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  • Gmail mail server

    - by Neveen
    Hello, I used use Google’s slick interface to get my mail and It’s always going to be here: https://mail.google.com/a/yourdomainhere.com I want to write python script that send mail so i failed to configure server settings smtp = smtplib.SMTP('what is mail server will be?', what is the port) smtp.login('username@yourdomainhere.com', 'pass') Please could any one help me ?? Thanks

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  • What is the opposite of Jquery .not - OR - How to I target href links that contain the following....

    - by stolkramaker
    Right. So here we go. I am currently using the following code to target all links and apply an iframe toolbar $("a[href^='http:']").not("[href*='www.domiain.com']").not("[href*='www.twitter.com']").each(function(){ var tempurl = 'http://www.domain.com/shiftbar/shiftbar.html?iframe='; var $this = $(this); var currenturl = this.getAttribute("href"); var href = tempurl + currenturl; $this.attr('href', href ); }); I need to do the same, but now for links that ONLY contain twitter $("a[href^='http:']").contains("[href*='www.twitter.com']").each(function(){ $this.attr("target", "_blank"); }); it doesn't work. I've tried .has .contains But I suppose I am not familiar with jquery enough at this point.

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  • Launch Activity with Intent Filter on Right Time

    - by user511853
    Hi. I want to launch my own media player application when I want to watch a video from Youtube. When I write android:scheme="http" and android:host="m.youtube.com" it is OK. But, it asks everywhere in m.youtube.com to open my app. So, it gets annoying. I tried to use pathPattern, pathPrefix and path to solve this but I didn't get ahead. All I want is clearly this: When the link is like "http://m.youtube.com/index?desktop_uri=%2F%gl=US#" the intent filter shouldn't launch my app. When the link is like "http://m.youtube.com/index?desktop_uri=%2F&gl=US#/watch?xl=xl_blazer&v=k3Cdqx1qFX8" my application should be launched. Is there anyone that can help me?

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  • Do not match if word appears in regex

    - by David542
    I have a url, and I want it to NOT match if the word 'season' is contained in the url. Here are two examples: CONTAINS SEASON, DO NOT MATCH 'http://imdb.com/title/tt0285331/episodes?this=1&season=7&ref_=tt_eps_sn_7' DOES NOT CONTAIN SEASON, MATCH 'http://imdb.com/title/tt0285331/ Here is what I have so far, but I'm afraid the .+ will match everything until the end. What would be the correct regex to use here? r'http://imdb.com/title/tt(\d)+/.+^[season].+'

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  • How to get the domain value for a cookie in Javascript?

    - by Wabbitseason
    Using Javascript I'd like to get the domain value for a specific cookie. Is this possible? If so, how? To clarify: I'm not looking for the value of the cookie. I'm on "subdomain.domain.com" and I need to remove a cookie whose name is known but its domain value is something like ".domain.com". In short: I'd like to get the value of ".domain.com".

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  • Problems using Custom Layout in XML

    - by Kevin
    I've created a new GridLayout class that I want to use in an XML File. The class is in another project. I've created the attrs.xml file in the other project with my properties but when the constructor gets called with the AttributeSet, none of the values are set. In my xml for my screen layout, I refer to the layout with the following: xmlns:gridLayout="@com.mastertechsoftware.AndroidUtil:http://schemas.android.com/apk/res/com.mastertechsoftware.AndroidUtil" Not sure if that is right. I have the attrs.xml file being compiled to R.java in com/mastertechsoftware/AndroidUtil. All the right styleable values are there. In my constructor, I use: TypedArray a = c .obtainStyledAttributes(attrs, R.styleable.GridLayout); this.numRows = a.getInt(R.styleable.GridLayout_numRows, -1); Nothing comes back (-1 does but that means nothing is there) If I use int n = a.getIndexCount(); I get 0.

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  • Simple ant build script that supports src/ and test/?

    - by M-x
    Currently I use an IDE for all my builds and unit tests. Now I have a need to use ant. I found a few simple ant build.xml scripts but they didn't support a separate Junit test/ dir. My projects are structured as follows: src/ com/foo/ com/bar/ test/ -- Mirror of src/, with all *Test.java files. com/foo/ com/bar/ lib/ -- All Java libs, including junit 4. How can a construct a small ant script that builds my src/ and test/ Java classes then runs all my JUnit tests?

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  • Converting IIS Redirect to .htaccess

    - by user1641321
    I am having trouble getting the rewrite to work on an apache server. The end result is so i can make subdomains on the fly just by adding a directory. For example anysubdomain.domain.com will redirect to domain.com/anysubdomain and still appear as anysubdomain.domain.com. Is there anyone out there that convert this for me? <rewrite> <rules> <rule name="Subdomain Redirect" patternSyntax="ECMAScript" stopProcessing="true"> <match url="^(.*)$" /> <conditions trackAllCaptures="true"> <add input="{HTTP_HOST}" pattern="^www\.obdevsite\.com" negate="true" /> <add input="{HTTP_HOST}" pattern="^(.*)\.obdevsite\.com" /> <add input="{REQUEST_URI}" pattern="^(.*)$" /> </conditions> <action type="Rewrite" url="/{C:1}/{C:2}" appendQueryString="false" /> </rule> </rules> </rewrite>

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  • How to get final destination URL from AJAX?

    - by Maurice Lam
    When I do an XMLHttpRequest, I always get redirected automatically to the URL (presumably by the headers of the response). For example, if I query "http://www.stackoverflow.com" I will be redirected to "http://stackoverflow.com". How can I get that final URL? (http://stackoverflow.com/ in the example) I checked in the response headers but I cannot seem to find it. (I just used the GET/POST method not HEAD).

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  • Unable to open the landing page on server

    - by Zerotoinfinite
    Hi Experts, I am using asp.net 3.5. My Hosting provider has given me a folder to upload my publish application, now when I am entering www.mysite.com, I am not getting my homepage , but when I am running the same application on my local I am getting home page. Please let me know what I have to modify so that when usertype www.mysite.com it will open like www.mysite.com/homepage.aspx Please help. Thanks in advance

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  • Subdomain Routing Rules (using chaining) Broke after upgrading to Zend Framework 1.9.5, but only for

    - by Dan
    I asked a similar question months ago (see How do I write Routing Chains for a Subdomain in Zend Framework in a routing INI file?), on how to write chaining rules in an app.ini format. The answer to this question worked wonderfully! Now, however, I have upgraded to the latest version of the Zend Framework 1.9.5 (I needed to upgrade for another issue) and now my subdomains no longer work! To clarify, if I visit subdomain.domain.com, it does not recognize my rule. However, if I visit subdomain.domain.com/somepage/ it does recognize my routing rule. Here is my code: ;; the following is apparently being ignored, and does not work routes.manager.type = "Zend_Controller_Router_Route_Hostname" routes.manager.route = "manager.sitename.com" routes.manager.defaults.module = "manager" ;; this is not being ignored and works! routes.manager.chains.settings.type = "Zend_Controller_Router_Route_Static" routes.manager.chains.settings.route = "/settings" routes.manager.chains.settings.defaults.controller = "manager" routes.manager.chains.settings.defaults.action = "settings" So for example, if I go to manager.sitename.com, it just redirects to my default index and controller (does not access the module, $this-getRequest()-getModuleName() is blank). However, if I go to manager.sitename.com/settings, the page comes up! This app.ini configuration works fine in ZF 1.7.8, But now since I upgraded to 1.9.5, it no longer works. I have tried adding routes.manager.defaults.controller = "manager" and routes.manager.defaults.action = 'index" to my configuration as well, but this didn't work. There is not much out there on the internet with chaining and app.ini dealing with Zend Framework. Any help on this issue would be greatly appreciated.

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  • Parsing Domain From URL In PHP

    - by zuk1
    I need to build a function which parses the domain from a url. So: http://google.com/dhasjkdas/sadsdds/sdda/sdads.html or http://www.google.com/dhasjkdas/sadsdds/sdda/sdads.html Would become "google.com" and http://google.co.uk/dhasjkdas/sadsdds/sdda/sdads.html would become "google.co.uk"

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  • Need help on how to setup package structure and project

    - by jax
    I am new to Java and am making a license generator. This is my current setup. com.example.licensegenerator.client (used by the client application) :LicenseLoader (no Main method) :LicenseDownloader (no Main method) com.example.licensegenerator.server.keys (used by the server) :ProductKeyGenerator(Main method) com.example.licensegenerator.server.license (used on the server also) :LicenseGenerator(Main method) com.example.licensegenerator.lib (Shared classes between client and server) :Contants (no main) Now I have a few questions. Is it OK to have multiple Main() methods in a single project? Will I be able to compile them to different .jar files? (In this case I need two different jars for the server) Is there a better way to setup the packages? And a totally unrelated question, with exceptions, is it better to handle them right then and there or throw them and let the main method catch them all (the program cannot recover if an error occurs)

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  • [perl] Efficient processing of large text

    - by jesper
    I have text file that contains over one million urls. I have to process this file in order to assign urls to groups, based on host address: { 'http://www.ex1.com' = ['http://www.ex1.com/...', 'http://www.ex1.com/...', ...], 'http://www.ex2.com' = ['http://www.ex2.com/...', 'http://www.ex2.com/...', ...] } My current basic solution takes about 600mb of RAM to do this (size of file is about 300mb). Could You provide some more efficient ways? My current solution simply reads line by line, extracts host address by regex and put url into hash.

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  • Configure main domain and sub domain with diffrent resourcs in apache server

    - by Ritesh Patadiya
    I have an issue to creating a sub domain in apache server. Normally we can do that by following way. <VirtualHost *:80> ServerName www.maindomain.com ServerAlias *.maindomain.com DocumentRoot "/home/abc/xyz" <Directory "/home/abc/xyz"> AllowOverride All Allow from All </Directory> </VirtualHost> In above example both main and sub domain share same Directory. But my requirement is main domain have its own resource and rest of sub domains have other resource. I want to do something like this. <VirtualHost *:80> ServerName www.maindomain.com DocumentRoot "/home/abc/xyz" <Directory "/home/abc/xyz"> AllowOverride All Allow from All </Directory> </VirtualHost> <VirtualHost *:80> ServerName xyz.maindomain.com ServerAlias *.maindomain.com DocumentRoot "/home/ghi/pqr" <Directory "/home/ghi/pqr"> AllowOverride All Allow from All </Directory> </VirtualHost> Above thing didn't work for me

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  • Virtualhost subdomain Internal Server Error

    - by Andrew
    I am trying to set up user generated sub domains for my PHP application. When I go to sub.domain.com and if I upload an index.html file it works fine, however if I use index.php it gives me a "Internal Server Error 500" message I have done the steps below to get subdomains working STEP 1: Edited my DNZ zone file and appended *.domain.com. IN A 91.111.111.111 STEP 2: Appended to httpd.conf the following: <VirtualHost 91.111.111.111:80> ServerName domain.com ServerAlias *.domain.com DocumentRoot /home/domain/public_html/sub <Directory "/home/domain/public_html/sub"> Options -Indexes Options FollowSymLinks AllowOverride All </Directory> </VirtualHost> Step 3: Tested by uploading an index.html file to the document directory in step 2, and works fine. Tried with an index.php gives a internal server error and then I looked into Apache error log and shows error for a redirect loop more than 10 times Update: getting this error: No user or group set - set suPHP_UserGroup Any ideas why I can not use any .php file in the directory?

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  • HTACCESS redirection with a word replacement in url

    - by Marwen
    I'm having trouble with this reg expression which i belive is correct, but it is not working. What im trying to do is redirect bunch of urls containing a specific string like this: http://www.example.com/**undesired-string**_another-string to http://www.example.com/**new-string**_another-string and http://www.example.com/folder/**undesired-string**/another-string to http://www.example.com/folder/**new-string**/another-string So i have this code in the .htaccess: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteRule (.+)+(undesired-string)+(.+) $1new-string$2 [R=301,L] </IfModule> This should replace ANY undesired-string in any url to new-string, but it is not working, any idea why ? Thank you

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  • CFPreferences creates multiple files

    - by Nobik
    I have only a little question: Why the CFPreferences-API creates multiple files in my UserPrefs-Directory? All the files have my Bundle-Identifier as name and all (except the one, the original) have added a suffix like this: com.myComp.myApp.plist <- (only this plist-file should be created) com.myComp.myApp.plist.0qzcicc com.myComp.myApp.plist.8dhjfht

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  • How do I make a URL text a link?

    - by jpjp
    Say on Facebook or Twitter, when I type "www.google.com" and submit it, it becomes a link. How do I code this in PHP? Do I use regular expressions to get where the www starts and the .com ends? Is this how they do it? <?PHP //some regular expression to get www and .com part $link="<a href='$url'>$url</a>"; echo $link; ?> How do I write a regular expression to get the "www" and ".com" part? And for twitter's @obama, obama would become a link to obama's site. What regular expression do they use to get the text after the @ and before the space?

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  • exim redirect mail to a script

    - by DevilWAH
    I am looking to set up a mail relay so that any mail sent to for example @example.com gets parsed be a PHP script. I know to do this for indervidual address I could do some thing like (from the following web site http://evolt.org/incoming_mail_and_php) Con figure an Aliases such as script: |/our/script.php then any emails sent to script@example.com will be passed to the script given.. but how can I make it that every email to @example.com is passed to the script? thank you

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  • Is it possible to make a div 50px less than 100% in CSS?

    - by Derek
    Exact duplicate > http://stackoverflow.com/questions/11103728/css-to-achieve-width100-150px > http://stackoverflow.com/questions/8877827/how-can-an-element-have-a-width-of-100-50px-using-only-css > http://stackoverflow.com/questions/651317/div-width-100-minus-fixed-amount-of-pixels > http://stackoverflow.com/questions/899107/how-can-i-do-width-100-100px-in-css Is it possible to make a div 50px less than 100% in pure CSS? I want the <div> to be only 50px less than 100%. I don't want any JavaScript.

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  • java version 1.6 applet requistes

    - by gautam
    Hi, I upgraded my java version 1.5 to 1.6. My applet is not working what are prequesties ? i have changed classid and MIME type to 1.6. Its giving exception: load: class com.timer.AppletGenerator.class not found. java.lang.ClassNotFoundException: com.timer.AppletGenerator.class at sun.plugin2.applet.Applet2ClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.plugin2.applet.Plugin2ClassLoader.loadCode(Unknown Source) at sun.plugin2.applet.Plugin2Manager.createApplet(Unknown Source) at sun.plugin2.applet.Plugin2Manager$AppletExecutionRunnable.run(Unknown Source) at java.lang.Thread.run(Unknown Source) Caused by: java.io.IOException: open HTTP connection failed:http://localhost:8080/Perfmonitoringgui-000.004.000/com/timer/AppletGenerator/class.class at sun.plugin2.applet.Applet2ClassLoader.getBytes(Unknown Source) at sun.plugin2.applet.Applet2ClassLoader.access$000(Unknown Source) at sun.plugin2.applet.Applet2ClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) ... 7 more Exception: java.lang.ClassNotFoundException: com.timer.AppletGenerator.class Thanks

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  • What is the perfect skill set for a software engineer? [closed]

    - by Sergey
    Of course, except technology stack. I'm asking about more fundamental skills such as design patterns or math. POSSIBLE DUPLICATES: http://stackoverflow.com/questions/76364/what-is-the-single-most-effective-thing-you-did-to-improve-your-programming-skill http://stackoverflow.com/questions/132798/what-should-every-programmer-know http://stackoverflow.com/questions/1177724/what-soft-skills-make-a-great-programmer

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