Search Results

Search found 35068 results on 1403 pages for 'adam right'.

Page 120/1403 | < Previous Page | 116 117 118 119 120 121 122 123 124 125 126 127  | Next Page >

  • Setup and configure a MVC4 project for Cloud Service(web role) and SQL Azure

    - by MagnusKarlsson
    I aim at keeping this blog post updated and add related posts to it. Since there are a lot of these out there I link to others that has done kind of the same before me, kind of a blog-DRY pattern that I'm aiming for. I also keep all mistakes and misconceptions for others to see. As an example; if I hit a stacktrace I will google it if I don't directly figure out the reason for it. I will then probably take the most plausible result and try it out. If it fails because I misinterpreted the error I will not delete it from the log but keep it for future reference and for others to see. That way people that finds this blog can see multiple solutions for indexed stacktraces and I can better remember how to do stuff. To avoid my errors I recommend you to read through it all before going from start to finish.The steps:Setup project in VS2012. (msdn blog)Setup Azure Services (half of mpspartners.com blog)Setup connections strings and configuration files (msdn blog + notes)Export certificates.Create Azure package from vs2012 and deploy to staging (same steps as for production).Connections string error Set up the visual studio project:http://blogs.msdn.com/b/avkashchauhan/archive/2011/11/08/developing-asp-net-mvc4-based-windows-azure-web-role.aspx Then login in to Azure to setup the services:Stop following this guide at the "publish website" part since we'll be uploading a package.http://www.mpspartners.com/2012/09/ConfiguringandDeployinganMVC4applicationasaCloudServicewithAzureSQLandStorage/ When set up (connection strings for debug and release and all), follow this guide to set up the configuration files:http://msdn.microsoft.com/en-us/library/windowsazure/hh369931.aspxTrying to package our application at this step will generate the following warning:3>MvcWebRole1(0,0): warning WAT170: The configuration setting 'Microsoft.WindowsAzure.Plugins.Diagnostics.ConnectionString' is set up to use the local storage emulator for role 'MvcWebRole1' in configuration file 'ServiceConfiguration.Cloud.cscfg'. To access Windows Azure storage services, you must provide a valid Windows Azure storage connection string. Right click the web role under roles in solution manager and choose properties. Choose "Service configuration: Cloud". At "specify storage account credentials" we will copy/paste our account name and key from the Azure management platform.3.1 4. Right click Remote desktop Configuration and select certificate and export to file. We need to allow it in Portal manager.4.15 Now right click the cloud project and select package.5.1 Showing dialogue box. 5.2 Package success Now copy the path to the packaged file and go to management portal again. Click your web role and choose staging (or production). Upload. 5.3Tick the box about the single instance if that's what you want or you don't know what it means. Otherwise the following will happen (see image 4.6)5.4 Dialogue box When you have clicked the symbol for accept- button you will see the following screen with some green indicators down at the right corner. Click them if you want to see status.5.5 Information screen.5.6 "Failed to deploy application. The upload application has at least one role with only one instance. We recommend that you deploy at least two instances per role to ensure high availability in case one of the instances becomes unavailable. "To fix, go to step 5.4If you forgot to (or just didn't know you were supposed to) export your certificates. The following error will occur. Side note, the following thread suggests. To prevent: "Enable Remote Desktop for all roles" when right-clicking BIAB and choosing "Package". But in my case it was the not so present certificates. I fund the solution here.http://social.msdn.microsoft.com/Forums/en-US/dotnetstocktradersampleapplication/thread/0e94c2b5-463f-4209-86b9-fc257e0678cd5.75.8 Success! 5.9 Nice URL n' all. (More on that at another blog post).6. If you try to login and getWhen this error occurs many web sites suggest this is because you need:http://nuget.org/packages/Microsoft.AspNet.Providers.LocalDBOr : http://nuget.org/packages/Microsoft.AspNet.ProvidersBut it can also be that you don't have the correct setup for converting connectionstrings between your web.config to your debug.web.config(or release.web.config, whichever your using).Run as suggested in the "ordinary project in your solution. Go to the management portal and click update.

    Read the article

  • Joomla Admin module in "New Article" form?

    - by Honus Wagner
    In Joomla 1.5, I am interested in developing a fairly simple module that I was hoping would live on the right side of the create new article page. I've created a handful of modules before, one on the admin page at the dashboard that is on the right side that you click to expand/collapse. So, can I create a module that I could attach to any new article form on the right side, somewhere under "advanced settings" or something? Thanks.

    Read the article

  • CSS layout with 2 columns, taking up all width of browser, where left column can collapse

    - by Matt Dawdy
    I want to have a 2 column layout, and have the left column able to be 200 px at first, and have a "shrink" button to shrink it down to 10px, and have the right column expand to fill all the rest of the available space. Then if they click on the "show" button (which will be all they see in the now 10px wide left column) have the left grow back to 200px and have the right column shrink by that amount. I can't figure out how to make the right column grown and shrink without knowing the exact width of the window. I hope this makes sense, and I really hope someone can point me in the right direction. Browser requirements are IE8, FF3.6, Safari, and Chrome, so in theory I can use some advanced CSS techniques. At least I don't have to support IE6.

    Read the article

  • Add inset box-shadow on Google Maps element

    - by linkyndy
    I am willing to add some inset box-shadow to a tag that is containing a Google Maps element. However, it seems nothing happens, probably because Google loads some other div's in the original element, hence covering the generated box-shadow. How can I achieve this effect? Here's the code I have: <section id="map-container"> <figure id="map"></figure> </section> #map-container { position: relative; float: right; width: 700px; background-color: #F9FAFC; border-top-right-radius: 5px; border-bottom-right-radius: 5px; } #map { position: relative; height: 400px; border-top-right-radius: 5px; border-bottom-right-radius: 5px; box-shadow: 0 1px 0 0 #F6F7FB inset, 0 -1px 0 0 #E0E5E1 inset, 0 -2px 0 0 #EBEBED inset, 0 -3px 0 0 #F4F4F6 inset; } Thank you!

    Read the article

  • Existing web-site CSS replacement (re-skinning) best-practices without changing the HTML

    - by Enigmativity
    I can see a number of other good answers to questions relating to CSS best-practices on stack overflow: How to Manage CSS Explosion CSS Conventions / Code Layout Models Are there any CSS standards that I should follow while writing my first stylesheet? What is the best method for tidying CSS? Best Practices - CSS Stylesheet Formatting But I think I have a different problem. I'm trying to "re-skin" an existing site that has been nicely built using div's and ul's, etc, and it has a good existing CSS file, but when I start making changes to the CSS I quickly find that I break the layout. My feeling is that it is very hard to get a feel for how all the CSS will work together and indeed what CSS is affecting parent and sibling elements in the HTML. So, my question is "what are the best-practices around re-skinning an existing web-site by replacing the CSS only and not modifying the existing HTML?" I can't change the classes, ids, node hierarchy, etc. An example of the particular site that I am trying to re-skin is http://demo.nopcommerce.com/. The existing CSS can be as complicated/detailed as this extract from the main CSS file: .header-selectors-wrapper { text-align: right; float: right; width: 500px; } .header-currencyselector { float: right; } .header-languageselector { float: left; } .header-taxDisplayTypeSelector { float: right; } .header-links-wrapper { float: right; text-align: right; width: 570px; } .header-links { border: solid 1px #9a9a9a; padding: 5px 5px 5px 5px; margin-bottom: 5px; display: inline-table; } .order-summary-content .cart .cart-item-row td, .wishlist-content .cart .cart-item-row td { border-bottom: 1px solid #c5c5c5; vertical-align: middle; line-height: 30px; } .order-summary-content .cart .cart-item-row td.product, .wishlist-content .cart .cart-item-row td.product { text-align: left; padding: 0px 10px 0px 10px; } .order-summary-content .cart .cart-item-row td.product a, .wishlist-content .cart .cart-item-row td.product a { font-weight: bold; } Any help would be appreciated.

    Read the article

  • CSS layout mystery

    - by selfthinker
    Among the many two (or three) column layout techniques I sometimes use the following one: <div class="variant1"> <div class="left1"> <div class="left2"> left main content </div> </div> <div class="right1"> <div class="right2"> right sidebar </div> </div> </div> together with: .variant1 .left1 { float: left; margin-right: -200px; width: 100%; } .variant1 .left1 .left2 { margin-right: 200px; } .variant1 .right1 { float: right; width: 200px; } This works in all major browsers. But for some very strange reason exactly the same technique but reversed doesn't work: <div class="variant2"> <div class="left1"> <div class="left2"> left main content </div> </div> <div class="right1"> <div class="right2"> right sidebar </div> </div> </div> with .variant2 .left1 { float: left; width: 200px; } .variant2 .right1 { float: right; margin-left: -200px; width: 100%; } .variant2 .right1 .right2 { margin-left: 200px; } In the second variant all text in the sidebar cannot be selected and all links cannot be clicked. This is at least true for Firefox and Chrome. In IE7 the links can at least be clicked and Opera seems completely fine. Does anyone know the reason for this strange behaviour? Is it a browser bug? Please note: I am not looking for a working two column CSS layout technique, I know there are loads of them. And I don't necessarily need this technique to work. I only like to understand the reason why the second variant behaves like it does. Here is a link to a small test page which should illustrate the problem: http://selfthinker.org/stuff/css_layout_mystery.html

    Read the article

  • Tail-recursive merge sort in OCaml

    - by CFP
    Hello world! I’m trying to implement a tail-recursive list-sorting function in OCaml, and I’ve come up with the following code: let tailrec_merge_sort l = let split l = let rec _split source left right = match source with | [] -> (left, right) | head :: tail -> _split tail right (head :: left) in _split l [] [] in let merge l1 l2 = let rec _merge l1 l2 result = match l1, l2 with | [], [] -> result | [], h :: t | h :: t, [] -> _merge [] t (h :: result) | h1 :: t1, h2 :: t2 -> if h1 < h2 then _merge t1 l2 (h1 :: result) else _merge l1 t2 (h2 :: result) in List.rev (_merge l1 l2 []) in let rec sort = function | [] -> [] | [a] -> [a] | list -> let left, right = split list in merge (sort left) (sort right) in sort l ;; Yet it seems that it is not actually tail-recursive, since I encounter a "Stack overflow during evaluation (looping recursion?)" error. Could you please help me spot the non tail-recursive call in this code? I've searched quite a lot, without finding it. Cout it be the let binding in the sort function? Thanks a lot, CFP.

    Read the article

  • CSS: Aligning problem with rounded corners in IE 6/7 but ok in IE8/ Firefox etc

    - by mark smith
    Hi there, can anyone help? I have a problem aligning rounded corners in IE6/7. Basically everything seems to work in Firefox / IE8 but in IE6/7 the left / center / and right divs get misaligned. This basically shows exactly what i am refering to. here is the example in IE8 and everything works ok http://es.drop.io/ern0fye/asset/ie8-jpg And here is the problem (this example is running in IE8 with compat mode set to IE7) http://es.drop.io/ern0fye/asset/ie7-jpg I seem to remember there being a bug in IE6/7 with lineheight or similar but i don't recall exactly. I will paste the CSS and HTML below it is very very simple. Basically there is a left div that holds the left corner image and center div which has a background of RED which is the same as the corner images and finally a right div which holds the right corner image. I would appreciate any input anyone has. Thanks in advance. Here is the CSS .vl-top-left { float:left; width:12px; height:12px; } .vl-top-center { float:left; width: 485px; background-color: #F04A23; height:12px; } .vl-top-right { float:left; height:12px; width:12px; } and the HTML is :- <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <title></title> <link href="Stylesheet1.css" rel="stylesheet" type="text/css" /> </head> <body> <div class="vl-top-left"> <img src="content/images/esquina_sup_izq.gif" width="12" height="12"> </div> <div class="vl-top-center"> &nbsp; </div> <div class="vl-top-right"> <img src="content/images/esquina_sup_der.gif" width="12" height="12"> </div> </body> </html> EDIT Applied also margin:0 and padding:0 on the body and on each DIV but still the left and right div drops down as per the screenshot

    Read the article

  • SED - Regular Expression over multiple lines

    - by herrherr
    Hi there, I'm stuck with this for several hours now and cycled through a wealth of different tools to get the job done. Without success. It would be fantastic, if someone could help me out with this. Here is the problem: I have a very large CSV file (400mb+) that is not formatted correctly. Right now it looks something like this: Alan Smithee ist ein Anagramm von „The [...] „Alan Smythee“, und „Adam Smithee“." ,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen. ,Aussagenlogik As you can probably see the words ",Alan Smithee" and ",Aussagenlogik" should actually be on the same line as the foregoing sentence. Then it would look something like this: Alan Smithee ist ein Anagramm von „The Smitheeeee [...] „Alan Smythee“, und „Adam Smithee“.,Alan Smithee Die Aussagenlogik ist der Bereich der Logik, der sich mit [...] ihrer Teilaussagen bestimmen.,Aussagenlogik Please note that the end of the sentence can contain quotes or not. In the end they should be replaced too. Here is what I came up with so far: sed -n '1h;1!H;${;g;s/\."?.*,//g;p;}' out.csv > out1.csv This should actually get the job done of matching the expression over multiple lines. Unfortunately it doesn't :) The expression is looking for the dot at the end of the sentence and the optional quotes plus a newline character that I'm trying to match with .*. Help much appreciated. And it doesn't really matter what tool gets the job done (awk, perl, sed, tr, etc.). Thanks, Chris

    Read the article

  • implement alphabetical scroll in MPMediaPickerController app

    - by Pavan
    If you go to the iphone library and then go to songs, you will see the songs being displayed in a similar way to the MPMediaItemPicker class does. The only difference is that the ipod application shows the search bar right at the top of the list and also a nice alphabetical scroll on the right hand side whereas the MPMediaItemPicker class only isplays a simple scroll going up and down. How can i implement an alphabetical scroll on the right in the MPMediaItemPicker class? Can someone please help me.

    Read the article

  • jQuery CSS plugin that returns computed style of element to pseudo clone that element?

    - by Keith Bentrup
    I'm looking for a way using jQuery to return an object of computed styles for the 1st matched element. I could then pass this object to another call of jQuery's css method. For example, with width, I can do the following to make the 2 divs have the same width: $('#div2').width($('#div1').width()); It would be nice if I could make a text input look like an existing span: $('#input1').css($('#span1').css()); where .css() with no argument returns an object that can be passed to .css(obj). (I can't find a jQuery plugin for this, but it seems like it should exist. If it doesn't exist, I'll turn mine below into a plugin and post it with all the properties that I use.) Basically, I want to pseudo clone certain elements but use a different tag. For example, I have an li element that I want to hide and put an input element over it that looks the same. When the user types, it looks like they are editing the element inline. I'm also open to other approaches for this pseudo cloning problem for editing. Any suggestions? Here's what I currently have. The only problem is just getting all the possible styles. This could be a ridiculously long list. jQuery.fn.css2 = jQuery.fn.css; jQuery.fn.css = function() { if (arguments.length) return jQuery.fn.css2.apply(this, arguments); var attr = ['font-family','font-size','font-weight','font-style','color', 'text-transform','text-decoration','letter-spacing','word-spacing', 'line-height','text-align','vertical-align','direction','background-color', 'background-image','background-repeat','background-position', 'background-attachment','opacity','width','height','top','right','bottom', 'left','margin-top','margin-right','margin-bottom','margin-left', 'padding-top','padding-right','padding-bottom','padding-left', 'border-top-width','border-right-width','border-bottom-width', 'border-left-width','border-top-color','border-right-color', 'border-bottom-color','border-left-color','border-top-style', 'border-right-style','border-bottom-style','border-left-style','position', 'display','visibility','z-index','overflow-x','overflow-y','white-space', 'clip','float','clear','cursor','list-style-image','list-style-position', 'list-style-type','marker-offset']; var len = attr.length, obj = {}; for (var i = 0; i < len; i++) obj[attr[i]] = jQuery.fn.css2.call(this, attr[i]); return obj; } Edit: I've now been using the code above for awhile. It works well and behaves exactly like the original css method with one exception: if 0 args are passed, it returns the computed style object. As you can see, it immediately calls the original css method if that's the case that applies. Otherwise, it gets the computed styles of all the listed properties (gathered from Firebug's computed style list). Although it's getting a long list of values, it's quite fast. Hope it's useful to others.

    Read the article

  • Check Checkboxes dynamically

    - by Selom
    Hi, ive been dealing with this for some time now and need your help. well I have an array $arrayAmenities which contains a combination of the following data based on what is fetched from the database: Air Conditioned Bar Brunch Party Room Tea Room Terrace Valet I would like the application to dynamically check the following set of checkboxes based on the data contained in the array. With my code only one checkbox is checked based on the first data contained in the array. Can you please tell what Im missing? Thanks for answering. code: //get amenities one by one in order to set the checkboxes $arrayAmenities = explode(',', $rest_amenities ); $i=0; while(count($arrayAmenities) > $i) { var_dump($arrayAmenities[$i]); switch($arrayAmenities[$i]) { case 'Air Conditioned': $checkedAir = 'checked=true'; break; case 'Bar': $checkedBar = 'checked=true'; break; case 'Brunch': $checkedBru = 'checked=true'; break; case 'Party Room'; $checkedPar = 'checked=true'; break; } $i+=1; } } checkboxes <table cellpadding="0" cellspacing="0" style="font-size:10px"> <tr> <td style="border-top:1px solid #CCC;border-right:1px solid #CCC;border-left:1px solid #CCC; padding-left:5px ">Air Conditioned <input type="checkbox" name="air_cond" <?php print $checkedAir;?> value="Air Conditioned"></td> <td style="padding-left:10px; border-top:1px solid #CCC;border-right:1px solid #CCC;">Bar <input type="checkbox" name="bar" value="Bar" <?php print $checkedBar;?>></td> <td style="padding-left:10px; border-top:1px solid #CCC;border-right:1px solid #CCC; ">Brunch <input type="checkbox" name="brunch" value="Brunch" <?php print $checkedBru;?>></td> </tr> <tr> <td style="border-top:1px solid #CCC;border-right:1px solid #CCC; border-bottom:1px solid #CCC; border-left:1px solid #CCC; padding-left:5px">Party Room <input <?php print $checkedPar;?> type="checkbox" name="party_room" value="Party Room" ></td> <td style="padding-left:10px; border-top:1px solid #CCC;border-right:1px solid #CCC; border-bottom:1px solid #CCC;">Tea Room <input type="checkbox" name="tea_room" value="Tea Room" ></td> <td style="padding-left:10px; border-top:1px solid #CCC;border-right:1px solid #CCC; border-bottom:1px solid #CCC;">Terrace <input type="checkbox" name="terrace" value="Terrace"></td> </tr> <tr> <td colspan="3" style="border-bottom:1px solid #CCC; border-left:1px solid #CCC; border-right:1px solid #CCC; padding-left:5px">Valet <input type="checkbox" name="valet" value="Valet" ></td> </tr> </table>

    Read the article

  • Binary Search Tree in C

    - by heapzero
    Hi, I'm a Python guy. Learning C language and I've been trying to implement Binary Search Tree in C. I wrote down the code, and I've been trying from few hours but, not able to get the output as expected. Please help! Please correct me. #include<stdlib.h> #include<stdio.h> typedef int ElementType; typedef struct TreeNode { ElementType element; struct TreeNode *left, *right; } TreeNode; TreeNode *createTree(){ //Create the root of tree TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = 0; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *createNode(ElementType X){ //Create a new leaf node and return the pointer TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = X; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *insertElement(TreeNode *node, ElementType X){ //insert element to Tree if(node==NULL){ return createNode(X); } else{ if(X < node->element){ node->left = insertElement(node->left, X); } else if(X > node->element){ node->right = insertElement(node->right, X); } else if(X == node->element){ printf("Oops! the element is already present in the tree."); } } } TreeNode *displayTree(TreeNode *node){ //display the full tree if(node==NULL){ return; } displayTree(node->left); printf("| %d ", node->element); displayTree(node->right); } main(){ //pointer to root of tree #2 TreeNode *TreePtr; TreeNode *TreeRoot; TreeNode *TreeChild; //Create the root of tree TreePtr = createTree(); TreeRoot = TreePtr; TreeRoot->element = 32; printf("%d\n",TreeRoot->element); insertElement(TreeRoot, 8); TreeChild = TreeRoot->left; printf("%d\n",TreeChild->element); insertElement(TreeRoot, 2); insertElement(TreeRoot, 7); insertElement(TreeRoot, 42); insertElement(TreeRoot, 28); insertElement(TreeRoot, 1); insertElement(TreeRoot, 4); insertElement(TreeRoot, 5); // the output is not as expected :( displayTree(TreeRoot); }

    Read the article

  • Create matplotlib legend out of the figure

    - by Werner
    I added the legend this way: leg = fig.legend((l0,l1,l2,l3,l4,l5,l6), ('0 Cl : r2, slope, origin', '1 Cl :'+str(r1b)+' , '+str(m1)+' , '+str(b1), '2 Cl :'+str(r2b)+' , '+str(m2)+' , '+str(b2), '3 Cl :'+str(r3b)+' , '+str(m3)+' , '+str(b3), '4 Cl :'+str(r4b)+' , '+str(m4)+' , '+str(b4), '5 Cl :'+str(r5b)+' , '+str(m5)+' , '+str(b5), '6 Cl :'+str(r6b)+' , '+str(m6)+' , '+str(b6), ), 'upper right') but the legend appears inside the plot. How can I tell matplotlib to put it to the right of the plot and at the right?

    Read the article

  • How to detect the position of window in vim

    - by Yogesh Arora
    I am trying to customize the mappings for vimdiff and make them similar to winmerge In a vertical 2 way split, I want to map alt-left <a-left> to move current diff to left side and alt-right <a-right> to move current diff to right side. For merging i can use :diffg and :diffp. But I need to know which split i am in so that i can use :diffg/:diffp in that. Is there any way by which i can detect which split i am in. Specifically is there is any way by which i can know whether the cursor is in left split or right split

    Read the article

  • How to make a div to fill a remaining horizontal space (a very simple but annoying problem for CSS e

    - by janoChen
    I have 2 divs: one in the left side and one in the right side of my page. The one in the left side has fixed width and I want the one of the right side to fill the remaining space. The one on the right side is the navigation and I want it to to fill the remaining space on it right side: My CSS: #search { width: 160px; height: 25px; float: left; background-color: #FFF; } #navigation { width: 780 float: left; /*background-color: url('../images/transparent.png') ;*/ background-color: #A53030; } My Html: <div id="search"> </div> <?php include("navigation.html"); ?> <div id="left-column"> Thank in advance!

    Read the article

  • adding nodes to a binary search tree randomly deletes nodes

    - by SDLFunTimes
    Hi, stack. I've got a binary tree of type TYPE (TYPE is a typedef of data*) that can add and remove elements. However for some reason certain values added will overwrite previous elements. Here's my code with examples of it inserting without overwriting elements and it not overwriting elements. the data I'm storing: struct data { int number; char *name; }; typedef struct data data; # ifndef TYPE # define TYPE data* # define TYPE_SIZE sizeof(data*) # endif The tree struct: struct Node { TYPE val; struct Node *left; struct Node *rght; }; struct BSTree { struct Node *root; int cnt; }; The comparator for the data. int compare(TYPE left, TYPE right) { int left_len; int right_len; int shortest_string; /* find longest string */ left_len = strlen(left->name); right_len = strlen(right->name); if(right_len < left_len) { shortest_string = right_len; } else { shortest_string = left_len; } /* compare strings */ if(strncmp(left->name, right->name, shortest_string) > 1) { return 1; } else if(strncmp(left->name, right->name, shortest_string) < 1) { return -1; } else { /* strings are equal */ if(left->number > right->number) { return 1; } else if(left->number < right->number) { return -1; } else { return 0; } } } And the add method struct Node* _addNode(struct Node* cur, TYPE val) { if(cur == NULL) { /* no root has been made */ cur = _createNode(val); return cur; } else { int cmp; cmp = compare(cur->val, val); if(cmp == -1) { /* go left */ if(cur->left == NULL) { printf("adding on left node val %d\n", cur->val->number); cur->left = _createNode(val); } else { return _addNode(cur->left, val); } } else if(cmp >= 0) { /* go right */ if(cur->rght == NULL) { printf("adding on right node val %d\n", cur->val->number); cur->rght = _createNode(val); } else { return _addNode(cur->rght, val); } } return cur; } } void addBSTree(struct BSTree *tree, TYPE val) { tree->root = _addNode(tree->root, val); tree->cnt++; } The function to print the tree: void printTree(struct Node *cur) { if (cur == 0) { printf("\n"); } else { printf("("); printTree(cur->left); printf(" %s, %d ", cur->val->name, cur->val->number); printTree(cur->rght); printf(")\n"); } } Here's an example of some data that will overwrite previous elements: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "rooty"; myData2.number = 1; myData2.name = "lefty"; myData3.number = 10; myData3.name = "righty"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which will print: (( righty, 10 ) lefty, 1 ) Finally here's some test data that will go in the exact same spot as the previous data, but this time no data is overwritten: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "i"; myData2.number = 5; myData2.name = "h"; myData3.number = 5; myData3.name = "j"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which prints: (( j, 5 ) i, 5 ( h, 5 ) ) Does anyone know what might be going wrong? Sorry if this post was kind of long.

    Read the article

  • CSS : How can I add shadow to a label or box

    - by Rachel
    I have an button just as have Ask Question on SO and here is the CSS for it: .rfs .grey_btn{ float: right; margin: 15px 5px; } Now I have to add border shadow to it and I have tried border-radius and box-shadow but it does not give me proper result. Also other question is that I have a label or box say and now I want to increase size of that box so that I have move the text inside that box to right, currently if I move it to right than it reaches the end limit of box and so I want to increase the size of box so that I can push text more towards right. Hope I have made my question clear. Any guidance would be highly appreciated. Thanks.

    Read the article

  • Wrap text around an image in rails and prawn

    - by stevenheidel
    I have a document with dynamic image and dynamic text and would like the text around the image. The image is right aligned on the landscape page. Here is what I have so far: pdf.bounding_box([0,pdf.bounds.top - 50], :width => pdf.bounds.width, :height => pdf.bounds.height-50) do pdf.text @article.title, :size => 30, :style => :bold pdf.text @article.content, :align => :left # image pdf.bounding_box([pdf.bounds.right - 250, pdf.bounds.top], :width => 250, :height => 250) do pdf.image image_path, :width => 250 end end The text goes right underneath the image. I tried doing this http://stackoverflow.com/questions/2085151/ruby-prawn-how-to-wrap-text-around-an-aligned-right-image but it didn't work. Help is appreciated, thanks.

    Read the article

  • Moving the Gallery view to the next image on one swipe in Android?

    - by sunil
    Hi All, I have four images in the Gallery View. When we do swipe from left to right or right to left the Gallery View moves all the images i.e if I swipe from left to right from the first image then it will move to all the four images. What I want is that when I swipe it should only move to the next image. Can someone let me know how is this possible? Hope to get a reply soon. Regards Sunil

    Read the article

  • Sizers... - wxPython

    - by Francisco Aleixo
    Ok, so I'm learning about sizers in wxPython and I was wondering if it was possible to do something like: ============================================== |WINDOW TITLE _ [] X| |============================================| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxNOTEBOOKxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx| |________ ___________| |IMAGE | |LoginForm | |________| |___________| ============================================== NOTE:Yeah, I literally got this from http://stackoverflow.com/questions/1892110/wxpython-picking-the-right-sizer-to-use-in-an-application With NOTEBOOK expanded to left and bottom, IMAGE to align to left and bottom and loginform align to right and bottom and I managed to do almost everything but now I have a problem.. The problem is that I can't align Loginform and Image separately (im using Box Sizers), and I would like to. This is the code I'm using that is causing the problem at the moment, any help is appreciated. NOTE:The code might be (HUGELY) sloppy as I'm still learning box sizers. sizer = wx.BoxSizer(wx.VERTICAL) sizer1 = wx.BoxSizer(wx.HORIZONTAL) sizer1.Add(self.nb,1, wx.EXPAND) sizer.Add(sizer1,1, wx.LEFT | wx.RIGHT | wx.EXPAND, 10) sizer.Add((-1, 25)) sizer2 = wx.BoxSizer(wx.VERTICAL) sizer2.Add(self.userLabel, 0) sizer2.Add(self.userText, 0) sizer2.Add(self.pwdLabel, 0) sizer2.Add(self.pwdText, 0) sizer2.Add(self.rem, 0) sizer3 = wx.BoxSizer(wx.HORIZONTAL) sizer3.Add(self.login, 0) sizer3.Add(self.sair,0, wx.LEFT, 5) sizer2.Add(sizer3, 0) sizer4 = wx.BoxSizer(wx.HORIZONTAL) sizer4.Add(image, 1, wx.LEFT | wx.BOTTOM) sizer4.Add(sizer2,0, wx.RIGHT | wx.BOTTOM , 5) sizer.Add(sizer4,0, wx.ALIGN_RIGHT | wx.RIGHT, 10)

    Read the article

  • Counting the number of objects that meets a certain criteria

    - by Candy Chiu
    The title doesn't tell the complete story. Please read the message. I have two objects: Adult and Child. Child has a boolean field isMale, and a reference to Adult. Adult doesn't reference Child. public class Adult { long id; } public class Child { long id; boolean isMale; Adult parent; } I want to create a query to list the number of sons each adult has including adults who don't have any sons. I tried: Query 1 SELECT adult, COUNT(child) FROM Child child RIGHT OUTER JOIN child.parent as adult WHERE child.isMale='true' GROUP BY adult which translates to sql select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id where child.isMale = 'true' group by adult.id Query 1 doesn't pick up adults that don't have any sons. Query 2: SELECT adult, COUNT(child.isMale) FROM Child child RIGHT OUTER JOIN child.parent as adult GROUP BY adult translates to sql: select adult.id as col_0_0_, count(child.id) as col_1_0_, ... {omit properties} from Child child right outer join Adult adult on child.parentId=adult.id group by adult.id Query 2 doesn't have the right count of sons. Basically COUNT doesn't evaluate isMale. The where clause in Query 1 filtered out Adults with no sons. How do I build a HQL or a Criteria query for this use case? Thanks.

    Read the article

  • parsing css measures

    - by david
    When i write a jQuery plugin i like to specify options for spacings the CSS way. I wrote a function that returns a CSS String as values in a object. 5px 10px returns top: 5px, right: 10px, bottom: 5px, left: 10px Now i often use the returned values to do some calculations and its not very nice to have to extract the measuring unit every time... I suck in writing regular expressions could someone help me complete this function: this.cssMeasure = function(cssString, separateUnits){ if ( cssString ){ var values = {} }else{ return errorMsg } var spacing = cssString.split(' ') var errorMsg = 'please format your css values correctly dude' if( spacing[4] || (spacing[2] && !spacing[3]) ) { return errorMsg } else if ( spacing[3] ) { values = {top: spacing[0], right:spacing[1], bottom:spacing[2], left:spacing[3]} } else if ( spacing[1] ) { values = {top: spacing[0], right:spacing[1], bottom:spacing[0], left:spacing[1]} } else { values = {top: spacing[0], right:spacing[0], bottom:spacing[0], left:spacing[0]} } if (separateUnits) { $.each(values, function(i, value){ /* at this place i need to extract the measuring unit of each value and return them separately something like top: {value: 10, unit: 'px'}, right: {bla} and so on */ }) } return values } if you have any idea how to improve this function i am open to your comments.

    Read the article

  • CSS vertical centering split background image not overlapping

    - by user295292
    is it possible to split 2 images vertically and when resizing the browser, it wont overlap but stay vertically centered? can the left image stay fixed so the right side of it won't cut off(overlap) this is what i have now, but when resizing the browser smaller, it pushes the left image underneath the right. rather have the images cut off on the outer sides and never overlap each other in the middle, make sense? #wrapper { width:1680px; max-width:1680px; height:500px; margin: 0 auto; } #left-image { width: 50%; position:absolute; left: auto; height:500px; } #right-image { width: 50%; position:absolute; right: 0px; height:500px; }

    Read the article

  • how to move and print squares visited by a knight in following order?

    - by josh kant
    Lets say you have a 5/5 board and you place and the knight started moving form the middle square. Every time knight moves it has to follow the following pattern. its easy if you draw what i mean. I am trying to code for the possible moves and print out the no. of moves in the nXn (in this case 5X5) board. The print out should be the no. of order in which the knight moved. { //move 1 //2 squares up and 1 to the left //move 2 //2 squares up and 1 to the right //move 3 //1 square up and 2 to the right //move 4 //1 square down and 2 to the right //move 5 //2 squares down and 1 to the right //move 6 //2 squares down and 1 to the left //move 7 //1 square down and 2 to the left //move 8 //one square up and 2 to the left } Any help would be appreciated. Thank you in advance..

    Read the article

< Previous Page | 116 117 118 119 120 121 122 123 124 125 126 127  | Next Page >