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  • How to write a Python 2.6+ script that does gracefully fail with older pyhton?

    - by Sorin Sbarnea
    I'm using the new print from Python 3.x and I observed that the following code does not compile due to the end=' '. from __future__ import print_function import sys if sys.hexversion < 0x02060000: raise Exception("py too old") ... print("x",end=" ") # fails to compile with py24 How can I continue using the new syntax but make the script fails nicely? Is it mandatory to call another script and use only safe syntax in this one?

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  • Is there some way to make variables like $a and $b in regard to strict?

    - by Axeman
    In light of Michael Carman's comment, I have decided to rewrite the question. Note that 11 comments appear before this edit, and give credence to Michael's observation that I did not write the question in a way that made it clear what I was asking. Question: What is the standard--or cleanest way--to fake the special status that $a and $b have in regard to strict by simply importing a module? First of all some setup. The following works: #!/bin/perl use strict; print "\$a=$a\n"; print "\$b=$b\n"; If I add one more line: print "\$c=$c\n"; I get an error at compile time, which means that none of my dazzling print code gets to run. If I comment out use strict; it runs fine. Outside of strictures, $a and $b are mainly special in that sort passes the two values to be compared with those names. my @reverse_order = sort { $b <=> $a } @unsorted; Thus the main functional difference about $a and $b--even though Perl "knows their names"--is that you'd better know this when you sort, or use some of the functions in List::Util. It's only when you use strict, that $a and $b become special variables in a whole new way. They are the only variables that strict will pass over without complaining that they are not declared. : Now, I like strict, but it strikes me that if TIMTOWTDI (There is more than one way to do it) is Rule #1 in Perl, this is not very TIMTOWDI. It says that $a and $b are special and that's it. If you want to use variables you don't have to declare $a and $b are your guys. If you want to have three variables by adding $c, suddenly there's a whole other way to do it. Nevermind that in manipulating hashes $k and $v might make more sense: my %starts_upper_1_to_25 = skim { $k =~ m/^\p{IsUpper}/ && ( 1 <= $v && $v <= 25 ) } %my_hash ;` Now, I use and I like strict. But I just want $k and $v to be visible to skim for the most compact syntax. And I'd like it to be visible simply by use Hash::Helper qw<skim>; I'm not asking this question to know how to black-magic it. My "answer" below, should let you know that I know enough Perl to be dangerous. I'm asking if there is a way to make strict accept other variables, or what is the cleanest solution. The answer could well be no. If that's the case, it simply does not seem very TIMTOWTDI.

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  • php extending but with a new constructor...possible?

    - by Patrick
    I have a class: class test { function __construct() { print 'hello'; } function func_one() { print 'world'; } } what I would like to do is a have a class that sort of extends the test class. I say 'sort of', because the class needs to be able to run whatever function the test class is able to run, but NOT run the construct unless I ask it to. I do not want to override the construct. Anyone has any idea how to achieve this?

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  • Merge decorator function as class

    - by SyetemHog
    How to make this merge function as class decorator? def merge(*arg, **kwarg): # get decorator args & kwargs def func(f): def tmp(*args, **kwargs): # get function args & kwargs kwargs.update(kwarg) # merge two dictionaries return f(*args, **kwargs) # return merged data return tmp return func Usage: @other_decorator # return *args and **kwarg @merge(list=['one','two','three']) # need to merge with @other_decorator def test(*a, **k): # get merged args and kwargs print 'args:', a print 'kwargs:', k

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  • Specifics of List Membership

    - by phasetwenty
    How does Python (2.6.4, specifically) determine list membership in general? I've run some tests to see what it does: def main(): obj = fancy_obj(arg='C:\\') needle = (50, obj) haystack = [(50, fancy_obj(arg='C:\\')), (1, obj,), needle] print (1, fancy_obj(arg='C:\\'),) in haystack print needle in haystack if __name__ == '__main__': main() Which yields: False True This tells me that Python is probably checking the object references, which makes sense. Is there something more definitive I can look at?

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  • Enable "Current Page" in PrintDialog

    - by mizipzor
    Im using a System.Windows.Controls.PrintDialog to let the user print one or more pages from my application. This is what I currently got: PrintDialog printDialog = new PrintDialog(); printDialog.PageRangeSelection = PageRangeSelection.AllPages; printDialog.UserPageRangeEnabled = true; if (printDialog.ShowDialog() == true) { // do print ... } Im looking for the option to enable the Current Page radio button in the dialog. How to enable it?

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  • Unable to get set intersection to work

    - by chavanak
    Sorry for the double post, I will update this question if I can't get things to work :) I am trying to compare two files. I will list the two file content: File 1 File 2 "d.complex.1" "d.complex.1" 1 4 5 5 48 47 65 21 d.complex.10 d.complex.10 46 6 21 46 109 121 192 192 TI am trying to compare the contents of the two file but not in a trivial way. I will explain what I want with an example. If you observe the file content I have typed above, the d.complex.1 of file_1 has "5" similar to d.complex.1 in file_2; the same d.complex.1 in file_1 has nothing similar to d.complex.10 in file_2. What I am trying to do is just to print out those d.complex. which has nothing in similar with the other d.complex. Consider the d.complex. as a heading if you want. But all I am trying is compare the numbers below each d.complex. and if nothing matches, I want that particular d.complex. from both files to be printed. If even one number is present in both d.complex. of both files, I want it to be rejected. My Code: The method I chose to achieve this was to use sets and then do a difference. Code I wrote was: first_complex=open( "file1.txt", "r" ) first_complex_lines=first_complex.readlines() first_complex_lines=map( string.strip, first_complex_lines ) first_complex.close() second_complex=open( "file2.txt", "r" ) second_complex_lines=second_complex.readlines() second_complex_lines=map( string.strip, second_complex_lines ) second_complex.close() list_1=[] list_2=[] res_1=[] for line in first_complex_lines: if line.startswith( "d.complex" ): res_1.append( [] ) res_1[-1].append( line ) res_2=[] for line in second_complex_lines: if line.startswith( "d.complex" ): res_2.append( [] ) res_2[-1].append( line ) h=len( res_1 ) k=len( res_2 ) for i in res_1: for j in res_2: print i[0] print j[0] target_set=set ( i ) target_set_1=set( j ) for s in target_set: if s not in target_set_1: if s[0] != "d": print s The above code is giving an output like this (just an example): d.complex.1.dssp d.complex.1.dssp 1 48 65 d.complex.1.dssp d.complex.10.dssp 46 21 109 What I would like to have is: d.complex.1 d.complex.1 (name from file2) d.complex.1 d.complex.10 (name from file2) I am sorry for confusing you guys, but this is all that is required. I am so new to python so my concept above might be flawed. Also I have never used sets before :(. Can someone give me a hand here?

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  • urllib open - how to control the number of retries

    - by user1641071
    how can i control the number of retries of the "opener.open"? for example, in the following code, it will send about 6 "GET" HTTP requests (i saw it in the Wireshark sniffer) before it goes to the " except urllib.error.URLError" success/no-success lines. password_mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm() password_mgr.add_password(None,url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) opener = urllib.request.build_opener(handler) try: resp = opener.open(url,None,1) except urllib.error.URLError as e: print ("no success") else: print ("success!")

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  • perl, module variable

    - by Mike
    I don't really understand how scoping works in perl modules. This doesn't print anything. I would like it if running a.pl printed 1 b.pm $f=1; a.pl use b; print $f

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  • passing back answers in prolog

    - by AhmadAssaf
    i have this code than runs perfectly .. returns a true .. when tracing the values are ok .. but its not returning back the answer .. it acts strangely when it ends and always return empty list .. uninstantiated variable .. test :- extend(4,12,[4,3,1,2],[[1,5],[3,4],[6]],_ExtendedBins). %printing basic information about the extend(NumBins,Capacity,RemainingNumbers,BinsSoFar,_ExtendedBins) :- getNumberofBins(BinsSoFar,NumberOfBins), msort(RemainingNumbers,SortedRemaining),nl, format("Current Number of Bins is :~w\n",[NumberOfBins]), format("Allowed Capacity is :~w\n",[Capacity]), format("maximum limit in bin is :~w\n",[NumBins]), format("Trying to fit :~w\n\n",[SortedRemaining]), format("Possible Solutions :\n\n"), fitElements(NumBins,NumberOfBins, Capacity,SortedRemaining,BinsSoFar,[]). %this is were the creation for possibilities will start %will check first if the number of bins allowed is less than then %we create a new list with all the possible combinations %after that we start matching to other bins with capacity constraint fitElements(NumBins,NumberOfBins, Capacity,RemainingNumbers,Bins,ExtendedBins) :- ( NumberOfBins < NumBins -> print('Creating new set: '); print('Sorry, Cannot create New Sets')), createNewList(Capacity,RemainingNumbers,Bins,ExtendedBins). createNewList(Capacity,RemainingNumbers,Bins,ExtendedBins) :- createNewList(Capacity,RemainingNumbers,Bins,[],ExtendedBins), print(ExtendedBins). createNewList(0,Bins,Bins,ExtendedBins,ExtendedBins). createNewList(_,[],_,ExtendedBins,ExtendedBins). createNewList(Capacity,[Element|Rest],Bins,Temp,ExtendedBins) :- conjunct_to_list(Element,ListedElement), append(ListedElement,Temp,NewList), sumlist(NewList,Sum), (Sum =< Capacity, append(ListedElement,ExtendedBins,Result); Capacity = 0), createNewList(Capacity,Rest,Bins,NewList,Result). fit(0,[],ExtendedBins,ExtendedBins). fit(Capacity,[Element|Rest],Bin,ExtendedBins) :- conjunct_to_list(Element,Listed), append(Listed,Bin,NewBin), sumlist(NewBin,Sum), (Sum =< Capacity -> fit(Capacity,Rest,NewBin,ExtendedBins); Capacity = 0, append(NewBin,ExtendedBins,NewExtendedBins), print(NewExtendedBins), fit(0,[],NewBin,ExtendedBins)). %get the number of bins provided getNumberofBins(List,NumberOfBins) :- getNumberofBins(List,0,NumberOfBins). getNumberofBins([],NumberOfBins,NumberOfBins). getNumberofBins([_List|Rest],TempCount,NumberOfBins) :- NewCount is TempCount + 1, %calculate the count getNumberofBins(Rest,NewCount,NumberOfBins). %recursive call %Convert set of terms into a list - used when needed to append conjunct_to_list((A,B), L) :- !, conjunct_to_list(A, L0), conjunct_to_list(B, L1), append(L0, L1, L). conjunct_to_list(A, [A]). Greatly appreciate the help

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • UnicodeDecodeError in pyton 2.7

    - by user2913962
    i try to write this code to process Arabic language by python import codecs file = codecs.open("C:\Python27\CCA_raw_utf8.txt","r","utf-8") text= file.read() #################################### print "\n "," --------------------------------------------" text=text[1:] words=text.split() for w in words: if w == unicode ("?????","utf-8"): print w but it doesn't and take error " if w == unicode ("?????","utf-8"): UnicodeDecodeError: 'utf8' codec can't decode byte 0xc7 in position 0: invalid continuation byte " why program gives this result and how we can correct that??

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  • Python: for statement behavior

    - by BandGap
    Hi all. My question concerns the output of this statement: for x in range(4), y in range(4): print x print y Results in: [0, 1, 2, 3] 2 True 2 It seems there is a comparison involved, I just can't figure out why the output is structured like this.

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  • Count numbers in words.

    - by bachchan
    I need an assembler 8080 software which counts words (delimited by space) which have more than two number in it. Example : this sh0uld b3 l1ke th1s would print : 0 words but Example : this sh0uld b3 l1k3 th1s f000k would print : 2 words <- word l1k3 contain number 1,3 and f000k number 0,0,0 the output should be displayer in hexadecimal format (optional)

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  • Space as grouping separator in printf

    - by blekione
    I know how to use comma in printf as grouping separator to print value in format like 1,000,000.00 to print it that way I'm using command System.out.printf ("%,.2f", value); but how to use space as grouping separator to format value like 1 000 000.00 I tried to find solution but solutions with using DecimalFormat look at now to complicate for me (beginner level). Is there as easy way as in example with comma to do it?

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  • Why does my table values return nil when i clearly initialized them?

    - by user3717078
    players = {} function newPlayer(name) players[name]={x = 200, y = 100} --assign each player their x and y coordinates, which is x: 200 and y: 100 end function checkPosition(name?) -- Do i need a parameter? if players[name].x == 200 and players[name].y == 100 then --says players[name].x is a nil value print("good") else print("bad") end end Error: attempt to index ? (a nil value) Current Situation: The code above says players[name].x is a nil value, I would like to know why since i thought i assigned it in the function newPlayer.

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  • Perl, foreach order

    - by Mike
    Does Perl's foreach loop operator require that the list items be presented in order? For example my @a=(1,2,3); foreach my $item (@a) { print $item; } will always print 1 2 3? I suspect so, but I can't find it documented.

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