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  • Is it worth the effort to block failed login attempts

    - by dunxd
    Is it worthwhile running fail2ban, sshdfilter or similar tools, which blacklist IP addresses which attempt and fail to login? I've seen it argued that this is security theatre on a "properly secured" server. However, I feel that it probably makes script kiddies move on to the next server in their list. Let's say that my server is "properly secured" and I am not worried that a brute force attack will actually succeed - are these tools simply keeping my logfiles clean, or am I getting any worthwhile benefit in blocking brute force attack attempts?

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  • Juju instances in aganet-state: down after turning them off (and back on) on EC2

    - by Tyler McAdams
    I turned my Juju instances off on EC2 for a while and after bringing them back online they seem to be in an odd state: [code] claude-vm@claude-vm-fusion:~/Documents/Shell Scripts$ juju status 2012-11-17 17:06:44,094 INFO Connecting to environment... 2012-11-17 17:06:45,590 INFO Connected to environment. machines: 0: agent-state: not-started dns-name: ec2-54-242-142-196.compute-1.amazonaws.com instance-id: i-b0996fcf instance-state: running 1: agent-state: down dns-name: ec2-50-19-186-245.compute-1.amazonaws.com instance-id: i-8c8375f3 instance-state: running 2: agent-state: down dns-name: ec2-54-242-255-238.compute-1.amazonaws.com instance-id: i-56807629 instance-state: running services: wordpress: charm: cs:precise/wordpress-9 exposed: true relations: db: - wordpress-db loadbalancer: - wordpress units: wordpress/0: agent-state: down machine: 2 open-ports: - 80/tcp public-address: ec2-54-242-227-57.compute-1.amazonaws.com wordpress-db: charm: cs:precise/mysql-10 relations: db: - wordpress units: wordpress-db/0: agent-state: down machine: 1 public-address: ec2-54-242-212-177.compute-1.amazonaws.com 2012-11-17 17:06:47,274 INFO 'status' command finished successfully [/code] Can I not take my instances down for a while? Or is this something else?

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  • Best way to use mod_rewrite to replace WordPress pages with static files

    - by David Moles
    Here's the situation: I've got an old WordPress installation that I'd like to archive as static files, but I'd also like to preserve old URLs. I've already created the static archive with wget and sorted out the filenames and links. Now I'd like to configure Apache to intercept requests for the old dynamic URL and replace them with the new static one, e.g.: http://www.example.org/log/?p=1234 or http://www.example.org/log/index.php?p=1234 should redirect to http://www.example.org/log/archives/1234.html I've tried adding the following to the VirtualHost config for example.org, but to no effect -- I just get the PHP page. RewriteCond %{REQUEST_URI} /log/ RewriteCond %{QUERY_STRING} p=([^&;]*) RewriteRule ^/$ http://%{SERVER_NAME}/log/archives/%1.html [R,L] I've enabled logging and I can see what look like other rules being applied, but not this one. None of my other guesses at match patterns for %{REQUEST_URI} seem to have any effect either (log, log/, log.*, even .*). I'm new to mod_rewrite and this is mostly cargo cult, so I'm pretty sure I've gotten it wrong. Anyone know what I should be doing here?

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  • ssh login - execute command - exit

    - by renton
    hi folks, is there a way to just execute a command (or script) on a user (ssh) login and then exit? some kind of replacing the default shell with a custom script. i want a user only be able to restart a service, but not to have regular shell-access thanks

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  • Run script on login with ssh

    - by user912447
    I have a feeling this is quite easy to do but every solution found on google has to do with adding a script to be run whenever someone logs into the machine. What I am looking for is a way to run a script when only I log into the machine. I ssh into a shared computer and need to have it load a couple modules for me and I imagined the easiest way to do this would to just run a script on login. Is there a simple way?

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  • Login Facebook using Web-Harvest

    - by parin
    I tried to login Facebook using Web-Harvest. I used the following xml code to login < ?xml version="1.0" encoding="UTF-8"? < config charset="ISO-8859-1" < file action="write" path="homepage.xml" charset="UTF-8" < html-to-xml < http method="post" url="http://www.facebook.com/login.php" cookie-policy="browser" < http-param name="email"myemail < http-param name="pass"mypassword < /http < /html-to-xml < /file The homepage.xml (output) file contains the xml code for the login page of facebook along with the following lines: < h2 class="main_message" id="standard_error"Cookies Required< /h2< p class="sub_message" id="standard_explanation"Cookies are not enabled on your browser. Please adjust this in your security preferences before continuing.< /p I tried all the allowed values for cookie-policy in the http processor of the xml code but was unsuccessful.

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  • HttpServletRequest#login() not working in Java.

    - by Nitesh Panchal
    Hello, j_security_check just doesn't seem enough for me to perform login process. So, instead of submitting the form to j_security_check i created my own servlet and in that i am programmatically trying to do login. This works but i am not able to redirect to my restricted resource. Can anybody tell me what can be the problem? This is processRequest method of my servlet :- protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { String strUsername = request.getParameter("txtusername"); String strPassword = request.getParameter("txtpassword"); if(strUsername == null || strPassword == null || strUsername.equals("") || strPassword.equals("")) throw new Exception("Username and/or password missing."); request.login(strUsername, strPassword); System.out.println("Login succeeded!!"); if(request.isUserInRole(ROLES.ADMIN.getValue())){//enum System.out.println("Found in Admin Role"); response.sendRedirect("/Admin/home.jsf"); } else if (request.isUserInRole(ROLES.GENERAL.getValue())) response.sendRedirect("/Common/index.jsf"); else //guard throw new Exception("No role for user " + request.getRemoteUser()); }catch(Exception ex){ //patch work why there needs to be blogger here? System.out.println("Invalid username and/or password!!"); response.sendRedirect("/Common/index.jsf"); }finally { out.close(); } } Everything works fine and i can even see message "Found in Admin Role" but problem is even after authenticating i am not able to redirect my request to some other page. Please help geeks.

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  • Asp.net Login Status Question: It Aint Working

    - by contactmatt
    I'm starting to use Role Management in my website, and I'm current following along on the tutorial from http://www.asp.net/Learn/Security/tutorial-02-vb.aspx . I'm having a problem with the asp:LoginStatus control. It is not telling me that I am currently logged in after a successful login. This can't be true because after successfully logging in, my LoggedInTemplate is shown. The username and passwords are simply stored in a array. Heres the Login.aspx page code. Protected Sub btnLogin_Click(ByVal sender As Object, ByVal e As System.EventArgs) _ Handles btnLogin.Click ' Three valid username/password pairs: Scott/password, Jisun/password, and Sam/password. Dim users() As String = {"Scott", "Jisun", "Sam"} Dim passwords() As String = {"password", "password", "password"} For i As Integer = 0 To users.Length - 1 Dim validUsername As Boolean = (String.Compare(txtUserName.Text, users(i), True) = 0) Dim validPassword As Boolean = (String.Compare(txtPassword.Text, passwords(i), False) = 0) If validUsername AndAlso validPassword Then FormsAuthentication.RedirectFromLoginPage(txtUserName.Text, chkRemember.Checked) End If Next ' If we reach here, the user's credentials were invalid lblInvalid.Visible = True End Sub Here is the content place holder on the master page specifically designed to hold Login Information. On successfull login, the page is redirected to '/Default.aspx', and the LoggedIn Template below is shown...but the status says Log In. <asp:ContentPlaceHolder Id="LoginContent" runat="server"> <asp:LoginView ID="LoginView1" runat="server"> <LoggedInTemplate> Welcome back, <asp:LoginName ID="LoginName1" runat="server" />. </LoggedInTemplate> <AnonymousTemplate> Hello, stranger. </AnonymousTemplate> </asp:LoginView> <br /> <asp:LoginStatus ID="LoginStatus1" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" /> </asp:ContentPlaceHolder> Forms authentication is enabled. I'm not sure what to do about this :o.

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  • django: cannot import settings, cannot login to admin, cannot change admin password

    - by xpanta
    Hi, It seems that I am completely lost here. Yesterday I noticed that I cannot login to the admin panel (don't use it much, so it's been some weeks since last login). I thought that I might have changed the admin password and now I can't remember it (though I doubt it). I tried django-admin.py changepassword (using django 1.2.1) but it said that 'changepassword' is unknown command (I have all the necessary imports in my settings.py. Admin interface used to work ok). Then I gave a django-admin.py validate. Then the hell begun. django-admin.py validate gave me this error: Error: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined. I then gave a set DJANGO_SETTINGS_MODULE=myproject.settings and then again a django-admin.py validate This is what I get now: Error: Could not import settings 'myproject.settings' (Is it on sys.path? Does it have syntax errors?): No module named myproject.settings and now I am lost. I tried django console and sys.path.append('c:\workspace') or sys.append('c:\workspace\myproject') but still get the same errors. I use windows 7 and my project dir is c:\workspace. I don't use a PYTHONPATH variable (although I tried setting it temporarily to C:\workspace but I still get the same error). I don't use Apache, just the django development server. What am I doing wrong? My web page works fine. I think that the fact that I can't login as admin is related to the previous import error, no? PS: I also tried this: http://coderseye.com/2007/howto-reset-the-admin-password-in-django.html but still I couldn't change admin password for some reason. Although I could create another admin user (with which I couldn't login).

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  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

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  • Have to login twice. PHP sessions and login troubles with Chrome and Opera.

    - by Robert
    The problem I am encountering is that for my login form I have to login twice for the session to register properly, but only in Chrome (my version is 4.0.249.89) and Opera (my version is 10.10). Here is the stripped down code that I am testing on: Login Page: session_start(); $_SESSION['user_id'] = 8; $_SESSION['user_name'] = 'Jim'; session_write_close(); header('Location: http://www.my-domain-name.com/'); exit(); Home Page: session_start(); if ( isset($_SESSION['user_id']) ) { echo "You are logged in!"; } else { echo "You are NOT logged in!"; } Logout Page: session_start(); session_unset(); session_destroy(); header('Location: http://www.my-domain-name.com/'); exit(); Currently, under a fresh load with no cookies, if I go to my-domain-name.com/login/ it will redirect to the home page and say "You are NOT logged in!" but if I go there again it will say "You are logged in!". Any ideas? Thanks for your help.

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  • Cannot open database "DataDir" requested by the login. The login failed

    - by Turkan Caglar
    Hi, I have a single user software that uses SQL Server database 2005. My computer was crushed while my software was on. I saved a copy of my database after I rescued my computer. However my software gives my following message. ( I don't know anything about SQL) However, I guess my database has the last login information. Since software was not shot down properly, it still thinks that I am logged in doesn't allow me to login again. How can I solve the problem? Can you help me? Or do you know any source that I can get help? Cannot open database "DataDir" requested by the login. The login failed ComputerName = GURELS User ID=sa;Initial Catalog=DataDir;Data Source=GURELS\CSS;Application Name=ChefTec User ID=sa;Initial Catalog=CTDir;Data Source=GURELS\CSS;Use Procedure for Prepare=1;Auto Translate=True;Packet Size=4096;Application Name=ChefTec;Workstation ID=GURELS;Use Encryption for Data=False;Tag with column collation when possible=False Thank you very much Turkan e-mail" [email protected] phone:617 259 6644

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  • YQL + PHP : how to make a facebook login

    - by Jonathan
    Hi! I was reading some stuff about the YQL api that Yahoo! has provided, I am not sure, but it appears to be a collection of lots of third party api into one common language, right? what I don't get is how to make the facebook login through it so I can get the user profile data... My project is to add a facebook(and other social networks) form login, because the website won't have his own login, people will have to use a social network to link in. Then I thought the YQL would help me out with this task so I wouldn't have to develop lots of functions to each one of the networks. Reading this http://developer.yahoo.com/yql/guide/yql-code-examples.html#sdk_yql, I understood how to make a Yahoo login so I can access some private data, but couldn't find how I could do it with facebook and others So my question... Can YQL help me with this? Can you give me a simple example of a facebook session using it within PHP? Are there alternatives to aid me in this task? thanks, Jonathan

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  • Xcode: Display Login View in applicationDidBecomeActive

    - by Patrick
    In my app I would like to show a login screen - which will be displayed when the app starts and when the app becomes active. For reference, I am using storyboards, ARC and it is a tabbed bar application. First off, I have this method which returns the topViewController. - (UIViewController *)topViewController:(UIViewController *)rootViewController { if (rootViewController.presentedViewController == nil) { return rootViewController; } if ([rootViewController.presentedViewController isMemberOfClass:[UINavigationController class]]) { UINavigationController *navigationController = (UINavigationController *)rootViewController.presentedViewController; UIViewController *lastViewController = [[navigationController viewControllers] lastObject]; return [self topViewController:lastViewController]; } UIViewController *presentedViewController = (UIViewController *)rootViewController.presentedViewController; return [self topViewController:presentedViewController]; } And I call this method here: - (void)applicationDidBecomeActive:(UIApplication *)application { if ( ... ) { // if the user needs to login PasswordViewController *passwordView = [[PasswordViewController alloc] init]; UIViewController *myView = [self topViewController:self.window.rootViewController]; [myView presentModalViewController:passwordView animated:NO]; } } To an extent this does work - I can call a method in viewDidAppear which shows an alert view to allow the user to log in. However, this is undesirable and I would like to have a login text box and other ui elements. If I do not call my login method, nothing happens and the screen stays black, even though I have put a label and other elements on the view. Does anyone know a way to resolve this? My passcode view is embedded in a Navigation Controller, but is detached from the main storyboard.

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  • Ruby on Rails user login form in main layout

    - by Jimmy
    Hey guys I have a simple ror application for some demo stuff. I am running into a problem with trying to move my login form from the users controller and just have it displayed in the main navigation so that a user can easily log in from anywhere. The problem is the form doesn't generate the correct action for the html form. Ruby code: <% form_for(url_for(:action => 'login'), :method => 'post') do |f| %> <li><%= f.text_field("username") %></li> <li><%= f.password_field("password") %></li> <li><%= submit_tag("Login")%></li> <% end %> The problem is depending on the controller I am currently in this generates HTML actions like <form action="/home" method="post">...</form> when it should be generating HTML like so <form action="/login" method="post">...</form> I know I could simply do an HTML form here but I want to keep things as easy to maintain as possible. Any help?

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  • Codeigniter Session Data not available in other pages after login

    - by jswat
    So, I have set up a login page that verifies the user's credentials, and then sets codeigniter session data 'email' and 'is_logged_in' and a few other items. The first page after the login, the data is accessible. After that page, I can no longer access the session data. In fact, if I try reloading that first page, the session data is gone. I have tried storing it in the database, storing it unencrypted (bad idea I know, but it was for troubleshooting), and storing it encrypted. I have autoloaded the session library in config.php. Here's an example of the code I'm using to set the session data: $data = array( 'email' => $this->input->post('username'), 'is_logged_in' => true ); $this->session->set_userdata($data); And to retrieve it, I'm using : $this->session->userdata('email'); Or $this->session->userdata('is_logged_in'); I've done lots of work with PHP and cookies, and sessions before, but this is my first project with Codeigniter and I'm perplexed. Could it have something to do with directory issues? I have the login page and process controlled by a 'login' controller, and then it redirects to a 'site' controller. Thanks for your help, and please let me know if I need to clarify anything.

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  • Login to website and use cookie to get source for another page

    - by Stu
    I am trying to login to the TV Rage website and get the source code of the My Shows page. I am successfully logging in (I have checked the response from my post request) but then when I try to perform a get request on the My Shows page, I am re-directed to the login page. This is the code I am using to login: private string LoginToTvRage() { string loginUrl = "http://www.tvrage.com/login.php"; string formParams = string.Format("login_name={0}&login_pass={1}", "xxx", "xxxx"); string cookieHeader; WebRequest req = WebRequest.Create(loginUrl); req.ContentType = "application/x-www-form-urlencoded"; req.Method = "POST"; byte[] bytes = Encoding.ASCII.GetBytes(formParams); req.ContentLength = bytes.Length; using (Stream os = req.GetRequestStream()) { os.Write(bytes, 0, bytes.Length); } WebResponse resp = req.GetResponse(); cookieHeader = resp.Headers["Set-cookie"]; String responseStream; using (StreamReader sr = new StreamReader(resp.GetResponseStream())) { responseStream = sr.ReadToEnd(); } return cookieHeader; } I then pass the cookieHeader into this method which should be getting the source of the My Shows page: private string GetSourceForMyShowsPage(string cookieHeader) { string pageSource; string getUrl = "http://www.tvrage.com/mytvrage.php?page=myshows"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookieHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); } return pageSource; } I have been using this previous question as a guide but I'm at a loss as to why my code isn't working.

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  • how to programatically compare permissions of login/user in sql server 2005

    - by titanium
    There's a login/user in SQL Server who is having a problem importing accounts in production server. I don't have an idea what method he is doing this. According to the one importing, this import is working fine in development server. But when he did the same import in production it is giving him errors. Below are the errors he is getting for each accounts. 2009-06-05 18:01:05.8254 ERROR [engine-1038] Task [1038:00001 - Members]: Step 1.0 [<Insert step description>]: Task.RunStep(): StoreRow has failed 2009-06-05 18:01:05.9035 ERROR [engine-1038] Task [1038:00001 - Members]: Step 1.0 [<Insert step description>]: Task.RunStep(): StoreRow exception: Exception caught while storing Data. [Microsoft][ODBC SQL Server Driver][SQL Server]'ACCOUNT1' is not a valid login or you do not have permission. Please note that 'ACCOUNT1' is not the real account name. I just changed it for security reason. Using SQL Server Management Studio (SSMS), I viewed/checked the permissions of the user/login who is performing the import from development server and production for comparison. I found no difference. My question is: Is there a way to programmatically query permissions in server and database level of a particular login/user so I can compare/contrast for any differences?

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