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  • Problems With Eclipse and Ruby Plugin

    - by Jesse J
    I installed Eclipse and then the Ruby Development Tools (RDT), but it would crash when I try to alter certain features, like having line numbers, how far back to have history, and the code coloring scheme didn't work fully. I decided to try to uninstall Eclipse by doing sudo aptitude remove eclipse and then sudo aptitude install eclipse but instead it installed it back with the broken Ruby plugin. I also tried aptitude purge but that didn't help either. How can I freshly reinstall eclipse and get a properly working Ruby plugin?

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  • excel sum if string

    - by user1834348
    I have table similar to this: 102938 bob 038128 Marc 398401 Tom 298421 Jim 102938 Alex 102938 Junior 209381 Rex 398401 Oby I want to make sometthing like =sumif(A:A, 102938,B:B) and to get "bobAlexJunior" as result. But this is not working becouse sum works with numbers not strings. If i go with lookup, it works with strings but finds only first line, not all lines. Do you have an Idea on how to fix this issue? Thanx

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  • How to update a collection based on another collection in MongoDB?

    - by Sean Zhu
    Now I get two collections: coll01 and coll02. And the structure of coll01 is like this: { id: 01, name: "xxx", age: 30 } and the structure of coll02 is like: { id: 01, name: "XYZ" gender: "male" } The two id fields in the both collection are indices. And the numbers of documents in these two collections are same. And what I want to do in traditional SQL is : update coll01, coll02 set coll01.name = coll02.name where coll01.id = coll02.id

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  • Find a base case for a recursive void method

    - by Evan S
    I am doing homework. I would like to build a base case for a recursion where ordering given numbers (list2) in ascending order. Purpose of writing this codes is that when all numbers are in ascending order then should stop calling a method called ascending(list2, list1); and all values in list2 should be shipped to list1. For instance, list2 = 6,5,4,3,2,1 then list2 becomes empty and list1 should be 1,2,3,4,5,6. I am trying to compare result with previous one and if matches then stop. But I can't find the base case to stop it. In addition, Both ascending() and fixedPoint() are void method. Anybody has idea? lol Took me 3 days... When I run my code then 6,5,4,3,2,1 5,6,4,3,2,1 4,5,6,3,2,1 3,4,5,6,2,1 2,3,4,5,6,1 1,2,3,4,5,6 1,2,3,4,5,6 1,2,3,4,5,6 1,2,3,4,5,6 1,2,3,4,5,6 infinite............. public class Flipper { public static void main(String[] args) { Flipper aFlipper = new Flipper(); List<Integer> content = Arrays.asList(6,5,4,3,2,1); ArrayList<Integer> l1 = new ArrayList<Integer>(content); ArrayList<Integer> l2 = new ArrayList<Integer>(); // empty list aFlipper.fixedPoint(l2,l1); System.out.println("fix l1 is "+l1); System.out.println("fix l2 is "+l2); } public void fixedPoint(ArrayList<Integer> list1, ArrayList<Integer> list2) { // data is in list2 ArrayList<Integer> temp1 = new ArrayList<Integer>(); // empty list if (temp1.equals(list2)) { System.out.println("found!!!"); } else { ascending(list2, list1); // data, null temp1 = list1; // store processed value System.out.println("st list1 is "+list1); System.out.println("st list2 is "+list2); } fixedPoint(list2, list1); // null, processed data }

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  • Split a PDF by Bookmarks?

    - by Jason
    Going to be getting a single PDF that has been created by 'merging' multiple pdf's. When I view the merged PDF each single PDF is displayed as a bookmark. Is there any way to automatically split this up by bookmarks with a script? We would not know the page numbers, so that's not an option.

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  • Simpler range finder?

    - by dotty
    Hay guys I've programmed a very simple range finder. The user can only select numbers 1 - 180 (axis) if the number is 90 or below i have to add 90 on to it if the number is 91 - 180 i have to take off 90 from it. Here's what i have $min_range = range(1,90); $max_range = range(91,180); if(in_array($axis, $min_range)){ $c = $axis + 90; }elseif(in_array($axis, $max_range)){ $c = $axis - 90; } Has anyone got a better solution

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  • Grails - How to format a value in a textfield into comma style such that it can be easily read?

    - by WaZ
    Hi there, I want to allow users enter numbers in textfield and once the textbox loses focus. The number is formatted with commas. e.g. User enters 100000 textfield looses focus value displayed: 100,000 How can I achieve this in Grails. I have looked at <g:formatNumber number="${myNumber}" format="\\$###,##0" /> But it doesnt solve my problem as the number is from a textfield. thanks Much appreciated.

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  • How to display Currency in Indian Numbering Format in PHP

    - by Somnath Muluk
    I have a question about formatting the Rupee currency (Indian Rupee - INR). For example, numbers here are represented as: 1 10 100 1,000 10,000 1,00,000 10,00,000 1,00,00,000 10,00,00,000 Refer Indian Numbering System I have to do with it PHP. I have saw this question Displaying Currency in Indian Numbering Format. But couldn't able to get it for PHP my problem. Update: How to use money_format() in indian currency format?

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  • mySQL search for a number in VARCHAR field

    - by sea_1987
    Hi There, I have a field in my database that contain comma seperated values these values are numbers, and I am trying to do a search and count the number of times that a number appears in that column throughout the column, $sql = "SELECT sector_id_csv, COUNT(sector_id_csv) as count FROM cv WHERE sector_id_csv LIKE '$sectorId'"; This seems slow and does not return any results, and I know the sector_id it is search exsists in the table.

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  • Procedure/ Oracle

    - by DAVID
    How do you write a procedure which shows that one field's value cannot be higher than another field value, in terms of numbers... ive never done one before say. employee salary field cant be higher than his manager salary

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  • Error in Print Function in Bubble Sort MIPS?

    - by m00nbeam360
    Sorry that this is such a long block of code, but do you see any obvious syntax errors in this? I feel like the problem is that the code isn't printing correctly since the sort and swap methods were from my textbook. Please help if you can! .data save: .word 1,2,4,2,5,6 size: .word 6 .text swap: sll $t1, $a1, 2 #shift bits by 2 add $t1, $a1, $t1 #set $t1 address to v[k] lw $t0, 0($t1) #load v[k] into t1 lw $t2, 4($t1) #load v[k+1] into t1 sw $t2, 0($t1) #swap addresses sw $t0, 4($t1) #swap addresses jr $ra #return sort: addi $sp, $sp, -20 #make enough room on the stack for five registers sw $ra, 16($sp) #save the return address on the stack sw $s3, 12($sp) #save $s3 on the stack sw $s2, 8($sp) #save Ss2 on the stack sw $s1, 4($sp) #save $s1 on the stack sw $s0, 0($sp) #save $s0 on the stack move $s2, $a0 #copy the parameter $a0 into $s2 (save $a0) move $s3, $a1 #copy the parameter $a1 into $s3 (save $a1) move $s0, $zero #start of for loop, i = 0 for1tst: slt $t0, $s0, $s3 #$t0 = 0 if $s0 S $s3 (i S n) beq $t0, $zero, exit1 #go to exit1 if $s0 S $s3 (i S n) addi $s1, $s0, -1 #j - i - 1 for2tst: slti $t0, $s1, 0 #$t0 = 1 if $s1 < 0 (j < 0) bne $t0, $zero, exit2 #$t0 = 1 if $s1 < 0 (j < 0) sll $t1, $s1, 2 #$t1 = j * 4 (shift by 2 bits) add $t2, $s2, $t1 #$t2 = v + (j*4) lw $t3, 0($t2) #$t3 = v[j] lw $t4, 4($t2) #$t4 = v[j+1] slt $t0, $t4, $t3 #$t0 = 0 if $t4 S $t3 beq $t0, $zero, exit2 #go to exit2 if $t4 S $t3 move $a0, $s2 #1st parameter of swap is v(old $a0) move $a1, $s1 #2nd parameter of swap is j jal swap #swap addi $s1, $s1, -1 j for2tst #jump to test of inner loop j print exit2: addi $s0, $s0, 1 #i = i + 1 j for1tst #jump to test of outer loop exit1: lw $s0, 0($sp) #restore $s0 from stack lw $s1, 4($sp) #resture $s1 from stack lw $s2, 8($sp) #restore $s2 from stack lw $s3, 12($sp) #restore $s3 from stack lw $ra, 16($sp) #restore $ra from stack addi $sp, $sp, 20 #restore stack pointer jr $ra #return to calling routine .data space:.asciiz " " # space to insert between numbers head: .asciiz "The sorted numbers are:\n" .text print:add $t0, $zero, $a0 # starting address of array add $t1, $zero, $a1 # initialize loop counter to array size la $a0, head # load address of print heading li $v0, 4 # specify Print String service syscall # print heading out: lw $a0, 0($t0) # load fibonacci number for syscall li $v0, 1 # specify Print Integer service syscall # print fibonacci number la $a0, space # load address of spacer for syscall li $v0, 4 # specify Print String service syscall # output string addi $t0, $t0, 4 # increment address addi $t1, $t1, -1 # decrement loop counter bgtz $t1, out # repeat if not finished jr $ra # return

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  • Matlab - applying low-pass filter to a vector?

    - by waitinforatrain
    If I have a simple low-pass filter, e.g. filt = fir1(20, 0.2); and a matrix with a list of numbers (a signal), e.g. [0.1, -0.2, 0.3, -0.4] etc, how do I actually apply the filter I've created to this signal? Seems like a simple question but I've been stuck for hours. Do I need to manually calculate it from the filter coefficients?

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  • Split an array, not working

    - by Kyle Hudson
    Hi OK I need to figure out how to count how many numbers are in the following example. 07000000000,07000000001,07000000002,07000000003,07000000004 etc... I have tried the following PHP functions. explode, implode, count, foreach and for. None of them seemed to have worked and I am really stuck now. Any help will is appriciated. Kyle

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  • PHP - How to remove the first number in a string?

    - by Dodi300
    Hello. How can I remove the first number in a string? Say if I had these 48 numbers seperated with a ',' (comma): 8,5,8,10,15,20,27,25,60,31,25,39,25,31,26,28,80,28,27,31,27,29,26,35,8,5,8,10,15,20,27,25,60,31,25,39,25,31,26,28,80,28,27,31,27,29,26,35 How would I remove the "8," from the string? Thanks.

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  • Question on First Order Logic formula

    - by none
    Hi, Can someone validate the following. I am supposed to 'write a formula asserting that for every number there's a unique next number...true for integers for instance' L(x,y) means x is smaller than y the intended Domain is the Integer numbers Can I give ∀x ∀y [ x<y ⇒ ( ∃z : z<x ∨ y<z ) ] Thanks

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  • Explained shell statement

    - by Mats Stijlaart
    The following statement will remove line numbers in a txt file: cat withLineNumbers.txt | sed 's/^.......//' >> withoutLineNumbers.txt The input file is created with the following statement (this one i understand): nl -ba input.txt >> withLineNumbers.txt I know the functionality of cat and i know the output is written to the 'withoutLineNumbers.txt' file. But the part of '| sed 's/^.......//'' is not really clear to me. Thanks for your time.

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  • Are there known problems with >= and <= and the eval function in JS?

    - by Augier
    I am currently writing a JS rules engine which at one point needs to evaluate boolean expressions using the eval() function. Firstly I construct an equation as such: var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "relation.value"; relation.relatedTrigger.previousValue is the value I want to compare. relation.operator is the operator (either "==", "!=", <=, "<", "", ="). relation.value is the value I want to compare with. I then simply pass this string to the eval function and it returns true or false as such: return eval(equation); This works absolutely fine (with words and numbers) or all of the operators except for = and <=. E.g. When evaluating the equation: relation.relatedTrigger.previousValue <= 100 It returns true when previousValue = 0,1,10,100 & all negative numbers but false for everything in between. I would greatly appreciate the help of anyone to either answer my question or to help me find an alternative solution. Regards, Augier. P.S. I don't need a speech on the insecurities of the eval() function. Any value given to relation.relatedTrigger.previousValue is predefined. edit: Here is the full function: function evaluateRelation(relation) { console.log("Evaluating relation") var currentValue; //if multiple values if(relation.value.indexOf(";") != -1) { var values = relation.value.split(";"); for (x in values) { var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "values[x]"; currentValue = eval(equation); if (currentValue) return true; } return false; } //if single value else { //Evaluate the relation and get boolean var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "relation.value"; console.log("relation.relatedTrigger.previousValue " + relation.relatedTrigger.previousValue); console.log(equation); return eval(equation); } } Answer: Provided by KennyTM below. A string comparison doesn't work. Converting to a numerical was needed.

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  • Emulating Button Press Using Kinect/SimpleOpenNI + Processing Depth

    - by Alex Lu
    I am using Kinect with Simple OpenNI and Processing, and I was trying to use the Z position of a hand to emulate a button press. So far when I try it using one hand it works really well, however, when I try to get it to work with a second hand, only one of the hands work. (I know it can be more efficient by moving everything except the fill out of the if statements, but I kept those in there just in case I want to change the sizes or something.) irz and ilz are the initial Z positions of the hands when they are first recognized by onCreateHands and rz and lz are the current Z positions. As of now, the code works fine with one hand, but the other hand will either stay pressed or unpressed. If i comment one of the sections out, it works fine as well. if (rz - irz > 0) { pushStyle(); fill(60); ellipse(rx, ry, 10, 10); popStyle(); rpressed = true; } else { pushStyle(); noFill(); ellipse(rx, ry, 10, 10); popStyle(); rpressed = false; } if (lz - ilz > 0) { pushStyle(); fill(60); ellipse(lx, ly, 10, 10); popStyle(); lpressed = true; } else { pushStyle(); noFill(); ellipse(lx, ly, 10, 10); popStyle(); lpressed = false; } I tried outputting the values of rz - irz and lz - ilz and the numbers range from small negative values to small positive values (around -8 to 8) for lz - ilz. But rz - irz outputs numbers from around 8-30 depending on each time I run it and is never consistent. Also, when I comment out the code for the lz-ilz, the values for rz-irz look just fine and it operates as intended. Is there a reason tracking both Z positions throws off one hand? And is there a way to get it to work? Thanks!

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