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  • How to select the most recent set of dated records from a mysql table

    - by Ken
    I am storing the response to various rpc calls in a mysql table with the following fields: Table: rpc_responses timestamp (date) method (varchar) id (varchar) response (mediumtext) PRIMARY KEY(timestamp,method,id) What is the best method of selecting the most recent responses for all existing combinations of method and id? For each date there can only be one response for a given method/id. Not all call combinations are necessarily present for a given date. There are dozens of methods, thousands of ids and at least 356 different dates Sample data: timestamp method id response 2009-01-10 getThud 16 "....." 2009-01-10 getFoo 12 "....." 2009-01-10 getBar 12 "....." 2009-01-11 getFoo 12 "....." 2009-01-11 getBar 16 "....." Desired result: 2009-01-10 getThud 16 "....." 2009-01-10 getBar 12 "....." 2009-01-11 getFoo 12 "....." 2009-01-11 getBar 16 "....." (I don't think this is the same question - it won't give me the most recent response)

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  • Why is this MySQL Join Statement not Working?

    - by Timmy
    Here is my code: $query2 = mysql_query("SELECT * FROM categories WHERE parent = $id JOIN SELECT * FROM posts WHERE main_nav_page = '$idTwo'"); while ($row2 = mysql_fetch_assoc($query2)) { $id = $row2['id']; $name = $row2['name']; $slug = $row2['slug']; $subMenuOrder = $row2['sub_menu_order']; echo "<tr>\n"; echo "<td>&nbsp; -- $name</td>\n"; echo "</tr>\n"; } Is my syntax wrong? EDIT: the error message is: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/studentw/public_html/new_nav.php on line 30

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  • Converting delimited string to multiple values in mysql

    - by epo
    I have a mysql legacy table which contains an client identifier and a list of items, the latter as a comma-delimited string. E.g. "xyz001", "foo,bar,baz". This is legacy stuff and the user insists on being able to edit a comma delimited string. They now have a requirement for a report table with the above broken into separate rows, e.g. "xyz001", "foo" "xyz001", "bar" "xyz001", "baz" Breaking the string into substrings is easily doable and I have written a procedure to do this by creating a separate table, but that requires triggers to deal with deletes, updates and inserts. This query is required rarely (say once a month) but has to be absolutely up to date when it is run, so e.g. the overhead of triggers is not warranted and scheduled tasks to create the table might not be timely enough. Is there any way to write a function to return a table or a set so that I can join the identifier with the individual items on demand?

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  • PHP MySQL New Lines / Whitespaces from textarea

    - by rob_robsen
    I've a problem about whitespaces and new lines at the beginning of a textarea. I send a json string with ajax to the php script. Then I decode the string into an php array (with json_decode). So I have a string in this array with two line breaks at the beginning. If a print the text from the array, the line breaks are there, but if I store the text into the mysql database, the line breaks are gone... Only at the beginning of the string, the line breaks gone... At the rest of the string, the line breaks are ok. Thanks for your answers! rob

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  • Help me for creating huge database in Mysql

    - by user90552
    We are building a website for business on global wise, for every country major cities are covered in this concept. I need some suggestions from PHP Mysql People. Can i create single databse for all cities or multiple databases. Because in this system contains some relations between cities ,every chamber need nearly 50 tables for networking and some other tables. If I can create separate databases for every chamber there would be nearly 50*1000 tables need because we have 1000 cities. So Please give suggestions how can i build database for my system. Thank you Ravi

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  • not null usage in mysql

    - by pradeep
    Hi, I use syntax like name varchar(20) NOT NULL in mysql..i have a big confusion over here. typically does it mean that this field is mandatory? but when i store a space in this field it accepts it.is it correct. its like while insert i say '".$_POST['name']."'. even if the name does not have any value query is executed. can any1 just clarify me on this ? is NULL and blank space same ?

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  • mysql multiple where and inner join query combination

    - by bandhunt
    I'm a little lost as how to run two mysql queries as one(return one result set to be sorted etc). I understand how to do multiple JOINS but need to combine the below which is more than just a multiple join - it would include a multiple where etc. 1st query sql = "SELECT s.id, s.song_name FROM `songs` as s INNER JOIN `artists` as a ON s.artist_id = a.id WHERE ((`a`.id = #{search}))" 2nd query sql = "SELECT s.id, s.song_name FROM `songs` as s INNER JOIN `similarments` as si ON s.artist_id = si.artist_id WHERE ((`si`.similar_id = #{search}))" And then run both queries at once so I can ORDER them etc. Or combine them as one big query (maybe put an OR somewhere)? Thanks!

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  • Deleting partial data from a field in MySQL

    - by Graham
    I am trying to remove a specific set of data from a MySQL database field, however I am not sure what the best statement would be for this. For example, if I have a data in a field such as... The use of a secondary password will allow you to gain access to your account from a non-authenticated computer. A non-authenticated computer is any computer that is not your primary computer, an elected authenticated computer or a computer that automatically deletes cookies. <p>This is a test</p> ...and I want to remove <p>This is a test</p> from the field, what statement would be best?

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  • mySQL php query - news/ friends feed

    - by rpsep2
    I want to show a user the recent uploads from their friends. I have the users friends id's in an array: $friends A user could have, potentially, thousands of friends. I can select the uploads from 1 of a users friends with: $row = $mysqli->query("SELECT * FROM photos WHERE uploader_id = ".$friend." ORDER BY date_uploaded DESC LIMIT ".$page.", 25"); But I need to find all of a users friends uploads. I thought about doing this in a loop iterating over the $friends array, but then I'd be potentially running thousands of mysql queries. How can I do this most efficiently? so to clarify: search a 'photos' table for photos which are uploaded by specific users(friends), held in $friends variable, sort by date_uploaded and limit to x results so I can have pages 1, 2, 3 etc.

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  • maven tomcat plugin with mysql driver in $catalina_home/lib

    - by gerolf
    Hi everybody, i am trying to use a container managed datasource (via context.xml) in tomcat. The corresponding jar file needs to go in $catalina_home/lib, otherwise tomcat can't find it. (not in webapp/WEB-INF/lib, because it is managed by the webserver, not by the application itself) the problem is: I am using maven with the maven-tomcat-plugin, so I don't have a $catalina_home (everything is distributed in my .m2 -repository). So the question is: how can I add the mysql driver jar to the classpath of the tomcat server (mvn tomcat:run)? thanks a lot, gerolf.

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  • MySQL Query involving column names containing math operators

    - by devil_fingers
    I'm a MySQL scrub, and I have asked around and checked around the internet for what I'm sure will turn out to be something obvious, but I'm very frustrated with what I thought would be a very, very simple query not working. So here goes. Please be gentle. Basically, in a large database, some of the column names contain mathematical operators like "/" and "+." (Don't ask, it's not my database, I can't do anything about it). Here is the "essence" of my query (I took out the irrelevant stuff for the sake of this question): SELECT PlayerId, Season, WPA/LI AS WPALI FROM tht.stats_batting_master WHERE Season = "2010" AND teamid > 0 AND PA >= 502 GROUP BY playerid ORDER BY WPALI DESC When I run this, it returns "Unknown column 'LI' in 'field list'," I assume because it sees the "/" in WPA/LI as a division sign. Like I said, I'm sure this is easy enough to work around (it must be given how much this database is used), but I haven't' been able to figure out how. Thanks in advance for any help.

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  • MySQL ON DUPLICATE KEY UPDATE issue

    - by user644347
    Hi could some one look at this and tell me where I am going wrong. I have an SQL statement that when I echo using php I get this to screen INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY UPDATE 'GenreName' = 'Drama' WHERE 'GenreID' = '18' INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '16' , 'GenreName' = 'Animation' ON DUPLICATE KEY UPDATE 'GenreName' = 'Animation' WHERE 'GenreID' = '16' And here is the statement $sql="INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '{$genresID[$i]}' , 'GenreName' = '{$genreName[$i]}' ON DUPLICATE KEY UPDATE 'GenreName' = '{$genreName[$i]}' WHERE 'GenreID' = '{$genresID[$i]}'"; This is the error I recieve: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY ' at line 1 Any help would be greatly appreciated, thanks in advance.

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  • Why doesn't MySQL support millisecond / microsecond precision?

    - by Byron Whitlock
    So I just found the most frustrating bug ever in MySQL. Apparently the TIMESTAMP field, and supporting functions do not support any greater precision than seconds!? So I am using PHP and Doctrine, and I really need those microseconds (I am using the actAs: [Timestampable] property). I found a that I can use a BIGINT field to store the values. But will doctrine add the milliseconds? I think it just assigns NOW() to the field. I am also worried the date manipulation functions (in SQL) sprinkled through the code will break. I also saw something about compiling a UDF extension. This is not an acceptable because I or a future maintainer will upgrade and poof, change gone. Has anyone found a suitable workaround?

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  • Export MySQL Data as Insert Statements

    - by gav
    Hi All, I'm working in Ubuntu with MySql and I also have Query Browser and Administrator installed, I'm not afraid of the command line either if it helps. I want simply to be able to run a query and see a result set but then convert that result set into a series of commands that could be used to create the same rows in a table of an identical schema. I hope the question makes sense, it's quite a simple problem and one that must have been solved but I can't for the life of me work out where this kind of conversion is made available. Thanks in advance, Gav

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  • Simplest one-to-many Map case in Hibernate doesn't work in MySQL

    - by Malvolio
    I think this is pretty much the simplest case for mapping a Map (that is, an associative array) of entities. @Entity @AccessType("field") class Member { @Id protected long id; @OneToMany(cascade = CascadeType.ALL, fetch=FetchType.LAZY) @MapKey(name = "name") private Map<String, Preferences> preferences = new HashMap<String, Preferences>(); } @Entity @AccessType("field") class Preferences { @ManyToOne Member member; @Column String name; @Column String value; } This looks like it should work, and it does, in HSQL. In MySQL, there are two problems: First, it insists that there be a table called Members_Preferences, as if this were a many-to-many relationship. Second, it just doesn't work: since it never populates Members_Preferences, it never retrieves the Preferences. [My theory is, since I only use HSQL in memory-mode, it automatically creates Members_Preferences and never really has to retrieve the preferences map. In any case, either Hibernate has a huge bug in it or I'm doing something wrong.]

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  • mysql - offset problem

    - by Phil Jackson
    Hi, I recently posted a question about getting last 3 results in table in the correct order. I now want the get all comments apart from the last 3 in the correct order. Here is my syntax; SELECT * FROM (SELECT * FROM $table ORDER BY ID DESC OFFSET 3) AS T ORDER BY TIME_STAMP the error i am receiving is; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OFFSET, 3) AS T ORDER BY TIME_STAMP' at line 1 I can't seem to get it to work. Any help much appreciated.

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  • Using AND/OR mysql commands with FROM_UNIXTIME

    - by scatteredbomb
    Trying to select a query in php/mysql to get "Upcoming Items" in a calendar. We store the dates in the DB as a unix time. Here's what my query looks like right now SELECT * FROM `calendar` WHERE (`eventDate` > '$yesterday') OR (FROM_UNIXTIME(eventDate, '%m') > '$current_month' AND `$yearly` = '1') ORDER BY `eventDate` LIMIT 4 This is giving me an error "Unknown column '' in 'where clause'". I'm sure it has to do with my use of parenthesis (which I've never used before in a query) and the FROM_UNIXTIME command. Can someone help me out and let me know how I've screwed this up? Thanks!

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  • mySQL INSERT INTO SELECT not working

    - by Industrial
    Hi everyone, I am trying to implement the "Closure Table" structure in a php/mySQL webapp from Bill Karwins "SQL Antipatterns" slideshare presentation: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back The first step is to insert some stuff into my tree (page 73 in slide): Easy to insert a new child of comment #5: INSERT INTO Comments ... (Generates comment #8) INSERT INTO TreePaths (ancestor, descendant) VALUES (8, 8); INSERT INTO TreePaths (ancestor, descendant) SELECT ancestor, 8 FROM TreePaths WHERE descendant = 5; I try to translate all this into Codeigniters active record db-style language, and that's about where I get stuck. I cant understand how the second insert gets it's values. Is there anyone out there who can help me out with this?

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  • MySQL order by error in PHP

    - by theflyinghaiwian
    Hi, I'm making a simple cms system for a site I'm making for non-tech users to edit... So far so good but when I try and run this code I keep getting: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''pages' ORDER BY 'pages'.'pageOrder' ASC LIMIT 0 , 30' at line 1 By the error it looks like a problem with the order by section and indeed it works without it... $sql = "SELECT * FROM 'pages' ORDER BY 'pages'.'pageOrder' ASC LIMIT 0 , 30"; $result = mysql_query($sql) or die(mysql_error()); Now I know there is nothing wrong with the code because originally I wrote my own SQL but then after it failed I robbed some from phpmyadmin and it still gives the error but it works in phpmyadmin... I'm really at my wits end with this, help is very much appreciated thank you...

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  • mysql join with a "bounce" off a third table

    - by Enkay
    I have 3 mysql tables. companies with company_id and company_name products with product_id and company_id names with product_id, product_name and other info about the product I'm trying to output the product_name and the company_name in one query for a given product_id. Basically I need information from the names and companies tables and the link between them is the products table. How do I do a join that needs to "bounce" off a third table? Something like this but this obviously doesn't work : SELECT product_name, company_name FROM names LEFT OUTER JOIN companies ON (names.product_id = products.product_id and products.company_id = companies.company_id) WHERE product_id = '12345' Thanks!

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  • How to add indexes to MySQL tables?

    - by Michael
    I've got a very large MySQL table with about 150,000 rows of data. Currently, when I try and run SELECT * FROM table WHERE id = '1'; the code runs fine as the ID field is the primary index. However, recently for a development in the project, I have to search the database by another field. For example SELECT * FROM table WHERE product_id = '1'; This field was not previously indexed, however, I've added it as an index but when I try to run the above query, the results is very slow. An EXPLAIN query reveals that there is no index for the product_id field when I've already added one and as a result the query takes any where from 20 minutes to 30 minutes to return a single row. EDIT: My full EXPLAIN results are: | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+----------------------+------+---------+------+------+------------------+ | 1 | SIMPLE | table | ALL | NULL | NULL | NULL | NULL | 157211 | Using where | +----+-------------+-------+------+----------------------+------+---------+------+------+------------------+

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  • mysql - check if data exists across multiple tables

    - by Dd Daym
    I am currently running this query inside MySQL to check if the specified values exists within the table associated with them. SELECT COUNT(artist.artist_id), COUNT(album.album_id), COUNT(tracks.track_id) FROM artist, album, tracks WHERE artist.artist_id = 320295 OR album.album_id = 1234 OR tracks.track_id = 809 The result I get from running this query is all 1, meaning that all the statements after the WHERE clause is true. To further check the query's reliability, I changed the tracks.track_ = 809 to 802, which I know does not match. However the results displayed are still all 1, meaning that they were all successfully matched even when I purposefully inserted a value which would not have matched. How do I get it to show 1 for a match and 0 for no matches within the same query? EDIT: I have inserted an image of the query running

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  • how to select and group mysql data based on the follwoing table

    - by user1151680
    how can I achieve the desired result in mysql if my table looks like this. result|year 1 |2011 2 |2011 1 |2011 0 |2011 1 |2012 2 |2012 1 = Won, 2 = lost, 0 = draw Every year can have multiple values like this. Not sure how I can get the desired result like below. year won lost draw totalPlayed 2011 2 1 1 3 2012 1 1 0 2 I have tried the following query but does not get the desired result select year, league_types.league_name, sum(if(result = 1,1,0)) as won, sum(if(result = 0,1,0)) as draw, sum(if(result = 4,1,0)) as noResult, sum(if(result = 2,1,0)) as lost, sum(if(result = 3,1,0)) as tied, sum(if(result > 0 and result < 4,1,0)) as played from match_score_card inner join fixtures on match_score_card.match_id = fixtures.match_id inner join league_types on fixtures.league_id = league_types.league_id where team_id = 1 group by year order by year desc

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  • Improving MySQL Update Query Efficiency

    - by Russell C.
    In our database tables we keep a number of counting columns to help reduce the number of simple lookup queries. For example, in our users table we have columns for the number of reviews written, photos uploaded, friends, followers, etc. To help make sure these stay in sync we have a script that runs periodically to check and update these counting columns. The problem is that now that our database has grown significantly the queries we have been using are taking forever to run since they are totally inefficient. I would appreciate someone with more MySQL knowledge than myself to recommend how we can improve it's efficiency: update users set photos=(select count(*) from photos where photos.status="A" AND photos.user_id=users.id) where users.status="A"; If this were a select statement I would just use a join but I'm not sure if that is possible with update. Thanks in advance for your help!

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  • QSql can not connect to MySQL

    - by haha
    I have this code db.QSqlDatabase::addDatabase("QMYSQL"); db.setHostName("localhost"); //db.setHostName("127.0.0.1"); //db.setPort(3306); db.setDatabaseName("final"); db.setUserName("ll"); db.setPassword("123456"); bool ok = db.open(); When I run it, I get the following error message error code : Access denied for user 'root'@'localhost' (using password: NO) QMYSQL: Unable to connect I'm not connecting to MySQL by root@localhost but *ll@localhost. Why do I get this error message? Where is the problem?

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