Search Results

Search found 17563 results on 703 pages for 'remote login'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 100/703 | < Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >

  • Configure X connections over TCP without using an X connection

    - by Darren Cook
    I want to run a GUI application on a remote machine I only have ssh access to. I don't need to, or want to, see the GUI window. (I know I could use something like ssh -C -X remote_server if I wanted the GUI to be on my client.) I know X is running on the remote machine, as ps shows this: root ... /usr/bin/Xorg :0 -br -audit 0 -auth /var/gdm/:0.Xauth -nolisten tcp vt7 I set DISPLAY=:0.0 but I then get "Xlib: connection to ":0.0" refused by server" when I try to use it. At Get remote x display working in linux without ssh tunneling and Xserver doesn't work unless DISPLAY=0.0 I see the advice to use gdmsetup to allow X to listen on TCP. But, gdmsetup is a GUI application! And trying to run it over ssh -X did not work ("X11 connection rejected because of wrong authentication"). So, is there a text file I can edit to remove -nolisten? And, after editing it, how do I safely restart X, remotely? (There is other stuff running on this machine, so requesting a reboot is possible, but undesirable.) If not, should gdmsetup be able to run over ssh and I should persevere in that direction? UPDATE: I had to do the ssh -X session as root (ssh as a normal user, then sudo or su, does not work.) So, I did the edit with gdmsetup. I then restarted X with gdm-restart. I've also done xhost + from that ssh -X session. The ps line no longer shows the -nolisten tcp part. But still no luck connecting to it, with either DISPLAY=:0 or DISPLAY=localhost:0

    Read the article

  • Autologin on Ubuntu Server

    - by hekevintran
    I have a machine running Ubuntu Server. It has only a command-line interface. How can I make the system login with a specific user automatically (I don't want to type the username/password). I know that this is insecure and I don't care.

    Read the article

  • Tried to join a workgroup but now can't loginto system

    - by Ali
    Help - I tried to join a workgroup but now all of a sudden I can't log into my system. I get an account not found error - also for some reason when I click the options button on the log in screen I can't see the domain option at all.. whats going on! I can't even log in using the adminstrator login or anything!!

    Read the article

  • SSH closing by itself - root works fine

    - by Antti
    I'm trying to connect to a server but if i use any other user than root the connection closes itself after a successful login: XXXXXXX:~ user$ ssh -v [email protected] OpenSSH_5.2p1, OpenSSL 0.9.8l 5 Nov 2009 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to XXXXXXX.XXXXXX.XXX [xxx.xxx.xxx.xxx] port 22. debug1: Connection established. debug1: identity file /Users/user/.ssh/identity type -1 debug1: identity file /Users/user/.ssh/id_rsa type -1 debug1: identity file /Users/user/.ssh/id_dsa type 2 debug1: Remote protocol version 2.0, remote software version OpenSSH_4.3 debug1: match: OpenSSH_4.3 pat OpenSSH_4* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.2 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'XXXXXXX.XXXXXX.XXX' is known and matches the RSA host key. debug1: Found key in /Users/user/.ssh/known_hosts:12 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: publickey debug1: Offering public key: /Users/user/.ssh/woo_openssh debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Offering public key: /Users/user/.ssh/sidlee.dsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Trying private key: /Users/user/.ssh/identity debug1: Trying private key: /Users/user/.ssh/id_rsa debug1: Offering public key: /Users/user/.ssh/id_dsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: password [email protected]'s password: debug1: Authentication succeeded (password). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 29 01:41:51 2010 from 193.67.179.2 debug1: client_input_channel_req: channel 0 rtype exit-status reply 0 debug1: channel 0: free: client-session, nchannels 1 Connection to XXXXXXX.XXXXXX.XXX closed. Transferred: sent 2976, received 2136 bytes, in 0.5 seconds Bytes per second: sent 5892.2, received 4229.1 debug1: Exit status 1 If i log in as root the exact same way it works as expected. I've added the users i want to log in with to a group (sshusers) and added that group to /etc/sshd_config: AllowGroups sshusers I'm not sure what to try next as i don't get a clear error anywhere. I would like to enable specific accounts to log in so that i can disable root. This is a GridServer/Media Temple (CentOS).

    Read the article

  • How can I log in with my Google OpenID

    - by compie
    I'm trying to login to www.refactormycode.com with my Google OpenID. But the site keeps saying: "Sorry, the OpenID server couldn't be found" What am I doing wrong? I have tried https://www.google.com/accounts/o8/id and http://google.com/profiles/me

    Read the article

  • Override LDAP shell

    - by Incredible
    I have a LDAP server and a predefined shell (bash) set in it. But there are some machine on which I want a different shell to be used whenever user login to that instead of the shell stored in LDAP. How can I do this?? Can someone give me some direction in this? Thank you

    Read the article

  • Computer keeps locking me out

    - by me32
    When I'm away from my computer (Windows XP) for more than ~30 minutes, I get locked out, and have to press Ctrl+Alt+Delete to login. I've checked the screensaver settings, and it's not set to lock the screen. Does anyone know what else could be causing this? Thanks

    Read the article

  • Fortigate Remote VPN : no matching gateway for new request

    - by Kedare
    I am trying to configure a Fortigate 60C to act as an IPSec endpoint for remote VPN. I configured it like this : SCR-F0-FGT100C-1 # diagnose vpn ike config vd: root/0 name: SCR-REMOTEVPN serial: 7 version: 1 type: dynamic mode: aggressive dpd: enable retry-count 3 interval 5000ms auth: psk dhgrp: 2 xauth: server-auto xauth-group: VPN-group interface: wan1 distance: 1 priority: 0 phase2s: SCR-REMOTEVPN-PH2 proto 0 src 0.0.0.0/0.0.0.0:0 dst 0.0.0.0/0.0.0.0:0 dhgrp 5 replay keep-alive dhcp policies: none Here is the configuration: config vpn ipsec phase1-interface edit "SCR-REMOTEVPN" set type dynamic set interface "wan1" set dhgrp 2 set xauthtype auto set mode aggressive set proposal aes256-sha1 aes256-md5 set authusrgrp "VPN-group" set psksecret ENC xxx next config vpn ipsec phase2-interface edit "SCR-REMOTEVPN-PH2" set keepalive enable set phase1name "SCR-REMOTEVPN" set proposal aes256-sha1 aes256-md5 set dhcp-ipsec enable next end But when I try to connect from a remote device (I tested with an Android Phone), the phone fail to connect and the fortinet return this error : 2012-07-20 13:08:51 log_id=0101037124 type=event subtype=ipsec pri=error vd="root" msg="IPsec phase 1 error" action="negotiate" rem_ip=xxx loc_ip=xxx rem_port=1049 loc_port=500 out_intf="wan1" cookies="xxx" user="N/A" group="N/A" xauth_user="N/A" xauth_group="N/A" vpn_tunnel="N/A" status=negotiate_error error_reason=no matching gateway for new request peer_notif=INITIAL-CONTACT I tried searching on the web, but i did not find anything revelant to this. Do you have any idea of what can be the problem ? I tried many combinaisons of settings on the fortigate without success..

    Read the article

  • Maintain cookie session in Android

    - by datguywhowanders
    Okay, I have an android application that has a form in it, two EditText, a spinner, and a login button. The user selects the service from the spinner, types in their user name and password, and clicks login. The data is sent via POST, a response is returned, it's handled, a new webview is launched, the html string generated form the response is loaded, and I have the home page of whatever service the user selected. That's all well and good. Now, when the user clicks on a link, the login info can't be found, and the page asks the user to login again. My login session is being dropped somewhere, and I'm not certain how to pass the info from the class that controls the main part of my app to the class that just launches the webview activity. The on click handler from the form login button: private class FormOnClickListener implements View.OnClickListener { public void onClick(View v) { String actionURL, user, pwd, user_field, pwd_field; actionURL = "thePageURL"; user_field = "username"; //this changes based on selections in a spinner pwd_field = "password"; //this changes based on selections in a spinner user = "theUserLogin"; pwd = "theUserPassword"; List<NameValuePair> myList = new ArrayList<NameValuePair>(); myList.add(new BasicNameValuePair(user_field, user)); myList.add(new BasicNameValuePair(pwd_field, pwd)); HttpParams params = new BasicHttpParams(); DefaultHttpClient client = new DefaultHttpClient(params); HttpPost post = new HttpPost(actionURL); HttpResponse response = null; BasicResponseHandler myHandler = new BasicResponseHandler(); String endResult = null; try { post.setEntity(new UrlEncodedFormEntity(myList)); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } try { response = client.execute(post); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { endResult = myHandler.handleResponse(response); } catch (HttpResponseException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } List cookies = client.getCookieStore().getCookies(); if (!cookies.isEmpty()) { for (int i = 0; i < cookies.size(); i++) { cookie = cookies.get(i); } } Intent myWebViewIntent = new Intent(MsidePortal.this, MyWebView.class); myWebViewIntent.putExtra("htmlString", endResult); myWebViewIntent.putExtra("actionURL", actionURL); startActivity(myWebViewIntent); } } And here is the webview class that handles the response display: public class MyWebView extends android.app.Activity{ private class MyWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.web); MyWebViewClient myClient = new MyWebViewClient(); WebView webview = (WebView)findViewById(R.id.mainwebview); webview.getSettings().setBuiltInZoomControls(true); webview.getSettings().setJavaScriptEnabled(true); webview.setWebViewClient(myClient); Bundle extras = getIntent().getExtras(); if(extras != null) { // Get endResult String htmlString = extras.getString("htmlString"); String actionURL = extras.getString("actionURL"); Cookie sessionCookie = MsidePortal.cookie; CookieSyncManager.createInstance(this); CookieManager cookieManager = CookieManager.getInstance(); if (sessionCookie != null) { cookieManager.removeSessionCookie(); String cookieString = sessionCookie.getName() + "=" + sessionCookie.getValue() + "; domain=" + sessionCookie.getDomain(); cookieManager.setCookie(actionURL, cookieString); CookieSyncManager.getInstance().sync(); } webview.loadDataWithBaseURL(actionURL, htmlString, "text/html", "utf-8", actionURL); } } } I've had mixed success implementing that cookie solution. It seems to work for one service I log into that I know keeps the cookies on the server (old, archaic, but it works and they don't want to change it.) The service I'm attempting now requires the user to keep cookies on their local machine, and it does not work with this setup. Any suggestions?

    Read the article

  • How to avoid open-redirect vulnerability and safely redirect on successful login (HINT: ASP.NET MVC

    - by Brad B.
    Normally, when a site requires that you are logged in before you can access a certain page, you are taken to the login screen and after successfully authenticating yourself, you are redirected back to the originally requested page. This is great for usability - but without careful scrutiny, this feature can easily become an open redirect vulnerability. Sadly, for an example of this vulnerability, look no further than the default LogOn action provided by ASP.NET MVC 2: [HttpPost] public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (!String.IsNullOrEmpty(returnUrl)) { return Redirect(returnUrl); // open redirect vulnerability HERE } else { return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "User name or password incorrect..."); } } return View(model); } If a user is successfully authenticated, they are redirected to "returnUrl" (if it was provided via the login form submission). Here is a simple example attack (one of many, actually) that exploits this vulnerability: Attacker, pretending to be victim's bank, sends an email to victim containing a link, like this: http://www.mybank.com/logon?returnUrl=http://www.badsite.com Having been taught to verify the ENTIRE domain name (e.g., google.com = GOOD, google.com.as31x.example.com = BAD), the victim knows the link is OK - there isn't any tricky sub-domain phishing going on. The victim clicks the link, sees their actual familiar banking website and is asked to logon Victim logs on and is subsequently redirected to http://www.badsite.com which is made to look exactly like victim's bank's website, so victim doesn't know he is now on a different site. http://www.badsite.com says something like "We need to update our records - please type in some extremely personal information below: [ssn], [address], [phone number], etc." Victim, still thinking he is on his banking website, falls for the ploy and provides attacker with the information Any ideas on how to maintain this redirect-on-successful-login functionality yet avoid the open-redirect vulnerability? I'm leaning toward the option of splitting the "returnUrl" parameter into controller/action parts and use "RedirectToRouteResult" instead of simply "Redirect". Does this approach open any new vulnerabilities? Side note: I know this open-redirect may not seem to be a big deal compared to the likes of XSS and CSRF, but us developers are the only thing protecting our customers from the bad guys - anything we can do to make the bad guys' job harder is a win in my book. Thanks, Brad

    Read the article

  • SQL 2008 R2 login/network issue

    - by martinjd
    I have a Windows Server 2008 R2 new clean install , not a VM, that I have added to a Windows Server 2003 based domain using my account which has domain admin rights. The domain functional level is 2003. I performed a clean install of SQL Server 2008 R2 using my account which has domain admin rights. The installation completed without any errors. I logged into SSMS locally and attempted to add another domain account by clicking Search, Advanced and finding the user in the domain. When I return to the "Dialog - New" window and click OK I receive the following error: Create failed for Login 'Domain\User'. (Microsoft.SqlServer.Smo) An exception occurred while executing a Transact-SQL statement or batch. (Microsoft.SqlServer.ConnectionInfo) Windows NT user or group 'Domain\User' not found. Check the name again. (Microsoft SQL Server, Error: 15401) I have verified that the firewall is off, tried adding a different domain user, tried using SA to add a user, installed the hotfix for KB 976494 and verified that the Local Security Policy for Domain Member: Digitally encrypt or sign secure channel Domain Member: Digitally encrypt secure channel Domain Member: Digitally sign secure channel are disabled none of which have made a difference. I can RDP to a Server 2003 server running SQL 2008 and add the same domain user without issue. Also if I try to connect with SSMS to the sql server from another system on the domain using my account I get the following error: Login failed. The login is from an untrusted domain and cannot be used with Windows authentication. (Microsoft SQL Server, Error: 18452) and on the database server I see the following in the security event log: An account failed to log on. Subject: Security ID: NULL SID Account Name: - Account Domain: - Logon ID: 0x0 Logon Type: 3 Account For Which Logon Failed: Security ID: NULL SID Account Name: myUserName Account Domain: MYDOMAIN Failure Information: Failure Reason: An Error occured during Logon. Status: 0xc000018d Sub Status: 0x0 Process Information: Caller Process ID: 0x0 Caller Process Name: - Network Information: Workstation Name: MYWKS Source Network Address: - Source Port: - Detailed Authentication Information: Logon Process: NtLmSsp Authentication Package: NTLM Transited Services: - Package Name (NTLM only): - Key Length: 0 I am sure that the "NULL SID" has some significant meaning but have no idea at this point what the issue could be.

    Read the article

  • IPhone Example : Login Page and then Navigate to another Screen (UI Table View)

    - by Smc
    Hi, I am an .Net Expert but a new to the IPhone App Development. Recently I have started workinf on Objective - c. I need a help I need a example which shows a Login Screen and then Navigates to the another Screen (UITableView) when username and password and found correct. As of now I am assuming that username and passwords are hardcoded in app. I have tried to Design the Screen for Login UI but unable to Load the another ViewController but it wont worked Can some one help me out with examples, Links?

    Read the article

  • Remote SQL server connection failure

    - by Sevki
    I am trying to connect to my MSSQL server 2008 web instance and im failing horribly... i get the error 26 and before you jump on me i have done these Check the spelling of the SQL Server instance name that is specified in the connection string. Use the SQL Server Surface Area Configuration tool to enable SQL Server to accept remote connections over the TCP or named pipes protocols. For more information about the SQL Server Surface Area Configuration Tool, see Surface Area Configuration for Services and Connections. Make sure that you have configured the firewall on the server instance of SQL Server to open ports for SQL Server and the SQL Server Browser port (UDP 1434). Make sure that the SQL Server Browser service is started on the server. in addition to theese i have disabled the firewall completely and tried other ports nothing works the same credentials work on the server but not on the client. this is the exact error message A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: SQL Network Interfaces, error: 26 - Error Locating Server/Instance Specified) (.Net SqlClient Data Provider) Can anybody help?

    Read the article

  • How to inspect remote SMTP server's TLS certificate?

    - by Miles Erickson
    We have an Exchange 2007 server running on Windows Server 2008. Our client uses another vendor's mail server. Their security policies require us to use enforced TLS. This was working fine until recently. Now, when Exchange tries to deliver mail to the client's server, it logs the following: A secure connection to domain-secured domain 'ourclient.com' on connector 'Default external mail' could not be established because the validation of the Transport Layer Security (TLS) certificate for ourclient.com failed with status 'UntrustedRoot. Contact the administrator of ourclient.com to resolve the problem, or remove the domain from the domain-secured list. Removing ourclient.com from the TLSSendDomainSecureList causes messages to be delivered successfully using opportunistic TLS, but this is a temporary workaround at best. The client is an extremely large, security-sensitive international corporation. Our IT contact there claims to be unaware of any changes to their TLS certificate. I have asked him repeatedly to please identify the authority that generated the certificate so that I can troubleshoot the validation error, but so far he has been unable to provide an answer. For all I know, our client could have replaced their valid TLS certificate with one from an in-house certificate authority. Does anyone know a way to manually inspect a remote SMTP server's TLS certificate, as one can do for a remote HTTPS server's certificate in a web browser? It could be very helpful to determine who issued the certificate and compare that information against the list of trusted root certificates on our Exchange server.

    Read the article

  • iPhone Remote with iTunes Library via VPN

    - by sudo work
    Alright, so I'm currently behind a network router (not under my control). The router performs NAT and somehow prevents a computer from scanning other nodes. At least, you're unable, in this instance, to locate an iTunes library. You can, however, communicate with a node's open ports if the local IP address is known, as well as the port. I haven't actually tried port scanning a specific IP using nmap or another tool yet. So I've tried one solution to remove the contribution of the router entirely (to verify that it works without the influence of the routers). I set up an access point using my iPhone and tethered my computer (with the library) to it. From here, I was able to pair my library and the iPhone Remote application. Control of the library was normal as well. This solution is not ideal, however, because I am actively using bandwidth with my computer and cannot afford to be tethered to my 3G connection. A viable solution for me is to use a common VPN connection, which I have set up on a Ubuntu (Intrepid) server that is remote. Both my computer and iPhone are able to access the VPN via PPTP. The server is setup with PPTPD as the VPN-server; I'm using IPTables to perform IP masquerading and forwarding traffic. I however, still cannot connect the library to the phone. I can however, see both devices on the VPN subnet (192.168.0.0/24). SSH'ing and such works fine. What settings on the VPN server must I change to get this to work? Also, how can I assign static IP addresses to various PPTP clients based on MAC addresses?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >