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  • Parallel.Foreach loop creating multiple db connections throws connection errors?

    - by shawn.mek
    Login failed. The login is from an untrusted domain and cannot be used with Windows authentication I wanted to get my code running in parallel, so I changed my foreach loop to a parallel foreach loop. It seemed simple enough. Each loop connects to the database, looks up some stuff, performs some logic, adds some stuff, closes the connection. But I get the above error? I'm using my local sql server and entity framework (each loop uses it's own context). Is there some problem with connecting multiple times using the same local login or something? How did I get around this? I have (before trying to covert to a parallel.foreach loop) split my list of objects that I am foreach looping through into four groups (separate csv files) and run four concurrent instances of my program (which ran faster overall than just one, thus the idea for parallel). So it seems connecting to the db shouldn't be a problem? Any ideas? EDIT: Here's before var gtgGenerator = new CustomGtgGenerator(); var connectionString = ConfigurationManager.ConnectionStrings["BioEntities"].ConnectionString; var allAccessionsFromObs = _GetAccessionListFromDataFiles(collectionId); ForEach(cloneIdAndAccessions in allAccessionsFromObs) DoWork(gtgGenerator, taxonId, organismId, cloneIdAndAccessions, connectionString)); after var gtgGenerator = new CustomGtgGenerator(); var connectionString = ConfigurationManager.ConnectionStrings["BioEntities"].ConnectionString; var allAccessionsFromObs = _GetAccessionListFromDataFiles(collectionId); Parallel.ForEach(allAccessionsFromObs, cloneIdAndAccessions => DoWork(gtgGenerator, taxonId, organismId, cloneIdAndAccessions, connectionString)); Inside the DoWork I use the BioEntities using (var bioEntities = new BioEntities(connectionString)) {...}

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  • Constant CMS Session Expiry On 1&1 Cloud Server?

    - by leen3o
    I have a couple of 1&1's 'Dynamic Cloud Servers' and running Win2008R2 and they are setup as web servers, I have a number of Umbraco CMS installs on them and they have been running fine for over a year. On Saturday on BOTH servers, a very strange thing happened - As soon as I login to the CMS/Umbraco admin I am logged out with about 5 seconds? It's as if my session expires the moment I login? I have checked everything I can as I'm not really a server admin, and everything seems to be exactly as it was last week? Like I say this has happened EXACTLY the same time (Saturday) on TWO different servers? I'm just looking for ideas of what I should be looking for? Also the front end of the sites seem fine... Its only the backend when I login. I have gone to 1&1 about this, and as usual they have washed their hands saying its nothing to do with them - When I am certain it is. How can this happen on two different servers, and affect the same sites in exactly the same way? Any help, tips, things to try would be greatly appreciated.

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  • Deployment problems of asp.net 3.5 in iis 5.1

    - by peter
    i have microsoft.net 3.5 application and have IIS5.1,,for deploying website do i need to do any thing aother than this 1.In IIS i created virtual directory named SPA and i browsed in to the location where my project is lacated and i added entire project file there( Do i need to add only bin file and login page or i need to add all pages???) 2.In asp.net folder i selected tab version 2.0,, 3.when i browsed i can see all pages when i click login.aspx i am getting this error [SqlException (0x80131904): User does not have permission to perform this action.] System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection) +821651 System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj) +186 System.Data.SqlClient.TdsParser.Run(RunBehavior runBehavior, SqlCommand cmdHandler, SqlDataReader dataStream, BulkCopySimpleResultSet bulkCopyHandler, TdsParserStateObject stateObj) +1932 System.Data.SqlClient.SqlInternalConnectionTds.CompleteLogin(Boolean enlistOK) +33 System.Data.SqlClient.SqlInternalConnectionTds.AttemptOneLogin(ServerInfo serverInfo, String newPassword, Boolean ignoreSniOpenTimeout, Int64 timerExpire, SqlConnection owningObject) +172 System.Data.SqlClient.SqlInternalConnectionTds.LoginNoFailover(String host, String newPassword, Boolean redirectedUserInstance, SqlConnection owningObject, SqlConnectionString connectionOptions, Int64 timerStart) +381 System.Data.SqlClient.SqlInternalConnectionTds.OpenLoginEnlist(SqlConnection owningObject, SqlConnectionString connectionOptions, String newPassword, Boolean redirectedUserInstance) +181 System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, Object providerInfo, String newPassword, SqlConnection owningObject, Boolean redirectedUserInstance) +173 System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection) +133 System.Data.ProviderBase.DbConnectionFactory.CreatePooledConnection(DbConnection owningConnection, DbConnectionPool pool, DbConnectionOptions options) +30 System.Data.ProviderBase.DbConnectionPool.CreateObject(DbConnection owningObject) +424 System.Data.ProviderBase.DbConnectionPool.UserCreateRequest(DbConnection owningObject) +66 System.Data.ProviderBase.DbConnectionPool.GetConnection(DbConnection owningObject) +494 System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) +82 System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) +105 System.Data.SqlClient.SqlConnection.Open() +111 ChatTool.LoginForm.Page_Load(Object sender, EventArgs e) in D:\Chat tool_Ameya\ProjectCode\Unisys Project Testing\Unisys Project\Login.aspx.cs:25 System.Web.Util.CalliHelper.EventArgFunctionCaller(IntPtr fp, Object o, Object t, EventArgs e) +15 System.Web.Util.CalliEventHandlerDelegateProxy.Callback(Object sender, EventArgs e) +33 System.Web.UI.Control.OnLoad(EventArgs e) +99 System.Web.UI.Control.LoadRecursive() +47 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1436

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  • CMD Prompt > FTP Size Command

    - by Samuel Baldus
    I'm developing a PHP App on IIS 7.5, which uses PHP FTP commands. These all work, apart from ftp_size(). I've tested: cmd.exe > ftp host > username > password > SIZE filename = Invalid Command However, if I access the FTP site through an Internet Browser, the filesize is displayed. Do I need to install FTP Extensions, and if so, which ones and where do I get them? Here is the PHP Code: <?php // FTP Credentials $ftpServer = "www.domain.com"; $ftpUser = "username"; $ftpPass = "password"; // Unlimited Time set_time_limit(0); // Connect to FTP Server $conn = @ftp_connect($ftpServer) or die("Couldn't connect to FTP server"); // Login to FTP Site $login = @ftp_login($conn, $ftpUser, $ftpPass) or die("Login credentials were rejected"); // Set FTP Passive Mode = True ftp_pasv ($conn, true); // Build the file list $ftp_nlist = ftp_nlist($conn, "."); // Alphabetical sorting sort($ftp_nlist); // Display Output foreach ($ftp_nlist as $raw_file) { // Get the last modified time $mod = ftp_mdtm($conn, $raw_file); // Get the file size $size = ftp_size($conn, $raw_file); // Size is not '-1' => file if (!(ftp_size($conn, $raw_file) == -1)) { //output as file echo "Filename: $raw_file<br />"; echo "FileSize: ".number_format($size, '')."Kb</br>"; echo "Last Modified: ".date("d/m/Y H:i", $mod)."</br>"; } } ?>

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  • How do I use Perl's LWP to log in to a web application?

    - by maxjackie
    I would like to write a script to login to a web application and then move to other parts of the application: use HTTP::Request::Common qw(POST); use LWP::UserAgent; use Data::Dumper; $ua = LWP::UserAgent->new(keep_alive=>1); my $req = POST "http://example.com:5002/index.php", [ user_name => 'username', user_password => "password", module => 'Users', action => 'Authenticate', return_module => 'Users', return_action => 'Login', ]; my $res = $ua->request($req); print Dumper(\$res); if ( $res->is_success ) { print $res->as_string; } When I try this code I am not able to login to the application. The HTTP status code returned is 302 that is found, but with no data. If I post username/password with all required things then it should return the home page of the application and keep the connection live to move other parts of the application.

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  • How can I change the back button function in navigation toolbar?

    - by jackrobert
    I have developed a simple web application using JSP. It has a login page which contains username, password fields and sumbit button. It has a logout page which contains a link to the login page. And there are some pages like page1, page2, page3, page4, etc. Normal workflow is the following: After login comes page1. Then click some action and it will go to page2. Then click some action and it will go to page3. Then click some action and it will go to page4. So now I am in page4. Now click back button in navigation toolbar in browser, generally go to previous page (page3). But my requirement is, if you click back button in navigation toolbar from any page in the application, then you should go to logout page. For example: if you are in page4 and press the back button, then you should go to logout page and not to page3. How to achieve this? Is it anyway possible? Maybe with Javascript?

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  • ASP can't connect to SQL Server database

    - by birdus
    I'm trying to get a classic ASP application to connect to a local SQL Server 2008 database. The app and database were built by someone else. I'm just trying to get them installed and running on my machine (Windows 7). I'm getting the following error when when the ASP app tries to connect to the database: Could not connect to database: Error Number: -2147467259 Error Message: [ConnectionOpen (Connect()).] does not exist or access denied. I don't see any messages in the Windows Event Viewer. I'm looking at: Event Viewer-Windows Logs-Application. It's a fresh database install using a simple restore. The SQL Server install uses the default instance. SQL Server and Windows authentication are both allowed. I left the existing connection string (in the ASP code) in tact and just tried adding that to my SQL Server installation. Here's the connection string: strConn = "PROVIDER=SQLOLEDB;SERVER=localhost;UID=TheUser;PWD=ThePassword;DATABASE=TheDatabase;" To add that user to SQL Server, I went to Security/Logins in SSMS and added the user and the password. I selected the database in question as the Default database. I thought that might do the trick, but it didn't. Then, I went into TheDatabase, then went into Security there. I added a new user there, referencing the new user I had already added in server Security. Under Owned Schemas, I clicked db_owner and under Role Members I checked db_accessadmin and db_owner. None of this gave the ASP application access to the database. The sid values match in sys.database_principals and sys.server_principals for the login in question. I am able to login to SSMS using this login. The app needs to execute selects against the database like this: oConn.Execute('select * from someTable') I'm not a DBA and am sort of grasping at straws here. How do I get this thing connected? Thanks, Jay

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  • How to write custom (odd) authentication plugins for Wordpress, Joomla and MediaWiki?

    - by Bart van Heukelom
    On our network (a group of related websites - not a LAN) we have a common authentication system which works like this: On a network site ("consumer") the user clicks on a login link This redirects the user to a login page on our auth system ("RAS"). Upon successful login the user is directed back to the consumer site. Extra data is passed in the query string. This extra data does not include any information about the user yet. The consumer site's backend contacts RAS, with this extra data, to get the information about the logged in user (id, name, email, preferences, etc.). So as you can see, the consumer site knows nothing about the authentication method. It doesn't know if it's by username/password, fingerprint, smartcard, or winning a game of poker. This is the main problem I'm encountering when trying to find out how I could write custom authentication plugins for these packages, acting as consumer sites: Wordpress Joomla MediaWiki For example Joomla offers a pretty simple auth plugin system, but it depends on a username/password entered on the Joomla site. Any hints on where to start?

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  • Is there an easier way to do Classic ASP "relative path"?

    - by Alex.Piechowski
    Right now, I'm having trouble. First of all I have a page, let's call it "http://blah.com/login". That obviously goes strait to "index.asp" A line of Main.asp: <!--#include file="resource/menu.asp"--> Page top includes all of what I need for my menu... so: Part of resource/menu.htm: <div id="colortab" class="ddcolortabs"> <ul> <li><a href="main.asp" title="Main" rel="dropmain"><span>Main</span></a></li> ... </ul> </div> <!--Main drop down menu --> <div id="dropmain" class="dropmenudiv_a"> <a href="main/announcements.asp">Announcements</a> <a href="main/contacts.asp">Contact Information</a> <a href="main/MeetingPlans.asp">Meeting Plan</a> <a href="main/photos.asp">Photo Gallery</a> <a href="main/events.asp">Upcoming Events</a> </div> Let's say I click on the "announcements" (http://blah.com/login/main/announcements.asp) link... Now I'm at the announcements page! But wait, I include the same menu file. Guess what happens: I get sent to "http://blah.com/login/main/main/announcements.asp Which doesn't exist... My solution: Make a menu_sub.asp include for any subpages. But wait a second... this WORKS, but it gets REALLY REALLY messy... What can I do to use just one main "menu.asp" instead of "menu_sub.asp"? using "/main/announcements.asp" WON'T be an option because this is a web application that will be on different directories per server. Any ideas? PLEASE

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  • python global variable not working in apache

    - by Suhail
    I am facing issue with the global variable, when i run in the django development server it works fine, but in apache it doesn't work here is the code below: red= "/foodfolio3/test/" def showAddRecipe(request): #global objc if "userid" in request.session: objc["ErrorMsgURL"]= "" try: urlList= request.POST URL= str(urlList['url']) URL= URL.strip('http://') URL= "http://" + URL recipe= __addRecipeUrl__(URL) if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'): #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL" print "here global_context =", objc arurl= HttpResponseRedirect("/foodfolio3/add/import/") arurl['ErrorMsgURL']= objc["ErrorMsgURL"] #return HttpResponseRedirect("/foodfolio3/add/import/") #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) return (arurl) else: objc["recipe"] = recipe return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) except: objc["recipe"] = "" return render_to_response('addRecipe.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/" return HttpResponseRedirect("/foodfolio3/login") def showAddRecipeUrl(request): if "userid" in request.session: return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request)) else: global red red= "/foodfolio3/add/import/" return HttpResponseRedirect("/foodfolio3/login") def showLogin(request): obj = {} obj["error_message"] = "" obj["registered"] = "" if request.method == "POST": if (red == "/foodfolio3/test"): next= '/foodfolio3/recipes' else: next= red try: username = request.POST['username'] password = request.POST['password'] user = authenticate(username=username, password=password) except: user = authenticate(request=request) if user is not None: if user.is_active: login(request, user) request.session["userid"] = user.id # Redirect to a success page. return HttpResponseRedirect(next) this code works fine in django development server, but in apache, the url is getting redirected to '/foodfolio3/recipes'

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  • Rails redirections with new users and logins

    - by Kenji Crosland
    So I'm trying to get the user to return to the page they were looking at before they click "log in" This is what I got in my user application controller: def redirect_back_or_default(default) redirect_to(session[:return_to] || default) session[:return_to] = nil end And this is what I have in my sessions controller: def new @user_session = UserSession.new session[:return_to] = request.referer end end def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_back_or_default(home_path) else render :action => :new end end This works fine most of the time but if a user logs in right after they register to the site, they will get redirected to a blank page. I imagine this is the "create" action because it was the last action before going to user sessions new. So I tried this: def new @user_session = UserSession.new unless request.referer == join_path session[:return_to] = request.referer end end And this tries to take me back to the login page after I log in. What I'd really like to do is have the user see their profile when they log in for the very first time. This wouldn't give me a user id and raised a routing error def create @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_back_or_default(user_path(current_user)) else render :action => :new end end Anybody gone through these redirecting acrobatics before? I can't seem to get it to work. I'm using authlogic if that helps.

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  • Facebook Application with PHP running losing session

    - by ArneRie
    Iam trying to build an Facebook Application based on PHP. The Application is running under php on my own Webhost inside an Canvas as iFrame. I have included the newest Client Library for PHP from Facebook: facebook-php-sdk-94fcb13 To Authorize the user inside my application iam trying to use Facebook Connect, like the example shipped with the Client. Everything works fine the 1st Login, but when i hit the F5 Key to reload the page, the session is lost and i have to login again. When i call my application outside of the Facebook Canvas everything is fine. Iam not sure, but i think my Browser (Chrome/FireFox - Ubuntu) is not allowing to store an cookie inside an iFrame. Does someone knows an solution for this Problem? Here are some Parts of the Sourcecode: $facebook = new Facebook(array( 'appId' => 'x', 'secret' => 'x', 'cookie' => 'true', )); $session = $facebook->getSession(); $facebook->setSession($session); $me = null; // Session based API call. if ($session) { try { $uid = $facebook->getUser(); $me = $facebook->api('/me'); } catch (FacebookApiException $e) { error_log($e); } } // login or logout url will be needed depending on current user state. if ($me) { $logoutUrl = $facebook->getLogoutUrl(); } else { $loginUrl = $facebook->getLoginUrl(); }

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  • Linq, should I join those two queries together?

    - by 5YrsLaterDBA
    I have a Logins table which records when user is login, logout or loginFailed and its timestamp. Now I want to get the list of loginFailed after last login and the loginFailed happened within 24 hrs. What I am doing now is get the last login timestamp first. then use second query to get the final list. do you think I should join those two queris together? why not? why yes? var lastLoginTime = (from inRecord in db.Logins where inRecord.Users.UserId == userId && inRecord.Action == "I" orderby inRecord.Timestamp descending select inRecord.Timestamp).Take(1); if (lastLoginTime.Count() == 1) { DateTime lastInTime = (DateTime)lastLoginTime.First(); DateTime since = DateTime.Now.AddHours(-24); String actionStr = "F"; var records = from record in db.Logins where record.Users.UserId == userId && record.Timestamp >= since && record.Action == actionStr && record.Timestamp > lastInTime orderby record.Timestamp select record; }

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  • What is the benefit of using ONLY OpenID authentication on a site?

    - by Peter
    From my experience with OpenID, I see a number of significant downsides: Adds a Single Point of Failure to the site It is not a failure that can be fixed by the site even if detected. If the OpenID provider is down for three days, what recourse does the site have to allow its users to login and access the information they own? Takes a user to another sites content and every time they logon to your site Even if the OpenID provider does not have an error, the user is re-directed to their site to login. The login page has content and links. So there is a chance a user will actually be drawn away from the site to go down the Internet rabbit hole. Why would I want to send my users to another company's website? [ Note: my provider no longer does this and seems to have fixed this problem (for now).] Adds a non-trivial amount of time to the signup To sign up with the site a new user is forced to read a new standard, chose a provider, and signup. Standards are something that the technical people should agree to in order to make a user experience frictionless. They are not something that should be thrust on the users. It is a Phisher's Dream OpenID is incredibly insecure and stealing the person's ID as they log in is trivially easy. [ taken from David Arno's Answer below ] For all of the downside, the one upside is to allow users to have fewer logins on the Internet. If a site has opt-in for OpenID then users who want that feature can use it. What I would like to understand is: What benefit does a site get for making OpenID mandatory?

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  • Query to look up comment in one table, username in another table

    - by John
    Hello, I am using a MySQL table called "login" with the following structure: loginid, username, password, email, actcode, disabled, activated, created, points I am using another MySQL table called "comment" with the following structure: commentid, loginid, submissionid, comment, datecommented For a given "submisssionid", I would like to print out the following information from the table "comment": -The fields "comment" and "datecommented". At the same time, I would like to print out the following from the table "login": -The "username" that corresponds to the "loginid" for each row being row being selected from the table "comment". How can I do this? I tried the code below but it did not work. Thanks in advance, John $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); $sqlStr = "SELECT c.loginid ,c.submissionid ,c.comment ,c.datecommented ,l.username ,COUNT(c.commentid) countComments FROM comment c WHERE c.submissionid = $submissionid INNER JOIN login l ON c.loginid = l.loginid GROUP BY c.submissionid ORDER BY c.datecommented DESC LIMIT 100"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1">'.$row["comment"].'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a>'.$row["datecommented"].'</td>'; echo '</tr>'; } echo "</table>";

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  • Upload file onto Server from the IPhone using ASIHTTPRequest

    - by Nick
    I've been trying to upload a file (login.zip) using the ASIHTTPRequest libraries from the IPhone onto the inbuilt Apache Server in Mac OS X Snow Leopard. My code is: NSString *urlAddress = [[[NSString alloc] initWithString:self.uploadField.text]autorelease]; NSURL *url = [NSURL URLWithString:urlAddress]; ASIFormDataRequest *request; NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *dataPath = [documentsDirectory stringByAppendingPathComponent:@"login.zip"]; NSData *data = [[[NSData alloc] initWithContentsOfFile:dataPath] autorelease]; request = [[[ASIFormDataRequest alloc] initWithURL:url] autorelease]; [request setPostValue:@"login.zip" forKey:@"file"]; [request setData:data forKey:@"file"]; [request setUploadProgressDelegate:uploadProgress]; [request setShowAccurateProgress:YES]; [request setDelegate:self]; [request startAsynchronous]; The php code is : <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> I don't quite understand why the file is not uploading. If anyone could help me. I've stuck on this for 5 days straight. Thanks in advance Nik

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  • Unable to call storyboard from xib

    - by Shruti Kapoor
    I am new to iOS development. I am trying to connect to a storyboard from xib file. My xib View Controller has a "Login" which if successful should connect to storyboard. I have googled and searched on stackoverflow for a solution and I am using this code that is given everywhere: UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil]; YourViewController * yourView = (YourViewController *)[storyboard instantiateViewControllerWithIdentifier:@"identifier ID"]; I have created an identifier for my storyboard as well. However, I am not being redirected to the storyboard no matter what I try. When the login finishes, I go back to my main View Controller (xib). I should be instead redirected to the storyboard. Here is what my code looks like in a file called ProfileTabView.m: -(void) loginViewDidFinish:(NSNotification*)notification { [[NSNotificationCenter defaultCenter] removeObserver:self]; UIStoryboard* storyboard = [UIStoryboard storyboardWithName:@"Storyboard" bundle:nil]; ProfileTabView * yourView = (ProfileTabView *)[storyboard instantiateViewControllerWithIdentifier:@"myID"]; } I have implemeted this code in the function that gets called once the login is successful. However, the storyboard "Storyboard" never gets called. Am i doing this right? Am I supposed to be writing this code anywhere else? Thanks a lot for any help :)

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  • How Session out trigger on browser close?

    - by Hemant Kothiyal
    Hi, Yesterday morning i open gmail account in Internet Exlorer second tab. I checked my mail and closed that tab (not browser). Then at the time of evining i again open second tab of browser and enetr gmail.com, it automatically redirect me at my email account without asking login. I shocked and i thought i should remain browser open for whole night and today open gmail in second tab , it behave similar means without login screen it redirect in my gmail account. Then i closed that tab and open another browser session and enter gmail i again surprised that i redirect me login page. At the same time i open second tab of first browser and it automatically redirect me at mail account page. What i councluded by this behaviour is that might be gmail server keep my browser id at their server so that whenever i eneter gmail.com on second tab of first browser, it automatically redirect me at gmail account. I don't know i am right or not? Please clear me this concept? What happens with my session at gmail server when i closed my browser tab? As per my opinion it should automatically logout me but why this doesn't happened?

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  • SugarmCRM REST API always returns "null"

    - by TuomasR
    I'm trying to test out the SugarCRM REST API, running latest version of CE (6.0.1). It seems that whenever I do a query, the API returns "null", nothing else. If I omit the parameters, then the API returns the API description (which the documentation says it should). I'm trying to perform a login, passing as parameter the method (login), input_type and response_type (json) and rest_data (JSON encoded parameters). The following code does the query: $api_target = "http://example.com/sugarcrm/service/v2/rest.php"; $parameters = json_encode(array( "user_auth" => array( "user_name" => "admin", "password" => md5("adminpassword"), ), "application_name" => "Test", "name_value_list" => array(), )); $postData = http_build_query(array( "method" => "login", "input_type" => "json", "response_type" => "json", "rest_data" => $parameters )); echo $parameters . "\n"; echo $postData . "\n"; echo file_get_contents($api_target, false, stream_context_create(array( "http" => array( "method" => "POST", "header" => "Content-Type: application/x-www-form-urlencoded\r\n", "content" => $postData ) ))) . "\n"; I've tried different variations of parameters and using username instead of user_name, and all provide the same result, just a response "null" and that's it.

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  • Change a finder method w/ parameters to an association

    - by Sai Emrys
    How do I turn this into a has_one association? (Possibly has_one + a named scope for size.) class User < ActiveRecord::Base has_many :assets, :foreign_key => 'creator_id' def avatar_asset size = :thumb # The LIKE is because it might be a .jpg, .png, or .gif. # More efficient methods that can handle that are OK. ;) self.assets.find :first, :conditions => ["thumbnail = '#{size}' and filename LIKE ?", self.login + "_#{size}.%"] end end EDIT: Cuing from AnalogHole on Freenode #rubyonrails, we can do this: has_many :assets, :foreign_key => 'creator_id' do def avatar size = :thumb find :first, :conditions => ["thumbnail = ? and filename LIKE ?", size.to_s, proxy_owner.login + "_#{size}.%"] end end ... which is fairly cool, and makes syntax a bit better at least. However, this still doesn't behave as well as I would like. Particularly, it doesn't allow for further nice find chaining (such that it doesn't execute this find until it's gotten all its conditions). More importantly, it doesn't allow for use in an :include. Ideally I want to do something like this: PostsController def show post = Post.get_cache(params[:id]) { Post.find(params[:id], :include => {:comments => {:users => {:avatar_asset => :thumb}} } ... end ... so that I can cache the assets together with the post. Or cache them at all, really - e.g. get_cache(user_id){User.find(user_id, :include => :avatar_assets)} would be a good first pass. This doesn't actually work (self == User), but is correct in spirit: has_many :avatar_assets, :foreign_key => 'creator_id', :class_name => 'Asset', :conditions => ["filename LIKE ?", self.login + "_%"] (Also posted on Refactor My Code.)

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  • Spring security or BCrypt algorithm which one is good for accounts like project?

    - by Ranjith Kumar Nethaji
    I am using spring security for hashing my password.And is it safe ,because am using spring security for first time. my code here <security:http auto-config="true"> <security:intercept-url pattern="/welcome*" access="ROLE_USER" /> <security:form-login login-page="/login" default-target-url="/welcome" authentication-failure-url="/loginfailed" /> <security:logout logout-success-url="/logout" /> </security:http> authentication-failure-url="/loginfailed" /> <security:logout logout-success-url="/logout" /> </security:http> <authentication-manager> <authentication-provider> <password-encoder hash="sha" /> <user-service> <user name="k" password="7c4a8d09ca3762af61e59520943dc26494f8941b" authorities="ROLE_USER" /> </user-service> </authentication-provider> </authentication-manager> .And I havnt used bcrypt algorithm.what is your feedback for both?any recommendation?

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  • Safari and Chrome back button changes hidden and submit values in forms

    - by OverClocked
    The following problem happens on both Safari and Chrome, so probably a WebKit issue. Page A: a page that requires you to login to see, contains a form that has a type=submit button, with name=submit, and value=a Page B: some other page Page C: ask user to login page, contains a form with a type=submit button, with name=submit and value=c User visits page A, then page B. Then idles and the user's login session times out. User hits back button to go back to page A. Browser redirects user to page C. On Safari and Chrome, when C is rendered, the form on page C has the type=submit button, name=submit, but value shows up as "a". If you reload while on page C, "c" appears as the value of the name=submit button. The same problem appears with type=hidden input fields; when user hits back button, their values are also changed to some other value from some other form. Also, this problem also shows up w/o the redirect, with just submit then back. In this case the previous page renders with incorrect values for hidden and submit CGI variables. So far the only fix I can come up with is use Javascript to reset the type=hidden and type=submit variable values, after page C loads, to make sure the values are correct. But that's not clean and universally applicable. Short of WebKit fixing this error, has anyone ran into a better workaround? Thanks.

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  • How to organize RMI Client-Server eBanking architecture

    - by xenom
    I am developing a secured eBanking service in RMI with a GUI both for Server and Client. The Server must be able to log every operations (new User, deleted User, Withdrawal, Lodgement...) The Client will do these operations. As everything is secured, the Client must at first, create an account with a name and a password in the GUI. After that, the GUI adds the User in the Bank UserList(arrayList) as a new Customer and the User can do several operations. It seems straightforward at first but I think my conception is not correct. Is it correct to send the whole Bank by RMI ? Because at first I thought Bank would be the server but I cannot find another way to do that. Currently, the Client GUI asks for a login and a password, and receives the Bank by RMI. A User is characterized by a name and a hash of the password. private String name; private byte[] passwordDigest; In fact the GUI is doing every security checking and I don't know if it's relevant. When you type login//password, it will search the login in the Bank and compare the hash of the password. In fact I have the impression that the Client knows too much information because when you have the Bank you have everything.. Does it seem correct or do I need to change my implementation ?

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  • Struts 2 security

    - by Dewfy
    Does Struts 2 has complete solution for simple login task? I have simple declaration in struts.xml: <package namespace="/protected" name="manager" extends="struts-default" > <interceptors> <interceptor-stack name="secure"> <interceptor-ref name="roles"> <param name="allowedRoles">registered</param> </interceptor-ref> </interceptor-stack> </interceptors> <default-action-ref name="pindex"/> <action name="pindex" > <interceptor-ref name="completeStack"/> <interceptor-ref name="secure"/> <result>protected/index.html</result> </action> </package> Accessing to this resource shows only (Forbidden 403). So what should I do on the next step to: Add login page (standart Tomcat declaration on web.xml with <login-config> not works) ? Provide security round trip. Do I need write my own servlet or exists struts2 solutions? Thanks in advance!

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  • Problem with SQL Server "EXECUTE AS"

    - by Vilx-
    I've got the following setup: There is a SQL Server DB with several tables that have triggers set on them (that collect history data). These triggers are CLR stored procedures with EXECUTE AS 'HistoryUser'. The HistoryUser user is a simple user in the database without a login. It has enough permissions to read from all tables and write to the history table. When I backup the DB and then restore it to another machine (Virtual Machine in this case, but it does not matter), the triggers don't work anymore. In fact, no impersonation for the user works anymore. Even a simple statement such as this exec ('select 3') as user='HistoryUser' produces an error: Cannot execute as the database principal because the principal "HistoryUser" does not exist, this type of principal cannot be impersonated, or you do not have permission. I read in MSDN that this can occur if the DB owner is a domain user, but it isn't. And even if I change it to anything else (their recommended solution) this problem remains. If I create another user without login, I can use it for impersonation just fine. That is, this works just fine: create user TestUser without login go exec ('select 3') as user='TestUser' I do not want to recreate all those triggers, so is there any way how I can make the existing HistoryUser work? Bump: Sorry, but this is kinda urgent...

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