Search Results

Search found 3825 results on 153 pages for 'regex negation'.

Page 7/153 | < Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >

• regex : how to eliminiate urls ending with .dtd

  - by dorelal

  This is JavaScript regex. regex = /(http:\/\/[^\s]*)/g; text = "I have http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd and I like http://google.com a lot"; matches = text.match(regex); console.log(matches); I get both the urls in the result. However I want to eliminate all the urls ending with .dtd . How do I do that? Note that I am saying ending with .dtd should be removed. It means a url like http://a.dtd.google.com should pass .

  Read the article

• Regex for tollfree numbers in java

  - by arinte

  I have this regex to test for telephone # that should be a toll free. public static final Pattern patternTollFree = Pattern.compile("^((877)|(800)|(866)|(888))"); So I only want to get those # where the user may have left the 1 off of the front of the string, but I have tried several things and I can't get java to match. public String changeRingTo( String changedRinger ) { if ( null == changedRinger || changedRinger.length() != 10) return changedRinger; if ( patternTollFree.matcher(changedRinger).region(0, 2).matches() ) changedRinger = '1' + changedRinger; return changedRinger; } I can't get this 2nd test case below to succeed. What am I doing wrong? assertEquals( "Regex not working", "8189091000", of.changeRingTo("8189091000")); assertEquals( "Regex not working", "18769091000", of.changeRingTo("8769091000"));

  Read the article

• C# Find and Replace RegEx question

  - by fraXis

  Hello, I am starting to get a grip on RegEx thanks to all the great help here on SO with my other questions. But I am still suck on this one: My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); I am reading in a text file and I want to search for this text and change it (the X and Y value always follow each other in my text file): X17.8Y-1. But this text can also be X16.1Y2.3 (the values will always be different after X and Y) I want to change it to this X17.8Y-1.G54 or X(value)Y(value)G54 My RegEx statement follows but it is not working. content = Regex.Replace(content, @"(X(?:\d*\.)?\d+)*(Y(?:\d*\.)?\d+)", "$1$2G54"); Can someone please modify it for me so it works and will search for X(wildcard) Y(Wildcard) and replace it with X(value)Y(value)G54? Thanks, Shawn

  Read the article

• How to use variables with regex?

  - by dontoo

  This is the input string: 23x^45*y or 2x^2 or y^4*x^3. I am matching ^[0-9]+ after letter x. In other words I am matching x followed by ^ followed by numbers. Problem is that I don't know that I am matching x, it could be any letter that I stored as variable in my char array. For example: foreach (char cEle in myarray) // cEle is letter in char array x, y, z, ... { match CEle in regex(input) //PSEUDOCODE } I am new to regex and I new that this can be done if I define regex variables, but I don't know how.

  Read the article

• RegEx - Take all numeric characters following a text character

  - by Simon

  Given a string in the format: XXX999999v99 (where X is any alpha character and v is any numeric character and v is a literal v character) how can I get a regex to match the numeric characters following the v? So far I've got 'v\d\d' which includes the v but ideally I'd like just the numeric part. As an aside does anyone know of a tool in which you can specify a string to match and have the regex generated? Modifying an existing regex is one thing but I find starting from scratch painful! Edit: Re-reading this question I realise it reads like a homework assignment! However I can assure you it's not, the strings I'm trying to match represent product versions appended to product codes. The current code uses all sorts of substring expressions to retrieve the version part.

  Read the article

• Regex replace help

  - by Jeremy

  Using the .NET framework, I'm trying to replace double slash characters in a string with a single slash, but it seems to be removing an extra character and I don't know why. I have a string: http://localhost:4170/RCRSelfRegistration//Default.aspx My regex is: [^(://|:\\\\)](\\\\|//|\\/|/\\) And the return value is: http://localhost:4170/RCRSelfRegistratio/Default.aspx You can see that the n in RCRSelfRegistration has been removed. I am not sure why. /// <summary> /// Match on double slashes (//, \\, /\, \/) but do not match :// or :\\ /// </summary> private const string strMATCH = @"[^(://|:\\\\)](\\\\|//|\\/|/\\)"; /// <summary> /// Replace double slashes with single slash /// </summary> /// <param name="strUrl"></param> /// <returns></returns> public static string GetUrl(string strUrl) { string strNewUrl System.Text.RegularExpressions.Regex rxReplace = new System.Text.RegularExpressions.Regex(strMATCH); strNewUrl = rxReplace.Replace(strUrl, "/"); return strNewUrl; }

  Read the article

• Find and Replace RegEx question

  - by fraXis

  I am starting to get a grip on RegEx thanks to all the great help here on SO with my other questions. But I am still suck on this one: My code is: StreamReader reader = new StreamReader(fDialog.FileName.ToString()); string content = reader.ReadToEnd(); reader.Close(); I am reading in a text file and I want to search for this text and change it (the X and Y value always follow each other in my text file): X17.8Y-1. But this text can also be X16.1Y2.3 (the values will always be different after X and Y) I want to change it to this X17.8Y-1.G54 or X(value)Y(value)G54 My RegEx statement follows but it is not working. content = Regex.Replace(content, @"(X(?:\d*\.)?\d+)*(Y(?:\d*\.)?\d+)", "$1$2G54"); Can someone please modify it for me so it works and will search for X(wildcard) Y(Wildcard) and replace it with X(value)Y(value)G54?

  Read the article

• Regex and PHP for extracting contents between tags with several line breaks

  - by John

  How can I extract the content between tags with several line breaks? I'm a newbie to regex, who would like to know how to handle unknown numbers of line break to match my query. Task: Extract content between <div class="test"> and the first closing </div> tag. Original source: <div class="test">optional text<br/> content<br/> <br/> content<br/> ... content<br/><a href="/url/">Hyperlink</a></div></div></div> I've worked out the below regex, /<div class=\"test\">(.*?)<br\/>(.*?)<\/div>/ Just wonder how to match several line breaks using regex. There is DOM for us but I am not familiar with that.

  Read the article

• what perl regex should I use to get value from line

  - by Octopus

  I am trying to capture the cpu usage from the running process. For SunOS, I have below output process,10050,user1,218,59,0,1271M,1260M,sleep,58.9H,0.02%,java here the cpu % is at 11th field if we separate by comma(,). To get this value I am using below regex regex => q/^process,(?:.*?),((?:\d+)\.(?:\d+))%,java$/, but for the linux system I have below output. process,26190,user1,20,0,1236m,43m,6436,S,0.0,1.1,0:00.00,java, here the cpu usage is at 10th column What regex pattern should i use to get this value. Appreciate for any suggestion.

  Read the article

• C++: posix regex error reporting?

  - by Helltone

  I'm writing a small C++ program that parses some strings. I chose to use C's regex.h because I only need POSIX Extended Syntax and I'm concerned with portability. However, I've just noticed that when regexec fails to match, it returns != 0 and I have no idea of what was wrong :-(. I expected to be able to display at least a small message like: line:col: Syntax error or giig sdoigosdigo* sodfg ^ Syntax error Is there a way to know which character did not match? Should I use boost:regex instead? For reference, my regex is: "^" "[ ;\t\n]*" "(" // (1) identifier "[a-zA-Z_][a-zA-Z0-9_]*" ")" "[ \t]*" "(" // (2) non-marking "\[" "(" // (3) non-marking "[ \t]*" "(" // (4..n-1) argument "[a-zA-Z0-9_]+" ")" "[ \t]*" "," ")*" "[ \t]*" "(" // (n) last argument "[a-zA-Z0-9_]+" ")" "]" ")?" "[ \t\n]*" ";" Which matches for instance blablabla[arg1, arg2];

  Read the article

• Regex for splitting a german address into its parts

  - by Christian

  Good evening, I'm trying to splitting the parts of a german address string into its parts via Java. Does anyone know a regex or a library to do this? To split it like the following: Name der Straße 25a 88489 Teststadt to Name der Straße|25a|88489|Teststadt or Teststr. 3 88489 Beispielort (Großer Kreis) to Teststr.|3|88489|Beispielort (Großer Kreis) It would be perfect if the system / regex would still work if parts like the zip code or the city are missing. Is there any regex or library out there with which I could archive this? EDIT: Rule for german addresses: Street: Characters, numbers and spaces House no: Number and any characters (or space) until a series of numbers (zip) (at least in these examples) Zip: 5 digits Place or City: The rest maybe also with spaces, commas or braces

  Read the article

• Matching n parentheses in perl regex

  - by coding_hero

  Hi, I've got some data that I'm parsing in Perl, and will be adding more and more differently formatted data in the near future. What I would like to do is write an easy-to-use function, that I could pass a string and a regex to, and it would return anything in parentheses. It would work something like this (pseudocode): sub parse { $data = shift; $regex = shift; $data =~ eval ("m/$regex/") foreach $x ($1...$n) { push (@ra, $x); } return \@ra; } Then, I could call it like this: @subs = parse ($data, '^"([0-9]+)",([^:]*):(\W+):([A-Z]{3}[0-9]{5}),ID=([0-9]+)'); As you can see, there's a couple of issues with this code. I don't know if the eval would work, the 'foreach' definitely wouldn't work, and without knowing how many parentheses there are, I don't know how many times to loop. This is too complicated for split, so if there's another function or possibility that I'm overlooking, let me know. Thanks for your help!

  Read the article

• Parsing complex string using regex

  - by wojtek_z

  My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

  Read the article

• Regex - find all phrases except the one including specific word

  - by ekapek

  Hi, I have a text file with text like: "Lorem ipsum text. Second lorem ipsum. How are You. It's ok. Done. Something else now. New line. Halo. Text. Are You ok." I need a regex to find all sentences (between .) except ones with the word "else" within it. I'm trying many regex patterns but nothing works. Can I do this with regex?

  Read the article

• replace characters which do not matches the ones in a regex

  - by Cristian Boariu

  Hi, I have this regex: private static final String SPACE_PATH_REGEX ="[a-z|A-Z|0-9|\\/|\\-|\\_|\\+]+"; I check if my string matches these regex and IF NOT, i want to replace all characters which are not here, with "_". I;ve tried like: private static final String SPACE_PATH_REGEX_EXCLUDE ="[~a-z|A-Z|0-9|\\/|\\-|\\_|\\+]+"; if (myCompanyName.matches(SPACE_PATH_REGEX)) { myNewCompanySpaceName = myCompanyName; } else{ myNewCompanySpaceName = myCompanyName.replaceAll(SPACE_PATH_REGEX_EXCLUDE, "_"); } but does not work..., so in the 2nd regex "~" seems to not omit the following chars. Any ideea?

  Read the article

• Regex to find external links from the html file using grep

  - by Amar

  hello, From past few days I'm trying to develop a regex that fetch all the external links from the web pages given to it using grep. Here is my grep command grep -h -o -e "\(\(mailto:\|\(\(ht\|f\)tp\(s\?\)\)\)\://\)\{1\}\(.*\?\)" "/mnt/websites_folder/folder_to_search" -r now the grep seem to return everything after the external links in that given line Example if an html file contain something like this on same line GoogleYahoo then the given grep command return the following result http://www.google.com">Google</a><p><a href='https://yahoo.com'>Yahoo</a></p> the idea here is that if an html file contain more than one links(`irrespective in a,img etc`) in same line then the regex should fetch only the links and not all content of that line I managed to developed the same in rubular.com the regex is as follow ("|')(\b((ht|f)tps?:\/\/)(.*?)\b)("|') with work with the above input but iam not able to replicate the same in grep can anyone help I can't modify the html file so don't ask me to do that neither I can look for each specific tags and check their attributes to to get external links as it addup processing time and my application doesn't demand that Thank You

  Read the article

• Match regex from right to left?

  - by Balroq

  Hi! Is there any way of matching a regex from right to left? What Im looking for is a regex that gets MODULE WAS INSERTED EVENT LOST SIGNAL ON E1/T1 LINK OFF CRC ERROR EVENT CLK IS DIFF FROM MASTER CLK SRC OF from this input CLI MUX trap received: (022) CL-B MCL-2ETH MODULE WAS INSERTED EVENT 07-05-2010 12:08:40 CLI MUX trap received: (090) IO-2 ML-1E1 EX1 LOST SIGNAL ON E1/T1 LINK OFF 04-06-2010 09:58:58 CLI MUX trap received: (094) IO-2 ML-1E1 EX1 CRC ERROR EVENT 04-06-2010 09:58:59 CLI MUX trap received: (009) CLK IS DIFF FROM MASTER CLK SRC OFF 07-05-2010 12:07:32 If i could have done the matching from right to left I could have written something like everything to right of (EVENT|OFF) until the second appearance of more than one space [ ]+ The best I managed today is to get everything from (022) to EVENT with the regex CLI MUX trap received: \([0-9]+\)[ ]+(.*[ ]+(EVENT|OFF)) But that is not really what I wanted :)

  Read the article

• Apache complex regex crashing with 500 error

  - by digitalspaghetti

  I have been working with an existing website out company has running until I finish developing the new site. I've been asked to add some additional functionality to booking pages that will automatically set a booking button based on passed parameters. The existing working regex is as follows: RewriteRule ^.+-(\d+)\.accommodation$ property_detail.php?id=$1 Which works fine with the url like below and passes through the URL. this-is-the-property-name.1234.accomodation However as a quick shiv, I am trying to do the following: this-is-the-property-name.1234.accomodation?override=true&start_date=2010-05-14&numbernights=2&sleeps=10&price=1012 The regex I came up with for this was: RewriteRule ^.+-(\d+)\.accommodation\?override=(\w+)&start_date=(19|20)[0-9]{2}[- /.](0[1-9]|1[012])[- /.](0[1-9]|[12][0-9]|3[01])&numbernights=(\d+)&sleeps=(\d+)&price=(\d+)$ property_detail.php?id=$1&override=$2&start_date=$3-$4-$5&numbernights=$6&sleeps=$7&price=$8 The regex is passing as valid in RegexBuddy - however it keeps causing a 500 error on the server. Can anyone help me get my head around this one?

  Read the article

• replace characters which do not match with the ones in a regex

  - by Cristian Boariu

  Hi, I have this regex: private static final String SPACE_PATH_REGEX ="[a-z|A-Z|0-9|\\/|\\-|\\_|\\+]+"; I check if my string matches this regex and IF NOT, i want to replace all characters which are not here, with "_". I've tried like: private static final String SPACE_PATH_REGEX_EXCLUDE = "[~a-z|A-Z|0-9|\\/|\\-|\\_|\\+]+"; if (myCompanyName.matches(SPACE_PATH_REGEX)) { myNewCompanySpaceName = myCompanyName; } else{ myNewCompanySpaceName = myCompanyName.replaceAll( SPACE_PATH_REGEX_EXCLUDE, "_"); } but it does not work..., so in the 2nd regex "~" seems to not omit the following chars. Any idea?

  Read the article

• Regex Problem in PHP

  - by Chris

  I'm attempting to utilize the following Regex pattern: $regex = '/Name: [a-zA-Z ]*] [0-9]/'; When testing it in Rubular, it works fine, but when using PHP the expression never returns true, even when it should. Incidentally, if I remove the "[0-9]" part, it works fine. Is there some difference in PHP's regex syntax that I'm overlooking? Edit: I'm looking for the characters "Name:" then a name containing any number of letters or spaces, then a "]", then a space, then a single number. So "Name: Chris] 5" would return true and "Name: Chris] [lorem ipsum]" should return false. I also tried escaping the second bracket "\[" but this did not fix the problem.

  Read the article

• Which is the correct shorthand - "regex" or "regexp".

  - by Vilx-

  Most of us computer programmers are pretty obsessed about correct terminology. I certainly am, especially because sometimes changing just one character in a word can drastically change its meaning. So... what is the correct shorthand for "regular expression"? Is it "regex" or "regexp"? On the internet I see both uses, although "regex" seems to be more popular, and the tag list here on SO also includes just "regex". But plenty of people also use "regexp" in their questions.

  Read the article

• Regex only retrieves the first necessary element but not all of them

  - by Serge

  Can anybody help me with retrieving some elements from the following example text: sdfaasdflj asdfjl;a AB-12/34 BC-/85 CD-//8 DD-77 DE-78/9 EE-78-98 asdf; asdjf It is necessary to get the following elements: AB-12/34, BC-/85, CD-//8, DD-77, DE-78/9 When I'm using a regular expression like this: \s*(?<elements>\b[A-Z]{2}-[/0-9]+\b) everything works fine - all the necessary elements are being retrieved (except for the EE element are amonth them, but it doesn't matter). The problem is that this line is a part of a more complex regex, so when I'm trying to apply a regex like this: (?s).*\sas.*? \s*(?<elements>\b[A-Z]{2}-[/0-9]+\b)*.* .*as It only returns me just the first AB-12/34 element and nothing else. How to correct the regex to get all the elements? TIA.

  Read the article

• Having problems getting a PHP regex to match.

  - by dqhendricks

  Here is my problem. It's probably a simple fix. I have a regex that I am using to replace a url BBCode. What I have right now that is not working looks like this. <?php $input_string = '[url=www.test.com]Test[url]'; $regex = '/\[url=(.+?)](.+?)\[\/url]/is'; $replacement_string = '<a href="$1">$2</a>'; echo preg_replace($regex, $replacement_string, $input_string); ?> This currently outputs the original $input_string, while I would like it to output the following. <a href="www.test.com">Test</a> What am I missing?

  Read the article

• C++0x regex in GCC

  - by rwallace

  The following code: #include <regex> using namespace std; (snippage) regex_search(s, m, re); works in Microsoft C++, but GCC 4.4.3 gives the following error message: /usr/include/c++/4.4/tr1_impl/regex:2255: warning: inline function ‘bool std::regex_search(_Bi_iter, _Bi_iter, std::match_results<_Bi_iter, _Allocator&, const std::basic_regex<_Ch_type, _Rx_traits&, std::regex_constants::match_flag_type) [with _Bi_iter = __gnu_cxx::__normal_iterator, std::allocator , _Allocator = std::allocator, std::allocator , _Ch_type = char, _Rx_traits = std::regex_traits]’ used but never defined Of course it wouldn't surprise me if regex were simply one of the C++0x features still on the to-do list for GCC, but what I'm scratching my head over is, in that case, why does it happily take the include directive, variable declarations etc. and only trip over the function call (which it even seems to understand). Is there something I'm missing?

  Read the article

• RegEx - Indexed\Arrayed Named Capture groups?

  - by Josh

  I have a situation where something can appear in a format as follows: ---id-H-- Header: data Another Header: more data Message: sdasdasdasd Message: asdasdasdasd Message: asdasdasd There may be many messages, or just a couple. I'd prefer not having to step outside of RegEx, because I am using the RegEx to parse some header information above the messages and the messages along with the headers are part of the text I am parsing. The messages attached into the text might be many. I would also like to use named capture groups, so something like Message: (?<Message[index of match]>.+) Where it matches the match as many times as it can with the index filled in. Does anything like this exist in RegEx? (I will eventually be using this in Perl)

  Read the article

< Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >