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  • cannot modify header information [closed]

    - by mohanraj
    Possible Duplicate: cannot modify header information Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\register&login\logout.php:1) in C:\xampp\htdocs\register&login\logout.php on line 4 Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\register&login\logout.php:1) in C:\xampp\htdocs\register&login\logout.php on line 5 Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\register&login\logout.php:1) in C:\xampp\htdocs\register&login\logout.php on line 6

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  • Symfony form values missing

    - by Cav
    Hi, I was writing a simple login form, everything works fine (validation etc.) but I can't get the values, there's my code: public function executeIndex(sfWebRequest $request) { $this->getUser()->clearCredentials(); $this->getUser()->setAuthenticated(false); $this->form = new LoginForm(); if ($request->isMethod('post') && $request->hasParameter('login')) { $this->form->bind($request->getParameter('login')); if ($this->form->isValid()) { $this->getUser()->setAuthenticated(true); $this->getUser()->addCredential('user'); $this->login = $this->form->getValue('login'); } } } $this-login is NULL. Now I checked almost everything, the form is valid, isBound() is true, count() returns 3, I can see the values in my request: parameterHolder: action: index login: { login: foo, password: foo, _csrf_token: 53ebddee1883d7e3d6575d6fb1707a15 } module: login BUT getValues() returns NULL, getValue('login') etc. returns NULL as well. How can it be? And no, I don't want to use sfGuard-Plugins ;)

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  • How can I implement a login wall for expired or inappropriate pages?

    - by Redandwhite
    I am writing a website that very explicitly requires a login wall. Visitors should be required to log in before they are allowed to view a page. The page being built depends very much on the user's "ID". I am not sure how or where to store the user's login. I am not sure whether I should use a session variable (e.g. Session["userId"]), or some other method. The problem I see with session variables is that it's difficult to time out sessions. Note: I'm using C# 3.5 with ASP.NET in Visual Studio 2008.

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  • The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?)

    - by user1467175
    I encountered this error: The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?) Source Error: Line 28: Login Login1 = (WebControls.Login)LoginView1.FindControl("Login1"); // here the error code Line 29: TextBox UserName = (TextBox)Login1.FindControl("UserName"); Line 30: TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); I did some research and the solution was to add this into the source code: System.Web.UI.WebControls.Login but I have no idea where this code can be add into. At first I tried putting it as a namespace, but it was wrong. Anyone can tell me where should I place this code at?? EDIT protected void Login1_LoginError(object sender, System.EventArgs e) { //Login Login1 = (WebControls.Login).LoginView1.FindControl("Login1"); Login Login1 = (System.Web.UI.WebControls.Login)LoginView1.FindControl("Login1"); TextBox UserName = (TextBox)Login1.FindControl("UserName"); TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); //There was a problem logging in the user //See if this user exists in the database MembershipUser userInfo = Membership.GetUser(UserName.Text); if (userInfo == null) { //The user entered an invalid username... FailureText.Text = "There is no user in the database with the username " + UserName.Text; } else { //See if the user is locked out or not approved if (!userInfo.IsApproved) { FailureText.Text = "When you created your account you were sent an email with steps to verify your account. You must follow these steps before you can log into the site."; } else if (userInfo.IsLockedOut) { FailureText.Text = "Your account has been locked out because of a maximum number of incorrect login attempts. You will NOT be able to login until you contact a site administrator and have your account unlocked."; } else { //The password was incorrect (don't show anything, the Login control already describes the problem) FailureText.Text = string.Empty; } } }

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  • Struts2 linking actions

    - by SonOfTheEARTh
    I am working on the Login module of my Struts2 app. I have created the Login Page, and a home Page(which is rendered by Login.action). Now i want to add another feature, forgot password which after performing its business must call the Login.action so that the user need not have to Login explicitly. what should i code and where so that as soon as the ForgotPassword.action finishes its work it passes control to Login.action.

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  • Can't create add a SQL Server user: The login already has an account under a different user name.

    - by Zian Choy
    Environment: SQL Server 2005 Express Windows 7 When I installed SQL Server, I followed the instructions at http://msdn.microsoft.com/en-us/library/aa905868.aspx to set my computer's admin account as the SQL Server admin. However, when I try to access a database on my computer through Visual Studio 2008, I get the following error message: --------------------------- Microsoft Visual Studio --------------------------- The database 'Parkinsons' does not exist or you do not have permission to see it. Would you like to attempt to create it? --------------------------- Yes No --------------------------- Then, if I go to SQL Server and add a user to that database, I get the following error message: TITLE: Microsoft SQL Server Management Studio Express ------------------------------ Create failed for User 'zian'. (Microsoft.SqlServer.Express.Smo) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&ProdVer=9.00.2047.00&EvtSrc=Microsoft.SqlServer.Management.Smo.ExceptionTemplates.FailedOperationExceptionText&EvtID=Create+User&LinkId=20476 ------------------------------ ADDITIONAL INFORMATION: An exception occurred while executing a Transact-SQL statement or batch. (Microsoft.SqlServer.Express.ConnectionInfo) ------------------------------ The login already has an account under a different user name. (Microsoft SQL Server, Error: 15063) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&ProdVer=09.00.4053&EvtSrc=MSSQLServer&EvtID=15063&LinkId=20476 ------------------------------ BUTTONS: OK ------------------------------ Why doesn't VS piggy back on the dbo account? If the dbo account is unusable, then why won't SQL Server let me make an account so that I can access my own data?

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  • Inactive users in windows server after some time according to first login instead of defining a solid expiration date

    - by smhnaji
    We want to give access to some Windows Server users so they can remotely have access to our server and download from a special folder of the server. The licenses we give to users, are time base. There should be 1 month, 2 month, ..., 1 year, ... licenses. CURRENT SITUATION (WHAT I DON'T WANT): When users are created and added to the OS, a solid expiration date is given. WHAT I WANT: Users' expiration date should be calculated automatically after first login. The user might not need his account right when purchases the license. In another words: When a license of the user we create is purchased at Jan 1st, he should use the license until Feb 1st. No matter whether he really logs in or not. He cannot come Feb 5th and begin using his license because that has expired then. What I want is that when he comes at Feb 5th and begins using, the license update until March 5th. CLARIFICATION (Update after MDMarra's comment) Working environment is Windows Server 2012. By the word 'user', I mean Native Windows Server Users. Whenever a new person purchases a license with me, I create them manually using net user command like this: net user ali pass /add /expires:2013-12-25

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  • Start Chrome by command line, but adding some arguments to make it login into your Google account automatically

    - by jim
    Is there a way to start Chrome calling it from the command line (using Linux), but providing it some argument to make it login into some Google account automatically? I'm looking for something like google-chrome -account foo -pass bar that I can easily put in a bash script later. A little background: I have a laptop connected to my TV, which is currently using just a mouse for user interaction. There's no google account logged in by default, and that's the way I want to keep it, so my kids can't come across videos and pictures in google and youtube that they are not supposed to see (e.g.: adult content, or anything marked as not appropriate for kids by the google's safe search filters). The bad thing about this is that there are some music videos in youtube that requires you to be logged in to see, usually those we (the adults) used to sing when playing karaoke... as the only input available is a mouse, I'm looking for a way to start with my google account without having to type the whole thing usin the on-screen keyboard. You may think "Why you can't use the keyboard, if the laptop is right there?". Well, it's in a kind of uncomfortable position - too high for me without a chair or something, as it's right above the furniture in where the TV is located. Is there a way to make this scriptable? If not, do you know any other workaround? Note: using the remember me after logging off or alike options are discarded, as the safe-search chrome version must be always the default version to run.

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  • What can be a reason for phpMyAdmin login to be not working (not at all, no reaction on submit)?

    - by Ivan
    When I open "http://localhost/phpmyadmin/", enter "root" as the user name and my MySQL root password and press go, then if I was using Firefox, I was getting offered to download index.php file (of a zero length), if I was using Opera 11, it said "Connection closed by remote server". Following recommendations I've removed all packages related to phpMyAdmin, PHP, MySQL and Apache and then reinstalled them step-by step (instead of just issuing apt-get install phpmyadmin and relying on the system to install the whole LAMP stack via dependencies as I've done before). The only change I've got was Firefox to stop offering to download index.php - now when I press Ok to submit my password, it just doesn't show any visible reaction at all. What may the reason be and how to fix it? I use up-to-date Xubuntu 11.04. Reinstalling the whole LAMP stack and phpMyAdmin did not help, neither did removing AppArmor. I've tried to use SQLBuddy instead, but there's exactly the same problem. So, I think, the problem is not in phpMyAdmin but in MySQL, Apache or something. MySQL seems to work if I use command line to access it. Apache & PHP seems to work also, as the login page of phpMyAdmin displays correctly.

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  • What can be a reason for phpMyAdmin login to be not working (not at all, no reaction on submit)?

    - by Ivan
    When I open "http://localhost/phpmyadmin/", enter "root" as the user name and my MySQL root password and press go, then if I was using Firefox, I was getting offered to download index.php file (of a zero length), if I was using Opera 11, it said "Connection closed by remote server". Following recommendations I've removed all packages related to phpMyAdmin, PHP, MySQL and Apache and then reinstalled them step-by step (instead of just issuing apt-get install phpmyadmin and relying on the system to install the whole LAMP stack via dependencies as I've done before). The only change I've got was Firefox to stop offering to download index.php - now when I press Ok to submit my password, it just doesn't show any visible reaction at all. What may the reason be and how to fix it? I use up-to-date Xubuntu 11.04. Reinstalling the whole LAMP stack and phpMyAdmin did not help, neither did removing AppArmor. I've tried to use SQLBuddy instead, but there's exactly the same problem. So, I think, the problem is not in phpMyAdmin but in MySQL, Apache or something. MySQL seems to work if I use command line to access it. Apache & PHP seems to work also, as the login page of phpMyAdmin displays correctly.

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  • How to inactive Active Directory users, 1 month after their FIRST LOGIN, instead of defining a solid expiration date

    - by smhnaji
    We want to give access to some Active Directory users, so they can remotely have access to our server and download from a special folder of the server. The licenses we give to users, are time base. There should be 1 month, 2 month, ..., 1 year, ... licenses. CURRENT SITUATION (WHAT I DON'T WANT): When users are created and added to the OS, a solid expiration date is given. WHAT I WANT: Users' expiration date should be calculated automatically after the first login. The user might not need his account right when purchases the license. In other words: When a license of the user we create is purchased at Jan 1st, he should use the license until Feb 1st. No matter whether he really logs in or not. He cannot come Feb 5th and begin using his license because that has expired then. What I want is that when he comes at Feb 5th and begins using, the license update until March 5th. Working environment is Windows Server 2012. By the word 'user', I mean Active Directory Users.

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  • Recieving a 500 Internal Server error after login success?

    - by Jeremy Quick
    I created my first member login form which takes the typical username and password and then sends it to the code below: checklogin.php: mysql_connect($db_host, $db_username, $db_password) or die(mysql_error()); mysql_select_db($db_database) or die(mysql_error()); $username=$_POST['username']; $password=$_POST['password']; $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT * FROM users WHERE username='$username' and password='$password'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count == 1) //ERROR APPEARS TO TAKE PLACE HERE { session_start(); $_SESSION['username'] = $username; $_SESSION['password'] = $password; header('login_success.php'); } else { header("location:login_fail.php"); } If I type in the wrong information everything works properly so I know the error appears to be taking effect in the marked if statement. I have been searching the internet now looking for solutions but none seem to match mine or I am overlooking them. I've made a few changes which brought me to this point, before I was receiving deprecation warnings. Also, I have checked the logs and they are empty of errors relating to this.

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  • Server Migration Checklist II

    - by merrillaldrich
    Easy Breezy Login Audit for your Ol’ 2000 Server In the last post on this topic I put up the preparatory steps I’ve been using for server migrations. Here I am posting some code that has worked well for us to trace who/what is connecting to our older SQL Server 2000 machines. It’s a simple audit of login events, tracing the login name, host name, database, and last login time for connections to the server, and gave us valuable insight into who was really using the machines and which databases might...(read more)

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  • How to create a script which opens the browser and logins to a particular Gmail account?

    - by TechGuru
    I have created a bash script login.sh. I want it to open the browser and login to my Gmail account. I tried using the following command to open the browser with www.gmail.com. xdg-open http://gmail.com It opens Gmail home page perfectly. But I don't know how to pass the username and password for login to Gmail from the bash script. Is it possible to open the browser and login to Gmail from a script?

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  • visusal studio embedded crystal report keeps prompting database login?

    - by phill
    I'm using visual studio 2005 to develop a form with a combobox passing a value into the parameter of an embedded crystal report. I'm trying to figure out why it keeps prompting me for a database login every single time you try to run the report with a different combobox selection. Here is my code: private Sub Form1_load... Dim ConnName As String Dim ServerName As String Dim DBName As String Dim user As String Dim pass As String Dim gDBA As ADODB.Connection Dim records As ADODB.Recordset Dim datver As ADODB.Recordset Dim query As String '---OPEN THE DATABASE CONNECTIONS gDBA = New ADODB.Connection ': gDBA.CursorLocation = adUseServer 'Added to prevent time out error gDBA.CommandTimeout = 1000 : gDBA.ConnectionTimeout = 1000 gDBA.ConnectionString = "Server=svr13;Database=subscribers;User ID=KViews;Password=Solution;Trusted_Connection=True;" gDBA.Open("Data Source=Kaseya;Initial Catalog=subscribers;User Id=KViews;Password=Solution;", "KViews", "Solution") records = New ADODB.Recordset query = "select distinct groupname from _v_k order by groupname desc" 'records.ActiveConnection = gDBA.ConnectionString records.CursorType = CursorTypeEnum.adOpenForwardOnly records.LockType = LockTypeEnum.adLockReadOnly records.Open(query, gDBA) Do While Not records.EOF ComboBox1.Items.Add(records.Fields("groupname").Value) records.MoveNext() Loop end Sub Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim selected As String selected = ComboBox1.Text Dim cryRpt As New ReportDocument cryRpt.Load("C:\Visual Studio 2005\Projects\WindowsApplication1\WindowsApplication1\CrystalReport1.rpt") cryRpt.SetDatabaseLogon("KViews", "Solutions", "svr13", "subscribers") cryRpt.SetParameterValue("companyname", selected) CrystalReportViewer1.ReportSource = cryRpt CrystalReportViewer1.Refresh() End Sub I looked at this previous posting http://stackoverflow.com/questions/1132314/database-login-prompt-with-crystal-reports but this wasn't very helpful. I couldn't find where a CMC was to disable the prompt. Any ideas? thanks in advance

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  • How to add Remember me function at custom login box ?

    - by morningglory
    In my theme, there's custom page for the login. Login function at functions.php is like this function log_in($username, $password) { $user = parse_user($username); $username = $username; $password = $password; if(isEmptyString($username)) return new WP_Error('username', 'required'); if(isEmptyString($password)) return new WP_Error('password', "required"); if(!wp_check_password( $password, $user->user_pass ) ) return new WP_Error('wrong_password', "wrong"); wp_set_auth_cookie($user->ID, $remember); wp_login($username, $password); redirect_profile(); } function parse_user($info = null, $return = 'object') { if ( is_null( $info ) ) { global $current_user; if ( empty( $current_user->ID ) ) return null; $info = get_userdata( $current_user->ID ); } elseif ( empty( $info ) ) { return null; } if( $return == 'ID' ) { if ( is_object( $info ) ) return $info->ID; if ( is_numeric( $info ) ) return $info; } elseif( $return == 'object' ) { if ( is_object( $info ) && $info->ID) return $info; if ( is_object( $info )) return get_userdata( $info->ID ); if ( is_numeric( $info ) ) return get_userdata( $info ); if ( is_string( $info ) ) return get_userdatabylogin( $info ); } else { return null; } } I want to add remember me checkbox for user to logged in all the time until they logout. How can i add this ? Please kindly help me out. Thank you.

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  • Login failed for user ''. The user is not associated with a trusted SQL Server connection

    - by Tony_Henrich
    My web service app on my Windows XP box is trying to log in to my sql server 2005 database on the same box. The machine is part of a domain. I am logged in in the domain and I am an admin on my machine. I am using Windows Authentication in my connection string as in "Server=myServerAddress;Database=myDataBase;Trusted_Connection=True". SQLServer is configured for both types of authentication (mixed mode) and accepts remote connections and accepts tcp and named pipes protocols. Integrated authentication is enabled in IIS and with and without anonymous access. 'Everyone' has access to computer from network setting in local security settings. ASPNET is a user in the sql server and has access to the daatabase. user is mapped to the login. The app works fine for other developers which means the app shouldn't be changed (It's not new code). So it seems it's my machine which has an issue. I am getting the error "Login failed for user ''. The user is not associated with a trusted SQL Server connection" Note the blank user name. Why am I getting this error when both the app and database are on my machine? I can use SQL Server authentication but don't want to. I can connect to the database using SSMS and my Windows credentials. It might be related to setspn, kerberos, delegation, AD. I am not sure what further checks to make?

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  • does red5 read tomcat-users.xml

    - by baba
    Hi, I have been busy creating an app for Red5. Imagine what was my surprise when I tried to configure basic/digest authentication and I couldn't. What struck me as strange is that I have a running tomcat instance that works and authenticates correctly with the following xmls: web.xml (part of) <security-constraint> <web-resource-collection> <web-resource-name>A Protected Page</web-resource-name> <url-pattern>/stats.jsp</url-pattern> </web-resource-collection> <auth-constraint> <description/> <role-name>tomcat</role-name> </auth-constraint> </security-constraint> <login-config> <auth-method>DIGEST</auth-method> <realm-name>BLAAAAAAAAAAAAAAAAA</realm-name> </login-config> <security-role> <description/> <role-name>tomcat</role-name> </security-role> and a tomcat-users.xml in /conf that looks kinda like this: <?xml version="1.0" encoding="UTF-8"?> <tomcat-users> <role rolename="tomcat"/> <user username="ide" password="bogus" roles="tomcat"/> </tomcat-users> The annoying thing is that configuration authenticates correctly when on tomcat's servlet container, but on the red5's modified one, it just keeps asking for authentication. Am I becoming mad or it should work like a charm? Red5 is version 0_9_1 The stats.jsp is accessible in both servlet containers, the only difference is that when you input the correct password and username in tomcat, you are logged in, and in red5 you are not, it just keeps asking you for the password. Any pointers? Am I missing something? Here is a stack trace of the error I receive AT the moment I try the login: Caused by: java.io.IOException: Unable to locate a login configuration at com.sun.security.auth.login.ConfigFile.init(ConfigFile.java:250) [na:1.6.0_22] at com.sun.security.auth.login.ConfigFile.<init>(ConfigFile.java:91) [na:1.6.0_22] ... 27 common frames omitted [ERROR] [http-127.0.0.1-5080-1] org.apache.catalina.realm.JAASRealm - Cannot find message associated with key jaasRealm.unexpectedError java.lang.SecurityException: Unable to locate a login configuration at com.sun.security.auth.login.ConfigFile.<init>(ConfigFile.java:93) [na:1.6.0_22] at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) [na:1.6.0_22] at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) [na:1.6.0_22] at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) [na:1.6.0_22] at java.lang.reflect.Constructor.newInstance(Constructor.java:513) [na:1.6.0_22] at java.lang.Class.newInstance0(Class.java:355) [na:1.6.0_22] at java.lang.Class.newInstance(Class.java:308) [na:1.6.0_22] at javax.security.auth.login.Configuration$3.run(Configuration.java:247) [na:1.6.0_22] at java.security.AccessController.doPrivileged(Native Method) [na:1.6.0_22] at javax.security.auth.login.Configuration.getConfiguration(Configuration.java:242) [na:1.6.0_22] at javax.security.auth.login.LoginContext$1.run(LoginContext.java:237) [na:1.6.0_22] at java.security.AccessController.doPrivileged(Native Method) [na:1.6.0_22] at javax.security.auth.login.LoginContext.init(LoginContext.java:234) [na:1.6.0_22] at javax.security.auth.login.LoginContext.<init>(LoginContext.java:403) [na:1.6.0_22] at org.apache.catalina.realm.JAASRealm.authenticate(JAASRealm.java:394) [catalina-6.0.24.jar:na] at org.apache.catalina.realm.JAASRealm.authenticate(JAASRealm.java:357) [catalina-6.0.24.jar:na] at org.apache.catalina.authenticator.DigestAuthenticator.findPrincipal(DigestAuthenticator.java:283) [catalina-6.0.24.jar:na] at org.apache.catalina.authenticator.DigestAuthenticator.authenticate(DigestAuthenticator.java:176) [catalina-6.0.24.jar:na] at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:523) [catalina-6.0.24.jar:na] at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) [catalina-6.0.24.jar:na] at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) [catalina-6.0.24.jar:na] at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:555) [catalina-6.0.24.jar:na] at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) [catalina-6.0.24.jar:na] at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) [catalina-6.0.24.jar:na] at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) [tomcat-coyote-6.0.24.jar:na] at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) [tomcat-coyote-6.0.24.jar:na] at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) [tomcat-coyote-6.0.24.jar:na] at java.lang.Thread.run(Thread.java:662) [na:1.6.0_22] Caused by: java.io.IOException: Unable to locate a login configuration at com.sun.security.auth.login.ConfigFile.init(ConfigFile.java:250) [na:1.6.0_22] at com.sun.security.auth.login.ConfigFile.<init>(ConfigFile.java:91) [na:1.6.0_22] ... 27 common frames omitted In addition, here is the configuration of red5-web.properties webapp.contextPath=/project Even futher information: Seems to me like it is using the right realm: MemoryRealm [INFO] [main] org.red5.server.tomcat.TomcatLoader - Setting connector: org.apache.catalina.connector.Connector [INFO] [main] org.red5.server.tomcat.TomcatLoader - Address to bind: /127.0.0.1:5080 [INFO] [main] org.red5.server.tomcat.TomcatLoader - Setting realm: org.apache.catalina.realm.MemoryRealm [INFO] [main] org.red5.server.tomcat.TomcatLoader - Loading tomcat context [INFO] [main] org.red5.server.tomcat.TomcatLoader - Server root: C:/Program Files/Red5 [INFO] [main] org.red5.server.tomcat.TomcatLoader - Config root: C:/Program Files/Red5/conf [INFO] [main] org.red5.server.tomcat.TomcatLoader - Application root: C:/Program Files/Red5/webapps [INFO] [main] org.red5.server.tomcat.TomcatLoader - Starting Tomcat servlet engine [INFO] [main] org.apache.catalina.startup.Embedded - Starting tomcat server [INFO] [main] org.apache.catalina.core.StandardEngine - Starting Servlet Engine: Apache Tomcat/6.0.26 However, immediately after bootstraping Tomcat, I am presented with the following error: Exception in thread "Launcher:/administration" org.springframework.beans.factory.BeanDefinitionStoreException: Could not resolve bean definition resource pattern [/WEB-INF/red5-*.xml]; nested exception is java.io.FileNotFoundException: ServletContext resource [/WEB-INF/] cannot be resolved to URL because it does not exist at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:190) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:149) at org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:124) at org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:93) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:130) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:458) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:388) at org.red5.server.tomcat.TomcatLoader$1.run(TomcatLoader.java:594) Caused by: java.io.FileNotFoundException: ServletContext resource [/WEB-INF/] cannot be resolved to URL because it does not exist at org.springframework.web.context.support.ServletContextResource.getURL(ServletContextResource.java:132) at org.springframework.core.io.support.PathMatchingResourcePatternResolver.isJarResource(PathMatchingResourcePatternResolver.java:414) at org.springframework.core.io.support.PathMatchingResourcePatternResolver.findPathMatchingResources(PathMatchingResourcePatternResolver.java:343) at org.springframework.core.io.support.PathMatchingResourcePatternResolver.getResources(PathMatchingResourcePatternResolver.java:282) at org.springframework.context.support.AbstractApplicationContext.getResources(AbstractApplicationContext.java:1156) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:177) ... 7 more This error is kinda strange, because after this it seems that /WEB-INF/ is found by the rest of the program by the following output: [INFO] [Launcher:/SOSample] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] [INFO] [Launcher:/installer] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] [INFO] [Launcher:/] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] [INFO] [Launcher:/LiveMedia] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] What really annoys me is that, as you can see in the output, when I try to login, I get a JAASRealm-related exception, but in the debug output when Tomcat is loading, it is clear to me that it expects a MemoryRealm. I was wondering where and how in red5.xml should I specify bean properties such that I force red5 to use MemoryRealm that is under /conf/tomcat-users.xml, because it certainly doesn't do so now. It seems like the biggest question I have posted so far, but I tried to explain it as fully as possible as to avoid confusion.

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  • HTTP status 405 - HTTP method POST is not supported by this URL

    - by Wont Say
    I am getting this "HTTP method POST is not supported by this URL" error when I run my project. The funny thing is, it was running perfectly fine two days ago. After I made a few changes to my code but then restored my original code and its giving me this error. Could you please help me? Here is my index.html: <form method="post" action="login.do"> <div> <table> <tr><td>Username: </td><td><input type="text" name="e_name"/> </td> </tr> <tr><td> Password: </td><td><input type="password" name="e_pass"/> </td> </tr> <tr><td></td><td><input type="submit" name ="e_submit" value="Submit"/> Here is my Login servlet: public class Login extends HttpServlet { /** * Processes requests for both HTTP * <code>GET</code> and * <code>POST</code> methods. * * @param request servlet request * @param response servlet response * @throws ServletException if a servlet-specific error occurs * @throws IOException if an I/O error occurs */ protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, SQLException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { /* * TODO output your page here. You may use following sample code. */ int status; String submit = request.getParameter("e_submit"); String submit2 = request.getParameter("a_submit"); out.println("Here1"); String e_name = request.getParameter("e_name"); String e_password = request.getParameter("e_pass"); String a_name = request.getParameter("a_name"); String a_password = request.getParameter("a_pass"); out.println(e_name+e_password+a_name+a_password); Author author = new Author(a_name,a_password); Editor editor = new Editor(e_name,e_password); // If it is an AUTHOR login: if(submit==null){ status = author.login(author); out.println("Author Login"); //Incorrect login details if(status==0) { out.println("Incorrect"); RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- AUTHOR else { out.println("Correct login details"); HttpSession session = request.getSession(); session.setAttribute(a_name, "a_name"); RequestDispatcher view = request.getRequestDispatcher("index_S.jsp"); view.forward(request, response); } } //If it is an EDITOR login else if (submit2==null){ status = editor.login(editor); //Incorrect login details if(status==0) { RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- EDITOR else { out.println("correct"); HttpSession session = request.getSession(); session.setAttribute(e_name, "e_name"); session.setAttribute(e_password, "e_pass"); RequestDispatcher view = request.getRequestDispatcher("index_S_1.html"); view.forward(request, response); } } out.println("</body>"); out.println("</html>"); } finally { out.close(); } } @Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doPost(req, resp); } @Override protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doGet(req, resp); }} And my web.xml looks like this: <?xml version="1.0" encoding="UTF-8"?> <servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/struts-config.xml</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>2</param-value> </init-param> <init-param> <param-name>detail</param-name> <param-value>2</param-value> </init-param> <load-on-startup>2</load-on-startup> </servlet> <servlet> <servlet-name>Login</servlet-name> <servlet-class>controller.Login</servlet-class> </servlet> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Login</servlet-name> <url-pattern>/login.do</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> I use Glassfish v3 server - let me know anything else you need to know

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  • Outlook 2007 Does Not Accept Login Credentials, OWA Webmail Does. Troubleshooting Advice?

    - by Chris
    I am trying to connect Outlook 2007 to Exchange (Hosted Exchange from Rackspace). Soon, I will need to roll this out for our entire office. With the Exchange account added to Outlook, Outlook starts up and asks for the user's username and password. Unfortunately, it doesn't like the password I use for it. I can confirm this username (email address) and password combo works by using Outlook WebMail, and another user (in another network/office) confirmed the Exchange account does work within his Outlook client. In my network/office, I can confirm that an Outlook 2007 client (under Windows 7) can connect to the Hosted Exchange server from Rackspace. However, I have not been able to get Outlook 2007 (under Windows XP SP3) to connect to the very same Exchange server Outlook 2007 (under Windows 7) can connect to. Outlook continuously prompts me for the username and password and does not accept the correct combination. Now, regarding the Outlook client that cannot connect/login to Exchange: The user has full admin rights on the workstation We do not run a domain controller/LDAP The firewall on the workstation has been disabled Real time file scanning in Microsoft Security Essentials has been disabled There are no virus scanning applications that would interface with Outlook or an email server. The Exchange account is setup to run on a newly created Outlook profile The network firewall does not log any blocked attempts A packet capture at the router reveals communication between the workstation and the Exchange server or proxy (though, this is SSL encrypted, so I don't know what the computers are saying) I have applied a fix (Added DWORD value of 0 for DefConnectOpts under HKEY_CURRENT_USER\Software\Microsoft\Office\12.0\Outlook\RPC) that was recommended to make RPC function when the workstation does not have a default gateway set. Workstation is configured as DHCP. This fix did nothing, and it may be worth noting the RPC subkey was not present until I added it. RPC service is running on the workstation The program is not running under any compatibility mode. Side note: Outlook 2007 installs with compatibility mode for XP enabled by default in windows 7. Outlook 2007 will not even try to connect to exchange if this compatibility mode is checked. In windows xp, I tried checking compatibility mode for windows 2000, and was unable to connect to exchange as well. Here is the specific configuration I've used in a blank outlook profile: Microsoft Exchange Server: ##MASKED##-MBX-C18.mex07a.mlsrvr.com Username: (Full Email Address: [email protected]) Password: ##MASKED## Outlook Anywhere: Connect to Microsoft Exchange using HTTP Exchange Proxy Settings: Proxy Server: mex07a.emailsrvr.com Check "Connect using SSL only" Under "Only connect to proxy servers...", enter: msstd:mex07a.emailsrvr.com Check "On fast networks, connect using HTTP first, then connect using TCP/IP" Check "On slow networks, connect using HTTP first, then connect using TCP/IP" Proxy authentication settings: Basic Authentication Notes: mex07a.mlsrvr.com and mex07a.emailsrvr.com may look incorrect at first glance, but this is not a typo - these instructions were handed down from rackspace and are confirmed to be working, just not on this workstation. I have tried to use the RpcPing utility but must have been using it wrong. I got as far as "Bad Interface Descriptor". It would seem to me getting Outlook and Exchange to work together would be a breeze, especially since everything is done over port 80 with web services. Unfortunately, the user is stuck with WebMail access only, because Outlook won't accept the Exchange credentials. Do you have any ideas of other things I could try to debug this issue further? Any and all help is greatly appreciated. Thank you! -Chris

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  • System.AccessViolationException when calling DLL from WCF on IIS.

    - by Wodzu
    Hi guys. I've created just a test WCF service in which I need to call an external DLL. Everything works fine under Visutal Studio development server. However, when I try to use my service on IIS I am getting this error: Exception: System.AccessViolationException Message: Attempted to read or write protected memory. This is often an indication that other memory is corrupt. The stack trace leeds to the call of DLL which is presented below. After a lot of reading and experimenting I am almost sure that the error is caused by wrong passing strings to the called function. Here is how the wrapper for DLL looks like: using System; using System.Runtime.InteropServices; using System.Text; using System; using System.Security; using System.Security.Permissions; using System.Runtime.InteropServices; namespace cdn_api_wodzu { public class cdn_api_wodzu { [DllImport("cdn_api.dll", CharSet=CharSet.Ansi)] // [SecurityPermission(SecurityAction.Assert, Unrestricted = true)] public static extern int XLLogin([In, Out] XLLoginInfo _lLoginInfo, ref int _lSesjaID); } [Serializable, StructLayout(LayoutKind.Sequential)] public class XLLoginInfo { public int Wersja; public int UtworzWlasnaSesje; public int Winieta; public int TrybWsadowy; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x29)] public string ProgramID; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x15)] public string Baza; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 9)] public string OpeIdent; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 9)] public string OpeHaslo; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 200)] public string PlikLog; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x65)] public string SerwerKlucza; public XLLoginInfo() { } } } this is how I call the DLL function: int ErrorID = 0; int SessionID = 0; XLLoginInfo Login; Login = new XLLoginInfo(); Login.Wersja = 18; Login.UtworzWlasnaSesje = 1; Login.Winieta = -1; Login.TrybWsadowy = 1; Login.ProgramID = "TestProgram"; Login.Baza = "TestBase"; Login.OpeIdent = "TestUser"; Login.OpeHaslo = "TestPassword"; Login.PlikLog = "C:\\LogFile.txt"; Login.SerwerKlucza = "MyServ\\MyInstance"; ErrorID = cdn_api_wodzu.cdn_api_wodzu.XLLogin(Login, ref SessionID); When I comment all the string field assigments the function works - it returns me an error message that the program ID has not been given. But when I try to assign a ProgramID (or any other string fields, or all at once) then I am getting the mentioned exception. I am using VS2008 SP.1, WinXP and IIS 5.1. Maybe the ISS itself is a problem? I've tried all the workarounds that has been described here: http://forums.asp.net/t/675515.aspx Thansk for your time. After edit: Installing Windows 2003 Server and IIS 6.0 solved the problem.

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  • Why does the interpretted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def init(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • Why does the interpreted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def __init__(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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