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  • Why my autocomplete doesn't whant to be multiple ???

    - by Toni Michel Caubet
    please, give me a hand on this one; i'm trying to use autocomplete so user can enter tags by comma separated, example: 'autocomplete, jquery , next , last' ok, i had the autocomplete working by sending him an $array with all the tags of my website with the previous format aswell, this is my code: <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); mostrar_notificacion('autocomplete_etiquetas_cargado?'); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>] }); } </script> All i want it's user to select a tag, apply the ', ' and the autocomplete to be ready for next tag i'm trying with (i know they are diff id's, also diff inputs): <? $b = new ingrediente(0, ''); $c = $b->autocomplete_ingredientes(); ?> <script type="text/javascript"> function cargar_autocomplete_ingredientes(){ $("#ingredientes").autocomplete({ source: [<? echo $c; ?>], multiple: true, multipleSeparator: ", " }); } </script> But with out success.... 10€ via paypal if answered before 23h (its 21:50 now), it's not much, it's an incentive :P

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  • JSON Returning Null in PHP

    - by kira423
    Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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  • mysql_affected_rows() returns 0 for UPDATE statement even when an update actually happens

    - by Alex Moore
    I am trying to get the number of rows affected in a simple mysql update query. However, when I run this code below, PHP's mysql_affected_rows() always equals 0. No matter if foo=1 already (in which case the function should correctly return 0, since no rows were changed), or if foo currently equals some other integer (in which case the function should return 1). $updateQuery = "UPDATE myTable SET foo=1 WHERE bar=2"; mysql_query($updateQuery); if (mysql_affected_rows() > 0) { echo "affected!"; } else { echo "not affected"; // always prints not affected } The UPDATE statement itself works. The INT gets changed in my database. I have also double-checked that the database connection isn't being closed beforehand or anything funky. Keep in mind, mysql_affected_rows doesn't necessarily require you to pass a connection link identifier, though I've tried that too. Details on the function: mysql_affected_rows Any ideas? SOLUTION The part I didn't mention turned out to be the cause of my woes here. This PHP file was being called ten times consecutively in an AJAX call, though I was only looking at the value returned on the last call, ie. a big fat 0. My apologies!

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  • uploading images with the help of arrays and fetch errors

    - by bonny
    i use a script to upload a couple of images to a directory. the code works great in case of just one picture will be uploaded. if i like to upload two images or more and have an extension that is not accepted, the script will upload the one with the extension that is allowed to upload and shows the errormessage for the one who is not accepted. but the upload takes place. that's my first problem. second problem will be: in case of an errormessage i would like to display a message in which it is said, which of the images will be not allowed. i do not know how to fetch this one that has an unaccepted ending into a variable that i can echo to the errormessage. here is the code i use: if(!empty($_FILES['image']['tmp_name'])){ $allowed_extension = array('jpg', 'jpeg', 'png', 'bmp', 'tiff', 'gif'); foreach($_FILES['image']['name'] as $key => $array_value){ $file_name = $_FILES['image']['name'][$key]; $file_size = $_FILES['image']['size'][$key]; $file_tmp = $_FILES['image']['tmp_name'][$key]; $file_extension = strtolower(end(explode('.', $file_name))); if (in_array($file_extension, $allowed_extension) === false){ $errors[] = 'its an unaccepted format in picture $variable_that_count'; continue; } if ($file_size > 2097152){ $errors[] = 'reached maxsize of 2MB per file in picture $variable_that_count'; } if (count($errors) == 0){ $path = "a/b/c/"; $uploadfile = $path."/".basename($_FILES['image']['name'][$key]); if (move_uploaded_file($_FILES['image']['tmp_name'][$key], $uploadfile)){ echo "success."; } } } } hope it will be clear what i like to approach. if there is someone who could help out i really would appreciate. thanks a lot.

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  • How to do this in a smart way

    - by Azzyh
    Hello SO. My websystem im coding with now is integrated from the originally phpBB system. With this i mean when you log on my websystem, you have actually logged into the forum from the login page. Now i came to the "log out" part, and i want to make it smart. Right now its a simply link with logout: <a href="<?php echo BASEDIR; ?>../../ucp.php?mode=logout&sid=<? echo $user->data['session_id']; ?>" style="margin-left: 14px; font-size: 10px;">- Log Out</a> As you see in the link it refers to the forum´s ucp.php?mode=logout, and you need to have the SID variable in it in order to log out right.. anyway.. I want to do this log out part in a smart way, i mean, not so you land on the forum´s "you have now been logged out", i want something maybe like run this page in background when you click, and then it refreshes the current page your on. Or should it be smarter just try to modify the phpbb file ucp.php? I think its hard coded, and not the way I am coding, so thats why i find it abit tricky. Thank you for your answers and examples on how this could be done, in a smart way..

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  • artisteer wp-theme metadata (date, category) lost

    - by Mattias Svensson
    I am going nuts over wordpress and artisteer. I am trying something that used to be pretty straightforward - turning on and off the display of date and post category for my posts on my blog page. I find this in content.php global $post; theme_post_wrapper( array( 'id' => theme_get_post_id(), 'class' => theme_get_post_class(), 'title' => theme_get_meta_option($post->ID, 'theme_show_page_title') ? get_the_title() : '', 'heading' => theme_get_option('theme_single_article_title_tag'), 'before' => theme_get_metadata_icons('date', 'header'), 'content' => theme_get_content() ) ); And the instruction says that all you got to do is insert or remove 'date' in the 'before' line. I've done it back and forth with my content files and nothing changes on the output. I can't find the actual code that prints it all, wordpress used to be so simple before everything was dug down 10 levels deep and you now have to look through millions of different functions to find the simplest things... As you can probably tell, I usually don't work with WP =) But this is on my table now and I haven't stayed up to date with WP for a couple of years... Any input as to where I can find the variables is appreciated... I had expected to at some point find 'posted at '.echo($date).' in category '.echo($category) or something at least remotely similar...

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  • formatting mysql data for ouptut into a table

    - by bsandrabr
    Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

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  • how close a connection from server side that created by ajax from client side

    - by saeid
    I have this sample php code: <?php function response($a) { @ob_end_clean(); header("Connection: close"); ob_start(); echo $a; $length = ob_get_length(); header("Content-Length: $length"); ob_end_flush(); flush(); } response("test1"); sleep(5); echo "test2"; ?> now I make a connection to server from client by ajax. now I want to server only send "test1" to me and then close the connection. but connection not closed and wait 5 seconds and send me "test1 test2" !! this is response headers from server to me : X-Powered-By: PHP/5.3.27 Connection: close Vary: Accept-Encoding,User-Agent Content-Encoding: gzip Cache-Control: private, no-cache, no-store, ------revalidate, no-transform Transfer-Encoding: chunked Content-Type: text/html in response headers I do not see Content-Length header. is problem for this ?? or if not what I must do now for solving problem ??

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  • Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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  • Uploading File Problem in PHP on Drupal

    - by Nitz
    I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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  • Appending a TR to Table Not Formatting Correctly

    - by TimNguyenBSM
    My PHP script is sending back an array: $currentStatus = ( isset( $status ) ) ? "1" : "0"; $html = "<tr><td>" . $email . "</td><td>" . ( ( $status->type == 0 ) ? "View Only" : ( ( $status->type == 1 ) ? "View & Mark" : "View, Mark & Edit" ) ) . "</td><td>Invited</td></tr>"; echo json_encode( array( $html, $currentStatus ) ); Then my jquery is appending this to the table: ... success: function( result ) { var resultArray = eval( result ); $( "#myTable tr:last").append( resultArray[0] ); ... } Problem is, when it prints, it prints the following extra marks: [email protected]<\/td> View Only<\/td> Invited<\/td><\/tr>","1"] If I only echo the HTML it appends to table just fine, but I cant do that because I need the $currentStatus back too to do something with it. Thanks!

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  • Bash script not working on a new dedicated server

    - by Scott
    Recently I have migrated to the new dedicated server which is running on the same operating system - FreeBSD 8.2. I got a root account access and all permissions have been set properly. My problem is that, the bash script I was running on the old server doesn't works on the new machine, the only error appearing while running the script is: # sh script.sh script.sh: 3: Syntax error: word unexpected (expecting ")") Here is the code itself: #!/usr/local/bin/bash PORTS=(7777:GAME 11000:AUTH 12000:DB) MESSG="" for i in ${PORTS[@]} ; do PORT=${i%%:*} DESC=${i##*:} CHECK=`sockstat -4 -l | grep :$PORT | awk '{print $3}' | head -1` if [ "$CHECK" -gt 1 ]; then echo $DESC[$PORT] "is up ..." $CHECK else MESSG=$MESSG"$DESC[$PORT] wylaczony...\n" if [ "$DESC" == "AUTH" ]; then MESSG=$MESSG"AUTH is down...\n" fi if [ "$DESC" == "GAME" ]; then MESSG=$MESSG"GAME is down...\n" fi if [ "$DESC" == "DB" ]; then MESSG=$MESSG"DB is down...\n" fi fi done if [ -n "$MESSG" ]; then echo -e "Some problems ocurred:\n\n"$MESSG | mail -s "Problems" [email protected] fi I don't really code in bash, so I don't know why this happend...

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  • Why doesn't this short php script send email?

    - by RoryG
    I can't seem to get my php script to send email. <?php echo "Does this page work?"; mail('my email address', 'test subject', 'test message'); ?> First, I have set the mail function settings in the php.ini file as follows: I checked my email account settings on outlook. It does not require authentication, its port is 25, and its type of encrypted connection is 'Auto'. Given this I configured my php.ini file accordingly: SMTP = ssl://smtp1.iis.com smtp_port = 25 Then I set: sendmail_from: my email address The echo statement prints out in the browser, so I know the php file is recognized and processed. But the browser also shows the following error: Warning: mail() [function.mail]: "sendmail_from" not set in php.ini or custom "From:" header missing in C:\xampp\htdocs\mailtest.php on line 3 I have clearly set the sendmail_from so I don't know what else to do. I have also tried removing the 'ssl://' part from the SMTP setting in the php.ini file, and configuring the php5.ini file. Which of these .ini files should I be configuring anyways?

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  • Create new table with Wordpress API

    - by Fire G
    I'm trying to create a new plugin to track popular posts based on views and I have everything done and ready to go, but I can't seem to create a new table using the Wordpress API (I can do it with standard PHP or with phpMyAdmin, but I want this plugin to be self-sufficient). I've tried several ways ($wpdb-query, $wpdb-get_results, dbDelta) but none of them will create the new table. function create_table(){ global $wpdb; $tablename = $wpdb->prefix.'popular_by_views'; $ppbv_table = $wpdb->get_results("SHOW TABLES LIKE '".$tablename."'" , ARRAY_N); if(is_null($ppbv_table)){ $create_table_sql = "CREATE TABLE '".$tablename."' ( 'id' BIGINT(50) NOT NULL AUTO_INCREMENT, 'url' VARCHAR(255) NOT NULL, 'views' BIGINT(50) NOT NULL, PRIMARY KEY ('id'), UNIQUE ('id') );"; $wpdb->show_errors(); $wpdb->flush(); if(is_null($wpdb->get_results("SHOW TABLES LIKE '".$tablename."'" , ARRAY_N))) echo 'crap, the SQL failed.'; } else echo 'table already exists, nothing left to do.';}

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  • PHP Foreach statement issue. Multiple rows are returned

    - by Daniel Patilea
    I'm a PHP beginner and lately i've been having a problem with my source code. Here it is: <html> <head> <title> Bot </title> <link type="text/css" rel="stylesheet" href="main.css" /> </head> <body> <form action="bot.php "method="post"> <lable>You:<input type="text" name="intrebare"></lable> <input type="submit" name="introdu" value="Send"> </form> </body> </html> <?php //error_reporting(E_ALL & ~E_NOTICE); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("robo") or die(mysql_error()); $intrebare=$_POST['intrebare']; $query = "SELECT * FROM dialog where intrebare like '%$intrebare%'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); ?> <div id="history"> <?php foreach($row as $rows){ echo "<b>The robot says: </b><br />"; echo $row['raspuns']; } ?> </div> It returns me the result x6 times. This problem appeared when I've made that foreach because I wanted the results to stuck on the page one by one after every sql querry. Can you please tell me what seems to be the problem? Thanks!

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  • php search database for row

    - by Brenden Morley
    Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

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  • Wordpress Admin Panel Code Input

    - by Wes
    I've got a wordpress admin panel for one of my themes and one of the boxes has an input for some code to drive google adsense. when I put the code into the box and call it with my php tags the code comes out like this: <script type="\&quot;text/javascript\&quot;"><!-- google_ad_client = \"pub-9295546347478163\"; /* Leaderboard 5/17/2010 */ google_ad_slot = \"7593465074\"; google_ad_width = 728; google_ad_height = 90; //--> </script> <script type="\&quot;text/javascript\&quot;" src="%5C%22http://pagead2.googlesyndication.com/pagead/show_ads.js%5C%22"> </script> Which I assume is a feature to stop SQL injections. How can I call pure code form a box? This is how I currently have that textbox setup. array( "name" => "Code for Top ad", "desc" => "Enter the HTML that will drive the banner ad for the page header", "id" => $shortname."_headerAd", "type" => "textarea"), and then echo it out with this: <?php echo get_option('lifestyle_headerAd'); ?>

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  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

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  • Redirect in codeigniter after login

    - by edelweiss
    Trying to do a redirect after a successful login. The login info is sent using ajax to the controller. My controller code as below public function login_controller_function() { $this->load->model('login_model'); if ($this->input->is_ajax_request()) { $user_name=$this->input->post('username'); $user_password = $this->input->post('password'); $this->load->helper('url'); $result = $this->login_model->verify_user($user_name,$user_password); // echo 'user_logged_in'; if(strcmp($result,'user_logged_in')==0) { redirect('welcome'); } } } But it is not working at all. Anyone knows whats wrong? Hi my html as requested. i am using twitter bootstrap as well <li class="divider-vertical"></li> <li><a href="#" id="login_btn">Login</a></li> <li><a href="<?php echo base_url('register'); ?>">Register</a></li> for the buttons so when i click the login button, a modal window will appear and ask for login info. so when i click on the login button, my js code will send an ajax request my js code as below /*Attempt register user jquery ajax*/ $('#login').click(function(){ var user_name = $('#loginHere').find('#user_name').val(); var user_password = $('#loginHere').find('#login_pwd').val(); if(user_name==""||user_password=="") return; var login_data = { username:user_name, password:user_password}; $.ajax({ type: "POST", dataType: "json", async: false, url:"login_register/login_controller_function", data: login_data, success: function(data) { if(data.login) { alert(data.redirect); window.location.replace(data.redirect); } else if(!data.login) { alert('data login not true'); } }, error:function(data){ alert('ajax error'); } }); }); });

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  • PHP checking/refreashing functions

    - by user1284360
    ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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  • php while loop throwing a error over a $var < 10 statement

    - by William
    Okay, so for some reason this is giving me a error as seen here: http://prime.programming-designs.com/test_forum/viewboard.php?board=0 However if I take away the '&& $cur_row < 10' it works fine. Why is the '&& $cur_row < 10' causing me a problem? $sql_result = mysql_query("SELECT post, name, trip, Thread FROM (SELECT MIN(ID) AS min_id, MAX(ID) AS max_id, MAX(Date) AS max_date FROM test_posts GROUP BY Thread ) t_min_max INNER JOIN test_posts ON test_posts.ID = t_min_max.min_id WHERE Board=".$board." ORDER BY max_date DESC", $db); $num_rows = mysql_num_rows($sql_result); $cur_row = 0; while($row = mysql_fetch_row($sql_result) && $cur_row < 10) { $sql_max_post_query = mysql_query("SELECT ID FROM test_posts WHERE Thread=".$row[3].""); $post_num = mysql_num_rows($sql_max_post_query); $post_num--; $cur_row++; echo''.$cur_row.'<br/>'; echo'<div class="postbox"><h4>'.$row[1].'['.$row[2].']</h4><hr />' .$row[0]. '<br /><hr />[<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread='.$row[3].'">Reply</a>] '.$post_num.' posts omitted.</div>'; }

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  • PHP/Javascript: Restart Form Button Isn't Working, Code Insde

    - by Josh K
    Basically I want a confirmation box to pop up when they click the button asking if they sure they want to restart, if yes, then it destroys session and takes them to the first page. Heres what i got... echo "<form id=\"form\" name=\"form\" method=\"post\" action=\"nextpage.php\">\n"; echo " <input type=\"button\" name='restart' value='Restart' id='restart' onclick='restartForm()' />"; and for the script... <script type=\"text/javascript\"> <!-- function restartForm() { var answer = confirm('Are you sure you want to start over?'); if (answer) { form.action=\"firstpage.php\"; session_destroy(); form.submit(); } else alert ('Restart Cancelled'); } // -- </script>"; EDIT: Note that pressing the button brings up the confirm box, but if you click okay nothing happens sometimes. Sometimes if u click cancel it still submits the form (To the original action)

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  • $_FILES is null, $_POST is not null

    - by Cory Dee
    When I am going to upload a file, my $_POST variable knows the file name, but the $_FILES variable is null. I've used this code before, so I'm really stumped. Here's what I'm using for input: <label for="importFile">Attach Resume:</label> <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input type="file" name="importFile" id="importFile" class="validate['required']"> And for processing: $uploaddir = "E:/Sites/OPL/2008/assets/apps/newjobs/resumes/"; $uploadfile = $uploaddir . time() . '-' . urlencode(basename($_FILES['importFile']['name'])); if (!move_uploaded_file($_FILES['importFile']['tmp_name'], $uploadfile)) { echo 'Error uploading file. Error number: ' . $_FILES['importFile']['error']; var_dump($_FILES['importFile']); echo $_POST['importFile']; die(); } Which is giving me this result: Error uploading file. Error number: NULL Maintaining The OPL Website.doc Any help would be greatly appreciated.

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  • Error after redirection using CakePHP

    - by Praveen kalal
    I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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  • Fatal error: Call to a member function escape() on a non-object in .....on line 10

    - by danyo
    i am making a simple javascript login form for wordpress. i have the form submitting to the following bit of php to handle the login: <?php get_header(); global $user_ID; if (!$user_ID) { if($_POST){ //We shall SQL escape all inputs $username = $wpdb->escape($_REQUEST['username']); $password = $wpdb->escape($_REQUEST['password']); $remember = $wpdb->escape($_REQUEST['rememberme']); if($remember) $remember = "true"; else $remember = "false"; $login_data = array(); $login_data['user_login'] = $username; $login_data['user_password'] = $password; $login_data['remember'] = $remember; $user_verify = wp_signon( $login_data, false ); //wp_signon is a wordpress function which authenticates a user. It accepts user info parameters as an array. if ( is_wp_error($user_verify) ) { echo "<span class='error'>Invalid username or password. Please try again!</span>"; exit(); } else { echo "<script type='text/javascript'>window.location='". get_bloginfo('url') ."'</script>"; exit(); } } else { //get_header(); ?> any ideas on why i am getting the error? Cheers, Dan

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