UTF-8 bit representation
- by Yanick Rochon
I'm learning about UTF-8 standards and this is what I'm learning :
Definition and bytes used
UTF-8 binary representation Meaning
0xxxxxxx 1 byte for 1 à 7 bits chars
110xxxxx 10xxxxxx 2 bytes for 8 à 11 bits chars
1110xxxx 10xxxxxx 10xxxxxx 3 bytes for 12 à 16 bits chars
11110xxx 10xxxxxx 10xxxxxx 10xxxxxx 4 bytes for 17 à 21 bits chars
And I'm wondering, why 2 bytes UTF-8 code is not 10xxxxxx instead, thus gaining 1 bit all the way up to 22 bits with a 4 bytes UTF-8 code? The way it is right now, 64 possible values are lost (from 1000000 to 10111111). I'm not trying to argue the standards, but I'm wondering why this is so?
** EDIT **
Even, why isn't it
UTF-8 binary representation Meaning
0xxxxxxx 1 byte for 1 à 7 bits chars
110xxxxx xxxxxxxx 2 bytes for 8 à 13 bits chars
1110xxxx xxxxxxxx xxxxxxxx 3 bytes for 14 à 20 bits chars
11110xxx xxxxxxxx xxxxxxxx xxxxxxxx 4 bytes for 21 à 27 bits chars
...?
Thanks!
