Let`s have a example hotels table:
CREATE TABLE `hotels` (
`HotelNo` varchar(4) character set latin1 NOT NULL default '0000',
`Hotel` varchar(80) character set latin1 NOT NULL default '',
`City` varchar(100) character set latin1 default NULL,
`CityFR` varchar(100) character set latin1 default NULL,
`Region` varchar(50) character set latin1 default NULL,
`RegionFR` varchar(100) character set latin1 default NULL,
`Country` varchar(50) character set latin1 default NULL,
`CountryFR` varchar(50) character set latin1 default NULL,
`HotelText` text character set latin1,
`HotelTextFR` text character set latin1,
`tagsforsearch` text character set latin1,
`tagsforsearchFR` text character set latin1,
PRIMARY KEY (`HotelNo`),
FULLTEXT KEY `fulltextHotelSearch` (`HotelNo`,`Hotel`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`,`HotelText`,`HotelTextFR`,`tagsforsearch`,`tagsforsearchFR`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_german1_ci;
In this table for example we have only one hotel with Region name = "Graubünden" (please note umlaut ü character)
And now I want to achieve same search match for phrases:
'graubunden' and
'graubünden'
This is simple with use of MySql built in
collations in regular searches as follows:
SELECT *
FROM `hotels`
WHERE `Region` LIKE CONVERT(_utf8 '%graubunden%' USING latin1)
COLLATE latin1_german1_ci
This works fine for 'graubunden' and 'graubünden' and
as a result I receive proper result, but problem is
when we make MySQL full text search
Whats wrong with this SQL statement?:
SELECT
*
FROM
hotels
WHERE
MATCH (`HotelNo`,`Hotel`,`Address`,`City`,`CityFR`,`Region`,`RegionFR`,`Country`,`CountryFR`, `HotelText`, `HotelTextFR`, `tagsforsearch`, `tagsforsearchFR`)
AGAINST( CONVERT('+graubunden' USING latin1) COLLATE latin1_german1_ci IN BOOLEAN MODE)
ORDER BY Country ASC, Region ASC, City ASC
This doesn`t return any result.
Any ideas where the dog is buried ?
