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  • Passing a URL as a URL parameter

    - by Andrea
    I am implementing OpenId login in a CakePHP application. At a certain point, I need to redirect to another action, while preserving the information about the OpenId identity, which is itself a URL (with GET parameters), for instance https://www.google.com/accounts/o8/id?id=31g2iy321i3y1idh43q7tyYgdsjhd863Es How do I pass this data? The first attempt would be function openid() { ... $this->redirect(array('controller' => 'users', 'action' => 'openid_create', $openid)); } but the obvious problem is that this completely messes up the way CakePHP parses URL parameters. I'd need to do either of the following: 1) encode the URL in a CakePHP friendly manner for passing it, and decoding it after that, or 2) pass the URL as a POST parameter but I don't know how to do this. EDIT: In response to comments, I should be more clear. I am using the OpenId component, and I have a working OpenId implementation. What I need to do is to link OpenId with an existing user system. When a new user logs in via OpenId, I ask for more details, and then create a new user with this data. The problem is that I have to keep the OpenId URL throughout this process.

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  • How to Access value of dynamically created control?

    - by sharad
    i have asp.net web application in which i need to create form dynamically depend upon table which user selected.however,i created form dynamically with it's control like text box,drop downlist etc. but not able to access those controls at particular button click event. My form scenario is like this: i have dropdownlist in which i display list of tables,button control say display( on click event which i redirect page with some addition in querystring so that at page init it dynamically genrate controls) and another button control which used to access this controls value say Submit and store in database. This is my code: At Display button Click event: Response.Redirect("dynamic_main.aspx?mode=edit&tablename=" + CMBTableList.SelectedItem.ToString()); This is code For page.Init level if (Request.QueryString["mode"] != null) { if (Request.QueryString["mode"].ToString() == "edit") { Session["tablename"] = Request.QueryString["tablename"].ToString(); // if (Session["tablename"].ToString() == CMBTableList.SelectedItem.ToString()) //{ createcontrol(Session["tablename"].ToString()); // } } } i have used createcontrol() which genrate controls Code For Submit Button: string[] contid=controlid.Value.Split(','); MasterPage ctl00 = FindControl("ctl00") as MasterPage; ContentPlaceHolder cplacehld = ctl00.FindControl("ContentPlaceHolder2") as ContentPlaceHolder; Panel panel1 = cplacehld.FindControl("plnall") as Panel; Table tabl1 = panel1.FindControl("id1") as Table; foreach (string sin in contid) { string splitcvalu = sin.Split('_')[0].ToString(); ControlsAccess contaccess = new ControlsAccess(); if (splitcvalu.ToString() == "txt") { TextBox txt = (TextBox)tabl1.FindControl(sin.ToString()); //TextBox txt = cplacehld.FindControl(sin.ToString()) as TextBox; val = txt.ID; } else { DropDownList DDL = cplacehld.FindControl(sin.ToString()) as DropDownList; } } Here i am no able to access this textbox or drop downlist.i am getting id of particular control from hidden field controlid in which i have stored it during genrating controls. i have used findcontrol() it works in case of finding masterpage,contentplaceholder,table etc. but in case of textbox or other control it doesnt work it shows it returns null. Anyone can help me. Thanks

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  • Handling form from different view and passing form validation through session in django

    - by Mo J. Mughrabi
    I have a requirement here to build a comment-like app in my django project, the app has a view to receive a submitted form process it and return the errors to where ever it came from. I finally managed to get it to work, but I have doubt for the way am using it might be wrong since am passing the entire validated form in the session. below is the code comment/templatetags/comment.py @register.inclusion_tag('comment/form.html', takes_context=True) def comment_form(context, model, object_id, next): """ comment_form() is responsible for rendering the comment form """ # clear sessions from variable incase it was found content_type = ContentType.objects.get_for_model(model) try: request = context['request'] if request.session.get('comment_form', False): form = CommentForm(request.session['comment_form']) form.fields['content_type'].initial = 15 form.fields['object_id'].initial = 2 form.fields['next'].initial = next else: form = CommentForm(initial={ 'content_type' : content_type.id, 'object_id' : object_id, 'next' : next }) except Exception as e: logging.error(str(e)) form = None return { 'form' : form } comment/view.py def save_comment(request): """ save_comment: """ if request.method == 'POST': # clear sessions from variable incase it was found if request.session.get('comment_form', False): del request.session['comment_form'] form = CommentForm(request.POST) if form.is_valid(): obj = form.save(commit=False) if request.user.is_authenticated(): obj.created_by = request.user obj.save() messages.info(request, _('Your comment has been posted.')) return redirect(form.data.get('next')) else: request.session['comment_form'] = request.POST return redirect(form.data.get('next')) else: raise Http404 the usage is by loading the template tag and firing {% comment_form article article.id article.get_absolute_url %} my doubt is if am doing the correct approach or not by passing the validated form to the session. Would that be a problem? security risk? performance issues? Please advise Update In response to Pol question. The reason why I went with this approach is because comment form is handled in a separate app. In my scenario, I render objects such as article and all I do is invoke the templatetag to render the form. What would be an alternative approach for my case? You also shared with me the django comment app, which am aware of but the client am working with requires a lot of complex work to be done in the comment app thats why am working on a new one.

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  • PHP .htaccess issue, specific/dynamic keywords

    - by Kunal
    Here goes my .htaccess file's content. Options +FollowSymLinks RewriteEngine On RewriteRule ^online-products$ products.php?type=online RewriteRule ^land-products$ products.php?type=land RewriteRule ^payment-methods$ payment-methods.php RewriteRule ^withdrawal-methods$ withdrawal-methods.php RewriteRule ^deposit-methods$ deposit-methods.php RewriteRule ^product-bonuses$ product-bonuses.php RewriteRule ^law-and-regulations$ law-and-regulations.php RewriteRule ^product-news$ product-news.php RewriteRule ^product-games$ product-games.php RewriteRule ^no-products$ no-products.php RewriteRule ^page-not-found$ notfound.php RewriteCond %{SCRIPT_FILENAME} !-f RewriteCond %{SCRIPT_FILENAME} !-d RewriteRule ^casinos/(.*)$ product.php?id=$1 RewriteCond %{SCRIPT_FILENAME} !-f RewriteCond %{SCRIPT_FILENAME} !-d RewriteRule ^(.*)$ cms.php?link=$1 ErrorDocument 404 /notfound.php What I am trying to achive here is that the first set of rules apply to some specific keywords which should redirect to specific hard coded pages. But anything else parat from those keywords should redirect to cms.php as a parameter as you can see. But the problem is that every keyword is getting redirected to cms.php. Whereas I want any other keyword apart from which are already hard coded in .htaccess file should go cms.php. Not just every keyword. Example: www.sitename.com/online-products -> www.sitename.com/products.php?type=online www.sitename.com/about-the-website -> www.sitename.com/cms.php?id=about-the-website www.sitename.com/product-news -> www.sitename.com/product-news.php Also another issue I am facing is I can not use any keyword with space. Like "online-products" is fine, but I can't use "online products". Please help me out with your expert knowledge. Many thanks in advance for your kind help. Appreciate it.

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  • WebKit and Opera won't load from this server when it's in a frame

    - by crimson_penguin
    This site loads fine in Firefox, but in WebKit browsers (Safari and Google Chrome) it won't load the frame, and in Opera I get this error: "The Web site does not permit its content to be displayed in a frame. It must be displayed in a separate window.". I don't expect to be able to actually fix this, as I don't have control over the frames page (only the content of the frame), but my question is: why? The content of the frame loads fine by itself, and saving the frames page and changing the src of the frame to http://w3.org/ loads fine. I did a bit of searching based on the Opera error, and it seemed to suggest it had to do with redirecting. That URL does indeed redirect, but if I change it to http://mini.milli.no/tonje/main (which doesn't redirect), it still doesn't work. Even Apache directory listings don't work - which to me suggests it's server related. But how can a server do that? To be total clear, I'm using Mac OS X 10.6.3, and I tested with Safari 4.0.5, Chrome 5.0.375.55, Opera 10.53, and Firefox 3.6.3. Basically, the newest of all of those things currently.

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  • need help about process........

    - by adeel amin
    when i start process like process= Runtime.getRuntime().exec("gnome-terminal");, it start shell execution, i want to stop shell execution and want to redirect I/O from process, can anybody tell how i can do this? my code is: public void start_process() { try { process= Runtime.getRuntime().exec("bash"); pw= new PrintWriter(process.getOutputStream(),true); br=new BufferedReader(new InputStreamReader(process.getInputStream())); err=new BufferedReader(new InputStreamReader(process.getErrorStream())); } catch (Exception ioe) { System.out.println("IO Exception-> " + ioe); } } public void execution_command() { if(check==2) { try { boolean flag=thread.isAlive(); if(flag==true) thread.stop(); Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } else { try { Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); check=2; }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } } private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) { // TODO add your handling code here: command=tfCmd.getText().toString().trim(); pw.println(command); execution_command(); } when i enter some command in textfield and press execute button, nothing displayed on my output textarea, how i can stop shellexecution and can redirect Input and output?

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  • django-social-auth for Facebook is redirecting home and not logging in

    - by Scott Rogowski
    I have had django-social-auth working for Google for quite some time now but am having problems with Facebook. I am at the point where clicking on the /login/facebook/ link will take me to the Facebook authorization page. I then click "go to app" and it redirects me to my home page but does not log in or create a user but does put some strange "#=" onto the back of my URL. Reading up on that, here https://developers.facebook.com/blog/post/552/, and here https://github.com/omab/django-social-auth/issues/199, it seems that would be happening if the redirect uri was not defined. However, on my facebook app settings, I have the following (replacing my site with example.com): + App Namespace: "example" + Site URL: "http://example.com/complete/facebook/" + Site Domain: "example.com" + Sandbox Mode: "On" + Post-Authorize Redirect URL: "http://apps.facebook.com/example/" + Deauthorize URL: "http://www.example.com/" + Post-Authorize URL: "http://example.com/complete/facebook/" The request that django-social-auth is sending to facebook is (replacing my info again): "https://www.facebook.com/dialog/oauth?scope=email&state=*&redirect_uri=http%3A%2F%2Fexample.com%2Fcomplete%2Ffacebook%2F%3Fredirect_state%3D***&client_id=*" The /complete/facebook/ is what is in the documentation and google works as /complete/google/ What am I missing here?

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  • My android tests don't get internet access!

    - by Malachii
    The subject says it all. My application gets internet access thanks to the android.permission.INTERNET permission, but my test cases don't while using the instrumentation test runner. This means I can't test my server IO routines in my test cases. What's up? Here's my manifest in case it helps you. Thanks! Sorry about the lack of indents - could not get it working on short notice with this site. Thanks! <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.example.helloandroid" android:versionCode="1" android:versionName="1.0"> <uses-permission android:name="android.permission.INTERNET"></uses-permission> <application android:icon="@drawable/icon" android:label="@string/app_name"> <uses-library android:name="android.test.runner" /> <activity android:name=".HelloAndroid" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <uses-sdk android:minSdkVersion="2" /> <instrumentation android:name="android.test.InstrumentationTestRunner" android:targetPackage="qnext.mobile.redirect" android:label="Qnext Redirect Tests" /> </manifest>

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  • URL with no query parameters - How to distinguish.

    - by Broken Link
    Env: .NET 1.1 I got into this situation. Where I need to give a URL that someone could redirect them to our page. When they redirect they also need to tell us, what message I need to display on the page. Initially I thought of something like this. http://example.com/a.aspx?reason=100 http://example.com/a.aspx?reason=101 ... http://example.com/a.aspx?reason=115 So when we get this url based on 'reason' we can display different message. But the problem turns out to be that they can not send any query parameters at all. They want 15 difference URL's since they can't send query params. It doesn't make any sense to me to created 15 pages just to display a message. Any smart ideas,that have one URL and pass the 'reason' thru some means? EDIT: Options I'm thinking based on Answers Try HttpRequest.PathInfo or Second option I was thinking was to have a httphanlder read read the path like this - HttpContext.Request.Path based on path act. Ofcourse I will have some 15 entries like this in web.config. <add verb="*" path="reason1.ashx" type="WebApplication1.Class1, WebApplication1" /> <add verb="*" path="reason2.ashx" type="WebApplication1.Class1, WebApplication1" /> Does that look clean?

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  • Codeigniter php activerecord orm limit and offset

    - by user2167174
    I am a bit stuck with this problem I have in phpactiverecord. What I am trying to do is a pagination so I need to limit and offset the query results. I am accessing all of the user posts like so: $user-post; How can I query this to limit and offset the results? Thanx in advance. Code: public function office() { if (!$this->session->userdata('username')) { redirect(base_url()); } $data = array(); $data['posts'] = []; $user = User::find('first', array('id' => $this->session->userdata('id'))); if ($user != null) { if ($user->post != null) { foreach ($user->post as $post) { $posts = array($post->name, $post->description, $post->date,'<a href="'.base_url().'Posts/edit/'.$post->id.'">Edit</a> <br /><a href="'.base_url().'Posts/delete/'.$post->id.'">Delete</a>'); array_push($data['posts'], $posts); } $this->table->set_heading('Name', 'Description', 'Date', '<a href="'.base_url().'Posts/create">+Add</a>'); $tmpl = array('table_open' => '<table class="table table-stripped table-bordered user-posts">'); $this->table->set_template($tmpl); $data['table'] = $this->table->generate($data['posts']); } $this->load->view('template/header.php'); $this->load->view('Users/office.php', $data); $this->load->view('template/footer.php'); } else { redirect(base_url()); } }

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  • Android : Handle OAuth callback using intent-filter

    - by Dave Allison
    I am building an Android application that requires OAuth. I have all the OAuth functionality working except for handling the callback from Yahoo. I have the following in my AndroidManifest.xml : <intent-filter> <action android:name="android.intent.action.VIEW"></action> <category android:name="android.intent.category.DEFAULT"></category> <category android:name="android.intent.category.BROWSABLE"></category> <data android:host="www.test.com" android:scheme="http"></data> </intent-filter> Where www.test.com will be substituted with a domain that I own. It seems : This filter is triggered when I click on a link on a page. It is not triggered on the redirect by Yahoo, the browser opens the website at www.test.com It is not triggered when I enter the domain name directly in the browser. So can anybody help me with When exactly this intent-filter will be triggered? Any changes to the intent-filter or permissions that will widen the filter to apply to redirect requests? Any other approaches I could use? Thanks for your help.

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  • cakephp phone number validation

    - by hellosheikh
    i am new to cakephp 2.x so i dont know how to do this .. i want to login the user from his email address and phone number..what my intention is if the number in database is this "12345" and the user is trying to login through this number "+12345" he can be login into the system.. i have written a code but i dont know how can i use this or to adjust my code within the auth component as the auth component is autometically logging the user .. here is my controller public function beforeFilter() { parent::beforeFilter(); $this->Auth->authenticate = array( 'Authenticate.Cookie' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'userModel' => 'User', 'scope' => array('User.active' => 1) ), 'Authenticate.MultiColumn' => array( 'fields' => array( 'username' => 'email', 'password' => 'password' ), 'columns' => array('email', 'mobileNo'), 'userModel' => 'User', ) ); } public function login() { if ($this->Auth->login() || $this->Auth->loggedIn()) { $this->redirect('/users/dashboard'); }else{ $this->layout='logindefault'; $this->set('title_for_layout', 'Account Login'); /*$this->Auth->logout(); $cookie = $this->Cookie->read('Auth.User'); */ if ($this->request->is('post')) { if ($this->Auth->login() || $this->Auth->loggedIn()) { if ($this->Session->check('Auth.User')){ $this->_setCookie($this->Auth->user('idUser')); $this->redirect('/users/dashboard'); } }else { $this->Session->setFlash('Incorrect Email/Password Combination'); } }} } here is the code which i am trying to add .. $mobileNo='+123456789'; if (strpos($mobileNo,'+') !== false) { $mobileNo=str_replace("+", "",$mobileNo); } ?

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  • Javascript ended event when video playback ends on android

    - by Tjofras
    I have been trying to create a web page that will redirect the user after he has watched a video (or if he aborted the playback). I've got this working on the iphone but can't really figure out how it works on the android. On the Iphone i have found two ways of doing this. using the tag to embed the quicktime plugin and then adding a event listener with javascript to listen to the 'qt_ended' event. This does obviously not work on android because there is no quicktime plugin. The second thing i tried was using the html5 -tag and listening to the 'ended' event, again this worked on the iphone but to my surprise not on android. In this case i got the video playing on the android phone but no redirect occurred after the video had reached the end. So my guess is that the android browser does not fully support the video-tag and that it does not fire the event. So at this time i don't really know how to proceed. I'm guessing i could do something similar to the quicktime embed solution but using a plugin available on android. But i cant find any information on what plugins is available on the android and if they support some kind of 'ended'-event.

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  • How to avoid shell execution of a Process?

    - by adeel amin
    When I start a process like process = Runtime.getRuntime().exec("gnome-terminal");, it starts shell execution. I want to stop shell execution and want to redirect I/O from process, can anybody tell how I can do this? My code is: public void start_process() { try { process= Runtime.getRuntime().exec("gnome-terminal"); pw= new PrintWriter(process.getOutputStream(),true); br=new BufferedReader(new InputStreamReader(process.getInputStream())); err=new BufferedReader(new InputStreamReader(process.getErrorStream())); } catch (Exception ioe) { System.out.println("IO Exception-> " + ioe); } } public void execution_command() { if(check==2) { try { boolean flag=thread.isAlive(); if(flag==true) thread.stop(); Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } else { try { Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); check=2; }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } } private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) { // TODO add your handling code here: command=tfCmd.getText().toString().trim(); pw.println(command); execution_command(); } When I enter some command in textfield and press execute button, nothing is displayed on my output textarea, how I can stop shell execution and redirect input and output?

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  • cakephp read and display from more than one related table

    - by z22
    I have 2 tables Users and Artists. User: id name password city_id state_id country_id Artist: id user_id description I wish to create add and edit form(single form acts as add and edit). But on click of edit link, I wish to fill in the form fields from user as well as artist table. How do i do that? Below is my controller code: public function artist_register() { $this->country_list(); if ($this->request->is('post')) { $this->request->data['User']['group_id'] = 2; if ($this->{$this->modelClass}->saveAll($this->request->data)) { $this->redirect(array('controller' => 'Users', 'action' => 'login')); } } $this->render('artist_update'); } public function artist_update($id) { $artist = $this->{$this->modelClass}->findByuser_id($id); $artist_id = $artist[$this->modelClass]['id']; if($this->request->is('get')) { $this->request->data = $this->{$this->modelClass}->read(null, $artist_id); $this->request->data = $this->{$this->modelClass}->User->read(null, $id); } else { if($this->{$this->modelClass}->save($this->request->data)) { $this->Session->setFlash('Your Profile has been updated'); $this->redirect(array('action' => 'index')); } } } The code doesnt work. how do i solve it?

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • Clicking on MenuItem without clicking on the text

    - by pringlesinn
    I've got a Menu, and I want to click on the menu, but not on the text if you guys know what i mean. The MenuItem has a border, or something like this, but when I click on it it won't redirect to the page I want unless I click on text. Is it possible to click on the whole "Button" and redirect or do what is need to do? My menu is like this: <rich:dropDownMenu showDelay="250" hideDelay="0" submitMode="none"> <f:facet name="label">Tools</f:facet> <rich:menuItem> <s:link view="/pages/tools/ppaParameters/PpaParametersEdit.xhtml" value="Parameters" id="PpaParametersId" includePageParams="false" propagation="none"/> </rich:menuItem> <rich:menuGroup value="Security"> <rich:menuItem> <s:link view="/pages/tools/security/ppaModule/PpaModuleEdit.xhtml" value="Module" id="PpaModuleId" includePageParams="false" propagation="none" /> </rich:menuItem> </rich:menuGroup> </rich:dropDownMenu> There's an example. I need to click on text to make it work out.

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  • Redirecting users after destroy

    - by mathee
    I have 3 models: Questions, Answers, and Profiles (I know, it should be called "Users"). When you view a question Q, I query the database for the answers to Q. (They are linked by id.) In the view, the current user has the option to delete his answer by clicking on the destroy link displayed next to his answer: %table %tr %td Answers: - @answers.each do |a| %tr %td - @provider = Profile.find(a.provider) %i #{h @provider.username} said: %br #{h a.description} %td = link_to 'View full answer', a %td - if a.provider == @profile.id #{link_to 'Delete my answer', a, :confirm => 'Are you sure?', :method => :delete} The problem is that when the user clicks on the destroy link, it redirects to the /answers/index. I want it to redirect to /questions/Q. What's the best way to do this? I know that there's a redirect_to method, but I don't know how to implement it when I want to redirect to an action for a different controller. It also needs to remember the question from which the answer is being deleted. I tried passing something like :question_id in link_to as: #{link_to 'Delete my answer', a, :confirm => 'Are you sure?', :question_id => @question.id, :method => :delete} In AnswersController#destroy: def destroy @answer = Answer.find(params[:id]) @answer.destroy respond_to do |format| format.html { redirect_to(answers_url) } format.xml { head :ok } end @question = Question.find(params[:question_id]) redirect_to question_path(@question) end The :question_id information is not passed to the destroy method, so I get this error: Couldn't find Question without an ID To confirm, I added a puts call before Question.find, and it returned nil.

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  • In my cakephp project the save function is not working?

    - by Faheem
    My controller action is: function add() { if (!empty($this-data)) { $this-Customer-create(); if ($this-Customer-save($this-data)) { $this-Session-setFlash('A new Customer has been added'); $this-redirect(array('action'='index')); } else { $this-Session-setFlash('The customer cannot be added this time. Try again later.'); $this-redirect(array('action'='index')); } } } My model is: class Customer extends AppModel { var $name = 'Customer'; var $validate = array( 'name' = array( 'length'= array( 'rule' = array('between', 4,50), 'message' = 'Name must be minimum 4 and maximum 50 characters long.' ), 'checkUnique'= array( 'rule' = 'isUnique', 'message' = 'This Name is already registered' ) )); and this is my view: create('Customer',array('action'='add'));? input('Customer.name'); echo $form-input('Customer.balance',array('type'='hidden','default'=0)); ? end('Submit');? every time I submit the form it splashes: The customer cannot be added this time. Try again later.

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  • Rackspace Cloud rewrite jpg causes Session reset

    - by willoller
    This may be the .Net version of this question. I have an image script with the following: ... Response.WriteFile(filename); Response.End(); I am rewriting .jpg files using the following rewrite rule in web.config: <rule name="Image Redirect" stopProcessing="true"> <match url="^product-images/(.*).jpg" /> <conditions> <add input="{REQUEST_URI}" pattern="\.(jp?g|JP?G)$" /> </conditions> <action type="Redirect" redirectType="SeeOther" url="/product-images/ProductImage.aspx?path=product-images/{tolower:{R:1}}.jpg" /> </rule> It basically just rewrites the image path into a query parameter. The problem is that (intermittently of course) Mosso returns a new Asp Session cookie which breaks the whole world. Directly accessing a static .jpg file does not cause this problem. Directly accessing the image script does not cause it either. Only rewriting a .jpg file to the .aspx script causes the Session loss. Things I have tried (From the Rackspace doc How can I bypass the cache?) I added Private cacheability to the image script itself: Response.Cache.SetCacheability(HttpCacheability.Private); I tried adding these cache-disabling nodes to web.config: <staticContent> <clientCache cacheControlMode="DisableCache" /> </staticContent> and <httpProtocol> <customHeaders> <add name="Cache-Control private" value="Cache-Control private" </customHeaders> </httpProtocol> The Solution I need The browser cache cannot be disabled. This means potential solutions involving Cache.SetNoStore() or HttpCacheability.NoCache will not work.

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  • Rewrite a URL that's already been redirected?

    - by Jack
    Hi guys, I'm running an Apache2 web server with a dynamic IP address. I bought exampledomain.net, and I use no-ip.com's domain-update service to redirect any visitors to my current ip address (endnote #1). For example, someone visits exampledomain.net and they get redirected to 73.181.57.34. It works like a charm. However, it isn't all that user-friendly. Can I rewrite the redirected, ip-address URL? I tried these rewrite rules in the root folder's .htaccess... RewriteEngine On RewriteCond %{HTTP_HOST} ^73\.181\.57\.34:88 RewriteRule ^(.*)$ http://www.exampledomain.net/$1 [L,NC] # I simplified the RewriteCond. I would use regex in a real situation. Of course, this creates an infinite loop. The user visits www.exampledomain.net. They're redirected to 73.181.57.34:88 by no-ip. Apache redirects them to www.exampledomain.net which redirects them back to 73.181.57.34:88... so on and so forth. I'm a noob when it comes to rewriting, but is there a way to rewrite a URL without redirecting? I tried these rewrite rules too (a shot in the dark)... RewriteEngine On RewriteCond %{HTTP_HOST} ^73\.181\.57\.34:88 RewriteRule ^(.*)$ my.exampledomain.net/$1 [L,NC] # I'd read that Apache replied with a redirect header when you include http Thanks! (1) No-IP works like this: You download and install their dynamic update client on your server. Every couple of minutes it polls your server for its current external ip address. If it's changed, it updates your server's ip address in no-ip's records.

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  • What are some methods to prevent double posting in a form? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit. METHODS: someone suggested using sessions. I would set the random token to $_SESSION['_token'] and check if that session token is equal to the $_POST['_token'], but how do I do that? When I tried, it still doesn't check

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  • Spring security - same page to deliver different content based on user role

    - by Ramesh
    Hello, i tried to search for any previous post related to my issue but couldnt find any. I have a scenario where in page handles 3 different scenarios and one of them not working. This page returns different content depending on if the user is authenticated or anonymous. localhost:8080/myApp/muUrl?test=authenticatedContent - used for Scenario 1 & 2 localhost:8080/myApp/muUrl?test=anonymousContent - used for Scenario 3 Scenario: 1) Authenticated user accesing the page url - the user gets displayed correct information. Works fine 2) Anonymous user accesing page URL with parameters that requires authentication - If anonymous, there is second level of check on the content they are accessing. for example, based on the GET parameters, there is custom logic to determine if the user has to be authenticated. In which case the page gets redirected to login page (WORKS fine). 3) Anonymous user accessing page URL with parameters that doesnt need authentication - in this case i get the SAvedRequest and redirect to the URL which is taking me to an infinite loop. Am i missing something very obvious or is there a way in AuthenticationProcessFilterEntryPoint to say "DON'T redirect to LOGIN page but process it" ? thanks.

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  • I can't get RedirectToAction to work

    - by DaveDev
    I have the following Action Method that I'm trying to redirect from if the user is valid. But nothing happens. The breakpoint in the redirected-to action method never gets hit. [AcceptVerbs(HttpVerbs.Post)] public ActionResult Login(User user) { try { if (ModelState.IsValid) { if (userRepository.ValidUser(user)) { return RedirectToAction("Index", "Group"); } else { return Json("Invalid"); } } } catch (Exception) { return Json("Invalid"); } } And in another Controller, I have the following Action Method that I'm trying to redirect to: // HttpVerbs.Post doesn't work either [AcceptVerbs(HttpVerbs.Get)] public ActionResult Index(int? page) { const int pageSize = 10; IEnumerable<Group> groups = GetGroups(); var paginatedGroups = new PaginatedList<Group>(groups, page ?? 0, pageSize); return View(paginatedGroups); } private IEnumerable<Group> GetGroups() { return groupRepository.GetGroups(); } Is there anything obviously wrong with what I'm doing? Could somebody suggest a different approach I could take?

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  • How to connect to a third party website in classic asp using javascript for password encryption and yet not giving in the password.

    - by Abbi
    Hi I have to make changes to classic asp website where once a button is clicked it autologins to a third party website with a intermediate page that warns that you are logging in to a third party website. The thirdparty is providing us with a username and password and gave us an examle javascript to encode the password to send to them. Now where do I store the userid and password. I cannot execute the javascript on the serverside. It has to go to the client. If the asp page which has the encryption javascript goes to the client side then the source can be viewed and the username and password is given out. Is there a way that I can have hidden asp page whose only job is to encrypt the password and create a new url and auto redirect it to that new url. So when the user clicks ok on the intermediate warning page I redirect it to this hidden asp page which does the encryption and a creates a url for get method and redirects to that page. I am a novice as far as java script and classic asp is concerned. Any ideas/ advice will be appreciated. Thanks, --Abbi

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