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  • What needs to be passed to an editor from a keyboard app to move the cursor one char left?

    - by yno
    What key code does an Android editor app expect the keyboard app to send when it is going to be interpreted as a left arrow? In other words, what is the keyboard program supposed to send to its calling program (some kind of editor) if the user intends to move the cursor one char to the left? A related issue: what do the minus values for the "android:codes" attribute mean? () Any pointers to these issues will be appreciated.

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  • using jQuery .animate to animate a div from right to left?

    - by Alex
    Hi, I have a div absolutely positioned at top: 0px and right: 0px, and I would like to use jquery's .animate() to animate it from it's current position to left: 0px. How does one do this? I can't seem to get this to work: $("#coolDiv").animate({"left":"0px"}, "slow"); Why doesn't this work and how does one accomplish what I am looking to do? Thanks!!

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  • mysql : possible to put IF statment in LEFT JOIN ?

    - by Haroldo
    Ok so i want to get an artists info from the db, but i want to know if they have any forthcoming events. To do this i need to traverse 2 tables, where events_artists is a 2 col link table... (this doesnt work but is what id like to do) SELECT art.*, events.event_id FROM art LEFT JOIN events_artists ON art.art_id = events_artists.art_id LEFT JOIN events ON events_artists.event_id = events.event_id IF ( {criteria} ) what should i be doing here to get this to work?!!

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  • Responsive WordPress Theme Eleven40 by Studiopress

    - by Edward
    Eleven40 is a responsive layout premium WordPress child theme by StudioPress for the Genesis Framework. The theme is a crisp & clean layout that extends upto 1140 pixels in width with sixe other narrower content layouts in its responsive layout. Eleven40 theme pack include 4 colour schemes, six post / page layout options, custom menus [...] Related posts:Genesis WordPress Theme Framework Beveled Premium WordPress Theme by Woothemes PhotoNote WordPress Theme by WPZOOM

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  • How can text be set on both the left and right sides of a line in Word?

    - by Lord Torgamus
    Is it possible to set Microsoft Word to display some text left-aligned and other text right-aligned on a single line? Here's an example of what I mean: | Chickens, turkey and duck 30 | | Cows 240 | | Pigs and boar 83 | | Sheep Not applicable | where the vertical lines denote the sides of the page. The full justify option won't work because I don't want anything in the middle of the lines. The table of contents option has the formatting I want, but only supports page numbers, which does me no good.

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  • Why does the mouse always move to the bottom left?

    - by AngryHacker
    In the course of doing stuff on the computer, the mouse always moves, by itself, to the bottom left of the screen - I'd say several times in the course of an hour. I thought this might be an issue with the driver, so I re-installed the driver, but the problem continued. Then thinking that the mouse is faulty, I replaced my Microsoft Wheel Mouse with a Dell mouse. The problem still continues. How can I fix this problem?

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  • css, unordered list not displaying icon in right place...

    - by Ronedog
    I'm really frustrated with this one. A few weeks ago I got it working in both firefox and ie just fine. Went back today to do some testing and found a problem with the display in firefox and I've been searching the code but can't find anything. I could use a few tips from anyone willing, I'm sure I'm looking at the wrong things. I upgraded my firefox version but I imagine my code is broke, not firefox. I'm assuming the problem is somewhere in my css file, but I'm not sure. Here's what I've confirmed so far. There don't seem to be conflicts in other css files with < ul 's or < li 's that may be overriding settings. The other confirmation is that This works fine in Internet Explorer...therefore I must be an idiot, because its usually been the other way around (working in FF, but failing in IE). Here's How it looks in IE (Notice the position of the folder icon right next to the text): Here's how it looks in FF (Notice the folder icon is not being pushed down with its corresponding text). Here's the Unordered List: <ul id="nav"> <li><a>Utah</a></li> <ul> <li><a>ParkCity</a> <ul> <li><a>Com1</a></li> <ul> <li class="folder_closed"><a>Timber</a></li> <div>SQUARE CONTAINER IS INSIDE THIS DIV</div> </ul> </ul> </ul> </ul> Here's the CSS that is used for the whole menu: /* MENU NAVIGATION (<UL><LI> LISTS ****************************************/ ul#nav{ /* This handles the main root <ul> */ margin-left:0; margin-right:0; padding-left:0px; text-indent:15px; } ul#nav div{ overflow: hidden; } #nav li>a:hover { cursor: pointer; } #nav li > ul{ /* This will hide any element with an id of "nav" and an "li" that has a direct child that is a "ul" */ display:none; margin-left:0px; margin-right:0px; padding-left:15px; padding-right:0px; text-indent:15px; } #nav li { list-style-type:none; list-style-image: none; } #nav > li{ vertical-align: top; left:0px; text-align:left; clear: both; margin:0px; margin-right:0px; padding-right:0px; } .menu_parent{ background-image: url(../images/maximize.png); background-repeat: no-repeat; background-position: 0px 1px; position:relative; } .menu_parent_minimized{ background-image: url(../images/minimize.png); background-repeat: no-repeat; background-position: 0px 1px; position:relative; } .folder_closed{ position:relative; background-image: url(../images/folder_closed12x14.png); background-repeat: no-repeat; background-position: 0px -2px; } .folder_open{ position:relative; background-image: url(../images/folder_open12x14.png); background-repeat: no-repeat; background-position: 0px -2px; } </ul>

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  • embedding layout inside each tab? - (each tab has its own activity)

    - by Abhi
    I have started with the HelloTabwidget example and it works fine. Now what I am trying to do is have a layout inside each tab. here is what the code looks like myApp extends TabActivity { TabHost tabHost; onCreate() { setContentView (R.layout.main); tabHost = getTabHost(); TabHost.tabspec spec = tabHost.newTabSpec(..).setIndicator(...). setContent(new Intent().setClass(...)); tabHost.addTab(spec); : } } myTab1Actvity extends Activity { ListView myLV; EditText myET; onCreate() { setcontentView (TAB1_LAYOUT); myLV = findViewById(..); : myLV.setAdapter(aa); myET.setOnKeyListener(....) registerforContextMenu(myLV) } } when I run here is the stack trace ERROR/AndroidRuntime(691): java.lang.NullPointerException ERROR/AndroidRuntime(691): at android.widget.TabHost.dispatchWindowFocusChanged(TabHost.java:295) ERROR/AndroidRuntime(691): at android.view.ViewGroup.dispatchWindowFocusChanged(ViewGroup.java:661) ERROR/AndroidRuntime(691): at android.view.ViewGroup.dispatchWindowFocusChanged(ViewGroup.java:661) ERROR/AndroidRuntime(691): at android.widget.TabHost.dispatchWindowFocusChanged(TabHost.java:295) ERROR/AndroidRuntime(691): at android.view.ViewGroup.dispatchWindowFocusChanged(ViewGroup.java:661) ERROR/AndroidRuntime(691): at android.view.ViewGroup.dispatchWindowFocusChanged(ViewGroup.java:661) ERROR/AndroidRuntime(691): at android.view.ViewGroup.dispatchWindowFocusChanged(ViewGroup.java:661) ERROR/AndroidRuntime(691): at android.view.ViewRoot.handleMessage(ViewRoot.java:1819) ERROR/AndroidRuntime(691): at android.os.Handler.dispatchMessage(Handler.java:99) ERROR/AndroidRuntime(691): at android.os.Looper.loop(Looper.java:123) ERROR/AndroidRuntime(691): at android.app.ActivityThread.main(ActivityThread.java:4363) ERROR/AndroidRuntime(691): at java.lang.reflect.Method.invokeNative(Native Method) ERROR/AndroidRuntime(691): at java.lang.reflect.Method.invoke(Method.java:521) ERROR/AndroidRuntime(691): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:860) ERROR/AndroidRuntime(691): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:618) Does the code's flow look OK? basically each Tab has its own activity and each tab has its own layout. It appears that something is wrong in the TabHost - but I am unable to pinpoint it. Any suggestions/Qs you hav e will be very helpful.

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  • In Sharepoint I need to include a preview image for the screen of selecting layout for a new page.

    - by netadictos
    In Sharepoint 2007, I have created a layout. As you know when the user creates a page he chooses a layout from a listbox. When you select a different element in the listbox, there is a preview image that changes on the left. I thought this was controlled by the node PublishingPreviewImage in the xml of the layout. I have verified that the image exists in that place. It is not working. The code I use is: <File Path="TituloTextoCtrl.aspx" Url="TituloTextoCtrl.aspx" Type="GhostableInLibrary" IgnoreIfAlreadyExists ="TRUE"> <Property Name="PublishingPreviewImage" Value="~SiteCollection/_catalogs/masterpage/$Resources:core,Culture;/Preview Images/titulotextoctrl.png, ~SiteCollection/_catalogs/masterpage/$Resources:core,Culture;/Preview Images/titulotextoctrl.png" /> <Property Name="MasterPageDescription" Value="Plantilla Titulo+Texto+Control" /> <Property Name="ContentType" Value="Titulo+Texto+Control" /> <Property Name="PublishingAssociatedContentType" Value=";#Vialibre_ContentTypeGeneral;#0x010100C568DB52D9D0A14D9B2FDCC96666E9F2007948130EC3DB064584E219954237AF39005215cca003b74e479baa123eb1dc5702;#" /> </File>

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  • does log4net AdoNetAppender support sql server 2008?

    - by schrodinger's code
    my config file below: very strange, i have spent a day to find out where i am wrong, but still not working, it still not log anything in the database,but i can output them using RollingFileAppender. Also, the store procedure WriteLog is working well.(I have tested it using sql server studio). I have tried to change the connectionType but not working. Unfortunately I dont have sql server 2000/2005 to test, my log4net version should be the latest one: log4net 1.2.10. Any help is appreciated. <?xml version="1.0" encoding="utf-8"?> <configuration> <configSections> <section name="log4net" type="log4net.Config.Log4NetConfigurationSectionHandler, log4net" /> </configSections> <log4net> <appender name="AdoNetAppender_SqlServer" type="log4net.Appender.AdoNetAppender"> <!--<threshold value="OFF" />--> <bufferSize value="1" /> <connectionType value="System.Data.SqlClient.SqlConnection, System.Data, System.Data, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" /> <!--<connectionType value="System.Data.SqlClient.SqlConnection, System.Data, Version=1.0.3300.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" />--> <connectionString value="Data Source=.\MSSQLSERVER2008,2222;Initial Catalog=UnleashedSaaS;User ID=sa;Password=dogblack;" /> <commandType value="StoredProcedure" /> <commandText value="WriteLog" /> <parameter> <parameterName value="@log_date" /> <dbType value="DateTime" /> <layout type="log4net.Layout.PatternLayout" value="%date{yyyy'-'MM'-'dd HH':'mm':'ss'.'fff}" /> </parameter> <parameter> <parameterName value="@thread" /> <dbType value="String" /> <size value="255" /> <layout type="log4net.Layout.PatternLayout" value="%thread" /> </parameter> <parameter> <parameterName value="@log_level" /> <dbType value="String" /> <size value="50" /> <layout type="log4net.Layout.PatternLayout" value="%level" /> </parameter> <parameter> <parameterName value="@logger" /> <dbType value="String" /> <size value="255" /> <layout type="log4net.Layout.PatternLayout" value="%logger" /> </parameter> <parameter> <parameterName value="@message" /> <dbType value="String" /> <size value="4000" /> <layout type="log4net.Layout.PatternLayout" value="%message" /> </parameter> <parameter> <parameterName value="@exception" /> <dbType value="String" /> <size value="4000" /> <layout type="log4net.Layout.ExceptionLayout" /> </parameter> </appender> <appender name="RollingLogFileAppender" type="log4net.Appender.RollingFileAppender" > <!--<threshold value="OFF" />--> <file value="LogData\\" /> <appendToFile value="true" /> <datePattern value="ul_yyyy-MM-dd.LOG" /> <maxSizeRollBackups value="10" /> <rollingStyle value="Date" /> <maximumFileSize value="2MB" /> <staticLogFileName value="false" /> <layout type="log4net.Layout.PatternLayout"> <param name="ConversionPattern" value="%d{yyyy-MM-dd HH:mm:ss} %p %u %c %l %m %n%n%n" /> </layout> </appender> <root> <level value="ALL"/> <appender-ref ref="AdoNetAppender_SqlServer" /> <appender-ref ref="RollingLogFileAppender" /> </root> </log4net> </configuration>

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  • Is there a workaround to the disappearing Perl/Tk text widget scrollbar for right justified content?

    - by Streamline
    I've come across a bug I believe in Perl/Tk 804.027 Text Widget (using Scrollable('ROText')). When I add a tag that selects all and apply the configuration change to justify to the right, the scrollbars do not show up. If I comment out the tagConfigure where I justify to the right, the scrollbars come back. Does anyone have a workaround or fix for being able to right justify a text widget's contents (includes text and embedded entry widgets) and still have functional horizontal scrollbars?

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  • iPhone - Have the keyboard slide into view from the right like when editing a note in Contacts

    - by Toon Van Acker
    Hello, I'm looking for a way to slide the keyboard into view from the right, like what happens in the Contacts application when you edit a note. My problem is that when I call [someTextView becomeFirstResponder] in viewWillAppear, the keyboard immediatly pops up with no animation. And when I call it in viewDidAppear, the view first slides in from the right (UINavigationController does the sliding), and then the keyboard slides in from the bottom. Is it possible to have the keyboard slide in from the right, together with the view?

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  • How do I make a suckerfish/superfish CSS dropdown that sticks to the right hand side of the page?

    - by joeforker
    I am developing a CSS dropdown menu based on the suckerfish CSS. I would like to put it on the right hand side of the page but the menus extend from the leftmost edge of each menu to the right, instead of from the rightmost edge of each menu to the left (as is necessary to keep the rightmost dropdown menu from opening outside the visible area.) How do I position my suckerfish dropdown menus to extend to the left, instead of the right?

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  • SplitView Controller portrait mode- Top button keeps shifting to right.

    - by nishantcm
    Hi, I am using SplitViewController in ipad. On a button click from detail view, I open a modalview which is in full screen mode. Whenever I dismiss the modal view, the button which displays the table view in portrait mode shifts to the right. If I continue the process of opening the modal view and dismissing it, it keeps moving to the right until it disappears to the right of the screen. Any idea why this is happening?

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  • Am I getting the right memory for my motherboard?

    - by Daniel Carvalho
    Hi technophiles; I have a Gigabyte GA-EP45-DS motherboard. Also, the memory that came with my computer was two Transcend aXe RAM 1066MHZ 1GB modules. The thing is, I noticed that my motherboard has "DDR2 1200" written on it. This concerns me, have I bought slower memory than my computer is supposed to have ideally? Now, I'm not super concerned at a granular level about the best optimal RAM with the best CAS latency etc... but I do hope at least that I've got the right speed. Now, as far as I know, there is no such thing as ram at 1200MHZ? Am I right? You see, because I'm thinking of getting more RAM now, before I can't find the same type or speed any-more and just want to make sure it's the right thing. Furthermore, if the memory is slower than what I should be getting for my motherboard, what RAM should I be getting, and will that new RAM play nice with my old RAM? If I get new RAM at a different speed, would it be better / more beneficial performance-wise to omit the old RAM because of how the whole DUAL channel RAM thing works? I'm not too clued up on this area. Thanks chiefs.

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  • back button android

    - by Raogrimm
    i am having trouble implementing the back button properly. all of the code snippets i have seen have not worked for me. what i am trying to do when i press the back button is just go back to the previous list. pretty much i have a list within a list and i just want it to go back to the previous list. how would i go about doing this? this is the list i have, every item has a separate list that it has. lets say you click on weapons, you then get a list of different weapon types and so on final String[] weapons = getResources().getStringArray(R.array.weapons); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, weapons)); lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { System.out.println("item clicked: "+weapons[position]); switch(position) { case 0: final String[] axes = getResources().getStringArray(R.array.axes); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, axes)); break; case 1: final String[] clubs = getResources().getStringArray(R.array.clubs); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, clubs)); break; case 2: final String[] daggers = getResources().getStringArray(R.array.daggers); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, daggers)); break; case 3: final String[] great_axes = getResources().getStringArray(R.array.great_axes); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, great_axes)); break; case 4: final String[] great_katana = getResources().getStringArray(R.array.great_katana); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, great_katana)); break; case 5: final String[] great_swords = getResources().getStringArray(R.array.great_swords); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, great_swords)); break; case 6: final String[] hand_to_hand = getResources().getStringArray(R.array.hand_to_hand); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, hand_to_hand)); break; case 7: final String[] katana = getResources().getStringArray(R.array.katana); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, katana)); break; case 8: final String[] polearms = getResources().getStringArray(R.array.polearms); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, polearms)); break; case 9: final String[] scythes = getResources().getStringArray(R.array.scythes); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, scythes)); break; case 10: final String[] staves = getResources().getStringArray(R.array.staves); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, staves)); break; case 11: final String[] swords = getResources().getStringArray(R.array.swords); setListAdapter(new ArrayAdapter<String>(ffxidirectory.this, R.layout.list_item, swords)); break; } } });

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  • Permuting a binary tree without the use of lists

    - by Banang
    I need to find an algorithm for generating every possible permutation of a binary tree, and need to do so without using lists (this is because the tree itself carries semantics and restraints that cannot be translated into lists). I've found an algorithm that works for trees with the height of three or less, but whenever I get to greater hights, I loose one set of possible permutations per height added. Each node carries information about its original state, so that one node can determine if all possible permutations have been tried for that node. Also, the node carries information on weather or not it's been 'swapped', i.e. if it has seen all possible permutations of it's subtree. The tree is left-centered, meaning that the right node should always (except in some cases that I don't need to cover for this algorithm) be a leaf node, while the left node is always either a leaf or a branch. The algorithm I'm using at the moment can be described sort of like this: if the left child node has been swapped swap my right node with the left child nodes right node set the left child node as 'unswapped' if the current node is back to its original state swap my right node with the lowest left nodes' right node swap the lowest left nodes two childnodes set my left node as 'unswapped' set my left chilnode to use this as it's original state set this node as swapped return null return this; else if the left child has not been swapped if the result of trying to permute left child is null return the permutation of this node else return the permutation of the left child node if this node has a left node and a right node that are both leaves swap them set this node to be 'swapped' The desired behaviour of the algoritm would be something like this: branch / | branch 3 / | branch 2 / | 0 1 branch / | branch 3 / | branch 2 / | 1 0 <-- first swap branch / | branch 3 / | branch 1 <-- second swap / | 2 0 branch / | branch 3 / | branch 1 / | 0 2 <-- third swap branch / | branch 3 / | branch 0 <-- fourth swap / | 1 2 and so on... Sorry for the ridiculisly long and waddly explanation, would really, really apreciate any sort of help you guys could offer me. Thanks a bunch!

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  • Float right is making background-color disappear in IE while hovering.

    - by janoChen
    Everything works OK in this language menu: http://alexchen.co.nr/beta (top right of the page). But I want the li elements to float to the right. But when I add float:right to #lang li a the background-color stop working while hovering when I hover them in IE7. #lang { float: right; padding: 50px 25px 0 0px; margin: 0 0 0 0px; width: 295px; } #lang li { font-size: 10px; width: 325px; /*ie hack */ } #lang li a { color: #FFF; padding: 5px 25px 5px 249px; line-height: 220%; } #lang li a:hover { color: #444; background-color: #FFF; } #lang li.current a { color: #444; background-color: #FFF; cursor: default; }

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  • WPF problem modify style of images in multiple Button Templates

    - by user556415
    I'm trying to create a control panel for a video camera, the panel has buttons for up, down, left and right etc. Each camera function up, down, left and right is represented by three images (see code below) for the left side, middle and right side. The control panel is circular so the corner images kind of overlap (its complicated to explain this without a visual). When I click on up for example I have to hide the initial three images (leftside, middle and right side) and display another three images for left , middle and right that indicate that the button is pressed. I am achieving this by having a grid inside a button template. The problem I have is that for the corner images for the control there are really four images that represent this. For example for the top left corner the four images would be represent 1. Top not clicked. 2. Top Clicked and 3. Left Not clicked and 4. Left Clicked. My problem is if I need to make the images contained within the Top button have precedence when the top control is clicked or the images in the left button have precedence when the left button is clicked. So it's like I want to modify the left button's image visible property when the top button is clicked and vise versa. This is really difficult to explain so I apologize if it makes little sense but I can email the source code on request if anyone is interested in my predicament. <Grid> <Canvas> <!--<StackPanel>--> <Button Name="TopSide" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" Height="34" Width="102" Canvas.Left="97" Canvas.Top="60" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" > <Button.Template> <ControlTemplate TargetType="{x:Type Button}"> <Grid Width="100"> <Canvas> <Image Name="TopRightNormal" Source="Resources/topright_off.jpg" Height="34" Width="34" Canvas.Left="66"></Image> <Image Name="TopRightDown" Source="Resources/topright_down.jpg" Height="34" Width="34" Canvas.Left="66" Visibility="Hidden" ></Image> <Image Name="TopNormal" Source="Resources/topcenter_off.jpg" Height="34" Width="34" Canvas.Left="34" /> <Image Name="TopPressed" Source="Resources/topcenter_down.jpg" Height="34" Width="34" Canvas.Left="34" Visibility="Hidden" /> <Image Name="TopDisabled" Source="Resources/topcenter_off.jpg" Height="34" Width="34" Canvas.Left="34" Visibility="Hidden" /> <Image Name="TopLeftNormal" Source="Resources/topleft_off.jpg" Height="34" Width="34" Canvas.Left="2" ></Image> <Image Name="TopLeftDown" Opacity="0" Source="Resources/topleft_down.jpg" Height="34" Width="34" Canvas.Left="2" Visibility="Hidden" ></Image> </Canvas> </Grid> <ControlTemplate.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter TargetName="TopNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="TopPressed" Property="Visibility" Value="Visible" /> <Setter TargetName="TopRightNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="TopRightDown" Property="Visibility" Value="Visible" /> <Setter TargetName="TopLeftNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="TopLeftDown" Property="Visibility" Value="Visible" /> <Setter TargetName="TopLeftDown" Property="Opacity" Value="100" /> </Trigger> <Trigger Property="IsEnabled" Value="False"> <Setter TargetName="TopNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="TopDisabled" Property="Visibility" Value="Visible" /> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Button.Template> </Button> <!--</StackPanel>--> <!--<StackPanel>--> <Button Name="LeftSide" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" Canvas.Left="100" Canvas.Top="60" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" MouseDown="Button_MouseDown_1"> <Button.Template> <ControlTemplate TargetType="{x:Type Button}"> <Grid Width="34" Height="100"> <Canvas> <Image Name="TopLeftNormal" Source="Resources/topleft_off.jpg" Height="34" Width="34" Canvas.Left="0"></Image> <Image Name="TopLeftDown" Opacity="0" Source="Resources/topleft_leftdown.jpg" Height="34" Width="34" Canvas.Left="0" Visibility="Hidden" ></Image> <Image Name="Normal" Source="Resources/leftcenter_off.jpg" Height="34" Width="34" Canvas.Top="32" Canvas.Left="0"/> <Image Name="Pressed" Source="Resources/leftcenter_down.jpg" Visibility="Hidden" Canvas.Top="32" Height="34" Width="34" /> <Image Name="Disabled" Source="Resources/leftcenter_off.jpg" Visibility="Hidden" Height="34" Width="34" Canvas.Top="32" /> </Canvas> </Grid> <ControlTemplate.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter TargetName="Normal" Property="Visibility" Value="Hidden" /> <Setter TargetName="Pressed" Property="Visibility" Value="Visible" /> <Setter TargetName="TopLeftNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="TopLeftNormal" Property="Opacity" Value="0" /> <Setter TargetName="TopLeftDown" Property="Visibility" Value="Visible" /> <Setter TargetName="TopLeftDown" Property="Opacity" Value="100" /> </Trigger> <Trigger Property="IsEnabled" Value="False"> <Setter TargetName="Normal" Property="Visibility" Value="Hidden" /> <Setter TargetName="Disabled" Property="Visibility" Value="Visible" /> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Button.Template> </Button> <!--</StackPanel>--> <!--<StackPanel>--> <Button xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" Height="34" Width="34" Canvas.Left="165" Canvas.Top="92" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" MouseDown="Button_MouseDown_2" > <Button.Template> <ControlTemplate TargetType="{x:Type Button}"> <Grid> <Image Name="Normal" Source="Resources/rightcenter_off.jpg" /> <Image Name="Pressed" Source="Resources/rightcenter_down.jpg" Visibility="Hidden" /> <Image Name="Disabled" Source="Resources/rightcenter_off.jpg" Visibility="Hidden" /> </Grid> <ControlTemplate.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter TargetName="Normal" Property="Visibility" Value="Hidden" /> <Setter TargetName="Pressed" Property="Visibility" Value="Visible" /> </Trigger> <Trigger Property="IsEnabled" Value="False"> <Setter TargetName="Normal" Property="Visibility" Value="Hidden" /> <Setter TargetName="Disabled" Property="Visibility" Value="Visible" /> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Button.Template> </Button> <!--</StackPanel>--> <!--<StackPanel>--> <Button xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" Height="34" Width="34" Canvas.Left="133" Canvas.Top="124" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" > <Button.Template> <ControlTemplate TargetType="{x:Type Button}"> <Grid> <Image Name="BottomNormal" Source="Resources/bottomcenter_off.jpg" /> <Image Name="BottomPressed" Source="Resources/bottomcenter_down.jpg" Visibility="Hidden" /> <Image Name="BottomDisabled" Source="Resources/bottomcenter_off.jpg" Visibility="Hidden" /> </Grid> <ControlTemplate.Triggers> <Trigger Property="IsPressed" Value="True"> <Setter TargetName="BottomNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="BottomPressed" Property="Visibility" Value="Visible" /> </Trigger> <Trigger Property="IsEnabled" Value="False"> <Setter TargetName="BottomNormal" Property="Visibility" Value="Hidden" /> <Setter TargetName="BottomDisabled" Property="Visibility" Value="Visible" /> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Button.Template> </Button> <!--</StackPanel>--> <Image Source="Resources/bottomright_off.jpg" Height="34" Width="34" Canvas.Left="165" Canvas.Top="124"></Image> <Image Source="Resources/bottomleft_off.jpg" Height="34" Width="34" Canvas.Left="100" Canvas.Top="124"></Image> <!--<ToggleButton Style="{StaticResource MyToggleButtonStyle}" Height="34" Width="34" Margin="150,100"/>--> </Canvas> </Grid>

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  • Does IE6 Really not Allow Me to set width/height from left/right/top/bottom???

    - by viatropos
    Building a site super quick and having it work on all my Mac browsers, I thought I'd take a gander on a friends old dell laptop with Windows XP and IE6. Nothing looks remotely correct. It's because I used lots of left/right/top/bottom (constraint) declarations to size elements proportionally to their parent's size (I didn't use percent sizes because the percents refer to the parent's size before margins and padding are applied, left/right/top/bottom refer to them after with position:absolute. I'm asking about that here :)). I've read lots these past few weeks on how horrible IE6 (and IE) is in general, but because of all the reasons people say to support it (large market share and the fear of installing better software), and because half the people in the company we're building a site for use IE6 (getting them to upgrade to Chrome slowly but surely), I thought if I could just get IE6 to render my constraints, that might help. So I am messing around with simple layouts here, and they work fine in my latest versions of Firefox, Safari, Chrome, and Opera, but IE6 is basically saying: If you haven't set a width or height on me, I'm assuming it's zero. But position:absolute; left:0px; right:0px; top:0px; bottom:0px; on a container that's width:1000px; height:1000px; should be the same as setting width:1000px; height:1000px on the child, no? Taking a quick look at the source for this, why won't IE6 render the constraint based absolutely positioned AND SIZED elements? (note: I will be messing around with that file for a while) Thanks

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  • How facebook extracts the right thumbnail of a link?

    - by David
    Hi, I'm wondering how facebook extracts the right picture of the article from a link? they ignore any icons, ads images, or other not related images, & they gives you the right image? What technique/method they use? because i've tried to extract all images using a php regex but how to find the right one? Thanks

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  • Given a 2d array sorted in increasing order from left to right and top to bottom, what is the best w

    - by Phukab
    I was recently given this interview question and I'm curious what a good solution to it would be. Say I'm given a 2d array where all the numbers in the array are in increasing order from left to right and top to bottom. What is the best way to search and determine if a target number is in the array? Now, my first inclination is to utilize a binary search since my data is sorted. I can determine if a number is in a single row in O(log N) time. However, it is the 2 directions that throw me off. Another solution I could use, if I could be sure the matrix is n x n, is to start at the middle. If the middle value is less than my target, then I can be sure it is in the left square portion of the matrix from the middle. I then move diagnally and check again, reducing the size of the square that the target could potentially be in until I have honed in on the target number. Does anyone have any good ideas on solving this problem? Example array: Sorted left to right, top to bottom. 1 2 4 5 6 2 3 5 7 8 4 6 8 9 10 5 8 9 10 11

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