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  • Windows XP-64 loses audio sounds, drive letters... why?

    - by Ira Baxter
    Until sometime in early December, I had a wonderfully functioning XP-64 system. It was configured to auto download/install MS patches. I occassionally update the software on it, e.g. Open Office, Adobe Reader, Skype, but I don't fetch hundreds of tools or anything much beyond what I just mentioned. In December, suddenly my audio stopped, and drive letters assigned to various mount points on other machines quit being available. Apparantly, the services that support these (and some others) are now not starting up when I boot/login. There isn't anything obvious in the event log. If I manually restart the associated services, these facilities come back on line and work for awhile (a day) but pretty soon the problem reappears. I don't reboot very often, nor do I log out out much. Hints?

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  • How to send Bluetooth audio to non-Bluetooth speakers?

    - by wonsungi
    In short, I am looking for a Bluetooth-3.5 mini stereo converter. What is this type of device called, and what are some of the best models (is there a difference in audio quality/lag)? I wish to connect some speakers (Altec Lansing inMotion IM7), which does not support Bluetooth, to my laptop (Lenovo X301) wirelessly. Currently, I can connect my laptop's headphone jack to the AUX jack on my speakers via a mini stereo cable. How do I replace this cable with some type of Bluetooth setup? I am not sure what this Bluetooth device is called. I thought I found something, but it actually does the opposite of what I need (3.5 mini stereo-Bluetooth). (My OS is Vista Enterprise, if that matters)

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  • No audio driver for ECS 7050-M v1.0a for Windows 7?

    - by NudeRaider
    I have an Elitegroup 7050-M v1.0a motherboard and I've used the Realtek HD audio driver it came with for years under Windows XP. There was a nice mixer panel, an equalizer and sound profiles that added effects. All of these menus are gone now that I've moved on to Windows 7 64 Bit. All I have is the basic settings under system control - sound, but they are not nearly as detailed. To clarify: Sound works, but the advanced settings I got when using older OS's are gone. Older drivers don't seem to work under Win7 and I can't find one for Win7. So how can I fully utilize the capabilities of my HD sound chip under Win7?

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  • How do I get FEATURE_LEVEL_9_3 to work with shaders in Direct3D11?

    - by Dominic
    Currently I'm going through some tutorials and learning DX11 on a DX10 machine (though I just ordered a new DX11 compatible computer) by means of setting the D3D_FEATURE_LEVEL_ setting to 10_0 and switching the vertex and pixel shader versions in D3DX11CompileFromFile to "vs_4_0" and "ps_4_0" respectively. This works fine as I'm not using any DX11-only features yet. I'd like to make it compatible with DX9.0c, which naively I thought I could do by changing the feature level setting to 9_3 or something and taking the vertex/pixel shader versions down to 3 or 2. However, no matter what I change the vertex/pixel shader versions to, it always fails when I try to call D3DX11CompileFromFile to compile the vertex/pixel shader files when I have D3D_FEATURE_LEVEL_9_3 enabled. Maybe this is due to the the vertex/pixel shader files themselves being incompatible for the lower vertex/pixel shader versions, but I'm not expert enough to say. My shader files are listed below: Vertex shader: cbuffer MatrixBuffer { matrix worldMatrix; matrix viewMatrix; matrix projectionMatrix; }; struct VertexInputType { float4 position : POSITION; float2 tex : TEXCOORD0; float3 normal : NORMAL; }; struct PixelInputType { float4 position : SV_POSITION; float2 tex : TEXCOORD0; float3 normal : NORMAL; }; PixelInputType LightVertexShader(VertexInputType input) { PixelInputType output; // Change the position vector to be 4 units for proper matrix calculations. input.position.w = 1.0f; // Calculate the position of the vertex against the world, view, and projection matrices. output.position = mul(input.position, worldMatrix); output.position = mul(output.position, viewMatrix); output.position = mul(output.position, projectionMatrix); // Store the texture coordinates for the pixel shader. output.tex = input.tex; // Calculate the normal vector against the world matrix only. output.normal = mul(input.normal, (float3x3)worldMatrix); // Normalize the normal vector. output.normal = normalize(output.normal); return output; } Pixel Shader: Texture2D shaderTexture; SamplerState SampleType; cbuffer LightBuffer { float4 ambientColor; float4 diffuseColor; float3 lightDirection; float padding; }; struct PixelInputType { float4 position : SV_POSITION; float2 tex : TEXCOORD0; float3 normal : NORMAL; }; float4 LightPixelShader(PixelInputType input) : SV_TARGET { float4 textureColor; float3 lightDir; float lightIntensity; float4 color; // Sample the pixel color from the texture using the sampler at this texture coordinate location. textureColor = shaderTexture.Sample(SampleType, input.tex); // Set the default output color to the ambient light value for all pixels. color = ambientColor; // Invert the light direction for calculations. lightDir = -lightDirection; // Calculate the amount of light on this pixel. lightIntensity = saturate(dot(input.normal, lightDir)); if(lightIntensity > 0.0f) { // Determine the final diffuse color based on the diffuse color and the amount of light intensity. color += (diffuseColor * lightIntensity); } // Saturate the final light color. color = saturate(color); // Multiply the texture pixel and the final diffuse color to get the final pixel color result. color = color * textureColor; return color; }

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  • Getting FEATURE_LEVEL_9_3 to work in DX11

    - by Dominic
    Currently I'm going through some tutorials and learning DX11 on a DX10 machine (though I just ordered a new DX11 compatible computer) by means of setting the D3D_FEATURE_LEVEL_ setting to 10_0 and switching the vertex and pixel shader versions in D3DX11CompileFromFile to "vs_4_0" and "ps_4_0" respectively. This works fine as I'm not using any DX11-only features yet. I'd like to make it compatible with DX9.0c, which naively I thought I could do by changing the feature level setting to 9_3 or something and taking the vertex/pixel shader versions down to 3 or 2. However, no matter what I change the vertex/pixel shader versions to, it always fails when I try to call D3DX11CompileFromFile to compile the vertex/pixel shader files when I have D3D_FEATURE_LEVEL_9_3 enabled. Maybe this is due to the the vertex/pixel shader files themselves being incompatible for the lower vertex/pixel shader versions, but I'm not expert enough to say. My shader files are listed below: Vertex shader: cbuffer MatrixBuffer { matrix worldMatrix; matrix viewMatrix; matrix projectionMatrix; }; struct VertexInputType { float4 position : POSITION; float2 tex : TEXCOORD0; float3 normal : NORMAL; }; struct PixelInputType { float4 position : SV_POSITION; float2 tex : TEXCOORD0; float3 normal : NORMAL; }; PixelInputType LightVertexShader(VertexInputType input) { PixelInputType output; // Change the position vector to be 4 units for proper matrix calculations. input.position.w = 1.0f; // Calculate the position of the vertex against the world, view, and projection matrices. output.position = mul(input.position, worldMatrix); output.position = mul(output.position, viewMatrix); output.position = mul(output.position, projectionMatrix); // Store the texture coordinates for the pixel shader. output.tex = input.tex; // Calculate the normal vector against the world matrix only. output.normal = mul(input.normal, (float3x3)worldMatrix); // Normalize the normal vector. output.normal = normalize(output.normal); return output; } Pixel Shader: Texture2D shaderTexture; SamplerState SampleType; cbuffer LightBuffer { float4 ambientColor; float4 diffuseColor; float3 lightDirection; float padding; }; struct PixelInputType { float4 position : SV_POSITION; float2 tex : TEXCOORD0; float3 normal : NORMAL; }; float4 LightPixelShader(PixelInputType input) : SV_TARGET { float4 textureColor; float3 lightDir; float lightIntensity; float4 color; // Sample the pixel color from the texture using the sampler at this texture coordinate location. textureColor = shaderTexture.Sample(SampleType, input.tex); // Set the default output color to the ambient light value for all pixels. color = ambientColor; // Invert the light direction for calculations. lightDir = -lightDirection; // Calculate the amount of light on this pixel. lightIntensity = saturate(dot(input.normal, lightDir)); if(lightIntensity > 0.0f) { // Determine the final diffuse color based on the diffuse color and the amount of light intensity. color += (diffuseColor * lightIntensity); } // Saturate the final light color. color = saturate(color); // Multiply the texture pixel and the final diffuse color to get the final pixel color result. color = color * textureColor; return color; }

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  • C# Neural Networks with Encog

    - by JoshReuben
    Neural Networks ·       I recently read a book Introduction to Neural Networks for C# , by Jeff Heaton. http://www.amazon.com/Introduction-Neural-Networks-C-2nd/dp/1604390093/ref=sr_1_2?ie=UTF8&s=books&qid=1296821004&sr=8-2-spell. Not the 1st ANN book I've perused, but a nice revision.   ·       Artificial Neural Networks (ANNs) are a mechanism of machine learning – see http://en.wikipedia.org/wiki/Artificial_neural_network , http://en.wikipedia.org/wiki/Category:Machine_learning ·       Problems Not Suited to a Neural Network Solution- Programs that are easily written out as flowcharts consisting of well-defined steps, program logic that is unlikely to change, problems in which you must know exactly how the solution was derived. ·       Problems Suited to a Neural Network – pattern recognition, classification, series prediction, and data mining. Pattern recognition - network attempts to determine if the input data matches a pattern that it has been trained to recognize. Classification - take input samples and classify them into fuzzy groups. ·       As far as machine learning approaches go, I thing SVMs are superior (see http://en.wikipedia.org/wiki/Support_vector_machine ) - a neural network has certain disadvantages in comparison: an ANN can be overtrained, different training sets can produce non-deterministic weights and it is not possible to discern the underlying decision function of an ANN from its weight matrix – they are black box. ·       In this post, I'm not going to go into internals (believe me I know them). An autoassociative network (e.g. a Hopfield network) will echo back a pattern if it is recognized. ·       Under the hood, there is very little maths. In a nutshell - Some simple matrix operations occur during training: the input array is processed (normalized into bipolar values of 1, -1) - transposed from input column vector into a row vector, these are subject to matrix multiplication and then subtraction of the identity matrix to get a contribution matrix. The dot product is taken against the weight matrix to yield a boolean match result. For backpropogation training, a derivative function is required. In learning, hill climbing mechanisms such as Genetic Algorithms and Simulated Annealing are used to escape local minima. For unsupervised training, such as found in Self Organizing Maps used for OCR, Hebbs rule is applied. ·       The purpose of this post is not to mire you in technical and conceptual details, but to show you how to leverage neural networks via an abstraction API - Encog   Encog ·       Encog is a neural network API ·       Links to Encog: http://www.encog.org , http://www.heatonresearch.com/encog, http://www.heatonresearch.com/forum ·       Encog requires .Net 3.5 or higher – there is also a Silverlight version. Third-Party Libraries – log4net and nunit. ·       Encog supports feedforward, recurrent, self-organizing maps, radial basis function and Hopfield neural networks. ·       Encog neural networks, and related data, can be stored in .EG XML files. ·       Encog Workbench allows you to edit, train and visualize neural networks. The Encog Workbench can generate code. Synapses and layers ·       the primary building blocks - Almost every neural network will have, at a minimum, an input and output layer. In some cases, the same layer will function as both input and output layer. ·       To adapt a problem to a neural network, you must determine how to feed the problem into the input layer of a neural network, and receive the solution through the output layer of a neural network. ·       The Input Layer - For each input neuron, one double value is stored. An array is passed as input to a layer. Encog uses the interface INeuralData to hold these arrays. The class BasicNeuralData implements the INeuralData interface. Once the neural network processes the input, an INeuralData based class will be returned from the neural network's output layer. ·       convert a double array into an INeuralData object : INeuralData data = new BasicNeuralData(= new double[10]); ·       the Output Layer- The neural network outputs an array of doubles, wraped in a class based on the INeuralData interface. ·        The real power of a neural network comes from its pattern recognition capabilities. The neural network should be able to produce the desired output even if the input has been slightly distorted. ·       Hidden Layers– optional. between the input and output layers. very much a “black box”. If the structure of the hidden layer is too simple it may not learn the problem. If the structure is too complex, it will learn the problem but will be very slow to train and execute. Some neural networks have no hidden layers. The input layer may be directly connected to the output layer. Further, some neural networks have only a single layer. A single layer neural network has the single layer self-connected. ·       connections, called synapses, contain individual weight matrixes. These values are changed as the neural network learns. Constructing a Neural Network ·       the XOR operator is a frequent “first example” -the “Hello World” application for neural networks. ·       The XOR Operator- only returns true when both inputs differ. 0 XOR 0 = 0 1 XOR 0 = 1 0 XOR 1 = 1 1 XOR 1 = 0 ·       Structuring a Neural Network for XOR  - two inputs to the XOR operator and one output. ·       input: 0.0,0.0 1.0,0.0 0.0,1.0 1.0,1.0 ·       Expected output: 0.0 1.0 1.0 0.0 ·       A Perceptron - a simple feedforward neural network to learn the XOR operator. ·       Because the XOR operator has two inputs and one output, the neural network will follow suit. Additionally, the neural network will have a single hidden layer, with two neurons to help process the data. The choice for 2 neurons in the hidden layer is arbitrary, and often comes down to trial and error. ·       Neuron Diagram for the XOR Network ·       ·       The Encog workbench displays neural networks on a layer-by-layer basis. ·       Encog Layer Diagram for the XOR Network:   ·       Create a BasicNetwork - Three layers are added to this network. the FinalizeStructure method must be called to inform the network that no more layers are to be added. The call to Reset randomizes the weights in the connections between these layers. var network = new BasicNetwork(); network.AddLayer(new BasicLayer(2)); network.AddLayer(new BasicLayer(2)); network.AddLayer(new BasicLayer(1)); network.Structure.FinalizeStructure(); network.Reset(); ·       Neural networks frequently start with a random weight matrix. This provides a starting point for the training methods. These random values will be tested and refined into an acceptable solution. However, sometimes the initial random values are too far off. Sometimes it may be necessary to reset the weights again, if training is ineffective. These weights make up the long-term memory of the neural network. Additionally, some layers have threshold values that also contribute to the long-term memory of the neural network. Some neural networks also contain context layers, which give the neural network a short-term memory as well. The neural network learns by modifying these weight and threshold values. ·       Now that the neural network has been created, it must be trained. Training a Neural Network ·       construct a INeuralDataSet object - contains the input array and the expected output array (of corresponding range). Even though there is only one output value, we must still use a two-dimensional array to represent the output. public static double[][] XOR_INPUT ={ new double[2] { 0.0, 0.0 }, new double[2] { 1.0, 0.0 }, new double[2] { 0.0, 1.0 }, new double[2] { 1.0, 1.0 } };   public static double[][] XOR_IDEAL = { new double[1] { 0.0 }, new double[1] { 1.0 }, new double[1] { 1.0 }, new double[1] { 0.0 } };   INeuralDataSet trainingSet = new BasicNeuralDataSet(XOR_INPUT, XOR_IDEAL); ·       Training is the process where the neural network's weights are adjusted to better produce the expected output. Training will continue for many iterations, until the error rate of the network is below an acceptable level. Encog supports many different types of training. Resilient Propagation (RPROP) - general-purpose training algorithm. All training classes implement the ITrain interface. The RPROP algorithm is implemented by the ResilientPropagation class. Training the neural network involves calling the Iteration method on the ITrain class until the error is below a specific value. The code loops through as many iterations, or epochs, as it takes to get the error rate for the neural network to be below 1%. Once the neural network has been trained, it is ready for use. ITrain train = new ResilientPropagation(network, trainingSet);   for (int epoch=0; epoch < 10000; epoch++) { train.Iteration(); Debug.Print("Epoch #" + epoch + " Error:" + train.Error); if (train.Error > 0.01) break; } Executing a Neural Network ·       Call the Compute method on the BasicNetwork class. Console.WriteLine("Neural Network Results:"); foreach (INeuralDataPair pair in trainingSet) { INeuralData output = network.Compute(pair.Input); Console.WriteLine(pair.Input[0] + "," + pair.Input[1] + ", actual=" + output[0] + ",ideal=" + pair.Ideal[0]); } ·       The Compute method accepts an INeuralData class and also returns a INeuralData object. Neural Network Results: 0.0,0.0, actual=0.002782538818034049,ideal=0.0 1.0,0.0, actual=0.9903741937121177,ideal=1.0 0.0,1.0, actual=0.9836807956566187,ideal=1.0 1.0,1.0, actual=0.0011646072586172778,ideal=0.0 ·       the network has not been trained to give the exact results. This is normal. Because the network was trained to 1% error, each of the results will also be within generally 1% of the expected value.

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  • Steganography : Encoded audio and video file not being played, getting corrupted. What is the issue

    - by Shantanu Gupta
    I have made a steganography program to encrypt/Decrypt some text under image audio and video. I used image as bmp(54 byte header) file, audio as wav(44 byte header) file and video as avi(56 byte header) file formats. When I tries to encrypt text under all these file then it gets encrypted successfully and are also getting decrypted correctly. But it is creating a problem with audio and video i.e these files are not being played after encrypted result. What can be the problem. I am working on Turbo C++ compiler. I know it is super outdated compiler but I have to do it in this only. Here is my code to encrypt. int Binary_encode(char *txtSourceFileName, char *binarySourceFileName, char *binaryTargetFileName,const short headerSize) { long BinarySourceSize=0,TextSourceSize=0; char *Buffer; long BlockSize=10240, i=0; ifstream ReadTxt, ReadBinary; //reads ReadTxt.open(txtSourceFileName,ios::binary|ios::in);//file name, mode of open, here input mode i.e. read only if(!ReadTxt) { cprintf("\nFile can not be opened."); return 0; } ReadBinary.open(binarySourceFileName,ios::binary|ios::in);//file name, mode of open, here input mode i.e. read only if(!ReadBinary) { ReadTxt.close();//closing opened file cprintf("\nFile can not be opened."); return 0; } ReadBinary.seekg(0,ios::end);//setting pointer to a file at the end of file. ReadTxt.seekg(0,ios::end); BinarySourceSize=(long )ReadBinary.tellg(); //returns the position of pointer TextSourceSize=(long )ReadTxt.tellg(); //returns the position of pointer ReadBinary.seekg(0,ios::beg); //sets the pointer to the begining of file ReadTxt.seekg(0,ios::beg); //sets the pointer to the begining of file if(BinarySourceSize<TextSourceSize*50) //Minimum size of an image should be 50 times the size of file to be encrypted { cout<<"\n\n"; cprintf("Binary File size should be bigger than text file size."); ReadBinary.close(); ReadTxt.close(); return 0; } cout<<"\n"; cprintf("\n\nSize of Source Image/Audio File is : "); cout<<(float)BinarySourceSize/1024; cprintf("KB"); cout<<"\n"; cprintf("Size of Text File is "); cout<<TextSourceSize; cprintf(" Bytes"); cout<<"\n"; getch(); //write header to file without changing else file will not open //bmp image's header size is 53 bytes Buffer=new char[headerSize]; ofstream WriteBinary; // writes to file WriteBinary.open(binaryTargetFileName,ios::binary|ios::out|ios::trunc);//file will be created or truncated if already exists ReadBinary.read(Buffer,headerSize);//reads no of bytes and stores them into mem, size contains no of bytes in a file WriteBinary.write(Buffer,headerSize);//writes header to 2nd image delete[] Buffer;//deallocate memory /* Buffer = new char[sizeof(long)]; Buffer = (char *)(&TextSourceSize); cout<<Buffer; */ WriteBinary.write((char *)(&TextSourceSize),sizeof(long)); //writes no of byte to be written in image immediate after header ends //to decrypt file if(!(Buffer=new char[TextSourceSize])) { cprintf("Enough Memory could not be assigned."); return 0; } ReadTxt.read(Buffer,TextSourceSize);//read all data from text file ReadTxt.close();//file no more needed WriteBinary.write(Buffer,TextSourceSize);//writes all text file data into image delete[] Buffer;//deallocate memory //replace Tsize+1 below with Tsize and run the program to see the change //this is due to the reason that 50-54 byte no are of colors which we will be changing ReadBinary.seekg(TextSourceSize+1,ios::cur);//move pointer to the location-current loc i.e. 53+content of text file //write remaining image content to image file while(i<BinarySourceSize-headerSize-TextSourceSize+1) { i=i+BlockSize; Buffer=new char[BlockSize]; ReadBinary.read(Buffer,BlockSize);//reads no of bytes and stores them into mem, size contains no of bytes in a file WriteBinary.write(Buffer,BlockSize); delete[] Buffer; //clear memory, else program can fail giving correct output } ReadBinary.close(); WriteBinary.close(); //Encoding Completed return 0; } Code to decrypt int Binary_decode(char *binarySourceFileName, char *txtTargetFileName, const short headerSize) { long TextDestinationSize=0; char *Buffer; long BlockSize=10240; ifstream ReadBinary; ofstream WriteText; ReadBinary.open(binarySourceFileName,ios::binary|ios::in);//file will be appended if(!ReadBinary) { cprintf("File can not be opened"); return 0; } ReadBinary.seekg(headerSize,ios::beg); Buffer=new char[4]; ReadBinary.read(Buffer,4); TextDestinationSize=*((long *)Buffer); delete[] Buffer; cout<<"\n\n"; cprintf("Size of the File that will be created is : "); cout<<TextDestinationSize; cprintf(" Bytes"); cout<<"\n\n"; sleep(1); WriteText.open(txtTargetFileName,ios::binary|ios::out|ios::trunc);//file will be created if not exists else truncate its data while(TextDestinationSize>0) { if(TextDestinationSize<BlockSize) BlockSize=TextDestinationSize; Buffer= new char[BlockSize]; ReadBinary.read(Buffer,BlockSize); WriteText.write(Buffer,BlockSize); delete[] Buffer; TextDestinationSize=TextDestinationSize-BlockSize; } ReadBinary.close(); WriteText.close(); return 0; } int text_encode(char *SourcefileName, char *DestinationfileName) { ifstream fr; //reads ofstream fw; // writes to file char c; int random; clrscr(); fr.open(SourcefileName,ios::binary);//file name, mode of open, here input mode i.e. read only if(!fr) { cprintf("File can not be opened."); getch(); return 0; } fw.open(DestinationfileName,ios::binary|ios::out|ios::trunc);//file will be created or truncated if already exists while(fr) { int i; while(fr!=0) { fr.get(c); //reads a character from file and increments its pointer char ch; ch=c; ch=ch+1; fw<<ch; //appends character in c to a file } } fr.close(); fw.close(); return 0; } int text_decode(char *SourcefileName, char *DestinationName) { ifstream fr; //reads ofstream fw; // wrrites to file char c; int random; clrscr(); fr.open(SourcefileName,ios::binary);//file name, mode of open, here input mode i.e. read only if(!fr) { cprintf("File can not be opened."); return 0; } fw.open(DestinationName,ios::binary|ios::out|ios::trunc);//file will be created or truncated if already exists while(fr) { int i; while(fr!=0) { fr.get(c); //reads a character from file and increments its pointer char ch; ch=c; ch=ch-1; fw<<ch; //appends character in c to a file } } fr.close(); fw.close(); return 0; }

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  • iftop - how to generate text file with its output?

    - by mickula
    iftop is great tool to view almost live bandwidth usage distinguished by source-ip source-port destination-ip destination port. I'm using it to see which client's ip is using most bandwidth. Now I would like to store output somewhere. iftop uses ncurses so iftop > log.txt does not work as expected, result file is not readable. Is there any tool like this which can be used to pipe output to a text file? Thanks for your replies.

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  • How can I use a delimiter in wmic output, separating columns?

    - by Abhishek Simon
    I want to fetch Windows Hotfix listing with some format, whose output can be separated with some delimiter. so far I found a wmic command which gives me a desired output but the problem is the \s delimiter is not going to work here. Is there a way I can place some , or anyother character, which I can later use in java program to get individual columns? Command wmic qfe get caption,csname,description,hotfixid,installedby,installedon Output Caption CSName Description HotFixID InstalledBy InstalledOn http://go.microsoft.com/fwlink/?LinkId=161784 Abhishek Update KB971033 NT AUTHORITY\SYSTEM 3/15/2012 http://support.microsoft.com/?kbid=2032276 Abhishek Security Update KB2032276 NT AUTHORITY\SYSTEM 3/15/2012 .. . Update I am trying for /f "tokens=1,2,3,4,5,6,7,8,9,10,11" %g in ('wmic qfe get caption,csname,description,fixcomments,hotfixid,installdate,installedby,installedon,name,servicepackineffect,status') do @echo %g,%h,%i,%j,%k,%l,%m,%n,%o,%p but it gives me invalid GET Expression C:\Users\Abhishek\Desktop>for /f "tokens=1,2,3,4,5,6,7,8,9,10,11" %g in ('wmic qfe get caption,csname,description,fixcomments,hotfixid,installdate,installedby,installedon,name,servicepackineffect,status') do @echo %g,%h,%i,%j,%k,%l,%m,%n,%o,%p Invalid GET Expression. What is the problem here? This might solve the problem for me . More Update I even tried the below command but this too does not solve space problem Command for /f "tokens=1,2,3,4,5,6,7,8,9,10,11" %g in ('wmic qfe list') do @echo %g,%h,%i,%j,%k,%l,%m,%n,%o,%p Output Caption,CSName,Description,FixComments,HotFixID,InstallDate,InstalledBy,InstalledOn,Name,ServicePackInEffect http://go.microsoft.com/fwlink/?LinkId=161784,Abhishek,Update,KB971033,NT,AUTHOR,,Y\SYSTEM,3/15/2012, http://support.microsoft.com/?kbid=2281679,Abhishek,Security,Update,KB2281679,NT,AUTHORITY\SYSTEM,3/15/2012, http://support.microsoft.com/?kbid=2284742,Abhishek,Update,KB2284742,NT,AUTHORIT,,SYSTEM,3/15/2012, http://support.microsoft.com/?kbid=2286198,Abhishek,Security,Update,KB2286198,NT,AUTHORITY\SYSTEM,3/15/2012,

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  • Make mysqldump output USE statements or full table names when dumping a single table with where clause

    - by tobyodavies
    Is it possible to get mysqldump to output USE statements for a single (partial) table dump? I've already got some scripts that I'd like to reuse which run mysqldump with some arguments and apply them to a remote server. However, since I haven't bothered to parse all the arguments to mysqldump, and there is no USE in the dump, the remote server is saying no database selected. I'm a programmer more than anything else, so I can easily use sed to modify the dump before applying it in the worst case, but those scripts won't allow me to do this as I don't have access to the dump between creation and application. EDIT: the ability to output fully qualified table names may also solve my problem

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  • How can I capture Rake output when invoked from with a Ruby script?

    - by Adrian O'Connor
    I am writing a web-based dev-console for Rails development. In one of my controller actions, I am calling Rake, but I am unable to capture any of the output that Rake generates. For example, here is some sample code, from the controller: require 'rake' require 'rake/rdoctask' require 'rake/testtask' require 'tasks/rails' require 'stringio' ... def show_routes @results = capture_stdout { Rake.tasks['routes'].invoke } # @results is nil -- the capture_stdout doesn't catpure anything that Rake generates end def capture_stdout s = StringIO.new $stdout = s yield s.string ensure $stdout = STDOUT end Does anybody know why I can't capture the Rake output? I've tried going through the Rake source, and I can't see where it fires a new process or anything, so I think I ought to be able to do this. Many thanks! Adrian I have since discovered the correct way to call Rake from inside Ruby that works much better: Rake.application['db:migrate:redo'].reenable Rake.application['db:migrate:redo'].invoke Strangely, some rake tasks work perfectly now (routes), some capture the output the first time the run and after that are always blank (db:migrate:redo) and some don't seem to ever capture output (test). Odd.

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  • Getting Vars to bind properly across multiple files

    - by Alex Baranosky
    I am just learning Clojure and am having trouble moving my code into different files. I keep detting this error from the appnrunner.clj - Exception in thread "main" java.lang.Exception: Unable to resolve symbol: -run-application in this context It seems to be finding the namespaces fine, but then not seeing the Vars as being bound... Any idea how to fix this? Here's my code: APPLICATION RUNNER - (ns src/apprunner (:use src/functions)) (def input-files [(resource-path "a.txt") (resource-path "b.txt") (resource-path "c.txt")]) (def output-file (resource-path "output.txt")) (defn run-application [] (sort-files input-files output-file)) (-run-application) APPLICATION FUNCTIONS - (ns src/functions (:use clojure.contrib.duck-streams)) (defn flatten [x] (let [s? #(instance? clojure.lang.Sequential %)] (filter (complement s?) (tree-seq s? seq x)))) (defn resource-path [file] (str "C:/Users/Alex and Paula/Documents/SoftwareProjects/MyClojureApp/resources/" file)) (defn split2 [str delim] (seq (.split str delim))) (defstruct person :first-name :last-name) (defn read-file-content [file] (apply str (interpose "\n" (read-lines file)))) (defn person-from-line [line] (let [sections (split2 line " ")] (struct person (first sections) (second sections)))) (defn formatted-for-display [person] (str (:first-name person) (.toUpperCase " ") (:last-name person))) (defn sort-by-keys [struct-map keys] (sort-by #(vec (map % [keys])) struct-map)) (defn formatted-output [persons output-number] (let [heading (str "Output #" output-number "\n") sorted-persons-for-output (apply str (interpose "\n" (map formatted-for-display (sort-by-keys persons (:first-name :last-name)))))] (str heading sorted-persons-for-output))) (defn read-persons-from [file] (let [lines (read-lines file)] (map person-from-line lines))) (defn write-persons-to [file persons] (dotimes [i 3] (append-spit file (formatted-output persons (+ 1 i))))) (defn sort-files [input-files output-file] (let [persons (flatten (map read-persons-from input-files))] (write-persons-to output-file persons)))

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  • How do I check if output stream of a socket is closed?

    - by Roman
    I have this code: public void post(String message) { output.close(); final String mess = message; (new Thread() { public void run() { while (true) { try { output.println(mess); System.out.println("The following message was successfully sent:"); System.out.println(mess); break; } catch (NullPointerException e) { try {Thread.sleep(1000);} catch (InterruptedException ie) {} } } } }).start(); } As you can see I close the socket in the very beginning of the code and then try to use it to send some information to another computer. The program writes me "The following message was successfully sent". It means that the NullPointerException was not thrown. So, does Java throw no exception if it tries to use a closed output stream of a socket? Is there a way to check if a socket is closed or opened? ADDED I initialize the socket in the following way: clientSideSocket = new Socket(hostname,port); PrintWriter out = new PrintWriter(clientSideSocket.getOutputStream(), true); browser.output = out;

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  • How to redirect the output of the vmrun listProcessesInGuest command on windows?

    - by mark
    I run vmrun.exe with listProcessesInGuest on the command line and get the list of processes displayed in the console window. The exact command line is: "C:\VIX\vmrun.exe" -T vc -h "https://myserver/sdk" -u "mydomain\myuser" -p 123 -gu Administrator -gp 123 listProcessesInGuest "[Storage1] QA-W-7-SP1-64-0/QA-W-7-SP1-64-0.vmx" It works fine. Now I wish to redirect the output, however, neither 2> nor 1> work! The former has no effect - the output is still displayed in the console window, so I conclude it is send to stdout. But the latter does not work too - now nothing is displayed in the console window, but the redirection file is empty! It is created all right, but it has the zero size! Can someone explain what is going on?

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  • cl.exe Difference in object files when /E output is the same and flags are the same

    - by madiyaan damha
    Hello: I am using Visual Studio 2005's cl.exe compiler. I call it with a bunch of /I /D and some compilation/optimization flags (example: /Ehsc). I have two compilation scripts, and both differ only in the /I flags (include directories are different). All other flags are the same. These scripts produce different object files (and not just a timestamp difference as noted below). The strange thing is that the /E output of both scripts is the same. That means that the include files are not causing the difference in object files, but then again, where is the difference coming from? Can anyone elucidate on how I am seeing two different object files in my situation. If the include files are causing the difference, how come I see identical /E output? PS. The object files are different not only in the timestamp, but in the code sections also. In fact the behavior of my final executable is different in both cases. Edit: PSS: I even looked at the /includeFiles output of cl.exe and that output is identical. The object files, however, differ in more than just the timestamp (in fact, one is 1KB bigger than another!)

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  • converting a Tree to newick format. java

    - by Esmond
    I'm having problems converting a binary rooted tree to newick format. The full explanation for such a format can be found: http://code.google.com/p/mrsrf/wiki/NewickTree An example of a newick format would be as follows: for a tree T such as http://www.cs.mcgill.ca/~cs251/OldCourses/1997/topic8/images/completetreetwo.gif the newick representation would be: (((8,9),(10,11)),((12,13),(14,15))) the internal node will become the commas while the leaves will be retained. such trees have internal nodes which will always have 2 children. I have a problem using recursion to come out with this newick format. The output contains far too many nodes and braces. Any comments to resolve this problem is appreciated or even an iterative algorithm would be welcomed import java.util.Stack; public class Tree { .... public String inOrderNewick(Node root, String output) throws ItemNotFoundException { if (root.hasChild()) { output += "("; output += inOrderNewick(root.child1, output); output += ","; output += inOrderNewick(root.child2, output); output += ")"; return output; } else { output += root.getSeq(); return output; } } }

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  • Is it possible to limit output bandwidth between eth0 and lo?

    - by mmcbro
    I'm trying to limit the bandwidth between my eth0 output (nginx proxy) to my loopback inteface (apache) by filtering on destination port. Incoming Packet -> Eth0 -> 0.0.0.0:80 Nginx -> tc qdisc class/iptable mangle 2525port -> 127.0.0.1:2525 Apache I don't know if it's even possible I'm just experimenting. My rules are the followings : tc qdisc add dev eth0 root handle 1:0 htb tc class add dev eth0 parent 1:0 classid 1:10 htb rate 2mbps ceil 2mbps prio 0 tc filter add dev eth0 parent 1:0 prio 0 protocol ip handle 10 fw flowid 1:10 iptables -A OUTPUT -t mangle -p tcp --dport 2525 -j MARK --set-mark 10 I also tried to with FORWARD chain but its still the same.

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  • update terminal title from standard output of long running command?

    - by Sam Hasler
    I'd like to change the title of a terminal window during a long running command (for example: git svn fetch) with values greped from the output, whilst still writing to standard output. Is this possible using named pipes or tee and xargs? I'm thinking something like git svn fetch | sed "s/^\(r\d*\).*$/ \"\\\033]0;\"\1\"\\\007\"/" | xargs -l1 echo -ne based on: http://tldp.org/HOWTO/Xterm-Title-3.html Update: getting this to work would be enough: (echo "r9" ; echo "r10") | sed "s/^\(r\d*\).*$/ \"\\\033]0;\"\1\"\\\007\"/" | xargs -l1 echo -ne Update 2: This almost does what I want. I see r10, but not r9: (echo "r9" ; sleep 1 ; echo "r10") | sed "s/^\(r[0-9]*\)\.*$/\\\033]0;\1\\\007/" | xargs -0 echo -ne

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  • How to get the pid of a running process using a single command that parse the output of ps?

    - by Sorin Sbarnea
    I am looking for a single line that does return the pid of a running process. Currently I have: ps -A -o pid,cmd|grep xxx|head -n 1 And this returns the fist pid, command. I need only the first number from the output and ignore the rest. I suppose sed or awk would help here but my experience with them is limited. Also, this has another problem, it will return the pid of grep if the xxx is not running. It's really important to have a single line, as I want to reuse the output for doing something else, like killing that process.

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  • How do I change the output line length from the "top" linux command running in batch mode

    - by Tom
    The following command is useful to capture the current processes that are taking up the most CPU in a file: top -c -b -n 1 > top.log The -c flag is particularly useful because it gives you the command line arguments of each process rather than just the process name. The problem is that each line of output is truncated to fit on the current terminal window. This is ok if you can have a wide terminal because you have a lot of the output but if your terminal is only 165 characters wide, you only get 165 characters of information per process and it is often not enough characters to show the full process command. This is a particular problem when the command is executed without a terminal, for example if you do it via a cron job. Does anyone know how to stop top truncating data or force top to display a certain number of characters per line? This is not urgent because there is an alternative method of getting the top 10 CPU using processes: ps -eo pcpu,pmem,user,args | sort -r -k1 | head -n 10

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  • How can I dynamically set the default namespace declaration of an XSLT transformation's output XML?

    - by Paralife
    I can do it, but not for the default namespace, using the <xsl:namespace>. If I try to do it for the default namespace: <xsl:namespace name="" select"myUri"/> it never works. It demands that I explicitly define the namespace of the element to be able to use the above null prefix declaration. The reason I want this is because I have a task to transform an input XML file to another output xml. The output XML has many elements and i dont want to have to explicitly set the namespace for every element. Thats why I want to set the default and never bother again. But the default must be computed from some data in the source XML. It does not change during the whole transformation, but it is dependent on input XML data. Any solution? EDIT 1: To sup up: I want to create a namespace dynamically and set it to be the default namespace of the output xml document. The uri of the namespace is derived from some data in the input XML. If I use <xsl:namespace> in my root output element, I cannot create a default namespace for it, only a prefixed one. And even with the prefixed one, it does not propagate to children.

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  • xvidcap: Error accessing sound input from /dev/dsp

    - by stivlo
    I'm running Ubuntu 11.10 and I'm trying xvidcap to record a screencast with audio from the microphone, however it can't record any sound: $ xvidcap --file appo.avi --cap_geometry 700x500-0+0 Error accessing sound input from /dev/dsp Sound disabled! Sure enough /dev/dsp doesn't even exist: $ sudo ls -lh /dev/dsp ls: cannot access /dev/dsp: No such file or directory I found a blog post about fixing xvidcap sound input, however if I try the suggestion I get: $ sudo modprobe snd-pcm-oss FATAL: Module snd_pcm_oss not found. So the question is, how can I create /dev/dsp? The problem behind the problem is: how can I record sound from the microphone with xvidcap? So workarounds are welcome too. UPDATE: I've followed the suggestion of James, and something has improved. The error accessing /dev/dsp is gone, however now I get: [oss @ 0x8e0c120] Estimating duration from bitrate, this may be inaccurate xtoffmpeg.c add_audio_stream(): Can't initialize fifo for audio recording Now when I record xvidcap appears in the recording tab of pavucontrol and I can choose Audio stream from Internal Audio Analog Stereo or Monitor of Internal Audio Analog Stereo, I tried both just in case, but the video is still mute. UPDATE 2: I found that "Monitor of" is the one to record application sounds, while for microphone, I should choose "Internal Audio Analog Stereo". To rule out other problems, such as with the microphone, I tried with gnome-sound-recorder and it works. Actually I jumped on my chair, since the volume was too high! :-)

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