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  • Django sitemap intermittent www

    - by Jen Z
    The automatic sitemap for my Django site fluctuates between including the www on urls and leaving it out (I'm aiming to have it in all the time). This has ramifications in google not indexing my pages properly so I'm trying to narrow down what would be causing this issue. I have set PREPEND_WWW = True and my site record in the sites framework is set to include the www e.g. it's set to www.example.com as opposed to example.com. I'm using memcached but pages should expire from the cache after 48 hours so I wouldn't have thought that would be causing the issue? You can see the problem in effect at http://www.livingspaceltd.co.uk/sitemap.xml (refresh the page a few times). My sitemaps setup is fairly prosaic so I'm doubtful that that is the issue, but in case it's something obvious I'm missing here's the code: ***urls.py*** sitemaps = { 'subpages': Subpages_Sitemap, 'standalone_pages': Standalone_Sitemap, 'categories': Categories_Sitemap, } urlpatterns = patterns('', (r'^sitemap\.xml$', 'django.contrib.sitemaps.views.sitemap', {'sitemaps': sitemaps}), ... ***sitemaps.py*** # -*- coding: utf-8 -*- from django_ls.livingspace.models import Page, Category, Standalone_Page, Subpage from django.contrib.sitemaps import Sitemap class Subpages_Sitemap(Sitemap): changefreq = "monthly" priority = 0.4 def items(self): return Subpage.objects.filter(restricted_to__isnull=True) class Standalone_Sitemap(Sitemap): changefreq = "weekly" priority = 1 def items(self): return Standalone_Page.objects.all() class Categories_Sitemap(Sitemap): changefreq = "weekly" priority = 0.7 def items(self): return Category.objects.all()

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  • No resource type specified (at 'id' with value '@+id\st')

    - by Refaat
    I'm new at android programming, I'm now trying to make some buttons, I configured these buttons using the following code: The MainActivity class : public class MainActivity extends Activity { /** Called when the activity is first created. */ Button st,nd,center; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); st = (Button)findViewById(R.id.st); st = (Button)findViewById(R.id.center); st = (Button)findViewById(R.id.nd); } } and the XML Layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/background" > <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Hello from animation!!" /> <button android:layout_width="100dp" android:layout_height="50dp" android:text="1st half" android:id="@+id\st" /> // and the other two points defined the same way </LinearLayout> And i got that syntax error: error: Error: No resource type specified (at 'id' with value '@+id\st'). // and the same error with the other two buttons HINT: The R class is imported and accessible from the MainActivity class but it can't read R.id.

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  • Removing related elements using XSLT 1.0

    - by pmdarrow
    I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same "Id" values as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements (i.e. those that have the same "Id" values). The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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  • sending mail in rails from tutorial - outdated?

    - by Stacia
    I'm trying to use this tutorial (http://www.tutorialspoint.com/ruby-on-rails-2.1/rails-send-emails.htm) to send mail on rails, but nothing seems to happen. I have ActionMailer::Base.delivery_method = :sendmail in my environment.rb. It's possible the tutorial may be out of date for the more recent version of rails? If so can someone tell me where it goes wrong or a link to another tutorial. I see this in the log. It's a little supsicious that the "to" has subject and stuff appended to it, but I don't know where it went wrong. Processing EmailerController#sendmail (for 127.0.0.1 at 2010-03-10 19:02:21) [POST] Parameters: {"commit"=>"Send", "authenticity_token"=>"251d315cc4dfc6c58c2c7f6f633d52b101d10c14", "email"=>{"recipient"=>"[email protected]", "subject"=>"booooooo", "message"=>"aabdsaf"}} SQL (0.1ms) SET NAMES 'utf8' SQL (0.1ms) SET SQL_AUTO_IS_NULL=0 Sent mail to subject, booooooo, recipient, [email protected], message, aabdsaf Date: Wed, 10 Mar 2010 19:02:21 -0800 From: [email protected] To: [email protected] Mime-Version: 1.0 Content-Type: text/plain; charset=utf-8 Hi! You are having one email message from [email protected] with a title This is title and following is the message: Thanks edit: I manually changed "recipient" to my mail address and I still don't get mail, even though the problem in the log with all of the things stuck together is fixed.

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  • Hibernate - Problem in parsing mapping file (.hbm.xml)

    - by Yatendra Goel
    I am new to Hibernate. I have an exception while running an Hibernate-based application. The exception is as follows: 16 [main] INFO org.hibernate.cfg.Environment - Hibernate 3.3.2.GA 16 [main] INFO org.hibernate.cfg.Environment - hibernate.properties not found 16 [main] INFO org.hibernate.cfg.Environment - Bytecode provider name : javassist 31 [main] INFO org.hibernate.cfg.Environment - using JDK 1.4 java.sql.Timestamp handling 94 [main] INFO org.hibernate.cfg.Configuration - configuring from resource: /hibernate.cfg.xml 94 [main] INFO org.hibernate.cfg.Configuration - Configuration resource: /hibernate.cfg.xml 219 [main] INFO org.hibernate.cfg.Configuration - Reading mappings from resource : app/data/City.hbm.xml 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(12) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(13) Attribute "coloumn" must be declared for element type "property". 266 [main] ERROR org.hibernate.util.XMLHelper - Error parsing XML: XML InputStream(14) Attribute "coloumn" must be declared for element type "property". It seems that it is not finding coloumn attribute of the property element in the mappings file but my mappings file do have the coloumn attribute. Below is the mappings file (City.hbm.xml) <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="app.data"> <class name="City" table="CITY"> <id column="CITY_ID" name="cityId"> <generator class="native"/> </id> <property name="cityDisplyaName" coloumn="CITY_DISPLAY_NAME" /> <property coloumn="CITY_MEANINGFUL_NAME" name="cityMeaningFulName" /> <property coloumn="CITY_URL" name="cityURL" /> </class> </hibernate-mapping>

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  • Read XML with PHP

    - by sea_1987
    I am trying to check a field in some XML that is returned from an outside. The XML is returned in a variable call $out and when you view the source of the page you get a XML output of the following, <?xml version="1.0" encoding="UTF-8"?> <ResponseBlock Live="FALSE" Version="3.51"> <Response Type="AUTH"> <OperationResponse> <TransactionReference>23-9-1334895</TransactionReference> <TransactionCompletedTimestamp>2010-04-30 15:59:05</TransactionCompletedTimestamp> <AuthCode>AUTH CODE:TEST</AuthCode> <TransactionVerifier>AlaUOS1MOnN/iwc5s2WPDm5ggrCLwesUnHs9h+W0N3CRaln2W6lh+6dtaRFFhLdwfnw6y7lRemyJUYl9a3dpWfzORE6DaZkFMb+dIb0Ne1UxjFEJkrEtjzx/i8KSayrIBrT/yGZOoOT42EZ9loc+UkdGk/pqYvj8bZztvgBNo2Ak=</TransactionVerifier> <Result>1</Result> <SettleStatus>0</SettleStatus> <SecurityResponseSecurityCode>1</SecurityResponseSecurityCode> <SecurityResponsePostCode>1</SecurityResponsePostCode> <SecurityResponseAddress>1</SecurityResponseAddress> </OperationResponse> <Order> <OrderInformation>This is a test order</OrderInformation> <OrderReference>Order0001</OrderReference> </Order> </Response> </ResponseBlock> I want check what value is in the 'Result' field. I am unsure how to access the information using PHP, so far I have, $xml = simplexml_load_string($out); Many Thanks

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  • I need a true mouseOver...

    - by invertedSpear
    Ok, so mouseOver and RollOver, and their respective outs work great as long as your mouse is actually over the item, or one of it's children. My problem is that I may have another UI component "between" my mouse and the item I want to process the mouse/rollover(maybe a button that is on top of a canvas, but is not a child of the canvas). The mouse is still over the component, there's just something else that it's over at the same time. Any tips or help how to deal with this? Let me know if I'm not being clear enough. Here is a simplified code example detailing my question copy/paste that into your flex/flash builder and you'll see what I mean: <?xml version="1.0" encoding="utf-8"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" width="500" height="226" creationComplete="ccInit()"> <mx:Script> <![CDATA[ private function ccInit():void{ myCanv.addEventListener(MouseEvent.ROLL_OVER,handleRollOver); } private function handleRollOver(evt:MouseEvent):void{ myCanv.setStyle("backgroundAlpha",1); myCanv.addEventListener(MouseEvent.ROLL_OUT,handleRollOut); } private function handleRollOut(evt:MouseEvent):void{ myCanv.setStyle("backgroundAlpha",0); myCanv.removeEventListener(MouseEvent.ROLL_OUT,handleRollOut); } ]]> </mx:Script> <mx:Canvas id="myCanv" x="10" y="10" width="480" height="200" borderStyle="solid" borderColor="#000000" backgroundColor="#FFFFFF" backgroundAlpha="0"> </mx:Canvas> <mx:Button x="90" y="50" label="Button" width="327" height="100"/> </mx:Application>

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  • java.lang.ExceptionInInitializerError Exception when creating Application Context in Spring

    - by cyotee
    I am practicing with Spring, and am getting a java.lang.ExceptionInInitializerError exception when I try to instantiate the context. The Exception appears below, with my code following it. I have simplified my experiment from before. The Exception Oct 17, 2012 5:54:22 PM org.springframework.context.support.AbstractApplicationContext prepareRefresh INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@570c16b7: startup date [Wed Oct 17 17:54:22 CDT 2012]; root of context hierarchy Exception in thread "main" java.lang.ExceptionInInitializerError at org.springframework.context.support.AbstractRefreshableApplicationContext.createBeanFactory(AbstractRefreshableApplicationContext.java:195) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:128) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:535) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:449) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83) at helloworld.HelloWorldTest.main(HelloWorldTest.java:13) Caused by: java.lang.NullPointerException at org.springframework.beans.factory.support.DefaultListableBeanFactory.<clinit>(DefaultListableBeanFactory.java:105) ... 7 more My configuration XML <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:c="http://www.springframework.org/schema/c" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <bean id="messageContainer" class="helloworld.MessageContainer"> <property name="message" value="Hello World"> </property> </bean> <bean id="messageOutputService" class="helloworld.MessageOutputService"> </bean> My test class. package helloworld; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class HelloWorldTest { /** * @param args */ public static void main(String[] args) { ApplicationContext context = new ClassPathXmlApplicationContext("HelloWorldTest-context.xml"); MessageContainer message = context.getBean(MessageContainer.class); MessageOutputService service = context.getBean(MessageOutputService.class); service.outputMessageToConsole(message); } }

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  • PhoneGap/Cordova. childBrowser plugin giving starnge URL (iOS)

    - by MeltingDog
    I am having a great deal of difficulty getting the childBrowser plugin to work Currently when I click my link it does nothing on my iOS simulator and when I click it using a browser I get a Web Page Not Found error with the web address looking something like: file://myapp/www/%C3%A2%E2%82%AC%C2%9D#??????? I am really stuck for ideas on whats going on and what is causing this, any advice would be greatly appreciated. My code is: <script type="text/javascript" charset="utf-8" src="js/ChildBrowser.js"></script> <script> function onDeviceReady() { childbrowser = ChildBrowser.install(); var root = this; cb = window.plugins.childBrowser; if(cb != null) { cb.onLocationChange = function(loc){ root.locChanged(loc); }; cb.onClose = function(){root.onCloseBrowser(); }; cb.onOpenExternal = function(){root.onOpenExternal(); }; //cb.showWebPage(“http://google.com”); } } function onCloseBrowser() { console.log(“onCloseBrowser!”); } function locChanged(loc) { console.log(“locChanged!”); } function onOpenExternal() { alert(“onOpenExternal!”); } <body onLoad=”onBodyLoad()”> <a href=”#” onclick=’cb.showWebPage(“http://www.google.com”);’>Click Me</a>

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  • jquery touch punch - draggable on ipad

    - by dshuta
    i am starting to work with the jquery touch punch extensions in order to allow draggability on ipad, but i am getting tripped up right away. probably something terribly dumb on my part. the draggable example from the developer works fine on my ipad: http://furf.com/exp/touch-punch/draggable.html but not for me: http://danshuta.com/touchpunch/ this works fine in my desktop browser, but on the ipad it just focuses on the block and scrolls the entire page as i drag, as if it were just an image or other normal embedded object. as this is what happens normally with jquery/ui on ipad, this makes me think it is not loading or otherwise ignoring the "punch" code from my site (though if i host the jquery files on my site via the same path, those load and function fine in desktop browser). here's the entire code, very basic: <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8" /> <title>Touchpunchtest</title> <script src="http://code.jquery.com/jquery.min.js"></script> <script src="http://code.jquery.com/ui/1.8.17/jquery-ui.min.js"></script> <script src="js/jquery.ui.touch-punch.js"></script> </head> <body> <div id="draggybox" onclick="void(0)" style="width: 150px; height: 150px; background: green;"></div> <script>$('#draggybox').draggable();</script> </body> </html> what am i missing?!

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  • (HARD)Remove accents from a JSON response using the raw content

    - by Pentium10
    This is a follow up of this question: Remove accents from a JSON response. The accepted answer there works for a single item/string of a raw JSON content. But I would like to run a full transformation over the entire raw content of the JSON without parsing each object/array/item. What I've tried is this function removeAccents($jsoncontent) { $obj=json_decode($jsoncontent); // use decode to transform the unicode chars to utf $content=serialize($obj); // serialize into string, so the whole obj structure can be used string as a whole $a = 'ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõöøùúûýýþÿRr'; $b = 'aaaaaaaceeeeiiiidnoooooouuuuybsaaaaaaaceeeeiiiidnoooooouuuyybyRr'; $content=utf8_decode($content); $jsoncontent = strtr($content, $a, $b); // at this point the accents are removed, and everything is good echo $jsoncontent; $obj=unserialize($jsoncontent); // this unserialization is returning false, probably because we messed up with the serialized string return json_encode($obj); } As you see after I decoded JSON content, I serialized the object to have a string of it, than I remove the accents from that string, but this way I have problem building back the object, as the unserialize stuff returns false. How can I fix this?

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  • MXML composite container initialization error

    - by mkorpela
    I'm getting an odd error from my composite canvas component: An ActionScript error has occurred: Error: null at mx.core::Container/initialize()[C:\autobuild\galaga\frameworks\projects\framework\src\mx\core\Container.as:2560] at -REMOVED THIS FOR STACK OVERFLOW-.view::EditableCanvas/initialize()[.../view/EditableCanvas .... It seems to be related to the fact that my composite component has a child and I'm trying to add one in the place I'm using the component. So how can I do this correctly? Component code looks like this (EditableCanvas.mxml): <?xml version="1.0" encoding="utf-8"?> <mx:Canvas xmlns:mx="http://www.adobe.com/2006/mxml"> <mx:Script> <mx:Image id="editTextImage" source="@Embed('/../assets/icons/small/edit.png')"/> </mx:Canvas> The code that is using the code looks like this: <view:EditableCanvas width="290" height="120" backgroundColor="#FFFFFF" horizontalScrollPolicy="off" borderStyle="solid" cornerRadius="3"> <mx:Text id="textContentBox" width="270" fontFamily="nautics" fontSize="12" text="{_text}"/> </view:EditableCanvas>

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  • Problem loading scripts from Ajax Response

    - by konathamrajesh
    The problem is I am using get_info() to make a ajax call to Result.lasso and paste the response in div with id 'test'.I am unable to use the sendForm() function from the page where i am calling the get_info(). I have also tried using different versions of jQuery 1.1.1.3 is working fine.But i am facing the problem while using higher versions of jquery. The error with higher versions is as follows missing } in XML expression [Break on this error] alert('hi');\n test.lasso (line 3) sendForm is not defined [Break on this error] sendForm(); get_info() function definition <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js" type="text/javascript"></script> <SCRIPT> function get_info() { $.ajax({url: "Result.lasso", context: document.body, success: function(response){ document.getElementById('test').innerHTML = response ;},dataType:"script"}); } </SCRIPT> The code in Result.lasso is as follows [Content_Type: 'text/html; charset=UTF-8'] <script type="text/javascript"> function sendForm() { alert('hi'); } </script> [Date] form name= "abc" method = "get" action = "abcd.lasso"> input type ="text" name = "element1"/> input type = "button" value="Click" onClick = "javascript: sendForm();"/> </form> Please help me out in resolving this problem Thanks, Rajesh Konatham

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  • How do I build a JSON object to send to an AJAX WebService?

    - by Ben McCormack
    After trying to format my JSON data by hand in javascript and failing miserably, I realized there's probably a better way. Here's what the code for the web service method and relevant classes looks like in C#: [WebMethod] public Response ValidateAddress(Request request) { return new test_AddressValidation().GenerateResponse( test_AddressValidation.ResponseType.Ambiguous); } ... public class Request { public Address Address; } public class Address { public string Address1; public string Address2; public string City; public string State; public string Zip; public AddressClassification AddressClassification; } public class AddressClassification { public int Code; public string Description; } The web service works great with using SOAP/XML, but I can't seem to get a valid response using javascript and jQuery because the message I get back from the server has a problem with my hand-coded JSON. I can't use the jQuery getJSON function because the request requires HTTP POST, so I'm using the lower-level ajax function instead: $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "http://bmccorm-xp/HBUpsAddressValidation/AddressValidation.asmx/ValidateAddress", data: "{\"Address\":{\"Address1\":\"123 Main Street\",\"Address2\":null,\"City\":\"New York\",\"State\":\"NY\",\"Zip\":\"10000\",\"AddressClassification\":null}}", dataType: "json", success: function(response){ alert(response); } }) The ajax function is submitting everything specified in data:, which is where my problem is. How do I build a properly formatted JSON object in javascript so I can plug it in to my ajax call like so: data: theRequest I'll eventually be pulling data out of text inputs in forms, but for now hard-coded test data is fine. How do I build a properly formatted JSON object to send to the web service?

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  • Uploading to S3 using Curl

    - by Carl Crawley
    Hi All, I'm currently using cURL to upload a file from my server to S3 using AJAX to call the script. So I have the following: $fullfilepath = '/server/sitepath/files/' . $_POST['file']; $upload_url = 'https://'.$_POST['buckets'].'.s3.amazonaws.com/'; $params = array( 'key'=>$_POST['key'], 'AWSAccessKeyId'=>$_POST['AWSAccessKeyId'], 'acl'=>$_POST['acl'], 'success_action_status'=>$_POST['success_action_status'], 'policy'=>$_POST['policy'], 'signature'=>$_POST['signature'], 'Content-Type'=>$_POST['Content-Type'], 'file'=>"@$fullfilepath" ); $ch = curl_init(); curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_URL, $upload_url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $params); $response = curl_exec($ch); curl_close($ch); echo $response; However, I'm getting an S3 error as follows when it posts and I'm unsure why because I'm not passing JSON to it. <?xml version="1.0" encoding="UTF-8"?> <Error><Code>InvalidPolicyDocument</Code><Message>Invalid Policy: Invalid JSON.</Message><RequestId>B29469C6151BE0E8</RequestId><HostId>BFPk6W2kt1b6hTtx0mEq6dWdN/IhO0gNR5bct//7LAOwJxm1C3PrxS4RPv1blzJ8</HostId></Error> I've googled it for the last hour or so and can't seem to figure it out. If I change the order of the Array fields, it gives me a different error - I believe the order of the posted fields is important somehow. any help would be much appreciated! C

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  • How do I use XML Builder to create xml in rails?

    - by Angela
    I am trying the following, but the output XML is badly formed: def submit xml = Builder::XmlMarkup.new xml.instruct! xml.mail xml.documents xml.document xml.template xml.source "gallery" xml.name "Postcard: Image fill front" @xml_display = xml end I need it to look more like this: <?xml version="1.0" encoding="UTF-8"?> <mail> <documents> <document> <template> <source>gallery</source> <name>Postcard: Image fill front</name> </template> <sections> <section> <name>Text</name> <text>Hello, World!</text> </section> <section> <name>Image</name> <attachment>...attachment id...</attachment> </section> </sections> </document> </documents> <addressees> <addressee> <name>John Doe</name> <address>123 Main St</address> <city>Anytown</city> <state>AZ</state> <postal-code>10000</postal-code> </addressee> </addressees> </mail>

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  • WebClient Lost my Session

    - by kamiar3001
    Hi folks I have a problem first of all look at my web service method : [WebMethod(), ScriptMethod(ResponseFormat = ResponseFormat.Json)] public string GetPageContent(string VirtualPath) { WebClient client = new WebClient(); string content=string.Empty; client.Encoding = System.Text.Encoding.UTF8; try { if (VirtualPath.IndexOf("______") > 0) content = client.DownloadString(HttpContext.Current.Request.UrlReferrer.AbsoluteUri.Replace("Main.aspx", VirtualPath.Replace("__", "."))); else content = client.DownloadString(HttpContext.Current.Request.UrlReferrer.AbsoluteUri.Replace("Main.aspx", VirtualPath)); } catch { content = "Not Found"; } return content; } As you can see my web service method read and buffer page from it's localhost it works and I use it to add some ajax functionality to my web site it works fine but my problem is Client.DownloadString(..) lost all session because my sessions are all null which are related to this page for more description. at page-load in the page which I want to load from my web service I set session : HttpContext.Current.Session[E_ShopData.Constants.SessionKey_ItemList] = result; but when I click a button in the page this session is null I mean it can't transfer session. How I can solve this problem ? my web service is handled by some jquery code like following : $.ajax({ type: "Post", url: "Services/NewE_ShopServices.asmx" + "/" + "GetPageContent", data: "{" + "VirtualPath" + ":" + mp + "}", contentType: "application/json; charset=utf-8", dataType: "json", complete: hideBlocker, success: LoadAjaxSucceeded, async: true, cache: false, error: AjaxFailed });

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  • how to multithread on a python server

    - by user3732790
    HELP please i have this code import socket from threading import * import time HOST = '' # Symbolic name meaning all available interfaces PORT = 8888 # Arbitrary non-privileged port s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) print ('Socket created') s.bind((HOST, PORT)) print ('Socket bind complete') s.listen(10) print ('Socket now listening') def listen(conn): odata = "" end = 'end' while end == 'end': data = conn.recv(1024) if data != odata: odata = data print(data) if data == b'end': end = "" print("conection ended") conn.close() while True: time.sleep(1) conn, addr = s.accept() print ('Connected with ' + addr[0] + ':' + str(addr[1])) Thread.start_new_thread(listen,(conn)) and i would like it so that when ever a person comes onto the server it has its own thread. but i can't get it to work please someone help me. :_( here is the error code: Socket created Socket bind complete Socket now listening Connected with 127.0.0.1:61475 Traceback (most recent call last): File "C:\Users\Myles\Desktop\test recever - Copy.py", line 29, in <module> Thread.start_new_thread(listen,(conn)) AttributeError: type object 'Thread' has no attribute 'start_new_thread' i am on python version 3.4.0 and here is the users code: import socket #for sockets import time s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) print('Socket Created') host = 'localhost' port = 8888 remote_ip = socket.gethostbyname( host ) print('Ip address of ' + host + ' is ' + remote_ip) #Connect to remote server s.connect((remote_ip , port)) print ('Socket Connected to ' + host + ' on ip ' + remote_ip) while True: message = input("> ") #Set the whole string s.send(message.encode('utf-8')) print ('Message send successfully') data = s.recv(1024) print(data) s.close

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  • innerHTML doesn't work correctly with xhtml in Chrome

    - by Desperadeus
    Hi! I've got a trouble with Chrome5.0.375.70, but FF 3.6.3 and Opera 10.53 are OK. Below is the line of code: document.getElementById('content').innerHTML = data.documentElement.innerHTML; The data object from the code is a document (typeof(data) == 'object') and I've got it by ajax request to chapter01.xhtml: <?xml version="1.0" encoding="utf-8"?> <!DOCTYPE html [ <!ENTITY D "&#x2014;"> <!ENTITY o "&#x2018;"> <!ENTITY c "&#x2019;"> <!ENTITY O "&#x201C;"> <!ENTITY C "&#x201D;"> ]> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Alice's Adventures in Wonderland by Lewis Carroll. Chapter I: Down the Rabbit-Hole</title> <link rel="stylesheet" type="text/css" href="style.css"/> <link rel="stylesheet" type="application/vnd.adobe-page-template+xml" href="page-template.xpgt"/> </head> <body> <div class="title_box"> <h2 class="chapnum">Chapter I</h2> <h2 class="chaptitle">Down the Rabbit-Hole</h2> <hr/> </div> The Chrome cuts all before body and as a result link to css in header is missed; user can't see formatted text and images. How can I fix it or bypass?

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  • Opening a Unicode file with Perl

    - by Jaco Pretorius
    I'm using osql to run several sql scripts against a database and then I need to look at the results file to check if any errors occurred. The problem is that perl doesn't seem to like the fact that the results files are unicode. I wrote a little test script to test it and the output comes out all warbled. $file = shift; open OUTPUT, $file or die "Can't open $file: $!\n"; while (<OUTPUT>) { print $_; if (/Invalid|invalid|Cannot|cannot/) { push(@invalids, $file); print "invalid file - $inputfile - schedule for retry\n"; last; } } Any ideas? I've tried decoding using decode_utf8 but it makes no difference. I've also tried to set the encoding when opening the file. I think the problem might be that osql puts the result file in UTF-16 format, but I'm not sure. When I open the file in textpad it just tells me 'Unicode'. Edit: Using perl v5.8.8

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  • Foreign/accented characters in sql query

    - by FromCanada
    I'm using Java and Spring's JdbcTemplate class to build an SQL query in Java that queries a Postgres database. However, I'm having trouble executing queries that contain foreign/accented characters. For example the (trimmed) code: JdbcTemplate select = new JdbcTemplate( postgresDatabase ); String query = "SELECT id FROM province WHERE name = 'Ontario';"; Integer id = select.queryForObject( query, Integer.class ); will retrieve the province id, but if instead I did name = 'Québec' then the query fails to return any results (this value is in the database so the problem isn't that it's missing). I believe the source of the problem is that the database I am required to use has the default client encoding set to SQL_ASCII, which according to this prevents automatic character set conversions. (The Java environments encoding is set to 'UTF-8' while I'm told the database uses 'LATIN1' / 'ISO-8859-1') I was able to manually indicate the encoding when the resultSets contained values with foreign characters as a solution to a previous problem with a similar nature. Ex: String provinceName = new String ( resultSet.getBytes( "name" ), "ISO-8859-1" ); But now that the foreign characters are part of the query itself this approach hasn't been successful. (I suppose since the query has to be saved in a String before being executed anyway, breaking it down into bytes and then changing the encoding only muddles the characters further.) Is there a way around this without having to change the properties of the database or reconstruct it? PostScript: I found this function on StackOverflow when making up a title, it didn't seem to work (I might not have used it correctly, but even if it did work it doesn't seem like it could be the best solution.):

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  • XmlSerialize a custom collection with an Attribute

    - by roomaroo
    I've got a simple class that inherits from Collection and adds a couple of properties. I need to serialize this class to XML, but the XMLSerializer ignores my additional properties. I assume this is because of the special treatment that XMLSerializer gives ICollection and IEnumerable objects. What's the best way around this? Here's some sample code: using System.Collections.ObjectModel; using System.IO; using System.Xml.Serialization; namespace SerialiseCollection { class Program { static void Main(string[] args) { var c = new MyCollection(); c.Add("Hello"); c.Add("Goodbye"); var serializer = new XmlSerializer(typeof(MyCollection)); using (var writer = new StreamWriter("test.xml")) serializer.Serialize(writer, c); } } [XmlRoot("MyCollection")] public class MyCollection : Collection<string> { [XmlAttribute()] public string MyAttribute { get; set; } public MyCollection() { this.MyAttribute = "SerializeThis"; } } } This outputs the following XML (note MyAttribute is missing in the MyCollection element): <?xml version="1.0" encoding="utf-8"?> <MyCollection xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> What I want is <MyCollection MyAttribute="SerializeThis" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <string>Hello</string> <string>Goodbye</string> </MyCollection> Any ideas? The simpler the better. Thanks.

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  • accessing a value of a nested hash

    - by st
    Hello! I am new to perl and I have a problem that's very simple but I cannot find the answer when consulting my perl book. When printing the result of Dumper($request); I get the following result: $VAR1 = bless( { '_protocol' => 'HTTP/1.1', '_content' => '', '_uri' => bless( do{\(my $o = 'http://myawesomeserver.org:8081/counter/')}, 'URI::http' ), '_headers' => bless( { 'user-agent' => 'Mozilla/5.0 (X11; U; Linux i686; en; rv:1.9.0.4) Gecko/20080528 Epiphany/2.22 Firefox/3.0', 'connection' => 'keep-alive', 'cache-control' => 'max-age=0', 'keep-alive' => '300', 'accept' => 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'accept-language' => 'en-us,en;q=0.5', 'accept-encoding' => 'gzip,deflate', 'host' => 'localhost:8081', 'accept-charset' => 'ISO-8859-1,utf-8;q=0.7,*;q=0.7' }, 'HTTP::Headers' ), '_method' => 'GET', '_handle' => bless( \*Symbol::GEN0, 'FileHandle' ) }, 'HTTP::Server::Simple::Dispatched::Request' ); How can I access the values of '_method' ('GET') or of 'host' ('localhost:8081'). I know that's an easy question, but perl is somewhat cryptic at the beginning. Thank you, St.

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  • java.lang.ClassNotFoundException: org.springframework.ui.ModelMap

    - by aelshereay
    I create a simple webapp using tomcat 6, spring 2.5.6 and maven. The problem is when I boot up tomcat, I am getting the following errors: SEVERE: StandardWrapper.Throwable java.lang.NoClassDefFoundError: org/springframework/ui/ModelMap ... Caused by: java.lang.ClassNotFoundException: org.springframework.ui.ModelMap The ModelMap class does exist in spring-2.5.6.jar and spring-context-2.5.6.jar, I also have some other spring jars. All of them are being deployed to tomcat correctly, when I check the application WEB-INF (deployed to tomcat) I found all those jars there! I have only one @Controller that has a @RequestMapping("/home.htm") showForm(ModelMap model) method. My applicationContext is quite simple: <?xml version="1.0" encoding="utf-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:dwr="http://www.directwebremoting.org/schema/spring-dwr" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd http://www.directwebremoting.org/schema/spring-dwr http://www.directwebremoting.org/schema/spring-dwr-3.0.xsd" default-autowire="byName"> <context:component-scan base-package="org.myapp"/> <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/> <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter"/> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/view/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans>

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  • xmlEncoder not writing in netBeans

    - by Greg
    Hi, I am trying to use the xmlEncoder to write to xml file in net-beans but it doesnt work. Here is the call to the writing function: dbManipulator.writeStudents(deps); where deps = new Hashtable<String, Department>(); dbManipulator = new DataBaseManipulator(); Department is an class-object I made, and here is writeStudents method which is located in the DataBaseManipulator class: public void writeStudents(Hashtable<Integer, Student> students) { XMLEncoder encoder = null; try { encoder = new XMLEncoder(new FileOutputStream(".\\test\\Students.xml")); } catch(Exception e){} encoder.writeObject(students); encoder.close(); }//end of function writeStudents() Any ideas why it isnt working? I tried changing the hashtable to vector but still the xml file looks like that after the writing: <?xml version="1.0" encoding="UTF-8"?> <java version="1.6.0_18" class="java.beans.XMLDecoder"> <object class="java.util.Hashtable"/> </java> Thanks in advance, Greg

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