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Get data on jquery ajax success

- by jbatson

anyone know how i would get from opening <table> to </table> in this data that is returned from ajax with jquery. // BEGIN Subsys_JsHttpRequest_Js Subsys_JsHttpRequest_Js.dataReady( '3599', // this ID is passed from JavaScript frontend '<table border=\"0\" width=\"100%\" cellspacing=\"0\" cellpadding=\"0\">\n <tr>\n <td>\n <script type=\"text/javascript\" language=\"javascript\" src=\"includes/ajax_sc.js\"></script>\n <div id=\"divShoppingCard\">\n\n <div class=\"infoBoxHeading\"><a href=\"shopping_cart.php\">Shopping Cart</a></div>\n\n <div>\n <div class=\"boxText\">\n<script language=\"javascript\" type=\"text/javascript\">\nfunction couponpopupWindow(url) {\n window.open(url,\"popupWindow\",\"toolbar=no,location=no,directories=no,status=no,menubar=no,scrollbars=yes,resizable=yes,copyhistory=no,width=450,height=280,screenX=150,screenY=150,top=150,left=150\")\n}\n//--></script><table width=\"100%\" cellspacing=\"0\" cellpadding=\"0\"><tr><td align=\"left\" valign=\"top\" class=\"infoBoxContents\"><span class=\"infoBoxContents\">1 x </span></td><td valign=\"top\" class=\"infoBoxContents\"><a href=\"http://beta.vikingwholesale.com/catalog/eagle-vanguard-limited-edition-p-3769.html\"><span class=\"infoBoxContents\">192 Eagle Vanguard Limited Edition</span></a></td></tr><tr><td align=\"left\" valign=\"top\" class=\"infoBoxContents\"><span class=\"newItemInCart\">4 x </span></td><td valign=\"top\" class=\"infoBoxContents\"><a href=\"http://beta.vikingwholesale.com/catalog/family-traditions-adrenaline-avid-black-p-3599.html\"><span class=\"newItemInCart\">085 Family Traditions Adrenaline - Avid, Black</span></a></td></tr><tr><td align=\"left\" valign=\"top\" class=\"infoBoxContents\"><span class=\"infoBoxContents\">1 x </span></td><td valign=\"top\" class=\"infoBoxContents\"><a href=\"http://beta.vikingwholesale.com/catalog/painted-pony-paradigm-p-4022.html\"><span class=\"infoBoxContents\">336 Painted Pony Paradigm</span></a></td></tr></table></div>\n\n\n <div class=\"boxText\"><img src=\"images/pixel_black.gif\" width=\"100%\" height=\"1\" alt=\"\"/></div>\n\n\n <div class=\"boxText\">$940.00</div>\n\n\n</div>\n\n\n \n </div>\n </td>\n </tr></table>', null ) // END Subsys_JsHttpRequest_Js

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Replace .sln with MSBuild and wrap contained projects into targets

- by Filburt

I'd like to create a MSBuild project that reflects the project dependencies in a solution and wraps the VS projects inside reusable targets. The problem I like solve doing this is to svn-export, build and deploy a specific assembly (and its dependencies) in an BizTalk application. My question is: How can I make the targets for svn-exporting, building and deploying reusable and also reuse the wrapped projects when they are built for different dependencies? I know it would be simpler to just build the solution and deploy only the assemblies needed but I'd like to reuse the targets as much as possible. The parts The project I like to deploy <Project DefaultTargets="Deploy" xmlns="http://schemas.microsoft.com/developer/msbuild/2003"> <PropertyGroup> <ExportRoot Condition="'$(Export)'==''">Export</ExportRoot> </PropertyGroup> <Target Name="Clean_Export"> <RemoveDir Directories="$(ExportRoot)\My.Project.Dir" /> </Target> <Target Name="Export_MyProject"> <Exec Command="svn export svn://xxx/trunk/Biztalk2009/MyProject.btproj --force" WorkingDirectory="$(ExportRoot)" /> </Target> <Target Name="Build_MyProject" DependsOnTargets="Export_MyProject"> <MSBuild Projects="$(ExportRoot)\My.Project.Dir\MyProject.btproj" Targets="Build" Properties="Configuration=Release"></MSBuild> </Target> <Target Name="Deploy_MyProject" DependsOnTargets="Build_MyProject"> <Exec Command="BTSTask AddResource -ApplicationName:CORE -Source:MyProject.dll" /> </Target> </Project> The projects it depends upon look almost exactly like this (other .btproj and .csproj).

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How do I deploy my ASP MVC project to my Win7 system?

- by MedicineMan

Hi, I am deploying my first ASP MVC project. The project runs just fine, I would like to take the next step and run this outside of my visual studio environment on my local IIS. I am running Windows7, Visual Studio 2008, and I have created a basic ASP MVC project. On my solution, I find the project I would like to deploy. I right click and select Publish. I have backed up C:\inetpub\wwwroot\ and would like to deploy there. I accept all defaults, and click the "Publish" button. The Output Build window shows 1 project failed. Basically is says that it is unable to add any of the binaries to the site, copy files, create new directories... Access is denied. When I do click "Publish" at work, I don't get these errors. What do I have to do here to publish the website to make the website available to the rest of my home network? Also wwwroot appears to be readonly, but telling the folder to not be read only doesn't seem to help, it still appears to be readonly even after I've unselected this property in the property dialog.

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Extracting a .app from a zip file in Python, using ZipFile

- by Yakattak

I'm trying to extract new revisions of Chromium.app from their snapshots, and I can download the file fine, but when it comes to extracting it, ZipFile either extracts the chrome-mac folder within as a file, says that directories don't exist, etc. I am very new to python, so these errors make little sense to me. Here is what I have so far. import urllib2 response = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/LATEST') latestRev = response.read() print latestRev # we have the revision, now we need to download the zip and extract it latestZip = urllib2.urlopen('http://build.chromium.org/buildbot/snapshots/chromium-rel-mac/%i/chrome-mac.zip' % (int(latestRev)), '~/Desktop/ChromiumUpdate/%i-update' % (int(latestRev))) #declare some vars that hold paths n shit workingDir = '/Users/slehan/Desktop/ChromiumUpdate/' chromiumZipPath = '%s%i-update.zip' % (workingDir, (int(latestRev))) chromiumAppPath = 'chrome-mac/' #the path of the chromium executable within the zip file chromiumAppExtracted = '%s/Chromium.app' % (workingDir) # path of the extracted executable output = open(chromiumZipPath, 'w') #delete any current file there output.write(latestZip.read()) output.close() # we have the .zip now we need to extract the Chromium.app file, it's in ziproot/chrome-mac/Chromium.app import zipfile, os zippedFile = open(chromiumZipPath) zippedChromium = zipfile.ZipFile(zippedFile, 'r') zippedChromium.extract(chromiumAppPath, workingDir) #print zippedChromium.namelist() zippedChromium.close() #zippedChromium.close() Any ideas?

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Host Primary Domain from a subfolder

- by TandemAdam

I am having a problem making a sub directory act as the public_html for my main domain, and getting a solution that works with that domains sub directories too. My hosting allows me to host multiple sites, which are all working great. I have set up a subfolder under my ~/public_html/ directory called /domains/, where I create a folder for each separate website. e.g. public_html domains websiteone websitetwo websitethree ... This keeps my sites nice and tidy. The only issue was getting my "main domain" to fit into this system. It seems my main domain, is somehow tied to my account (or to Apache, or something), so I can't change the "document root" of this domain. I can define the document roots for any other domains ("Addon Domains") that I add in cPanel no problem. But the main domain is different. I was told to edit the .htaccess file, to redirect the main domain to a subdirectory. This seemed to work great, and my site works fine on it's home/index page. The problem I'm having is that if I try to navigate my browser to say the images folder (just for example) of my main site, like this: www.yourmaindomain.com/images/ then it seems to ignore the redirect and shows the entire server directory in the url, like this: www.yourmaindomain.com/domains/yourmaindomain/images/ It still actually shows the correct "Index of /images" page, and show the list of all my images. Here is an example of my .htaccess file that I am using: RewriteEngine on RewriteCond %{HTTP_HOST} ^(www.)?yourmaindomain.com$ RewriteCond %{REQUEST_URI} !^/domains/yourmaindomain/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /domains/yourmaindomain/$1 RewriteCond %{HTTP_HOST} ^(www.)?yourmaindomain.com$ RewriteRule ^(/)?$ domains/yourmaindomain/index.html [L] Does this htaccess file look correct? I just need to make it so my main domain behaves like an addon domain, and it's subdirectories adhere to the redirect rules.

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php (rar) i want to rar a folder using rar on Ubuntu (linux) by php (on dedi server) noob

- by Steve

hey guyz i want rar (not tar) my folder on my server by using php RAR RAR 3.93 Copyright (c) 1993-2010 Alexander Roshal 15 Mar 2010 Registered to my real name OS Ubuntu Release (Karmic) kernel linux 2.6.32.2-xxxx-grs-ipv4-32 Gnome 2.28.1 latest php an lighthttpd i have tried these things http://php.net/manual/en/function.escapeshellarg.php // may be wrong code http://php.net/manual/en/function.exec.php http://php.net/manual/en/function.shell-exec.php my command (working in ssh and nautilus script) rar a -m0 /where/file/will/saved/file_name.rar /location/ti/data/dir/datafolder php code $log=Shell_exec("rar a -m0 /where/file/will/saved/file_name.rar /location/ti/data/dir/datafolder"); echo $log; one method is left which i don't know how to use and its working on server that is by somefile_to_execute_command.sh i have to execute .sh file from php need to send some variables (command) and i tried this method can rar file with a script named RapidLeech but its rar from only its own files dir only :( but i want to do in different directories. Rapid Leech rar class http://paste2.org/p/791668 i m able run shell command with php (cp(copy),mv(move),ls(directory list),rm(remove aka delete)) but got failed to run rar i gives no output i also tried to given path rar and i used alot commands with php Shell_exec function and working like they work with ssh and i have tried almost 80 % method given on net and failed from last 3days i m over now plz help me i need php script file working plz reply if u have any info n code and experience about rar and this kinda :( problem i m 99% noob just used code mean search Google collect script make my own working thing (for personal use only) n now i m failed to rar folder and file :(( now plz provide me code plz don't talk in technical language because i m just reading my first php book (for dummies :D) mean noob and 0.1 plz help me as much u can thankx

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Minimal deployment of couchdb on windows

- by MartinStettner

Hi, I'd like to use couchdb for a client-only application on Windows (the document-oriented structure and the synchronization features would be perfect for me). There is a Windows installer package here, but the installer itself has about 45 MB, when installed it takes more than 100 MB on my HD. This is far to much for my (relatively small) application. I noticed that there are a lot of "src" directories in the couchdb/lib subdirs. I've been experimenting with removing some of them and it didn't seem to break the system. Now I'm wondering what would be the "minimal" set of files (preferably binary-only) that would be needed in order to run a local couchdb server. Are there already any efforts to create such a deployment-friendly installer? Or could anyone give some (even very general) hints how to create it? How much disk space would be minimally required for such an installation? Needless to say that I'm not at all familiar with neither the couchdb internals nor the Erlang system :). But perhaps I could figure out if I got some direction (or I could stop trying if someone told me that this would be impossible or didn't make sense at all ...) Thanks anyway!

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How to maintain base files for development environment central while allowing people to change their

- by Ittai

Hi, what I'd like to do is have files in a central location so that when I add people to my development team they can see the base version of these files but meanwhile have the ability for the rest of the team to work with their own local version. I know I can just put the files in source-control (we use Tortoiese-SVN) and have my team change the local versions but I'd rather not as the exclamation mark signaling the file has been changed and needs to be committed, quite frankly, irritates me greatly. I'll give two examples of what I mean: We use quite a few build.xml files which relate to a single properties files which contains many definitions. Some of them can be different between team-members (mainly temporary working directories) and I'd like a new team-member to have the ability to get the properties file with the base config but change it if they wish. Have the eclipse settings file in the SVN so that when a new team-member joins they can just retrieve the files from the server and have a base system running. If they wish they will be able to change some of these settings. Thanks, Ittai

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SVN checkout or export for production environment?

- by Eran Galperin

In a project I am working on, we have an ongoing discussion amongst the dev team - should the production environment be deployed as a checkout from the SVN repository or as an export? The development environment is obviously a checkout, since it is constantly updated. For the production, I'm personally for checking out the main trunk, since it makes future updates easier (just run svn update). However some of the devs are against it, as svn creates files with the group/owner and permissions of the svn process (this is on a linux OS, so those things matter), and also having the .svn directories on the production seem to them to be somewhat dirty. Also, if it is a checkout - how do you push individual features to the production without including in-development code? do you use tags or branch out for each feature? any alternatives? EDIT: I might not have been clear - one of the requirement is to be able to constantly be able to push fixes to the production environment. We want to avoid a complete build (which takes much longer than a simple update) just for pushing critical fixes.

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Using SVN post-commit hook to update only files that have been commited

- by fondie

I am using an SVN repository for my web development work. I have a development site set up which holds a checkout of the repository. I have set up an SVN post-commit hook so that whenever a commit is made to the repository the development site is updated: cd /home/www/dev_ssl /usr/bin/svn up This works fine but due to the size of the repository the updates take a long time (approx. 3 minutes) which is rather frustrating when making regular commits. What I'd like is to change the post-commit hook to only update those files/directories that have been committed but I don't know how to go about doing this. Updating the "lowest common directory" would probably be the best solution, e.g. If committing the follow files: /branches/feature_x/images/logo.jpg /branches/feature_x/css/screen.css It would update the directory: /branches/feature_x/ Can anyone help me create a solution that achieves this please? Thanks! Update: The repository and development site are located on the same server so network issues shouldn't be involved. CPU usage is very low, and I/O should be ok (it's running on hi-spec dedicated server) The development site is approx. 7.5GB in size and contains approx. 600,000 items, this is mainly due to having multiple branches/tags

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Avoiding Multiple Dialog Calls with htaccess

- by Jeffrey J Weimer

OK, I'm new to this, so pardon if the question is already a FAQ. Searching multiple places still leaves me dumbfounded. I have a Web site generated with iWeb09/Mac hosting on an ISP. To secure certain pages, I am trying to set up .htaccess + .htpasswd files. The basic directory structure is ... Main index.html Images.html Images (some css, js stuff) Media Image01 Image01.jpeg ... Image02 Image02.jpeg ... I want to password protect access to the Images directory and all the files therein. The index.html file has a link to the Images.html file that contains the layout for the files in the Images directory. I have put a basic .htaccess file at the Main level that restricts access via ... <Files "Images.html"> AuthType Basic AuthName "Images" AuthUserFile /Main/.htpasswd AuthGroupFile /dev/null Require valid-user </Files> I have then created a valid .htpasswd file. All works at the start, however after the first call to set up the Images.html page, the secure login prompt is displayed multiple times, presumably once for every sub-sub-directory Images/Media/ImageXX (with multiple sub-directories, I just give up after two or three times). I have also tried placing the .htaccess file inside the Images directory with the same problem. Recommendations I have seen suggest a better convention is needed in the basic .htaccess file itself. Alternatively, perhaps a companion .htaccess is needed in the Images directory. So, how do I fix this problem? -- JJW

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PHP: Best solution for links breaking in a mod_rewrite app

- by psil

I'm using mod rewrite to redirect all requests targeting non-existent files/directories to index.php?url=* This is surely the most common thing you do with mod_rewrite yet I have a problem: Naturally, if the page url is "mydomain.com/blog/view/1", the browser will look for images, stylesheets and relative links in the "virtual" directory "mydomain.com/blog/view/". Problem 1: Is using the base tag the best solution? I see that none of the PHP frameworks out there use the base tag, though. I'm currently having a regex replace all the relative links to point to the right path before output. Is that "okay"? Problem 2: It is possible that the server doesn't support mod_rewrite. However, all public files like images, stylesheets and the requests collector index.php are located in the directory /myapp/public. Normally mod_rewrite points all request to /public so it seems as if public was actually the root directory too all users. However if there is no mod_rewrite, I then have to point the users to /public from the root directory with a header() call. That means, however that all links are broken again because suddenly all images, etc. have to be called via /public/myimage.jpg Additional info: When there is no mod_rewrite the above request would look like this: mydomain.com/public/index.php/blog/view/1 What would be the best solutions for both problems?

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How do I use IIS6 style metabase paths in IIS7 AppCmd tool?

- by Mike Atlas

I'm currently in the process of upgrading old II6 automation scripts that use the IISVdir tool to create/modify/update apps and virtual directories, and replacing them with AppCmd for IIS7. The IIS6, "IISVDir" commands reference paths in that are from the metabase, eg, "/W3SVC/1/ROOT/MyApp" - where 1 is ID of the "Default Web Site" site. The command doesn't actually require the display name of the site to make changes to it. This works well, since on a different language OS, the "Default Web Site" site name could be named, for example, "??? Web ???" or anything else for that matter. But this flexibility is lost if AppCmd can only reference "Default Web Site" via its name, and not a language-neutral identifier. So, how can I script AppCmd to refer to sites, vdirs and apps using language neutral identifiers to reference the "Default App Site"? Perhaps I need to start creating my own site instead, from the start, and name it something else specific, and stop using "Default Web Site" as the root? (Disclosure: I only have a IIS7-English machine that I am working on currently, but I have both IIS6-English and IIS6-Japanese machines for testing my old scripts - so perhaps it really is just "Default Web Site" still on Win2k8-Japanese?)

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python packaging causes importerror

- by Absolute0

I am getting an annoying import error when I try to import a variable in an init.py file. I have attached the files involved and my directory structure: #/home/me/app/app/__init__.py from flaskext.sqlalchemy import SQLAlchemy db = SQLAlchemy(app) #/home/me/app/app/models/__init__.py from datetime import datetime from app import db #shell [me@archlinux app]$ pwd /home/me/app [me@archlinux app]$ ./manage.py /home/me/app/app/__init__.pyc Traceback (most recent call last): File "./manage.py", line 7, in <module> from app import app File "/home/me/app/app/__init__.py", line 3, in <module> from app.views.post import post File "/home/me/app/app/views/post.py", line 4, in <module> from app.models import Post File "/home/me/app/app/models/__init__.py", line 5, in <module> from app import db ImportError: cannot import name db [me@archlinux app]$ tree . +-- apikey.txt +-- manage.py +-- app ¦ +-- forms ¦ ¦ +-- __init__.py ¦ ¦ +-- __init__.py~ ¦ +-- __init__.py ¦ +-- __init__.py~ ¦ +-- __init__.pyc ¦ +-- models ¦ ¦ +-- __init__.py ¦ ¦ +-- __init__.py~ ¦ ¦ +-- __init__.pyc ¦ +-- static ¦ ¦ +-- css ¦ ¦ ¦ +-- style.css ¦ ¦ +-- images ¦ ¦ ¦ +-- favicon.png ¦ ¦ ¦ +-- logo.png ¦ ¦ ¦ +-- text_logo.png ¦ ¦ ¦ +-- thumb_down_active.png ¦ ¦ ¦ +-- thumb_down_inactive.png ¦ ¦ ¦ +-- thumb_up_active.png ¦ ¦ ¦ +-- thumb_up_inactive.png ¦ ¦ +-- js ¦ ¦ ¦ +-- index.js ¦ ¦ +-- sitemap.xml ¦ +-- templates ¦ ¦ +-- 404.html ¦ ¦ +-- 500.html ¦ ¦ +-- about.html ¦ ¦ +-- base.html ¦ ¦ +-- feedback ¦ ¦ ¦ +-- feedback_form.html ¦ ¦ +-- form.html ¦ ¦ +-- posts ¦ ¦ ¦ +-- comment.html ¦ ¦ ¦ +-- post.html ¦ ¦ ¦ +-- posts.html ¦ ¦ +-- spam.html ¦ ¦ +-- terms.html ¦ ¦ +-- users ¦ ¦ +-- login_form.html ¦ ¦ +-- sign_up_form.html ¦ +-- util ¦ ¦ +-- forms.py ¦ ¦ +-- honeypot.py ¦ ¦ +-- __init__.py ¦ ¦ +-- __init__.py~ ¦ ¦ +-- json_http.py ¦ ¦ +-- models.py ¦ ¦ +-- spam.py ¦ +-- views ¦ +-- feedback.py ¦ +-- __init__.py ¦ +-- __init__.pyc ¦ +-- post.py ¦ +-- post.pyc ¦ +-- user.py +-- settings.py +-- settings.pyc +-- TiddlyWiki.html 13 directories, 49 files What might be the problem?

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Compose path (with boost::filesystem)

- by ypnos

I have a file that describes input data, which is split into several other files. In my descriptor file, I first give the path A that tells where all the other files are found. The originator may set either a relative (to location of the descriptor file) or absolute path. When my program is called, the user gives the name of the descriptor file. It may not be in the current working directory, so the filename B given may also contain directories. For my program to always find the input files at the right places, I need to combine this information. If the path A given is absolute, I need to just that one. If it is relative, I need to concatenate it to the path B (i.e. directory portion of the filename). I thought boost::filesystem::complete may do the job for me. Unfortunately, it seems it is not. I also did not understand how to test wether a path given is absolute or not. Any ideas?

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Use .bat file to recursively loop through folders and get hold of .class files

- by user320550

HI all, This is what i'm trying to do. I have a .bat file which takes in a argument which is nothing but a folder name. What i do first is go one level up (cd ..). Now in this directory i have 3 folders and each folders have sub-folders and have .class files in them. What i want to do is recursively loop through the folders and get hold of the .class files. Once this is done i want to echo the target folder of the .class file as well as echo the name of the.class file. So c:\temp\potter\myclass.class. I would echo out c:\temp\potter\ and myclass. I'm able to do this by writing a separate bat file which works. But when i integrate this with the recursive function it seems to break. This is what i'm doing: :: call the junit classes... and save the results echo step 3... cd %1 cd .. for /r %%a in (*.class) do set Var=%%a echo Full file location %Var% for %%i in ("%Var%") do Set CF=%%~dpi Set CF=%CF:~0,-1% :LOOP If "%CF:~-1,1%"=="\" GoTo :DONE Set CF=%CF:~0,-1% GoTo :LOOP :DONE Set CF=%CF:~0,-1% echo Folder Location %CF% ::cd %CF% For %%j in ("%Var%") Do Set name=%%~nxj :: -6 because of Quotations Set name=%name:~0,-6% echo File Name %name% echo step 3 complete... However i only get the output of one directory, while i have multiple directories having .class files. This is the output i get: step 3... Full file location C:\NKCV\Project\MyActivities\6_Selenium\htmlTestCasesConve rted2JUnit\iexplore\flow2\testCase_app2.class Folder Location C:\NKCV\Project\MyActivities\6_Selenium\htmlTestCasesConverte d2JUnit\iexplore\flow2 File Name testCase_app2 step 3 complete... missing argument! usage htmltestCaseLocation for eg., "C:\NKCV\Project\MyActivities\6_Selenium\htmlTestCases" Could anyone please let me know whats wrong here? Thanks.

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How do I create a new project in TFS from an existing project (breaking history)?

- by Lindsay

My team is taking over a project from a previous team. We use a different TFS server than the original team, and we are also not interested in keeping the history of the project because we are accepting the latest version of the code as the beginning of our history with the project. Branching is not an option since we want to start our history from the current version of the code. We just want a fresh project with the existing code. I have not been able to create the new project from the old code successfully. I keep getting an error: "Source control cannot add the solution: Solution would span multiple workspaces" My process for attempting the new project creation: Create a workspace for the previous team's version of the code. Get latest version of that code into local mapped workspace directory Open the solution. Unbind all projects and solution. Close solution. Create a workspace for the new version of the code on our TFS server. Copy the unbound code on my local box to the new local workspace mapped folder. Open the solution from the new directory. "Add to source control" from the new solution. Then I get the error. I have tried removing the TFS security files out of the code directories in the unbound version and tried changing source control instead of adding to source control (but it just binds back to the original instead of letting me bind to the new). Is there any other way to do this besides recreating the solution/projects and adding back all the files and references? It doesn't seem like it should be this difficult... Any advice much appreciated!

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need advice on Zend framework Application architecture, or say approach dealing with modules

- by simple

Let me start with the things that I did and how am I using some things to get results I have set up modular structure as: application/ /configs /layouts /models /modules /users /profile /frontend /backend /controllers /views .... I write a plugin that does addes changes with FrontController-setModuleControllerDirectoryName() FrontController-addModuleDirectory() and It is all good I have a changed all the directories according weather admin page is requested in the url or not (it is some thing like /admin/some/some) Let's say I have a single layout for anything that is related to Profile viewing , in this case the "Profile" module. The Profile layout is divided into three parts In the layout I was pulling out the Profile/PhotoController 's index action with a action() $this->action('index', 'photo', 'profile'); Then I have faced few issues 1. Can get passed Params inside the Photo Controller when calling ( profile/profile/index); 2. found out that helper Action() is evil cause it starts another dispatching loop =) --- and now I am thinking that my approach on plugging in controllers modules into layout also evil =). anyhow how Should I deal with plugging in some controllers (another module controllers) into the layout ?

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php when to use get method?

- by user329394

how all, when is the right time to use $_GET['data']? i want to pass value of userid from page A to page B by using popup javascript. $qry="SELECT * FROM dbase WHERE id='".$id."'"; $sql=mysql_query($qry); $rs=mysql_fetch_array($sql); <script language="JavaScript"> function myPopup() { window.open( "<?=$CFG->wwwroot.'/ptk/main.php?task=ptk_checkapp&id='.$rs['userid'];?>" ,"myWindow", "status = 1, height = 500, width = 500, scrollbars=yes,toolbar=no,directories=no,location=no,menubar=no, resizable='yes';" ) } </script> calling by hyperlink: <a href="#" onclick="myPopup()"> <?=ucwords(strtolower($rs->nama));?> </a> It seems that , the $rs['user'] dont hold any value on it. can tell me what problem or may be solution? thank you very much.

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problem with running Servlet on Tomcat: InvocationTargetException

- by Fahim

Hi, I am new to Tomcat, and trying to run a simple HelloWorld servlet. I have installed Tomcat 6, and Jdk1.6 on Mandriva Linux, set CLASSPATH and JAVA_HOME. I have the following files and directories: $CATALINA_HOME/webapps/MyApp/WEB_INF/classes/TestServlet.class $CATALINA_HOME/webapps/MyApp/WEB_INF/web.xml My web.xml file contains the following: http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5" <description>ZibJana Localization</description> <display-name>ZibJana Localization</display-name>  <servlet> <servlet-name>ZibJana</servlet-name> <servlet-class>TestServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ZibJana</servlet-name> <url-pattern>*</url-pattern> </servlet-mapping> But when I try to invoke my servlet with url http://localhost:8080/MyApp, tomcat fails to launch launch the servlet. I checked in the $CATALINA_HOME/logs/catalina.out log-file and found the following error, which occurs every time I start tomcat service. INFO: Deploying web application directory MyApp 16-Mar-2010 12:05:38 AM org.apache.tomcat.util.digester.Digester endElement SEVERE: End event threw exception java.lang.reflect.InvocationTargetException at sun.reflect.GeneratedMethodAccessor18.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) Please let me know where my mistake is. Thanks in advance.

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How do I set the Eclipse build path and class path from an Ant build file?

- by Nels Beckman

Hey folks, There's a lot of discussion about Ant and Eclipse, but no previously answered seems to help me. Here's the deal: I am trying to build a Java program that compiles successfully with Ant from the command-line. (To confuse matters further, the program I am attempting to compile is Ant itself.) What I really want to do is to bring this project into Eclipse and have it compile in Eclipse such that the type bindings and variable bindings (nomenclature from Eclipse JDT) are correctly resolved. I need this because I need to run a static analysis on the code that is built on top of Eclipse JDT. The normal way I bring a Java project into Eclipse so that Eclipse will build it and resolve all the bindings is to just import the source directories into a Java project, and then tell it to use the src/main/ directory as a "source directory." Unfortunately, doing that with Ant causes the build to fail with numerous compile errors. It seems to me that the Ant build file is setting up the class path and build path correctly (possibly by excluding certain source files) and Eclipse does not have this information. Is there any way to take the class path & build path information embedded in an Ant build file, and given that information to Eclipse to put in its .project and .classpath files? I've tried, creating a new project from an existing build file (an option in the File menu) but this does not help. The project still has the same compile errors. Thanks, Nels

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gcc compilation without using system defined header locations

- by bogertron

I am attempting to compile a c++ class using gcc. Due to the nature of the build, I need to invoke gcc from a non-standard location and include non-system defined headers, only to add a set from a different location. However, when I do this, I run into an issue where I cannot find some base symbols (suprise suprise). So i am basically running this command to compile my code: -->(PARENT_DIR)/usr/bin/gcc # invoke compiler -B$(PARENT_DIR)/usr/lib64/gcc/suselinux-x8664 -B$(PARENT_DIR)/usr/lib64 #C/C++ flags -fPIC -fvisibility=default -g -c -Wall -m64 -nostdinc # source files -I$(SRC_DIR_ONE)/ -I$(SRC_DIR_TWO) -I../include # 'Mock' include the system header files -I$(PARENT_DIR)/usr/include/c++/$(GCC_VERSION) -I$(PARENT_DIR)/usr/include/c++/$(GCC_VERSION)/backward -I$(PARENT_DIR)/usr/include/c++/$(GCC_VERSION)/x86_64-suse-linux -I$(PARENT_DIR)/usr/lib64/x86_64-suse-linux/$(GCC_VERSION)/include -I$(PARENT_DIR)/usr/lib64/gcc/x86_64-suse-linux/$(GCC_VERSION)/include -I$(PARENT_DIR)/usr/lib64/gcc/x86_64-suse-linux/$(GCC_VERSION)/include-fixed -I$(PARENT_DIR)/usr/src/linux/include -I$(PARENT_DIR)/usr/x86_64-suse-linux/include -I$(PARENT_DIR)/usr/include/suselinux-x8664 -I$(PARENT_DIR)/usr/suselinux-x8664/include -I$(PARENT_DIR)/usr/include -I$(PARENT_DIR)/usr/include/linux file.cpp I am getting several errors which indicate that the base headers are not being included: such as: $(PARENT_DIR)/usr/include/c++/$(GCC_VERSION)/cstddef ::prtdiff_t has not been declared $(PARENT_DIR)/usr/include/c++/$(GCC_VERSION)/cstddef ::size_t has not bee declared. Is there something that I am doing wrong when I include the header file directories? Or am I looking in the wrong place?

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IIS Restrict Access to Directory for table of users

- by Dave

I am trying to restrict access to files in a directory and it's sub directories based user rights. My user rights are stored in an MS SQL database in a custom format, however it is easy to query the list of users with rights to this directory. I need to know how to apply this to a web config on the server to authenticate against a query of a database table to determine if the username is authenticated and allowed to view the file. Of course if they are not they should be blocked / given a 404. I am using IIS and ASP.Net MVC3 with a form based security as opposed to the built in roles and responsibilities that was custom made for us and that works great. There are over 10k users tied to this non-Active Directory authentication so I am not planning to change my authentication type so please don't go there. It is not my decision on the choice of platform, or I would have gone with a LAMP server and been done with this. Edit 11-13-2012 @ 8:57a: In the web config can you put the result of an SQL query?

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Component based web project directory layout with git and symlinks

- by karlthorwald

I am planning my directory structure for a linux/apache/php web project like this: Only www.example.com/webroot/ will be exposed in apache www.example.com/ webroot/ index.php comp1/ comp2/ component/ comp1/ comp1.class.php comp1.js comp2/ comp2.class.php comp2.css lib/ lib1/ lib1.class.php the component/ and lib/ directory will only be in the php path. To make the css and js files visible in the webroot directory I am planning to use symlinks. webroot/ index.php comp1/ comp1.js (symlinked) comp2/ comp2.css (symlinked) I tried following these principles: layout by components and libraries, not by file type and not by "public' or 'non public', index.php is an exception. This is for easier development. symlinking files that need to be public for the components and libs to a public location, but still mirroring the layout. So the component and library structure is also visible in the resulting html code in the links, which might help development. git usage should be safe and always work. it would be ok to follow some procedure to add a symlink to git, but after that checking them out or changing branches should be handled safely and clean How will git handle the symlinking of the single files correctly, is there something to consider? When it comes to images I will need to link directories, how to handle that with git? component/ comp3/ comp3.class.php img/ img1.jpg img2.jpg img3.jpg They should be linked here: webroot/ comp3/ img/ (symlinked ?) If using symlinks for that has disadvantages maybe I could move images to the webroot/ tree directly, which would break the first principle for the third (git practicability). So this is a git and symlink question. But I would be interested to hear comments about the php layout, maybe you want to use the comment function for this.

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How can I diff against a revision of a single file using only the default Git GUI tools?

- by Rich

I want to view the history of a single file, and then compare a single revision from that history against the current version. On the command line, this is easy: Run: git log -- <filename> Locate the version you want to compare, Run: git diff <commitid> -- <filename> But how can this be done using only the default Git gui tools, git gui and gitk? I know of two methods using gitk, but they're both horribly clunky: Either: Select the New View option from the View menu, Type in the full path to your file into the box labelled Enter files and directories to include, one per line, Locate the version you want to compare by looking at the highlighted items in the top pane, and click on it to select it, Right-click on the current version and select Diff selected - this, Or: Select Tree in the bottom right-hand pane, Locate the file you want to look at, right-click on it, and select Highlight this only, Locate the version you want to compare by looking at the highlighted items in the top pane, and click on it to select it, Right-click on the current version and select Diff selected - this, Click on the file in the bottom right-hand pane to jump to it in the diff output, or scroll manually. Is a better method than this?

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