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  • Ajax file upload

    - by ajay009ajay
    I want to upload a file using Ajax and php. I have a form with file inclusion tag. I want when user will browse a file and click on submit then file should be uploaded without refresh. How will i do this ?It does't matter if refresh occur but i want to upload file with help of ajax.

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  • ASP.NET MVC - how to make users confirm the delete

    - by H4mm3rHead
    He, I have this page where i have checkboxes next to every item in a table, and want to allow the user to select some of them and press my delete button. I just cant come up with the jquery for making the confirm window and submitting only if 'yes' is pushed - this is my page <%Html.BeginForm(); %> <%List<ShopLandCore.Model.SLGroup> groups = (List<ShopLandCore.Model.SLGroup>)Model; %> <%Html.RenderPartial("AdminWorkHeader"); %> <table width="100%" id="ListTable" cellpadding="0" cellspacing="0"> <tr> <td colspan="5" class="heading"> <input type="submit" name="closeall" value="Close selected" /> <input type="submit" name="deleteall" value="Delete selected" /> </td> </tr> <tr> <th width="20px"> </th> <th> Name </th> <th> Description </th> <th width="150px"> Created </th> <th width="150px"> Closed </th> </tr> <%foreach (ShopLandCore.Model.SLGroup g in groups) { %> <tr> <td> <%=Html.CheckBox(g.Id.ToString()) %> </td> <td> <%=g.Name %> </td> <td> <%=g.Description %> </td> <td> <%=g.Created %> </td> <td> <%=g.Closed %> </td> </tr> <%} %> </table> <%Html.EndForm(); %> Please note that its only for the delete that it should confirm, and not necessarily for the close button.

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  • Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

    - by user303043
    Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

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  • select multiple double side

    - by Mercer
    hello, i want to do a select multiple double side like this : http://www.senamion.com/blog/jmultiselect2side.html (Demo2) but i don't know how i can retrieve my data when i click submit button..?

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  • Adding data dynamically to a html page

    - by Hulk
    In a htmlpage using jquery or javascript how can the following be achieved? User types in a question in a textarea and press on enter button ,then the same question should be displayed dynamically in the page below the textarea and the user can enter as many questions. And when the user is done the page is submitted through a submit button Can u please give a small hint of how this can be done.. Thanks..

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  • Android: ScoreNinja is only displaying 1 highscore....

    - by Dave B
    Hi All, I am trying to implement ScoreNinja into one of my apps. It all seems to work, but when I submit a score it replaces the current #1 score with any that I supply, even it is lower. This means that only one score is ever displayed. Anyone got any idea what I'm doing wrong? I have e-mailed the dev but he/they haven't responded. Thanks in advance for any info on this, most appreciated! Dave B

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  • Return a result in the original page.

    - by Josh
    When the user submit his data, I take him to a different page where plenty of calculations are made, then I redirect him to the original page with a simple : <?php header("Location:http://mysite.com/index.php"); The problem is I need all the variables and results to be show in this page, but they are obviously stored in the other one, so I need your help please :) ! Thank you for reading this !

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  • Reorder inputs before submiting form

    - by Jason
    Is there any way to reorder or manipulate a set of inputs before posting to a script for processing? I'm able to reorder the elements in the DOM no problem, but getting this to happen after the user presses the submit button and before the browser makes the POST is a bit tricky. I'm using the ajaxForm plugin in jQuery. There is a beforeSubmit callback, but this doesn't seem to allow me to reorded the inputs.

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  • Problem with jquery ajax form on Codeigniter

    - by Code Burn
    Everytime I test the email is send correctly. (I have tested in PC: IE6, IE7, IE8, Safari, Firefox, Chrome. MAC: Safari, Firefox, Chrome.) The _POST done in jquery (javascript). Then when I turn off javascript in my browser nothing happens, because nothing is _POSTed. Nome: Jon Doe Empresa: Star Cargo: Developer Email: [email protected] Telefone: 090909222988 Assunto: Subject here.. But I keep recieving emails like this from costumers: Nome: Empresa: Cargo: Email: Telefone: Assunto: CONTACT_FORM.PHP <form name="frm" id="frm"> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >Nome<font style="color:#EE3063;">*</font></div> <div class="campoFormulario inputDeCampo" ><input class="texto textocinzaescuro" size="31" name="Cnome" id="Cnome" value=""/></div> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >Empresa<font style="color:#EE3063;">*</font></div> <div class="campoFormulario inputDeCampo" ><input class="texto textocinzaescuro" size="31" name="CEmpresa" id="CEmpresa" value=""/></div> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >Cargo</div> <div class="campoFormulario inputDeCampo" ><input class="texto textocinzaescuro" size="31" name="CCargo" id="CCargo" value=""/></div> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >Email<font style="color:#EE3063;">*</font></div> <div class="campoFormulario inputDeCampo" ><input class="texto textocinzaescuro" size="31" name="CEmail" id="CEmail" value=""/></div> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >Telefone</div> <div class="campoFormulario inputDeCampo" ><input class="texto textocinzaescuro" size="31" name="CTelefone" id="CTelefone" value=""/></div> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >Assunto<font style="color:#EE3063;">*</font></div> <div class="campoFormulario inputDeCampo" ><textarea class="texto textocinzaescuro" name="CAssunto" id="CAssunto" rows="2" cols="28"></textarea></div> <div class="campoFormulario nomeDeCampo texto textocinzaescuro" >&nbsp;</div> <div class="campoFormulario inputDeCampo" style="text-align:right;" ><input id="Cbutton" class="texto textocinzaescuro" type="submit" name="submit" value="Enviar" /></div> </form> <script type="text/javascript"> $(function() { $("#Cbutton").click(function() { if(validarForm()){ var Cnome = $("input#Cnome").val(); var CEmpresa = $("input#CEmpresa").val(); var CEmail = $("input#CEmail").val(); var CCargo = $("input#CCargo").val(); var CTelefone = $("input#CTelefone").val(); var CAssunto = $("textarea#CAssunto").val(); var dataString = 'nome='+ Cnome + '&Empresa=' + CEmpresa + '&Email=' + CEmail + '&Cargo=' + CCargo + '&Telefone=' + CTelefone + '&Assunto=' + CAssunto; //alert (dataString);return false; $.ajax({ type: "POST", url: "http://www.myserver.com/index.php/pt/envia", data: dataString, success: function() { $('#frm').remove(); $('#blocoform').append("<br />Obrigado. <img id='checkmark' src='http://www.myserver.com/public/images/estrutura/ok.gif' /><br />Será contactado brevemente.<br /><br /><br /><br /><br /><br />") .hide() .fadeIn(1500); } }); } return false; }); }); function validarForm(){ var error = 0; if(!validateNome(document.getElementById("Cnome"))){ error = 1 ;} if(!validateNome(document.getElementById("CEmpresa"))){ error = 1 ;} if(!validateEmail(document.getElementById("CEmail"))){ error = 1 ;} if(!validateNome(document.getElementById("CAssunto"))){ error = 1 ;} if(error == 0){ //frm.submit(); return true; }else{ alert('Preencha os campos correctamente.'); return false; } } function validateNome(fld){ if( fld.value.length == 0 ){ fld.style.backgroundColor = '#FFFFCC'; //alert('Descrição é um campo obrigatório.'); return false; }else { fld.style.background = 'White'; return true; } } function trim(s) { return s.replace(/^\s+|\s+$/, ''); } function validateEmail(fld) { var tfld = trim(fld.value); var emailFilter = /^[^@]+@[^@.]+\.[^@]*\w\w$/ ; var illegalChars= /[\(\)\<\>\,\;\:\\\"\[\]]/ ; if (fld.value == "") { fld.style.background = '#FFFFCC'; //alert('Email é um campo obrigatório.'); return false; } else if (!emailFilter.test(tfld)) { //alert('Email inválido.'); fld.style.background = '#FFFFCC'; return false; } else if (fld.value.match(illegalChars)) { fld.style.background = '#FFFFCC'; //alert('Email inválido.'); return false; } else { fld.style.background = 'White'; return true; } } </script> FUNCTION ENVIA (email sender): function envia() { $this->load->helper(array('form', 'url')); $nome = $_POST['nome']; $empresa = $_POST['Empresa']; $cargo = $_POST['Cargo']; $email = $_POST['Email']; $telefone = $_POST['Telefone']; $assunto = $_POST['Assunto']; $mensagem = " Nome:".$nome." Empresa:".$empresa." Cargo:".$cargo." Email:".$email." Telefone:".$telefone." Assunto:".$assunto.""; $headers = 'From: [email protected]' . "\r\n" . 'Reply-To: no-reply' . "\r\n" . 'X-Mailer: PHP/' . phpversion(); mail('[email protected]', $mensagem, $headers); }

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  • Webbrowser component C++

    - by pwnu91
    Hey stackoverflow :) I wanna use webbrowser control in c++(im using dev cpp). Ages ago when i was using VB6 i just added webbrowser control (C:\Windows\System32\shdocvw.dll) to my form and it worked but im lost in C++... should i load it dynamically with LoadLibrary and then somehow put it on my dialog window or how? I also wanna use all features like navigate to page, edit html elements, submit a form, read page source, ... Someome got some snippet? Cheers

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  • How to Get Current User Name ?

    - by user325739
    Hi i have a problem like this i have two text boxes(A,B) which i have selected as " Computed when Composed " when 'A' Login then in Text A Current User Login Name Should come automatically, if 'B' Login then 'B' user name should come automatically in 'B' Text and it should be saved when i submit the form to the next level how to do this ? Regards Smitha

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  • HTML Character Identities in Twitter

    - by Patrick Gates
    I'm developing a twitter app, and when I submit a new tweet from php with abrahams twitteroauth and with any special character it submits it to twitter as the HTML identity. I've tried all the html_entity_decode() and the htmlspecialchars_decode() but nothings working. Thank you :)

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  • bash shell date parsing, start with specifc date and loop through each day in month

    - by Joe Stein
    Hi, I need to create a bash shell script starting with a day and then loop through each subsequent day formatting that output as %Y_%m_d I figure i can submit a start day and then another param for the number of days. My issue/question is how to set a DATE (that is not now) and then add a day. so my input would be 2010_04_01 6 my output would be 2010_04_01 2010_04_02 2010_04_03 2010_04_04 2010_04_05 2010_04_06 Thanks

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • Download File from server that uses Icefaces form based authentication

    - by user266443
    I am a newbie to ICEfaces and i have a requirement where i need to download a document from a given url (http://ipaddress/formexec?objectid=201). This URL uses a form based authentication that is deployed through ICEFaces. i tracked the request of this URL and i get the following line: &ice.submit.partial=false&ice.event.target=loginForm%3Aj_id33&ice.event.captured=loginForm%3Aj_id33 Is there any libraries or code to download the document by successfully passing the username and password.

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  • Rails controller not rendering correct view when form is force-submitted by Javascript

    - by whazzmaster
    I'm using Rails with jQuery, and I'm working on a page for a simple site that prints each record to a table. The only editable field for each record is a checkbox. My goal is that every time a checkbox is changed, an ajax request updates that boolean attribute for the record (i.e., no submit button). My view code: <td> <% form_remote_tag :url => admin_update_path, :html => { :id => "form#{lead.id}" } do %> <%= hidden_field :lead, :id, :value => lead.id %> <%= check_box :lead, :contacted, :id => "checkbox"+lead.id.to_s, :checked => lead.contacted, :onchange => "$('#form#{lead.id}').submit();" %> <% end %> </td> In my routes.rb, admin_update_path is defined by map.admin_update 'update', :controller => "admin", :action => "update", :method => :post I also have an RJS template to render back an update. The contents of this file is currently just for testing (I just wanted to see if it worked, this will not be the ultimate functionality on a successful save)... page << "$('#checkbox#{@lead.id}').hide();" When clicked, the ajax request is successfully sent, with the correct params, and the action on the controller can retrieve the record and update it just fine. The problem is that it doesn't send back the JS; it changes the page in the browser and renders the generated Javascript as plain text rather than executing it in-place. Rails does some behind-the-scenes stuff to figure out if the incoming request is an ajax call, and I can't figure out why it's interpreting the incoming request as a regular web request as opposed to an ajax request. I may be missing something extremely simple here, but I've kind-of burned myself out looking so I thought I'd ask for another pair of eyes. Thanks in advance for any info!

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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