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  • how to make changes to database in WPF?

    - by user353573
    Drag access database into designer xsd, toolkit:datagrid get datacontext from resources correctly show the table content through this binding. Press button in the button column, can show each row correctly. delete row and add row also work in datagrid however, when i press button column to add a new row or delete a row, there is no change in the underlying database, how to commit the changes from datagrid to database in WPF if not using ADO.net ? The following code is what i try do not work private void datagrid2_delete(object sender, RoutedEventArgs e) { Button showButton = (Button)sender; //person p = (person)showButton.DataContext; DataRowView ds = (DataRowView)showButton.DataContext; //DataSet1.customertableRow p = (DataSet1.customertableRow)ds; //ds.BeginEdit(); //ds.Delete(); //ds.EndEdit(); /* DataSourceProvider provider = (DataSourceProvider)this.FindResource("Family"); WpfApplication1.DataSet1.customertableDataTable table = (WpfApplication1.DataSet1.customertableDataTable)provider.Data; table.AddcustomertableRow("hello3", 5, System.DateTime.Today); table.AcceptChanges(); }

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  • How to cleverly stop "while loop" (php)

    - by user3735697
    I'm having trouble with creating code that echoes a bunch of stuff that is corresponding to the mysql database row. It needs to keep creating the content until all rows are used and then stop. But for some reason the php file causes the browser to keep loading (it never ends). Any help would be appreciated! Thanks! <?php mysql_connect ("localhost", "root", "") or die ("We couldn't connect!"); mysql_select_db ("dr"); mysql_query ("SELECT * FROM songs"); $result = mysql_query ("SELECT * FROM songs"); while ($row=mysql_fetch_array($result)) { $name = $row ['songname']; $genres = $row ['songgenres']; $mediafire = $row ['mediafirelink']; $dropbox = $row ['dropboxlink']; $source = $row ['audiosource']; echo " <div class='playing'> <!-- ======== Song Name ======== --> <li class='songnameli' id='$source'> <span class='info'>$name</span> <audio> <source src='music/singles/$source.mp3'> <source src='music/singles/$source.ogg'> </audio> </li> <!-- ======== Playlist ======== --> <li class='playlistli'> <img src='icons/addtoplaylist.png' title='Add tot the playlist!' /> </li> <!-- ======== Genres ======== --> <li class='genresli'> <img src='icons/genres.png' title='Related genres' /> <span class='addedtext genres'>$genres</span> </li> <!-- ======== Social Media links ======== --> <li> <span> <img src='icons/share.png' alt='Share this with your friends!' title='Share this!'> <!-- /// facebook /// --> <a href='http://www.facebook.com/sharer.php?u=http://www.declassified-recordings.com' class='addedtext nlink' target='blank_' onclick='popup (this.href, 800, 500); return false'>Facebook </a> <span>/</span> <!-- /// Twitter /// --> <a href='http://twitter.com/share? text=Thank%20you%20For%20Sharing!%20It%20means%20the%20world%20to%20us!%40Declassifi3d%20 &url=http://www.declassified-recordings.com' class='twitterlink nlink' target='blank_' onclick='popup (this.href, 800, 500); return false'>Twitter</a> </span> </li> <!-- ======== Download links ======== --> <li> <img src='icons/download.png' title='Download!' /> <span> <!-- /// Mediafire /// --> <a href='$mediafire' class='addedtext nlink' target='_blank'>Mediafire</a> <span class='genres'>/</span> <!-- /// Dropbox /// --> <a href='$mediafire' class='twitterlink nlink' target='_blank'>Dropbox</a> </span> </li> </div>"; } mysql_close (); ?>

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  • When page loads display 1st image text - hide all other text

    - by Jonah1289
    Hi I have created http://techavid.com/design/test3.html and when you load the page you see there are 3 images. The sun image is focused(in color), while the others are greyed out until clicked. That is how it should be for the images. Also when you load the page you see under each image it's own text(i.e. 1st: Sun, 2nd: Airplane, 3rd: Nano), but on page load I only want 1st:Sun to display and hide all other text until their respective image is clicked. Any idea how to do this? thanks :) J

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  • How to insert <br/> after each 5 results?

    - by Axel
    This is my code: $query = mysql_query("SELECT * FROM books ORDER BY id") or die(mysql_error()); while($row = mysql_fetch_assoc($query)) { echo $row["bookname"]." - "; } How to make only 5 books displayed in each line, by inserting a at the start if the row is 5 or 10 or 15 etc... Thanks

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  • Javascript onclick() event bubbling - working or not?

    - by user1071914
    I have a table in which the table row tag is decorated with an onclick() handler. If the row is clicked anywhere, it will load another page. In one of the elements on the row, is an anchor tag which also leads to another page. The desired behavior is that if they click on the link, "delete.html" is loaded. If they click anywhere else in the row, "edit.html" is loaded. The problem is that sometimes (according to users) both the link and the onclick() are fired at once, leading to a problem in the back end code. They swear they are not double-clicking. I don't know enough about Javascript event bubbling, handling and whatever to even know where to start with this bizarre problem, so I'm asking for help. Here's a fragment of the rendered page, showing the row with the embedded link and associated script tag. Any suggestions are welcomed: <tr id="tableRow_3339_0" class="odd"> <td class="l"></td> <td>PENDING</td> <td>Yabba Dabba Doo</td> <td>Fred Flintstone</td> <td> <a href="/delete.html?requestId=3339"> <div class="deleteButtonIcon"></div> </a> </td> <td class="r"></td> </tr> <script type="text/javascript">document.getElementById("tableRow_3339_0").onclick = function(event) { window.location = '//edit.html?requestId=3339'; };</script>

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  • Termite colony simulator using java

    - by ashii
    hi everyone, i hve to design a simulator that will maintain an environment, which consists of a collection of patches arranged in a rectangular grid of arbitrary size. Each patch contains zero or more wood chips. A patch may be occupied by one or more termites or predators, which are mobile entities that live within the world and behave according to simple rules. A TERMITE can pick up a wood chip from the patch that it is currently on, or drop a wood chip that it is carrying. Termites travel around the grid by moving randomly from their current patch to a neighbouring patch, in one of four possible directions. New termites may hatch from eggs, and this is simulated by the appearance of a new termite at a random patch within the environment. A PREDATOR moves in a similar way to termites, and if a predator moves onto a patch that is occupied by a termite, then the predator eats the termite. At initialization, the termites, predators, and wood chips are distributed randomly in the environment. Simulation then proceeds in a loop, and the new state of the environment is obtained at each iteration. i have designed the arena using jpanel but im not able to randomnly place wood,termite and predator in that arena. can any one help me out?? my code for the arena is as following: 01 import java.awt.*; 02 import javax.swing.*; 03 04 public class Arena extends JPanel 05 { 06 private static final int Rows = 8; 07 private static final int Cols = 8; 08 public void paint(Graphics g) 09 { 10 Dimension d = this.getSize(); 11 // don't draw both sets of squares, when you can draw one 12 // fill in the entire thing with one color 13 g.setColor(Color.WHITE); 14 // make the background 15 g.fillRect(0,0,d.width,d.height); 16 // draw only black 17 g.setColor(Color.BLACK); 18 // pick a square size based on the smallest dimension 19 int sqsize = ((d.width<d.height) ? d.width/Cols : d.height/Rows); 20 // loop for rows 21 for (int row=0; row<Rows; row++) 22 { 23 int y = row*sqsize; // y stays same for entire row, set here 24 int x = (row%2)*sqsize; // x starts at 0 or one square in 25 for (int i=0; i<Cols/2; i++) 26 { 27 // you will only be drawing half the squares per row 28 // draw square 29 g.fillRect(x,y,sqsize,sqsize); 30 // move two square sizes over 31 x += sqsize*2; 32 } 33 } 34 35 } 36 37 38 39 public void update(Graphics g) { paint(g); } 40 41 42 43 public static void main (String[] args) 44 { 45 46 JFrame frame = new JFrame("Arena"); 47 frame.setSize(600,400); 48 frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); 49 frame.setContentPane(new Arena()); 50 frame.setVisible(true); 51 } 52 53 }

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  • Jquery hover function doesn't work for a table...

    - by chandru_cp
    I dynamically added rows to a table but it doesn't seem to take hover effects given in jquery... Here is my code, <table id="chkbox" cellpadding="0" cellspacing="2" width="100%" class="table_Style_Border"> <tr> <td style="width:150px" class="grid_header" align="center">RackName</td> <td style="width:150px" class="grid_header" align="center">LibraryName</td> <td style="width:200px" class="grid_header" align="center">LibrarianName</td> <td style="width:200px" class="grid_header" align="center">Location</td> <td style="width:1%" class="grid_header"></td> </tr> <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <?php foreach($rackData as $key => $row) { ?> <?php printf('<tr class="%s">', ($key % 2) ? 'rowcolor' : 'alternaterowcolor'); ?> <td align="left" class="table_label"> <?=$row['rack_name']?> </td> <td align="left" class="table_label"> <?=$row['library_name']?> </td> <td align="center" class="table_label"> <?=$row['librarian']?> </td> <td align="center" class="table_label"> <?=$row['location']?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['rack_id']?>" onclick="display(this);" > </td> </tr> <? } ?> </table><div align="right" class="pagination"> <?php /*?><?php echo $links;?><?php */?></div> <script type="text/javascript"> $("#chkbox").hover(function() { $(this).addClass("resultshover"); }, function() { $(this).removeClass("resultshover"); }); </script>

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  • Is adding a bit mask to all tables in a database useful?

    - by Tom
    A colleague is adding a bit mask to all our database tables. In theory this is so we can track certain properties of each row across the entire system. For example... Is the row shipped with the system or added by the client once they've started using the system Has the row been deleted from the table (soft deletes) Is the row a default value within a set of rows Is this a good idea? Are there other uses where this approach would be beneficial? My preference is these properties are obviously important, and having a dedicated column for each property is justified to make what is happening clearer to fellow developers.

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  • Is there an algorithm for determining how much daylight there is?

    - by Pharaun
    Is there a function/algorithm that allows me to input the latitude and the approximate orbital position of the earth in so that I can determine how long the sun is up? IE during the winter it would show that the sun is only up a few hours in the far north hemisphere. I did some basic Google search and didn't find much so I was thinking that I might have to do some trigonometry that would allow me to calculate how much the earth is inclined or not toward the sun then use that information along with the latitude to figure out how much sunshine a site would be getting.

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  • first Occurrence Of Non Blank Cell vba

    - by Madhu Kiran
    Hi, I am trying to write VBA code which works on my Excel sheet. Range("A65536").End(xlUp).Row gives me the row number of the last non blank cell. similarly i am trying to get the row number of the first non blank cell in that particular column. Thanks in advance. madhu

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  • Retrieving ids from MySQL query

    - by Matt Maclennan
    I am having trouble accessing the "model_id" and "brand_id" from the foreach loop that I am using. They are the right field names, because I have echoed them successfully, and I have also "var_dumped" the array, and the IDs are there. It is just a case of implementing the relevant links on each list section. Below is the code I have. <? $output = mysqli_query("SELECT * FROM bikes, bikeTypes WHERE bikes.model_id = bikeTypes.model_id"); $result = array(); while($row = mysqli_fetch_array($output)) { $result[$row['model']][] = $row; } foreach ($result as $category => $values) { echo "<li><a href='test.php?id=" . $row['model_id'] . "'>".$category.'</a><ul>'; foreach ($values as $value) { echo "<li><a href='details.php?id=" . $row['brand_id'] . "'>" . $value['bikeName'] . "</a></li>"; } echo '</ul>'; echo '</li>'; } ?>

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  • Java RMI cannot connect to host from external client.

    - by Koe
    I've been using RMI in this project for a while. I've gotten the client program to connect (amongst other things) to the server when running it over my LAN, however when running it over the internet I'm running into the following exception: java.rmi.ConnectException: Connection refused to host: (private IP of host machine); nested exception is: java.net.ConnectException: Connection timed out: connect at sun.rmi.transport.tcp.TCPEndpoint.newSocket(Unknown Source) at sun.rmi.transport.tcp.TCPChannel.createConnection(Unknown Source) at sun.rmi.transport.tcp.TCPChannel.newConnection(Unknown Source) at sun.rmi.server.UnicastRef.invoke(Unknown Source) at java.rmi.server.RemoteObjectInvocationHandler.invokeRemoteMethod(Unknown Source) at java.rmi.server.RemoteObjectInvocationHandler.invoke(Unknown Source) at $Proxy1.ping(Unknown Source) at client.Launcher$PingLabel.runPing(Launcher.java:366) at client.Launcher$PingLabel.<init>(Launcher.java:353) at client.Launcher.setupContentPane(Launcher.java:112) at client.Launcher.<init>(Launcher.java:99) at client.Launcher.main(Launcher.java:59) Caused by: java.net.ConnectException: Connection timed out: connect at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.PlainSocketImpl.doConnect(Unknown Source) at java.net.PlainSocketImpl.connectToAddress(Unknown Source) at java.net.PlainSocketImpl.connect(Unknown Source) at java.net.SocksSocketImpl.connect(Unknown Source) at java.net.Socket.connect(Unknown Source) at java.net.Socket.connect(Unknown Source) at java.net.Socket.<init>(Unknown Source) at java.net.Socket.<init>(Unknown Source) at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(Unknown Source) at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(Unknown Source) ... 12 more This error is remeniscent of my early implementation of RMI and I can obtain the error verbatum if I run the client locally without the server program running as well. To me Connection Timed Out means a problem with the server's response. Here's the client initiation: public static void main(String[] args) { try { String host = "<WAN IP>"; Registry registry = LocateRegistry.getRegistry(host, 1099); Login lstub = (Login) registry.lookup("Login Server"); Information istub = (Information) registry.lookup("Game Server"); new Launcher(istub, lstub); } catch (RemoteException e) { System.err.println("Client exception: " + e.toString()); e.printStackTrace(); } catch (NotBoundException e) { System.err.println("Client exception: " + e.toString()); e.printStackTrace(); } } Interestingly enough no Remote Exception is thrown here. Here's the server initiation: public static void main(String args[]) { try { GameServer gobj = new GameServer(); Information gstub = (Information) UnicastRemoteObject.exportObject( gobj, 1099); Registry registry = LocateRegistry.createRegistry(1099); registry.bind("Game Server", gstub); LoginServer lobj = new LoginServer(gobj); Login lstub = (Login) UnicastRemoteObject.exportObject(lobj, 7099); // Bind the remote object's stub in the registry registry.bind("Login Server", lstub); System.out.println("Server ready"); } catch (Exception e) { System.err.println("Server exception: " + e.toString()); e.printStackTrace(); } } Bad practice with the catch(Exception e) I know but bear with me. Up to this stage I know it works fine over the LAN, here's where the exception occurs over the WAN and is the first place a method in the server is called: private class PingLabel extends JLabel { private static final long serialVersionUID = 1L; public PingLabel() { super(""); runPing(); } public void setText(String text) { super.setText("Ping: " + text + "ms"); } public void runPing() { try { PingThread pt = new PingThread(); gameServer.ping(); pt.setRecieved(true); setText("" + pt.getTime()); } catch (RemoteException e) { e.printStackTrace(); } } } That's a label placed on the launcher as a ping test. the method ping(), in gameserver does nothing, as in is a null method. It's worth noting also that ports 1099 and 7099 are forwarded to the server machine (which should be obvious from the stack trace). Can anyone see anyting I'm missing/doing wrong? If you need any more information just ask. EDIT: I'm practically certain the problem has nothing to do with my router settings. When disabling my port forwarding settings I get a slightly different error: Client exception: java.rmi.ConnectException: Connection refused to host: (-WAN IP NOT LOCAL IP-); but it appears both on the machine locally connected to the server and on the remote machine. In addition, I got it to work seamlessly when connecting the server straight tho the modem (cutting out the router. I can only conclude the problem is in my router's settings but can't see where (I've checked and double checked the port forwarding page). That's the only answer i can come up with.

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  • How to print an isosceles triangle

    - by Steve
    Hello, I'm trying to learn programming by myself, I'm working from a book that has the following problem which I can't solve: Allow the user to input two values: a character to be used for printing an isosceles triangle and the size of the peak for the triangle. For example, if the user inputs # for the character and 6 for the peak, you should produce the following display: # ## ### #### ##### ###### ##### #### ### ## # This is the code I've got so far: char character; int peak; InputValues(out character, out peak); for (int row = 1; row < peak * 2; row++) { for (int col = 1; col <= row; col++) { Console.Write(character); } Console.WriteLine(); } Console.Read() // hold console open Thanks in advance.

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  • passing a scalar query result to coalesce

    - by Fakrudeen
    How can I pass the result from a scalar [single row, single value] query to coalesce? I am trying to pick the priority as (the biggest priority so far in the table) + 1. [0 if it is the first row.] create trigger priority_SuperRuleSamples before insert on SuperRuleSamples FOR EACH ROW SET NEW.Priority=coalesce(NEW.Priority, coalesce( select Priority from SuperRuleSamples order by Priority desc limit 1, -1 )+1 )

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  • Using fopen and str_replace to auto fill a select option

    - by Anders Kitson
    Hi Everyone, I have this file 'gardens.php', which pulls data from a table called 'generalinfo' and I use fopen to send that data to a file called 'index.html'. Here is the issue, only one option is filled. I have a demo running here Garden Demo <-- this is a new updated page and location, there are more errors than I have locally If anyone could help me fix them Username:stack1 Password:stack1 Is there a better way to achieve what I want to? Thanks! Always. GARDENS.PHP <?php include("connect.php"); $results = mysql_query("SELECT * FROM generalinfo"); while($row = mysql_fetch_array($results)){ $country = $row['country']; $province = $row['province']; $city = $row['city']; $address = $row['address']; //echo $country; //echo $province; //echo $city; //echo $address; } $fd = fopen("index.html","r") or die ("Can not fopen the file"); while ($buf =fgets($fd, 1024)){ $template .= $buf; } $template = str_replace("<%country%>",$country,$template); echo $template; ?> INDEX.PHP SNIPPET <form name="filter" method="get" action="filter.php"> <select class="country" name="country"> <option><%country%></option> </select> </form>

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  • JQuery,ajax problem?

    - by user303832
    Hello,I have one table,and when I click on row,it load some content in another table,problem is,when I first time click on row it loads just one time(message 'Some msg' and message 'Some other msg' is showen one time),when I click on other row,it loads twice(messages is shown twice),third time when I click on row it loads three times,ets.Here is my code. $.ajax({ url:'<?php echo $full_path_ajax_php; ?>', data:{'what':'2','mypath':'12345678'}, dataType:'json', type: 'GET', beforeSend:function(){alert('Some msg')}, success: function(){alert('Some other msg')} }); return false; Can someone help me please to understand this.Tnx in advance.

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  • Android Parcelable create array

    - by Ozik Abdullaev
    In background i parse JSON, and then in this background i send Json to parcelable And in Parcelable i writestring with JSONObject.optString how i can write ArrayList? List<Row> result = new ArrayList<Row>(array.length()); for (int i = 0; i < array.length(); i++) { result.add(new Row(array.optJSONObject(i))); } Parcelable.java public Row(JSONObject from) { thumb = from.optString(TAG_THUMBNAILS); bigImage = from.optString(TAG_BIG_IMAGE); author = from.optString(TAG_AUTHOR); description = from.optString(TAG_DESCRIPTION); date = from.optString(TAG_DATE); } public Row(Parcel parcel) { thumb = parcel.readString(); bigImage = parcel.readString(); author = parcel.readString(); description = parcel.readString(); date = parcel.readString(); } @Override public int describeContents() { return 0; } @Override public void writeToParcel(Parcel parcel, int flags) { parcel.writeString(thumb); parcel.writeString(bigImage); parcel.writeString(author); parcel.writeString(description); parcel.writeString(date); }

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  • vba Loop over a non-contiguous range

    - by Jeffrey
    I have a non-contiguous range on rows (example address of myRange: $2:$2,$4:$205,$214:$214) and I would like to access a specific row and column within the range. I have tried the following: 'Get the value of the 2nd row, 1st column within the range myRange.rows(2).Cells(, 1).Value However, this is giving me the value of the 2nd row in the WorkSheet, and NOT in the range - meaning it is giving me address $3$1 - and not $4$1 Can someone please explain how I can access the values within in my range? (It may have to do with different areas) Thank You

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  • Converting switch statements to more elegant solution.

    - by masfenix
    I have a 9 x 9 matrix. (think of suduko). 4 2 1 6 8 1 8 5 8 3 1 5 8 1 1 7 5 8 1 1 4 0 5 6 7 0 4 6 2 5 5 4 4 8 1 2 6 8 8 2 8 1 6 3 5 8 4 2 6 4 7 4 1 1 1 3 5 3 8 8 5 2 2 2 6 6 0 8 8 8 0 6 8 7 2 3 3 1 1 7 4 now I wanna be able to get a "quadrant". for example (according to my code) the quadrant 2 , 2 returns the following: 5 4 4 2 8 1 6 4 7 If you've noticed, this is the matrix from the very center of the 9 x 9. I've split everything up in to pairs of "3" if you know what i mean. the first "ROW" is from 0 - 3, the second from 3 - 6, the third for 6 - 9.. I hope this makes sense ( I am open to alternate ways to go about this) anyways, heres my code. I dont really like this way, even though it works. I do want speed though beccause i am making a suduko solver. //a quadrant returns the mini 3 x 3 //row 1 has three quads,"1", "2", 3" //row 2 has three quads "1", "2", "3" etc public int[,] GetQuadrant(int rnum, int qnum) { int[,] returnMatrix = new int[3, 3]; int colBegin, colEnd, rowBegin, rowEnd, row, column; //this is so we can keep track of the new matrix row = 0; column = 0; switch (qnum) { case 1: colBegin = 0; colEnd = 3; break; case 2: colBegin = 3; colEnd = 6; break; case 3: colBegin = 6; colEnd = 9; break; default: colBegin = 0; colEnd = 0; break; } switch (rnum) { case 1: rowBegin = 0; rowEnd = 3; break; case 2: rowBegin = 3; rowEnd = 6; break; case 3: rowBegin = 6; rowEnd = 9; break; default: rowBegin = 0; rowEnd = 0; break; } for (int i = rowBegin ; i < rowEnd; i++) { for (int j = colBegin; j < colEnd; j++) { returnMatrix[row, column] = _matrix[i, j]; column++; } column = 0; row++; } return returnMatrix; }

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  • Cant display button on specific rows of UITableView properly for iPhone

    - by varunwg
    Hi, I am trying to have a button for selected rows of my table. Here is the example code I am using: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *ControlRowIdentifier = @"ControlRowIdentifier"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:ControlRowIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:ControlRowIdentifier] autorelease]; } if ([indexPath row] > 5) { UIImage *buttonUpImage = [UIImage imageNamed:@"button_up.png"]; UIImage *buttonDownImage = [UIImage imageNamed:@"button_down.png"]; UIButton *button = [UIButton buttonWithType:UIButtonTypeCustom]; button.frame = CGRectMake(0.0, 0.0, buttonUpImage.size.width, buttonUpImage.size.height); [button setBackgroundImage:buttonUpImage forState:UIControlStateNormal]; [button setBackgroundImage:buttonDownImage forState:UIControlStateHighlighted]; [button setTitle:@"Tap" forState:UIControlStateNormal]; [button addTarget:self action:@selector(buttonTapped:) forControlEvents:UIControlEventTouchUpInside]; cell.accessoryView = button; } NSUInteger row = [indexPath row]; NSString *rowTitle = [list objectAtIndex:row]; cell.textLabel.text = rowTitle; return cell; } This code works absolutely fine when loaded for 1st time. So, as per the logic it shows 'Tap' button for all rows greater than 5. Problem occurs when I scroll up and down. Once I do that it just starts putting that button at any random row. I dont understand why it does that and it'll be really helpful if someone can give some tips on this. Thanks.

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  • Catchable fatal error: Object of class view_user could not be converted to string in C:\xampp\xampp\htdocs\textile\admin\view_class.php on line 9 [closed]

    - by user1282142
    <?php include('config.inc'); class view_user { function view($user) { $temp = mysql_query("SELECT * from register_user where user_name = '$user'"); $value = mysql_fetch_array($temp); $query = mysql_query("SELECT order_user.design_name, order_user.reaad, order_user.pick, order_user.yarn_detail FROM register_user INNER JOIN order_user ON register_user.register_id = '$value[register_id]' and order_user.register_id = $value[register_id]"); if($query) { echo "<center><table border = 1> <tr> <th>Design Name</th> <th>Read</th> <th>Pick</th> <th>Design Detail</th> </tr>"; while($row = mysql_fetch_array($query)) { echo "<tr>"; echo "<td>$row[design_name]</td>"; echo "<td>$row[reaad]</td>"; echo "<td>$row[pick]</td>"; echo "<td>$row[yarn_detail]</td>"; echo"</tr></center>"; } } else { echo"User doesn't Exist"; include('footer1.php'); } } } ?>

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  • Parsing XML file using a for loop

    - by Johnny Spintel
    I have been working on this program which inserts an XML file into a MYSQL database. I'm new to the whole .jar idea by inserting packages. Im having an issue with parse(), select(), and children(). Can someone inform me how I could fix this issue? Here is my stack trace and my program below: Exception in thread "main" java.lang.Error: Unresolved compilation problems: The method select(String) is undefined for the type Document The method children() is undefined for the type Element The method children() is undefined for the type Element The method children() is undefined for the type Element The method children() is undefined for the type Element at jdbc.parseXML.main(parseXML.java:28) import java.io.*; import java.sql.*; import org.jsoup.Jsoup; import org.w3c.dom.*; import javax.xml.parsers.*; public class parseXML{ public static void main(String xml) { try{ BufferedReader br = new BufferedReader(new FileReader(new File("C:\\staff.xml"))); String line; StringBuilder sb = new StringBuilder(); while((line=br.readLine())!= null){ sb.append(line.trim()); } Document doc = Jsoup.parse(line); StringBuilder queryBuilder; StringBuilder columnNames; StringBuilder values; for (Element row : doc.select("row")) { // Start the query queryBuilder = new StringBuilder("insert into customer("); columnNames = new StringBuilder(); values = new StringBuilder(); for (int x = 0; x < row.children().size(); x++) { // Append the column name and it's value columnNames.append(row.children().get(x).tagName()); values.append(row.children().get(x).text()); if (x != row.children().size() - 1) { // If this is not the last item, append a comma columnNames.append(","); values.append(","); } else { // Otherwise, add the closing paranthesis columnNames.append(")"); values.append(")"); } } // Add the column names and values to the query queryBuilder.append(columnNames); queryBuilder.append(" values("); queryBuilder.append(values); // Print the query System.out.println(queryBuilder); } }catch (Exception err) { System.out.println(" " + err.getMessage ()); } } }

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  • What does Apache need to support both mysqli and PDO?

    - by Nathan Long
    I'm considering changing some PHP code to use PDO for database access instead of mysqli (because the PDO syntax makes more sense to me and is database-agnostic). To do that, I'd need both methods to work while I'm making the changeover. My problem is this: so far, either one or the other method will crash Apache. Right now I'm using XAMPP in Windows XP, and PHP Version 5.2.8. Mysqli works fine, and so does this: $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database'; $sql = "SELECT * FROM `employee`"; But this line makes Apache crash: $dbc->query($sql); I don't want to redo my entire Apache or XAMPP installation, but I'd like for PDO to work. So I tried updating libmysql.dll from here, as oddvibes recommended here. That made my simple PDO query work, but then mysqli queries crashed Apache. (I also tried the suggestion after that one, to update php_pdo_mysql.dll and php_pdo.dll, to no effect.) Test Case I created this test script to compare PDO vs mysqli. With the old copy of libmysql.dll, it crashes if $use_pdo is true and doesn't if it's false. With the new copy of libmysql.dll, it's the opposite. if ($use_pdo){ $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database<br />'; $sql = "SELECT * FROM `employee`"; $dbc->query($sql); foreach ($dbc->query($sql) as $row){ echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } else { $dbc = @mysqli_connect($hostname, $username, $password, $dbname) OR die('Could not connect to MySQL: ' . mysqli_connect_error()); $sql = "SELECT * FROM `employee`"; $result = @mysqli_query($dbc, $sql) or die(mysqli_error($dbc)); while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } What does Apache need in order to support both methods of database query?

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