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  • validation of special characters

    - by jpallavi
    I want to validate login name with special characters !@#S%^*()+_-?/<:"';. space using regular expression in ruby on rails. These special characters should not be acceptable. What is the code for that? Thanks, Pallavi

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  • Split by Caps in Javascript,

    - by user1294188
    I am trying to split up a string by caps using Javascript, Examples of what Im trying to do: "HiMyNameIsBob" -> "Hi My Name Is Bob" "GreetingsFriends" -> "Greetings Friends" I am aware of the str.split() function, however I am not sure how to make this function work with capital letters. I've tried: str.split("(?=\\p{Upper})") Unfortunately that doesn't work, any help would be great.

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  • regular expression for challenge value

    - by Salman
    Hi what will be the regular expression to extract challenge var value i am interested in this vlaue 03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig this value changes every time we refresh it so the expression has to be generic enough to pick up what ever is the value var RecaptchaState = { site : '6LeKCL8SAAAAADV5Dr-lfY2eOEV8rubeN25BAKp2', challenge : '03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig', is_incorrect : false, programming_error : '', error_message : '', server : 'http://www.google.com/recaptcha/api/', timeout : 18000}; any help will be appreciated, or any method to extract this value in any server side lang

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  • How to code an efficient blacklist filter function in php?

    - by achairapart
    So, I have three arrays like this: [items] => Array ( [0] => Array ( [id] => someid [title] => sometitle [author] => someauthor ... ) ... ) and also a string with comma separated words to blacklist: $blacklist = "some,words,to,blacklist"; Now I need to match these words with (as they can be one of) id, title, author and show results accordingly. I was thinking of a function like this: $pattern = '('.strtr($blacklist, ",", "|").')'; // should return (some|words|etc) foreach ($items as $item) { if ( !preg_match($pattern,$item['id']) || !preg_match($pattern,$item['title']) || !preg_match($pattern,$item['author']) ) { // show item } } and I wonder if this is the most efficient way to filter the arrays or I should use something with strpos() or filter_var with FILTER_VALIDATE_REGEXP ... Note that this function is repeated per 3 arrays. However, each array will not contain more than 50 items.

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  • Mutually exclusive regular expressions

    - by CaptnCraig
    If I have a list of regular expressions, is there an easy way to determine that no two of them will both return a match for the same string? That is, the list is valid if and only if for all strings a maximum of one item in the list will match the entire string. It seems like this will be very hard (maybe impossible?) to prove definitively, but I can't seem to find any work on the subject. The reason I ask is that I am working on a tokenizer that accepts regexes, and I would like to ensure only one token at a time can match the head of the input.

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  • Regular Expression for accurate word-count using JavaScript

    - by Haidon
    I'm trying to put together a regular expression for a JavaScript command that accurately counts the number of words in a textarea. One solution I had found is as follows: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\b\w+\b/).length -1; But this doesn't count any non-Latin characters (eg: Cyrillic, Hangul, etc); it skips over them completely. Another one I put together: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\s+/g).length -1; But this doesn't count accurately unless the document ends in a space character. If a space character is appended to the value being counted it counts 1 word even with an empty document. Furthermore, if the document begins with a space character an extraneous word is counted. Is there a regular expression I can put into this command that counts the words accurately, regardless of input method?

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  • Complex regular expression

    - by Jose3d
    Hello, i will like to capture a substring part of a text choosing the number of characters but if any word is cut then get until de last blank. As example if this is the text: "This is an example of text lorem ipsum, etc..." and i would like to get for instance 12 characters that are: "This is an e". In this case example is cutted, then i would like to get "This is an". Its possible do this with Regular Expressions? Thanks in advance. Jose

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  • Regular expression to truncate a String

    - by user470184
    To truncate a String here is what I'm using : String test1 = "this is test truncation 1.pdf"; String p1 = test1.substring(0, 10) + "..."; System.out.println(p1); The output is 'this is te...' How can I access the file name extension so that output becomes : 'this is te... pdf' I could use substring method to access the last three characters but other file extensions could be 4 chars in length such as .aspx Is there a regular expression I can use so that "this is test truncation 1.pdf" becomes "this is te... pdf"

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  • Efficient way to organise data file in columns with Python

    - by user1700959
    I'm getting an output data file of a program which looks like this, with more than one line for each time step: 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 0.0000E+00 7.9819E-06 1.7724E-02 2.3383E-02 3.0048E-02 3.8603E-02 4.9581E-02 5.6635E-02 4.9991E-02 3.9052E-02 3.0399E-02 .... I want to arrange it in ten columns I have made a Python script, using regular expressions to delete \n in the proper lines, but I think that there should be a simpler more elegant way to do it, here is my script: import re with open('inputfile', encoding='utf-8') as file1: datai=file1.read() dataf=re.sub(r'(?P<nomb>( \d\.\d\d\d\dE.\d\d){8})\n','\g<nomb>',datai) with open('result.txt',mode='w',encoding='utf-8') as resultfile: resultfile.write(datof) Thanks in advance

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  • Php and python regexp difference?

    - by Ajel
    I need to parse a string 'Open URN: 100000 LA: ' and get 100000 from it. on python regexp (?<=Open URN: )[0-9]+(?= LA:) works fine but in php it gives following error: preg_match(): Unknown modifier '[' I need it working php, so please help me to solve this problem and tell about difference in python and php regexps.

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  • preg_replace - don't include string if $4 is blank

    - by bradenkeith
    I have this expression: $regex_phone = '/^(?:1(?:[. -])?)?(?:\((?=\d{3}\)))?([2-9]\d{2})' .'(?:(?<=\(\d{3})\))? ?(?:(?<=\d{3})[.-])?([2-9]\d{2})' .'[. -]?(\d{4})(?: (?i:ext)\.? ?(\d{1,5}))?$/'; if(!preg_match($regex_phone, $data['phone'])){ $error[] = "Please enter a valid phone number."; }else{ $data['phone'] = preg_replace($regex_phone, '($1) $2-$3 ext.$4', $data['phone']); } That will take a phone number such as: 803-888-8888 ext 2 as well as 803-888-8888 First number formats as: (803) 888-8888 ext.2 -- the desired effect Second number formats as: (803) 888-8888 ext. -- blank extension How can I set it so that if $4 is blank, that ext. won't show? Thanks so much for any help you can offer. I hope this was clear.

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  • Find images that have a certain HTML class name

    - by Frederik Vig
    I have some markup that contains certain HTML image tags with the class featured. What I need is to find all those images, add an anchor tag around the image, set the href attribute of the anchor to the images src value (the image path), and lastly replace the images src value with a new value (I call a method that will return this value). <p>Some text here <img src="/my/path/image.png" alt="image description" class="featured" />. Some more text and another image that should not be modified <img src="/my/path/image2.png" alt="image description" /></p> Should become. <p>Some text here <a href="/my/path/image.png"><img src="/new/path/from/method.png" alt="image description" class="featured" /></a>. Some more text and another image that should not be modified <img src="/my/path/image2.png" alt="image description" /></p>

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  • Java String replaceAll with conditions

    - by user1483570
    I am not good in regular expressions and I need help in replacing the string. String str = "Name_XYZ_"; str = "XYZ_NAME_"; So how can I replace "Name_" or "_NAME_" from above two strings with empty string? The conditions are "Name" can be in any case and it can be at index 0 or at any index but preceded by "_". So far I tried, String replacedString = str.replaceAll("(?i)Name_", ""); // This is not correct. This is not the homework. I am working on XML file that needs such kind of processing. Please help. Thank you.

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  • sed find pattern on line with another pattern

    - by user2962390
    I am trying to extract text from a file between a '<' and a '', but only on a line starting with another specific pattern. So in a file that looks like: XXX Something here XXX Something more here XXX <\Lines like this are a problem ZZZ something <\This is the text I need XXX Don't need any of this I would like to print only the "<\This is the text I need". If I do sed -n '/^ZZZ/p' FILENAME it pulls the correct lines I need to look at, but obviously prints the whole line. sed -n '/</,//p' FILENAME prints way too much. I have looked into grouping and tried sed -n '/^ZZZ/{/</,//} FILENAME but this doesn't seem to work at all. Any suggestions? They will be much appreciated. (Apologies for formatting, never posted on here before)

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  • Getting a date value in a postgres table column and check if it's bigger than todays date

    - by Roland
    I have a Postgres table called clients. The name column contains certain values eg. test23233 [987665432,2014-02-18] At the end of the value is a date, I need to compare this date, and return all records where this specific date is younger than today I tried select id,name FROM clients where name ~ '(\d{4}\-\d{1,2}\-\d{1,2})'; but this isn't returning any values. How would I go about to achieve the results I want?

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  • Constructing a regular expression to wrap images with <a>

    - by bobo
    A web page contains lots of image elements: <img src="myImage.gif" width="180" height="18" /> But they may not be very well-formed, for example, the width or height attribute may be missing. And it also may not be properly closed with /. The src attribute is always there. I need a regular expression that wraps these with a hyperlink having href set to the src of the img. <a href="myImage.gif" target="_blank"><img src="myImage.gif" width="180" height="18" /></a> I can successfully locate the images using this regexp in this editor: http://gskinner.com/RegExr/: <img src="([^<]*)"[^<]*> But what is the next step?

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  • Javascript replace using regexp

    - by netcrash
    <input type="text" value="[tabelas][something][oas]" id="allInput"> <script type="text/javascript"> allInput = document.getElementById('allInput'); var nivel = new Array('tabelas', 'produto'); for (var i =0; i < nivel.length ; i++ ) { alert(" oi => " + allInput.value + " <-- " + nivel[i]) ; var re = new RegExp("^\[" + nivel[i] + "\]\[.+\].+", "g"); alert(re); allInput.value = allInput.value.replace( re, "OLA"); alert(" oi 2 => " + allInput.value + " <-- " + nivel[i]) ; } </script> Basically I whant to replace "something2 in the [tabelas][something][otherfield] by a number of quantity, I have been playing with regexp and had different results from this using .replace(/expression/,xxx ) and new RegExp() . Best regards and thank you for any help.

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  • ruby parametrized regular expression

    - by astropanic
    I have a string like "{some|words|are|here}" or "{another|set|of|words}" So in general the string consists of an opening curly bracket,words delimited by a pipe and a closing curly bracket. What is the most efficient way to get the selected word of that string ? I would like do something like this: @my_string = "{this|is|a|test|case}" @my_string.get_column(0) # => "this" @my_string.get_column(2) # => "is" @my_string.get_column(4) # => "case" What should the method get_column contain ?

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  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a regular expression in my cocoa-touch app (using RegexKitLite). NSString *week = [[NSString alloc] initWithFormat:@"%@", [pageContent stringByReplacingOccurrencesOfRegex:@"<select name=\"week\" class=\"selectbox\" style='width:134' onChange=\"doDisplayTimetable(NavBar, topDir);\">(.+?)<option value=\"(.+?)\">(.+?)</option>" withString:@"$2"]]; I expect it to match with the section of this (what is in NSString pageContent): <span class="selection"> <nobr> Periode<br> <span class="absatz"> &nbsp;<br> </span> <select name="week" class="selectbox" style='width:134' onChange="doDisplayTimetable(NavBar, topDir);"> <option value="14">17-5 - 16-7</option> </select> </nobr> </span> But it doesn't... I need the value of the option, it is possible that there is more than one (in that case I need them both separated by a ,. Can someone help me out? Regards, Dodo

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