDestFile.Substring(1); // Remove any leading backslashes } Debug.Assert(!Path.IsPathRooted(strDestFile), "This will make the Path.Combine(,) fail)."); strDestFile = Path.Combine(_application.Client.BaseDir, strDestFile); strDestFile = strDestFile.Replace(Path.GetExtension(strDestFile), String.Empty); ZSharpLib.ZipExtractor.ExtractZip(enumer.Current.ToString(), strDestFile); FileUtility.DeleteFile(enumer.Current.ToString()); } } Please do not laugh at the use of ArrayList and the way it is being iterated - it was pioneered by a C++ coder during a .Net 1.1 era. I will change it. What I am interested in: what is a better way of replacing PathPart1/pending_install/PathPart2/fileName with PathPart1/PathPart2/fileName within the current code. Note that _application.Client.TempDir is just _application.Client.BaseDir + @"\pending_install". While there are many ways to improve the code, I am mainly concerned with the part which has to do with String.Replace(...) and Path.Combine(,). I do not want to make changes outside of this function. I wish Path.Combine(,) took an optional bool flag, but it does not. So ... given my constraints, how can I rework this so that it starts to suck less?

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  • Validate dependent model validation and show error message.

    - by piemesons
    Just taking a simple example. We have a question on stackoverflow and while posting a question we want to validate title_of_question, description_of_question that they should be present. Now we have a another model tag having habtm relationshio with question model. How to validate that while saving the question. Means question must have some tags. here the code:-- Models:-- class Question < ActiveRecord::Base belongs_to :user has_and_belongs_to_many :tags has_many :comments, :as => :commentable has_many :answers, :dependent => :destroy validates_presence_of :title, :content, :user_id end class Tag < ActiveRecord::Base has_and_belongs_to_many :questions validates_presence_of :tag end Form for entering question and tag <div class="form"> <% form_for :question ,@question, :url => {:action => "create" } do |f| %> <fieldset> <%= f.error_messages %> <legend>Post a question</legend> <div> <%= f.label :title %>: <%= f.text_field :title, :size => 100 %> </div> <div> <%= f.label :content ,'Question' %>: <%= f.text_area :content, :rows => 10, :cols => 100 %> </div> <div> <%= label_tag 'tags' %>: <%= text_field_tag 'tag' ,'',:size=> 60 %> add multiple tag using comma </div> <div> <%= submit_tag "Post question" %> </div> </fieldset> <% end %> </div> From Controller.. (Right now question will be saved without validating tag) def create @question = Question.new(params[:question]) @question.user_id=session[:user_id] if @question.save flash[:notice] = "Question has been posted." redirect_to question_index_path else render :action => "new" end end questions_tags table has been created. One approach is creating a virtual column using attribute accessors. another approach is validate associated. right now assuming new tags can be created.(but not duplicate).

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  • unrecognized selector sent to instance while trying to add an object to a mutable array

    - by madpoet
    I'm following the "Your Second iOS App" and I decided to play with the code to understand Objective C well... What I'm trying to do is simply adding an object to a mutable array in a class. Here are the classes: BirdSighting.h #import <Foundation/Foundation.h> @interface BirdSighting : NSObject @property (nonatomic, copy) NSString *name; @property (nonatomic, copy) NSString *location; @property (nonatomic, copy) NSDate *date; -(id) initWithName: (NSString *) name location:(NSString *) location date:(NSDate *) date; @end BirdSighting.m #import "BirdSighting.h" @implementation BirdSighting -(id) initWithName:(NSString *)name location:(NSString *)location date:(NSDate *)date { self = [super init]; if(self) { _name = name; _location = location; _date = date; return self; } return nil; } @end BirdSightingDataController.h #import <Foundation/Foundation.h> @class BirdSighting; @interface BirdSightingDataController : NSObject @property (nonatomic, copy) NSMutableArray *masterBirdSightingList; - (NSUInteger) countOfList; - (BirdSighting *) objectInListAtIndex: (NSUInteger) theIndex; - (void) addBirdSightingWithSighting: (BirdSighting *) sighting; @end BirdSightingDataController.m #import "BirdSightingDataController.h" @implementation BirdSightingDataController - (id) init { if(self = [super init]) { NSMutableArray *sightingList = [[NSMutableArray alloc] init]; self.masterBirdSightingList = sightingList; return self; } return nil; } -(NSUInteger) countOfList { return [self.masterBirdSightingList count]; } - (BirdSighting *) objectInListAtIndex: (NSUInteger) theIndex { return [self.masterBirdSightingList objectAtIndex:theIndex]; } - (void) addBirdSightingWithSighting: (BirdSighting *) sighting { [self.masterBirdSightingList addObject:sighting]; } @end And this is where I'm trying to add a BirdSighting instance to the mutable array: #import "BirdsMasterViewController.h" #import "BirdsDetailViewController.h" #import "BirdSightingDataController.h" #import "BirdSighting.h" @implementation BirdsMasterViewController - (void)awakeFromNib { [super awakeFromNib]; BirdSightingDataController *dataController = [[BirdSightingDataController alloc] init]; NSDate *date = [NSDate date]; BirdSighting *sighting = [[[BirdSighting alloc] init] initWithName:@"Ebabil" location:@"Ankara" date: date]; [dataController addBirdSightingWithSighting: sighting]; NSLog(@"dataController: %@", dataController.masterBirdSightingList); self.dataController = dataController; } .......... @end It throws NSInvalidArgumentException in BirdSightingDataController addBirdSightingWithSighting method... What am I doing wrong?

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  • Error #1009 Cannot access a property or method of a null object reference.

    - by user288920
    Hey everyone, I'm trying to import an external SWF with a scrollbar, calling out to an external .AS, into my main SWF. Someone told me, it's an issue that my scrollbar isn't instantiated yet, but stopped short of helping me how to fix the problem. Here's the error below: TypeError: Error #1009: Cannot access a property or method of a null object reference. at Scrollbar/init() at Sample2_fla::MainTimeline/scInit() at flash.display::DisplayObjectContainer/addChild() at Sample2_fla::MainTimeline/frame1() On my main SWF, I was to click a button and load my external SWF. I want to then click another button in the external SWF and reveal my scrollbar (alpha=1;). The scrollbar is the issue. Here's my script: Sample1.swf (main) this.addEventListener(MouseEvent.CLICK, clickListener); var oldSection=null; function clickListener(evt:Event) { if (evt.target.name=="button_btn") { loadSection("Sample2.swf"); } } function loadSection(filePath:String) { var url:URLRequest=new URLRequest(filePath); var ldr:Loader = new Loader(); ldr.contentLoaderInfo.addEventListener(Event.COMPLETE, sectionLoadedListener); ldr.load(url); } function sectionLoadedListener(evt:Event) { var section=evt.target.content; if (oldSection) { removeChild(oldSection); } oldSection=section; addChild(section); section.x=0; section.y=0; } Sample2.SWF (external): import com.greensock.*; import com.greensock.easing.*; import com.greensock.plugins.*; scroll_mc.alpha=0; import Scrollbar; var sc:Scrollbar=new Scrollbar(scroll_mc.text,scroll_mc.maskmc,scroll_mc.scrollbar.ruler,scroll_mc.scrollbar.background,scroll_mc.area,true,6); sc.addEventListener(Event.ADDED, scInit); addChild(sc); function scInit(e:Event):void { sc.init(); } button2_btn.addEventListener(MouseEvent.CLICK, clickListener); function clickListener(evt:MouseEvent){ TweenMax.to(this.scroll_mc, 1,{alpha:1}); } I really appreciate your help. Cheers!

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  • Swing: does DefaultBoundedRangeModel coalesce multiple events?

    - by Jason S
    I have a JProgressBar displaying a BoundedRangeModel which is extremely fine grained and I was concerned that updating it too often would slow down my computer. So I wrote a quick test program (see below) which has a 10Hz timer but each timer tick makes 10,000 calls to microtick() which in turn increments the BoundedRangeModel. Yet it seems to play nicely with a JProgressBar; my CPU is not working hard to run the program. How does JProgressBar or DefaultBoundedRangeModel do this? They seem to be smart about how much work it does to update the JProgressBar, so that as a user I don't have to worry about updating the BoundedRangeModel's value. package com.example.test.gui; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.BoundedRangeModel; import javax.swing.DefaultBoundedRangeModel; import javax.swing.JFrame; import javax.swing.JPanel; import javax.swing.JProgressBar; import javax.swing.Timer; public class BoundedRangeModelTest1 extends JFrame { final private BoundedRangeModel brm = new DefaultBoundedRangeModel(); final private Timer timer = new Timer(100, new ActionListener() { @Override public void actionPerformed(ActionEvent arg0) { tick(); } }); public BoundedRangeModelTest1(String title) { super(title); JPanel p = new JPanel(); p.add(new JProgressBar(this.brm)); getContentPane().add(p); this.brm.setMaximum(1000000); this.brm.setMinimum(0); this.brm.setValue(0); } protected void tick() { for (int i = 0; i < 10000; ++i) { microtick(); } } private void microtick() { this.brm.setValue(this.brm.getValue()+1); } public void start() { this.timer.start(); } static public void main(String[] args) { BoundedRangeModelTest1 f = new BoundedRangeModelTest1("BoundedRangeModelTest1"); f.pack(); f.setVisible(true); f.setDefaultCloseOperation(EXIT_ON_CLOSE); f.start(); } }

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  • ActionScript 2: Event doesn't fire?

    - by Pascal Schuster
    So I have a soundHandler class that's supposed to play sounds and then point back to a function on the timeline when the sound has completed playing. But somehow, only one of the sounds plays when I try it out. EDIT: After that sound plays, nothing happens, even though I have EventHandlers set up that are supposed to do something. Here's the code: import mx.events.EventDispatcher; class soundHandler { private var dispatchEvent:Function; public var addEventListener:Function; public var removeEventListener:Function; var soundToPlay; var soundpath:String; var soundtype:String; var prefix:String; var mcname:String; public function soundHandler(soundpath:String, prefix:String, soundtype:String, mcname:String) { EventDispatcher.initialize(this); _root.createEmptyMovieClip(mcname, 1); this.soundpath = soundpath; this.soundtype = soundtype; this.prefix = prefix; this.mcname = mcname; } function playSound(file, callbackfunc) { _root.soundToPlay = new Sound(_root.mcname); _global.soundCallbackfunc = callbackfunc; _root.soundToPlay.onLoad = function(success:Boolean) { if (success) { _root.soundToPlay.start(); } }; _root.soundToPlay.onSoundComplete = function():Void { trace("Sound Complete: "+this.soundtype+this.prefix+this.file+".mp3"); trace(arguments.caller); dispatchEvent({type:_global.soundCallbackfunc}); trace(this.toString()); trace(this.callbackfunction); }; _root.soundToPlay.loadSound("../sound/"+soundpath+"/"+soundtype+prefix+file+".mp3", true); _root.soundToPlay.stop(); } } Here's the code from the .fla file: var playSounds:soundHandler = new soundHandler("signup", "su", "s", "mcs1"); var file = "000"; playSounds.addEventListener("sixtyseconds", this); playSounds.addEventListener("transition", this); function sixtyseconds() { trace("I am being called! Sixtyseconds"); var phase = 1; var file = random(6); if (file == 0) { file = 1; } if (file<10) { file = "0"+file; } file = phase+file; playSounds.playSound(file, "transition"); } function transition() { trace("this works"); } playSounds.playSound(file, "sixtyseconds"); I'm at a total loss for this one. Have been wasting hours to figure it out already. Any help will be deeply appreciated.

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  • IE sends multiple cookies with same name?

    - by akach
    I have a strange bug that occurs in IE7/XP and IE8/Vista on my website. IE sends two cookies named PHPSESSID. How to reproduce: Clear cookies in IE (not necessary if you never visited unisender.com). Visit unisender.com (exactly without www to reproduce!) and it will redirect to www.unisender.com Login with any valid username and password (I've registered username testmsdn with password testmsdn - feel free to use for testing) Run your favourite capture-the-traffic program (I prefer wireshark) Now click any menu link (e.g. "messages") Look at captured traffic - you will see that IE sends double PHPSESSID cookie (and you are logged out after click because of this). It seems like first PHPSESSID is from unisender.com and second from www.unisender.com. Captured sample: GET /en/letter_list HTTP/1.1 Accept: image/gif, image/jpeg, image/pjpeg, application/x-ms-application, application/vnd.ms-xpsdocument, application/xaml+xml, application/x-ms-xbap, application/x-shockwave-flash, / Referer: http://www.unisender.com/en/intro Accept-Language: ru User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.0; Trident/4.0; Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1) ; SLCC1; .NET CLR 2.0.50727; .NET CLR 3.5.21022; .NET CLR 3.5.30729; FDM; .NET CLR 3.0.30729) Accept-Encoding: gzip, deflate Host: www.unisender.com Connection: Keep-Alive Cookie: authchallenge=3a9cfcfc9fe33822e3e21d75c8a3d3e4; PHPSESSID=14ea1cb133632951592397c86eaf037e; us_reg_ref=unknown; us_reg_url=http%3A%2F%2Funisender.com%2F; __utma=1.778517853.1271204400.1271204400.1271204400.1; __utmb=1.3.10.1271204400; __utmc=1; __utmz=1.1271204400.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none); PHPSESSID=65e110aeb995a66b9dc8da5656c7a3da; last_login_name=testmsdn I've tried to use session and non-session cookies, tried to use .unisender.com instead of unisender.com for cookie - nothing helps. I suppose there should not be cookies with same name. Am I right? Is it a bug in IE? If it's a bug then is there a workaround? Or am I wrong and it's an expected behavior?

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  • Controlling the USB from Windows

    - by b-gen-jack-o-neill
    Hi, I know this probably is not the easiest thing to do, but I am trying to connect Microcontroller and PC using USB. I dont want to use internal USART of Microcontroller or USB to RS232 converted, its project indended to help me understand various principles. So, getting the communication done from the Microcontroller side is piece of cake - I mean, when I know he protocol, its relativelly easy to implement it on Micro, becouse I am in direct control of evrything, even precise timing. But this is not the case of PC. I am not very familiar with concept of Windows handling the devices connected. In one of my previous question I ask about how Windows works with devices thru drivers. I understood that for internal use of Windows, drivers must have some default set of functions available to OS. I mean, when OS wants to access HDD, it calls HDD driver (which is probably internal in OS), with specific "questions" so that means that HDD driver has to be written to cooperate with Windows, to have write function in the proper place to be called by the OS. Something similiar is for GPU, Even DirectX, I mean DirectX must call specific functions from drivers, so drivers must be written to work with DX. I know, many functions from WinAPI works on their own, but even "simple" window must be in the end written into framebuffer, using MMIO to adress specified by drivers. Am I right? So, I expected that Windows have internal functions, parts of WinAPI designed to work with certain comonly used things. To call manufacturer-designed drivers. But this seems to not be entirely true becouse Windows has no way to communicate thru Paralel port. I mean, there is no function in the WinAPI to work with serial port, but there are funcions to work with HDD,GPU and so. But now there comes the part I am getting very lost at. So, I think Windows must have some built-in functions to communicate thru USB, becouse for example it handles USB flash memory. So, is there any WinAPI function designed to let user to operate USB thru that function, or when I want to use USB myself, do I have to call desired USB-driver function myself? Becouse all you need to send to USB controller is device adress and the infromation right? I mean, I don´t have to write any new drivers, am I right? Just to call WinAPI function if there is such, or directly call original USB driver. Does any of this make some sense?

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  • Android - dialer icon gets placed in recently used apps after finish()

    - by Donal Rafferty
    In my application I detect the out going call when a call is dialled from the dialer or contacts. This works fine and I then pop up a dialog saying I have detected the call and then the user presses a button to close the dialog which calls finish() on that activity. It all works fine except that when I then hold the home key to bring up the recently used apps the dialer icon is there. And when it is clicked the dialog is brought back into focus in the foreground when the dialog activity should be dead and gone and not be able to be brought back to the foreground. Here is a picture of what I mean. So two questions arise, why would the dialer icon be getting placed there and why would it be recalling my activity to the foreground? Here is the code for that Activity which has a dialog theme: public class CallDialogActivity extends Activity{ boolean isRecording; AudioManager audio_service; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.dialog); audio_service = (AudioManager) getSystemService(Context.AUDIO_SERVICE); getWindow().addFlags(WindowManager.LayoutParams.FLAG_BLUR_BEHIND); Bundle b = this.getIntent().getExtras(); String number = b.getString("com.networks.NUMBER"); String name = b.getString("com.networks.NAME"); TextView tv = (TextView) findViewById(R.id.voip) ; tv.setText(name); Intent service = new Intent(CallAudio.CICERO_CALL_SERVICE); startService(service); final Button stop_Call_Button = (Button) findViewById(R.id.widget35); this.setVolumeControlStream(AudioManager.STREAM_VOICE_CALL); stop_Call_Button.setOnClickListener(new View.OnClickListener(){ public void onClick(View v){ Intent service = new Intent(CallAudio._CALL_SERVICE); //this is for Android 1.5 (sets speaker going for a few seconds before shutting down) stopService(service); Intent setIntent = new Intent(Intent.ACTION_MAIN); setIntent.addCategory(Intent.CATEGORY_HOME); setIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivity(setIntent); finish(); isRecording = false; } }); final Button speaker_Button = (Button) findViewById(R.id.widget36); speaker_Button.setOnClickListener(new View.OnClickListener(){ public void onClick(View v){ if(true){ audio_service.setSpeakerphoneOn(false); } else{ audio_service.setSpeakerphoneOn(true); } } }); } @Override protected void onResume() { super.onResume(); } @Override protected void onPause() { super.onPause(); } public void onCofigurationChanged(Configuration newConfig) { super.onConfigurationChanged(newConfig); } } It calls a service that uses AudioRecord to record from the Mic and AudioTrack to play it out the earpiece, nothing in the service to do with the dialler. Has anyone any idea why this might be happening?

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  • Need MYSQL query for finding lowest score per game player

    - by Chris Barnhill
    I have a game on Facebook called Rails Across Europe. I have a Best Scores page where I show the players with the best 20 scores, which in game terms refers to the lowest winning turn. The problem is that there are a small number of players who play frequently, and their scores dominate the page. I'd like to make the scores page open to more players. So I thought that I could display the single lowest winning turn for each player instead of displaying all of the lowest winning turns for all players. The problem is that the query for this eludes me. So I hope that one of you brilliant StackOverflow folks can help me with this. I have included the relevant MYSQL table schemas below. Here are the the table relationships: player_stats contains statistics for either a game in progress or a completed game. If a game is in progress, winning_turn is zero (which means that games with a winning_turn of zero should not be included in the query). player_stats has a game_player table id reference. game_player contains data describing games currently in progress. game_player has a player table id reference. player contains data describing a person who plays the game. Here's the query I'm currently using: 'SELECT p.fb_user_id, ps.winning_turn, gp.difficulty_level, c.name as city_name, g.name as goods_name, d.cost FROM game_player as gp, player as p, player_stats as ps, demand as d, city as c, goods as g WHERE p.status = "ACTIVE" AND gp.player_id = p.id AND ps.game_player_id = gp.id AND d.id = ps.highest_demand_id AND c.id = d.city_id AND g.id = d.goods_id AND ps.winning_turn > 0 ORDER BY ps.winning_turn ASC, d.cost DESC LIMIT '.$limit.';'; Here are the relevant table schemas: -- -- Table structure for table `player_stats` -- CREATE TABLE IF NOT EXISTS `player_stats` ( `id` int(11) NOT NULL auto_increment, `game_player_id` int(11) NOT NULL, `winning_turn` int(11) NOT NULL, `highest_demand_id` int(11) NOT NULL, PRIMARY KEY (`id`), KEY `game_player_id` (`game_player_id`,`highest_demand_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `game_player` -- CREATE TABLE IF NOT EXISTS `game_player` ( `id` int(10) unsigned NOT NULL auto_increment, `game_id` int(10) unsigned NOT NULL, `player_id` int(10) unsigned NOT NULL, `player_number` int(11) NOT NULL, `funds` int(10) unsigned NOT NULL, `turn` int(10) unsigned NOT NULL, `difficulty_level` enum('STANDARD','ADVANCED','MASTER','ULTIMATE') NOT NULL, `date_last_used` datetime NOT NULL, PRIMARY KEY (`id`), KEY `game_id` (`game_id`,`player_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=3814 ; -- -- Table structure for table `player` -- CREATE TABLE IF NOT EXISTS `player` ( `id` int(11) NOT NULL auto_increment, `fb_user_id` char(255) NOT NULL, `fb_proxied_email` text NOT NULL, `first_name` char(255) NOT NULL, `last_name` char(255) NOT NULL, `birthdate` date NOT NULL, `date_registered` datetime NOT NULL, `date_last_logged_in` datetime NOT NULL, `status` enum('ACTIVE','SUSPENDED','CLOSED') NOT NULL, PRIMARY KEY (`id`), KEY `fb_user_id` (`fb_user_id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=1646 ;

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  • video player for HTML 5 page not loading

    - by philippe
    I'm using VideoJS to as my video player for a project I've been working on. Basically I have a div, and I wanted to have the video player within that div, however when I load the page nothing happens, and the video is never played. In fact, the video is never loaded nor shown in the page. I basically copied the example from VideoJS' page. Any thoughts? <div class="video-js-box"> <!-- Using the Video for Everybody Embed Code http://camendesign.com/code/video_for_everybody --> <div style="position: absolute; top: 50px; left: 600px; display:none"> <video id="example_video_1" class="video-js vjs-default-skin" controls preload="auto" width="640" height="264" poster="http://video-js.zencoder.com/oceans-clip.png" data-setup='{"example_option":true}'> <source src="http://video-js.zencoder.com/oceans-clip.mp4" type='video/mp4'></source> <source src="http://video-js.zencoder.com/oceans-clip.webm" type='video/webm'>></source> <source src="http://video-js.zencoder.com/oceans-clip.ogv" type='video/ogg'></source> </video> <!-- Download links provided for devices that can't play video in the browser. --> <p class="vjs-no-video"><strong>Download Video:</strong> <a href="http://video-js.zencoder.com/oceans-clip.mp4">MP4</a>, <a href="http://video-js.zencoder.com/oceans-clip.webm">WebM</a>, <a href="http://video-js.zencoder.com/oceans-clip.ogv">Ogg</a><br> <!-- Support VideoJS by keeping this link. --> <a href="http://videojs.com">HTML5 Video Player</a> by VideoJS </p> </div> <div style="clear:both;"></div> </div><!--main-->

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  • Illegal Start of Expression

    - by Kraivyne
    Hello there, I have just started to learn the very basics of Java programming. Using a book entitled "Programming Video Games for the Evil Genius". I have had an Illegal Start of Expression error that I can't for the life of me get rid of. I have checked the sample code from the book and mine is identical. The error is coming from the for(int i = difficulty; i = 0; i- - ) line. Thanks for helping a newbie out. import javax.swing.*; public class S1P4 {public static void main(String[] args) throws Exception { int difficulty; difficulty = Integer.parseInt(JOptionPane.showInputDialog("How good are you?\n"+ "1 = Great\n"+"10 = Terrible")); boolean cont = false; do { cont = false; double num1 = (int)(Math.round(Math.random()*10)); double num2; do { num2 = (int)(Math.round(Math.random()*10)); } while(num2==0.0); int sign = (int)(Math.round(Math.random()*3)); double answer; System.out.println("\n\n*****"); if(sign==0) { System.out.println(num1+" times "+num2); answer = num1*num2; } else if(sign==1) { System.out.println(num1+" divided by"+num2); answer = num1/num2; } else if(sign==1) { System.out.println(num1+" plus "+num2); answer = num1+num2; } else if(sign==1) { System.out.println(num1+" minus "+num2); answer = num1-num2; } else { System.out.println(num1+" % "+num2); answer = num1%num2; } System.out.println("*****\n"); for(int i = difficulty; i >= 0; i- - ) { System.out.println(i+"..."); Thread.sleep(500); } System.out.println("ANSWER: "+answer); String again; again = JOptionPane.showInputDialog("Play again?"); if(again.equals("yes")) cont = true; } while(cont); } }

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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  • Do While loop breaks after incorrect input?

    - by Daminkz
    I am trying to have a loop continue to prompt the user for an option. When I get a string of characters instead of an int, the program loops indefinitely. I have tried setting the variable result to NULL, clearing the input stream, and have enclosed in try{}catch blocks (not in this example). Can anyone explain to me why this is? #include <iostream> #include <vector> #include <string> using namespace std; int menu(string question, vector<string> options) { int result; cout << question << endl; for(int i = 0; i < options.size(); i++) { cout << '[' << i << ']' << options[i] << endl; } bool ans = false; do { cin >> result; cin.ignore(1000, 10); if (result < options.size() ) { ans = true; } else { cout << "You must enter a valid option." << endl; result = NULL; ans = false; } } while(!ans); return result; } int main() { string menuQuestion = "Welcome to my game. What would you like to do?"; vector<string> mainMenu; mainMenu.push_back("Play Game"); mainMenu.push_back("Load Game"); mainMenu.push_back("About"); mainMenu.push_back("Exit"); int result = menu(menuQuestion, mainMenu); cout << "You entered: " << result << endl; return 0; }

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  • jQuery .load(), don't show new content until images loaded

    - by Jarred
    Hi. I have been working on a jQuery photo slideshow. It scales the images to the browser size, and slides them left and right. There is no pre-determined size or aspect ratio, the script does everything on the fly. It requires that all images be fully loaded, so it can custom resize each individual image based on it's own aspect ratio ( width():height(), etc ), calculate the width of containing div, and calculate the slide distance from one image to another. As a stand-alone, it works pretty well (despite my lack of skills)! I simply hide the slideshow containing div at (document).ready, allow the images to load, then run the slideshow prep scripts at (window).load. Once this is done, it only then makes the slideshow divs, images, etc appear, properly sized, positioned and ready to roll. The ultimate goal is to be able to load in any number of slideshows without refreshing the page. The point of this is to be able to play uninterrupted background music. I know music on websites is annoying, but the target market likes it, a lot! I am using (target).load(page.php .element, function prepInsertNewShow() { //Prepare slideshow resizeImages(); slideArray(); //Show slideshow (target).fadeIn(); }); and it definitely works! The problem is that I cannot find a way to hold off on preparing and showing the new content until the images have finished loading. It is running the slideshow prep scripts (which are totally dependent on the images being fully loaded), before the images are loaded. This results in a completely jacked up show! What I want to do is this - (target).load(page.php .element, function prepInsertNewShow() { //Wait until images are loaded $('img').load( function() { //Prepare slideshow resizeImages(); slideArray(); //Show slideshow (target).fadeIn(); } }); But this doesn't seem to work, the new content is never shown. You can see a live version here. The initial gallery loads correctly, everything looks good. The only nav link that works is Galleries Engagement, which will load a new show (a containing div with multiple <img> tags). You will see that the images are not centered, the containing div and slide distances are much too small, as they were calculated using images that were not actually loaded. Is there any way I can delay handling and showing new content until it is fully loaded? Any suggestions would be most appreciated, thanks for your time! PS - It just occurred to me while typing this that a decent solution may be to insert "width=x" height="x" into the <img> tags, so the script can work from those values, even if the images have not loaded...hmm...

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  • My webpage ignores changes in CSS file

    - by Pavel
    No matter what I change in my .css file, the page remains the same - what's more, neither changing the link tag so that it points to another .css file nor deleting it completely makes no difference. Other changes in html code are applied. The sourcecode of the webpage shows everything as it should be. This behavior started when I redirected the link tag from previous file to the one I use now (plus there have been some changes in the tag while this problem occured, to test the behavior of my webpage); changes in neither file affect the page. For the first time when this happened, this was caused by copies of head tag in included chunks of code (for header, left menu etc. - their head part overrode the head part of the main page) and the problem was solved by removing these redundant heads from these files. But it happened again when I changed the link tag for the next time. I couldn't find any head parts in my included files, but the problem lasts (only solution I can see now is to delete the included files and copy the code directly to the file, but this would mean lots of redundant code). How can I solve this problem, so that my page response to changes in .css files without increasing redundancy? How to ensure that I can change the link to .css file just on one place with no such problems? Do I have to unload the CSS file somehow? I saw this problem both in Firefox and in Chrome. I use PSPad to write the code, just in case it would play role. EDIT: I have cleared browser cache now, and I changed the link to .css files from one to another before, but nothing helped. Now I accept the best answer saying the problem is in caching and I start a related question to find out how to solve the caching issue. If the other question's answers would say that in this case I can be sure that problem isn't in caching (very unlikely, but fail of ordinary methods of caching-problems-solving is unlikely too), I'd update this question and start searching for other possible problems, but now the message seems to be clear: when webpage ignores changes in .css files, caching is to blame.

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  • Query string problem if we use header

    - by avani-nature
    Hai frnds i am new to php actually i am facing following problems in coding please can anyone give the solution? Actually i am having one audio player and i am displaying some word dcoument if i click word document corresponding audio file should play actually when i click doc file it should pop ip with save as and open with for that i am using some header code also i am passing query string in the browser query string is not working if i use header can anyone give me a solution for it below is my code i am attaching <?php $f_name = $_POST["fn"]; $id = $_POST["id1"]; echo $id; //echo "../public_html/sites/default/files/ourfiles/$f_name"; $res2=db_query("select * from mt_files where id='".$id."' "); $row2=db_fetch_array($res2); $job_audio=$row2["audio_name"]; //echo $job_audio; //$job_audi=explode("/",$job_audio); //$job_audio=$job_audi[8]; $job_audio= "C:/xampp/htdocs/med/sites/default/files/audio/$job_audio"; //$job_audio= "C:/Documents and Settings/swuser/My Documents/$job_audio"; //echo $job_audio; echo "<object data='$job_audio' type='application/x-mplayer2' width='150' height='45'> <param name='src' value='$job_audio'> <param name='autoplay' value='true'> <param name='autoStart' value='1'> </object> "; $file = "../mts/sites/default/files/docs/$f_name"; if (file_exists($file)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename='.basename($file)); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . filesize($file)); ob_clean(); flush(); readfile($file); exit; } //The download table query goes here put the $f_name in insert into with the //time varible ?>

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  • Have main thread wait for a boost thread complete a task (but not finish).

    - by JAKE6459
    I have found plenty on making one thread wait for another to finish executing before continuing, but that is not what I wanted to do. I am not very familiar with using any multi-threading apis but right now I'm trying to learn boost. My situation is that I am using my main thread (the starting one from int main()) to create an instance of a class that is in charge of interacting with the main GUI. A class function is then called that creates a boost thread which in turn creates the GUI and runs the message pump. The thing I want to do is when my main thread calls the classes member function to create the GUI, I don't want that function to return until I tell it to from the newly created thread. This way my main thread can't continue and call more functions from the GUI class that interact with the GUI thread until that thread has completed GUI creation and entered the message loop. I think I may be able to figure it out if it was multiple boost thread objects interacting with each other, but when it is the main thread (non-boost object) interacting with a boost thread object, I get lost. Eventually I want a loop in my main thread to call a class function (among other tasks) to check if the user as entered any new input into the GUI (buy any changes detected by the message loop being updated into a struct and changing a bool to tell the main thread in the class function a change has occurred). Any suggestions for any of this would be greatly appreciated. This is the member function called by the main thread. int ANNGUI::CreateGUI() { GUIMain = new Main(); GUIThread = new boost::thread(boost::bind(&Main::MainThreadFunc, GUIMain)); return 0; }; This is the boost thread starting function. void Main::MainThreadFunc() { ANNVariables = new GUIVariables; WndProc = new WindowProcedure; ANNWindowsClass = new WindowsClass(ANNVariables, WndProc); ANNWindow = new MainWindow(ANNVariables); GUIMessagePump = new MessagePump; ANNWindow-ShowWindows(); while(true) { GUIMessagePump-ProcessMessage(); } }; BTW, everything compiles fine and when I run it, it works I just put a sleep() in the main thread so I can play with the GUI a little.

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  • Ajax posting to PHP

    - by JQonfused
    Hi guys, I'm testing a jQuery ajax post method on a local Apache 2.2 server with PHP 5.3 (totally new at this). Here are the files, all in the same folder. html body (jQuery library included in head): <form id="postForm" method="post"> <label for="name">Input Name</label> <input type="text" name="name" id="name" /><br /> <label for="age">Input Age</label> <input type="text" name="age" id="age" /><br /> <input type="submit" value="Submit" id="submitBtn" /> </form> <div id="resultDisplay"></div> <script src="queryRequest.js"></script> queryRequest.js $(document).ready(function(){ $('#s').focus(); $('#postForm').submit(function(){ var name = $('#name').val(); var age = $('#age').val(); var URL = "post.php"; $.ajax({ type:'POST', url: URL, datatype:'json', data:{'name': name ,'age': age}, success: function(data){ $('#resultDisplay').append("Value returned.<br />name: "+data.name+" age: "+data.age); }, error: function() { $('resultDisplay').append("ERROR!") } }); }); }); post.php <?php $name = $_POST['name']; $age = $_POST['age']; $return = array('name' => $name, 'age' => $age); echo json_encode($return); ?> After inputting the two fields and pressing 'Submit', the success method is called, text appended, but the values returned from ajax post are undefined. And then after less than a second, the text fields are emptied, and the text appended to the div is gone. Doesn't seem like it's a page refresh, though, since there's no empty page flash. What's going on here? I'm sure it's a silly mistake but Firebug isn't telling me anything.

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  • progress at work

    - by noopize
    I work in a small department in a very large company. Our department operates largely as a independent unit within the company. Each member of the team has a different role. My role within the team is a operations/admin and no one knew of my skills in programing as I never said anything before about it. I just did my work and in the free time read up on things for my own development Our developer who used to look after our websites has left a few months ago. Now when we require edits to our websites even basic HTML changes we outsource the work. We are getting shafted big time. I could of so said something sooner to highlight my skills in this area but I guess I was just happy to do my own development projects. And one reason was they are using asp.net and I have mainly done things in php. I only hinted before that I have done things but I did not want to reveal them before I had completed anything. I was working on something for myself that the company was also trying to implement something similar(e commerce site). I used open source and they decided to go for a propriety solution. Now I have finished my project and showed it to my boss, their project is still not completed and is quite expensive. He was impressed with what I showed him and suggested I should go for courses to learn asp.net. that I may be able to do the development work for them and there are some big upcoming projects in the future. He said this would be a benefit for me that I should look to be doing a better then role then admin. My employer does have a policy if relevent to the role they may support the costs of courses. Now how do I play this what should I say to my boss. I want to get advise on which MS certified courses would be good for asp.net and how to best approach my boss to see if they will pay all the amount for the course. And how much different will asp.net be from php.

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  • OCR anything with OneNote 2007 and 2010

    - by Matthew Guay
    Quality OCR software can often be very expensive, but you may have one already installed on your computer that you didn’t know about.  Here’s how you can use OneNote to OCR anything on your computer. OneNote is one of the overlooked gems in recent versions of Microsoft Office.  OneNote makes it simple to take notes and keep track of everything with integrated search, and offers more features than its popular competitor Evernote.  One way it is better is its high quality optical character recognition (OCR) engine.  One of Evernote’s most popular features is that you can search for anything, including text in an image, and you can easily find it.  OneNote takes this further, and instantly OCRs any text in images you add.  Then, you can use this text easily and copy it from the image.  Let’s see how this works and how you can use OneNote as the ultimate OCR. Please Note: This feature is available in OneNote 2007 and 2010.  OneNote 2007 is included with Office 2007 Home and Student, Enterprise, and Ultimate, while OneNote 2010 is included with all edition of Office 2010 except for Starter edition. OCR anything First, let’s add something to OCR into OneNote.  There are many different ways you can add items to OCR into OneNote.  Open a blank page or one you want to insert something into, and then follow these steps to add what you want into OneNote. Picture Simply drag-and-drop a picture with text into a notebook… You can insert a picture directly from OneNote as well.  In OneNote 2010, select the Insert tab, and then choose Picture. In OneNote 2007, select the Insert menu, select Picture, and then choose From File.   Screen Clipping There are many times we’d like to copy text from something we see onscreen, but there is no direct way to copy text from that thing.  For instance, you cannot copy text from the title-bar of a window, or from a flash-based online presentation.  For these cases, the Screen Clipping option is very useful.  To add a clip of anything onscreen in OneNote 2010, select the Insert tab in the ribbon and click Screen Clipping. In OneNote 2007, either click the Clip button on the toolbar or select the Insert menu and choose Screen Clipping.   Alternately, you can take a screen clipping by pressing the windows key + S. When you click Screen Clipping, OneNote will minimize, your desktop will fade lighter, and your mouse pointer will change to a plus sign.  Now, click and drag over anything you want to add to OneNote.  Here we’re selecting the title of this article. The section you selected will now show up in your OneNote notebook, complete with the date and time the clip was made. Insert a file You’re not limited to pictures; OneNote can even OCR anything in most files on your computer.  You can add files directly in OneNote 2010 by selecting File Printout in the Insert tab. In OneNote 2007, select the Insert menu and choose Files as Printout. Choose the file you want to add to OneNote in the dialog. Select Insert, and OneNote will pause momentarily as it processes the file. Now your file will show up in OneNote as a printout with a link to the original file above it. You can also send any file directly to OneNote via the OneNote virtual printer.  If you have a file open, such as a PDF, that you’d like to OCR, simply open the print dialog in that program and select the “Send to OneNote” printer. Or, if you have a scanner, you can scan documents directly into OneNote by clicking Scanner Printout in the Insert tab in OneNote 2010. In OneNote 2003, to add a scanned document select the Insert menu, select Picture, and then choose From Scanner or Camera. OCR the image, file, or screenshot you put in OneNote Now that you’ve got your stuff into OneNote, let’s put it to work.  OneNote automatically did an OCR scan on anything you inserted into OneNote.  You can check to make sure by right-clicking on any picture, screenshot, or file you inserted.  Select “Make Text in Image Searchable” and then make sure the correct language is selected. Now, you can copy text from the Picture.  Simply right-click on the picture, and select “Copy Text from Picture”. And here’s the text that OneNote found in this picture: OCR anything with OneNote 2007 and 2010 - Windows Live Writer Not bad, huh?  Now you can paste the text from the picture into a document or anywhere you need to use the text. If you are instead copying text from a printout, it may give you the option to copy text from this page or all pages of the printout.   This works the exact same in OneNote 2007. In OneNote 2010, you can also edit the text OneNote has saved in the image from the OCR.  This way, if OneNote read something incorrectly you can change it so you can still find it when you use search in OneNote.  Additionally, you can copy only a specific portion of the text from the edit box, so it can be useful just for general copying as well.  To do this, right-click on the item and select “Edit Alt Text”. Here is the window to edit alternate text.  If you want to copy only a portion of the text, simply select it and press Ctrl+C to copy that portion. Searching OneNote’s OCR engine is very useful for finding specific pictures you have saved in OneNote.  Simply enter your search query in the search box on top right, and OneNote will automatically find all instances of that term in all of your notebooks.  Notice how it highlights the search term even in the image! This works the same in OneNote 2007.  Notice how it highlighted “How-to” in a shot of the header image in our favorite website. In Windows Vista and 7, you can even search for things OneNote OCRed from the Start Menu search.  Here the start menu search found the words “Windows Live Writer” in our OCR Test notebook in OneNote where we inserted the screen clip above. Conclusion OneNote is a very useful OCR tool, and can help you capture text from just about anything.  Plus, since you can easily search everything you have stored in OneNote, you can quickly find anything you insert anytime.  OneNote is one of the least-used Office tools, but we have found it very useful and hope you do too. Similar Articles Productive Geek Tips Add or Remove Apps from the Microsoft Office 2007 or 2010 SuiteRemove Office 2010 Beta and Reinstall Office 2007How To Create and Publish Blog Posts in Word 2010 & 2007How To Copy Worksheets in Excel 2007 & 2010Add Page Numbers to Documents in Word 2007 & 2010 TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Using TrueCrypt to Secure Your Data Quickly Schedule Meetings With NeedtoMeet Share Flickr Photos On Facebook Automatically Are You Blocked On Gtalk? Find out Discover Latest Android Apps On AppBrain The Ultimate Guide For YouTube Lovers

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