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  • How can I find the shortest path between two subgraphs of a larger graph?

    - by Pops
    I'm working with a weighted, undirected multigraph (loops not permitted; most node connections have multiplicity 1; a few node connections have multiplicity 2). I need to find the shortest path between two subgraphs of this graph that do not overlap with each other. There are no other restrictions on which nodes should be used as start/end points. Edges can be selectively removed from the graph at certain times (as explained in my previous question) so it's possible that for two given subgraphs, there might not be any way to connect them. I'm pretty sure I've heard of an algorithm for this before, but I can't remember what it's called, and my Google searches for strings like "shortest path between subgraphs" haven't helped. Can someone suggest a more efficient way to do this than comparing shortest paths between all nodes in one subgraph with all nodes in the other subgraph? Or at least tell me the name of the algorithm so I can look it up myself? For example, if I have the graph below, the nodes circled in red might be one subgraph and the nodes circled in blue might be another. The edges would all have positive integer weights, although they're not shown in the image. I'd want to find whatever path has the shortest total cost as long as it starts at a red node and ends at a blue node. I believe this means the specific node positions and edge weights cannot be ignored. (This is just an example graph I grabbed off Wikimedia and drew on, not my actual problem.)

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  • mdadm starts resync on every boot

    - by Anteru
    Since a few days (and I'm positive it started shortly before I updated my server from 13.04-13.10) my mdadm is resyncing on every boot. In the syslog, I get the following output [ 0.809256] md: linear personality registered for level -1 [ 0.811412] md: multipath personality registered for level -4 [ 0.813153] md: raid0 personality registered for level 0 [ 0.815201] md: raid1 personality registered for level 1 [ 1.101517] md: raid6 personality registered for level 6 [ 1.101520] md: raid5 personality registered for level 5 [ 1.101522] md: raid4 personality registered for level 4 [ 1.106825] md: raid10 personality registered for level 10 [ 1.935882] md: bind<sdc1> [ 1.943367] md: bind<sdb1> [ 1.945199] md/raid1:md0: not clean -- starting background reconstruction [ 1.945204] md/raid1:md0: active with 2 out of 2 mirrors [ 1.945225] md0: detected capacity change from 0 to 2000396680192 [ 1.945351] md: resync of RAID array md0 [ 1.945357] md: minimum _guaranteed_ speed: 1000 KB/sec/disk. [ 1.945359] md: using maximum available idle IO bandwidth (but not more than 200000 KB/sec) for resync. [ 1.945362] md: using 128k window, over a total of 1953512383k. [ 2.220468] md0: unknown partition table I'm not sure what's up with that detected capacity change, looking at some old logs, this does have appeared earlier as well without a resync right afterwards. In fact, I let it run yesterday until completion and rebooted, and then it wouldn't resync, but today it does resync again. For instance, yesterday I got: [ 1.872123] md: bind<sdc1> [ 1.950946] md: bind<sdb1> [ 1.952782] md/raid1:md0: active with 2 out of 2 mirrors [ 1.952807] md0: detected capacity change from 0 to 2000396680192 [ 1.954598] md0: unknown partition table So it seems to be a problem that the RAID array does not get marked as clean after every shutdown? How can I troubleshoot this? The disks themselves are both fine, SMART tells me no errors, everything ok.

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  • lower-case 'c' key not working in bash

    - by gavin
    This is a bit of a strange one. I'm running Ubuntu 12.04. It's been working well but today, I ran into a hell of strange phenomenon. I can no longer type a lower-case 'c' in bash. At first I thought it was a misconfiguration for the gnome terminal but I tried both a stock xterm and directly at the console (ctrl+alt+F1) and the issue was the same. I can type an upper-case C without any difficulty and I can type lower-case 'c' in any other terminal based program (vim, bash, less, etc.). The lower 'c' also works if I jump into plain old sh. I looked at all the configuration files I know of and haven't found anything incriminating in there. I suspect it's not going to be that simple anyway because if I run bash with the '--norc' option from within sh, the problem remains. I don't know what else to check. In fact, if I wanted to cause this problem on a given machine, I have no idea how it could be done. Total mystery.

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  • Cloud computing - database loading question

    - by workwise
    Following is the situation, I want to know whether what I want is possible in cloud computing and is it the best way for me: 1) My main site has a Database with tables with millions of rows, and entries are added almost every second. 2) I will setup a mysql mirror, so there will be a backup database always in sync with the main one. 3) There are few tens of thousands of images- growing. So say total size of images few tens of gigabytes. I will be keeping the image data also in sync on the backup server. 4) There can be short periods where traffic can go 100X the average traffic. 5) I will be using memcache heavily - most database and even frequently used disk files/images will be in RAM. I want that the main site runs on a dedicated server. The backup server is say an Amazon EC2 instance. Now note that since it is live backup, I need to run a small instance continuously. I want that when I anticipate high traffic, I should be able to run a large instance on the cloud and transfer the traffic there. The main point is - I do not want to spend time in "loading" the database on the large instance, as it typically can take few minutes or even hours (experience). So is it possible to just scale the memory/CPU on demand, and not having to load the database or sync up the filesystem? I want to setup my backup scripts etc just ONCE. Thanks JP

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  • How to access an encrypted INI file from C on an embedded system with little RAM

    - by Mawg
    I want to encrypt an INI file using a Delphi program on a Windows PC. Then I need to decrypt & access it in C on an embedded system with little RAM. I will do that once & fetch all info; I will not be consutinuously accessing the INI file whenever my program needs data from the file. Any advice as to which encryption to use? Nothing too heavyweight, just good enough for "Security through obscurity" and FOSS for both Delphi & C. And how can I decrypt, get all the info from the INI file - using as little RAM as possible, and then free any allocated RAM? I hope that someone can help. [Update] I am currently using an Atmel UC3, although I am not sure if that will be the final case. It has 512kB falsh & 128kB RAM. For an INI file, I am talking of max 8 sections, with a total of max 256 entries, each max 8 chars. I chose INI (but am not married to it), because i have had major problems in the past when the format of a data fiel changes, no matter whether binary, or text. For tex, I prefer the free format of INI (on PC), but suppose I could switch to line_1=data_1, line_2=data_2 and accept that if I add new fields in future software erleases they must come at the end, even if it is not pretty when read directly by humans. I suppose if I choose a fixed format text file then I never need get more than one line into RAM at a time ...

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  • How to determine if you should use full or differential backup?

    - by Peter Larsson
    Or ask yourself, "How much of the database has changed since last backup?". Here is a simple script that will tell you how much (in percent) have changed in the database since last backup. -- Prepare staging table for all DBCC outputs DECLARE @Sample TABLE         (             Col1 VARCHAR(MAX) NOT NULL,             Col2 VARCHAR(MAX) NOT NULL,             Col3 VARCHAR(MAX) NOT NULL,             Col4 VARCHAR(MAX) NOT NULL,             Col5 VARCHAR(MAX)         )   -- Some intermediate variables for controlling loop DECLARE @FileNum BIGINT = 1,         @PageNum BIGINT = 6,         @SQL VARCHAR(100),         @Error INT,         @DatabaseName SYSNAME = 'Yoda'   -- Loop all files to the very end WHILE 1 = 1     BEGIN         BEGIN TRY             -- Build the SQL string to execute             SET     @SQL = 'DBCC PAGE(' + QUOTENAME(@DatabaseName) + ', ' + CAST(@FileNum AS VARCHAR(50)) + ', '                             + CAST(@PageNum AS VARCHAR(50)) + ', 3) WITH TABLERESULTS'               -- Insert the DBCC output in the staging table             INSERT  @Sample                     (                         Col1,                         Col2,                         Col3,                         Col4                     )             EXEC    (@SQL)               -- DCM pages exists at an interval             SET    @PageNum += 511232         END TRY           BEGIN CATCH             -- If error and first DCM page does not exist, all files are read             IF @PageNum = 6                 BREAK             ELSE                 -- If no more DCM, increase filenum and start over                 SELECT  @FileNum += 1,                         @PageNum = 6         END CATCH     END   -- Delete all records not related to diff information DELETE FROM    @Sample WHERE   Col1 NOT LIKE 'DIFF%'   -- Split the range UPDATE  @Sample SET     Col5 = PARSENAME(REPLACE(Col3, ' - ', '.'), 1),         Col3 = PARSENAME(REPLACE(Col3, ' - ', '.'), 2)   -- Remove last paranthesis UPDATE  @Sample SET     Col3 = RTRIM(REPLACE(Col3, ')', '')),         Col5 = RTRIM(REPLACE(Col5, ')', ''))   -- Remove initial information about filenum UPDATE  @Sample SET     Col3 = SUBSTRING(Col3, CHARINDEX(':', Col3) + 1, 8000),         Col5 = SUBSTRING(Col5, CHARINDEX(':', Col5) + 1, 8000)   -- Prepare data outtake ;WITH cteSource(Changed, [PageCount]) AS (     SELECT      Changed,                 SUM(COALESCE(ToPage, FromPage) - FromPage + 1) AS [PageCount]     FROM        (                     SELECT CAST(Col3 AS INT) AS FromPage,                             CAST(NULLIF(Col5, '') AS INT) AS ToPage,                             LTRIM(Col4) AS Changed                     FROM    @Sample                 ) AS d     GROUP BY    Changed     WITH ROLLUP ) -- Present the final result SELECT  COALESCE(Changed, 'TOTAL PAGES') AS Changed,         [PageCount],         100.E * [PageCount] / SUM(CASE WHEN Changed IS NULL THEN 0 ELSE [PageCount] END) OVER () AS Percentage FROM    cteSource

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  • SD-CARD reader does not show in ubuntu

    - by shantanu
    I bought Acer asipre 4250. It have built-in SD card reader. But it is not working. Nothing show in /media or fdisk but something in dmesg. dmesg: new high-speed USB device number 3 using ehci_hcd [ 127.396733] scsi5 : usb-storage 2-2:1.0 [ 128.526562] scsi 5:0:0:0: Direct-Access Multiple Card Reader 1.00 PQ: 0 ANSI: 0 [ 128.532512] sd 5:0:0:0: Attached scsi generic sg2 type 0 [ 129.008110] ohci_hcd 0000:00:12.0: PCI INT A disabled [ 129.032083] ohci_hcd 0000:00:13.0: PCI INT A disabled [ 129.056411] ohci_hcd 0000:00:16.0: PCI INT A disabled [ 129.338026] sd 5:0:0:0: [sdb] Attached SCSI removable disk [ 129.808328] ohci_hcd 0000:00:14.5: PCI INT C disabled [ 167.728616] usb 2-2: USB disconnect, device number 3 [ 169.872284] ehci_hcd 0000:00:13.2: PCI INT B disabled [ 169.872340] ehci_hcd 0000:00:13.2: PME# enabled fdisk -l: Disk /dev/sda: 320.1 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x0006bc6d Device Boot Start End Blocks Id System /dev/sda1 * 2048 48828415 24413184 7 HPFS/NTFS/exFAT /dev/sda2 48828416 50829311 1000448 82 Linux swap / Solaris /dev/sda3 50829312 99657727 24414208 83 Linux /dev/sda4 99659774 625141759 262740993 5 Extended Partition 4 does not start on physical sector boundary. /dev/sda5 99659776 275439615 87889920 7 HPFS/NTFS/exFAT /dev/sda6 275441664 451221503 87889920 7 HPFS/NTFS/exFAT /dev/sda7 451223552 625141759 86959104 7 HPFS/NTFS/exFAT I found another problem just right now. I format last three drives as EXT4 with disk utility. But they are showing as NTFS/exFAT in fdisk. :-(

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  • ArchBeat Link-o-Rama for October 22, 2013

    - by OTN ArchBeat
    The road ahead for WebLogic 12c | Edwin Biemond Oracle ACE Edwin Biemond shares his thoughts on announced new features in Oracle WebLogic 12.1.3 & 12.1.4 and compares those upcoming releases to Oracle WebLogic 12.1.2. Oracle BI Apps 11.1.1.7.1 – GoldenGate Integration - Part 2: Setup and Configuration | Michael Rainey Michael Rainey continues his series with another technical article for you GoldenGate fans. There's A Virtual Developer Day in Your Future Have you experienced OTN VDD? Relax, it's not something that requires medical attention. But an OTN Virtual Developer Day event will enlarge your brain with hands-on information on Oracle technologies. Upcoming events will cover Oracle WebLogic and Coherence (Nov 5) and Oracle ADF (Nov 19). My Summary of Oracle Open World 2013 | Luis Weir SOA/Middleware specialist Luis Weir's first trip to Oracle OpenWorld was what you might call a total immersion experience. His blog post includes details about what kept him very, very busy during his OOW13 experience. Live Blog: Book Review of Building Modular Cloud Apps with OSGi by Bert Ertman and Paul Bakker | Lucas Jellema This interesting post from Oracle ACE Director Lucas Jellema is a work in progress. He's updating as he goes. Check it out. Thought for the Day padding-left: 20px; padding-right: 20px;"> "In the information age, you don't teach philosophy as they did after feudalism. You perform it. If Aristotle were alive today he'd have a talk show." — Timothy Leary, American psychologist and writer (October 22, 1920 – May 31, 1996) Source: brainyquote.com

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  • Rawr Code Clone Analysis&ndash;Part 0

    - by Dylan Smith
    Code Clone Analysis is a cool new feature in Visual Studio 11 (vNext).  It analyzes all the code in your solution and attempts to identify blocks of code that are similar, and thus candidates for refactoring to eliminate the duplication.  The power lies in the fact that the blocks of code don't need to be identical for Code Clone to identify them, it will report Exact, Strong, Medium and Weak matches indicating how similar the blocks of code in question are.   People that know me know that I'm anal enthusiastic about both writing clean code, and taking old crappy code and making it suck less. So the possibilities for this feature have me pretty excited if it works well - and thats a big if that I'm hoping to explore over the next few blog posts. I'm going to grab the Rawr source code from CodePlex (a World Of Warcraft gear calculator engine program), run Code Clone Analysis against it, then go through the results one-by-one and refactor where appropriate blogging along the way.  My goals with this blog series are twofold: Evaluate and demonstrate Code Clone Analysis Provide some concrete examples of refactoring code to eliminate duplication and improve the code-base Here are the initial results:   Code Clone Analysis has found: 129 Exact Matches 201 Strong Matches 300 Medium Matches 193 Weak Matches Also indicated is that there was a total of 45,181 potentially duplicated lines of code that could be eliminated through refactoring.  Considering the entire solution only has 109,763 lines of code, if true, the duplicates lines of code number is pretty significant. In the next post we’ll start examining some of the individual results and determine if they really do indicate a potential refactoring.

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  • Big AdventureWorks2012

    - by jamiet
    Last week I launched AdventureWorks on Azure, an initiative to make SQL Azure accessible to anyone, in my blog post AdventureWorks2012 now available for all on SQL Azure. Since then I think its fair to say that the reaction has been lukewarm with 31 insertions into the [dbo].[SqlFamily] table and only 8 donations via PayPal to support it; on the other hand those 8 donators have been incredibly generous and we nearly have enough in the bank to cover a full year’s worth of availability. It was always my intention to try and make this offering more appealing and to that end I have used an adapted version of Adam Machanic’s make_big_adventure.sql script to massively increase the amount of data in the database and give the community more scope to really push SQL Azure and see what it is capable of. There are now two new tables in the database: [dbo].[bigProduct] with 25200 rows [dbo].[bigTransactionHistory] with 7827579 rows The credentials to login and use AdventureWorks on Azure are as they were before: Server mhknbn2kdz.database.windows.net Database AdventureWorks2012 User sqlfamily Password sqlf@m1ly Remember, if you want to support AdventureWorks on Azure simply click here to launch a pre-populated PayPal Send Money form - all you have to do is login, fill in an amount, and click Send. We need more donations to keep this up and running so if you think this is useful and worth supporting, please please donate.   I mentioned that I had to adapt Adam’s script, the main reasons being: Cross-database queries are not yet supported in SQL Azure so I had to create a local copy of [dbo].[spt_values] rather than reference that in [master] SELECT…INTO is not supported in SQL Azure The 1GB limit of SQLAzure web edition meant that there would not be enough space to store all the data generated by Adam’s script so I had to decrease the total number of rows. The amended script is available on my SkyDrive at https://skydrive.live.com/redir.aspx?cid=550f681dad532637&resid=550F681DAD532637!16756&parid=550F681DAD532637!16755 @Jamiet

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  • how can I fix error: hd0 out of disk?

    - by rux
    I am running Ubuntu 12.04 on a netbook - Acer AS 1410. After a download session, I restarted the computer and it said: error: hd0 out of disk. Press any key to continue... I pressed everything, but it's just frozen there. Any idea what's wrong with it and what I can do to fix it? I haven't been able to run my computer at all since it's frozen like that. Help please! I booted the live cd and ran sudo fdisk -lu into terminal, and here's what it gave me: Disk /dev/sda: 60.0 GB, 60022480896 bytes 255 heads, 63 sectors/track, 7297 cylinders, total 117231408 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x9a696263 Device Boot Start End Blocks Id System /dev/sda3 2048 117229567 58613760 5 Extended /dev/sda5 * 71647232 109039615 18696192 83 Linux /dev/sda6 109041664 117229567 4093952 82 Linux swap / Solaris /dev/sda7 4096 71645183 35820544 83 Linux Partition table entries are not in disk order I am somewhat of a beginner in this, so don't know what this means. any ideas? Thanks!

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  • grub shows same linux image twice

    - by binW
    After a recent update, I get multiple entries for same linux kernel version in the boot menu. I have tried running update-grub2 but it also lists the same linux-image version twice i.e adnan@adnan-laptop:/boot$ sudo update-grub2 Generating grub.cfg ... Found linux image: /boot/vmlinuz-2.6.32-26-generic Found initrd image: /boot/initrd.img-2.6.32-26-generic Found Windows 7 (loader) on /dev/sda1 Found linux image: /boot/vmlinuz-2.6.32-26-generic Found initrd image: /boot/initrd.img-2.6.32-26-generic Found memtest86+ image: /boot/memtest86+.bin done As you can see vmlinuz and initrd are found multiple times. But there is only one vmlinuz and initrd file in /boot adnan@adnan-laptop:/boot$ ls -l total 15120 -rw-r--r-- 1 root root 646144 2010-11-24 15:58 abi-2.6.32-26-generic -rw-r--r-- 1 root root 110601 2010-11-24 15:58 config-2.6.32-26-generic drwxr-xr-x 3 root root 4096 2011-01-01 18:59 grub -rw-r--r-- 1 root root 8335528 2010-12-20 23:36 initrd.img-2.6.32-26-generic -rw-r--r-- 1 root root 160280 2010-03-23 14:40 memtest86+.bin -rw-r--r-- 1 root root 2156100 2010-11-24 15:58 System.map-2.6.32-26-generic -rw-r--r-- 1 root root 1336 2010-11-24 16:00 vmcoreinfo-2.6.32-26-generic -rw-r--r-- 1 root root 4050080 2010-11-24 15:58 vmlinuz-2.6.32-26-generic Can some one tell me why does update-grub2 finds vmlinuz and initrd twice? and how to stop this from happening.

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  • Atelier gratuit : Découvrir la solution d'exploration de données structuré et non structuré

    - by David lefranc
    Explorer et découvrir l’information… Nous vous proposons un atelier découverte pour vous permettre d’explorer toute type de données grace à la solution Oracle Endeca Information Discovery. Quand : 7 Décembre 2012 De 9h30 à 12h30  Lieu : Oracle 15 Boulevard Charles de gaulle 92715 Colombes Pour s'inscrire : [email protected] Réalisé pour des utilisateurs métiers, cet atelier vous permettera en une demi journée , de découvrir Oracle Endeca Information Discovery afin de : Comprendre et explorer toute information venant de différents horizons ( Big Data, réseaux sociaux, forums, sondages, blogs..) Découvrir en quoi et comment OEID est un complément à des solutions de BI classiques Par une navigation simple et rapide, vous découvrirez combien il est facile de trouver des réponses à des questions imprévues en utilisant OEID sans formation préalable. Utilisez la recherche et la navigation guidée pour voir comment les informations structurées et non structurées peuvent être rapidement réunies pour dégager la valeur cachée. Explorer toutes vos données dans n'importe quel format et à partir de n'importe quelle source, y compris les médias sociaux, documents, fichiers,…. Pouvoir découvrir et explorer vos données sans référentiel pour permettre aux utilisateurs d’être autonome et d’analyser leurs propres données de manière rapide Élaborer une stratégie visant à accroître la valeur des données de l'entreprise tout en réduisant le coût total de possession Découvrez l'incroyable performance d’ Endeca sur Oracle Exalytics la machine In Memory Agenda Après une introduction sur la solution Oracle information Endeca, suivi d’un atelier, vous verrez comment il est facile de: Utiliser la navigation guidée et le moteur de recherche pour explorer les données structurées et non structurées intégrer rapidement les nouvelles sources de données comme les médias sociaux Construire de nouvelles interfaces utilisateur tout en découvrant l’information répondre rapidement aux besoins changeants des entreprises et des environnements de données Quand Lieu 7 Décembre 2012 De 9h30 à 12h30 Oracle 15 Boulevard Charles de gaulle 92715 Colombes

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  • Oracle Global HR Cloud Implementation Training Can Help Meet Your Business Needs

    - by HCM-Oracle
    By Jim Vonick A key goal for the deployment of your Oracle Global HR Cloud applications is to accelerate the implementation and adoption of your applications, so that your business can start realizing all of the benefits that this rich solution offers.    Implementation team members need to have the skills and knowledge to ensure a smooth, rapid and successful implementation of your applications. During set-up, you want to optimize the configuration to best meet your business needs. In order to do this you need to understand the foundation and configuration options of your applications, so that decisions can be made during set-up that best align with your business.  To that end product level implementation training is recommended for Oracle Global HR Cloud deployments. Training For Implementation Team Members and Consultants Fusion Applications: HCM Security: Learn how to implement security for Oracle Fusion HCM applications by creating and customizing roles. You'll learn how to create security profiles to restrict data access, provision roles to users, create and manage user accounts, and verify security setup. Fusion Applications: HCM Global Human Resources: Learn how to set up your enterprise and workforce structures, how to perform functional tasks, and how to configure security for Global Human Resources data. Fusion Applications: HCM Compensation: Learn how to implement, configure, and use Oracle Fusion Compensation to manage base pay, individual compensation, workforce compensation, and total compensation statements. Fusion Applications: HCM Benefits: This course teaches you to implement, configure and manage Oracle Fusion Benefits, including how to implement benefit plans and programs.  Fusion Applications: HCM Payroll Implementation (US): This course provides implementation training for payroll managers or payroll administrators. Learn how to process payroll to ensure accurate setup results.  Learn More: See all Fusion HCM Training Jim Vonick is a Senior Product Manager with Oracle University focusing on training for Oracle Applications and Industry Solutions.

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  • Calculating the "power" of a player in a "Defend Your Castle" type game

    - by Jesse Emond
    I'm a making a "Defend Your Castle" type game, where each player has a castle and must send units to destroy the opponent's castle. It looks like this (and yeah, this is the actual game, not a quick paint drawing..): Now, I'm trying to implement the AI of the opponent, and I'd like to create 4 different AI levels: Easy, Normal, Hard and Hardcore. I've never made any "serious" AI before and I'd like to create a quite complete one this time. My idea is to calculate a player's "power" score, based on the current health of its castle and the individual "power" score of its units. Then, the AI would just try to keep a score close to the player's one(Easy would stay below it, Normal would stay near it and Hard would try to get above it). But I just don't know how to calculate a player's power score. There are just too many variables to take into account and I don't know how to properly use them to create one significant number(the power level). Could anyone help me out on this one? Here are the variables that should influence a player's power score: Current castle health, the unit's total health, damage, speed and attack range. Also, the player can have increased Income(the money bag), damage(the + Damage) and speed(the + speed)... How could I include them in the score? I'm really stuck here... Or is there an other way that I could implement AI for this type of game? Thanks for your precious time.

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  • Exalytics Increases Customer Revenue, and Saves Time, Risk & Cost

    - by Mike.Hallett(at)Oracle-BI&EPM
    We are getting some great proof point stories now from our customers who are succeeding with the Exalytics in-memory system for OBI and Essbase.  See below for some recent testimony: San Diego Unified School District Harnesses Attendance, Procurement, and Operational Data with Oracle Exalytics, Generating $4.4 Million in Savings: according to independent assessment by Mainstay Salire, the district is on track to achieve substantial benefits from the Oracle Exalytics solution, including an $8.25 million increase in attendance revenue, $75,000 a year savings in operational efficiencies, and $1 million in hardware cost avoidance. NilsonGroup chooses Oracle Exalytics In-Memory Machine as their solution to access critical data to keep its stores competitive with real-time Mobile BI: it took only “3 days to get up and running” with Exalytics.  Video Nykredit, in the Danish Financial Sector, describes their experiences from testing the Exalytics Business Intelligence Machine: “it was up and running within 4 days” with “more intuitive dashboards” and “up to 70x better performance” and “cheaper maintenance and lower total cost of ownership”. Video Sodexo chose Oracle Exalytics as their business analytics platform; accelerating Essbase “more than 8x” performance for more than 2,000 Excel-addin users, “significantly changing how people in information management now deal with data”.  Video Polk, Savvis, Nykredit, and Key Energy describe testing of the Oracle Exalytics In-Memory Machine: to “reach more users than we ever have before”, “to fly through the data without impeding the analytic process”, “drive our enterprise groups into this tool instead of having departmental solutions”, and the “advanced visualisation this product enables”.  Video

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  • Algorithm to shift the car

    - by Simran kaur
    I have a track that can be divided into n number of tracks and a car as GamObject. The track has transforms such that some part of the track's width lies in negative x axis and other in positive. Requirement: One move should cross one track. On every move(left or right), I want the car to reach exact centre of the next track on either sides i.e left or right. My code: Problem: : Because of negative values , somewhere I am missing out something that is making car move not in desirable positions and that's because of negative values only. variable tracks is the number of tracks the whole track is divided in. variable dist is the total width of the complete track. On left movement: if (Input.GetKeyDown (KeyCode.LeftArrow)) { if (this.transform.position.x < r.renderer.bounds.min.x + box.size.x) { this.transform.position = new Vector3 (r.renderer.bounds.min.x + Mathf.FloorToInt(box.size.x), this.transform.position.y, this.transform.position.z); } else { int tracknumber = Mathf.RoundToInt(dist - transform.position.x)/tracks; float averagedistance = (tracknumber*(dist/tracks) + (tracknumber-1)*(dist/tracks))/2; if(transform.position.x > averagedistoftracks) { amountofmovement = amountofmovement + (transform.position.x - averagedistance); } else { amountofmovement = amountofmovement - (averagedistance - transform.position.x); } this.transform.position = new Vector3 (this.transform.position.x - amountofmovement, this.transform.position.y, this.transform.position.z); } }

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  • How can I start the desktop without having to "startx"?

    - by gtldsp
    I dont want to start every time startx is there any way to get GUI Direct login screen. my files are root@ubuntu:~# locate org.conf /usr/share/X11/xorg.conf.d /usr/share/X11/xorg.conf.d/10-evdev.conf /usr/share/X11/xorg.conf.d/11-evdev-quirks.conf /usr/share/X11/xorg.conf.d/11-evdev-trackpoint.conf /usr/share/X11/xorg.conf.d/50-synaptics.conf /usr/share/X11/xorg.conf.d/50-vmmouse.conf /usr/share/X11/xorg.conf.d/50-wacom.conf /usr/share/X11/xorg.conf.d/51-synaptics-quirks.conf /usr/share/man/man5/xorg.conf.5.gz /usr/share/man/man5/xorg.conf.d.5.gz root@ubuntu:~# cd /usr/share/X11/xorg.conf.d root@ubuntu:/usr/share/X11/xorg.conf.d# ll total 36 drwxr-xr-x 2 root root 4096 Apr 23 04:38 ./ drwxr-xr-x 5 root root 4096 Apr 23 04:38 ../ -rw-r--r-- 1 root root 1099 Apr 4 17:04 10-evdev.conf -rw-r--r-- 1 root root 590 Mar 15 08:52 11-evdev-quirks.conf -rw-r--r-- 1 root root 364 Mar 15 08:52 11-evdev-trackpoint.conf -rw-r--r-- 1 root root 956 Apr 13 06:00 50-synaptics.conf -rw-r--r-- 1 root root 115 Mar 22 09:54 50-vmmouse.conf -rw-r--r-- 1 root root 842 Mar 30 03:13 50-wacom.conf -rw-r--r-- 1 root root 590 Apr 13 05:59 51-synaptics-quirks.conf root@ubuntu:/usr/share/X11/xorg.conf.d# Please provide me step by step details.

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  • How to determine where on a path my object will be at a given point in time?

    - by Dave
    I have map and an obj that is meant to move from start to end in X amount of time. The movements are all straight lines, as curves are beyond my ability at the moment. So I am trying to get the object to move from these points, but along the way there are way points which keep it on a given path. The speed of the object is determined by how long it will take to get from start to end (based on X). This is what i have so far: //get_now() returns seconds since epoch var timepassed = get_now() - myObj[id].start; //seconds since epoch for departure var timeleft = myObj[id].end - get_now(); //seconds since epoch for arrival var journey_time = 60; //this means 60 minutes total journey time var array = [[650,250]]; //way points along the straight paths if(step == 0 || step =< array.length){ var destinationx = array[step][0]; var destinationy = array[step][1]; }else if( step == array.length){ var destinationx = 250; var destinationy = 100; } else { var destinationx = myObj[id].startx; var destinationy = myObj[id].starty; } step++; When the user logs in at any given time, the object needs to be drawn in the correct place of the path, almost as if its been travelling along the path whilst the user has not been at the PC with the available information i have above. How do I do this? Note: The camera angle in the game is a birds eye view so its a straight forward X:Y rather than isometric angles.

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  • Page Titles - Including gender of a fashion product in page titles?

    - by Cedric
    I need a bit of help to decide whether it is worth including gender in page titles. In the webmaster tools: I looked at our search queries that include "women", and they account for 9% of our total search queries for the site. I am wondering if it is the right way assess the benefit of including "woman" or "men" in page titles, looking at it with existing results pointing to us already? Is there another tool that I can check the actual queries that may not include us in search results? Like google insights maybe? http://www.google.com/insights/search/#q=shoes%2Cshoes%20for%20women&cmpt=q So it looks like 1.1% of searches for "shoes" are also "shoes for women" is that correct? As a direct comparison, doing the same analysis on our own search queries, I get 1.8% when comparing "shoes for women" to "shoes" Implementing this automation would probably affect 99% of our site if not more, splitting it in 2 segments (one portion of page titles including "women" and the other including "men") Will doing so create a massively repetitive keyword throughout the site, hurting SEO? http://support.google.com/webmasters/bin/answer.py?hl=en&answer=35624 (see "Avoid repeated or boilerplate titles.")

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  • Advantages and Disadvantages of the Waterfall Methodology

    In my personal opinion I believe the waterfall method is one of the worst methodologies to use when developing larger systems because it leaves is no room for mistakes. As the name implies the waterfall methodology does not allow  for projects to go back up stream to recover from design errors, missing and/or limited requirements. In addition, hidden bugs are not usually found until the testing phase. This can prove to be very costly and time consuming to the developer and the client. According to NCycles.com, the waterfall methodology structures a project into separate stages with defined deliverables from each phase. Define Design Code Test Implement Document and Maintain The advantages found by Ncycle.com to this methodology are: Ease in analyzing potential changes  Ability to coordinate larger teams, even if geographically distributed Can enable precise dollar budget Less total time required from Subject Matter Experts The disadvantages found by Ncycle.com to this methodology are: Lack of flexibility Hard to predict all needs in advance Intangible knowledge lost between hand-offs Lack of team cohesion Design flaws not discovered until the Testing phase References: NCycles.com  (2002). Retrieved from http://www.ncycles.com/e_whi_Methodologies.htmmethodology on April 17, 2009

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  • Random World Generation

    - by Alex Larsen
    I'm making a game like minecraft (although a different idea) but I need a random world generator for a 1024 block wide and 256 block tall map. Basically so far I have a multidimensional array for each layer of blocks (a total of 262,114 blocks). This is the code I have now: Block[,] BlocksInMap = new Block[1024, 256]; public bool IsWorldGenerated = false; Random r = new Random(); private void RunThread() { for (int BH = 0; BH <= 256; BH++) { for (int BW = 0; BW <= 1024; BW++) { Block b = new Block(); if (BH >= 192) { } BlocksInMap[BW, BH] = b; } } IsWorldGenerated = true; } public void GenWorld() { new Thread(new ThreadStart(RunThread)).Start(); } I want to make tunnels and water but the way blocks are set is like this: Block MyBlock = new Block(); MyBlock.BlockType = Block.BlockTypes.Air; How would I manage to connect blocks so the land is not a bunch of floating dirt and stone?

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  • Full Portfolio of x86 Systems On Display at Oracle OpenWorld

    - by kgee
    This OpenWorld, Oracle’s x86 hardware team will have two hardware demos, showcasing the new X3 systems, as well as several other x86 solutions such as the ZFS Storage Appliance, Oracle Database Appliance and the Carrier Grade NETRA systems. These two demos are located in the South Hall in Oracle’s booth 1133 and Intel’s booth 1101.  The Intel booth will feature additional demos including 3D demos of each server, a static architectural demo, the Oracle x86 Grand Prix video game and the Intel Theatre featuring several presentations by Intel’s partners. Oracle’s Intel Theatre Schedule and Topics Include:Monday 1. 10:30 a.m. - Engineered to Work Together: Oracle x86 Systems in the Data Center2. 12:30 a.m. - The Oracle NoSQL Database on the Intel Platform.3. 1:30 p.m. - Accelerate Your Path to Cloud with Oracle VM4. 3:30 p.m. - Why Oracle Linux is the Best Linux for Your Intel Based Systems5. 4:30 p.m. - Accelerate Your Path to Cloud with Oracle VMTuesday 1. 10:00 a.m. - Speed of thought” Analytics using In-Memory Analytics2. 1:30 a.m. - A Storage Architecture for Big Data:  "It’s Not JUST Hadoop"3. 2:00 a.m. - Oracle Optimized Solution for Enterprise Cloud Infrastructure.4. 2:30 p.m. - Configuring Storage to Optimize Database Performance and Efficiency.5. 3:30 p.m. - Total Cloud Control for Oracle's x86 SystemsWednesday 1. 10:00 a.m. - Big Data Analysis Using R-Programming Language2. 11:30 a.m. - Extreme Performance Overview, The Oracle Exadata Database Machine3. 1:30 p.m. - Oracle Times Ten In-Memory Database Overview

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  • Gemalto Mobile Payment Platform on Oracle T4

    - by user938730
    Gemalto is the world leader in digital security, at the heart of our rapidly evolving digital society. Billions of people worldwide increasingly want the freedom to communicate, travel, shop, bank, entertain and work – anytime, everywhere – in ways that are convenient, enjoyable and secure. Gemalto delivers on their expanding needs for personal mobile services, payment security, identity protection, authenticated online services, cloud computing access, eHealthcare and eGovernment services, modern transportation solutions, and M2M communication. Gemalto’s solutions for Mobile Financial Services are deployed at over 70 customers worldwide, transforming the way people shop, pay and manage personal finance. In developing markets, Gemalto Mobile Money solutions are helping to remove the barriers to financial access for the unbanked and under-served, by turning any mobile device into a payment and banking instrument. In recent benchmarks by our Oracle ISVe Labs, the Gemalto Mobile Payment Platform demonstrated outstanding performance and scalability using the new T4-based Oracle Sun machines running Solaris 11. Using a clustered environment on a mid-range 2x2.85GHz T4-2 Server (16 cores total, 128GB memory) for the application tier, and an additional dedicated Intel-based (2x3.2GHz Intel-Xeon X4200) Oracle database server, the platform processed more than 1,000 transactions per second, limited only by database capacity --higher performance was easily achievable with a stronger database server. Near linear scalability was observed by increasing the number of application software components in the cluster. These results show an increase of nearly 300% in processing power and capacity on the new T4-based servers relative to the previous generation of Oracle Sun CMT servers, and for a comparable price. In the fast-evolving Mobile Payment market, it is crucial that the underlying technology seamlessly supports Service Providers as the customer-base ramps up, use cases evolve and new services are launched. These benchmark results demonstrate that the Gemalto Mobile Payment Platform is designed to meet the needs of any deployment scale, whether targeting 5 or 100 million subscribers. Oracle Solaris 11 DTrace technology helped to pinpoint performance issues and tune the system accordingly to achieve optimal computation resources utilization.

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  • Windows 7 disappeared in list of Grub while loading

    - by Riyad A.
    Installed Ubuntu 12.04 alongside the Windows 7 two weeks ago. Initially haven't any issues with that. day ago installed updates on Ubuntu and after restarting the system found the absence of Win7 in Grub list. Before the HDD has been partitioned on two volumes Disk C and Work Disk(don't remember the name). When doing the fdisk -l: Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0xa93031e0 Device Boot Start End Blocks Id System /dev/sda1 * 2048 408833842 204415897+ 7 HPFS/NTFS/exFAT /dev/sda2 488386560 976773119 244193280 7 HPFS/NTFS/exFAT /dev/sda3 408834046 488386559 39776257 5 Extended Partition 3 does not start on physical sector boundary. /dev/sda5 408834048 484421631 37793792 83 Linux /dev/sda6 484423680 488386559 1981440 82 Linux swap / Solaris Partition table entries are not in disk order Disk /dev/mmcblk0: 3965 MB, 3965190144 bytes 49 heads, 48 sectors/track, 3292 cylinders, total 7744512 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/mmcblk0p1 8192 7744511 3868160 b W95 FAT32 When sudo mount /dev/sda ~/1 -o offset [488386560*512] - opens and mounts WORK disk. Need help: how to See and mount disk C. how to see and adjust the Grub to appear both systems in Grub menu when loading?

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