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  • Regexp match in Java

    - by tinti
    Regexp in Java I want to make a regexp who do this verify if a word is like [0-9A-Za-z][._-'][0-9A-Za-z] example for valid words A21a_c32 daA.da2 das'2 dsada ASDA 12SA89 non valid words dsa#da2 34$ Thanks

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  • Problem with Javascript RegExp-mask

    - by OrjanL
    I have a string that looks something like this: {theField} > YEAR (today, -3) || {theField} < YEAR (today, +3) I want it to be replaced into: {theField} > " + YEAR (today, -3) + " || {theField} < " + YEAR (today, +3) + " I have tried this: String.replace(/(.*)(YEAR|MONTH|WEEK|DAY+)(.*[)]+)/g, "$1 \" + $2 $3 + \"") But that gives me: {theField} > YEAR (today, +3) || {theField} > " + YEAR (today, +3) + " Does anyone have any ideas?

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  • Find ASCII "arrows" in text

    - by ulver
    I'm trying to find all the occurrences of "Arrows" in text, so in "<----=====><==->>" the arrows are: "<----", "=====>", "<==", "->", ">" This works: String[] patterns = {"<=*", "<-*", "=*>", "-*>"}; for (String p : patterns) { Matcher A = Pattern.compile(p).matcher(s); while (A.find()) { System.out.println(A.group()); } } but this doesn't: String p = "<=*|<-*|=*>|-*>"; Matcher A = Pattern.compile(p).matcher(s); while (A.find()) { System.out.println(A.group()); } No idea why. It often reports "<" instead of "<====" or similar. What is wrong?

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  • Building a Hashtag in Javascript without matching Anchor Names, BBCode or Escaped Characters

    - by Martindale
    I would like to convert any instances of a hashtag in a String into a linked URL: #hashtag - should have "#hashtag" linked. This is a #hashtag - should have "#hashtag" linked. This is a [url=http://www.mysite.com/#name]named anchor[/url] - should not be linked. This isn&#39;t a pretty way to use quotes - should not be linked. Here is my current code: String.prototype.parseHashtag = function() { return this.replace(/[^&][#]+[A-Za-z0-9-_]+(?!])/, function(t) { var tag = t.replace("#","") return t.link("http://www.mysite.com/tag/"+tag); }); }; Currently, this appears to fix escaped characters (by excluding matches with the amperstand), handles named anchors, but it doesn't link the #hashtag if it's the first thing in the message, and it seems to grab include the 1-2 characters prior to the "#" in the link. Halp!

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  • preg_replace only part of match

    - by Tony Vipros
    Hi, I'm using preg_replace to create urls for modrewrite based paging links. I use: $nextURL = preg_replace('%/([\d]+)/%','/'.($pageNumber+1).'/',$currentURL); which works fine, however I was wondering if there is a better way without having to include the '/' in the replacement parameter. I need to match the number as being between two / as the URLs can sometimes contain numbers other than the page part. These numbers are never only numbers however, so have /[\d]+/ stops them from getting replaced.

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  • Intersection of two regular expressions

    - by Henry
    Hi, Im looking for function (PHP will be the best), which returns true whether exists string matches both regexpA and regexpB. Example 1: $regexpA = '[0-9]+'; $regexpB = '[0-9]{2,3}'; hasRegularsIntersection($regexpA,$regexpB) returns TRUE because '12' matches both regexps Example 2: $regexpA = '[0-9]+'; $regexpB = '[a-z]+'; hasRegularsIntersection($regexpA,$regexpB) returns FALSE because numbers never matches literals. Thanks for any suggestions how to solve this. Henry

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  • Replaceing <a href="mailto: with just email aadress

    - by Lauri
    I want to replace all "mailto:" links in html with plain emails. In: text .... <a href="mailto:[email protected]">not needed</a> text Out: text .... [email protected] text I did this: $str = preg_replace("/\<a.+href=\"mailto:(.*)\".+\<\/a\>/", "$1", $str); But it fails if there are multiple emails in string or html inside "a" tag In: <a href="mailto:[email protected]">not needed</a><a href="mailto:[email protected]"><font size="3">[email protected]</font></a> Out: [email protected]">

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  • regular expression of 0's and 1's

    - by Lopa
    Hello all I got this question which asks me to figure out why is it foolish to write a regular expression for the language that consists of strings of 0's and 1's that are palindromes( they read the same backwards and forwards). part 2 of the question says using any formal mechanism of your choice, show how it is possible to express the language that consists of strings of 0's and 1's that are palindromes?

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  • How do you implement a good profanity filter?

    - by Ben Throop
    Many of us need to deal with user input, search queries, and situations where the input text can potentially contain profanity or undesirable language. Oftentimes this needs to be filtered out. Where can one find a good list of swear words in various languages and dialects? Are there APIs available to sources that contain good lists? Or maybe an API that simply says "yes this is clean" or "no this is dirty" with some parameters? What are some good methods for catching folks trying to trick the system, like a$$, azz, or a55? Bonus points if you offer solutions for PHP. :) Edit: Response to answers that say simply avoid the programmatic issue: I think there is a place for this kind of filter when, for instance, a user can use public image search to find pictures that get added to a sensitive community pool. If they can search for "penis", then they will likely get many pictures of, yep. If we don't want pictures of that, then preventing the word as a search term is a good gatekeeper, though admittedly not a foolproof method. Getting the list of words in the first place is the real question. So I'm really referring to a way to figure out of a single token is dirty or not and then simply disallow it. I'd not bother preventing a sentiment like the totally hilarious "long necked giraffe" reference. Nothing you can do there. :)

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  • Bash: Extract Range with Regular Expressioin (maybe sed?)

    - by sixtyfootersdude
    I have a file that is similar to this: <many lines of stuff> SUMMARY: <some lines of stuff> END OF SUMMARY I want to extract just the stuff between SUMMARY and END OF SUMMARY. I suspect I can do this with sed but I am not sure how. I know I can modify the stuff in between with this: sed "/SUMMARY/,/END OF SUMMARY/ s/replace/with/" fileName (But not sure how to just extract that stuff). I am Bash on Solaris.

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  • Pattern/Matcher in Java?

    - by user1007059
    I have a certain text in Java, and I want to use pattern and matcher to extract something from it. This is my program: public String getItemsByType(String text, String start, String end) { String patternHolder; StringBuffer itemLines = new StringBuffer(); patternHolder = start + ".*" + end; Pattern pattern = Pattern.compile(patternHolder); Matcher matcher = pattern.matcher(text); while (matcher.find()) { itemLines.append(text.substring(matcher.start(), matcher.end()) + "\n"); } return itemLines.toString(); } This code works fully WHEN the searched text is on the same line, for instance: String text = "My name is John and I am 18 years Old"; getItemsByType(text, "My", "John"); immediately grabs the text "My name is John" out of the text. However, when my text looks like this: String text = "My name\nis John\nand I'm\n18 years\nold"; getItemsByType(text, "My", "John"); It doesn't grab anything, since "My" and "John" are on different lines. How do I solve this?

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  • Regexp: Replace only in specific context

    - by blinry
    In a text, I would like to replace all occurrences of $word by [$word]($word) (to create a link in Markdown), but only if it is not already in a link. Example: [$word homepage](http://w00tw00t.org) should not become [[$word]($word) homepage](http://w00tw00t.org). Thus, I need to check whether $word is somewhere between [ and ] and only replace if it's not the case. Can you think of a preg_replace command for this?

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  • Convert regular expression to CFG

    - by user242581
    How can I convert some regular language to its equivalent Context Free Grammar(CFG)? Whether the DFA corresponding to that regular expression is required to be constructed or is there some rule for the above conversion? For example, considering the following regular expression 01+10(11)* How can I describe the grammar corresponding to the above RE?

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  • Filtering out emoticons using sed

    - by user349222
    Hello, I have a grep expression using cygwin grep on Win. grep -a "\\,,/\|\\m/\|\\m/\\>\.</\\m/\|:u" all_fbs.txt > rockon_fbs.txt Once I identify the emoticon class, however, I want to strip them out of the data. However, the same regexp above within a sed results in a syntax error (yes, I realize I could use /d instead of //g, but this doesn't make a difference, I still get the error.) sed "s/\(\\,,/\|\\m/\|\\m/\\>\.</\\m/\|:u\)*//g" The full line is: grep -a "\\,,/\|\\m/\|\\m/\\>\.</\\m/\|:u" all_fbs.txt | sed "s/\(\\,,/\|\\m/\|\\m/\\>\.</\\m/\|:u\)*//g" | sed "s/^/ROCKON\t/" > rockon_fbs.txt The result is: sed: -e expression #1, char 14: unknown option to `s' I know it's coming from the sed regexp I'm asking about it b/c if I remove that portion of the full line, then I get no error (but, of course, the emoticons are not filtered out). Thanks in advance, Steve

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  • How to split a space separated file?

    - by simplesimon
    Hi I am trying to import this: http://en.wikipedia.org/wiki/List_of_countries_by_continent_%28data_file%29 which is of the format like: AS AF AFG 004 Afghanistan, Islamic Republic of EU AX ALA 248 Åland Islands EU AL ALB 008 Albania, Republic of AF DZ DZA 012 Algeria, People's Democratic Republic of OC AS ASM 016 American Samoa EU AD AND 020 Andorra, Principality of AF AO AGO 024 Angola, Republic of NA AI AIA 660 Anguilla if i do <? explode(" ",$data"); ?> that works fine apart from countries with more than 1 word. how can i split it so i get the first 4 bits of data (the chars/ints) and the 5th bit of data being whatever remains? this is in php thank you

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  • How to remove a tab attribute in ASP .NET AJAX Toolkit using Regular Expression

    - by Nassign
    I have tried to remove the following tag generated by the AJAX Control toolkit. The scenario is our GUI team used the AJAX control toolkit to make the GUI but I need to move them to normal ASP .NET view tag using MultiView. I want to remove all the __designer: attributes Here is the code <asp:TextBox ID="a" runat="server" __designer:wfdid="w540" /> <asp:DropdownList ID="a" runat="server" __designer:wfdid="w541" /> ..... <asp:DropdownList ID="a" runat="server" __designer:wfdid="w786" /> I tried to use the regular expression find replace in Visual Studio using: Find: :__designer\:wfdid="w{([0-9]+)}" Replace with empty space Can any regular expression expert help?

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  • Replacing values using preg_replace

    - by Jeepstone
    I have a Joomla plugin (not important in this context), which is designed to take an input with a load of numbers (within a paragraph of text) and replace them with a series of s. My problem is that I need to do a preg_replace on my $article-text, but I don't know how to then apply the changes to the matched terms. I've seen the preg_replace_callback, but I don't know how I can call that within a function. function onPrepareContent( &$article, &$params, $limitstart ) { global $mainframe; // define the regular expression $pattern = "#{lotterynumbers}(.*?){/lotterynumbers}#s"; if(isset($article->text)){ preg_match($pattern, $article->text, $matches); $numbers = explode("," , $matches[1]); foreach ($numbers as $number) { echo "<div class='number'><span>" . $number . "</span></div>"; } }else{ $article->text = 'No numbers'; } return true; } AMENDED CODE: function onPrepareContent( &$article, &$params, $limitstart ) { global $mainframe; // define the regular expression $pattern = "#{lotterynumbers}(.*?){/lotterynumbers}#s"; if(isset($article->text)){ preg_match($pattern, $article->text, $matches); $numbers = explode("," , $matches[1]); foreach ($numbers as $number) { $numberlist[] = "<div class='number'><span>" . $number . "</span></div>"; } $numberlist = implode("", $numberlist); $article->text = preg_replace($pattern, $numberlist, $article->text); }else{ $article->text = 'No numbers'; } return true; }

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  • how to check whether for each value in array is a numeric, alphabetical or alphanumeric (Perl)

    - by dexter
    i have array which values are user input like: aa df rrr5 4323 54 hjy 10 gj @fgf %d would be that array, now i want to check each value in array whether its numeric or alphabetic (a-zA-Z) or alphanumeric and save them in other respective arrays i have done: my @num; my @char; my @alphanum; my $str =<>; my @temp = split(" ",$str); foreach (@temp) { print "input : $_ \n"; if ($_ =~/^(\d+\.?\d*|\.\d+)$/) { push(@num,$_); } } this works, similarly i want to check for alphabet, and alphanumeric values note: alphanumeric ex. fr43 6t$ $eed5 *jh

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  • postgres - regex_replace in distinct clause?

    - by n00b0101
    Ok... changing the question here... I'm getting an error when I try this: SELECT COUNT ( DISTINCT mid, regexp_replace(na_fname, '\\s*', '', 'g'), regexp_replace(na_lname, '\\s*', '', 'g')) FROM masterfile; Is it possible to use regexp in a distinct clause like this? The error is this: WARNING: nonstandard use of \\ in a string literal LINE 1: ...CT COUNT ( DISTINCT mid, regexp_replace(na_fname, '\\s*', ''...

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  • How to with extract url from tweet using Regular Expressions

    - by neutreno
    Ok so i'm executing the following line of code in javascript RegExp('(http:\/\/t.co\/)[a-zA-Z0-9\-\.]{8}').exec(tcont); where tcont is equal to some string like 'Test tweet to http://t.co/GXmaUyNL' (the content of a tweet obtained by jquery). However it is returning, in the case above for example, 'http://t.co/GXmaUyNL,http://t.co/'. This is frustracting because I want the url without the bit on the end - after and including the comma. Any ideas why this is appearing? Thanks

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  • PHP Regular Expression

    - by saturngod
    I want to change &lt;lang class='brush:xhtml'&gt;test&lt;/lang&gt; to <pre class='brush:xhtml'>test</pre> my code like that. <?php $content="&lt;lang class='brush:xhtml'&gt;test&lt;/lang&gt;"; $pattern=array(); $replace=array(); $pattern[0]="/&lt;lang class=([A-Za-z='\":])* &lt;/"; $replace[0]="<pre $1>"; $pattern[1]="/&lt;lang&gt;/"; $replace[1]="</pre>"; echo preg_replace($pattern, $replace,$content); ?> but it's not working. How to change my code or something wrong in my code ?

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  • How can I split a string by whitespace unless inside of a single quoted string?

    - by Kivin
    I'm seeking a solution to splitting a string which contains text in the following format: "abcd efgh 'ijklm no pqrs' tuv" which will produce the following results: ['abcd', 'efgh', 'ijklm no pqrs', 'tuv'] In other words, it splits by whitespace unless inside of a single quoted string. I think it could be done with .NET regexps using "Lookaround" operators, particularly balancing operators. I'm not so sure about Perl.

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