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  • Regular expression replace in PL/pgSQL

    - by dreamlax
    If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

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  • Regular expression to match maximium of five words.

    - by KhanS
    I have a regular expression ^[a-zA-Z+#-.0-9]{1,5}$ which validates that the word contains alpha-numeric characters and few special characters and length should not be more than 5 characters. How do I make this regular expression to accept a maximum of five words matching the above regular expression.

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  • How to sort output of "s3cmd ls"

    - by dba.in.ua
    Amazon "s3cmd ls" takes like this output: 2010-02-20 21:01 1458414588 s3://file.tgz.00 2010-02-20 21:10 1458414527 s3://file.tgz.01 2010-02-20 22:01 1458414588 s3://file.tgz.00 2010-02-20 23:10 1458414527 s3://file.tgz.01 2010-02-20 23:20 1458414588 s3://file.tgz.02 How to select all files of archive, ending at 0 ... X, with the latest date of fileset ? Bash, regexp ? Thanx!

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  • Determining whether values can potentially match a regular expression, given more input

    - by Andreas Grech
    I am currently writing an application in JavaScript where I'm matching input to regular expressions, but I also need to find a way how to match strings to parts of the regular expressions. For example: var invalid = "x", potentially = "g", valid = "ggg", gReg = /^ggg$/; gReg.test(invalid); //returns false (correct) gReg.test(valid); //returns true (correct) Now I need to find a way to somehow determine that the value of the potentially variable doesn't exactly match the /^ggg$/ expression, BUT with more input, it potentially can! So for example in this case, the potentially variable is g, but if two more g's are appended to it, it will match the regular expression /^ggg$/ But in the case of invalid, it can never match the /^ggg$/ expression, no matter how many characters you append to it. So how can I determine if a string has or doesn't have potential to match a particular regular expression?

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  • Java Preprocessor in C#

    - by Olaseni
    Say I want to create a sort of Pre-processor for existing java code, so I can get the language specific keywords and objects, and then create routines that convert them to their Csharp equivalents, using Csharp code - what route should this take? I'm thinking of Regular Expressions, but I'm fuzzed. I have a bunch of about a 100 .java files and I need to convert them to csharp code in record time. I have manually done just about five of them and I have serious headaches already. Or are there any tools out there that already do that?

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  • preg_replace, exact opposite of a preg_match

    - by SoLoGHoST
    I need to do a preg_replace for the exact opposite of this preg_match regular expression: preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string); So I need to replace all strings that are not valid with an empty string - '' So it needs to remove the first / and last / if found, and all non-valid characters, that is the only valid characters are A-Z, a-z, 0-9, _, ., and / (if it's not the first or last characters of the string). How can I accomplish this with the preg_replace? Thanks :)

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  • PHP Form Validation Regular Expression, no symbols or numbers

    - by MrEnder
    Ok I am trying to get the users First Name the form gets their name perfectly fine and posts it into a variable. Now I am trying to do error checking else if(!preg_match("/^[\w-]+$/", $firstNameSignup)) { $firstNameSignupError = "Your first name cannot contain numbers or symbols, you entered " . $firstNameSignup; $firstNameSignup = ""; } I tried the above code and it does not like me but my if statement if(!isset($firstNameSignup) || $firstNameSignup == "") { $firstNameSignupError = "You must enter your first name"; } works fine so I know that the error is in that else if statement... most likely in my regular expression any help??? I'm totally at a loss (really new to PHP and regular expressions) Thanks Shelby

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  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

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  • Regular expression works normally, but fails when placed in an XML schema

    - by Eli Courtwright
    I have a simple doc.xml file which contains a single root element with a Timestamp attribute: <?xml version="1.0" encoding="utf-8"?> <root Timestamp="04-21-2010 16:00:19.000" /> I'd like to validate this document against a my simple schema.xsd to make sure that the Timestamp is in the correct format: <?xml version="1.0" encoding="utf-8"?> <xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="root"> <xs:complexType> <xs:attribute name="Timestamp" use="required" type="timeStampType"/> </xs:complexType> </xs:element> <xs:simpleType name="timeStampType"> <xs:restriction base="xs:string"> <xs:pattern value="(0[0-9]{1})|(1[0-2]{1})-(3[0-1]{1}|[0-2]{1}[0-9]{1})-[2-9]{1}[0-9]{3} ([0-1]{1}[0-9]{1}|2[0-3]{1}):[0-5]{1}[0-9]{1}:[0-5]{1}[0-9]{1}.[0-9]{3}" /> </xs:restriction> </xs:simpleType> </xs:schema> So I use the lxml Python module and try to perform a simple schema validation and report any errors: from lxml import etree schema = etree.XMLSchema( etree.parse("schema.xsd") ) doc = etree.parse("doc.xml") if not schema.validate(doc): for e in schema.error_log: print e.message My XML document fails validation with the following error messages: Element 'root', attribute 'Timestamp': [facet 'pattern'] The value '04-21-2010 16:00:19.000' is not accepted by the pattern '(0[0-9]{1})|(1[0-2]{1})-(3[0-1]{1}|[0-2]{1}[0-9]{1})-[2-9]{1}[0-9]{3} ([0-1]{1}[0-9]{1}|2[0-3]{1}):[0-5]{1}[0-9]{1}:[0-5]{1}[0-9]{1}.[0-9]{3}'. Element 'root', attribute 'Timestamp': '04-21-2010 16:00:19.000' is not a valid value of the atomic type 'timeStampType'. So it looks like my regular expression must be faulty. But when I try to validate the regular expression at the command line, it passes: >>> import re >>> pat = '(0[0-9]{1})|(1[0-2]{1})-(3[0-1]{1}|[0-2]{1}[0-9]{1})-[2-9]{1}[0-9]{3} ([0-1]{1}[0-9]{1}|2[0-3]{1}):[0-5]{1}[0-9]{1}:[0-5]{1}[0-9]{1}.[0-9]{3}' >>> assert re.match(pat, '04-21-2010 16:00:19.000') >>> I'm aware that XSD regular expressions don't have every feature, but the documentation I've found indicates that every feature that I'm using should work. So what am I mis-understanding, and why does my document fail?

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  • validate hostname in Python

    - by kostmo
    Following up to Regular expression to match hostname or IP Address? and using Restrictions on valid host names as a reference, what is the most readable, concise way to match/validate a hostname/fqdn (fully qualified domain name) in Python? I've answered with my attempt below, improvements welcome.

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  • Track results of a regular expression extractor in JMeter

    - by Glenn Slaven
    Our server returns a custom 'X-Execution-Time' HTTP response header that returns in miliseconds the time between the server getting a request and our code returning a page, ie how long our code takes to run. I'm using JMeter to do some testing & I'd like to be able to report on this number of over time. I've setup this regular expression extractor: X-Execution-Time:\s(\d+) but I don't know how to get JMeter to report on this number per request so i can get a trend over time

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  • Turning HTML character entities to 'regular' letters... why is it only partially working?

    - by Jack W-H
    I'm using all of the below to take a field called 'code' from my database, get rid of all the HTML entities, and print it 'as usual' to the site: <?php $code = preg_replace('~&#x([0-9a-f]+);~ei', 'chr(hexdec("\\1"))', $code); $code = preg_replace('~&#([0-9]+);~e', 'chr("\\1")', $code); $code = html_entity_decode($code); ?> However the exported code still looks like this: progid:DXImageTransform.Microsoft.AlphaImageLoader(src=’img/the_image.png’); See what's going on there? How many other things can I run on the string to turn them into darn regular characters?! Thanks! Jack

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  • replace string in preg_replace

    - by zahir hussain
    <?php $a="php.net s earch for in the all php.net sites this mirror only function list online documentation bug database Site News Archive All Changelogs just pear.php.net just pecl.php.net just talks.php.net general mailing list developer mailing list documentation mailing list What is PHP? PHP is a widely-used..."; ?> I want to highlight specific words. For example php, net and func: php.net s earch for in the all **php**.**net** sites this mirror only **func**tion list online documentation bug database Site News Archive All Changelogs just pear.**php**.**net** just pecl.**php**.**net** just talks.php.net general mailing list developer mailing list documentation mailing list What is **PHP**? **PHP** is a widely-used... Thanks advance.

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  • How to get regular expression matches between two boundaries

    - by Rubans
    Hi, I have the following text: started: Project: ProjectA, Configuration: Release Any CPU ------ I would like to get just the actual project name which in this example is "ProjectA". I do have a regular expression "started:(\s)Project:(\s).*," which will give me "started: Project: ProjectA," and then I can use further basic string searching to return the project name but was wondering if there is any way I can just grab the actual project name without doing the extra string searching, maybe using a correct regular expression. What I need is the string value between boundaries "started: Project: " and ",". Any ideas?

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  • Evaluating a regular expression range

    - by Dan Atkinson
    Hi there! Is there a nice way to evaluate a regular expression range, say, for a url such as http://example.com/[a-z]/[0-9].htm This would be converted into: http://example.com/a/0.htm http://example.com/a/1.htm http://example.com/a/2.htm ... http://example.com/a/9.htm ... http://example.com/z/0.htm http://example.com/z/1.htm http://example.com/z/2.htm ... http://example.com/z/9.htm I've been scratching my head about this, and there's no pretty way of doing it without going through the alphabet and looping through numbers. Thanks in advance!

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  • Finding duplicate files by content across multiple directories

    - by gagneet
    I have downloaded some files from the internet related to a particular topic. Now I wish to check if the files have any duplicates. The issue is that the names of the files would be different, but the content may match. Is there any way to implement some code, which will iterate through the multiple folders and inform which of the files are duplicates?

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  • Why String.replaceAll() don't work on this String ?

    - by Aloong
    //This source is a line read from a file String src = "23570006,music,**,wu(),1,exam,\"Monday9,10(H2-301)\",1-10,score,"; //This sohuld be from a matcher.group() when Pattern.compile("\".*?\"") String group = "\"Monday9,10(H2-301)\""; src = src.replaceAll("\"", ""); group = group.replaceAll("\"", ""); String replacement = group.replaceAll(",", "#@"); System.out.println(src.contains(group)); src = src.replaceAll(group, replacement); System.out.println(group); System.out.println(replacement); System.out.println(src); I'm trying to replace the "," between \"s so I can ues String.split() latter. But the above just not working , the result is: true Monday9,10(H2-301) Monday9#@10(H2-301) 23570006,music,**,wu(),1,exam,Monday9,10(H2-301),1-10,score, but when I change the src string to String src = "123\"9,10\"123"; String group = "\"9,10\""; It works well true 9,10 9#@10 1239#@10123 What's the matter with the string???

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  • Regular Expressions

    - by Rocky
    Hello Everyone, I am new to Stackoverflow and I have a quick question. Let's assume we are given a large number of HTML files (large as in theoretically infinite). How can I use Regular Expressions to extract the list of Phone Numbers from all those files? Explanation/expression will be really appreciated. The Phone numbers can be any of the following formats: (123) 456 7899 (123).456.7899 (123)-456-7899 123-456-7899 123 456 7899 1234567899 Thanks a lot for all your help and have a good one!

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  • data in mysql show after barcode split and matches character

    - by klox
    i need some code for the next step..this my first step: <script> $("#mod").change(function() { var barcode; barCode=$("#mod").val(); var data=barCode.split(" "); $("#mod").val(data[0]); $("#seri").val(data[1]); var str=data[0]; var matches=str.matches(/EE|[EJU]).*(D)/i); }); </script> after matches..i want the result can connect to data base then show data from table inside <div id="value">...how to do that?

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