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  • Why does VerticalScrollBarVisibility not work in a style in Silverlight?

    - by Edward Tanguay
    VerticalScrollBarVisibility works when I define it inline like this: <UserControl x:Class="TestScrollBar.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <UserControl.Resources> <Style TargetType="TextBox" x:Key="EditListContainerContentMultiLineTwoColumn"> <Setter Property="AcceptsReturn" Value="True"/> <Setter Property="Width" Value="400"/> <Setter Property="Height" Value="300"/> <Setter Property="IsReadOnly" Value="False"/> <Setter Property="Margin" Value="0 0 0 20"/> <Setter Property="HorizontalAlignment" Value="Left"/> <Setter Property="TextWrapping" Value="Wrap" /> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White" Margin="10"> <StackPanel HorizontalAlignment="Left"> <TextBox Text="this is a test" Style="{StaticResource EditListContainerContentMultiLineTwoColumn}" VerticalScrollBarVisibility="Auto" /> </StackPanel> </Grid> </UserControl> But when I put VerticalScrollBarVisibility in a style, it shows me a blank screen: <UserControl x:Class="TestScrollBar.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"> <UserControl.Resources> <Style TargetType="TextBox" x:Key="EditListContainerContentMultiLineTwoColumn"> <Setter Property="VerticalScrollBarVisibility" Value="Auto"/> <Setter Property="AcceptsReturn" Value="True"/> <Setter Property="Width" Value="400"/> <Setter Property="Height" Value="300"/> <Setter Property="IsReadOnly" Value="False"/> <Setter Property="Margin" Value="0 0 0 20"/> <Setter Property="HorizontalAlignment" Value="Left"/> <Setter Property="TextWrapping" Value="Wrap" /> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White" Margin="10"> <StackPanel HorizontalAlignment="Left"> <TextBox Text="this is a test" Style="{StaticResource EditListContainerContentMultiLineTwoColumn}" /> </StackPanel> </Grid> </UserControl> In WPF it works works fine. How can I get VerticalScrollBarVisibility to work in a style?

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  • One-liner javascript to collect values from object graph?

    - by Kevin Pauli
    Given the following object graph: { "children": [ { "child": { "pets": [ { "pet": { "name": "fido" } }, { "pet": { "name": "fluffy" } } ] } }, { "child": { "pets": [ { "pet": { "name": "spike" } } ] } } ] } What would be a nice one-liner (or two) to collect the names of my grandchildren's pets? The result should be ["fido", "fluffy", "spike"] I don't want to write custom methods for this... I'm looking for something like the way jQuery works in selecting dom nodes, where you can just give it a CSS-like path and it collects them up for you. I would expect the expression path to look something like "children child pets pet name"

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  • Date validation in PHP

    - by Rachel
    What would the regex expression that would go into preg_split function to validate date in the format of 7-Mar-10 or how can I validate a date of format 7-Mar-10 in PHP Thanks.

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  • How to replace only part of the match with python re.sub

    - by Arty
    I need to match two cases by one reg expression and do replacement 'long.file.name.jpg' - 'long.file.name_suff.jpg' 'long.file.name_a.jpg' - 'long.file.name_suff.jpg' I'm trying to do the following re.sub('(\_a)?\.[^\.]*$' , '_suff.',"long.file.name.jpg") But this is cut the extension '.jpg' and I'm getting long.file.name_suff. instead of long.file.name_suff.jpg I understand that this is because of [^.]*$ part, but I can't exclude it, because I have to find last occurance of '_a' to replace or last '.' Is there a way to replace only part of the match?

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  • Using RegEx to Identify parts of a Database Connection String

    - by David_Jarrett
    I'm trying to get to grips with regular expressions: I have a database connection string and I'd like to use a regular expression to identify specific Keys and Values within it. For example server=foo;database=bar;uid=foo;pwd=bar I'd like something to return "database=bar;" using the 'database' key to identify it, ideally it would be case insensitive. I can do this using normal code, but I think that this is exactly the sort of thing for which regular expressions were designed.

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  • regex breaks on \n

    - by Sourabh
    hi segmentText = <input from textarea>; testRgx = [/( \d+\.| [^\W\d_]\.|.)+?([!?.?](?= |$)|$)/g]; arrSegments = segmentText.match(testRgx); This expression fails if segmentText has \n or other white spaces in it.I want to add \n in to the list of chars that the above pattern use [!?.?] = [!?.?\n] so that the segment is separated based on the \n character

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  • Please help on multiple match replacement

    - by duenguyen
    I have a perl code: my $s = "The+quick+brown+fox+jumps+over+the+lazy+dog+that+is+my+dog"; what I want is to replace every + with space and dog with cat i have this regular expression $s =~ s/+(.*)dog/ ${1}cat/g; But it only match first occurrence of + and last dog. Please help

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  • preg_match_all image source

    - by David
    I have the following regex expression which is to extract the source of any img tag in HTML. /(<img).*(src\s*=\s*"([a-zA-Z0-9\.;:\/\?&=\-_|\r|\n]{1,})")/isxmU However, it doesn't appear to be matching the following: <IMG SRC='http://www.mysite.com/pix/lens/mtf/CAEF8512L.gif'> How can I build it to match this as well?

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  • Haskell type classes and type families (cont'd)

    - by Giuseppe Maggiore
    I need some help in figuring a compiler error which is really driving me nuts... I have the following type class: infixl 7 --> class Selectable a s b where type Res a s b :: * (-->) :: (CNum n) => (Reference s a) -> (n,(a->b),(a->b->a)) -> Res a s b which I instance twice. First time goes like a charm: instance Selectable a s b where type Res a s b = Reference s b (-->) (Reference get set) (_,read,write) = (Reference (\s -> let (v,s') = get s in (read v,s')) (\s -> \x -> let (v,s') = get s v' = write v x (_,s'') = set s' v' in (x,s''))) since the type checker infers (-->) :: Reference s a -> (n,a->b,a->b->a) -> Reference s b and this signature matches with the class signature for (--) since Res a s b = Reference s b Now I add a second instance and everything breaks: instance (Recursive a, Rec a ~ reca) => Selectable a s (Method reca b c) where type Res a s (Method reca b c) = b -> Reference s c (-->) (Reference get set) (_,read,write) = \(x :: b) -> from_constant( Constant(\(s :: s)-> let (v,s') = get s :: (a,s) m = read v ry = m x :: Reference (reca) c (y,v') = getter ry (cons v) :: (c,reca) v'' = elim v' (_,s'') = set s' v'' in (y,s''))) :: Reference s c the compiler complains that Couldn't match expected type `Res a s (Method reca b c)' against inferred type `b -> Reference s c' The lambda expression `\ (x :: b) -> ...' has one argument, which does not match its type In the expression: \ (x :: b) -> from_constant (Constant (\ (s :: s) -> let ... in ...)) :: Reference s c In the definition of `-->': --> (Reference get set) (_, read, write) = \ (x :: b) -> from_constant (Constant (\ (s :: s) -> ...)) :: Reference s c reading carefully the compiler is telling me that it has inferred the type of (--) thusly: (-->) :: Reference s a -> (n,a->(Method reca b c),a->(Method reca b c)->a) -> (b -> Reference s c) which is correct since Res a s (Method reca b c) = b -> Reference s c but why can't it match the two definitions? Sorry for not offering a more succint and standalone example, but in this case I cannot figure how to do it...

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  • whats the best way to parse and replace the string with its values ?

    - by shahjapan
    I may have string like, """Hello, %(name)s, how are you today, here is amount needed: %(partner_id.account_id.debit_amount)d """ what would be the best solution for such template may i need to combine regular expression and eval, input string may differ like $partner_id.account_id.debit_amount$ - for the moment I've kept as python string format - just for testing.

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  • How can I match a phone number with a regex? [closed]

    - by Zerobu
    Possible Duplicate: A comprehensive regex for phone number validation I would like a regular expression in this format. It Must match one of the following formats: (###)###-#### ###-###-#### ###.###.#### ########## Strip all whitespace. Make sure it's a valid phone number, then (if necessary) translate it to the first format listed above.

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  • Why is the order of evaluation for function parameters undefined in c++?

    - by kunj2aan
    The standard doesn't specify the order of evaluation of arguments with this line: The order of evaluation of arguments is unspecified. What does Better code can be generated in the absence of restrictions on expression evaluation order imply? What is the drawback in asking all the compilers to evaluate the function arguments Left to Right for example? What kinds of optimizations do compilers perform because of this undefined spec?

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  • eregi replace replacement

    - by apis17
    hi, since eregi replace was deprecated on version 5.3 i want to make my program compatible with new version of php http://php.net/manual/en/function.eregi-replace.php so, i'm trying to use preg_replace like this preg_replace(",",'','20,000.00'); but come with error i'm familiar with eregi_replace(',','','20,000.00'); i'm not familiar with regex expression. what is the best replacement for eregi_replace?

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  • Haskell: Gluing a char and a list together?

    - by Vincent
    So I have this code here: toWords :: String - [a] toWords "" = [] toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest The "toWords" function should simply remove all spaces and return a list with all the words. But I keep getting this error: test.hs:5:18: Couldn't match expected type a' against inferred typeChar' `a' is a rigid type variable bound by the type signature for `toWords' at test.hs:1:22 In the first argument of `(:)', namely `nr1' In the expression: nr1 : toWords rest In the definition of `toWords': toWords (nr1 : rest) | nr1 == ' ' = toWords rest | otherwise = nr1 : toWords rest Failed, modules loaded: none.

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  • What's the best way to aggregate the boolean values of a Python dictionary?

    - by Thierry Lam
    For the following Python dictionary: dict = { 'stackoverflow': True, 'superuser': False, 'serverfault': False, 'meta': True, } I want to aggregate the boolean values above into the following boolean expression: dict['stackoverflow'] and dict['superuser'] and dict['serverfault'] and dict['meta'] The above should return me False. I'm using keys with known names above but I want it to work so that there can be an infinite number of unknown key names.

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  • validation of special characters

    - by jpallavi
    I want to validate login name with special characters !@#S%^*()+_-?/<:"';. space using regular expression in ruby on rails. These special characters should not be acceptable. What is the code for that? Thanks, Pallavi

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  • Way to partialy match a Ruby string using Regexp

    - by Fabiano PS
    I'm working on 2 cases: assume I have those var: a = "hello" b = "hello-SP" b = "not_hello" 1 - Any partial matches I want to accept any string that has the var a inside, so b and c would match. 2 - Patterned match I want to match a string that has a inside, followed by '-', so b would match, c does not. I am having problem, because I always used the syntax /expression/ to define Regexp, so how dinamicaly define an RegExp on Ruby??

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • Regex for Eclipse/Flash Builder File Search for comments?

    - by Brian Bishop
    In Eclipse (and Flash/Flex Builder) you get the option with Ctrl+Shift+F to do a file search and look for a regular expression. Would be a real handy thing to know. I want to find the word negate if it appears in a Flex/java comment like the following: // It was negated because or /* The negate option was.... */ or /** * We have to negate the value */ Any ideas? Will test them out at http://www.regexplanet.com/simple/index.html

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