Search Results

Search found 35784 results on 1432 pages for 'number format'.

Page 123/1432 | < Previous Page | 119 120 121 122 123 124 125 126 127 128 129 130  | Next Page >

  • Why is my number being rounded incorrectly?

    - by izb
    This feels like the kind of code that only fails in-situ, but I will attempt to adapt it into a code snippet that represents what I'm seeing. float f = myFloat * myConstInt; /* Where myFloat==13.45, and myConstInt==20 */ int i = (int)f; int i2 = (int)(myFloat * myConstInt); After stepping through the code, i==269, and i2==268. What's going on here to account for the difference?

    Read the article

  • Can't insert a number into a C++ custom streambuf/ostream

    - by 0xbe5077ed
    I have written a custom std::basic_streambuf and std::basic_ostream because I want an output stream that I can get a JNI string from in a manner similar to how you can call std::ostringstream::str(). These classes are quite simple. namespace myns { class jni_utf16_streambuf : public std::basic_streambuf<char16_t> { JNIEnv * d_env; std::vector<char16_t> d_buf; virtual int_type overflow(int_type); public: jni_utf16_streambuf(JNIEnv *); jstring jstr() const; }; typedef std::basic_ostream<char16_t, std::char_traits<char16_t>> utf16_ostream; class jni_utf16_ostream : public utf16_ostream { jni_utf16_streambuf d_buf; public: jni_utf16_ostream(JNIEnv *); jstring jstr() const; }; // ... } // namespace myns In addition, I have made four overloads of operator<<, all in the same namespace: namespace myns { // ... utf16_ostream& operator<<(utf16_ostream&, jstring) throw(std::bad_cast); utf16_ostream& operator<<(utf16_ostream&, const char *); utf16_ostream& operator<<(utf16_ostream&, const jni_utf16_string_region&); jni_utf16_ostream& operator<<(jni_utf16_ostream&, jstring); // ... } // namespace myns The implementation of jni_utf16_streambuf::overflow(int_type) is trivial. It just doubles the buffer width, puts the requested character, and sets the base, put, and end pointers correctly. It is tested and I am quite sure it works. The jni_utf16_ostream works fine inserting unicode characters. For example, this works fine and results in the stream containing "hello, world": myns::jni_utf16_ostream o(env); o << u"hello, wor" << u'l' << u'd'; My problem is as soon as I try to insert an integer value, the stream's bad bit gets set, for example: myns::jni_utf16_ostream o(env); if (o.badbit()) throw "bad bit before"; // does not throw int32_t x(5); o << x; if (o.badbit()) throw "bad bit after"; // throws :( I don't understand why this is happening! Is there some other method on std::basic_streambuf I need to be implementing????

    Read the article

  • java number exceeds long.max_value - how to detect?

    - by jurchiks
    I'm having problems detecting if a sum/multiplication of two numbers exceeds the maximum value of a long integer. Example code: long a = 2 * Long.MAX_VALUE; System.out.println("long.max * smth > long.max... or is it? a=" + a); This gives me -2, while I would expect it to throw a NumberFormatException... Is there a simple way of making this work? Because I have some code that does multiplications in nested IF blocks or additions in a loop and I would hate to add more IFs to each IF or inside the loop. Edit: oh well, it seems that this answer from another question is the most appropriate for what I need: http://stackoverflow.com/a/9057367/540394 I don't want to do boxing/unboxing as it adds unnecassary overhead, and this way is very short, which is a huge plus to me. I'll just write two short functions to do these checks and return the min or max long. Edit2: here's the function for limiting a long to its min/max value according to the answer I linked to above: /** * @param a : one of the two numbers added/multiplied * @param b : the other of the two numbers * @param c : the result of the addition/multiplication * @return the minimum or maximum value of a long integer if addition/multiplication of a and b is less than Long.MIN_VALUE or more than Long.MAX_VALUE */ public static long limitLong(long a, long b, long c) { return (((a > 0) && (b > 0) && (c <= 0)) ? Long.MAX_VALUE : (((a < 0) && (b < 0) && (c >= 0)) ? Long.MIN_VALUE : c)); } Tell me if you think this is wrong.

    Read the article

  • adb doesn't get phone's device name/number

    - by Dona Hertel
    Okay, I have a strange problem I haven't seen listed anywhere. I'm developing an android app and I would like to run it on my Huawei Ascend. I have set up a file in /etc/udev/90-android.rules with the line: SUBSYSTEM=="usb", SYSFS{idVendor}=="12d1", MODE="0666" where '12d1' is the correct vendor ID for this phone (I verified this with 'lsusb' command). When I plug in the phone (it does have debugging on) and restart the adb server I get a connection but the name field does not get set. The output to 'adb devices' is: List of devices attached \n ???????????? device Plugging and unplugging the cable doesn't resolve this. Neither does restarting the adb server. Nor does a total reboot of both my computer or the phone. This is fine as I can get logs and a shell. The problem is that in the eclipse plugin, the device's name is list as "????????????" and so when it tries connect, it quits with an error message of 'device not found' even though the device is listed and 'online'. Is there something else I need to do? Do I need to set the name of the device somehow? cocofan P.S.: The app has 'debuggable' set to true in the manifest file.

    Read the article

  • Fast way to manually mod a number

    - by Nikolai Mushegian
    I need to be able to calculate (a^b) % c for very large values of a and b (which individually are pushing limit and which cause overflow errors when you try to calculate a^b). For small enough numbers, using the identity (a^b)%c = (a%c)^b%c works, but if c is too large this doesn't really help. I wrote a loop to do the mod operation manually, one a at a time: private static long no_Overflow_Mod(ulong num_base, ulong num_exponent, ulong mod) { long answer = 1; for (int x = 0; x < num_exponent; x++) { answer = (answer * num_base) % mod; } return answer; } but this takes a very long time. Is there any simple and fast way to do this operation without actually having to take a to the power of b AND without using time-consuming loops? If all else fails, I can make a bool array to represent a huge data type and figure out how to do this with bitwise operators, but there has to be a better way.

    Read the article

  • Accepts Nested Attributes For - edit form displays incorrect number of items ( + !map:ActiveSupport:

    - by Brightbyte8
    Hi, I have a teacher profile model which has many subjects (separate model). I want to add subjects to the profile on the same form for creating/editing a profile. I'm using accepts_nested_attributes for and this works fine for creation. However on the edit page I am getting a very strange error - instead of seeing 3 subjects (I added three at create and a look into the console confirms this), I see 12 subjects(!). #Profile model class Profile < ActiveRecord::Base has_many :subjects accepts_nested_attributes_for :subjects end #Subject Model class Subject < ActiveRecord::Base belongs_to :profile end #Profile Controller (only showing deviations from normal RESTFUL setup) def new @profile = Profile.new 3.times do @profile.subjects.build end end #Here's 1 of three parts of the subject output of = debug @profile errors: !ruby/object:ActiveRecord::Errors base: *id004 errors: !map:ActiveSupport::OrderedHash {} subjects: - &id001 !ruby/object:Subject attributes: exam: Either name: "7" created_at: 2010-04-15 10:38:13 updated_at: 2010-04-15 10:38:13 level: Either id: "31" profile_id: "3" attributes_cache: {} # Note that 3 of these attributes are displayed despite me seeing 12 subjects on screen Other info in case it's relevant. Rails: 2.3.5 Ruby 1.8.7 p149 HAML I've never had so much difficulty with a bug before - I've already lost about 8 hours to it. Would really appreciate any help! Thanks to any courageous takers Jack

    Read the article

  • Parallel Haskell in order to find the divisors of a huge number

    - by Dragno
    I have written the following program using Parallel Haskell to find the divisors of 1 billion. import Control.Parallel parfindDivisors :: Integer->[Integer] parfindDivisors n = f1 `par` (f2 `par` (f1 ++ f2)) where f1=filter g [1..(quot n 4)] f2=filter g [(quot n 4)+1..(quot n 2)] g z = n `rem` z == 0 main = print (parfindDivisors 1000000000) I've compiled the program with ghc -rtsopts -threaded findDivisors.hs and I run it with: findDivisors.exe +RTS -s -N2 -RTS I have found a 50% speedup compared to the simple version which is this: findDivisors :: Integer->[Integer] findDivisors n = filter g [1..(quot n 2)] where g z = n `rem` z == 0 My processor is a dual core 2 duo from Intel. I was wondering if there can be any improvement in above code. Because in the statistics that program prints says: Parallel GC work balance: 1.01 (16940708 / 16772868, ideal 2) and SPARKS: 2 (1 converted, 0 overflowed, 0 dud, 0 GC'd, 1 fizzled) What are these converted , overflowed , dud, GC'd, fizzled and how can help to improve the time.

    Read the article

  • Import a number of csv files and replace NA by Zeros

    - by tao.hong
    I know how to do this individually. However, I have more than 1000 files. I decided to use a for loop. However, it seems like I did not find the correct way to evaluate my variables. Here is my code setwd('C:/data') filenames=dir() #find file names for (i in filenames){ adt = substr(x = i, start = 1, stop = nchar(i)-4) name=paste("data_", adt, sep="") assign(name, read.csv(i,header=T,sep=",")) #read each file and assign a variable name starting with data_ to it func=paste('name[is.na(name)] <- 0',sep="") # here is the place I have problem. R will not consider name is a parameter whose values change in each iteration eval((text=func)) }

    Read the article

  • What version number should an unreleased project receive?

    - by Byran
    Note: I'm new to version numbering. Please excuse my ignorance. I have a project where an attempted major release (Version B) was abandoned then later re-attempted and release (Version C). Each version has major changes from the previous version that I wouldn't consider an minor update. Little to nothing of Version B made it into Version C. Version A (1.0) Developed, released, updated, etc. Version B (???) Developed, suspended, abandoned. Version C (2.0) Developed, released, updated, etc. I feel like I should have version them like so, but worried about confusion of the missing version: Version A (1.0) Version B (2.0) Version C (3.0)

    Read the article

  • Generate a sequence of Fibonacci number in Scala

    - by qin
    def fibSeq(n: Int): List[Int] = { var ret = scala.collection.mutable.ListBuffer[Int](1, 2) while (ret(ret.length - 1) < n) { val temp = ret(ret.length - 1) + ret(ret.length - 2) if (temp >= n) { return ret.toList } ret += temp } ret.toList } So the above is my code to generate a Fibonacci sequence using Scala to a value n. I am wondering if there is a more elegant way to do this in Scala?

    Read the article

  • Best way to get a random number from 1 to 50 which ISN'T x

    - by Cocorico
    Hi guys! So this is probably programming 101 stuff, but I have a problem: I have 2 numbers which are between 0 and 49. Let's call them x and y. Now I want to get a couple of other numbers which are not x or y, but are also between 0 and 49 (I am using Objective C but this is more of a general theory question I think?). Method I thought of is: int a; int b; int c; do { a = arc4random() % 49; } while ((a == x) || (a == y)); do { b = arc4random() % 49; } while ((b == x) || (b == y) || (b == a)); do { c = arc4random() % 49; } while ((c == x) || (c == y) || (c == a) || (c == b)); But it seem kind of bad to me, I don't know, I am just trying to learn to be a better programmer, what would be the most elegant sweet way to do this for best practices? Thanks!

    Read the article

  • Convert long number as string in the serialization

    - by Bruno
    I have a custom made class that use a long as ID. However, when I call my action using ajax, my ID is truncated and it loses the last 2 numbers because javascript loses precision when dealing with large numbers. My solution would be to give a string to my javascript, but the ID have to stay as a long on the server side. Is there a way to serialize the property as a string? I'm looking for some kind of attribute. Controller public class CustomersController : ApiController { public IEnumerable<CustomerEntity> Get() { yield return new CustomerEntity() { ID = 1306270928525862486, Name = "Test" }; } } Model public class CustomerEntity { public long ID { get; set; } public string Name { get; set; } } JSON Result [{"Name":"Test","ID":1306270928525862400}]

    Read the article

  • Need help with version number schemes

    - by Davy8
    I know the standard Major.Minor.Build.Revision but there's several considerations for us that are somewhat unique -We do internal releases almost daily, occasionally more than once a day. -Windows Installer doesn't check Revision so that's almost moot for our purposes. -Major and Minor numbers ideally are only updated for public releases and should be done manually. -That leaves the Build # that needs to be automatically updated. -We want internal releases to be able to be performed from any developer's machine so that leaves out using x.x.* in Visual Studio because different numbers could be generated from different machines and each build isn't guaranteed to be larger than the previous. -We have about 15 or so projects as part of the product so saving the version numbers in SVN isn't ideal since every release we'd have commit all those files. Given those criteria I can't really come up with a good versioning scheme. The last 2 criteria could be dropped but meeting all of those seems ideal. A date stamp is insufficient because we might do more than one a day, and given the max size of Uint32 (around 64000) (Actually using WiX it complains about numbers higher than Int32.MaxValue) a date/time won't fit.

    Read the article

  • number of months between two dates - using boost's date

    - by MartinP
    I've used boost::gregorian::date a bit now. I can see that there are the related months & years & weeks duration types. I can see how to use known durations to advance a given date. Qu: But how can I get the difference between two dates in months (or years or weeks) ? I was hoping to find a function like: template<typename DURATION> DURATION date_diff<DURATION>(const date& d1,const date& d2); There would need to be some handling of rounding too.

    Read the article

  • Dreamweaver regular expression substitution followed by number

    - by mark
    Hi. I'm using Dreamweaver to update copyright dates across my site. I want to preserve the existing spacing (or lack thereof) between years. Examples: © 2002-2008 should update to © 2002-2009 © 2003 - 2008 should update to © 2003 - 2009 This is the regular expression I'm using to accomplish this in Dreamweaver's find & replace function Find: ©\s*(\d{4}\s*-\s*)\d{3}[^9] Replace: © $1 2009 Here's the PROBLEM: This expression works, but has that that extra space between the hyphen and 2009. If I write the replace expression without the space, as © $12009 then dreamweaver looks for the 12,009th substitution in the find expression, and, not finding one, prints $12009. Any ideas?

    Read the article

  • inserting large number of dates

    - by Radhe
    How can I insert all dates in an year(or more) in a table using sql My dates table has following structure dates(date1 date); Suppose I want to insert dates between "2009-01-01" to "2010-12-31" inclusive. Is there any sql query for the above?

    Read the article

  • limit number of characters entered in textarea

    - by Abu Hamzah
    here is the script does what i want but not exactly, my question is, how can i stop user entering text once it reached the lmit of 255 characters? var limit = 255; var txt = $('textarea[id$=txtPurpose]'); $(txt).keyup(function() { var len = $(this).val().length; if (len > limit) { //this.value = this.value.substring(0, 50); $(this).addClass('goRed'); $('#spn').text(len - limit + " characters exceeded"); return false; } else { $(this).removeClass('goRed'); $('#spn').text(limit - len + " characters left"); } }); if there is a better way please let me know.

    Read the article

< Previous Page | 119 120 121 122 123 124 125 126 127 128 129 130  | Next Page >