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  • Wrap text around an image in rails and prawn

    - by stevenheidel
    I have a document with dynamic image and dynamic text and would like the text around the image. The image is right aligned on the landscape page. Here is what I have so far: pdf.bounding_box([0,pdf.bounds.top - 50], :width => pdf.bounds.width, :height => pdf.bounds.height-50) do pdf.text @article.title, :size => 30, :style => :bold pdf.text @article.content, :align => :left # image pdf.bounding_box([pdf.bounds.right - 250, pdf.bounds.top], :width => 250, :height => 250) do pdf.image image_path, :width => 250 end end The text goes right underneath the image. I tried doing this http://stackoverflow.com/questions/2085151/ruby-prawn-how-to-wrap-text-around-an-aligned-right-image but it didn't work. Help is appreciated, thanks.

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  • Counting the number of objects that meets a certain criteria

    - by Candy Chiu
    The title doesn't tell the complete story. Please read the message. I have two objects: Adult and Child. Child has a boolean field isMale, and a reference to Adult. Adult doesn't reference Child. public class Adult { long id; } public class Child { long id; boolean isMale; Adult parent; } I want to create a query to list the number of sons each adult has including adults who don't have any sons. I tried: Query 1 SELECT adult, COUNT(child) FROM Child child RIGHT OUTER JOIN child.parent as adult WHERE child.isMale='true' GROUP BY adult which translates to sql select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id where child.isMale = 'true' group by adult.id Query 1 doesn't pick up adults that don't have any sons. Query 2: SELECT adult, COUNT(child.isMale) FROM Child child RIGHT OUTER JOIN child.parent as adult GROUP BY adult translates to sql: select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id group by adult.id Query 2 doesn't have the right count of sons. Basically COUNT doesn't evaluate isMale. The where clause in Query 1 filtered out Adults with no sons. How do I build a HQL or a Criteria query for this use case? Thanks.

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  • parsing css measures

    - by david
    When i write a jQuery plugin i like to specify options for spacings the CSS way. I wrote a function that returns a CSS String as values in a object. 5px 10px returns top: 5px, right: 10px, bottom: 5px, left: 10px Now i often use the returned values to do some calculations and its not very nice to have to extract the measuring unit every time... I suck in writing regular expressions could someone help me complete this function: this.cssMeasure = function(cssString, separateUnits){ if ( cssString ){ var values = {} }else{ return errorMsg } var spacing = cssString.split(' ') var errorMsg = 'please format your css values correctly dude' if( spacing[4] || (spacing[2] && !spacing[3]) ) { return errorMsg } else if ( spacing[3] ) { values = {top: spacing[0], right:spacing[1], bottom:spacing[2], left:spacing[3]} } else if ( spacing[1] ) { values = {top: spacing[0], right:spacing[1], bottom:spacing[0], left:spacing[1]} } else { values = {top: spacing[0], right:spacing[0], bottom:spacing[0], left:spacing[0]} } if (separateUnits) { $.each(values, function(i, value){ /* at this place i need to extract the measuring unit of each value and return them separately something like top: {value: 10, unit: 'px'}, right: {bla} and so on */ }) } return values } if you have any idea how to improve this function i am open to your comments.

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  • UIView coordinate transforms on rotation during keyboard appearance

    - by SG
    iPad app; I'm trying to resize my view when the keyboard appears. It amounts to calling this code at appropriate times: CGRect adjustedFrame = self.frame; adjustedFrame.size.height -= keyboardFrame.size.height; [self setFrame:adjustedFrame]; Using this technique for a view contained in a uisplitview-based app works in all 4 orientations, but I've since discovered that a vanilla uiview-based app does not work. What happens is that apparently the uisplitview is smart enough to convert the coordinates of its subviews (their frame) such that the origin is in the "viewer's top left" regardless of the orientation. However, a uiview is not able to correctly report these coordinates. Though the origin is reported as (0,0) in all orientations, the view's effective origin is always as if the ipad were upright. What is weird about this is that the view correctly rotates and draws, but it always originates in the literal device top left. How can I get the view to correctly make its origin the "top left" to the viewer, not the device's fixed top left? What am I missing? Please, for something so trivial I've spent about 6 hours on this already with every brute force technique and research angle I could think of. This is the original source which doesn't work in this case: http://stackoverflow.com/questions/1951826/move-up-uitoolbar

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  • Can someone describe the nested set model from a C#/LINQ perspective?

    - by Chad
    I know the nested set model doesn't pertain to the C# language or LINQ directly... it's what I'm using to develop my web app. For hierarchical data (categories with sub-categories in my case), I'm currently using something similar to the Adjacency List model. At the moment, I've only got 2 levels of categories, but I'd like to take it further and allow for n levels of categories using the nested set model. I'm not quite clear on how to use it in a C# context. Here's the article I'm reading on the nested set model. Though this article cleared up my confusion some, I still have a big ?? in my head: - Is inserting, updating or deleting categories tedious? It looks like the left and right numbers would require re-numbering... what would the LINQ queries look like for the following scenarios? Delete a child node (re-number all node's left/right values) Delete a parent node (what do you do with the orphans?) Move a child node to a different parent node (renumber again) If my understanding is correct, at all times the child node's left/right values will always be between the parent node's left/right values, am I correct? Seems easy enough, if only the categories were static... most likely I need to spend more time to get my head around the concept. Any help is greatly appreciated!

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  • Table is centering by itself?

    - by user146780
    I have a page here: http://animactions.ca/Animactions/accueil.php and it has a right column. When the right column's content is longer than then the main content, the main content centers rather than start at the top despite I defining it in a style not to do so. From my style sheet: .tbsyles { margin: 0px; text-align: justify; width: 200px; border-left-style: solid; border-left-width: 1px; border-left-color: #A8CFE4; padding-left: 30px; height: 100%; line-height: 100%; vertical-align: top; padding-right: 0px; } .tablestylea { width: 900px; margin: 0px; text-align: justify; height: 100%; line-height: 100%; vertical-align: top; padding-right: 0px; } How can I make it so no matter what the length of my right col content the main content page resizes correctly and starts from the top rather than from the center? Thanks

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  • I'm having trouble with using std::stack to retrieve the values from a recursive function.

    - by Peter Stewart
    Thanks to the help I received in this post: http://stackoverflow.com/questions/2761918/how-do-i-use-this-in-a-member-function I have a nice, concise recursive function to traverse a tree in postfix order: void Node::postfix() { if (left != __nullptr) { left->postfix(); } if (right != __nullptr) { right->postfix(); } cout<<cargo<<"\n"; return; }; Now I need to evaluate the values and operators as they are returned. My problem is how to retrieve them. I tried the std::stack: #include <stack> stack <char*> s; void Node::postfix() { if (left != __nullptr) { left->postfix(); } if (right != __nullptr) { right->postfix(); } s.push(cargo); return; }; but when I tried to access it in main() while (!s.empty()) { cout<<s.top<<"\n"; s.pop; } I got the error: 'std::stack<_Ty::top': function call missing argument list; use '&std::stack<_Ty::top' to create a pointer to member' I'm stuck. Another question to follow shortly.

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  • Android custom xml widget

    - by DrogoNevets
    I have an XML file in my layout folder that has how i want my custom widget/view (not sure what correct terminology is here). but how do i make it so that i can programatically, add one or more to an activity the xml file is as follows <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="wrap_content" android:id="@+id/viewLog"> <TextView android:id="@+id/viewLogClimbName" android:layout_width="fill_parent" android:singleLine="true" android:ellipsize="end" android:gravity="left" /> <LinearLayout android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TextView android:id="@+id/viewLogDate" android:layout_width="fill_parent" android:singleLine="true" android:ellipsize="end" android:gravity="left" /> <TextView android:id="@+id/viewLogStyle" android:layout_width="fill_parent" android:singleLine="true" android:ellipsize="end" android:gravity="left" /> </LinearLayout> <TextView android:id="@+id/viewLogDetails" android:layout_width="fill_parent" android:layout_height="fill_parent" android:ellipsize="end" android:gravity="left" android:layout_weight="1" /> </LinearLayout> </LinearLayout> I have looked at the android how-to and dont really understand what its getting at

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  • How to create a Binary Tree from a General Tree?

    - by mno4k
    I have to solve the following constructor for a BinaryTree class in java: BinaryTree(GeneralTree<T> aTree) This method should create a BinaryTree (bt) from a General Tree (gt) as follows: Every Vertex from gt will be represented as a leaf in bt. If gt is a leaf, then bt will be a leaf with the same value as gt If gt is not a leaf, then bt will be constructed as an empty root, a left subTree (lt) and a right subTree (lr). Lt is a stric binary tree created from the oldest subtree of gt (the left-most subtree) and lr is a stric binary tree created from gt without its left-most subtree. The frist part is trivial enough, but the second one is giving me some trouble. I've gotten this far: public BinaryTree(GeneralTree<T> aTree){ if (aTree.isLeaf()){ root= new BinaryNode<T>(aTree.getRootData()); }else{ root= new BinaryNode<T>(null); // empty root LinkedList<GeneralTree<T>> childs = aTree.getChilds(); // Childs of the GT are implemented as a LinkedList of SubTrees child.begin(); //start iteration trough list BinaryTree<T> lt = new BinaryTree<T>(childs.element(0)); // first element = left-most child this.addLeftChild(lt); aTree.DeleteChild(hijos.elemento(0)); BinaryTree<T> lr = new BinaryTree<T>(aTree); this.addRightChild(lr); } } Is this the right way? If not, can you think of a better way to solve this? Thank you!

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  • iphone sdk: finding the direction of scrolling in UIScrollView

    - by Alex1987
    I have a UIScrollView with only horizontal scrolling allowed, and I would like to know which direction (left, right) the user scrolls. What I did was to subclass the UIScrollView and override the touchesMoved method: - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { [super touchesMoved:touches withEvent:event]; UITouch *touch = [touches anyObject]; float now = [touch locationInView:self].x; float before = [touch previousLocationInView:self].x; NSLog(@"%f %f", before, now); if (now > before){ right = NO; NSLog(@"LEFT"); } else{ right = YES; NSLog(@"RIGHT"); } } But this method sometimes doesn't get called at all when I move. What do you think?

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  • Extracting table rows with a particular attribute from an HTML File, using HTMLAgilityPack

    - by Soham
    Consider this html snippet: <tr> <td valign=top class="tim_new"><a href="/stocks/company_info/pricechart.php?sc_did=MI42" class="tim_new">3M India</a></td> <td class="tim_new" valign=top><a href='/stocks/marketstats/indcomp.php?optex=NSE&indcode=Diversified' class=tim>Diversified</a></td> <td class="tim_new" align=right valign=top>2,487.25</td> <td class="tim_new" align=right valign=top><font color=#16a903>187.25</font></td> <td class="tim_new" align=right valign=top><font color=#16a903>8.14</font></td> <td class="tim_new" align=right valign=top>2,801.90</td> <td class="tim_new" align=right valign=top>0.06</td> </tr> Realize these three things: The HTML file from which this snippet has been taken, contains multiple number of HTML tables. The table from which this snippet has been extracted doesnt contain only rows of the shown format, but also of other formats like this, for example: <tr><td colspan=7><img src="http://img1.moneycontrol.com/images/blank.gif"height="5"></td></tr>` This same table contains multiple rows of the format which I need to extract. So given this scenario, is it possible to run a code, which extracts, the link with the class name = "tim_new"? Help Appreciated, Soham

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  • Gradient a Parallelogram

    - by nuclearpenguin
    I'm working in JavaScript drawing on a canvas, and have four coordinates to draw a parallelogram, called A, B, C, and D starting from the top-left, top-right, bottom-left, and bottom right, respectively. An example of some coordinates might be: A: (3, 3) B: (4, 3) C: (1, 0) D: (2, 0) I can draw the parallelogram just fine, but I would like to fill it in with a gradient. I want the gradient to fill in from left to right, but matching the angle of the shape. The library I use (CAKE) requires a start and stop coordinate for the gradient. My stop and start would be somewhere half way between A and C, and end somewhere half way between B and D. Of course, it is not simply EXACTLY half way because the angles at A, B, C, and D are not right angles. So given this information (the coordinates), how to I find the point on the line A - C to start, and the point on the line B - D to stop? Remember, I'm doing this in JavaScript, so I have some good Math tools at my disposal for calculation.

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  • How to create a web-based Email Client in .NET?

    - by Blankman
    I am creating a web based email client in .NET using a 3rd party component. I just want to make sure I have the right idea: I will first pull the emails in using POP I will then parse each individual message that I got from POP using the MIME component right? My choices for 3rd party are: Nsoftware, Quiksoft or Dart. I am looking at Nsoftware right now though.

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  • Improve performance of searching JSON object with jQuery

    - by cale_b
    Please forgive me if this is answered on SO somewhere already. I've searched, and it seems as though this is a fairly specific case. Here's an example of the JSON (NOTE: this is very stripped down - this is dynamically loaded, and currently there are 126 records): var layout = { "2":[{"id":"40","attribute_id":"2","option_id":null,"design_attribute_id":"4","design_option_id":"131","width":"10","height":"10", "repeat":"0","top":"0","left":"0","bottom":"0","right":"0","use_right":"0","use_bottom":"0","apply_to_options":"0"}, {"id":"41","attribute_id":"2","option_id":"115","design_attribute_id":"4","design_option_id":"131","width":"2","height":"1", "repeat":"0","top":"0","left":"0","bottom":"4","right":"2","use_right":"0","use_bottom":"0","apply_to_options":"0"}, {"id":"44","attribute_id":"2","option_id":"118","design_attribute_id":"4","design_option_id":"131","width":"10","height":"10", "repeat":"0","top":"0","left":"0","bottom":"0","right":"0","use_right":"0","use_bottom":"0","apply_to_options":"0"}], "5":[{"id":"326","attribute_id":"5","option_id":null,"design_attribute_id":"4","design_option_id":"154","width":"5","height":"5", "repeat":"0","top":"0","left":"0","bottom":"0","right":"0","use_right":"0","use_bottom":"0","apply_to_options":"0"}] }; I need to match the right combination of values. Here's the function I currently use: function drawOption(attid, optid) { var attlayout = layout[attid]; $.each(attlayout, function(k, v) { // d_opt_id and d_opt_id are global scoped variable set elsewhere if (v.design_attribute_id == d_att_id && v.design_option_id == d_opt_id && v.attribute_id == attid && ((v.apply_to_options == 1 || (v.option_id === optid)))) { // Do stuff here } }); } The issue is that I might iterate through 10-15 layouts (unique attid's), and any given layout (attid) might have as many as 50 possibilities, which means that this loop is being run A LOT. Given the multiple criteria that have to be matched, would an AJAX call work better? (This JSON is dynamically created via PHP, so I could craft a PHP function that could possibly do this more efficently), or am I completely missing something about how to find items in a JSON object? As always, any suggestions for improving the code are welcome! EDIT: I apologize for not making this clear, but the purpose of this question is to find a way to improve the performance. The page has a lot of javascript, and this is a location where I know that performance is lower than it could be.

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  • Rails CSS not Loading using Heroku

    - by eWizardII
    I have the following site set up here on Heroku - http://www.peerinstruction.net/users/sign_up the issue is that I have updated the css yet it is not being actively reflected on the site, it just shows a textbox, with some edited/custom fonts. I have attached the css file in the following gist - https://gist.github.com/f74b626c54ecbb60bbde The signup page controller: !!! Strict %html %head %title= yield(:title) || "Untitled" = stylesheet_link_tag 'application', 'web-app-theme/base', 'web-app-theme/themes/activo/style', 'web-app-theme/override' = javascript_include_tag :defaults = csrf_meta_tag = yield(:head) %body #container #header %h1 %a{:href => "/"} Peer Instruction Network #user-navigation %ul.wat-cf %li .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => session_path(resource_name), :html => { :class => "form login" }) do |f| .group.wat-cf .left= f.label :email, :class => "label right" .right= f.text_field :email, :class => "text_field" .group.wat-cf .left= f.label :password, :class => "label right" .right= f.password_field :password, :class => "text_field" .group.wat-cf .right %button.button{ :type => "submit" } Login /= link_to "Sign In", destroy_user_session_path #box = yield The signup pages haml file: %h2 .block .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => registration_path(resource_name)) do |f| = devise_error_messages! %div = f.label :firstname %br/ = f.text_field :firstname %div = f.label :middlename %br/ = f.text_field :middlename %div = f.label :lastname %br/ = f.text_field :lastname %div = f.label :email %br/ = f.email_field :email %div = f.label :password %br/ = f.password_field :password %div = f.label :academic %br/ = f.text_field :academic %div= f.submit "Continue" = render :partial => "devise/shared/links" I used web-app-theme to create an activo theme and then modify it.

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  • Returning recursive ternary freaks out

    - by David Titarenco
    Hi, assume this following function: int binaryTree::findHeight(node *n) { if (n == NULL) { return 0; } else { return 1 + max(findHeight(n->left), findHeight(n->right)); } } Pretty standard recursive treeHeight function for a given binary search tree binaryTree. Now, I was helping a friend (he's taking an algorithms course), and I ran into some weird issue with this function that I couldn't 100% explain to him. With max being defined as max(a,b) ((a)>(b)?(a):(b)) (which happens to be the max definition in windef.h), the recursive function freaks out (it runs something like n^n times where n is the tree height). This obviously makes checking the height of a tree with 3000 elements take very, very long. However, if max is defined via templating, like std does it, everything is okay. So using std::max fixed his problem. I just want to know why. Also, why does the countLeaves function work fine, using the same programmatic recursion? int binaryTree::countLeaves(node *n) { if (n == NULL) { return 0; } else if (n->left == NULL && n->right == NULL) { return 1; } else { return countLeaves(n->left) + countLeaves(n->right); } } Is it because in returning the ternary function, the values a => countLeaves(n->left) and b => countLeaves(n->right) were recursively double called simply because they were the resultants? Thank you!

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  • Mixing a4 and a3 in one Latex file

    - by jorgusch
    Hello, I am finishing my thesis and have a large appendix. Some tables only look good, if first done on a3 and then (paper)printed on a4. Anyhow, working all the files seperalty is fine, but I struggle to compile all in one. I use the geometry package and start the document with: \usepackage[a4paper,left=30mm,right=20mm,top=20mm, bottom=20mm]{geometry} For the appendix, I want to include the table and use \newgeometry{a3paper,left=25mm,right=15mm, top=15mm, bottom=15mm} However, the command is completely ignored and I can read "a3paper,left=25mm,right=15mm, top=15mm, bottom=15mm" above the table. What did I miss? Is it even possible? If not, how do I get the numbers right, if I have to include it as a pdf (which works)? Thanks!

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  • Windows Screensaver Multi Monitor Problem

    - by Bryan
    I have a simple screensaver that I've written, which has been deployed to all of our company's client PCs. As most of our PCs have dual monitors, I took care to ensure that the screensaver ran on both displays. This works fine, however on some systems, where the primary screen has been swapped (to the left monitor), the screensaver only works on the left (primary) screen. The offending code is below. Can anyone see anything I've done wrong, or a better way of handling this? For info, the context of "this", is the screensaver form itself. // Make form full screen and on top of all other forms int minY = 0; int maxY = 0; int maxX = 0; int minX = 0; foreach (Screen screen in Screen.AllScreens) { // Find the bounds of all screens attached to the system if (screen.Bounds.Left < minX) minX = screen.Bounds.Left; if (screen.Bounds.Width > maxX) maxX = screen.Bounds.Width; if (screen.Bounds.Bottom < minY) minY = screen.Bounds.Bottom; if (screen.Bounds.Height > maxY) maxY = screen.Bounds.Height; } // Set the location and size of the form, so that it // fills the bounds of all screens attached to the system Location = new Point(minX, minY); Height = maxY - minY; Width = maxX - minX; Cursor.Hide(); TopMost = true;

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  • Monads and custom traversal functions in Haskell

    - by Bill
    Given the following simple BST definition: data Tree x = Empty | Leaf x | Node x (Tree x) (Tree x) deriving (Show, Eq) inOrder :: Tree x -> [x] inOrder Empty = [] inOrder (Leaf x) = [x] inOrder (Node root left right) = inOrder left ++ [root] ++ inOrder right I'd like to write an in-order function that can have side effects. I achieved that with: inOrderM :: (Show x, Monad m) => (x -> m a) -> Tree x -> m () inOrderM f (Empty) = return () inOrderM f (Leaf y) = f y >> return () inOrderM f (Node root left right) = inOrderM f left >> f root >> inOrderM f right -- print tree in order to stdout inOrderM print tree This works fine, but it seems repetitive - the same logic is already present in inOrder and my experience with Haskell leads me to believe that I'm probably doing something wrong if I'm writing a similar thing twice. Is there any way that I can write a single function inOrder that can take either pure or monadic functions?

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  • Combo box in a scrollable panel causing problems

    - by Dennis
    I have a panel with AutoScroll set to true. In it, I am programmatically adding ComboBox controls. If I add enough controls to exceed the viewable size of the panel a scroll bar appears (so far so good). However, if I open one of the combo boxes near the bottom of the viewable area the combo list isn't properly displayed and the scrollable area seems to be expanded. This results in all of the controls being "pulled" to the new bottom of the panel with some new blank space at the top. If I continue to tap on the drop down at the bottom of the panel the scrollable area will continue to expand indefinitely. I'm anchoring the controls to the left, right and top so I don't think anchoring is involved. Is there something obvious that could be causing this? Update: It looks like the problem lies with anchoring the controls to the right. If I don't anchor to the right then I don't get the strange behavior. However, without right anchoring the control gets cut off by the scroll bar. Here's a simplified test case I built that shows the issue: public Form1() { InitializeComponent(); Panel panel = new Panel(); panel.Size = new Size(80, 200); panel.AutoScroll = true; for (int i = 0; i < 10; ++i) { ComboBox cb = new ComboBox(); cb.Anchor = AnchorStyles.Left | AnchorStyles.Right | AnchorStyles.Top; cb.Items.Add("Option 1"); cb.Items.Add("Option 2"); cb.Items.Add("Option 3"); cb.Items.Add("Option 4"); cb.Location = new Point(0, i * 24); panel.Controls.Add(cb); } Controls.Add(panel); } If you scroll the bottom of the panel and tap on the combo boxes near the bottom you'll notice the strange behavior.

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  • RightBarButtonItem in iphone

    - by venkat
    hello all. i am using navigation control with left and right bar buttons.my right side bar button contains length of 10 chars. And my title contains 12 chars. when i press the right bar button my title is moving.how can i stop moving the title when clicking button.

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  • Improving SQL Code

    - by jeremib
    I'm using Pervasive SQL. I have the following UNION of mulitple SQL statements. Is there a way to clean this up, especially the Pay Date an the Loc No fields that are selected in each statement. Is there a way to pull this out and have only one place to need to change those two fields? ( SELECT '23400' as Gl_Number, y.Plan as Description, 0 as Hours, ROUND(SUM(Ee_Curr),2) as Debit, 0 as Credit FROM "PR_YLOC" y LEFT JOIN PR_SUMM s ON (s.Summ_No = y.Summ_No) WHERE y.Loc_No = 1041 AND s.Pay_Date = '2010-04-02' AND y.Code IN (100, 105, 110) AND y.Type = 3 GROUP BY y.Plan ) UNION ( SELECT '72000' as Gl_Number, y.Plan, 0, ROUND(SUM(Er_Curr),2), 0 FROM "PR_YLOC" y LEFT JOIN PR_SUMM s ON (s.Summ_No = y.Summ_No) WHERE y.Loc_No = 1041 AND s.Pay_Date = '2010-04-02' AND y.Code IN (100, 105, 110) AND y.Type = 3 GROUP BY y.Plan ) UNION ( SELECT '24800', c.Plan, 0, ROUND(SUM(Ee_Amt),2), 0 FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 100 GROUP BY c.Plan ) UNION ( SELECT '24800', c.Plan, 0, 0, ROUND(SUM(Ee_Amt),2) FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 115 GROUP BY c.Plan ) UNION ( SELECT '24150', c.Plan, 0, 0, ROUND(SUM(Ee_Amt),2) FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 241 GROUP BY c.Plan ) UNION ( SELECT '24150', c.Plan, 0, ROUND(SUM(Ee_Amt),2), 0 FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 239 GROUP BY c.Plan ) UNION ( SELECT '24120', c.Plan, 0, ROUND(SUM(Ee_Amt),2), 0 FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 230 GROUP BY c.Plan ) UNION ( SELECT '24100', c.Plan, 0, ROUND(SUM(Ee_Amt),2), 0 FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 225 GROUP BY c.Plan ) UNION ( SELECT '23800', c.Plan, 0, ROUND(SUM(Ee_Amt),2), 0 FROM "PR_CDED" c WHERE Pay_Date = '2010-04-02' AND Loc_No = 1041 AND Code = 245 GROUP BY c.Plan ) UNION ( select m.Def_Dept as Gl_Number, t.Short_Desc, (SELECT SUM(Hours) FROM pr_earn en WHERE en.Loc_No = e.Loc_No AND en.Emp_No = e.Emp_No AND en.Pay_Date = e.Pay_Date AND en.Pay_Code = e.Pay_Code) as Hours, (SELECT SUM(Pay_Amt) FROM pr_earn en WHERE en.Loc_No = e.Loc_No AND en.Emp_No = e.Emp_No AND en.Pay_Date = e.Pay_Date AND en.Pay_Code = e.Pay_Code) as Debit, 0 from pr_earn e left join pr_mast m on (e.Loc_No = m.Loc_No and e.Emp_No = m.Emp_No) left join pr_ptype t ON (t.Code = e.Pay_Code) where e.loc_no = 1041 and e.pay_date = '2010-04-02' group by m.Def_Dept, t.Short_Desc ) Thanks

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  • java.bigDecimal divide in ruby environment

    - by Eyal
    I right script in Ruby that include java classes require 'java' include_class 'java.math.BigDecimal' include_class 'java.math.RoundingMode' during the script I need to divide 2 java.bigDecimal one = BigDecimal.new("1") number1 = BigDecimal.new("3") number1 = one.divide(number1,RoundingMode.new(HALF_EVEN)) since I don't have intellisense in this IDE I'm not sure the syntax is right and the runtime error is: uninitialized constant::HALF_EVEN do I combine java object in the ruby scrpit in the right way? how should I divide two java.bigDecimal object in ruby env?

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  • Some jQuery-powered features not working in Chrome

    - by Enchantner
    I'm using a jCarouselLite plugin for creating two image galleries on the main page of my Django-powered site. The code of elements with navigation arrows is generating dynamically like this: $(document).ready(function () { $('[jq\\:corner]').each(function(index, item) { item = $(item); item.corner(item.attr('jq:corner')) }) $('[jq\\:menu]').each(function (index, item) { item = $(item); item.menu(item.attr('jq:menu')) }) $('[jq\\:carousel]').each(function(index, item) { item = $(item); var args = item.attr('jq:carousel').split(/\s+/) lister = item.parent().attr('class') + '_lister' item.parent().append('<div id="'+ lister +'"></div>'); $('#' + lister).append("<a class='nav left' href='#'></a><a class='nav right' href='#'></a>"); toparrow = $(item).position().top + $(item).height() - 50; widtharrow = $(item).width(); $('#' + lister).css({ 'display': 'inline-block', 'z-index': 10, 'position': 'absolute', 'margin-left': '-22px', 'top': toparrow, 'width': widtharrow }) $('#' + lister + ' .nav.right').css({ 'margin-left': $('#' + lister).width() + 22 }) item.jCarouselLite({ btnNext: '#' + lister + ' .nav.right', btnPrev: '#' + lister + ' .nav.left', visible: parseInt(args[0]) }) }) The problem is that if page is loaded through an url, typed in the adress bar, some functions doesn't work and the second gallery appears with the wrong parameters, but if I came to this page via clicking link - everything works perfectly. It happends only in Google Chrome (Ubuntu, stable 5.0.360.0), but not in Firefox or Opera. What could be the reason?

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  • Table cell in a split-view controller - selected cell becomes deselected when called by reloadData

    - by bpapa
    I'm working on a universal app that uses a SplitViewController to present a master-detail view. In the iPad HIG on Split Views, Apple states: In general, indicate the current selection in the left pane in a persistent way. This behavior helps people understand the relationship between the item in the left pane and the contents of the right pane. This is important because the contents of the right pane can change, but they should always remain related to the item selected in the left pane. So I'm trying to maintain selection state on the left. Easy enough when the user taps, I just remove the deselectRowAtIndexPath:animated: message from tableView:didSelectRowAtIndexPath: implementation. But, I also want the selection state to show up by default (without a user tap). I wound up putting this in my tableView:cellForRowAtIndexPath: implementation: if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) { if (cellShouldBeSelected) cell.selected = YES; else cell.selected = NO; } The behavior I'm seeing, is that when the cells finall appear, for a fraction of a section the cell is indeed selected, but then the selection disappears without any user interaction. Any ideas? I set the new clearsSelectionOnViewWillAppear property to NO, but that doesn't seem to fix it, and it shouldn't really matter because I'm marking the cell as selected long after viewWillAppear is called - I'm actually doing it after some network activity and then sending the table view a reloadData message.

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