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  • Nested entities in Google App Engine. Do I do it right?

    - by Aleksandr Makov
    Trying to make most of the GAE Datastore entities concept, but some doubts drill my head. Say I have the model: class User(ndb.Model): email = ndb.StringProperty(indexed=True) password = ndb.StringProperty(indexed=False) first_name = ndb.StringProperty(indexed=False) last_name = ndb.StringProperty(indexed=False) created_at = ndb.DateTimeProperty(auto_now_add=True) @classmethod def key(cls, email): return ndb.Key(User, email) @classmethod def Add(cls, email, password, first_name, last_name): user = User(parent=cls.key(email), email=email, password=password, first_name=first_name, last_name=last_name) user.put() UserLogin.Record(email) class UserLogin(ndb.Model): time = ndb.DateTimeProperty(auto_now_add=True) @classmethod def Record(cls, user_email): login = UserLogin(parent=User.key(user_email)) login.put() And I need to keep track of times of successful login operations. Each time user logs in, an UserLogin.Record() method will be executed. Now the question — do I make it right? Thanks. EDIT 2 Ok, used the typed arguments, but then it raised this: Expected Key instance, got User(key=Key('User', 5418393301680128), created_at=datetime.datetime(2013, 6, 27, 10, 12, 25, 479928), email=u'[email protected]', first_name=u'First', last_name=u'Last', password=u'password'). It's clear to understand, but I don't get why the docs are misleading? They implicitly propose to use: # Set Employee as Address entity's parent directly... address = Address(parent=employee) But Model expects key. And what's worse the parent=user.key() swears that key() isn't callable. And I found out the user.key works. EDIT 1 After reading the example form the docs and trying to replicate it — I got type error: TypeError('Model constructor takes no positional arguments.'). This is the exacto code used: user = User('[email protected]', 'password', 'First', 'Last') user.put() stamp = UserLogin(parent=user) stamp.put() I understand that Model was given the wrong argument, BUT why it's in the docs?

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  • Accessing Secure Web Services from ADF Mobile

    - by Shay Shmeltzer
    Most of the enterprise Web services you'll access are going to be secured - meaning they'll require you to pass a user/password in order to get to their data.  If you never created a secured Web service, it's simple in JDeveloper! For the below video I just right clicked on a Java class that I exposed as a Web service, and chose  "Web Service Properties" and then checked the "oracle/wss_username_token_service_policy" box from the list of options (that's the option supported by ADF Mobile right now): In the demo below we are going to use a "remote" login server that does the authentication of the user/pass.The easiest way to "create" a remote login server is to create a "regular" web ADF application, secure it, and deploy it on a server. The secured ADF application can just require ADF Authentication with a simple HTTP Basic Authentication - basically the next two images in the Application->Secure->Configure ADF Security menu wizard. ok - so now you have a secured ADF application - deploy it on a server and get the URL for that application.  From this point on you'll see the process in the video which deals with the configuration of your ADF Mobile app. First you'll need to enable security for your ADF mobile application, so it will prompt users to provide a user/pass combination. You'll also need to configure security on specific features. And you can have them use remote login pointing to your regular secured ADF application. Next define your Web service data control. Right click on the web service data control to "define Web Service Security". You'll also need to define the adfCredentialStoreKey property for the Web Service data control in the connections.xml file. This should be it. Here is the flow: If you haven't already - you can read more about this in the Mobile developer guide, and Andrejus has a sample for you.

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  • How to customize live Ubuntu CD?

    - by karthick87
    I would like to customize Ubuntu live CD by installing some additional packages. I have followed this link but it doesn't seems to work. Can anyone provide clear instructions? Thanks in advance! Customization Packages that I want to install: Thunderbird Samba SSH Changes that I need: Remove Games menu from the Application menu Firefox shortcut on desktop Radiance as the default theme Different default Ubuntu wallpaper Note I do not prefer Remastersys, manual way will be appreciated. updates I want the panel to be placed at the bottom. I want to paste my samba configuration file instead of default samba configuration. And i have few firefox shortcuts and Folders, i have to show that in Desktop. Also it will be nice if you say me how to change the icon sets. Recent Updates I have customized ubuntu 10.10 with firefox shortcuts and few folders on desktops. Everything went smooth. But the installer gets crashes after choosing the timezone. How do i fix this issue? Also setting wallpaper affects the login screen. The wallpaper which i set is displayed on the login screen also. I just want the default one for the login screen.

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  • How do I restore default menu/top panel text color in Gnome Classic?

    - by Kobby
    The default text/icon color in my top panel has changed from white to a very dark grey, making my menus virtually unreadable against the black of the Ambiance theme. This includes even the login screen menu. I used Gnome Tweak to change the theme to Adwaita, but while some text has gone light grey (e.g. Date/Time), the login menu text remains dark grey, as do most icons (e.g. dropbox, wireless, battery indicator...) in the top panel after I log in. I tried deleting the top panel altogether but the option of deleting under Super + Alt + Right Click is blocked off. I tried running a panel from the terminal, but it came up in strange colors too, plus icons had moved around and some parts of the panel were opaque and other parts transparent. Deleting the panel wouldn't solve the basic problem anyway, as my login menu would still be very dark grey and unreadable against the default (black) Ambiance background. I would like to keep Ambiance but I want to reset the color to default (white) again. Can anyone help me?

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  • How to customize the Ubuntu Live CD?

    - by karthick87
    I would like to customize Ubuntu live CD by installing some additional packages. I have followed this link but it doesn't seems to work. Can anyone provide clear instructions? Note: I do not prefer Remastersys, manual way will be appreciated. Customization Packages that I want to install: Thunderbird Samba SSH Changes that I need: Remove Games menu from the Application menu Firefox shortcut on desktop Radiance as the default theme Different default Ubuntu wallpaper Configuration file changes I want the panel to be placed at the bottom I want to paste my Samba configuration file instead of default Samba configuration I have few Firefox shortcuts and folders I would like to show that in Desktop Also it will be nice if you say me how to change the icon sets Recent Updates I have customized Ubuntu 10.10 with Firefox shortcuts and few folders on desktops. Everything went smooth. But the installer gets crashes after choosing the timezone. How do i fix this issue? Also setting wallpaper affects the login screen. The wallpaper which i set is displayed on the login screen also. I just want the default one for the login screen.

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  • Cannot get script to run at startup (tried all the simple answers)

    - by Carey Head
    I have Ubuntu Desktop 12.04 LTS running great on an older Acer desktop. I want to use this machine as an in-home server for hosting Minecraft. The command to start the Minecraft server is java -Xmx1024M -Xms1024M -jar minecraft_server.jar nogui and that works great when I cd into the correct directory and execute the above. I created a script to do this: #!/bin/bash cd /home/myuser/minecraft-server1 java -Xmx1024M -Xms1024M -jar minecraft_server.jar nogui & cd /home/myuser/minecraft-server2 java -Xmx1024M -Xms1024M -jar minecraft_server.jar nogui & exit 0 I made this .sh file executable, and it too runs great when I start it manually from the terminal. The problem I'm having is getting these to execute at startup. I have my user account on this machine to auto login. I have tried the following: Adding the following to "Startup Applications" : sh /home/myuser/myscript.sh (Nothing happens on reboot) Adding the same to /etc/rc.local (Nothing happens on reboot). I even tested this one by running /etc/rc.local from the terminal, and it executed great. Just not at boot/auto login Added the lines from the script directly to rc.local (Nothing happens on reboot). I can't help but think that there's something I'm missing. The script executes great when run manually, but will not run at boot/auto login. Many thanks in advance.

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  • C++ Database vs Reading Files

    - by Ohmages
    Ive been programing a C++ game/server for the past year. I have been using MYSQL for character logins, items, monsters, etc, etc. (im on windows). My question is, what are some of the databases that some big time developers use. IE. Battle.net, Diablo II, Diablo III, mythos, hellgate , etc, etc, etc. Do they have their own database they built? Or do they use an existing framework for logins, and character transfers. I do know that in diablo II, they use character files to to transfer characters into the game world. But what about the login into battle.net. Would it be wiser for me to stick with MYSQL, or is there something out there faster and more stable, or should I create a login type of system that looks through a file to see if you provided the correct password. Can't wait to get some replies. Thanks! PS. Currently the framework is much like battle.net, where you login into a lobby, create, and join games. The game server/lobby server are different servers too. So im just wondering about the lobby server for logins because I'm expecting several hundred thousand connections/logins.

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  • No root account

    - by user107744
    Okay, here's my problem. I was being an idiot and installed compiz-core on my Xubuntu 12.10. So there I was, trying to figure out how to fix my issue, and I did sudo xfwm4 --replace. Then I was unable to login. So I logging with guest, delete my old account, without deleting the home folder, of course, and I create a new account "michael2". Instead of creating a new home folder for it, I instead instructed the program to use my old home folder. Unfortunately, it completely erased the folder, along with over 150GB worth of downloads and about 200 hours worth of work (I work from home, so, yeah). And to top it all off, whenever I try to use the sudo command, I get the error michael2 is not in the sudoers file. This incident will be reported. I don't know how to fix this, nor can I login to root (I never set the root password, because I never had the need to login as root to do anything). Any help will be appreciated. Is there maybe a way that I can do system restore to restore my previous files and username? I need answers as soon as possible, because I'm literally losing money by the second (the entire work from home kinda thing).

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  • ASP.NET MVC Html.ValidationSummary(true) does not display model errors

    - by msi
    I have some problem with Html.ValidationSummary. I don't want to display property errors in ValidationSummary. And when I set Html.ValidationSummary(true) it does not display error messages from ModelState. When there is some Exception in controller action on string MembersManager.RegisterMember(member); catch section adds an error to the ModelState: ModelState.AddModelError("error", ex.Message); But ValidationSummary does not display this error message. When I set Html.ValidationSummary(false) all messages are displaying, but I don't want to display property errors. How can I fix this problem? Here is the code I'm using: Model: public class Member { [Required(ErrorMessage = "*")] [DisplayName("Login:")] public string Login { get; set; } [Required(ErrorMessage = "*")] [DataType(DataType.Password)] [DisplayName("Password:")] public string Password { get; set; } [Required(ErrorMessage = "*")] [DataType(DataType.Password)] [DisplayName("Confirm Password:")] public string ConfirmPassword { get; set; } } Controller: [HttpPost] public ActionResult Register(Member member) { try { if (!ModelState.IsValid) return View(); MembersManager.RegisterMember(member); } catch (Exception ex) { ModelState.AddModelError("error", ex.Message); return View(member); } } View: <% using (Html.BeginForm("Register", "Members", FormMethod.Post, new { enctype = "multipart/form-data" })) {%> <p> <%= Html.LabelFor(model => model.Login)%> <%= Html.TextBoxFor(model => model.Login)%> <%= Html.ValidationMessageFor(model => model.Login)%> </p> <p> <%= Html.LabelFor(model => model.Password)%> <%= Html.PasswordFor(model => model.Password)%> <%= Html.ValidationMessageFor(model => model.Password)%> </p> <p> <%= Html.LabelFor(model => model.ConfirmPassword)%> <%= Html.PasswordFor(model => model.ConfirmPassword)%> <%= Html.ValidationMessageFor(model => model.ConfirmPassword)%> </p> <div> <input type="submit" value="Create" /> </div> <%= Html.ValidationSummary(true)%> <% } %>

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  • MVC2 Controller is passed a null object as a parameter

    - by Steve Wright
    I am having an issue with a controller getting a null object as a parameter: [HttpGet] public ActionResult Login() { return View(); } [HttpPost] public ActionResult Login(LoginViewData userLogin) { Assert.IsNotNull(userLogin); // FAILS if (ModelState.IsValid) { } return View(userLogin); } The LoginViewData is being passed as null when the HttpPost is called: Using MvcContrib.FluentHtml: <h2>Login to your Account</h2> <div id="contact" class="rounded-10"> <%using (Html.BeginForm()) { %> <fieldset> <ol> <li> <%= this.TextBox(f=>f.UserLogin).Label("Name: ", "name") %> <%= Html.ValidationMessageFor(m => m.UserLogin) %> </li> <li> <%= this.Password(u => u.UserPassword).Label("Password:", "name") %> <%= Html.ValidationMessageFor(m => m.UserPassword) %> </li> <li> <%= this.CheckBox(f => f.RememberMe).LabelAfter("Remember Me")%> </li> <li> <label for="submit" class="name">&nbsp;</label> <%= this.SubmitButton("Login")%> </li> </ol> </fieldset> <% } %> <p>If you forgot your user name or password, please use the Password Retrieval Form.</p> </div> The view inherits from MvcContrib.FluentHtml.ModelViewPage and is strongly typed against the LoginViewData object: public class LoginViewData { [Required] [DisplayName("User Login")] public string UserLogin { get; set; } [Required] [DisplayName("Password")] public string UserPassword { get; set; } [DisplayName("Remember Me?")] public bool RememberMe { get; set; } } Any ideas on why this would be happening? UPDATE I rebuilt the web project from scratch and that fixed it. I am still concerned why it happened.

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  • Trying to read FormsAuthentication tickets to read in other areas of site

    - by Pasha Aryana
    Hi, NOTE: I have included 3 links in here to my localhost areas but could not submit the post so I seperetaed them with a space character so it would post on stackoverflow. I currently have 2 ASP.NET MVC apps in my solution. First I run the first one by setting it to be startup project. It goes to the login page, from there once the data has been entered I execute the following code: var authTicket = new FormsAuthenticationTicket(1, login.LoginDataContract.MSISDN, DateTime.Now, DateTime.Now.AddMinutes(Convert.ToDouble("30")), true, ""); string cookieContents = FormsAuthentication.Encrypt(authTicket); var cookie = new HttpCookie(FormsAuthentication.FormsCookieName, cookieContents) { Expires = authTicket.Expiration, //Path = FormsAuthentication.FormsCookiePath //Path = "http://localhost" Domain = "" }; if (System.Web.HttpContext.Current != null) { System.Web.HttpContext.Current.Response.Cookies.Add(cookie); } As you can see I have set the Domain = "", so theoretically speaking it should work on any thing under my http: //localhost. Then I have set the persist security of the cookie to true so I can access it from any where under localhost. The cookie writes fine and I get logged in and all godd for now. BTW the url for this login page is: http //localhost/MyAccount/Login Now then I stop the solution and set the other MVC apps to be the startup. Then I run it. The URL for the second site is: http: //localhost/WebActivations/ Here is the code in the other apps start controller: public class HomeController : Controller { public ActionResult Index() { ViewData["Message"] = "Welcome to ASP.NET MVC!"; // PASHA: Added code to read the authorization cookie set at // login in MyAccount *.sln for (int i = 0; i < System.Web.HttpContext.Current.Request.Cookies.Count;i++) { Response.Write(System.Web.HttpContext.Current.Request.Cookies[i].Name + " " + System.Web.HttpContext.Current.Request.Cookies[i].Value); } HttpCookie authorizationCookie = System.Web.HttpContext.Current.Request.Cookies[FormsAuthentication.FormsCookieName.ToString()]; // decrypt. FormsAuthenticationTicket authorizationForm = FormsAuthentication.Decrypt(authorizationCookie.Value); ViewData["Message"] = authorizationForm.UserData[0].ToString(); return View(); } public ActionResult About() { return View(); } The problem is in this Home controller when I run the solution it cannot read the authentication cookie, you see the loop there it does not find the .ASPXAUTH cookie. But once it crashes in Firefox I have a look in the Page Info and then security and Cookies and its there and its the same cookie. What am I doing wrong?

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  • Facebook Connect 'next' error

    - by Mark
    I am trying to experiment with the new facebook authentication system, and I can't getthe login to work. I'm getting the following error message: API Error Code: 100 API Error Description: Invalid parameter Error Message: next is not owned by the application. The url that is being sent to facebook is: http://www.facebook.com/connect/uiserver.php?app_id=444444444444444&next=http%3A%2F%2Fstatic.ak.fbcdn.net%2Fconnect%2Fxd_proxy.php%23%3F%3D%26cb%3Df357eceb0361a8a%26origin%3Dhttp%253A%252F%252Fwww.mysite.com%252Ff38fea4f9ea573%26relation%3Dopener%26transport%3Dpostmessage%26frame%3Df23b800f8a78%26result%3DxxRESULTTOKENxx&display=popup&channel=http%3A%2F%2Fwww.mysite.com%2Ffbtester.php&cancel=http%3A%2F%2Fstatic.ak.fbcdn.net%2Fconnect%2Fxd_proxy.php%23%3F%3D%26cb%3Df6095a98598be8%26origin%3Dhttp%253A%252F%252Fwww.mysite.com%252Ff38fea4f9ea573%26relation%3Dopener%26transport%3Dpostmessage%26frame%3Df23b800f8a78%26result%3DxxRESULTTOKENxx&locale=en_US&return_session=1&session_version=3&fbconnect=1&canvas=0&legacy_return=1&method=permissions.request Note that the 'Next' variable in the url is: next=http%3A%2F%2Fstatic.ak.fbcdn.net%2Fconnect%2Fxd_proxy.php%23%3F%3D%26cb%3Df357eceb0361a8a%26origin%3Dhttp%253A%252F%252Fwww.mysite.com%252Ff38fea4f9ea573%26relation%3Dopener%26transport%3Dpostmessage%26frame%3Df23b800f8a78%26result%3DxxRESULTTOKENxx Any ideas what could be going wrong? All I've done is copy and paste the facebook login demo code from facebook's website: <?php define('FACEBOOK_APP_ID', 'your application id'); define('FACEBOOK_SECRET', 'your application secret'); function get_facebook_cookie($app_id, $application_secret) { $args = array(); parse_str(trim($_COOKIE['fbs_' . $app_id], '\\"'), $args); ksort($args); $payload = ''; foreach ($args as $key => $value) { if ($key != 'sig') { $payload .= $key . '=' . $value; } } if (md5($payload . $application_secret) != $args['sig']) { return null; } return $args; } $cookie = get_facebook_cookie(FACEBOOK_APP_ID, FACEBOOK_SECRET); ?> <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml"> <body> <?php if ($cookie) { ?> Your user ID is <?= $cookie['uid'] ?> <?php } else { ?> <fb:login-button></fb:login-button> <?php } ?> <div id="fb-root"></div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script> FB.init({appId: '<?= FACEBOOK_APP_ID ?>', status: true, cookie: true, xfbml: true}); FB.Event.subscribe('auth.login', function(response) { window.location.reload(); }); </script> </body> </html> Thanks for the help!

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  • When does the .NET FormAuthentication ticket get checked and how do I tap into this event?

    - by Mustafakidd
    Hello everyone - We are attempting to integrate an ASP.NET MVC site with our client's SSO system using PingFederate. I would like to use the built in FormsAuthentication framework to do this. The way I've gone about it so far is: Set up my Web.config so that my FormsAuthentication LoginURL goes to my site's "BeginAuthentication" action on a "Security" controller. From this action, I set up some session variables (what URL was being accessed, for example, since Ping won't send this info back to me), and then redirect to our client's login page on an external site (www.client.com/Login for example). From here, the authentication takes place and a cookie is generated on the same domain as the one that our application is running on which contains the unique identifier of the authenticated user, I've set it up so that once this happens, the Ping server will redirect to my "EndAuthentication" action on my "Security" controller. In this action, I call my membership class's "ValidateUser" method which takes this unique identifier from the cookie and loads in the user on our application that this ID refers to. I save that logged in user in our Session (Session["LoggedInAs"], for example) and expire the cookie that contains the id of the authenticated user that the SSO system provided for me. All of this works well. The issue I'm wondering about is what happens after our user has already authenticated and manually goes back to our client's login page (www.client.com/login) and logs in as another user. If they do that, then the flow from #2 above to number 3 happens as normal - but since there already exists an authenticated user on our site, it seems as though the FormsAuthentication system doesn't bother kicking off anything so I don't get a chance to check for the cookie I'm looking for to login as this new user. What I'd like to do is, somewhere in my Global.asax file (probably FormsAuthenticate_OnAuthenticate), check to see if the cookie that the SSO system sends to me exists, and if so, sign out of the application using FormsAuthentication.SignOut(). Another issue that seems to be related is that if I let my Session expire, the FormsAuthentication still seems to think I am authenticated and it lets me access a page even though no currently logged in user exists in my Session, so the page doesn't render correctly. Should I tap into the Session_End event and do FormsAuthentication.SignOut() here as well? Basically, I want to know when the authentication ticket created by System.Web.Security.FormsAuthentication.SetAuthCookie(..) gets checked in the flow of a request so that I can determine whether I need to SignOut() and force revalidation or not. Thanks for any help. Sorry for the length of this message, trying to be as detailed as possible. Mustafa

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  • Logging in with WebFinger and OpenID

    - by Ryan
    I would like to apologize in advance for the ugly formatting. In order to talk about the problem, I need to be posting a bunch of URLs, but the excessive URLs and my lack of reputation makes StackOverflow think I could be a spammer. Any instance of 'ht~tp' is supposed to be 'http'. '{dot}' is supposed to be '.' and '{colon}' is supposed to be ':'. Also, my lack of reputation has prevented me from tagging my question with 'webfinger' and 'google-profiles'. Onto my question: I am messing around with WebFinger and trying to create a small rails app that enables a user to log in using nothing but their WebFinger account. I can succesfully finger myself, and I get back an XRD file with the following snippet: Link rel="ht~tp://specs{dot}openid{dot}net/auth/2.0/provider" href="ht~tp://www{dot}google{dot}com/profiles/{redacted}"/ Which, to me, reads, "I have an OpenID 2.0 login at the url: ht~tp://www{dot}google{dot}com/profiles/{redacted}". But when I try to use that URL to log in, I get the following error OpenID::DiscoveryFailure (Failed to fetch identity URL ht~tp://www{dot}google{dot}com/profiles/{redacted} : Error encountered in redirect from ht~tp://www{dot}google{dot}com/profiles/{redacted}: Error fetching /profiles/{Redacted}: Connection refused - connect(2)): When I replace the profile URL with 'ht~tps://www{dot}google{dot}com/accounts/o8/id', the login works perfectly. here is the code that I am using (I'm using RedFinger as a plugin, and JanRain's ruby-openid, installed without the gem) require "openid" require 'openid/store/filesystem.rb' class SessionsController < ApplicationController def new @session = Session.new #render a textbox requesting a webfinger address, and a submit button end def create ####################### # # Pay Attention to this section right here # ####################### #use given webfinger address to retrieve openid login finger = Redfinger.finger(params[:session][:webfinger_address]) openid_url = finger.open_id.first.to_s #openid_url is now: ht~tp://www{dot}google{dot}com/profiles/{redacted} #Get needed info about the acquired OpenID login file_store = OpenID::Store::Filesystem.new("./noncedir/") consumer = OpenID::Consumer.new(session,file_store) response = consumer.begin(openid_url) #ERROR HAPPENS HERE #send user to OpenID login for verification redirect_to response.redirect_url('ht~tp://localhost{colon}3000/','ht~tp://localhost{colon}3000/sessions/complete') end def complete #interpret return parameters file_store = OpenID::Store::Filesystem.new("./noncedir/") consumer = OpenID::Consumer.new(session,file_store) response = consumer.complete params case response.status when OpenID::SUCCESS session[:openid] = response.identity_url #redirect somehwere here end end end Is it possible for me to use the URL I received from my WebFinger to log in with OpenID?

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  • python getelementbyid from string

    - by matthewgall
    Hey, I have the following program, that is trying to upload a file (or files) to an image upload site, however I am struggling to find out how to parse the returned HTML to grab the direct link (contained in a ). I have the code below: #!/usr/bin/python # -*- coding: utf-8 -*- import pycurl import urllib import urlparse import xml.dom.minidom import StringIO import sys import gtk import os import imghdr import locale import gettext try: import pynotify except: print "Please install pynotify." APP="Uploadir Uploader" DIR="locale" locale.setlocale(locale.LC_ALL, '') gettext.bindtextdomain(APP, DIR) gettext.textdomain(APP) _ = gettext.gettext ##STRINGS uploading = _("Uploading image to Uploadir.") oneimage = _("1 image has been successfully uploaded.") multimages = _("images have been successfully uploaded.") uploadfailed = _("Unable to upload to Uploadir.") class Uploadir: def __init__(self, args): self.images = [] self.urls = [] self.broadcasts = [] self.username="" self.password="" if len(args) == 1: return else: for file in args: if file == args[0] or file == "": continue if file.startswith("-u"): self.username = file.split("-u")[1] #print self.username continue if file.startswith("-p"): self.password = file.split("-p")[1] #print self.password continue self.type = imghdr.what(file) self.images.append(file) for file in self.images: self.upload(file) self.setClipBoard() self.broadcast(self.broadcasts) def broadcast(self, l): try: str = '\n'.join(l) n = pynotify.Notification(str) n.set_urgency(pynotify.URGENCY_LOW) n.show() except: for line in l: print line def upload(self, file): #Try to login cookie_file_name = "/tmp/uploadircookie" if ( self.username!="" and self.password!=""): print "Uploadir authentication in progress" l=pycurl.Curl() loginData = [ ("username",self.username),("password", self.password), ("login", "Login") ] l.setopt(l.URL, "http://uploadir.com/user/login") l.setopt(l.HTTPPOST, loginData) l.setopt(l.USERAGENT,"User-Agent: Uploadir (Python Image Uploader)") l.setopt(l.FOLLOWLOCATION,1) l.setopt(l.COOKIEFILE,cookie_file_name) l.setopt(l.COOKIEJAR,cookie_file_name) l.setopt(l.HEADER,1) loginDataReturnedBuffer = StringIO.StringIO() l.setopt( l.WRITEFUNCTION, loginDataReturnedBuffer.write ) if l.perform(): self.broadcasts.append("Login failed. Please check connection.") l.close() return loginDataReturned = loginDataReturnedBuffer.getvalue() l.close() #print loginDataReturned if loginDataReturned.find("<li>Your supplied username or password is invalid.</li>")!=-1: self.broadcasts.append("Uploadir authentication failed. Username/password invalid.") return else: self.broadcasts.append("Uploadir authentication successful.") #cookie = loginDataReturned.split("Set-Cookie: ")[1] #cookie = cookie.split(";",0) #print cookie c = pycurl.Curl() values = [ ("file", (c.FORM_FILE, file)) ] buf = StringIO.StringIO() c.setopt(c.URL, "http://uploadir.com/file/upload") c.setopt(c.HTTPPOST, values) c.setopt(c.COOKIEFILE, cookie_file_name) c.setopt(c.COOKIEJAR, cookie_file_name) c.setopt(c.WRITEFUNCTION, buf.write) if c.perform(): self.broadcasts.append(uploadfailed+" "+file+".") c.close() return self.result = buf.getvalue() #print self.result c.close() doc = urlparse.urlparse(self.result) self.urls.append(doc.getElementsByTagName("download")[0].childNodes[0].nodeValue) def setClipBoard(self): c = gtk.Clipboard() c.set_text('\n'.join(self.urls)) c.store() if len(self.urls) == 1: self.broadcasts.append(oneimage) elif len(self.urls) != 0: self.broadcasts.append(str(len(self.urls))+" "+multimages) if __name__ == '__main__': uploadir = Uploadir(sys.argv) Any help would be gratefully appreciated. Warm regards,

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  • An AuthLogic form is giving me incorrect validation errors -- why?

    - by sscirrus
    Hi everyone, I set up AuthLogic for Rails according to the AuthLogic example: http://github.com/binarylogic/authlogic_example. I can log on successfully to the system, but when accessing users/new.html.erb to register a new user, the form returns the following validation errors: Email is too short (minimum is 6 characters) Email should look like an email address. Login is too short (minimum is 3 characters) Login should use only letters, numbers, spaces, and .-_@ please. Password is too short (minimum is 4 characters) Password confirmation is too short (minimum is 4 characters) None of these errors exist in the data I am entering. # new.html.erb <%= form.label :login, nil, :class => "label" %><br /> <%= form.text_field :login, :class => "inputBox", :name => "login", :type => "text" %><br /> <%= form.label :password, form.object.new_record? ? nil : "Change password", :class => "label" %><br /> <%= form.password_field :password, :class => "inputBox", :name => "password", :type => "text" %><br /> <%= form.label "Confirm password", nil, :class => "label" %><br /> <%= form.password_field :password_confirmation, :class => "inputBox", :name => "password_confirmation", :type => "text" %><br /> <%= form.label :email, nil, :class => "label" %><br /> <%= form.text_field :email, :class => "inputBox", :name => "email", :type => "text" %><br /> # Users controller def new @user = User.new render :layout => "forms" end I think the problem is that the data isn't being transferred somehow and therefore AuthLogic doesn't think the inputs are sufficient. Do you have any idea why AuthLogic is telling me the data doesn't satisfy its validation?

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  • Change the Session Variable Output

    - by user567230
    Hello I am using Dreamweaver CS5 with Coldfusion 9 to build a dynamic website. I have a MS Access Database that stores login information which includes ID, FullName, FirstName, LastName, Username, Pawword, AcessLevels. My question is this: I currently have session variable to track the Username when it is entered into the login page. However I would like to use that Username to pull the User's FullName to display throughout the web pages and use for querying data. How do I change the session variable to read that when they are not entering their FullName on the login page but only Username and password. I have listed my login information code below if there is any additional information needed please let me know. This is the path for which the FullName values reside DataSource "Access" Table "Logininfo" Field "FullName" I want the FullName to be unique based on the Username submitted from the Login page. I apologize in advance for any rookie mistake I may have made I am new to this but learning fast! Ha. <cfif IsDefined("FORM.username")> <cfset MM_redirectLoginSuccess="members_page.cfm"> <cfset MM_redirectLoginFailed="sorry.cfm"> <cfquery name="MM_rsUser" datasource="Access"> SELECT FullName, Username,Password,AccessLevels FROM Logininfo WHERE Username=<cfqueryparam value="#FORM.username#" cfsqltype="cf_sql_clob" maxlength="50"> AND Password=<cfqueryparam value="#FORM.password#" cfsqltype="cf_sql_clob" maxlength="50"> </cfquery> <cfif MM_rsUser.RecordCount NEQ 0> <cftry> <cflock scope="Session" timeout="30" type="Exclusive"> <cfset Session.MM_Username=FORM.username> <cfset Session.MM_UserAuthorization=MM_rsUser.AccessLevels[1]> </cflock> <cfif IsDefined("URL.accessdenied") AND false> <cfset MM_redirectLoginSuccess=URL.accessdenied> </cfif> <cflocation url="#MM_redirectLoginSuccess#" addtoken="no"> <cfcatch type="Lock"> <!--- code for handling timeout of cflock ---> </cfcatch> </cftry> </cfif> <cflocation url="#MM_redirectLoginFailed#" addtoken="no"> <cfelse> <cfset MM_LoginAction=CGI.SCRIPT_NAME> <cfif CGI.QUERY_STRING NEQ ""> <cfset MM_LoginAction=MM_LoginAction & "?" & XMLFormat(CGI.QUERY_STRING)> </cfif> </cfif>

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  • Re-Add tabBarController's view into window and the device is in landscape mode

    - by user285553
    Hello, I have an app that is a tabBarController based app. I have 4 tabs on it and one of these is for logging in/out in my app. The main ideea is that when I logout, I release the tabBarController (this will release the all 4 view controllers too - I have done this becuse I want to refersh all the views after logging out to look just like the first time).After this, I alloc it again and add the view controllers aagin,set the tabBarItem's titles,etc.This work ok. The problem is when I am in landscape mode;my logout view is painted to fit the landscape area,but after disconnect(now I releasse and alloc again the tabbarController) the view is painted in portrait mode but my device is in lanscape. After disconnected, I call the releaseOldTabView and the createNewTabView.After this tabBarController is in portrait insead of landscape. -(void)releaseOldTabView:(BOOL)tabViewEnabled{ if(tabViewEnabled){ [tabBarController.view removeFromSuperview]; [tabBarController release]; } } -(void)createNewTabView{ tabBarController = [[UITabBarController alloc] init]; NSMutableArray *oneArray = [[NSMutableArray alloc] init]; tabBarController.delegate = self; LoginViewController *login= [[LoginViewController2 alloc] initWithNibName:@"LoginViewController" bundle:nil]; SecondViewController *secondController = [[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:nil]; ThirdViewController *thirdController = [[ThirdViewController alloc] init]; FourthViewController *fourthController = [[FourthViewController alloc] init]; login.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"Login" image:[UIImage imageNamed:@"connect.png"] tag:0]; secondController.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"TabBar2" image:[UIImage imageNamed:@"tabBar2.png"] tag:1]; thirdController.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"TabBar3" image:[UIImage imageNamed:@"tabBar3.png"] tag:2]; fourthController.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"TabBar4" image:[UIImage imageNamed:@"tabBar4.png"] tag:3]; [oneArray addObject:login]; [oneArray addObject:secondController]; [oneArray addObject:thirdController]; [oneArray addObject:fourthController]; [tabBarController setViewControllers:oneArray]; //[tabBarController.view convertRect:tabBarController.view.frame toView:window]; [window addSubview:tabBarController.view]; [oneArray release]; [login release]; [secondController release]; [thirdController release]; [fourthController release]; } After calling this method, the tabbar view is in portrait,but statusBar(the top bar which says the carrier name) is painted normally(landscape). I also tried the [tabBarController.view convertRect:tabBarController.view.frame toView:window]; but without any succes. Can anyone give a hand of help? Thanks in advance, Alex.

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  • zend-framework navigation

    - by ulduz114
    i have this xml file for Creating a container , if i want create a db for save this items and and create container from db how should i do ? <?xml version="1.0" encoding="utf-8"?> <config> <nav> <logout> <label>logout</label> <controller>authentication</controller> <action>logout</action> <resource>logout</resource> </logout> <login> <label>login</label> <controller>authentication</controller> <action>login</action> <resource>login</resource> </login> <test> <label>test</label> <uri>#</uri> <resource>test</resource> <pages> <list> <label>list</label> <controller>tset</controller> <action>listtest</action> </list> <archive> <label>archive</label> <controller>myarchive</controller> <action>archive</action> </archive> </pages> </test> </nav> </config> and code in bootsrap $navContainerConfig = new Zend_Config_Xml(APPLICATION_PATH . 'navigation.xml', 'nav'); $navContainer = new Zend_Navigation($navContainerConfig);

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  • Instance Failure in asp.net

    - by user85511
    I have a web application that is working perfectly in my system. However, when I copied it to another system, I couldn't login to the application. There is an error: Server Error in '/' Application. -------------------------------------------------------------------------------- Instance failure. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.InvalidOperationException: Instance failure. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [InvalidOperationException: Instance failure.] System.Data.SqlClient.TdsParser.Connect(ServerInfo serverInfo, SqlInternalConnectionTds connHandler, Boolean ignoreSniOpenTimeout, Int64 timerExpire, Boolean encrypt, Boolean trustServerCert, Boolean integratedSecurity, SqlConnection owningObject) +4858423 System.Data.SqlClient.SqlInternalConnectionTds.AttemptOneLogin(ServerInfo serverInfo, String newPassword, Boolean ignoreSniOpenTimeout, Int64 timerExpire, SqlConnection owningObject) +90 System.Data.SqlClient.SqlInternalConnectionTds.LoginNoFailover(String host, String newPassword, Boolean redirectedUserInstance, SqlConnection owningObject, SqlConnectionString connectionOptions, Int64 timerStart) +257 System.Data.SqlClient.SqlInternalConnectionTds.OpenLoginEnlist(SqlConnection owningObject, SqlConnectionString connectionOptions, String newPassword, Boolean redirectedUserInstance) +221 System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, Object providerInfo, String newPassword, SqlConnection owningObject, Boolean redirectedUserInstance) +189 System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection) +4859187 System.Data.ProviderBase.DbConnectionFactory.CreatePooledConnection(DbConnection owningConnection, DbConnectionPool pool, DbConnectionOptions options) +31 System.Data.ProviderBase.DbConnectionPool.CreateObject(DbConnection owningObject) +433 System.Data.ProviderBase.DbConnectionPool.UserCreateRequest(DbConnection owningObject) +66 System.Data.ProviderBase.DbConnectionPool.GetConnection(DbConnection owningObject) +499 System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) +65 System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) +117 System.Data.SqlClient.SqlConnection.Open() +122 System.Web.DataAccess.SqlConnectionHolder.Open(HttpContext context, Boolean revertImpersonate) +87 System.Web.DataAccess.SqlConnectionHelper.GetConnection(String connectionString, Boolean revertImpersonation) +221 System.Web.Security.SqlMembershipProvider.GetPasswordWithFormat(String username, Boolean updateLastLoginActivityDate, Int32& status, String& password, Int32& passwordFormat, String& passwordSalt, Int32& failedPasswordAttemptCount, Int32& failedPasswordAnswerAttemptCount, Boolean& isApproved, DateTime& lastLoginDate, DateTime& lastActivityDate) +815 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved, String& salt, Int32& passwordFormat) +105 System.Web.Security.SqlMembershipProvider.CheckPassword(String username, String password, Boolean updateLastLoginActivityDate, Boolean failIfNotApproved) +42 System.Web.Security.SqlMembershipProvider.ValidateUser(String username, String password) +78 System.Web.UI.WebControls.Login.AuthenticateUsingMembershipProvider(AuthenticateEventArgs e) +60 System.Web.UI.WebControls.Login.OnAuthenticate(AuthenticateEventArgs e) +119 System.Web.UI.WebControls.Login.AttemptLogin() +115 System.Web.UI.WebControls.Login.OnBubbleEvent(Object source, EventArgs e) +101 System.Web.UI.Control.RaiseBubbleEvent(Object source, EventArgs args) +37 System.Web.UI.WebControls.Button.OnCommand(CommandEventArgs e) +118 System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) +166 System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +10 System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +13 System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +36 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1565 -------------------------------------------------------------------------------- Version Information: Microsoft .NET Framework Version:2.0.50727.3053; ASP.NET Version:2.0.50727.3053 What could be the reason for such an error? How could I solve this?

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  • Custom fail2ban Filter

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • Custom fail2ban Filter for phpMyadmin bruteforce attempts

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • SSH Public Key Authentication only works if active session exists before

    - by Webx10
    I have a rather strange problem with my SSH configuration. I set up my server with the help of a Remote Access Card and configured everything with a KVM viewer. So while being logged into the server via the KVM Viewer I configured SSH with only pubkey and tried to login from my local laptop. It worked fine. If I quit the KVM Session (or logout with the user in the KVM session) I cannot login via ssh anymore (pubkey denied). SSH login only works as long as the user is somewhere still logged in. Any hints what the problem might be? Console output for a failed login (all personal data exchanged): OpenSSH_6.2p2, OSSLShim 0.9.8r 8 Dec 2011 debug1: Reading configuration data /Users/mylocaluser/.ssh/config debug1: Reading configuration data /etc/ssh_config debug1: /etc/ssh_config line 20: Applying options for * debug1: /etc/ssh_config line 103: Applying options for * debug1: Connecting to 100.100.100.100 [100.100.100.100] port 12345. debug1: Connection established. debug1: identity file /Users/mylocaluser/.ssh/id_rsa type 1 debug1: identity file /Users/mylocaluser/.ssh/id_rsa-cert type -1 debug1: identity file /Users/mylocaluser/.ssh/id_dsa type -1 debug1: identity file /Users/mylocaluser/.ssh/id_dsa-cert type -1 debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_6.2 debug1: Remote protocol version 2.0, remote software version OpenSSH_6.6.1p1 Ubuntu-2ubuntu2 debug1: match: OpenSSH_6.6.1p1 Ubuntu-2ubuntu2 pat OpenSSH* debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr [email protected] none debug1: kex: client->server aes128-ctr [email protected] none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Server host key: RSA ab:12:23:34:45:56:67:78:89:90:12:23:34:45:56:67 debug1: Host '[100.100.100.100]:12345' is known and matches the RSA host key. debug1: Found key in /Users/mylocaluser/.ssh/known_hosts:36 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: /Users/mylocaluser/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Offering RSA public key: /Users/mylocaluser/.ssh/id_rsa2 debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/mylocaluser/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Console output for a successfull login (only possible while "active session" exists): OpenSSH_6.2p2, OSSLShim 0.9.8r 8 Dec 2011 debug1: Reading configuration data /Users/mylocaluser/.ssh/config debug1: Reading configuration data /etc/ssh_config debug1: /etc/ssh_config line 20: Applying options for * debug1: /etc/ssh_config line 103: Applying options for * debug1: Connecting to 100.100.100.100 [100.100.100.100] port 12345. debug1: Connection established. debug1: identity file /Users/mylocaluser/.ssh/id_rsa type 1 debug1: identity file /Users/mylocaluser/.ssh/id_rsa-cert type -1 debug1: identity file /Users/mylocaluser/.ssh/id_dsa type -1 debug1: identity file /Users/mylocaluser/.ssh/id_dsa-cert type -1 debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_6.2 debug1: Remote protocol version 2.0, remote software version OpenSSH_6.6.1p1 Ubuntu-2ubuntu2 debug1: match: OpenSSH_6.6.1p1 Ubuntu-2ubuntu2 pat OpenSSH* debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr [email protected] none debug1: kex: client->server aes128-ctr [email protected] none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Server host key: RSA ab:12:23:34:45:56:67:78:89:90:12:23:34:45:56:67 debug1: Host '[100.100.100.100]:12345' is known and matches the RSA host key. debug1: Found key in /Users/mylocaluser/.ssh/known_hosts:36 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: /Users/mylocaluser/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 279 debug1: Authentication succeeded (publickey). Authenticated to 100.100.100.100 ([100.100.100.100]:12345). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. debug1: Sending environment. debug1: Sending env LANG = de_DE.UTF-8 Welcome to Ubuntu 14.04.1 LTS

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  • Screen Scraping Twitter

    - by BRADINO
    I got an email today asking for help to scrape Twitter. In particular, to be able to login. So I am going to show everyone, NOT to encourage anyone to violate Twitters terms of use but as an educational blog post about how PHP and cURL can be used to post variables and store cookies. Again, I am using the cScrape class I wrote, which you can download. Step 1 First go to twitter.com and look at the source code of the login to get the form field names and the form post location. You will see that the form posts to https://twitter.com/session and the username and password fields are session[username_or_email] and session[password] respectively. Step 2 Now you are ready to login. So using the fetch function in the Scrape class you create an associative array to contain the form values you want to post. The other thing you will need to do is uncomment the lines for CURLOPT_COOKIEFILE and CURLOPT_COOKIEJAR. Cookies will be required to stay logged in and scrape around. The paths to the cookie files need to be writable by your app. Also you will need to uncomment the line about CURLOPT_FOLLOWLOCATION. $data = array('session[username_or_email]' => "bradino", 'session[password]' => "secret"); $scrape->fetch('https://twitter.com/sessions',$data); Step 1.5 Oops that didn't work. All I got back was 403 Forbidden: The server understood the request, but is refusing to fulfill it. Ahhh I see another variable called authenticity_token I bet Twitter was looking for that. So let's back up and first hit twitter.com to get the authenticity_token variable, and then make the login post request with that variable included in our array of parameters. $scrape->fetch('https://twitter.com'); $data = array('session[username_or_email]' => "bradino", 'session[password]' => "secret"); $data['authenticity_token'] = $scrape->fetchBetween('name="authenticity_token" type="hidden" value="','"',$scrape->result); $scrape->fetch('https://twitter.com/sessions',$data); echo $scrape->result; So that's basically it. Now you are logged in and can scrape around and request other pages as you normally would. Sorry it wasn't a longer post. I really do enjoy this kind of stuff so if anyone has a request, hit me up. Errors? 1) Make sure that you are properly parsing the token variable 2) Make sure that you uncommented the lines about CURLOPT_COOKIEFILE and CURLOPT_COOKIEJAR, those options need to be enabled and be sure the path set is writable by your application 3) Make sure that the path to the cookie file is writable and that it is getting data written to it 4) If you get a message about being redirected you need to uncomment the line about CURLOPT_FOLLOWLOCATION, that option needs to be enabled true

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  • SQL SERVER – Another lesser known feature of SQL Server Management Studio 2012 – Guest Post by Balmukund Lakhani

    - by Pinal Dave
    This is a fantastic blog post from my dear friend Balmukund ( blog | twitter | facebook ). He had presented a fantastic session in our last UG and there were lots of requests from attendees that he blogs about it. Well, here is the blog post about the same very popular UG session. Let us read the entire blog post in the voice of the Balmukund himself. In one of my previous guest blog on SQL Authority, I wrote about “Additional Connection Parameter” tab of login screen in SQL Server Management Studio (a.k.a. SSMS). On the similar lines, this blog is going to show little less known new feature of login main screen (“Connect to Server”) of SSMS 2012. You might have seen below screen countless times and you might wonder what is there is blog about in this simple screen. Well, continue reading and you would get the answer. Many times, DBA have to login to production server from non-regular machine, may be a developer’s workstation. Once you login to SQL, do your work and close the management studio. Do you know that your server name is saved in management studio? Of course, very useful feature because you may not like to type server name/IP address every time. Whatever servers you have connected, it would be stored by management studio. But sometime, it’s annoying! What you would do if you want SQL Server Management Studio to forget “all” the servers listed in drop down of Server name? To do that, you need to know how and where it’s stored. You can use one of my favorite tool from sysinternals called Process Monitor (also known as ProcMon) and easily figure out that this is stored in a file under your windows user profile. Below is the file in SQL 2008 R2 Management Studio. %appdata%\Microsoft\Microsoft SQL Server\100\Tools\Shell\SqlStudio.bin For SQL Server 2012, here is what we can see in ProcMon So, the path is %appdata%\Microsoft\Microsoft SQL Server\110\Tools\Shell\SqlStudio.bin So far, you might wonder, where is the new feature? I have been asked by many users to delete entries from SSMS “Connect to Server” server name list. Well, unofficially, you can delete the file directly which we found via ProcMon. Note that delete file to get rid of server list is not officially supported by Microsoft. Better way to achieve this is provided in SSMS 2012. To delete the servers from the list, highlight the name we want to delete (via keyboard or mouse) and then press delete key via keyboard. We can’t be multi-select and has to be done one by one. We can delete as many entries we want. I have delete few from first screenshot taken and here is the modified version. This is not available in SQL 2008 R2 and its previous version. This came from feedback given to SQL Server Product group. Hope you have learned something new today! Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, T SQL, Technology

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