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  • PHP post request to retrieve JSON

    - by Brian
    I'm trying to write some simple php code that will make a post request and then retrieve a JSON result from the server. It seemed simple to me, but the below code simply doesn't open a connection. $port = 2057; $path = "/validate/"; $request = "value1=somevalue&value2=somevalue&value3=somevalue"; $http_request = "POST $path HTTP/1.0\r\n"; $http_request .= "Host: $server\r\n"; $http_request .= "Content-Type: application/x-www-form-urlencoded;\r\n"; $http_request .= "Content-Length: " . strlen($request) . "\r\n"; $http_request .= "\r\n"; $http_request .= $request; $response = ''; if( false == ( $fs = @fsockopen($server, $port) ) ) { die ('Could not open socket'); } fwrite($fs, $http_request); while ( !feof($fs) ) { $response .= fgets($fs, 1160); } fclose($fs); In addition I've tried a more simple approach with: $handle = fopen('http://localhost:2057/validate/?'.$request, "r"); or $response = file_get_contents('http://localhost:2057/validate/' . $request); but both of these approaches just time out. I'm trying to connect to a development server I'm running in Visual Studio, so I'm not sure if that has anything to do with the timeout/connection issues. Open to any suggestions here as long as they are built in PHP.

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  • cannot modify header information puzzler

    - by outofmyleague_lucy
    hi im out of my league i have written what has now become identical code for two sites hosted on different servers. the first worked perfectly and i have therefore used it to compare the second to.from a login for i am directing to a loginaction.php when i include the db_connect.php ie <?php session_start(); include 'db_connect.php'; $user=$_POST['formUser'] $password=$_POST['formPassword']etc ? i am returning cannot modify header information header info already sent, but when i include the content of the db_connect ie <?php session_start(); $connect = mysql_connect("localhost", "user", "pass"); mysql_select_db(db_name, $connection); $user=$_POST['formUser'] $password=$_POST['formPassword']etc ? it works. any ideas? edit - requested error message Warning: Cannot modify header information - headers already sent by (output started at /home/avenncou/public_html/include/db_connect.php:4) in /home/avenncou/public_html/include/loginaction.php on line 14 at line 14 the is a header("Location: {$_SERVER["HTTP_REFERER"]}"); edit - requested db_connect.php <?php $connection = mysql_connect("localhost", "user", "pass");// or die ("Unable to connect!"); mysql_select_db("db", $connection);// or die ("Unable to select database!"); ?> that is all of it (dies commented out in case thats where the error was)!!!

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  • How do you use FastInfoset with JAXWS?

    - by Chris Kessel
    I've got code that looks like it should be correct based on what I can find, but the spewed output doesn't indicate that it's using FastInfoset. My understanding is the Accept should indicate it can accept Fastinfoset and the response would actually use it, meaning it's not text/xml as the response type. Any idea what I'm doing wrong? I've scoured with Google and I'm having a hard time finding much detail on how to use FastInfoset at all. JaxWsProxyFactoryBean factory = new JaxWsProxyFactoryBean(); factory.getInInterceptors().add(new LoggingInInterceptor()); factory.getOutInterceptors().add(new LoggingOutInterceptor()); factory.setServiceClass( C360Server.class); factory.setAddress("http://localhost:8501/cxfcontroller/cl_v5"); C360Server client = (C360Server)factory.create(); ((BindingProvider)client).getRequestContext().put( "com.sun.xml.ws.client.ContentNegotiation", "optimistic"); C360Request requestTrans = new C360Request(); ... code to fill in the request ... C360Response response = client.findContacts( requestTrans ); The logging doesn't seem to indicate FastInfoset is even attempted though: INFO: Outbound Message --------------------------- ID: 1 Address: http://localhost:8501/cxfcontroller/cl_v5 Encoding: UTF-8 Content-Type: text/xml Headers: {SOAPAction=[""], Authorization=[Basic cWFfc3VwZXI6cWFfc3VwZXI=], Accept=[*/*]} Payload: <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"><soap:Body><ns1:findContacts>...bunch of xml deleted for brevity...</ns1:findContacts></soap:Body></soap:Envelope> -------------------------------------- May 17, 2010 3:23:45 PM org.apache.cxf.interceptor.LoggingInInterceptor logging INFO: Inbound Message ---------------------------- ID: 1 Response-Code: 200 Encoding: UTF-8 Content-Type: text/xml; charset=utf-8 Headers: {content-type=[text/xml; charset=utf-8], Content-Length=[611], Server=[Jetty(6.1.x)]} Payload: <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"><soap:Body><ns1:findContactsResponse>...bunch of xml spew deleted for brevity...</ns1:findContactsResponse></soap:Body></soap:Envelope> -------------------------------------- Any ideas what I'm doing wrong? Even if the server wasn't supporting FastInfoset, I still should see the attempted negotiation in the request, right?

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  • Angularjs throws TypeError: Cannot read property 'indexOf' of undefined

    - by Ali
    I'm trying to debug the above code which I feel like this is very useful .< I can't even find what is wrong in my code and don't really know where to start since Angularjs still very new to me. I'm trying to localize Angularjs app. I know this is missing a lot of context in order to get a help, but I'm trying to see what information that I should give that would help on this debugging. I've gone through any indexOf in angularjs file and I can see few things is undefined but don't know if that would be helpful. So I've traced the problem here and this is what I have figured is the problem, but still counldn't figure out why... config(['$routeProvider', '$locationProvider', function ($routeProvider, $locationProvider) { $routeProvider.when('/:locale?/:username/badges', { templateUrl: '_partials/badges.html', controller: 'badges' }) .when('/:username/badges', { templateUrl: '_partials/badges.html', controller: 'badges' }) .when('/:username/teaching-resources', { templateUrl: '_partials/teaching-resources.html', controller: 'teachingResources' }) .when('/:username/makes', { templateUrl: '_partials/makes.html', controller: 'makes' }) .when('/:username/likes', { templateUrl: '_partials/likes.html', controller: 'likes' }) .when('/:username/events', { templateUrl: '_partials/events.html', controller: 'events' }) .when('/:username', { templateUrl: '_partials/badges.html', controller: 'badges' }); $routeProvider.otherwise({ redirectTo: '/error/404' }); The URL that I'm visiting for default page is: This will fail and throw the error. http://localhost:1969/en-US/user/someUserName This will work fine http://localhost:1969/user/someUserName UPDATE I figured out! This is the problem: $locationProvider.html5Mode(true); But why!?

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  • Tomcat does not pick up the class file - the JSP file is not displayed

    - by blueSky
    I have a Java code which is a controller for a jsp page, called: HomeController.java. Code is as follows: @Controller public class HomeController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/mypage") public String home() { System.out.println("HomeController: Passing through..."); return "home"; } } There is nothing especial in the jsp page: home.jsp. If I go to this url: http://localhost:8080/adcopyqueue/mypage I can view mypage and everything works fine. Also in the tomcat Dos page I can see the comment: HomeController: Passing through... As expected. Now under the same directory that I have HomeController.java, I've created another file called: LoginController.java. Following is the code: @Controller public class LoginController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/loginpage") public String login() { System.out.println("LoginController: Passing through..."); return "login"; } } And under the same place which I have home.jsp, I've created login.jsp. Also under tomcat folders, LoginController.class exists under the same folder that HomeController.class exists and login.jsp exists under the same folder which home.jsp exists. But when I go to this url: http://localhost:8080/adcopyqueue/loginpage Nothing is displayed! I think tomcat does not pick up LoginController.class b/c on the tomcat Dos window, I do NOT see this comment: LoginController: Passing through... Instead I see following which I do not know what do they mean? [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:34) got manifest [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:36) manifest entrie s 8 The structure and the code for HomeController.java and LoginController.java plus the jsp files match. I have no idea why tomcat sees one of the files and not the other? Clean build did not help. Does anybody have any idea? Any help is greatly appraciated.

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  • HTML relative links with URL Rewrite

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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  • testng multiple suites

    - by Eli
    Hi people. my problem is as follows: i am testing a web-ui using selenium and testng. i have a test suite with many test classes in it. i have a method with the @BeforeSuite witch also has a @Parameters annotation, this method recieves as a parameter the browser in witch the selenium will test by run,executing the lines: selenium = new DefaultSelenium("localhost", 4444, **browser**, "http://localhost:8099"); selenium.start(); the xml im using to run the test suite is: <suite name="suite"> <parameter name = "browser" value = "*firefox"/> <test name="allTests"> <classes> <class name="test.webui.MemcachedDeploymentTest" /> </classes> </test> </suite> this works fine and the test runs in firefox. my problem is that i would like to somehow run this suite again, immediatly after the first run finishes, but this time with chrome as the browser. i now have 2 xml suites, one with chrome and one with firefox, is there any way to run these test suites one after the other automatically? maybe using a third xml? Thanks in advance

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  • Ajax Request using jQuery in Rails

    - by Steve
    Hi... I am sending an Ajax Request using jQuery. What happens is that I am getting an "405 Method Not Allowed" Error. I am just posting a form, which would get the detail from the form and insert it into the DB. Just the usual stuff.I am using WEBrick that comes as default with the rails package. Can somebody please tell me how to fix this. This is the code that triggers the Ajax Request $.post($(this).attr("action") + ".js",$(this).serialize(),null,"script"); Response Headers Cache-Control no-cache Allow GET, PUT, DELETE Content-Type text/html; charset=utf-8 Content-Length 9502 Server WEBrick/1.3.1 (Ruby/1.9.1/2009-12-07) Date Wed, 02 Jun 2010 20:41:33 GMT Connection Keep-Alive Request Headers Host localhost:3000 User-Agent Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept application/json, text/javascript, */* Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 115 Connection keep-alive Content-Type application/x-www-form-urlencoded; charset=UTF-8 X-Requested-With XMLHttpRequest Referer http://localhost:3000/viewspot/3 Content-Length 141 Pragma no-cache Cache-Control no-cache

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  • Forcing user to new page in php. (PHP newbie)

    - by JohnC
    Hello I'm a newbie web programmer. My background is writing Windows applications with sql. I'm putting together my 1st data entry screens in Php. I have a search form that links to a form that displays records in a grid. On each row of the grid I have a delete url to allow the user to remove a record. This links to a form delete.php (which calls the sql to remove the record). Ideally I would like to automatically take the user back to the search form rather than forcing the user to click on a link to do so. I have used ob_start with the header to do this elsewhere but cannot get it to work on this page. Is there another way to do it? (Using php 5 as part of LAMP) file delete.php <?php $id = $_GET['recordID']; //ob_start(); require_once('connections/local.php'); mysql_select_db($database_local, $local); mysql_query("DELETE FROM user_access WHERE id = {$id}") or die(mysql_error()); echo("Record ".$id." deleted"); echo("<br>"); //header("location:http://localhost/search7.htm); //ob_flush(); echo("<a href=\"http://localhost/search7.htm\">Search for Members</a>"); ?>

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  • Jetty 7 will not allow me to customize a session cookie path

    - by Bob Obringer
    Using Jetty 7.0.2, I am unable to set a custom session cookie path. I am hosting multiple sites on the same server using apache to proxy requests to the proper context. (replaced http as htp as stackoverflow thinks my multiple links might be spam) <VirtualHost *:80> ServerName context.domain.com ProxyRequests On ProxyPreserveHost Off <Proxy *:80> Order deny,allow Allow from 127.0.0.1 </Proxy> ProxyPass / htp://localhost:8080/context/ ProxyPassReverse / htp://localhost:8080/context/ <Location /> Order allow,deny Allow from all </Location> </VirtualHost> Jetty is running on the same server on port 8080 and my context is available @ /context The user accesses the application @ htp://context.domain.com but jetty is setting the path for the session cookie @ /context. This prevents the browser from accessing the cookie since the the actual path to the context is not being used. I need to override Jetty's default setting to set the cookie for the context, and set the path at the root ( / ). In my Jetty's webdefault.xml I have the following, which is partially working: <context-param> <param-name>org.eclipse.jetty.servlet.SessionCookie</param-name> <param-value>CustomCookieName</param-value> </context-param> <context-param> <param-name>org.eclipse.jetty.servlet.SessionPath</param-name> <param-value>/</param-value> </context-param> The cookie is properly set with a custom name, but it is NOT setting the SessionPath. No matter what I set the value to... it refuses to set a cookie at any path but /context. This has been driving me crazy so any help would be greatly appreciated.

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  • How to configure and run a fastcgi application using Lighthttpd...

    - by Airy
    Hi, i've installed Lighthttpd for windows and i'd created a simple program in c++ which uses fastcgi libraries. i'll post the code here... #include "fcgi_stdio.h" #include <stdlib.h> int count; void initialize(void) { count=0; } void main(void) { initialize(); while (FCGI_Accept() >= 0) { printf("Content-type: text/html\r\n" "\r\n" "<title>FastCGI Hello! (C, fcgi_stdio library)</title>" "<h1>FastCGI Hello! (C, fcgi_stdio library)</h1>" "Request number %d running on host <i>%s</i>\n", ++count, getenv("SERVER_HOSTNAME")); } } I've spawned the fastcgi application in lighthttpd using the below configuration in lightttpd-inc.conf fastcgi.server = ( ".exe" => ( "" => ( "bin-path" => "D:\tinycgi.exe", "port" => 8080, "min-procs" => 1, "max-procs" => 1 ) ) ) while sending a request using the browser the server is responding with this message in the console 2009-02-18 16:08:34: (mod_fastcgi.c.2494) unexpected end-of-file (perhaps the fa stcgi process died): pid: 0 socket: tcp:localhost:8080 2009-02-18 16:08:34: (mod_fastcgi.c.3325) response not received, request sent: 1 024 on socket: tcp:localhost:8080 for /new/tinycgi.exe , closing connection I think the fastcgi application is not spawned correctly. Thank you, Varun

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  • Custom Controls Properties - C# , Forms - :(

    - by user353600
    Hi I m adding custom control to my flowlayoutpanel , its a sort of forex data , refresh every second , so on each timer tick , i m adding a control , changing controls button text , then adding it to flowlayout panel , i m doing it at each 100ms timer tick , it takeing tooo much CPU , here is my custom Control . public partial class UserControl1 : UserControl { public UserControl1() { InitializeComponent(); } private void UserControl1_Load(object sender, EventArgs e) { } public void displaydata(string name , string back3price , string back3 , string back2price , string back2 , string back1price , string back1 , string lay3price , string lay3 , string lay2price , string lay2 , string lay1price , string lay1 ) { lblrunnerName.Text = name.ToString(); btnback3.Text = back3.ToString() + "\n" + back3price.ToString(); btnback2.Text = back2.ToString() + "\n" + back2price.ToString(); btnback1.Text = back1.ToString() + "\n" + back1price.ToString(); btnlay1.Text = lay1.ToString() + "\n" + lay1price.ToString(); btnlay2.Text = lay2.ToString() + "\n" + lay2price.ToString(); btnlay3.Text = lay3.ToString() + "\n" + lay3price.ToString(); } and here is how i m adding control; private void timer1_Tick(object sender, EventArgs e) { localhost.marketData[] md; md = ser.getM1(); flowLayoutPanel1.Controls.Clear(); foreach (localhost.marketData item in md) { UserControl1 ur = new UserControl1(); ur.Name = item.runnerName + item.runnerID; ur.displaydata(item.runnerName, item.back3price, item.back3, item.back2price, item.back2, item.back1price, item.back1, item.lay3price, item.lay3, item.lay2price, item.lay2, item.lay1price, item.lay1); flowLayoutPanel1.SuspendLayout(); flowLayoutPanel1.Controls.Add(ur); flowLayoutPanel1.ResumeLayout(); } } now its happing on 10 times on each send , taking 60% of my Core2Duo cpu . is there any other way , i can just add contols first time , and then change the text of cutom controls buttons on runtime on each refresh or timer tick i m using c# .Net

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  • Multiple webroot folders with Jetty

    - by Lóránt Pintér
    I'm using Jetty (version 6.1.22) to service a Java web application. I would like to make Jetty look in two different folders for web resources. Take this layout: +- project1 | +- src | +- main | +- webapp | +- first.jsp | +- project2 +- src +- main +- webapp +- second.jsp I would like to make Jetty serve both URLs: http://localhost/web/first.jsp http://localhost/web/second.jsp I tried starting Jetty like this: Server server = new Server(); SocketConnector connector = new SocketConnector(); connector.setPort(80); server.setConnectors(new Connector[] { connector }); WebAppContext contextWeb1 = new WebAppContext(); contextWeb1.setContextPath("/web"); contextWeb1.setWar("project1/src/main/webapp"); server.addHandler(contextWeb1); WebAppContext contextWeb2 = new WebAppContext(); contextWeb2.setContextPath("/web"); contextWeb2.setWar("project2/src/main/webapp"); server.addHandler(contextWeb2); server.start(); But it only serves first.jsp, and it returns 404 for second.jsp. How can I get this to work?

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  • Why Response.Write behavior varies in the given scenario?

    - by Sri Kumar
    Hello All, When i POST the page using the following code, the Response.write("Hey") doesn't write the content ("Hello") to the parent page <form method="post" name="upload" enctype="multipart/form-data" action="http://localhost:2518/Web/CrossPage.aspx?cmd=getvalue" > <input type="file" name="filename" /> <input type="submit" value="Upload Data File" name="cmdSubmit" /> </form> But When i use following code , and POST the data, the Response.write("Hey") can be obtained in the parent page HttpWebRequest requestToSender = (HttpWebRequest)WebRequest.Create("http://localhost:2518/Web/CrossPage.aspx?cmd=getvalue"); requestToSender.Method = "POST"; requestToSender.ContentType = "multipart/form-data"; HttpWebResponse responseFromSender = (HttpWebResponse)requestToSender.GetResponse(); string fromSender = string.Empty; using (StreamReader responseReader = new StreamReader(responseFromSender.GetResponseStream())) { fromSender = responseReader.ReadToEnd(); } In the CrossPage.aspx i have the following code if (!Page.IsPostBack) { NameValueCollection postPageCollection = Request.Form; foreach (string name in postPageCollection.AllKeys) { Response.Write(name + " " + postPageCollection[name]); } HttpFileCollection postCollection = Request.Files; foreach (string name in postCollection.AllKeys) { HttpPostedFile aFile = postCollection[name]; aFile.SaveAs(Server.MapPath(".") + "/" + Path.GetFileName(aFile.FileName)); } Response.Write("Hey"); } I don't have any code in the Page_Load event of parent page.? What could be the cause? I need to write the "hey" to the Parent page using the first scenario. Both the application are of different domain. Edit: "Hey" would be from the CrossPage.aspx. I need to write this back to the Parent Page

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  • HTML relative links on various domains

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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  • Database class is not correctly connecting to my database.

    - by blerh
    I'm just venturing into the world of OOP so forgive me if this is a n00bish question. This is what I have on index.php: $dbObj = new Database(); $rsObj = new RS($dbObj); This is the Database class: class Database { private $dbHost; private $dbUser; private $dbPasswd; private $dbName; private $sqlCount; function __construct() { $this->dbHost = 'localhost'; $this->dbUser = 'root'; $this->dbPasswd = ''; $this->dbName = 'whatever'; $this->sqlCount = 0; } function connect() { $this->link = mysql_connect($this->db_host, $this->db_user, $this->db_passwd); if(!$this->link) $this->error(mysql_error()); $this->selection = mysql_select_db($this->db_name, $this->link); if(!$this->selection) $this->error(mysql_error()); } } I've shortened it to just the connect() method to simplify things. This is the RS class: class RS { private $username; private $password; function __construct($dbObj) { // We need to get an account from the db $dbObj->connect(); } } As you can probably see, I need to access and use the database class in my RS class. But I get this error when I load the page: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\includes\database.class.php on line 22 The thing is I have NO idea where it got the idea that it needs to use ODBC as a user... I've read up on doing this stuff and from what I can gather I am doing it correctly. Could anyone lend me a hand? Thank you.

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  • Can one connection get details of another? Or, how can I get the most detailed pending transaction

    - by bob-the-destroyer
    Is there a Mysql statement which provides full details of any other open connection or user? For this particular case, on myisam tables specifically. Looking at Mysql's SHOW TABLE STATUS documentation, it's missing some very important information for my purpose. For example: remote odbc connection one is inserting several thousand records, which due to a slow connection speed can take up to an hour. Tcp connection two, using PHP on the server's localhost, is running select queries with aggregate functions on that data. Before allowing connection two to run those queries, I'd like connection two to first check to make sure there's no pending inserts on any other connection on those specific tables so it can instead wait until all data is available. If the table is currently being written to, I'd like to spit back to the user of connection two an approximation of how much longer to wait based on the number of pending inserts. Ideally by table, I'd like to get back using a query the timestamp when connection one began the write, total inserts left to be done, and total inserts already completed. Instead of insert counts, even knowing number of bytes written and left to write would work just fine here. Obviously since connection two is a tcp connection via a PHP script, all I can really use in that script is some sort of query. I suppose if I have to, since it is on localhost, I can exec() it if the only way is by a mysql command line option that outputs this info, but I'd rather not. I suppose I could simply update a custom-made transaction log before and after this massive insert task which the PHP script can check, but hopefully there's already a built-in Mysql feature I can take advantage of.

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  • Help Installing phpMyAdmin on Linux Server

    - by Joe Majewski
    I constantly get this error when attempting to view index.php in the phpMyAdmin folder I have setup: Cannot start session without errors, please check errors given in your PHP and/or webserver log file and configure your PHP installation properly. I am using subversion with three co-workers and I am trying to install this on my repository, which is at /svni3/myusername/intranet/ on our linux development server. I do have shell access so I would be able to install it somewhere else if that may be causing the problem. My config.inc.php file looks like this (only the things I changed): $cfg['blowfish_secret'] = 'blah'; $cfg['Servers'][$i]['auth_type'] = 'cookie'; //$cfg['Servers'][$i]['user'] = 'username'; //$cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['host'] = 'localhost'; Other helpful information??? When I ping localhost it works. When I run the command "ls -l /var/lib/php": drwxrwx--- 2 root apache 4096 2009-04-17 02:31 session If there's anything else that may be helpful let me know; this has been plaguing me for a few hours now.

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  • XAMPP, MAMP, MySQL, PDO - A deadly combination?

    - by Rich
    Hey folks, Previously I've worked on a Symfony project (MySQL PDO based) with XAMPP, with no problems. Since then, I've moved to MAMP - I prefer this - but have hit a snag with my database connection. I've created a test.php like this: <?php try { $dbh = new PDO('mysql:host=localhost;dbname=xxx;port=8889', 'xxx', 'xxx'); foreach($dbh->query('SELECT * from FOO') as $row) { print_r($row); } $dbh = null; } catch (PDOException $e) { print "Error!: " . $e->getMessage() . "<br/>"; die(); } ?> Obviously the *xxx*s are real db connection details. Which when served by MAMP seems to work fine. From terminal however I keep getting the following error when running the file: Error!: SQLSTATE[28000] [1045] Access denied for user 'xxx'@'localhost' (using password: YES) Not sure if the terminal is aiming at a different MySQL socket or something along those lines; but I've tried pointing it to the MAMP socket with a local php.ini file. Any help would be greatly appreciated.

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  • trouble connecting to MySql DB (PHP)

    - by user332817
    Hi I have the following PHP code to connect to my db. <?php ob_start(); $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); ?> however I get the following error: Warning: mysql_connect() [function.mysql-connect]: [2002] A connection attempt failed because the connected party did not (trying to connect via tcp://localhost:3306) in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Warning: mysql_connect() [function.mysql-connect]: A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond. in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 Fatal error: Maximum execution time of 30 seconds exceeded in C:\Program Files (x86)\EasyPHP-5.3.2i\www\checklogin.php on line 11 I am able to add a db/tables via phpmyadmin but I cant connect using php. here is a screenshot of my phpmyadmin page: http://img294.imageshack.us/img294/1589/sqls.jpg any help would be appreciated, thanks in advance.

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  • AngularJS: Using Shared Service(with $resource) to share data between controllers, but how to define callback functions?

    - by shaunlim
    Note: I also posted this question on the AngularJS mailing list here: https://groups.google.com/forum/#!topic/angular/UC8_pZsdn2U Hi All, I'm building my first AngularJS app and am not very familiar with Javascript to begin with so any guidance will be much appreciated :) My App has two controllers, ClientController and CountryController. In CountryController, I'm retrieving a list of countries from a CountryService that uses the $resource object. This works fine, but I want to be able to share the list of countries with the ClientController. After some research, I read that I should use the CountryService to store the data and inject that service into both controllers. This was the code I had before: CountryService: services.factory('CountryService', function($resource) { return $resource('http://localhost:port/restwrapper/client.json', {port: ':8080'}); }); CountryController: //Get list of countries //inherently async query using deferred promise $scope.countries = CountryService.query(function(result){ //preselected first entry as default $scope.selected.country = $scope.countries[0]; }); And after my changes, they look like this: CountryService: services.factory('CountryService', function($resource) { var countryService = {}; var data; var resource = $resource('http://localhost:port/restwrapper/country.json', {port: ':8080'}); var countries = function() { data = resource.query(); return data; } return { getCountries: function() { if(data) { console.log("returning cached data"); return data; } else { console.log("getting countries from server"); return countries(); } } }; }); CountryController: $scope.countries = CountryService.getCountries(function(result){ console.log("i need a callback function here..."); }); The problem is that I used to be able to use the callback function in $resource.query() to preselect a default selection, but now that I've moved the query() call to within my CountryService, I seemed to have lost what. What's the best way to go about solving this problem? Thanks for your help, Shaun

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  • Error in FireFox Loading Images

    - by Brian
    Hello, Details of the app are: ASP.NET project, local web server, hosted in IIS locally, using latest FireFox, uses forms authentication. I'm getting a logon user name/pwd box when trying to access my local web server. Using the net panel in firebug, I see the issue is with an animated GIF, showing up as 401 unauthorized. I check the details and this is what I see for this URL: http://localhost/<virtual>/Images/loading.gif I'm getting the following: Response Headers: Server Microsoft-IIS/5.1 Date Thu, 17 Jun 2010 19:02:58 GMT WWW-Authenticate Negotiate NTLM Connection close Content-Length 4046 Content-Type text/html Request headers: Host localhost User-Agent Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 ( .NET CLR 3.5.30729; .NET4.0E) Accept image/png,image/*;q=0.8,*/*;q=0.5 Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 115 Connection keep-alive Referer <correct referer> Cookie ASP.NET_SessionId=ux4bt345qjz4p3u1wm1zgmez; .ASPXFormsAuth=33F12B444040827B8ABF154EE4EDE43B6CA532432EB846987B355097E00256DF0955C76A37BC593EAA961747BF1CC1D8949FF63C6F2CA69D77213EB15B4EDFAF57A83D9E1F88AB8D821C3A09C07EA2EE; .ASPROLES=qTFrGteJydYAE3118WGXbhJthTDdjdtuQ06t4bYVrM1BwIfcEHU1HhnEcs7TqSOaV-fIN5MH3uO57oNVWXDvrhkZ8gQuURuUk_K0TpoR-DEFXuF953Gl9aIilKAdV211jutMNQmhkt2rdPE2tEhHs3pz953fADxjAOyZl7K-AqNvMk3yqJshhKHhJIf-ALMhWIYlrrKy0WsYznUwh3WCtPfzEBD5XzmXU8HVMJ2-ArLjBISuegvSmxvK1PuXBPhoMRMi9Ynaw6xi9ypGk-R6uN0ljOMCGkB2-20WUlFuP0xWTfac_zCTDT00pbpnyjtygnM-LShOXTrZ_mhoRuXfKYEYSodNihwD6SRr19Nm-8uZ5BQ-W81svM17S2C0vc0FaxtiuAcN_vHcsN1OEJeCuVfRjeqzo9xWEViupP3Vh6aOcCm6yrftgw5x94piuCJO7tCfXjJAw5RVUWDBBWv5gmid171F0k-_XZ0CSv7Gm2Eai1BRfogAqQ_MV3tyPv7XVEyJXRXqYGlf1JpkfTW8S8On4E05v9gx9RcdnKHZebiOZwbP1_ho9nG7pMwXysbhjxtxwZ-zLx-v11_rhZw_i5m7iNcLtt4BbFU-sb_crzMpCKGywHIc452Zp1E0kx1Rfx-2eUnaiLiCfGed-QqelO88NYTpJHttGKEfhFrDgmaIXZPJRtuZ-GrS6t3Vla-8qDAVb1p6ovPwoVT4z4BhQyFsk542gDx-uQDw6D0B6zo7lXfcOjtolUxDcLbETsNlYsexZaxFpRSbw7M1ldwL_k92P9wLPlv9mw4NtyhXKJesMu7GjquZuoBN3hO00AqJEe1tKFFtfrvbE5ZH7uNu7myNdtlxRPe3WZe7qukbqHo1 Pragma no-cache Cache-Control no-cache Any ideas? Thanks.

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  • How do i integrate paypal in my website? Java

    - by Nitesh Panchal
    Hello, I want to integrate paypal in my java web application. I saw that they offer many methods to accomplish this. But i want my visitors to remain on my site only. My friend told me that Paypal offers webservice. But i can't seem to find any documentation on Paypal site. If anybody could help me with this, i would be really very grateful. Please offer me the relevant links on Paypal where i could read and get my things done. Secondly, my friend also told me that we need to give location to paypal where my visitors would be redirected once paypal payment is complete. But i am confused. I am working on localhost. How would Paypal know about my localhost? I have already created my sandbox testing account. What should be my next step. Please explain me in detail. I don't know anything about Paypal. Once i created a demo application of Express checkout where they give a simple button of Pay Now and on clicking on it shopping cart etc appears. But now i want my visitors to stay on same website. Thanks in advance :)

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  • I expect to see in the browswer "http://path/some_page.html" but instead it identifies with "http:/

    - by indiehacker
    I am developing with app engine SDK. I have a feeling this is much too basic a question so apologies ahead of time... A simple submit button doesnt work instead of just showing an alert box as expected it continues on afterwards and redirects me to the latest http-request, and I think this is because I dont understand how to tell the browser to recognize the proper URLs. Why does my browser say I am at the most recent http-request http://localhost:8080/putProjectInDB rather than the somepage.html that was actually served to the browser that I am currently looking at? How can I get the browser to recognize and show in its url spot the normal expected http://somepage.html ? Just in case, here are details of the specific problem which you might be able to ignore for answering the question: This hasnt been mattered for me until I just wanted to put into my .html a simple button that changes some stuff of the page without needing the server. The below code after displaying the alert box redirects me to the last server request http://localhost:8080/putProjectInDB instead of just staying in the same html page. in header: function MyFormCommands() { alert('Some Text'); } in body: <form onSubmit="MyFormCommands()" ><input type=submit ></form >

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  • Troubleshooting multiple GET variables In PHP

    - by V413HAV
    This may be a very simple question but I don't what's the wrong thing am doing here... To explain you clearly, I've set a real simple example below: <ul> <li><a href="test.php?link1=true">Link 1</a></li> <li><a href="test.php?link2=true">Link 2</a></li> <li><a href="test.php?link3=true">Link 3</a></li> </ul> <?php if(isset($_GET['link1'])) { if(($_GET['link1']) == 'true') { echo 'This Is Link 1'; } } if(isset($_GET['link2'])) { if(($_GET['link2']) == 'true') { echo 'This Is Link 2'; } } if(isset($_GET['link3'])) { if(($_GET['link3']) == 'true') { echo 'This Is Link 3'; } } ?> This is a test.php page, here I've set 3 different arguments for $_GET, and show contents accordingly, now everything works perfect, the only thing am not understanding is how to block this kind of url say if user clicks on link 1 the url will be : http://localhost/test.php?link1=true And the Output of this url is This is Link 1 Now if I change this url to : http://localhost/test.php?link3=true&link2=true&link1=true And the Output what I get is This Is Link 1This Is Link 2This Is Link 3 Now this is ok here, but it's very annoying if someone types this and see's forms one below the other, any way I can stop this tampering?

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