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  • Query filter design for string field

    - by Midhat
    A field in my table can have arbitrary strings. On the UI, there is a drop down having options like All, Value1, Value2 And the results were filtered by the selected option value. So far this is easy and adding new filters to the UI is not a problem. Needs no changes in my stored procedure. Now I want to have an "Others" option here as well, which will return rows not having the column value as Value1 or Value2. Apparently this will require a "not in" operator in my query, and will make maintenance difficult, as the list of values is likely to change Any suggestions, design tips?

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  • Wrong logic in If Statement?

    - by Charles
    $repeat_times = mysql_real_escape_string($repeat_times); $result = mysql_query("SELECT `code`,`datetime` FROM `fc` ORDER by datetime desc LIMIT 25") or die(mysql_error()); $output .=""; $seconds = time() - strtotime($fetch_array["datetime"]); if($seconds < 60) $interval = "$seconds seconds"; else if($seconds < 3600) $interval = floor($seconds / 60) . " minutes"; else if($seconds < 86400) $interval = floor($seconds / 3600) . " hours"; else $interval = floor($seconds / 86400) . " days"; while ($fetch_array = mysql_fetch_array($result)) { $fetch_array["code"] = htmlentities($fetch_array["code"]); $output .= "<li><a href=\"http://www.***.com/code=" . htmlspecialchars(urlencode($fetch_array["code"])) . "\" target=\"_blank\">" . htmlspecialchars($fetch_array["code"]) . "</a> (" . $interval . ") ago.</li>"; } $output .=""; return $output; Why is this returning janice (14461 days) instead of janice (15 minutes ago) The datetime function table has the DATETIME type in my table so it's returning a full string for the date.

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  • How can I select a column with no values?

    - by Lye
    I have a table with thousands of rows and hundreds of columns (not my design). I'm trying to find out which columns are never used so I can simplify the table a little. How can I find which of the columns have no value in all rows?

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  • Select multi-select form from array

    - by Budove
    Here's the issue. I have a database column called pymnt_meth_pref, which contains a comma separated string of payment methods chosen from a multiselect form. <td>Payment Methods Used:<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Cash">I can pay with cash.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Check">I can pay by check.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Credit Card">I can pay by credit card.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Paypal">I can pay with Paypal.<br /> </td> This array is posted to a variable and turned into a comma separated string if (isset($_POST['pyment_meth_pref'])) $pymntmethpref = implode(", ", $_POST['pyment_meth_pref']); if (isset($_POST['pyment_meth_acc'])) $pymntmethacc = implode(", ", $_POST['pyment_meth_acc']); This is then inserted into the database as a comma separated string. What I would like to do, is take this string and apply the values to the original form when the user goes back to the form as 'pre-selected' checkboxes, indicated that the user has already selected those values previously, and keeping those values in the database if they choose to edit any other information in the form. I'm assuming this would need to be done with javascript but if there is a way to do it with PHP I'd rather do it that way.

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  • Insert error when sending post array to activerecord

    - by Gonzalo
    I am using CodeIgniter + phpActiveRecord. I am getting all the records from the $_POST array and I want to send that same array to my activeRecord class to insert the data into the DB. This line doesn't seem to be working but I can't get the error because the page is just blank: Car::create($this->input->post()); If the names of the fields are equal to the names of the columns in the table, should it what I pasted above work? ==========SOLVED======== It is possible to do it, and in the model of the object one can add var $name_of_the_field_which_you_don't_process = FALSE; And that's it.

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  • mysqli_query SELECT FROM WHERE [ partial match ] ?

    - by user296516
    Hi guys, I have a database that a time filed that is stored in this format "2010.06.04. | 18:53 01". What I need is to select rows that have a specific date, for example "2010.06.04." Right now I am doing it my first selecting all rows and then looping through them and adding ones with the specified date to a new array. Maybe there is an easier way to do it and I somehow can select it using mysqli_query? Thanks!

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  • Query returning related assets

    - by GMo
    I have 2 tables, one is an assets table which holds digital assets (e.g. article, images etc), the 2nd table is an asset_links table which maps 1-1 relationships between assets contained within the assets table. Here are the table definitions: Asset +---------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | source | varchar(255) | YES | | NULL | | | title | varchar(255) | YES | | NULL | | | date_created | datetime | YES | | NULL | | | date_embargo | datetime | YES | | NULL | | | date_expires | datetime | YES | | NULL | | | date_updated | datetime | YES | | NULL | | | keywords | varchar(255) | YES | | NULL | | | status | int(11) | YES | | NULL | | | priority | int(11) | YES | | NULL | | | fk_site | int(11) | YES | MUL | NULL | | | resource_type | varchar(255) | YES | | NULL | | | resource_id | int(11) | YES | | NULL | | | fk_user | int(11) | YES | MUL | NULL | | +---------------+--------------+------+-----+---------+----------------+ Asset_links +-----------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+---------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | asset_id1 | int(11) | YES | | NULL | | | asset_id2 | int(11) | YES | | NULL | | +-----------+---------+------+-----+---------+----------------+ In the asset_links table there are the following rows: 1 - 3, 1 - 4, 2 - 10, 2 - 56 I am looking to write one query which will return all assets which satisfy any asset search criteria and within the same query return all of the linked asset data for linked assets for that asset. e.g. The query returning assets 1 and 2 would return : Asset 1 attributes - Asset 3 attributes - Asset 4 attributes Asset 2 attributes - Asset 10 attributes - Asset 56 attributes What is the best way to write the query?

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  • SQL clone record with a unique index

    - by Milhous
    Is there a clean way of cloning a record in SQL that has an index(auto increment). I want to clone all the fields except the index. I currently have to enumerate every field, and use that in an insert select, and I would rather not explicitly list all of the fields, as they may change over time.

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  • WHERE id IN doesn't work in UPDATE

    - by Donator
    UPDATE statistics' SET money = money + '$money' WHERE member_id IN ((SELECT member_id FROM races WHERE l_id = '$mem_id'), $other_id) What's wrong with that? I want to retrieve all member_ids from races and also include to member_id $other_id. Without $other_id it works. By the way, it gives me "Subquery returns more than 1 row" error.

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  • How trasmit a Dictionary in a jsons form

    - by xRobot
    I have a dictionary in jsons form like this: $user = "{ name: Mary , born: 1963, money: 213 }"; I need to pass it throught this field: <input type="hidden" name="custom" value="" > and then insert it in the db: INSERT INTO user ( name, born, money ) VALUE ( $name, $born, $money ) How can I do that ?

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  • How to UNION ALL two SELECT statements?

    - by Lisa
    I have 2 tables, one looks like this: TABLE ONE id | Last Name | First Name | Username | Password | Secret Question and another that looks like this: TABLE TWO id | Hobby | Country | I want to combine a Select statement that grabs data from both tables and output the results. The following code: $select = mysql_query(" SELECT * FROM table_one WHERE Username = 'Bob' UNION ALL SELECT * FROM table_two WHERE Hobby = 'Baseball' "); while ($return = mysql_fetch_assoc($select)) { $userName = $return['Username']; $hobby = $return['Hobby']; } echo "$userName likes $hobby"; results in a The used SELECT statements have a different number of columns error, what am I doing wrong?

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  • Database normalization and duplicate values

    - by bretddog
    Consider a Parent / Child / GrandChild structure in a database table schema, or even a deeper hierarchy. These being in the same aggregate. One table DAYS keeps a single row per day, and has a "Date" field. This is the root table, or maybe a child of the root. No row can ever be deleted in this table. In this case, however complex my table schema looks like, however far away in the hierarchy any other table is, is there any reason why any other table would hold a Date value? Can't it instead just have a FK to the DAYS table. I obviously assume that the creation of these date fields happen not before such datefield exist in the DAYS table. I'm now thinking just about the date part to be relevant, not the time part. Not sure if all databases can store these individually. That's maybe relevant, but not really the focus of the question.

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  • Web script to click some buttons and save some html pages

    - by Serge
    I am trying to go through a site with a bunch of links. I click on a link, save the page, click on a button, save a page. Then go back and repeat it for a huge number of links. I want to write a script to do that for me. I know C++ but I want to do Javascript for this, what is a good place to get me started? What would be a good IDE to use?

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  • How to get multiple counts with one SQL query?

    - by Crobzilla
    I am wondering how to write this query. I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it is part of a much bigger query. SELECT distributor_id, COUNT(*) AS TOTAL, COUNT(*) WHERE level = 'exec', COUNT(*) WHERE level = 'personal' I need this all returned in one query. Also, it need to be in one row, so the following won't work: 'SELECT distributor_id, COUNT(*) GROUP BY distributor_id'

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  • Wrong intrepretation of some columns in ireport

    - by Purushotham
    Hi, I got a strange problem. I am using iReport 3.7.1 tool to create some reports. The Query Editor has one query. It shows all the data types of the fields in that query exactly same as the data types shown when I execute it using SQLYOG editor. The problem is here: One field data type is mismatched. I don't know the reason. SQLYOG says it is INTEGER whereas iReport Query Editor says its a long value. BTW The value that assigned to that filed is zero. Can anyone help ? I want to zero-in on this issue.

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  • Seeking free ODBC database optimization tool for non-experts

    - by mawg
    I'm a database n00b and am reading as many books as I can. I have been given responsibility for an ODBC tool where the databases were designed by a hardware engineer with some VB experience - which made him a s/w guru in the small firm at that time. Things are running slowly and I suspect that the db could have been designed better. I hope to learn enough to use Explain/Describe, etc maybe add some indices, but, in the meantime, is there any free for commercial use tool which can examine an ODBC database and suggest improvements. I'm just talking about db schema here, but maybe I should also be looking at optimizing Selects with Joins? Is there a tool for that? ODBC compliant.

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  • Can I copy a cross compiler tool chain between systems (I did before)?

    - by Jamie
    I tested fairly extensively with Ubuntu 10.04 Beta 2 Server in a VM, and was able to simply copy (read tar x) a cross compiled tool chain from an Ubuntu 8.10 VM. I created the tar myself, which is essentially a lot of stuff in \usr\local. Now that I've got a bare metal installation of Ubuntu 10.04 proper, the copy isn't working. In particularly, I'm getting the error: $ arm-linux-gcc -bash: /usr/local/bin/arm-linux-gcc: No such file or directory I've got the systems side by side in SSH windows ... any suggestions?

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  • Efficient way to combine results of two database queries.

    - by ensnare
    I have two tables on different servers, and I'd like some help finding an efficient way to combine and match the datasets. Here's an example: From server 1, which holds our stories, I perform a query like: query = """SELECT author_id, title, text FROM stories ORDER BY timestamp_created DESC LIMIT 10 """ results = DB.getAll(query) for i in range(len(results)): #Build a string of author_ids, e.g. '1314,4134,2624,2342' But, I'd like to fetch some info about each author_id from server 2: query = """SELECT id, avatar_url FROM members WHERE id IN (%s) """ values = (uid_list) results = DB.getAll(query, values) Now I need some way to combine these two queries so I have a dict that has the story as well as avatar_url and member_id. If this data were on one server, it would be a simple join that would look like: SELECT * FROM members, stories WHERE members.id = stories.author_id But since we store the data on multiple servers, this is not possible. What is the most efficient way to do this? Thanks.

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  • Displaying code with <pre> tags.

    - by iMaster
    Currently I'm using <pre><code> code here </code><pre> to display code. I'm pulling this information from a DB for a blog. The problem I'm having is that some of the code isn't showing. For example, in the source code I have this: <pre><code><br /> echo '<ul class="mylist"><li><ul class="left">'; foreach($nameArray as $name) { if($countervar == $half) { echo '</ul></li>'; echo'<li><ul class="right">'; } echo '<li>$name</li>'; ++$i; } echo '</ul></li>'; echo '</ul>'; ?> But all that shows up is this: echo ''; foreach($nameArray as $name) { if($countervar == $half) { echo ''; echo''; } echo '$name'; ++$i; } echo ' An there's some really weird formatting/spacing issues as well. Any ideas as to what is causing this? I should also mention that some of the other sets of code show up just fine.

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