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  • scipy.io typeerror:buffer too small for requested array

    - by kartiku
    I have a problem in python. I'm using scipy, where i use scipy.io to load a .mat file. The .mat file was created using MATLAB. listOfFiles = os.listdir(loadpathTrain) for f in listOfFiles: fullPath = loadpathTrain + '/' + f mat_contents = sio.loadmat(fullPath) print fullPath Here's the error: Traceback (most recent call last): File "tryRankNet.py", line 1112, in demo() File "tryRankNet.py", line 645, in demo mat_contents = sio.loadmat(fullPath) File "/usr/lib/python2.6/dist-packages/scipy/io/matlab/mio.py", line 111, in loadmat matfile_dict = MR.get_variables() File "/usr/lib/python2.6/dist-packages/scipy/io/matlab/miobase.py", line 356, in get_variables getter = self.matrix_getter_factory() File "/usr/lib/python2.6/dist-packages/scipy/io/matlab/mio5.py", line 602, in matrix_getter_factory return self._array_reader.matrix_getter_factory() File "/usr/lib/python2.6/dist-packages/scipy/io/matlab/mio5.py", line 274, in matrix_getter_factory tag = self.read_dtype(self.dtypes['tag_full']) File "/usr/lib/python2.6/dist-packages/scipy/io/matlab/miobase.py", line 171, in read_dtype order='F') TypeError: buffer is too small for requested array The whole thing is in a loop, and I checked the size of the file where it gives the error by loading it interactively in IDLE. The size is (9,521), which is not at all huge. I tried to find if I'm supposed to clear the buffer after each iteration of the loop, but I could not find anything. Any help would be appreciated. Thanks.

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  • Python 3 with the range function

    - by Leif Andersen
    I can type in the following code in the terminal, and it works: for i in range(5): print(i) And it will print: 0 1 2 3 4 as expected. However, I tried to write a script that does a similar thing: print(current_chunk.data) read_chunk(file, current_chunk) numVerts, numFaces, numEdges = current_chunk.data print(current_chunk.data) print(numVerts) for vertex in range(numVerts): print("Hello World") current_chunk.data is gained from the following method: def read_chunk(file, chunk): line = file.readline() while line.startswith('#'): line = file.readline() chunk.data = line.split() The output for this is: ['OFF'] ['490', '518', '0'] 490 Traceback (most recent call last): File "/home/leif/src/install/linux2/.blender/scripts/io/import_scene_off.py", line 88, in execute load_off(self.properties.path, context) File "/home/leif/src/install/linux2/.blender/scripts/io/import_scene_off.py", line 68, in load_off for vertex in range(numVerts): TypeError: 'str' object cannot be interpreted as an integer So, why isn't it spitting out Hello World 490 times? Or is the 490 being thought of as a string? I opened the file like this: def load_off(filename, context): file = open(filename, 'r')

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  • Setting up Django on an internal server (os.environ() not working as expected?)

    - by monkut
    I'm trying to setup Django on an internal company server. (No external connection to the Internet.) Looking over the server setup documentation it appears that the "Running Django on a shared-hosting provider with Apache" method seems to be the most-likely to work in this situation. Here's the server information: Can't install mod_python no root access Server is SunOs 5.6 Python 2.5 Apache/2.0.46 I've installed Django (and flup) using the --prefix option (reading again I probably should've used --home, but at the moment it doesn't seem to matter) I've added the .htaccess file and mysite.fcgi file to my root web directory as mentioned here. When I run the mysite.fcgi script from the server I get my expected output (the correct site HTML output). But, it won't when trying to access it from a browser. It seems that it may be a problem with the PYTHONPATH setting since I'm using the prefix option. I've noticed that if I run mysite.fcgi from the command-line without setting the PYTHONPATH enviornment variable it throws the following error: prompt$ python2.5 mysite.fcgi ERROR: No module named flup Unable to load the flup package. In order to run django as a FastCGI application, you will need to get flup from http://www.saddi.com/software/flup/ If you've already installed flup, then make sure you have it in your PYTHONPATH. I've added sys.path.append(prefixpath) and os.environ['PYTHONPATH'] = prefixpath to mysite.fcgi, but if I set the enviornment variable to be empty on the command-line then run mysite.fcgi, I still get the above error. Here are some command-line results: >>> os.environ['PYTHONPATH'] = 'Null' >>> >>> os.system('echo $PYTHONPATH') Null >>> os.environ['PYTHONPATH'] = '/prefix/path' >>> >>> os.system('echo $PYTHONPATH') /prefix/path >>> exit() prompt$ echo $PYTHONPATH Null It looks like Python is setting the variable OK, but the variable is only applicable inside of the script. Flup appears to be distributed as an .egg file, and my guess is that the egg implementation doesn't take into account variables added by os.environ['key'] = value (?) at least when installing via the --prefix option. I'm not that familiar with .pth files, but it seems that the easy-install.pth file is the one that points to flup: import sys; sys.__plen = len(sys.path) ./setuptools-0.6c6-py2.5.egg ./flup-1.0.1-py2.5.egg import sys; new=sys.path[sys.__plen:]; del sys.path[sys.__plen:]; p=getattr(sys,'__egginsert',0); sy s.path[p:p]=new; sys.__egginsert = p+len(new) It looks like it's doing something funky, anyway to edit this or add something to my code so it will find flup?

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  • Problems in Linux Mint 13 MATE with NTFS partitions

    - by usr
    I'm using Linux Mint 13 MATE (32 bit). With Caja file manager (based on Nautilus 2.x) I can create, modify and remove folders and files on NTFS partitions whitout problems. But, for example, when I have a compressed file (.zip, .7z, ...) in a NTFS partition I can't extract it (with File-Roller, Peazip, ...). But I can extract the same file in a ext4 partition perfectly. What might the problem be? Are there (maybe) file permissions for each application?

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  • How can I transfer a file via XMPP using Python?

    - by Enchantner
    I'm using xmpppy library for my jabber remote administration bot, but I can't find how to send/receive a file and save it inside the directory specified. The documentation is poor and there isn't any examples, but I really want to make it. Can anyone show some examples or some links about it? Or maybe I should use an alternative xmpp bindings?

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  • What is a simple way to get ACID transactions with persistence on the local file system (in Java)?

    - by T.R.
    I'm working on a small (java) project where a website needs to maintain a (preferably comma-separated) list of registered e-mail addresses, nothing else, and be able to check if an address is in the list. I have no control over the hosting or the server's lack of database support. Prevayler seemed a good solution, but the website is a ghost town, with example code missing from just about everywhere it's supposed to be, so I'm a little wary. What other options are recommended for such a task?

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  • Create PHP DOM xml file and create a save file link/prompt without writing the file to the server wh

    - by Reed Richards
    I've created a PHP DOM xml piece and saved it to a string like this: <?php // create a new XML document $doc = new DomDocument('1.0'); ... ... ... $xmldata = $doc->saveXML(); ?> Now I can't use the headers to send a file download prompt and I can't write the file to the server, or rather I don't want the file laying around on it. Something like a save this file link or a download prompt would be good. How do I do it?

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  • Send all traffic over VPN connection not working Windows VPN host

    - by Adam Schiavone
    I am trying to get a mac (10.8) to connect to thru vpn to a server running Windows Server 2008 R2 pass all requests from the mac to the server. The VPN is setup and I can connect and access the server thru a web browser, but for all other sites, the DNS lookup fails. I have tried adding a DNS server to the VPN Host. ex. Lets say the the VPN server also hosts a website example.com. I connect to the VPN with my mac and point a browser to example.com and everything works fine. but when I point the browser to google.com it just sits there and will eventually come back with a DNS lookup failed message. HOWEVER: I tried running the command dig @myServersIpHere www.google.com. on the mac and it comes back with correct IP addresses. I really dont know what to do from here. How can I route all requests from my mac, thru my windows server via VPN?

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  • C++: ifstream::getline problem

    - by Jay
    I am reading a file like this: char string[256]; std::ifstream file( "file.txt" ); // open the level file. if ( ! file ) // check if the file loaded fine. { // error } while ( file.getline( string, 256, ' ' ) ) { // handle input } Just for testing purposes, my file is just one line, with a space at the end: 12345 My code first reads the 12345 successfully. But then instead of the loop ending, it reads another string, which seems to be a return/newline. I have saved my file both in gedit and in nano. And I have also outputted it with the Linux cat command, and there is no return on the end. So the file should be fine. Why is my code reading a return/newline? Thanks.

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  • Auto populate input based on file name with AngularJS

    - by LouieV
    I am playing around with AngularJS and have not been able to solve this problem. I have a view that has a form to upload a file to a node server. So far I have manage to do this using some directives and a service. I allow the user to send a custom name to the POST data if they desire. What I wan to accomplish is that when the user selects a file the filename models auto populates. My view looks like: <div> <input file-model="phpFile" type="file"> <input name="filename" type="text" ng-model="filename"> <button ng-click="send()">send</button> </div> file-model is my directive that allows the file to be assigned to a scope. myApp.directive('fileModel', ['$parse', function($parse) { return { restrict: 'A', link: function(scope, element, attrs) { var model = $parse.(attrs.fileModel); var modelSetter = model.assign; element.bind('change', function() { scope.$apply(function() { modelSetter(scope, element[0].files[0]); }); }); } }]); The service: myApp.service('fileUpload', ['$http', function($http){ this.uploadFileToUrl = function(file, uploadUrl, optionals) { var fd = new FormData(); fd.append('file', file); for (var key in file) { fd.append(key, file[key]); } for(var i = 0; i < optionals.length; i++){ fd.append(optionals[i].name, optionals[i].data); } }); }]); Here as you can see I pass the file, append its properties, and append any optional properties. In the controller is where I am having the troubles. I have tried $watch and using the file-model but I get the same error either way. myApp.controller('AddCtrl', function($scope, $location, PEberry, fileUpload){ //$scope.$watch(function() { // return $scope.phpFile; //},function(newValue, oldValue) { // $scope.filename = $scope.phpFile.name; //}, true); // if ($scope.phpFiles) { // $scope.filename = $scope.phpFiles.name; // } $scope.send = function() { var uploadUrl = "/files"; var file = $scope.phpFile; //var opts = [{ name: "uname", data: file.name }] fileUpload.uploadFileToUrl(file, uploadUrl); }; }); Thank you for your help!

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  • Ruby: output not saved to file

    - by Sophie
    I'm trying to give a file as input, have it changed within the program, and save the result to a file that is output. But the output file is the same as the input file. :/ Total n00b question, but what am I doing wrong?: puts "Reading Celsius temperature value from data file..." num = File.read("temperature.dat") celsius = num.to_i farenheit = (celsius * 9/5) + 32 puts "Saving result to output file 'faren_temp.out'" fh = File.new("faren_temp.out", "w") fh.puts farenheit fh.close

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  • Remote access not working without connected monitor

    - by winSharp93
    I am trying to configure a Windows Server 2008 as a Home Server for my personal use (mainly for storing documents, hosting source-control, etc.). The "server" consists of an Intel Atom 2700DC board and an Intel SSD. Configuring remote access to the server, I am confronted with a very strange problem: As long as a monitor is connected to my server, remote access works without any problems. However, when no monitor is connected at boot-time, remote access simply won't work (I keep getting errors when trying to connect that the remote server was not found or that remote access is disabled). Windows definitely boots when no monitor is connected as I receive a message asking me whether to enter safe mode when booting after powering the server down by plugging the power cord. When I plug in a monitor after boot, it stays turned off and remote desktop connections still fail. Do you have any ideas about what I could try?

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  • How do I turn an array of bytes back into a file and open it automatically with C#?

    - by Ace Grace
    Hi, I am writing some code to add file attachments into an application I am building. I have add & Remove working but I don't know where to start to implement open. I have an array of bytes (from a table field) and I don't know how to make it automatically open e.g. If I have an array of bytes which is a PDF, how do I get my app to automatically open Acrobat or whatever the currently assigned application for the extension is using C#?

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  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

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  • Symfony and uploadify

    - by Thomas
    Hi! I want to use uploadify with Symfony 1.4, but so far I couldn't. Uploadify loads correctly, I choose my files, it says that the files were successfully uploaded, but the are nowhere. (I'm doing this on localhost) Is there anybody who met this problem before? Thanks, Tom $file = $request->getParameter('file'); $filename = sha1($file->getOriginalName()).$file->getExtension($file->getOriginalExtension()); $file->save(sfConfig::get('sf_upload_dir').'/'.$filename);

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  • SQL Replication (subsciber) can't connect to publication

    - by a3code
    I have 2 Virtual Machines, One with MS SQL server 2008 R2, other with MS SQL Server 2012 Express.... On 1 I have configuration for replication (publication), and I would like to setup Express version like subscriber. but I can't to connect to publisher SQL Server replication requires the actual server name to make a connection to the server. Specify the actual server name, 'XXXX'. (Replication.Utilities) I have tried to cheat and added XXXX server name to hosts file, but it dos't help. Additianlly I used to run http://www.hagrin.com/332/fixing-sql-server-replication-requires-actual-server-name-make-connection-server-error action for setup publication in correct way What I need to do for successful connection ?

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  • Testing + production server and syncing MySQL data

    - by Matthew
    I have a web application running on LAMP with a testing server and a production server. Is there a standard practice for keeping the data on the testing server in sync with the production server? The data on the testing server gets out of date pretty quick and I feel like there must be an easier way than just dumping the production server and copying it onto the testing server every so often. It's not important that the data is in total sync, just that the testing server represents the production enviornment as accurately as possible.

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