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  • How to get ImageButton size within Android GridView?

    - by wufoo
    I'm subclassing ImageButton in order to draw lines on it and trying to figure out where the actual button coordinates are within my gridview. I am using onGlobalLayout to setup Top, Bottom, Right and Left, but these seem to be for the actual "square" within the grid, and not the actual button (see image). The purple lines are drawn in myImageButton.onDraw() using coords gathered from myImageButton.onGlobalLayout(). I thought these would be for the button, but they seem to be from something else. Not sure what. I'd like the purple lines to match the outline of the button so the lines I draw appear on the button and not just floating out in the LinearLayout somewhere. The light blue is the background color of the vertical LinearLayout holding the Textview (for the number) and myImageButton. Any way to get the actual button size? XML Layout: <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/lay_cellframe" android:layout_width="fill_parent" android:layout_height="fill_parent" > <LinearLayout android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="fill_vertical|fill_horizontal" android:orientation="vertical" > <TextView android:id="@+id/tv_cell" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2dp" android:gravity="center" android:text="TextView" android:textSize="10sp" /> <com.example.icaltest2.myImageButton android:id="@+id/imageButton1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_gravity="center" android:layout_margin="0dp" android:adjustViewBounds="false" android:background="@android:drawable/btn_default" android:scaleType="fitXY" android:src="@android:color/transparent" /> </LinearLayout> </FrameLayout> myImageButton.java public myImageButton (Context context, AttributeSet attrs) { super (context, attrs); mBounds = new Rect(); ViewTreeObserver vto = this.getViewTreeObserver (); vto.addOnGlobalLayoutListener (ogl); Log.d (TAG, "myImageButton"); } ... OnGlobalLayoutListener ogl = new OnGlobalLayoutListener() { @Override public void onGlobalLayout () { Rect b = getDrawable ().getBounds (); mBtnTop = b.centerY () - (b.height () / 2); mBtnBot = b.centerY () + (b.height () / 2); mBtnLeft = b.centerX () - (b.width () / 2); mBtnRight = b.centerX () + (b.width () / 2); } }; ... @Override protected void onDraw (Canvas canvas) { super.onDraw (canvas); Paint p = new Paint (); p.setStyle (Paint.Style.STROKE); p.setStrokeWidth (1); p.setColor (Color.MAGENTA); canvas.drawCircle (mBtnLeft, mBtnTop, 2, p); canvas.drawCircle (mBtnLeft, mBtnBot, 2, p); canvas.drawCircle (mBtnRight, mBtnTop, 2, p); canvas.drawCircle (mBtnRight, mBtnBot, 2, p); canvas.drawRect (mBtnLeft, mBtnTop, mBtnRight, mBtnBot, p); }

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  • UIBezierPath too many paths = too slow?

    - by HHHH
    I have a loop in which I'm adding many (10000+) lines to a UIBezierPath. This seems to be fine, but once I try and render the bezierpath, my device becomes extremely slow and jerky. Is this because I've added too many lines to my path? Adding lines to UIBezierPath - simplified: (this seems fine) [path moveToPoint:CGPointZero]; for (int i = 0; i < 10000; i++ ) { [path addLineToPoint:CGPointMake(i, i)]; } Rendering BeizerPath (Suggested by Rob) - this seems slow. - (void)drawBezierAnimate:(BOOL)animate { UIBezierPath *bezierPath = path; CAShapeLayer *bezier = [[CAShapeLayer alloc] init]; bezier.path = bezierPath.CGPath; bezier.strokeColor = [UIColor blueColor].CGColor; bezier.fillColor = [UIColor clearColor].CGColor; bezier.lineWidth = 2.0; bezier.strokeStart = 0.0; bezier.strokeEnd = 1.0; [self.layer addSublayer:bezier]; if (animate) { CABasicAnimation *animateStrokeEnd = [CABasicAnimation animationWithKeyPath:@"strokeEnd"]; animateStrokeEnd.duration = 100.0; animateStrokeEnd.fromValue = [NSNumber numberWithFloat:0.0f]; animateStrokeEnd.toValue = [NSNumber numberWithFloat:1.0f]; [bezier addAnimation:animateStrokeEnd forKey:@"strokeEndAnimation"]; } } Qs: 1) Is this because I'm adding too many paths too quickly? 2) I want to eventually draw many different lines of different colors, so I assume I would need to create multiple (10000+) UIBezierPaths - would this help or greatly slow the device as well? 3) How would I get around this? Thanks in advance for your help.

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  • Inner shadow issue in Illustrator CS5

    - by Joe Conlin
    I gave a comp to my client that I did in Photoshop. I used an inner shadow but now have realized the in Illustrator CS5 I have no such "easy" filter. I have spent 2 days seaching the web, trying tutorials, etc. to no avail. Every tutorial seems to use text but I am not using text. Anyone that can answer I would forever been in debt... :) This is the image with the inner shadow inside the stripes that I am needing to duplicate. Thanks!

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  • How can you deflect a direction/magnitude vector based on a direction/magnitude vector and a collided triangle?

    - by JeanOTF
    So, I have a Triangle-AABB collision algorithm and I have it returning the triangle that the AABB collided with. I was hoping with the 3 vectors of the triangle and the direction/magnitude of the movement would let me determine a deflected vector so that when you run against the wall at an angle you move slower, depending on the angle of collision, but along side the wall. This would remove the sticky collision problem with only moving when there is not a collision. Any suggestions or references would be greatly appreciated! Thanks.

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  • PDF Making with Rotated Image for iPhone

    - by MobiHunterz
    I'm having problems with drawing rotated images on PDF, my output is worse. My case is, we don't know have any fixed co-ordinates. X,Y, rotation, etc. depends on ImageView itself. I select the ImageView and rotate it through Sliders. Check on ZOSH application. I need to implement functionalities like that app. I want to make PDF by adding images one by one. Please send me link for any example that can help me out, I'm stuck here. I'm drawing the image on PDF based on center of the imageview. Please help me, Thank You.

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  • how to dynamically recolor a CGGradientRef

    - by saintmac
    I have three CGGradientRef's that I need to be able to dynamically recolor. When I Initialise the CGGradientRef's the first time I get the expected result, but every time I attempt to change the colors nothing happens. Why? gradient is an instance variable ins a subclass of CALayer: @interface GradientLayer : CALayer { CGGradientRef gradient; //other stuff } @end Code: if (gradient != NULL) { CGGradientRelease(gradient); gradient = NULL; } RGBA color[360]; //set up array CGColorSpaceRef rgb = CGColorSpaceCreateDeviceRGB(); gradient = CGGradientCreateWithColorComponents ( rgb, color, NULL, sizeof (color) / sizeof (color[0]) ); CGColorSpaceRelease(rgb); [self setNeedsDisplay];

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  • Animating removeFromSuperview

    - by user230949
    I'd like to animate the transition from a subview back to the super view. I display the subview using: [UIView beginAnimations:@"curlup" context:nil]; [UIView setAnimationDelegate:self]; [UIView setAnimationDuration:.5]; [UIView setAnimationTransition:UIViewAnimationTransitionCurlUp forView:self.view cache:YES]; [self.view addSubview:self.mysubview.view]; [UIView commitAnimations]; The above works fine. It's going back to the super view that I don't get any animation: [UIView beginAnimations:@"curldown" context:nil]; [UIView setAnimationDelegate:self]; [UIView setAnimationDuration:.5]; [UIView setAnimationTransition:UIViewAnimationTransitionCurlDown forView:self.view cache:YES]; [self.view removeFromSuperview]; [UIView commitAnimations]; Is there something different I should be doing to get the subview to animate when removed?

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  • Cloning ID3DXMesh with declration that has 12 floats breaks?

    - by meds
    I have the following vertex declration: struct MESHVERTInstanced { float x, y, z; // Position float nx, ny, nz; // Normal float tu, tv; // Texcoord float idx; // index of the vertex! float tanx, tany, tanz; // The tangent const static D3DVERTEXELEMENT9 Decl[6]; static IDirect3DVertexDeclaration9* meshvertinstdecl; }; And I declare it as such: const D3DVERTEXELEMENT9 MESHVERTInstanced::Decl[] = { { 0, 0, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_POSITION, 0 }, { 0, 12, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_NORMAL, 0 }, { 0, 24, D3DDECLTYPE_FLOAT2, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TEXCOORD, 0 }, { 0, 32, D3DDECLTYPE_FLOAT1, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TEXCOORD, 1 }, { 0, 36, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TANGENT, 0 }, D3DDECL_END() }; What I try to do next is copy an ID3DXMesh into another one with the new vertex declaration as such: model->CloneMesh( model->GetOptions(), MESHVERTInstanced::Decl, gd3dDevice, &pTempMesh ); When I try to get the FVF size of pTempMesh (D3DXGetFVFVertexSize(pTempMesh-GetFVF())) I get '0' though the size should be 48. The whole thing is fine if I don't have the last declaration, '{ 0, 36, D3DDECLTYPE_FLOAT3, D3DDECLMETHOD_DEFAULT, D3DDECLUSAGE_TANGENT, 0 },' in it and the CloneMesh function does not return a FAIL. I've also tried using different declarations such as D3DDECLUSAGE_TEXCOORD and that has worked fine, returning a size of 48. Is there something specific about D3DDECLUSAGE_TANGENT I don't know? I'm at a complete loss as to why this isn't working...

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  • implementation musical instrument using audio unit

    - by Develop.Kim
    post same question at apple developer forum ,too hi first sorry that my english is poor.. i want develop iphone application that playing musical instrument like 'ocarina' but don't need blow mic features. so first i tried to find that how implementation 'virtual musical instrument ' in iphone development. the during the decide implementation using 'Audio Unit' to report this article (link) so i want two kind of questions. i recognize that the 'musical instrument' can be divided into three sound that 'attack', 'sustain' , 'release'. 'decay' maybe included (link) . How implementation when audio unit base 'AUInstrumentBase' each sound ? i download sample 'SinSynth' (link) . i want play note this instrument unit for analyze source and study. Is there way to using AULab? expected the way using MIDI input . but i don't have MIDI. in addition, i wonder that i would think it right the way. to ask the advice... thank for reading poor english my article.

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  • What exactly is the Nullify delete rule doing?

    - by dontWatchMyProfile
    Does that mean that if I delete an managed object which has references (relationship) to some others, the relationships are removed to those others? Example: objectA references objectB and objectC. objectA gets deleted, it's relationship to objectB and objectC is set to the Nullify rule. What happens in detail?

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  • Merging and splitting overlapping rectangles to produce non-overlapping ones

    - by uj
    I am looking for an algorithm as follows: Given a set of possibly overlapping rectangles (All of which are "not rotated", can be uniformly represented as (left,top,right,bottom) tuplets, etc...), it returns a minimal set of (non-rotated) non-overlapping rectangles, that occupy the same area. It seems simple enough at first glance, but prooves to be tricky (at least to be done efficiently). Are there some known methods for this/ideas/pointers? Methods for not necessarily minimal, but heuristicly small, sets, are interesting as well, so are methods that produce any valid output set at all.

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  • Editable CATextLayer?

    - by Ron
    I have several CATextLayers. When I doubleclick one of them, I want to be able to edit it's string. Think of text as it's handled in Keynote or many other apps. Any ideas? I thought of putting an editable textfield right in front of the layer and then dismiss it on enter, but I didn't get far. :-( I target Mac OS X 10.5 with Objective-C 2.0 and Garbage Collection. Any help or pointers would be greatly appreciated. Thanks in advance!!

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  • Detecting coincident subset of two coincident line segments

    - by Jared Updike
    This question is related to: How do I determine the intersection point of two lines in GDI+? (great explanation of algebra but no code) How do you detect where two line segments intersect? (accepted answer doesn't actually work) But note that an interesting sub-problem is completely glossed over in most solutions which just return null for the coincident case even though there are three sub-cases: coincident but do not overlap touching just points and coincident overlap/coincident line sub-segment For example we could design a C# function like this: public static PointF[] Intersection(PointF a1, PointF a2, PointF b1, PointF b2) where (a1,a2) is one line segment and (b1,b2) is another. This function would need to cover all the weird cases that most implementations or explanations gloss over. In order to account for the weirdness of coincident lines, the function could return an array of PointF's: zero result points (or null) if the lines are parallel or do not intersect (infinite lines intersect but line segments are disjoint, or lines are parallel) one result point (containing the intersection location) if they do intersect or if they are coincident at one point two result points (for the overlapping part of the line segments) if the two lines are coincident

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  • How can I draw the control points of a Bézier Path in Java?

    - by Sanoj
    I have created a Path of Bézier curves and it works fine to draw the path. But I don't know How I can draw the Control Points together with the Path. Is that possible or do I have to keep track of them in another datastructure? I am creating the path with: Path2D.Double path = new Path2D.Double(); path.moveTo(0,0); path.curveTo(5, 6, 23, 12, 45, 54); path.curveTo(34, 23, 12, 34, 2, 3); And drawing it with: g2.draw(path);

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  • Can a JPEG compressed image be rotated without a loss in quality?

    - by Mat
    JPEG is a lossy compression scheme, so decompression-manipulation-recompression normally reduces the image quality further for each step. Is it possible to rotate a JPEG image without incurring further loss? From what little I know of the JPEG algorithm, it naively seems possible to avoid further loss with a bit of effort. Which common image manipulation programs (e.g. GIMP, Paint Shop Pro, Windows Photo Gallery) and graphic libraries cause quality loss when performing a rotation and which don't?

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  • Calculating the angle between two points

    - by kingrichard2005
    I'm currently developing a simple 2D game for Android. I have a stationary object that's situated in the center of the screen and I'm trying to get that object to rotate and point to the area on the screen that the user touches. I have the constant coordinates that represent the center of the screen and I can get the coordinates of the point that the user taps on. I'm using the formula outlined in this forum: How to get angle between two points? -It says as follows "If you want the the angle between the line defined by these two points and the horizontal axis: double angle = atan2(y2 - y1, x2 - x1) * 180 / PI;". -I implemented this, but I think the fact the I'm working in screen coordinates is causing a miscalculation, since the Y-coordinate is reversed. I'm not sure if this is the right way to go about it, any other thoughts or suggestions are appreciated.

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  • Transform shape built of contour splines to simple polygons

    - by Cheery
    I've dumped glyphs from truetype file so I can play with them. They have shape contours that consist from quadratic bezier curves and lines. I want to output triangles for such shapes so I can visualize them for the user. Traditionally I might use libfreetype or scan-rasterise this kind of contours. But I want to produce extruded 3D meshes from the fonts and make other distortions with them. So, how to polygonise shapes consisting from quadratic bezier curves and lines? There's many contours that form the shape together. Some contours are additive and others are subtractive. The contours are never open. They form a loop. (Actually, I get only contour vertices from ttf glyphs, those vertices define whether they are part of the curve or not. Even though it is easy to decompose these into bezier curves and lines, knowing the data is represented this way may be helpful for polygonizing the contours to triangles)

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