This is related to question 19245, in that one of the responders answered the question in an awesome way, and very VERY clear to any newbie. Now here is a question that i can't seem to figure.
i wrote a script for starting the vmware firefox plugin (don't worry. i gave that up and now run vBox VERY happily. i left vmware for my servers :) )
I needed to start the plugin as sudo, but i also needed to pass an argument (password) to it, that happen to be the same.
So, if my password was Hello123, the command would be: sudo ./myscript.sh hi other Hello123
running from command line, the script would ask for my sudo password and then run. i wanted to capture THAT password and pass it as well. i also wanted to run graphically, so i tried gksudo, and there is an option -p that returns the password for variable assignment.
well, that was a nightmare, because i would still get prompted for the original sudo: see below
Find UserName
vUser=$USER
Find password (and hopefully enable sudo)
vP=gksudo -p -D somedescriptiontext echo
Execute command
gksudo ./myscript.sh hi $vUser $vP
and i still get prompted twice.
so my question is tri-fold:
is there a variable i can use for the password, just like there is one for user, $USER?
is there a different way i should be assigning the value resulting of the command i have in $vP? i am wondering if executing the way i have it, does it in an uninitiated session and not the current one, since i am getting some addtl warning type errors on some variables blah blah
i tried using Zenity to just capture the text, but then of course, i couldn't pass that value to sudo, so i could only use as a parameter, which puts me back in 2 prompts.
Thanksssssssssss!
