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• mercurial .hgrc notify hook

  - by Eeyore

  Could someone tell me what is incorrect in my .hgrc configuration? I am trying to use gmail to send a e-mail after each push and/or commit. .hgrc [paths] default = ssh://www.domain.com/repo/hg [ui] username = intern <[email protected]> ssh="C:\Program Files (x86)\Mercurial\plink.exe" -ssh -i "C:\Program Files (x86)\Mercurial\key.pub" [extensions] hgext.notify = [hooks] changegroup.notify = python:hgext.notify.hook incoming.notify = python:hgext.notify.hook [email] from = [email protected] [smtp] host = smtp.gmail.com username = [email protected] password = sure port = 587 tls = true [web] baseurl = http://dev/... [notify] sources = serve push pull bundle test = False config = /path/to/subscription/file template = \ndetails: {baseurl}{webroot}/rev/{node|short}\nchangeset: {rev}:{node|short}\nuser: {author}\ndate: {date|date}\ndescription:\n{desc}\n maxdiff = 300 Error Incoming comand failed for P/project. running ""C:\Program Files (x86)\Mercurial\plink.exe" -ssh -i "C:\Program Files (x86)\Mercurial\key.pub" [email protected] "hg -R repo/hg serve --stdio"" sending hello command sending between command remote: FATAL ERROR: Server unexpectedly closed network connection abort: no suitable response from remote hg! , error code: -1 running ""C:\Program Files (x86)\Mercurial\plink.exe" -ssh -i "C:\Program Files (x86)\Mercurial\key.pub" [email protected] "hg -R repo/hg serve --stdio"" sending hello command sending between command remote: FATAL ERROR: Server unexpectedly closed network connection abort: no suitable response from remote hg!

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• How to Select Items in Dropdown in Selenium

  - by Marcus Gladir

  Firstly, I have been trying to get the dropdown from this web page: http://solutions.3m.com/wps/portal/3M/en_US/Interconnect/Home/Products/ProductCatalog/Catalog/?PC_Z7_RJH9U5230O73D0ISNF9B3C3SI1000000_nid=RFCNF5FK7WitWK7G49LP38glNZJXPCDXLDbl This is the code I have: import urllib2 from bs4 import BeautifulSoup import re from pprint import pprint import sys from selenium import common from selenium import webdriver import selenium.webdriver.support.ui as ui from boto.s3.key import Key import requests url = 'http://solutions.3m.com/wps/portal/3M/en_US/Interconnect/Home/Products/ProductCatalog/Catalog/?PC_Z7_RJH9U5230O73D0ISNF9B3C3SI1000000_nid=RFCNF5FK7WitWK7G49LP38glNZJXPCDXLDbl' element_xpath = '//*[@id="Component1"]' driver = webdriver.PhantomJS() driver.get(url) element = driver.find_element_by_xpath(element_xpath) element_xpath = '/option[@value="02"]' all_options = element.find_elements_by_tag_name("option") for option in all_options: print("Value is: %s" % option.get_attribute("value")) option.click() source = driver.page_source.encode('utf-8', 'ignore') driver.quit() source = str(source) soup = BeautifulSoup(source, 'html.parser') print soup What prints out is this: Traceback (most recent call last): File "../../../../test.py", line 58, in <module> Value is: XX main() File "../../../../test.py", line 46, in main option.click() File "/home/eric/dev/octocrawler-env/local/lib/python2.7/site-packages/selenium-2.33.0-py2.7.egg/selenium/webdriver/remote/webelement.py", line 54, in click self._execute(Command.CLICK_ELEMENT) File "/home/eric/dev/octocrawler-env/local/lib/python2.7/site-packages/selenium-2.33.0-py2.7.egg/selenium/webdriver/remote/webelement.py", line 228, in _execute return self._parent.execute(command, params) File "/home/eric/dev/octocrawler-env/local/lib/python2.7/site-packages/selenium-2.33.0-py2.7.egg/selenium/webdriver/remote/webdriver.py", line 165, in execute self.error_handler.check_response(response) File "/home/eric/dev/octocrawler-env/local/lib/python2.7/site-packages/selenium-2.33.0-py2.7.egg/selenium/webdriver/remote/errorhandler.py", line 158, in check_response raise exception_class(message, screen, stacktrace) selenium.common.exceptions.ElementNotVisibleException: Message: u'{"errorMessage":"Element is not currently visible and may not be manipulated","request":{"headers":{"Accept":"application/json","Accept-Encoding":"identity","Connection":"close","Content-Length":"81","Content-Type":"application/json;charset=UTF-8","Host":"127.0.0.1:51413","User-Agent":"Python-urllib/2.7"},"httpVersion":"1.1","method":"POST","post":"{\\"sessionId\\": \\"30e4fd50-f0e4-11e3-8685-6983e831d856\\", \\"id\\": \\":wdc:1402434863875\\"}","url":"/click","urlParsed":{"anchor":"","query":"","file":"click","directory":"/","path":"/click","relative":"/click","port":"","host":"","password":"","user":"","userInfo":"","authority":"","protocol":"","source":"/click","queryKey":{},"chunks":["click"]},"urlOriginal":"/session/30e4fd50-f0e4-11e3-8685-6983e831d856/element/%3Awdc%3A1402434863875/click"}}' ; Screenshot: available via screen And the weirdest most infuriating bit of it all is that sometimes it actually all works out. I have no clue what's going on here.

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• git push heroku master gives error ssh: connect to host heroku.com port 22: Connection refused

  - by user1476508

  I'm trying to run the heroku-django tutorial (using ubuntu 12.04) and it seems for some reason i cant push into heroku. here is what happens: yeinhorn@ubuntu:~/hellodjango$ git init Reinitialized existing Git repository in /home/yeinhorn/hellodjango/.git/ yeinhorn@ubuntu:~/hellodjango$ git add . yeinhorn@ubuntu:~/hellodjango$ git commit -m "my first commit" On branch master nothing to commit (working directory clean) yeinhorn@ubuntu:~/hellodjango$ heroku create Creating high-dusk-6308... done, stack is cedar http://high-dusk-6308.herokuapp.com/ | [email protected]:high-dusk-6308.git ! New default stack: Cedar. To use Bamboo, run heroku create -s bamboo. yeinhorn@ubuntu:~/hellodjango$ git remote -v heroku [email protected]:blazing-dusk-8587.git (fetch) heroku [email protected]:blazing-dusk-8587.git (push) yeinhorn@ubuntu:~/hellodjango$ git push heroku master ssh: connect to host heroku.com port 22: Connection refused fatal: The remote end hung up unexpectedly yeinhorn@ubuntu:~/hellodjango$ git push -f heroku ssh: connect to host heroku.com port 22: Connection refused fatal: The remote end hung up unexpectedly also when i run $telnet heroku.com 22 i get Trying 50.19.85.132... Trying 50.19.85.154... Trying 50.19.85.156... telnet: Unable to connect to remote host: Connection refused any ideas?

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• Virtual Lan on the Cloud -- Help Confirm my understanding?

  - by marfarma

  [Note: Tried to post this over at ServerFault, but I don't have enough 'points' for more than one link. Powers that be, move this question over there.] Please give this a quick read and let me know if I'm missing something before I start trying to make this work. I'm not a systems admin professional, and I'd hate to end up banging my head into the wall if I can avoid it. Goals: Create a 'road-warrior' capable star shaped virtual LAN for consultants who spend the majority of their time on client sites, and who's firm has no physical network or servers. Enable CIFS access to a cloud-server based installation of Alfresco Allow Eventual implementation of some form of single-sign-on ( OpenLDAP server ) access to Alfresco and other server applications implemented in the future Given: All Servers will live in the public internet cloud (Rackspace Cloud Servers) OpenVPN Server will be a Linux disto, probably Ubuntu 9.x, installed on same server as Alfresco (at least to start) Staff will access server applications and resources from client sites, hotels, trains, planes, coffee shops or their homes over various ISP, using their company laptops or personal home desktops. Based on my Research thus far, to accomplish this, I'll need: OpenVPN with Bridging Enabled to create a star shaped "virtual" LAN http://openvpn.net/index.php/open-source/documentation/miscellaneous/76-ethernet-bridging.html A Road Warrior Network Configuration, as described in this Shorewall article (lower down the page) http://www.shorewall.net/OPENVPN.html Configure bridge addressesing (probably DHCP) http://openvpn.net/index.php/open-source/faq.html#bridge-addressing Configure CIFS / Samba to accept VPN IP address http://serverfault.com/questions/137933/howto-access-samba-share-over-vpn-tunnel Set up Client software, with keys configured for access (potentially through a OpenVPN-Sa client portal) http://www.openvpn.net/index.php/access-server/download-openvpn-as/221-installation-overview.html

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• Accessing class member variables inside a BackgroundWorker's DoWork event handler, and other Backgro

  - by Justin

  Question 1 In the DoWork event handler of a BackgroundWorker, is it safe to access (for both reading and writing) member variables of the class that contains the BackgroundWorker? Is it safe to access other variables that are not declared inside the DoWork event handler itself? Obviously DoWork should not be accessing any UI objects of, say, a WinForms application, as the UI should only be updated from the UI thread. But what about accessing other (not UI-related) member variables? The reason why I ask is that I've seen the occasional comment come up while Googling saying that accessing member variables is not allowed. The only example I can find at the moment is a comment on this MSDN page, which says: Note, that the BGW can cause exceptions if it attempts to access or modify class level variables. All data must be passed to it by delegates and events. And also: NEVER. NEVER. Never try to reference variables not declared inside of DoWork. It may seem to work at times, but in reality you are just getting lucky. As far as I know, MSDN itself does not document any restrictions of this kind (although if I'm wrong, I'd appreciate a link). But comments like these do seem to pop up every now and again. (Of course if DoWork does access/modify a member variable that could be accessed/modified by the main thread at the same time, it is necessary to synchronise access to that field, eg by using a locking object. But the above quotes seem to require a blanket ban of accessing member variables, rather than just synchronising access!) Question 2 To make this into a more general question, are there any other (not documented?) restrictions that users of the BackgroundWorker should be aware of, aside from the above? Any "best practices", perhaps?

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• Is it possible to use OAuth starting from the service provider website?

  - by Brian Armstrong

  I want to let people create apps that use my API and authenticate them with OAuth. Normally this process starts from the consumer service website (say TwitPic) and they request an access token from the service provider (Twitter). The user is then taken to the service provider website where they have to allow/deny access to to the consumer. I'm wondering if it's possible to initiate this process from the service provider website instead. So in this example you would start on Twitter's site, and maybe there is a section marked "do you want to turn on access for TwitPic?". If you click yes, it passes the access token directly to TwitPic which now has access to your account. Basically, fewer steps. I'm looking at the OAuth docs and it looks like the request token is generated on the consumer side and used later to turn it into an access token. So it's not really designed with what I described above in mind, but I thought there might be a way. http://oauth.net/core/1.0/ (Search for "steps") Thanks!

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• sp_addlinkedserver on sql server 2005 giving problem

  - by Jit

  I am trying to create a link server of a remote database(both the servers are SQL serve2005). I am able to connect that remote server from my SQL Server management studio. I used the following syntax to create it. EXEC sp_addlinkedserver @server = N'LINKSQL2005', @srvproduct = N'', @provider = N'SQLNCLI', @provstr = N'SERVER=IP Address of remote server ;User ID=XXXXXX;Password=***' I have provided the IP addressntax. and user name and password in the above syntax. The link server is getting created. But when I try to execute a query on it I get the error below. Query Used. select * from LINKSQL2005.<DBName>.dbo.<TableName> OLE DB provider "SQLNCLI" for linked server "LINKSQL2005" returned message "Communication link failure". Msg 10054, Level 16, State 1, Line 0 TCP Provider: An existing connection was forcibly closed by the remote host. Msg 18456, Level 14, State 1, Line 0 Login failed for user 'sa'. OLE DB provider "SQLNCLI" for linked server "LINKSQL2005" returned message "Invalid connection string attribute". Pls help me, where am I making mistake.

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• asp.net doesn't render Sys.WebForms.PageRequestManager._initialize code

  - by ajitatif

  i'm using the ASP.NET 2.0 Ajax Extensions on a web site. as always, everything is fine on local but the remote web site does not use ajax calls. my local server has the ASP.NET Ajax extensions installed but the remote one doesn't. i know that i should be able to use the Ajax extensions without installing them. so in turn, i added the extensions' .dll among the web site's references but still no luck. after my further investigation, i found out that local and remote pages have exactly the same HTML code rendered, except that the local (working) one has these lines //<![CDATA[ Sys.WebForms.PageRequestManager._initialize('ctl00$ContentPlaceHolder1$ScriptManager1', document.getElementById('aspnetForm')); Sys.WebForms.PageRequestManager.getInstance()._updateControls(['tctl00$ContentPlaceHolder1$updReportArgs','tctl00$ContentPlaceHolder1$updReport'], ['ctl00$ContentPlaceHolder1$chkTumu','ctl00$ContentPlaceHolder1$btnGetir'], [], 90); //]]> obviously, these are the lines of code that make callbacks possible. the question is why doesn't asp.net render these lines? what could be missing? by the way, the ScriptResource.axd and WebResource.axd doesn't give a 404 or anything, i can see through their js codes via Firebug. and one more thing: i'm unsure if it is related or not, but there are client-side asp.net validators on the page whose js code are not rendered either. again, those work fine locally. for further investigation you can see the remote site here : http://www.ajitatif.com/subdomains/nazer/Raporlar/danismanbasarim.aspx

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• ASP.net file operations delay

  - by mtranda

  Ok, so here's the problem: I'm reading the stream from a FileUpload control, reading in chunks of n bytes and writing the array in a loop until I reach the stream's end. Now the reason I do this is because I need to check several things while the upload is still going on (rather than doing a Save(); which does the whole thing in one go). Here's the problem: when doing this from the local machine, I can see the file just fine as it's uploading and its size increases (had to add a Sleep(); clause in the loop to actually get to see the file being written). However, when I upload the file from a remote machine, I don't get to see it until the the file has completed uploading. Also, I've added another call to write the progress to a text file as the progress is going on, and I get the same thing. Local: the file updates as the upload goes on, remote: the token file only appears after the upload's done (which is somewhat useless since I need it while the upload's still happening). Is there some sort of security setting in (or ASP.net) that maybe saves files in a temporary location for remote machines as opposed to the local machine and then moves them to the specified destination? I would liken this with ASP.net displaying error messages when browsing from the local machine (even on the public hostname) as opposed to the generic compilation error page/generic exception page that is shown when browsing from a remote machine (and customErrors are not off) Any clues on this? Thanks in advance.

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• Using bitwise operators on > 32 bit integers

  - by dqhendricks

  I am using bitwise operations in order to represent many access control flags within one integer. ADMIN_ACCESS = 1; EDIT_ACCOUNT_ACCESS = 2; EDIT_ORDER_ACCESS = 4; var myAccess = 3; // ie: ( ADMIN_ACCESS | EDIT_ACCOUNT_ACCESS ) if ( myAccess & EDIT_ACCOUNT_ACCESS ) { // check for correct access // allow for editing of account } Most of this is occurring on the PHP side of my project. There is one piece however where Javascript is used to join several access flags using | when saving someone's access level. This works fine to a point. I have found that once an integer (flag) gets too large ( 32bit), it no longer works correctly with bitwise operators in Javascript. For instance: alert( 4294967296 | 1 ); // equals 1, but should equal 4294967297 I am trying to find a workaround for this so that I do not have to limit my number of access control flags to 32. Each access control flag is two times the previous control flag so that each control flag will not interfere with other control flags. dec(4) = bin(100) dec(8) = bin(1000) dec(16) = bin(10000) I have noticed that when adding two of these flags together with a simple +, it seems to come out with the same answer as a bitwise or operation, but am having trouble wrapping my head around whether this is a simple substitution, or if there might be problems with doing this. Can anyone comment on the validity of this workaround? Example: (4294967296 | 262144 | 524288) == (4294967296 + 262144 + 524288)

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• Integrating legacy Ajax script in CakePHP

  - by octavian

  Hi, I have a legacy script that I would like to integrate in a cakephp app. The script makes use of $_POST and such and since I'm quite a noob I would need some help for the integration. Here is how the script looks like: THE JAVASCRIPT: prototype.js builder.js (these two are from the prototype fw) lib.js (makes a ajax requests to remote.php) THE PHP remote.php (contains FastJSON class and $_POST vars) if ($_POST['cmd'] == 'SAVETEAM' && $_POST['info']) { $INFO = json_decode(str_replace('\"', '"', $_POST['info'])); $nr = 1; $SORT = array($INFO->GK, $INFO->DEF, $INFO->MID, $INFO->FOR, $INFO->RZ); foreach ($SORT as $STD) foreach ($STD as $v) mysql_query("UPDATE players_teams SET fieldposition = ".$nr++." WHERE player_id = {$v->player_id} AND team_id = {$v->team_id}") or die(mysql_error()); // CAPTAION mysql_query("UPDATE `teams` SET captain = '{$_POST['captain']}' WHERE `user_id` = {$_POST['userid']}") or die(mysql_error()); } transfers.php (containts the form that uses the javascript and link to the JS) I have really no idea how to structure the files and calls in cakephp. Currently I have "Undefined index: cmd [APP/vendors/remote.php, line 230]" errors since I use $_POST['cmd'] (I placed remote.php in Vendors and included it, the JS was just included old fashion way, as a link and appears in the source code). How can I make this work? I'm sorry but I'm not familiar with AJAX and Cake... If you want a full look at the code, here it is: http://octavian.be/thecode.zip Thank you for reading and helping me out.

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• Problem with Spring security's logout

  - by uther-lightbringer

  Hello, I've got a problem logging out in Spring framework. First when I want j_spring_security_logout to handle it for me i get 404 j_spring_security_logout not found: sample-security.xml: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout/> </http> Sample url link to logout in JSP page: <a href="<c:url value="/j_spring_security_logout" />">Logout</a> When i try to use a custom JSP page i.e. I use login form for this purpose then I get better result at least it gets to login page, but another problem is that you dont't get logged off as you can diretcly type url that should be guarded buy you get past it anyway. Slightly modified from previous listings: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout logout-success-url="/login.jsp" /> </http> <a href="<c:url value="/login.jsp" />">Logout</a> Thank you for help

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• How to find if a branch is a locally tracked branch or user created local branch?

  - by Senthil A Kumar

  I have a remote tracking branch tracked locally in my local repository using 'git branch -b branch-name origin/branch-name'. My remote branch is test2/test2 (origin/branch-name) which is being tracked locally as test2. The origin is also named test2. I haven't checked-out my local tracking branch test2. When i do a 'git pull origin remote-branch:local-tracked-branch' i get this error [test2]$ git pull test2 test2:test2 From /gitvobs/git_bare/test2 ! [rejected] test2 - test2 (non fast forward) Whereas when i checkout my local tracking branch test2 and do pull 'git pull origin local-tracked-branch' i don't get the error and i do a pull using 'git pull test2 test2' From /gitvobs/git_bare/test2 * branch test2 - FETCH_HEAD Auto-merging a.txt Automatic merge failed; fix conflicts and then commit the result. i know that adding a + (git pull test2 +test2:test2) would help but it overwrites local changes. So how do i know which of my local branches are created by me locally using 'git branch new-branch-name' or tracked locally from remote branches using git branch -b branch-name origin/branch-name'?

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• jndi binding on jboss4.2.3 and ejb3

  - by broschb

  I am trying to deploy a stateless ejb on jboss 4.2.3 using ejb3 annotations. Everything builds and deploys correctly, and I do not get any errors when jboss starts up. However the ejb is not getting bound to any JNDI location for lookup when I look at the bindings in jboss. Below is what I have for my ejb. Remote @Remote public interface TestWebService { public String TestWebMethod(String param1, String param2); } Stateless EJB @Stateless @RemoteBinding(jndiBinding="TestWeb") @Remote(TestWebService.class) public class TestWebServiceBean implements TestWebService{ public String TestWebMethod(String param1, String param2) { System.out.println("HELLO "+param1+" "+param2); return "Welcome!!"; } } I have tried not having the @Remote and @RemoteBinding and it doesn't make a difference. I have also added and ejb-jar.xml file (which should not be needed with ejb3) and that does not appear to make a difference. Below is the output I see in the jboss log on startup. installing MBean: jboss.j2ee:ear=ejb_web_service_ear-0.0.1- SNAPSHOT.ear,jar=ejb_web_service-0.0.1-SNAPSHOT.jar,name=TestWebServiceBean,service=EJB3 with dependencies: 21:56:00,633 INFO [EJBContainer] STARTED EJB: com.tomax.ejb.TestWebServiceBean ejbName: TestWebServiceBean

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• Manage multiple UDP calls

  - by rayman

  Hi all, I would like to have an advice for this issue: I am using Jbos 5.1.0, EJB3.0 I have system, which sending requests via UDP'S to remote modems, and suppose to wait for an answer from the target modem. the remote modems support only UDP calls, therefor I o design asynchronous mechanism. (also coz I want to request X modems parallel) this is what I try to do: all calls are retrieved from Data Base, then each call will be added as a message to JMS QUE. let's say i will set X MDB'S on that que, so I can work asynchronous. now each MDB will send UDP request to the IP-address(remote modem) which will be parsed from the que message. so basicly each MDB, which takes a message is sending a udp request to the remote modem and [b]waiting [/b]for an answer from that modem. [u]now here is the BUG:[/u] could happen a scenario where MDB will get an answer, but not from the right modem( which it requested in first place). that bad scenario cause two wrong things: a. the sender which sent the message will wait forever since the message never returned to him(it got accepted by another MDB). b. the MDB which received the message is not the right one, and probablly if it was on a "listener" mode, then it supposed to wait for an answer from diffrent sender.(else it wouldnt get any messages) so ofcourse I can handle everything with a RETRY mechanisem. so both mdb's(the one who got message from the wrong sender, and the one who never got the answer) will try again, to do thire operation with a hope that next time it will success. This is the mechanism, mybe you could tell me if there is any design pattren, or any other effective solution for this problem? Thanks, ray.

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• How do I create a selection list in ASP.NET MVC?

  - by Gary McGill

  I have a database table that records what publications a user is allowed to access. The table is very simple - it simply stores user ID/publication ID pairs: CREATE TABLE UserPublication (UserId INTEGER, PublicationID INTEGER) The presence of a record for a given user & publication means that the user has access; absence of a record implies no access. I want to present my admin users with a simple screen that allows them to configure which publications a user can access. I would like to show one checkbox for each of the possible publications, and check the ones that the user can currently access. The admin user can then check or un-check any number of publications and submit the form. There are various publication types, and I want to group the similarly-typed publications together - so I do need control over how the publications are presented (I don't want to just have a flat list). My view model obviously needs to have a list of all the publications (since I need to display them all regardless of the current selection), and I also need a list of the publications that the user currently has access to. (I'm not sure whether I'd be better off with a single list where each item includes the publication ID and a yes/no field?). But that's as far as I've got. I've really no idea how to go about binding this to some checkboxes. Where do I start?

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• Ruby on Rails Associations

  - by Eef

  Hey all, I am starting to create my sites in Ruby on Rails these days instead of PHP. I have picked up the language easily but still not 100% confident with associations :) I have this situation: User Model has_and_belongs_to_many :roles Roles Model has_and_belongs_to_many :users Journal Model has_and_belongs_to_many :roles So I have a roles_users table and a journals_roles table I can access the user roles like so: user = User.find(1) User.roles This gives me the roles assigned to the user, I can then access the journal model like so: journals = user.roles.first.journals This gets me the journals associated with the user based on the roles. I want to be able to access the journals like so user.journals In my user model I have tried this: def journals self.roles.collect { |role| role.journals }.flatten end This gets me the journals in a flatten array but unfortunately I am unable to access anything associated with journals in this case, e.g in the journals model it has: has_many :items When I try to access user.journals.items it does not work as it is a flatten array which I am trying to access the has_many association. Is it possible to get the user.journals another way other than the way I have shown above with the collect method? Hope you guys understand what I mean, if not let me know and ill try to explain it better. Cheers Eef

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• Git from localhost to remotehost with a team of three

  - by Mark McDonnell

  Hi, I'm completely new to Git. I've only just worked out how to use Github in a basic way (e.g. push my local file changes to Github - so I've not done 'pulling' down of content from Github and 'merging' it into my localhost version or anything like that). I had a look over at this existing question - Git: localhost remote development remote production - but I think it may have been a bit advanced for me at this stage as I didn't quite understand the terminology that most of the people were using. What I would like to achieve is to have a local server set-up that my team of developers can all 'push' to/'pull' from etc. And then have that local server upload any updated files automatically to our web server so we could see the updates live in the browser. I'm happy to get a server set-up in the office running Mac OSX Server and then installing Git on it and then getting the devs to write a shell script to push to the remote server but only if it was fairly easy for the devs local git to push to this new local server. I'm not a network engineer so I don't know what would need to be set-up for that to work, I know obviously we could set-up the server to be accessible via a local ip address like 192.168.0.xxx but not sure how that works with pushing to a git repository on that server? Would that literally be something like doing this on my local machine: git remote add MyGitFile git://192.168.0.xxx/MyGitFile.git ? Any ideas or advice you can give to a total Git newbie trying to help his team get a better work flow. Kind regards, Mark

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• SQLAlchemy & Complex Queries

  - by user356594

  I have to implement ACL for an existing application. So I added the a user, group and groupmembers table to the database. I defined a ManyToMany relationship between user and group via the association table groupmembers. In order to protect some ressources of the app (i..e item) I added a additional association table auth_items which should be used as an association table for the ManyToMany relationship between groups/users and the specific item. item has following columns: user_id -- user table group_id -- group table item_id -- item table at least on of user_id and group_id columns are set. So it's possible to define access for a group or for a user to a specific item. I have used the AssociationProxy to define the relationship between users/groups and items. I now want to display all items which the user has access to and I have a really hard time doing that. Following criteria are used: All items which are owned by the user should be shown (item.owner_id = user.id) All public items should be shown (item.access = public) All items which the user has access to should be shown (auth_item.user_id = user.id) All items which the group of the user has access to should be shown. The first two criteria are quite straightforward, but I have a hard time doing the 3rd one. Here is my approach: clause = and_(item.access == 'public') if user is not None: clause = or_(clause,item.owner == user,item.users.contains(user),item.groups.contains(group for group in user.groups)) The third criteria produces an error. item.groups.contains(group for group in user.groups) I am actually not sure if this is a good approach at all. What is the best approach when filtering manytomany relationships? How I can filter a manytomany relationship based on another list/relationship? Btw I am using the latest sqlalchemy (6.0) and elixir version Thanks for any insights.

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• Modifying SQL Database on Shared Hosting

  - by apocalypse9

  I have a live database on a shared hosting server. I am making some major changes to my site's code and I would like to fix some stupid mistakes I made in initially designing the database. These changes involve altering the size of a large number of fields, and enforcing referential integrity between tables properly. I would like to make the changes on both my local test server and the remote server if possible. I should note that while I'm fairly comfortable with writing complex queries to handle data, I have very little experience modifying database structure without a graphical interface. I can access the remote database in the visual studio database explorer but I can not use that for anything other than data manipulation. I installed Sql Management Studio express last night and after 40+ crashes I gave up - I couldn't even patch the damn thing. The remote server is SQL 2005 / The MyLittleAdmin web interface is available. So my question is what is the best way to accomplish these changes. Is there a graphical interface I can use on the remote server? If not is there an easy way to copy the database to my local machine, fix it, and re upload? Finally if none of the above are viable does anyone have links to a decent info on fixing referential integrity via query? Sorry for the somewhat general question - I feel like I am making this far harder than it should be but after searching / trying all night i haven't gotten anywhere. Thanks in advance for the help. I really appreciate it. ...Also does anyone have a time machine I can borrow- I need to go kick my past self's ass for this.

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• Silverlight ClientAccessPolicy issue...I think

  - by Terrence

  Fisrt of all I have my ClientAccessPolicy.xml file in the root of my website. If I access my website using the public domain name like this: h t t p://www.mydomain.com and then go to the page where my SL control is, I get the spinning % numbers up until about 98%, then it quits and my SL control does not appear on the page. If I access my website using the machine name (website is at datacenter, we have vpn setup) like this: h t t p://machinename and then go to the page where my SL control is everything works fine. this must be a ClientAccess Policy issue don't your think? Or what DO you thnik the issue is? Thanks in advance. Here is the contents of my ClientAccessPolicy.xml file: <?xml version="1.0" encoding="utf-8" ?> <access-policy> <cross-domain-access> <policy> <allow-from http-request-headers="*"> <domain uri="*" /> </allow-from> <grant-to> <resource path="/" include-subpaths="true" /> </grant-to> </policy> </cross-domain-access> </access-policy>

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• Semaphore - What is the use of initial count?

  - by Sandbox

  http://msdn.microsoft.com/en-us/library/system.threading.semaphoreslim.aspx To create a semaphore, I need to provide an initial count and maximum count. MSDN states that an initial count is - The initial number of requests for the semaphore that can be granted concurrently. While it states that maximum count is The maximum number of requests for the semaphore that can be granted concurrently. I can understand that the maximum count is the maximum number of threads that can access a resource concurrently. But, what is the use of initial count? If I create a semaphore with an initial count of 0 and a maximum count of 2, none of my threadpool threads are able to access the resource. If I set the initial count as 1 and maximum count as 2 then only thread pool thread can access the resource. It is only when I set both initial count and maximum count as 2, 2 threads are able to access the resource concurrently. So, I am really confused about the significance of initial count? SemaphoreSlim semaphoreSlim = new SemaphoreSlim(0, 2); //all threadpool threads wait SemaphoreSlim semaphoreSlim = new SemaphoreSlim(1, 2);//only one thread has access to the resource at a time SemaphoreSlim semaphoreSlim = new SemaphoreSlim(2, 2);//two threadpool threads can access the resource concurrently

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• how to get email id from google api response

  - by user1726508

  i am able to get user information from Google API response using oath2 . But i do't know how to get those responses individually . Response i am getting from Google Api: * Access token: ya29.AHES6ZQ3QxKxnfAzpZasdfd23423NuxJs29gMa39MXV551yMmyM5IgA { "id": "112361893525676437860", "name": "Ansuman Singh", "given_name": "Ansuman", "family_name": "Singh", "link": "https://plus.google.com/112361893525676437860", "gender": "male", "birthday": "0000-03-18", "locale": "en" } Original Token: ya29.AHES6ZQ3QxKxnfAzpZu0lYHYu8sdfsdafdgMa39MXV551yMmyM5IgA New Token: ya29.AHES6ZQ3QxKxnfdsfsdaYHYu8TNuxJs29gMa39MXV551yMmyM5IgA But i want only "id" & "name" indiviually to save in my Database table. How can i do this? I got those above response/output By using the below code. public static void main(String[] args) throws IOException { ------------------------- ------------------------- ------------------------- String accessToken = authResponse.accessToken; GoogleAccessProtectedResource access = new GoogleAccessProtectedResource(accessToken, TRANSPORT, JSON_FACTORY, CLIENT_ID, CLIENT_SECRET, authResponse.refreshToken); HttpRequestFactory rf = TRANSPORT.createRequestFactory(access); System.out.println("Access token: " + authResponse.accessToken); String url = "https://www.googleapis.com/oauth2/v1/userinfo?alt=json&access_token=" + authResponse.accessToken; final StringBuffer r = new StringBuffer(); final URL u = new URL(url); final URLConnection uc = u.openConnection(); final int end = 1000; InputStreamReader isr = null; BufferedReader br = null; isr = new InputStreamReader(uc.getInputStream()); br = new BufferedReader(isr); final int chk = 0; while ((url = br.readLine()) != null) { if ((chk >= 0) && ((chk < end))) { r.append(url).append('\n'); } } System.out.print(""); System.out.println(); System.out.print(" "+ r ); //this is printing at once but i want them individually access.refreshToken(); System.out.println("Original Token: " + accessToken + " New Token: " + access.getAccessToken()); }

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• Combine MD5 hashes of multiple files

  - by user685869

  I have 7 files that I'm generating MD5 hashes for. The hashes are used to ensure that a remote copy of the data store is identical to the local copy. Unfortunately, the link between these two copies of the data is mind numbingly slow. Changes to the data are very rare but I have a requirement that the data be synchronized at all times (or as soon as possible). Rather than passing 7 different MD5 hashes across my (extremely slow) communications link, I'd like to generate the hash for each file and then combine these hashes into a single hash which I can then transfer and then re-calculate/use for comparison on the remote side. If the "combined hash" differs, then I'd start sending the 7 individual hashes to determine exactly which file(s) have been changed. For example, here are the MD5 hashes for the 7 files as of last week: 0709d609d69385255c496436eb50402c 709465a74411bd596595c7b9b158ae6a 4ab657320ef33e3d5eb498e4c13d41b7 3b49c6ab199994fd776bb63761414e72 0fc28c5a010fc3c06c0c930c88e31a15 c4ecd214662cac5aae0e53f6f252bf0e 8b086431e43148a2c2d943ba30d31cc6 I'd like to combine these hashes together such that I get a single unique value (perhaps another MD5 hash?) that I can then send to the remote system. On the remote system, I'd then perform the same calculation to determine if the data as a whole has been changed. If it has, then I'd start sending the individual hashes, etc. The most important factor is that my "combined hash" be short enough so that it uses less bandwidth than just sending all 7 hashes in the first place. I thought of writing the 7 MD5 hashes to a file and then hashing that file but is there a better way?

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• Getting Started with Boxee

  - by DigitalGeekery

  Boxee is a free Media PC application that runs on Windows, Mac, and Ubuntu Linux. With Boxee, you can integrate online video, music and pictures, with your own local media and social networking. Today we are going to take a closer look at Boxee and some of it’s features. Note: We used Windows 7 for this tutorial. Your experience on a Mac or Ubuntu Linux build may vary slightly. Hardware Requirements x86 (Intel/AMD processor) based system running at 1.0GHz or greater 512MB system memory (RAM) or more Video card capable of OpenGL 1.4, Direct X 9.0 Software Requirements Mac OS X 10.4+ (Intel based processor) Ubuntu Linux 9.04+ x86 only Windows XP / Vista / 7 (64 bit in Vista or 7) Installing Boxee Before downloading and installing Boxee, you’ll need to register for a free account. (See link below) Once your account is registered and verified, you’ll be able to log in and download the application. Installation is pretty straightforward…just take the defaults. Boxee will open in full screen mode and you’ll be prompted to login with your username and password. Before you login, you may want to take a moment to click on the “Guide” icon and learn a bit about navigating in Boxee. Some basic keyboard navigation is as follows. Move right, left, up, & down with the arrow keys. Hit “Enter” to make a selection, the forward slash key “\” to toggle between full screen and windowed mode, and “Esc” to go back to the previous screen. For Playback, the volume is controlled by plus & minus (+/-) keys, you can Play / Pause using the spacebar, and skip using the arrow keys. Boxee will also work with any infrared remote. If you have an iPhone or iPod Touch you can download software to enable them as a Boxee remote. If you’re using a mouse and keyboard, hover over the username and password boxes to enter your login credentials. If using a a remote, click your OK button and enter credentials with the on screen keyboard. Click “Done” when finished.   When you are ready to login, enter your credentials and click “Login.” On first login, you’ll be prompted to calibrate your screen. If you choose “Skip” you can always calibrate your screen later under Settings > Appearance > Screen. When Boxee opens, you’ll be greeted by the Home screen. To the left will be your Feeds. This will be any recommended content from friends on Boxee, and social networks such as Facebook and Twitter. Although, when you first login, it will mainly be info from the Boxee staff. You’ll have “Featured” content in the center and your Queue on the right. You’ll also have the Menu along the top.   Pop Up Menu The Pop Menu can be accessed by hitting the “Esc” key, or back on your remote. Depending on where you are located in Boxee, you may have to hit it a few time to “back out” to the Pop Up menu. From the Pop Up Menu, you can easily access any of the resources, settings, and favorites. Queue The Queue is your playlist of TV shows, movies, or Internet videos you wish to watch. When you find an offering you’d like to watch, select it and then click “Add to Queue.” The selected item will be added to your Queue and can be accessed at any time from the Menu. TV Show Library The TV Show library can contain files from your local hard drive or streaming content from the Web. Boxee pulls content from a variety of online locations such as Hulu and TV network sites. Click on the show to see which specific episodes are currently available. To search for your favorite shows, click on the yellow arrow to the left, or navigate to the left with your keyboard or remote. Enter your selection into the search box. My Apps By default, the “My Apps” section includes a list of the most popular apps, such as Netflix, Pandora, YouTube, and others. You can remove Apps from “My Apps,” or add new Apps from the Apps Library.   To access all the available Apps, click on the left arrow button, or click on the yellow arrow at the left, then select “App Library.” Choose an App from the Library and click it to open… … and then select “Add to My Apps.” Or, you can click start to play the App if you don’t wish to Add it to your “My Apps.”   Music, Pictures, and Movies Boxee will scan your PC for movies, pictures, and music. You can choose to scan specific folders by clicking on “Scan Media Folders…” … or from the Pop Up Menu, selecting Settings > Media, and then browsing for your media.   Conclusion Boxee to be a great way to integrate your local media with online streaming content. It can be run as an application on your home PC, or as a stand alone media PC. It should also be noted, however, that your access to online content will vary depending on your country. If you are a Windows Media Center user and and want to add the additional features of Boxee, check out our article on integrating Boxee with Windows 7 Media Center. Download Boxee Similar Articles Productive Geek Tips Integrate Boxee with Media Center in Windows 7Disable Fast User Switching on Windows XPOops! Sorry About the Feed ErrorsDisplay a list of Started Services from the Command Line (Windows)Feedburner to Google: Worst Transition Ever. 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