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  • Linux bash: when to use egrep instead of grep?

    - by Michael Mao
    Hi all : I am preparing for a Linux terminal assessment now, I tried to Google and found most resources are referring to the basic "grep" rather than the more powerful "egrep" -- well, that is at least what the professor said in lecture. I am always working with small samples so performance tuning is a thing too far away. So basically I'd like to know are there any areas where I must switch to egrep to do it in a better way? Is it safe to work with basic "grep" as for now? will there be potential risks? Sorry about my limited knowledge on Linux shell commands, the man page looks like a maze to me and honestly I haven't put much time in understanding all the features both command provide.

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  • Converting Unicode strings to escaped ascii string

    - by Ali
    How can I convert this string: This string contains the unicode character Pi(p) into an escaped ascii string: This string contains the unicode character Pi(\u03a0) and vice versa ? The current Encoding available in C#, converts the p character into "?". I need to preserve that character.

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  • IBasic Accumulator

    - by Tara
    I am trying to do an accumulator in IBasic for a college assignment and I have the general stuff down but I cannot get it to accumulate. The code is below. My question is how do I get it to accumulate and pass to the different module. I'm trying to calculate how many right answers the user gets. Also, i need to calculate the percentage of right answers. so if the user gets 9 out of 10 right theyed answer 90% right. 'October 15, 2009 ' 'Lab 7.5 Programming Challenge 1 - Average Test Scores ' 'This is a dice game ' declare main() declare inputName(name:string) declare getAnswer(num1:int, num2:int) declare getResult(num1:int, num2:int, answer:int) declare avgRight(getRight:int) declare printInfo(name:string, getRight:int, averege:float) openconsole main() do:until inkey$<>"" closeconsole end sub main() def name:string def num1, num2, answer, total, getRight:int def averege:float inputName (name) getRight = 0 For counter = 1 to 10 getRight = getAnswer(num1, num2) getRight = getRight + 1 next counter average = avgRight (getRight) printInfo(Name, getRight, average) end sub inputName (name) Input "Please enter your name: " ,name return sub getAnswer(num1, num2) def answer, getRight:int num1 = rnd (10) + 1 num2 = rnd (10) + 1 Print num1, "+ " ,num2 Input "What is the answer to the equation? " ,answer getRight = getResult(num1, num2, answer) return getRight sub getResult(num1, num2, answer) def getRight:int if answer = num1 + num2 getRight = 1 else getRight = 0 endif return getRight sub avgRight(getRight) def average:float average = getRight / 10 return average sub printInfo(name, getRight, averege) Print "The students name is: " ,name Print "The number right is: " ,getRight Print Using ("&##.#&", "The average right is " ,averege * 100, "%") return

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  • Java: Using Comman line arguments to process the names of files

    - by Kat
    I'm a writing a program that will determine the number of lines, characters, and average word length for a text file. For the program, the specifications say that the file or files will be entered as a command line argument and that we should make a TestStatistic object for each file entered. I don't understand how to write the code for making the TestStatistic objects if the user enters more than one file.

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  • Need some help on how to replay the last game of a java maze game

    - by Marty
    Hello, I am working on creating a Java maze game for a project. The maze is displayed on the console as standard output not in an applet. I have created most of hte code I need, however I am stuck at one problem and that is I need a user to be able to replay the last game i.e redraw the maze with the users moves but without any input from the user. I am not sure on what course of action to take, i was thinking about copying each users move or the position of each move into another array, as you can see i have 2 variables which hold the position of the player, plyrX and plyrY do you think copying these values into a new array after each move would solve my problem and how would i go about this? I have updated my code, apologies about the textIO.java class not being present, not sure how to resolve that exept post a link to TextIO.java [TextIO.java][1] My code below is updated with a new array of type char to hold values from the original maze (read in from text file and displayed using unicode characters) and also to new variables c_plyrX and c_plyrY which I am thinking should hold the values of plyrX and plyrY and copy them into the new array. When I try to call the replayGame(); method from the menu the maze loads for a second then the console exits so im not sure what I am doing wrong Thanks public class MazeGame { //unicode characters that will define the maze walls, //pathways, and in game characters. final static char WALL = '\u2588'; //wall final static char PATH = '\u2591'; //pathway final static char PLAYER = '\u25EF'; //player final static char ENTRANCE = 'E'; //entrance final static char EXIT = '\u2716'; //exit //declaring member variables which will hold the maze co-ordinates //X = rows, Y = columns static int entX = 0; //entrance X co-ordinate static int entY = 1; //entrance y co-ordinate static int plyrX = 0; static int plyrY = 1; static int exitX = 24; //exit X co-ordinate static int exitY = 37; //exit Y co-ordinate //static member variables which hold maze values //used so values can be accessed from different methods static int rows; //rows variable static int cols; //columns variable static char[][] maze; //defines 2 dimensional array to hold the maze //variables that hold player movement values static char dir; //direction static int spaces; //amount of spaces user can travel //variable to hold amount of moves the user has taken; static int movesTaken = 0; //new array to hold player moves for replaying game static char[][] mazeCopy; static int c_plyrX; static int c_plyrY; /** userMenu method for displaying the user menu which will provide various options for * the user to choose such as play a maze game, get instructions, etc. */ public static void userMenu(){ TextIO.putln("Maze Game"); TextIO.putln("*********"); TextIO.putln("Choose an option."); TextIO.putln(""); TextIO.putln("1. Play the Maze Game."); TextIO.putln("2. View Instructions."); TextIO.putln("3. Replay the last game."); TextIO.putln("4. Exit the Maze Game."); TextIO.putln(""); int option; //variable for holding users option TextIO.put("Type your choice: "); option = TextIO.getlnInt(); //gets users option //switch statement for processing menu options switch(option){ case 1: playMazeGame(); case 2: instructions(); case 3: if (c_plyrX == plyrX && c_plyrY == plyrY)replayGame(); else { TextIO.putln("Option not available yet, you need to play a game first."); TextIO.putln(); userMenu(); } case 4: System.exit(0); //exits the user out of the console default: TextIO.put("Option must be 1, 2, 3 or 4"); } } //end of userMenu /**main method, will call the userMenu and get the users choice and call * the relevant method to execute the users choice. */ public static void main(String[]args){ userMenu(); //calls the userMenu method } //end of main method /**instructions method, displays instructions on how to play * the game to the user/ */ public static void instructions(){ TextIO.putln("To beat the Maze Game you have to move your character"); TextIO.putln("through the maze and reach the exit in as few moves as possible."); TextIO.putln(""); TextIO.putln("Your characer is displayed as a " + PLAYER); TextIO.putln("The maze exit is displayed as a " + EXIT); TextIO.putln("Reach the exit and you have won escaped the maze."); TextIO.putln("To control your character type the direction you want to go"); TextIO.putln("and how many spaces you want to move"); TextIO.putln("for example 'D3' will move your character"); TextIO.putln("down 3 spaces."); TextIO.putln("Remember you can't walk through walls!"); boolean insOption; //boolean variable TextIO.putln(""); TextIO.put("Do you want to play the Maze Game now? (Y or N) "); insOption = TextIO.getlnBoolean(); if (insOption == true)playMazeGame(); else userMenu(); } //end of instructions method /**playMazeGame method, calls the loadMaze method and the charMove method * to start playing the Maze Game. */ public static void playMazeGame(){ loadMaze(); plyrMoves(); } //end of playMazeGame method /**loadMaze method, loads the 39x25 maze from the MazeGame.txt text file * and inserts values from the text file into the maze array and * displays the maze on screen using the unicode block characters. * plyrX and plyrY variables are set at their staring co ordinates so that when * a game is completed and the user selects to play a new game * the player character will always be at position 01. */ public static void loadMaze(){ plyrX = 0; plyrY = 1; TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions maze = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ maze[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == plyrX && j == plyrY){ plyrX = i; plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (maze[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (maze[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (maze[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (maze[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end of loadMaze method /**redrawMaze method, method for redrawing the maze after each move. * */ public static void redrawMaze(){ TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions maze = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ maze[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == plyrX && j == plyrY){ plyrX = i; plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (maze[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (maze[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (maze[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (maze[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end redrawMaze method /**replay game method * */ public static void replayGame(){ c_plyrX = plyrX; c_plyrY = plyrY; TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions mazeCopy = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ mazeCopy[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == c_plyrX && j == c_plyrY){ c_plyrX = i; c_plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (mazeCopy[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (mazeCopy[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (mazeCopy[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (mazeCopy[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end replayGame method /**plyrMoves method, method for moving the players character * around the maze. */ public static void plyrMoves(){ int nplyrX = plyrX; int nplyrY = plyrY; int pMoves; direction(); //UP if (dir == 'U' || dir == 'u'){ nplyrX = plyrX; nplyrY = plyrY; for(pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again."); } else if (pMoves != spaces){ nplyrX =plyrX + 1; } else { plyrX = plyrX-spaces; c_plyrX = plyrX; movesTaken++; } } }//end UP if //DOWN if (dir == 'D' || dir == 'd'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves ++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again"); } else if (pMoves != spaces){ nplyrX = plyrX+1; } else{ plyrX = plyrX+spaces; c_plyrX = plyrX; movesTaken++; } } } //end DOWN if //LEFT if (dir == 'L' || dir =='l'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again"); } else if (pMoves != spaces){ nplyrY = plyrY + 1; } else{ plyrY = plyrY-spaces; c_plyrY = plyrY; movesTaken++; } } } //end LEFT if //RIGHT if (dir == 'R' || dir == 'r'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again."); } else if (pMoves != spaces){ nplyrY += 1; } else{ plyrY = plyrY+spaces; c_plyrY = plyrY; movesTaken++; } } } //end RIGHT if //prints message if player escapes from the maze. if (maze[plyrX][plyrY] == '3'){ TextIO.putln("****Congratulations****"); TextIO.putln(); TextIO.putln("You have escaped from the maze."); TextIO.putln(); userMenu(); } else{ movesTaken++; redrawMaze(); plyrMoves(); } } //end of plyrMoves method /**direction, method * */ public static char direction(){ TextIO.putln("Enter the direction you wish to move in and the distance"); TextIO.putln("i.e D3 = move down 3 spaces"); TextIO.putln("U - Up, D - Down, L - Left, R - Right: "); dir = TextIO.getChar(); if (dir =='U' || dir == 'D' || dir == 'L' || dir == 'R' || dir == 'u' || dir == 'd' || dir == 'l' || dir == 'r'){ spacesMoved(); } else{ loadMaze(); TextIO.putln("Invalid direction!"); TextIO.put("Direction must be one of U, D, L or R"); direction(); } return dir; //returns the value of dir (direction) } //end direction method /**spaces method, gets the amount of spaces the user wants to move * */ public static int spacesMoved(){ TextIO.putln(" "); spaces = TextIO.getlnInt(); if (spaces <= 0){ loadMaze(); TextIO.put("Invalid amount of spaces, try again"); spacesMoved(); } return spaces; } //end spacesMoved method } //end of MazeGame class

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  • Java: Using Command line arguments to process the names of files

    - by Kat
    I'm a writing a program that will determine the number of lines, characters, and average word length for a text file. For the program, the specifications say that the file or files will be entered as a command line argument and that we should make a TestStatistic object for each file entered. I don't understand how to write the code for making the TestStatistic objects if the user enters more than one file.

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  • How to use bean in JSP?

    - by Nick
    How to use bean in JSP with only <jsp:useBean>, not MVC? Assume you have a grade.txt file which contains following data: Tom 90 Jerry 70 Katy 80 John 60 It asks you to create a bean named grade.java, a JSP page named graderesult.jsp, and a html page named gradecheck.html. gradecheck.html provides a input textbox and a button submit, once you submit the name of the student, the graderesult.jsp will communicates with bean to show the name and the score corresponding to the person.

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  • Having problem with C++ file handling

    - by caramel1991
    Our lecturer has given us a task,I've attempted it and try every single effort I can,but I still struggle with one of the problem in it,here goes the question: The company you work at receives a monthly report in a text format. The report contains the following information. • Department Name • Head of Department Name • Month • Minimum spending of the month • Maximum spending of the month Your program is to obtain the name of the input file from the user. Implement a structure to represent the data: Once the file has been read into your program, print out the following statistics for the user: • List which department has the minimum spending per month by month • List which department has the minimum spending by month by month Write the information into a file called “MaxMin.txt” Then do a processing so that the Department Name, Head of Department Name, Minimum spending and Maximum spending are written to separate files based on the month, eg Jan, Feb, March and so on. and of course our lecturer does send us a text file with the content: Engineering Bill Jan 2000 15000 IT Jack Jan 300 20000 HR Jill Jan 1500 10000 Engineering Bill Feb 5000 45000 IT Jack Feb 4500 7000 HR Jill Feb 5600 60000 Engineering Bill Mar 5000 45000 IT Jack Mar 4500 7000 HR Jill Mar 5600 60000 Engineering Bill Apr 5000 45000 IT Jack Apr 4500 7000 HR Jill Apr 5600 60000 Engineering Bill May 2000 15000 IT Jack May 300 20000 HR Jill May 1500 10000 Engineering Bill Jun 2000 15000 IT Jack Jun 300 20000 HR Jill Jun 1500 10000 and here's the c++ code I've written ue#include include include using namespace std; struct Record { string depName; string head; string month; float max; float min; string name; }myRecord[19]; int main () { string line; ofstream minmax,jan,feb,mar,apr,may,jun; char a[50]; char b[50]; int i = 0,j,k; float temp; //float maxjan=myRecord[0].max,maxfeb=myRecord[0].max,maxmar=myRecord[0].max,maxapr=myRecord[0].max,maxmay=myRecord[0].max,maxjune=myRecord[0].max; float minjan=myRecord[1].min,minfeb=myRecord[1].min,minmar=myRecord[1].min,minapr=myRecord[1].min,minmay=myRecord[1].min,minjune=myRecord[1].min; float maxjan=0,maxfeb=0,maxmar=0,maxapr=0,maxmay=0,maxjune=0; //float minjan=0,minfeb=0,minmar=0,minapr=0,minmay=0,minjune=0; string maxjanDep,maxfebDep,maxmarDep,maxaprDep,maxmayDep,maxjunDep; string minjanDep,minfebDep,minmarDep,minaprDep,minmayDep,minjunDep; cout<<"Enter file name: "; cina; ifstream myfile (a); //minmax.open ("MaxMin.txt"); if (myfile.is_open()){ while (! myfile.eof()){ myfilemyRecord[i].depNamemyRecord[i].headmyRecord[i].monthmyRecord[i].minmyRecord[i].max; cout << myRecord[i].depName<<"\t"< cout<<"Enter file name: "; cinb; ifstream myfile1 (b); minmax.open ("MaxMin.txt"); jan.open ("Jan.txt"); feb.open ("Feb.txt"); mar.open ("March.txt"); apr.open ("April.txt"); may.open ("May.txt"); jun.open ("Jun.txt"); if (myfile1.is_open()){ while (! myfile1.eof()){ myfile1myRecord[i].depNamemyRecord[i].headmyRecord[i].monthmyRecord[i].minmyRecord[i].max; if (myRecord[i].month == "Jan"){ jan<< myRecord[i].depName<<"\t"< if (maxjan< myRecord[i].max){ maxjan=myRecord[i].max; maxjanDep=myRecord[i].depName;} //if (minjan myRecord[i].min){ // minjan=myRecord[i].min; //minjanDep=myRecord[i].depName; //} for (k=1;k<=3;k++){ for (j=0;j<2;j++){ if (myRecord[j].minmyRecord[j+1].min){ temp=myRecord[j].min; myRecord[j].min=myRecord[j+1].min; myRecord[j+1].min=temp; minjanDep=myRecord[j].depName; }}} } if (myRecord[i].month == "Feb"){ feb<< myRecord[i].depName<<"\t"< //if (minfebmyRecord[i].min){ //minfeb=myRecord[i].min; //minfebDep=myRecord[i].depName; //} for (k=1;k<=3;k++){ for (j=0;j<2;j++){ if (myRecord[j].minmyRecord[j+1].min){ temp=myRecord[j].min; myRecord[j].min=myRecord[j+1].min; myRecord[j+1].min=temp; minfebDep=myRecord[j+1].depName; }}} } if (myRecord[i].month == "Mar"){ mar<< myRecord[i].depName<<"\t"< if (myRecord[i].month == "Apr"){ apr<< myRecord[i].depName<<"\t"< if (minaprmyRecord[i].min){ minapr=myRecord[i].min; minaprDep=myRecord[i].min;} } if (myRecord[i].month == "May"){ may< if (minmaymyRecord[i].min){ minmay=myRecord[i].min; minmayDep=myRecord[i].depName;} } if (myRecord[i].month == "Jun"){ jun<< myRecord[i].depName<<"\t"< if (minjunemyRecord[i].min){ minjune=myRecord[i].min; minjunDep=myRecord[i].depName;} } i++; myfile.close(); } minmax<<"department that has maximum spending at jan "< else{ cout << "Unable to open file"< } sorry inside that code ue#include should has iostream along with another two #include fstream and string,but at here it was treated as html tag,so i can't type it. my problem here is,I can't seems to get the minimum spending,I've try all I can but I'm still lingering on it,any idea??THANK YOU!

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  • Why isnt this returning the new string?

    - by Evan Kimia
    I have a recursive method that reversed a string (HW assignment, has to be recursive). I did it....but its only returning the value of the string after the first pass. By analyzing the output after each pass i can see it does do its job correctly. heres my code, and the output i get below it: String s = "Hello, I love you wont you tell me your name?"; int k=0; public String reverseThisString(String s) { if(k!=s.length()) { String first =s.substring(0,k)+s.charAt(s.length()-1); String end = ""+s.substring(k, s.length()-1); k++; s=first+end; System.out.println(s); this.reverseThisString(s); } return s; } output: ?Hello, I love you wont you tell me your name

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  • I'm working on Peano Axioms in Agda and I've hit a bit of a sticking point

    - by Schroedinger
    PA6 : ?{m n} -> m = n -> n = m is the axiom I am trying to solve and support, I've tried using a cong (from the core library) but am having troubles with the cong constructor PA6 = cong gets me nowhere, I know for cong I am required to supply a refl for equality and a type, but I'm, not sure what type I'm supposed to supply. Ideas? This is for a small assignment at University, so I'd rather someone demonstrate what I've missed rather than write the acutual answer, but I'd appreciate any degree of support.

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  • Problem with FlowLayout

    - by atch
    public class MyFrame extends JFrame { public MyFrame(String title) { setSize(200, 200); setTitle(Integer.toString(super.getSize().width)); setLayout(new FlowLayout()); for (int i = 0; i < 5; ++i) { JButton b = new JButton(); b.setSize(90,50); b.setText(Integer.toString(b.getSize().width)); this.add(b);![alt text][1] } this.setVisible(true); } } why if having button widht 90 I'm getting window where three buttons are in one row instead of two?

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  • adding nodes to a binary search tree randomly deletes nodes

    - by SDLFunTimes
    Hi, stack. I've got a binary tree of type TYPE (TYPE is a typedef of data*) that can add and remove elements. However for some reason certain values added will overwrite previous elements. Here's my code with examples of it inserting without overwriting elements and it not overwriting elements. the data I'm storing: struct data { int number; char *name; }; typedef struct data data; # ifndef TYPE # define TYPE data* # define TYPE_SIZE sizeof(data*) # endif The tree struct: struct Node { TYPE val; struct Node *left; struct Node *rght; }; struct BSTree { struct Node *root; int cnt; }; The comparator for the data. int compare(TYPE left, TYPE right) { int left_len; int right_len; int shortest_string; /* find longest string */ left_len = strlen(left->name); right_len = strlen(right->name); if(right_len < left_len) { shortest_string = right_len; } else { shortest_string = left_len; } /* compare strings */ if(strncmp(left->name, right->name, shortest_string) > 1) { return 1; } else if(strncmp(left->name, right->name, shortest_string) < 1) { return -1; } else { /* strings are equal */ if(left->number > right->number) { return 1; } else if(left->number < right->number) { return -1; } else { return 0; } } } And the add method struct Node* _addNode(struct Node* cur, TYPE val) { if(cur == NULL) { /* no root has been made */ cur = _createNode(val); return cur; } else { int cmp; cmp = compare(cur->val, val); if(cmp == -1) { /* go left */ if(cur->left == NULL) { printf("adding on left node val %d\n", cur->val->number); cur->left = _createNode(val); } else { return _addNode(cur->left, val); } } else if(cmp >= 0) { /* go right */ if(cur->rght == NULL) { printf("adding on right node val %d\n", cur->val->number); cur->rght = _createNode(val); } else { return _addNode(cur->rght, val); } } return cur; } } void addBSTree(struct BSTree *tree, TYPE val) { tree->root = _addNode(tree->root, val); tree->cnt++; } The function to print the tree: void printTree(struct Node *cur) { if (cur == 0) { printf("\n"); } else { printf("("); printTree(cur->left); printf(" %s, %d ", cur->val->name, cur->val->number); printTree(cur->rght); printf(")\n"); } } Here's an example of some data that will overwrite previous elements: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "rooty"; myData2.number = 1; myData2.name = "lefty"; myData3.number = 10; myData3.name = "righty"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which will print: (( righty, 10 ) lefty, 1 ) Finally here's some test data that will go in the exact same spot as the previous data, but this time no data is overwritten: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "i"; myData2.number = 5; myData2.name = "h"; myData3.number = 5; myData3.name = "j"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which prints: (( j, 5 ) i, 5 ( h, 5 ) ) Does anyone know what might be going wrong? Sorry if this post was kind of long.

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  • Recursion problem in C

    - by jake
    Hi there. I've been trying to solve this problem for a few days now but it seems I haven't grasped the concept of recursion,yet. I have to build a program in C (recursion is a must here but loops are allowed as well) which does the following: The user inputs 2 different strings.For example: String 1 - ABC String 2 - DE The program is supposed to print strings which are combined of the ones the user has entered. the rule is that the inner order of the letters in each string (1&2) must remain. That's the output for string1=ABC & string2=DE ": abcde abdce abdec adbce adbec adebc dabce dabec daebc deabc If anyone could give me a hand here, it would be great. Thanks guys.

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  • Array Vs. Linked List

    - by Onorio Catenacci
    I apologize--this question may be a bit open-ended but I think there are probably definite, quantifiable answers to it so I'll post it anyway. A person I know is trying to learn C++ and software development (+1 to him) and he asked me why someone would want to use a linked list in preference to an array. Coding a linked list is, no doubt, a bit more work than using an array and he wondered what would justify the additional effort. I gave him the answer I know: insertion of new elements is trivial in linked list but it's a major chore in an array. But then I got to thinking about it a bit more. Besides the ease of insertion of a new element into a linked list are there other advantages to using a linked list to store a set of data vs. storing it in an array? As I said, I'm not meaning to start a long and drawn-out discussion. I'm just looking for other reasons that a developer might prefer a linked list to an array.

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  • Racket list in struct

    - by Tim
    I just started programming with Racket and now I have the following problem. I have a struct with a list and I have to add up all prices in the list. (define-struct item (name category price)) (define some-items (list (make-item "Book1" 'Book 40.97) (make-item "Book2" 'Book 5.99) (make-item "Book3" 'Book 20.60) (make-item "Item" 'KitchenAccessory 2669.90))) I know that I can return the price with: (item-price (first some-items)) or (item-price (car some-items)). The problem is, that I dont know how I can add up all Items prices with this. Answer to Óscar López: May i filled the blanks not correctly, but Racket mark the code black when I press start and don't return anything. (define (add-prices items) (if (null? items) (+ 0 items) ; Here I don't really know what to write for a 0. ; I tried differnt thnigs like null and this version. (+ (item-price (first some-items)) (add-prices (item-price (rest some-items))))))

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  • How do you solve the 15-puzzle with A-Star or Dijkstra's Algorithm?

    - by Sean
    I've read in one of my AI books that popular algorithms (A-Star, Dijkstra) for path-finding in simulation or games is also used to solve the well-known "15-puzzle". Can anyone give me some pointers on how I would reduce the 15-puzzle to a graph of nodes and edges so that I could apply one of these algorithms? If I were to treat each node in the graph as a game state then wouldn't that tree become quite large? Or is that just the way to do it?

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  • polynomial multiplication using fastfourier transform

    - by mawia
    i am going through the above topic from CLRS(CORMEN) (page 834) and I got stuck at this point. Can anybody please explain how the following expression, A(x)=A^{[0]}(x^2) +xA^{[1]}(x^2) follows from, n-1 ` S a_j x^j j=0 Where, A^{[0]} = a_0 + a_2x + a_4a^x ... a_{n-2}x^{\frac{n}{2-1}} A^{[1]} = a_1 + a_3x + a_5a^x ... a_{n-1}x^{\frac{n}{2-1}} WITH REGARDS THANKS

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  • Writing a blackjack console program in Java

    - by user337465
    Hello, I have an assignment of making a blackjack like program in a class. My first problem I am dealing with is creating an array of the cards. The professor wants an array setup with a txt file with the following format. 2 of hearts 2 of diamonds 2 of spades 2 of clubs 3 of hearts 3 of diamonds 3 of spades This goes on till face cards when it replaces the number with jack, queen, king, ace. Following the professors requirements, How would I take input from the txt file and just store the number and the hearts,diamonds,spades, and clubs. Thank you for the help

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  • Beginner problems with references to arrays in python 3.1.1

    - by Protean
    As part of the last assignment in a beginner python programing class, I have been assigned a traveling sales man problem. I settled on a recursive function to find each permutation and the sum of the distances between the destinations, however, I am have a lot of problems with references. Arrays in different instances of the Permute and Main functions of TSP seem to be pointing to the same reference. from math import sqrt class TSP: def __init__(self): self.CartisianCoordinates = [['A',[1,1]], ['B',[2,2]], ['C',[2,1]], ['D',[1,2]], ['E',[3,3]]] self.Array = [] self.Max = 0 self.StoredList = ['',0] def Distance(self, i1, i2): x1 = self.CartisianCoordinates[i1][1][0] y1 = self.CartisianCoordinates[i1][1][1] x2 = self.CartisianCoordinates[i2][1][0] y2 = self.CartisianCoordinates[i2][1][1] return sqrt(pow((x2 - x1), 2) + pow((y2 - y1), 2)) def Evaluate(self): temparray = [] Data = [] for i in range(len(self.CartisianCoordinates)): Data.append([]) for i1 in range(len(self.CartisianCoordinates)): for i2 in range(len(self.CartisianCoordinates)): if i1 != i2: temparray.append(self.Distance(i1, i2)) else: temparray.append('X') Data[i1] = temparray temparray = [] self.Array = Data self.Max = len(Data) def Permute(self,varray,index,vcarry,mcarry): #Problem Class array = varray[:] carry = vcarry[:] for i in range(self.Max): print ('ARRAY:', array) print (index,i,carry,array[index][i]) if array[index][i] != 'X': carry[0] += self.CartisianCoordinates[i][0] carry[1] += array[index][i] if len(carry) != self.Max: temparray = array[:] for j in range(self.Max):temparray[j][i] = 'X' index = i mcarry += self.Permute(temparray,index,carry,mcarry) else: return mcarry print ('pass',mcarry) return mcarry def Main(self): out = [] self.Evaluate() for i in range(self.Max): array = self.Array[:] #array appears to maintain the same reference after each copy, resulting in an incorrect array being passed to Permute after the first iteration. print (self.Array[:]) for j in range(self.Max):array[j][i] = 'X' print('I:', i, array) out.append(self.Permute(array,i,[str(self.CartisianCoordinates[i][0]),0],[])) return out SalesPerson = TSP() print(SalesPerson.Main()) It would be greatly appreciated if you could provide me with help in solving the reference problems I am having. Thank you.

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  • Java: why is declaration not sufficient in interface?

    - by HH
    Big class contains Format-interfcase and Format-class. The Format-class contains the methods and the interface has the values of the fields. I could have the fields in the class Format but the goal is with Interface. So do I just create dummy-vars to get the errors away, design issue or something ELSE? KEY: Declaration VS Initialisation Explain by the terms, why you have to init in interface. What is the logic behind it? To which kind of problems it leads the use of interface? Sample Code having the init-interface-problem import java.util.*; import java.io.*; public class FormatBig { private static class Format implements Format { private static long getSize(File f){return f.length();} private static long getTime(File f){return f.lastModified();} private static boolean isFile(File f){if(f.isFile()){return true;}} private static boolean isBinary(File f){return Match.isBinary(f);} private static char getType(File f){return Match.getTypes(f);} private static String getPath(File f){return getNoErrPath(f);} //Java API: isHidden, --- SYSTEM DEPENDED: toURI, toURL Format(File f) { // PUZZLE 0: would Stack<Object> be easier? size=getSize(f); time=getTime(f); isfile=isFile(f); isBinary=isBinary(f); type=getType(f); path=getPath(f); //PUZZLE 1: how can simplify the assignment? values.push(size); values.push(time); values.push(isfile); values.push(isBinary); values.push(type); values.push(path); } } public static String getNoErrPath(File f) { try{return f.getCanonicalPath(); }catch(Exception e){e.printStackTrace();} } public static final interface Format { //ERR: IT REQUIRES "=" public long size; public long time; public boolean isFile=true; //ERROR goes away if I initialise wit DUMMY public boolean isBinary; public char type; public String path; Stack<Object> values=new Stack<Object>(); } public static void main(String[] args) { Format fm=new Format(new File(".")); for(Object o:values){System.out.println(o);} } }

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  • More advanced usage of interfaces

    - by owca
    To be honest I'm not quite sure if I understand the task myself :) I was told to create class MySimpleIt, that implements Iterator and Iterable and will allow to run the provided test code. Arguments and variables of objects cannot be either Collections or arrays. The code : MySimpleIt msi=new MySimple(10,100, MySimpleIt.PRIME_NUMBERS); for(int el: msi) System.out.print(el+" "); System.out.println(); msi.setType(MySimpleIterator.ODD_NUMBERS); msi.setLimits(15,30); for(int el: msi) System.out.print(el+" "); System.out.println(); msi.setType(MySimpleIterator.EVEN_NUMBERS); for(int el: msi) System.out.print(el+" "); System.out.println(); The result I should obtain : 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 15 17 19 21 23 25 27 29 16 18 20 22 24 26 28 30 And here's my code : import java.util.Iterator; interface MySimpleIterator{ static int ODD_NUMBERS=0; static int EVEN_NUMBERS = 1; static int PRIME_NUMBERS = 2; int setType(int i); } public class MySimpleIt implements Iterable, Iterator, MySimpleIterator { public MySimple my; public MySimpleIt(MySimple m){ my = m; } public int setType(int i){ my.numbers = i; return my.numbers; } public void setLimits(int d, int u){ my.down = d; my.up = u; } public Iterator iterator(){ Iterator it = this.iterator(); return it; } public void remove(){ } public Object next(){ Object o = new Object(); return o; } public boolean hasNext(){ return true; } } class MySimple { public int down; public int up; public int numbers; public MySimple(int d, int u, int n){ down = d; up = u; numbers = n; } } In the test code I have error in line when creating MySimpleIt msi object, as it finds MySimple instead of MySimpleIt. Also I have errors in for-each loops, because compiler wants 'ints' there instead of Object. Anyone has any idea on how to solve it ?

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  • How does a web browser work?

    - by Anil Namde
    I have tried to find good documentation of browsers using google but failed to get what I am looking for. Can someone guide me to a location where I can actually see how a browser functions? The whole purpose of the exercise is to get answers for following queries and more like these: How images, CSS and JS files are downloaded How JS is executed How an Ajax request is executed and many more like these..... Thanks all,

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  • Proving that a function f(n) belongs to a Big-Theta(g(n))

    - by PLS
    Its a exercise that ask to indicate the class Big-Theta(g(n)) the functions belongs to and to prove the assertion. In this case f(n) = (n^2+1)^10 By definition f(n) E Big-Theta(g(n)) <= c1*g(n) < f(n) < c2*g(n), where c1 and c2 are two constants. I know that for this specific f(n) the Big-Theta is g(n^20) but I don't know who to prove it properly. I guess I need to manipulate this inequality but I don't know how

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  • How to use XPath to filter elements by TextContent? get parent by axis?

    - by Michael Mao
    Hi all: I've found a similar question on SO, however, that seems not exactly what I wanna achieve: Say, this is a sample XML file: <root> <item> <id isInStock="true">10001</id> <category>Loose Balloon</category> </item> <item> <id isInStock="true">10001</id> <category>Bouquet Balloon</category> </item> <item> <id isInStock="true">10001</id> <category>Loose Balloon</category> </item> </root> If I wanna get a "filtered" subset of the item elements from this XML, how could I use an XPath expression to directly address that? XPathExpression expr = xpath.compile("/root/item/category/text()"); I now know this would evaluate to be the collection of all the TextContent from the categories, however, that means I have to use a collection to store the values, then iterate, then go back to grab other related info such as the item id again. Another question is : how could I refer to the parent node properly? Say, this xpath expression would get me the collection of all the id nodes, right? But what I want is the collection of item nodes: XPathExpression expr = xpath.compile("/root/item/id[@isInStock='true']"); I know I should use the "parent" axis to refer to that, but I just cannot make it right... Is there a better way of doing this sort of thing? Learning the w3cschools tutorials now... Sorry I am new to XPath in Java, and thanks a lot in advance.

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