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  • a query is inserted from PHPMYAdmin but not from PHP

    - by iyad al aqel
    i'm writing a php code to insert form values in a forum values $dbServer = mysql_connect("localhost" , "root", "") ; if(!$dbServer) die ("Unable to connect"); mysql_select_db("kfumWonder"); $name= $_POST['name'] ; $password= md5($_POST['password']); $email= $_POST['email'] ; $major= $_POST['major'] ; $dateOfBirth=$_POST['dateOfBirth'] ; $webSite = $_POST['website']; $joinDate= date("Y m d") ; $query = "INSERT INTO user (name, password, email, major, dob, website, join_date) Values ('$name', '$password', '$email', '$major', '$dateOfBirth', '$webSite' , '$joinDate')" ; //echo $query ; $result = mysql_query($query) ; if (! $result ) echo " no results " ; this works perfectly fine when i took the printed query and run it in PHPMyAdmin but when i run this code nothing happens , any ideas !?

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  • Shell script for testing

    - by Helltone
    I want a simple testing shell script that launches a program N times in parallel, and saves each different output to a different file. I have made a start that launches the program in parallel and saves the output, but how can I keep only the outputs that are different? Also how can I actually make the echo DONE! indicate the end? #!/bin/bash N=10 for((i=1; j<=$N; ++i)); do ./test > output-$N & done echo DONE!

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  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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  • execute javascript before return in php

    - by user354051
    I do have a custom php script that validates captcha code and sends an email. If php script is sending a mail successfully then it returns "true". This is done by: if(!$Error){ echo "true"; exit; } Before returning true, I would like to execute a jQuery command that should refresh the captcha image. I shouldn't be doing this is client side as it might be risky from spammers point of view. To refresh the captcha image, The command is: jQuery('#captcha').attr('src', ('php/captcha/captchaimage_show.php?' + Math.random())); I need to call this command from within php scripts before return any results by "echo" Prashant

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  • how to get current date and time in command line

    - by Ieyasu Sawada
    I am using mysqldump to backup mysql database. Now I just need to use the current date and time as file name for the generated sql file. How do I do that if my current code looks like this: mysqldump -u root -p --add-drop-table --create-options --password= onstor >c:\sql.sql I also found this code from this site, but I do not know how to incorporate it in my current code: @echo off For /f "tokens=2-4 delims=/ " %%a in ('date /t') do (set mydate=%%c-%%a-%%b) For /f "tokens=1-2 delims=/:" %%a in ('time /t') do (set mytime=%%a%%b) echo %mydate%_%mytime% Please help, thanks:)

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  • status update error (null field)

    - by ejah85
    hai guys... i .ve the problem that i cannot be recovered yet... i have one form where admin need to approve or reject the booking request... i've set the b_status field in table usage IN PROCESS default value... i want to update the b_status value BOOKING APPROVED when user click APPROVE button.. otherwise, the b_status will update the value as BOOKING REJECTED when user click on the REJECT button here's is the form code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM vehicle WHERE v_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr><td>&nbsp;</td></tr> <tr> <tr> <td width="200"><font face="Arial" size="2" font color="#000000">Registration Number </font></td> <td><select name="regno"> <option value="" selected>--Registration No--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['regno']; ?>"><?php echo $row['regno']; ?></option> <?php } ?> </select></td> <td><font face="Arial" size="2" font color="#000000">Reason</font></td> <td><textarea name="reason" rows="3" cols="50 "value = ""></textarea></td> </tr> <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM driver WHERE d_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr> <td><font face="Arial" size="2" font color="#000000">Driver</font></td> <td><select id = "d_name" name="d_name"> <option value="" selected>--Driver Name--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['d_name']; ?>"><?php echo $row['d_name']; ?></option> <?php } ?> </select></td> </tr> <tr> <?php mysql_close($db); ?> </table> <p></p> <center><input name="APPROVED" type="submit" id="APPROVED" value="APPROVED"> <input name="REJECT" type="submit" id="REJECT" value="REJECT"> </center> </div> </center> and this is the process page code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $bookingno=mysql_real_escape_string($_POST['bookingno']); $username=mysql_real_escape_string($_POST['username']); $name=mysql_real_escape_string($_POST['name']); $department=mysql_real_escape_string($_POST['department']); $g_date=mysql_real_escape_string($_POST['g_date']); $g_time=mysql_real_escape_string($_POST['g_time']); $r_date=mysql_real_escape_string($_POST['r_date']); $r_time=mysql_real_escape_string($_POST['r_time']); $destination=mysql_real_escape_string($_POST['destination']); $pass_num=mysql_real_escape_string($_POST['pass_num']); $trip_purpose=mysql_real_escape_string($_POST['trip_purpose']); $regno=mysql_real_escape_string($_POST['regno']); $d_name=mysql_real_escape_string($_POST['d_name']); $reason=mysql_real_escape_string($_POST['reason']); $b_status=mysql_real_escape_string($_POST['b_status']); $sql = "INSERT INTO `usage` VALUES('$bookingno','$username','$name','$department','$g_date','$g_time','$r_date','$r_time','$destination', '$pass_num','$trip_purpose','$regno','$d_name','$reason','$b_status')"; $query = "INSERT INTO `usage` VALUES b_status ='BOOKING APPROVED'"; $result = @mysql_query($query); $query1 = "UPDATE driver SET d_status ='OUT' WHERE '$d_name'=d_name"; $result1 = @mysql_query($query1); if(isset($_POST['APPROVED'])) { $query2 = "UPDATE `usage` SET b_status ='BOOKING APPROVED' WHERE '$b_status'='IN PROCESS'"; $result2 = @mysql_query($query2); } if (isset($_POST['REJECT'])) { $query3 = "UPDATE `usage` SET b_status ='BOOKING REJECTED' WHERE '$b_status'='IN PROCESS'"; $result3 = @mysql_query($query3); } //$result = mysql_query($sql) or die ("error!"); $result = mysql_query($sql) or trigger_error (mysql_error().' in '.$sql); i.ve the problem on the b_status field.. plz guys... help me ya :-)

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  • Codeigniter: Retrieving data from multiple tables and displaying results

    - by Craig Ward
    Hi, I am developing my first big application using codeigniter and need a little help as I am fairly new to it all. I know how to get records out of the DB and display them, but I now have to get results from two tables and display them. I pass $data to the view, it works fine for $data['prop'] but I can't get the rest. $data['prop'] = $this->ManageProperty_model->get_property_details($p_id); $data['img'] = $this->ManageProperty_model->get_property_images($p_id); $this->load->model('ManageBranch_model'); $data['branch'] = $this->ManageBranch_model->get_branch_details($p_id); I usually echo out results like so: <?php foreach ($prop as $p) : ?> <?php echo $p->ID; ?> <?php endforeach; ?> Even if there is only 1 row being returned as I am not sure of another way.do I need a foreach for img and branch?

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  • Is there a Perl Syntax Highlighter (outputting to HTML) like PHP's GeSHi?

    - by nebukadnezzar
    Most PHP Developers are likely familar with the Syntax Highlighter called "GeSHi", which takes code, highlights it, with the use of HTML and CSS: include('geshi.php'); $source = 'echo "hello, world!"; $language = 'php'; $path = 'geshi/'; $geshi = new GeSHi($source, $language, $path); echo $geshi->parse_code(); GeSHi Supports a wide range of languages. I wonder, is there a similar Module for Perl?

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  • How do I set a variable inside a bash for loop?

    - by Isaac Moore
    I need to set a variable inside of a bash for loop, which for some reason, is not working for me. Here is an excerpt of my script: function unlockBoxAll { appdir=$(grep -i "CutTheRope.app" /tmp/App_list.tmp) for lvl in {0..24} key="UNLOCKED_$box_$lvl" plutil -key "$key" -value "1" "$appdir/../Library/Preferences/com.chillingo.cuttherope.plist" 2>&1> /dev/null successCheck=$(plutil -key "$key" "$appdir/../Library/Preferences/com.chillingo.cuttherope.plist") if [ "$successCheck" -eq "1" ]; then echo "Success! " else echo "Failed: Key is $successCheck " fi done } As you can see, I try to write to a variable inside the loop with: key="UNLOCKED_$box_$lvl" But when I do that, I get this: /usr/bin/cutTheRope.sh: line 23: syntax error near unexpected token `key="UNLOCKED_$box_$lvl"' /usr/bin/cutTheRope.sh: line 23: `key="UNLOCKED_$box_$lvl"' What am I not doing right? Is there another way to do this? Please help, thanks.

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  • How can I increment a Smarty variable?

    - by alex
    I am not usually a Smarty guy, so I'm a bit stuck. I want to echo the index of an array, but I want to increment it each time I echo it. This is what I have... <ul> {foreach from=$gallery key=index item=image} <li> <img src="{$image}" alt="" id="panel-{$index++}" /> </li> {/foreach} </ul> It doesn't work. Is the best way to do this to pre-process the array before handing it to Smarty? Is there a way I can do this using Smarty?

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  • MySQL Conventions?

    - by Moe
    Hi There, I just moved my website to a new server (Shared to VPS) I expected errors, and the only error that is really puzzling me is this SQL statement. echo mysql_query("SELECT COUNT(*) FROM users_online_now") This returns nothing! And if I try the mysql_num_rows, it returns mysql_num_rows(): supplied argument is not a valid MySQL result resource.. If I query another table though eg: echo mysql_query("SELECT COUNT(*) FROM users") It works fine. I'm guessing it's something to do with the naming of the table? It worked fine on my previous host, is there some setting I should modify?

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  • php strpos special characters

    - by Radu
    I'm using PHP Version 5.1.6 I have a string (session file) and need to extract a value from it, so i'm searching for a needle in the string but it returns false, I reduced the code to this: $string = ';SERVER_NAME|s:17:"stackoverflow.com";REMOTE_ADDR|s:13:"69.59.196.211";'; $start = strpos($string, ';SERVER_NAME|s:"'); echo $start; // prints nothing because $start = false $start = strpos($string, 'SERVER_NAME|s:'); echo $start; // prints 1; As you noticed if I have the character ';' or the character '"' in the needle, the search returns false, I tryed to use chr() for all characters in the needle but had the same result, If I remove the ';' and the '"' from the string if finds the needle in the string. How can I search special characters in a string using PHP ?

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  • Why does get_posts() return only 5 matching posts, when it should return 9?

    - by Scott B
    global $post; $cat1=get_cat_ID('test1'); $cat2=get_cat_ID('test2'); $myrecentposts = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2",'showposts' => 5)); $myrecentposts2 = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2")); $myrecentpostscount = count($myrecentposts2); echo $myrecentpostscount; The value of the echo is 5 (the correct value should be 9). The only way I can get it to return the correct value for the post count is to change the $myrecentposts2 calculation as follows... $myrecentposts2 = get_posts(array('post_not_in' => get_option('sticky_posts'), 'cat' => "-$cat1,-$cat2",'showposts' => 999));

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  • jquery load a specific #Div content from multiple html files

    - by Vikram
    Hello friends I am trying to make a Content Slider for my site. I have multiple HTML files and the structure of these files is like this: <div id="title"><h2>Title of the Slide</h2></div> <div id="image"><a href="http://mylink.com"><img src="image.jpg" width="600" height="300" alt="image"</a></div> <div id="content">Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s.</div> I have been trying to use the following script get content (but no success): <?php function render($position="") { ob_start(); foreach(glob("/slides/*.html") as $fileName) { $fname = basename( $fileName ); $curArr = file($fname); $slides[$fname ]['title'] = $curArr[0]; $slides[$fname ]['image'] = $curArr[1]; $slides[$fname ]['content'] = $curArr[2]; foreach($slides as $key => $value){ ?> <div id="slide-title"> <?php echo $value['title'] ?> </div> <div id="slide-content"> <?php echo $value['image'] ?> </div> <div id="slide-image"> <?php echo $value['content'] ?> </div> <?php }} ?> <?php return ob_get_clean(); } But then I came to know about a jQuery function.... (again no success) jQuery.noConflict(); (function($){ $(document).ready(function () { $('#slide-title').load('slides/slide1.html #title'); $('#slide-content').load('slides/slide1.html #content'); $('#slide-image').load('slides/slide1.html #image'); }); })(jQuery); Now My questions are..... Am I using the right syntax. How do I get the content from multiple files using jQuery. Please Note : My knowledge on Programming is almost '0'. I have just started learning it.

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  • php database session handling problem in IE8!

    - by psyb0rg
    I've got an html page from where Im making this call periodically: function logon(id) { $.get("data.php", { action: 'online', userID: id}, function(data){ $("#msg").html(data); }); } What this does is it calls this SQL script in data.php: $sql = "update user_sessions set expires=(expires + 2) where userID = $userID"; mysql_query($sql, $conn) or die(mysql_error()); echo $sql; I can see by the echo that the sql syntax and values are correct, but THE CHANGES TO THE expires FIELD ARE NOT DONE, ONLY IN IE8!! It works fine in other ff, safari, chrome, ie6 and 7. There is nothing browser specific about making this sql call, but the user_sessions table is used to store PHP's sessions. Im only increasing the session expiry time when the call is made. What in IE8's session handling is preventing the session time from changing? Is there any caching or cookie problem that needs to be changed?

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  • json jquery post request

    - by John
    <script type="text/javascript"> $(document).ready(function() { $("a").click(function() { var content = $('#content').html(); var data = {"content":content}; $.ajax({ type: "POST", dataType: "json", url: "ajax.php", data: {content:content}, success function (data) { alert('Hello!'); } }); }); }); </script> <div id="content"><?php echo $content; ?></div> ajax.php echo json_encode($_POST['content']); ?> Nothing happens... WhatI really want to achieve is to get that alert box and get the return data, but I am lost since I don't get any errors or nothing.

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  • multiple return values from PHP with jQuery AJAX

    - by benhowdle89
    I'm using this jQuery code: $.ajax ({ type: "POST", url: "customerfilter.php", data: dataString, cache: false, success: function(html) { $(".custName").html(html); } }); How can i do something like this: $(".projDesc").html(html1); So i can split the returned results into two html elements? echo "<p>" .$row['cust_name']. "</p>"; thats the PHP i'm using and i want to echo another statement which i can put into another HTML element Does this make sense?

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  • Working with EnumSet class in GWT

    - by zenmonkey
    I am having trouble using EnumSet on the client side. I get this runtime error message: java.util.EnumSet.EnumSetImpl is not default instantiable (it must have a zero-argument constructor or no constructors at all) and has no custom serializer. Is this is a known issue? Here is what I am doing (basically a hello world app) Service: String echo (EnumSet<Names> name) throws IllegalArgumentException; Client: echoServ.echo (EnumSet.of(Names.JOHN), new AsyncCallback<String>() { ....... }); Shared enum class enum Names { JOHN, NUMAN, OBAMA }

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  • how topass value to controller??

    - by rajesh
    hi all, actuallly when i trying to pass url value to controller action, action is not getting the required value... i ma sending the value like this function value(url,id) { alert(url); document.getElementById('rating').innerHTML=id; var params = 'artist='+id; alert(params); // var newurl='http://localhost/songs_full/public/eslresult/ratesong/userid/1/id/27'; var myAjax = new Ajax.Request(newurl,{method: 'post',parameters:params,onComplete: loadResponse}); //var myAjax = new Ajax.Request(url,{method:'POST',parameters:params,onComplete: load}); //alert(myAjax); } function load(http) { alert('success'); } and in controller i hav write like public function ratesongAction() { $user=$_POST['rating']; echo $user; $post= $this->getRequest()->getPost(); //echo $post; $ratesongid= $this->_getParam('id'); but still not getting the result i am using zend framework

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  • [CakePHP] I am so confused. What should I write in the default.ctp

    - by kwokwai
    Hi all, I am learning cakePHP, everything seems alright except that I am very confused of how to make use of the default.ctp and what should be put inside the Elements folder. Here is the default.ctp file that I have been using since my very first lesson on learning cakePHP: (I copied from this URL http://book.cakephp.org/view/96/Layouts) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><?php echo $title_for_layout?></title> <link rel="shortcut icon" href="favicon.ico" type="image/x-icon"> <!-- Include external files and scripts here (See HTML helper for more info.) --> <?php echo $scripts_for_layout ?> </head> <body> <!-- If you'd like some sort of menu to show up on all of your views, include it here --> <div id="header"> <div id="menu">...</div> </div> <!-- Here's where I want my views to be displayed --> <?php echo $content_for_layout ?> <!-- Add a footer to each displayed page --> <div id="footer">...</div> </body> </html> But the problem is that the layout will take effect to all web pages that I have created. Let's see the case that I have recently encountered. In one of the .ctp files, I need to use JQuery function and I need to ass some and tags in the .ctp file. Here are the and tags I used: <Script language="javascript"> $(document).ready(function() { // some functions here }); </Script> <style type="text/css"> { #toppage{ width:800px; } But when I followed the default.ctp file, I noticed that these tags (i.e. and ) happened to appear below the tag. As far as I know, the and self-defined Javascript functions should be put inside the tag of the HTML instead. I have considered to add the and in the default.ctp file, but then these codes would appear in every web pages instead of just a particular web page. Please help.

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  • Appending a Query String to the End of a Function Action URL

    - by John
    Hello, For the code below, I would like to append echo $_SERVER['QUERY_STRING']; to the end of index.php. But when I try to do it, it makes the code return a blank page. So I think I might be doing it wrong. How can I correctly make this appendage? Thanks in advance, John <?php function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> ... ?>

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  • PHP: How do I have a variable hhtp-header value for my GET request?

    - by Cortopasta
    I want the user to submit an answer to a question, then upon submission be redirected back to the page where they asked the question and I can't seem to get this to work: if (!isset($_POST['answer']) && !isset($_POST['verse'])) { echo "Please fill out form."; } elseif (!isset($_POST['answer']) || !isset($_POST['verse'])) { echo "one field left blank"; } else { $user->submitAnswer($question_id); header("Location: welcome.php?question_id=$question_id"); exit; } What am I doing wrong? EDIT: Sorry, wasn't very clear. I'm trying to pass the variable $question_id to the header(location: part so that it will pull up the question they were just on and show the answer they posted

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  • Making a Link Appear if a Condition is Met

    - by John
    Hello, The PHP code below echoes a link if the "loginid" of the logged-in user is on a list determined by getEditorList();. It works fairly well, but I think it might work better if I were to do it with Javascript instead. How could I accomplish the same thing with Javascript? Thanks in advance, John $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } Login function: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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  • foreach with an array of stdclass objects

    - by Jared Steffen
    So, what I want to do is quite simple in my mind. I have an array that consists solely of four objects. I want to create a loop that will echo an attribute of each object in the array. The only success I've had, however, is echoing every object and every property of the objects. I've never dealt with objects so this is probably the TRUE root of the problem. There's been a few revisions but the only thing I've really excelled at is creating error codes. Here is what I have: $categories = get_categories(array('child_of' => '8')); foreach ($categories as $cat) { echo $cat->name; };

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