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  • Is typeid of type name always evaluated at compile time in c++ ?

    - by cyril42e
    I wanted to check that typeid is evaluated at compile time when used with a type name (ie typeid(int), typeid(std::string)...). To do so, I repeated in a loop the comparison of two typeid calls, and compiled it with optimizations enabled, in order to see if the compiler simplified the loop (by looking at the execution time which is 1us when it simplifies instead of 160ms when it does not). And I get strange results, because sometimes the compiler simplifies the code, and sometimes it does not. I use g++ (I tried different 4.x versions), and here is the program: #include <iostream> #include <typeinfo> #include <time.h> class DisplayData {}; class RobotDisplay: public DisplayData {}; class SensorDisplay: public DisplayData {}; class RobotQt {}; class SensorQt {}; timespec tp1, tp2; const int n = 1000000000; int main() { int avg = 0; clock_gettime(CLOCK_REALTIME, &tp1); for(int i = 0; i < n; ++i) { // if (typeid(RobotQt) == typeid(RobotDisplay)) // (1) compile time // if (typeid(SensorQt) == typeid(SensorDisplay)) // (2) compile time if (typeid(RobotQt) == typeid(RobotDisplay) || typeid(SensorQt) == typeid(SensorDisplay)) // (3) not compile time ???!!! avg++; else avg--; } clock_gettime(CLOCK_REALTIME, &tp2); std::cout << "time (" << avg << "): " << (tp2.tv_sec-tp1.tv_sec)*1000000000+(tp2.tv_nsec-tp1.tv_nsec) << " ns" << std::endl; } The conditions in which this problem appear are not clear, but: - if there is no inheritance involved, no problem (always compile time) - if I do only one comparison, no problem - the problem only appears only with a disjunction of comparisons if all the terms are false So is there something I didn't get with how typeid works (is it always supposed to be evaluated at compilation time when used with type names?) or may this be a gcc bug in evaluation or optimization? About the context, I tracked down the problem to this very simplified example, but my goal is to use typeid with template types (as partial function template specialization is not possible). Thanks for your help!

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  • How to make OSX application that just runs opens some file type and runs arbitrary Ruby code?

    - by taw
    It's trivial to make a program executable from shell - just put #!/usr/bin/ruby on top, chmod +x it and done. Unfortunately OSX won't let me associate file type with such scripts - it requires its .apps instead. This sort of distinction doesn't seem to exist on other operating systems. What's the simplest way of making such .app, which would merely execute some arbitrary Ruby code?

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  • HTML / CSS How to add image icon to input type="button" ?

    - by Brett
    Hi, I'm using this css, but it puts an image in the center. Any way to left or right align an icon using an input type="button" html button, so that the text and the image fit on the button nicely? background: url('/common/assets/images/icons/16x16/add.png');background-position:center;background-repeat:no-repeat;

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  • How to display full documentation of a method as you type in VS?

    - by drasto
    The title is pretty descriptive... Is there any extension that let me see FULL documentation of the method I'm typing ? I would like to see the documentation as I can see it in Object Browser with description of parameters and everything not just some "summary". So what I'd like to see when I type String.Format is: Of cause with an option to see all overrides. It may be part of intelisence or I don't know what it does not really matter.

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  • How to find the class object of Java generic type?

    - by Samuel Yung
    Assume I have a generic type P which is an Enum, that is <P extends Enum<P>>, and I want to get the Enum value from a string, for example: String foo = "foo"; P fooEnum = Enum.valueOf(P.class, foo); This will get a compile error because P.class is invalid. So what can I do in order to make the above code work?

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  • Why can't your switch statement data type be long Java?

    - by Fostah
    Here's an excerpt from Sun's Java tutorials: A switch works with the byte, short, char, and int primitive data types. It also works with enumerated types (discussed in Classes and Inheritance) and a few special classes that "wrap" certain primitive types: Character, Byte, Short, and Integer (discussed in Simple Data Objects ). There must be a good reason why the long primitive data type is not allowed. Anyone know what it is?

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  • How can I check the network connection type using the Windows API?

    - by Jufkey
    How can I programmatically retrieve the current connection type (eg. LAN or Direct connection)? InternetGetConnectedState() isn't very reliable. For instance, I'm connected to a wireless network, but ConTypeRet is 18, which is INTERNET_CONNECTION_LAN & INTERNET_RAS_INSTALLED. Isn't there any way to make sure that ConTypeRet is either INTERNET_CONNECTION_LAN or INTERNET_CONNECTION_MODEM?

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  • Is prefixing Windows Forms control names with their type OK?

    - by name
    I have seen many responses that say that prefixing variables with their type is bad, since C# is statically typed and we have Intellisense, but I find that prefixing the names of the controls is useful because I don't need to remember the name of the controls or switch to the designer frequently. For example: btnLoad // Button tbFilePath // TextBox tvFileSystem // TreeView Is this considered bad? If it is, what's the alternative?

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  • Where i get the better idea to which type of application base should be in iphone?

    - by Rajendra Bhole
    Hi, I want to develop an application in which i doesn't any idea about how to create my app with which controller class i should i have gave? My application first screen contain TabBarController and i have also inserting UINavigationController. On above scenario i little bit confused which type of controller(confusion in TabBarController, NavigationBarController or simple ViewController ya windows based appliaction) should i take.

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  • Select Elements in nested Divs using JQuery

    - by PIKP
    I have the following html markup inside a Div named item and I want to select all the elements (inside nested divs) and clear the values. As shown in following given Jquery I have managed to access elements in each Div by using.children().each(). But the the problem is .children().each()goes one level down at a time from the parent div, so I have repeated the same code block with multiple .children() to access the elements inside nested Divs, can anyone suggest me a method to do this without repeating the code for N number of nested divs . html markup <div class="item"> <input type="hidden" value="1234" name="testVal"> <div class="form-group" id="c1"> <div class="controls "> <input type="text" value="Results" name="s1" maxlength="255" id="id2"> </div> </div> <div class="form-group" id="id4"> <input type="text" value="Results" name="s12" maxlength="255" id="id225"> <div class="form-group" id="id41"> <input type="text" value="Results" name="s12" maxlength="255" id="5"> <div class="form-group" id="id42"> <input type="text" value="Results" name="s12" maxlength="255" id="5"> <div class="form-group" id="id43"> <input type="text" value="Results" name="s12" maxlength="255" id="id224"> </div> </div> </div> </div> </div> My Qjuery script var row = $(".item:first").clone(false).get(0); $(row).children().each(function () { updateElementIndex(this, prefix, formCount); if ($(this).attr('type') == 'text') { $(this).val(''); } if ($(this).attr('type') == 'hidden' && ($(this).attr('name') != 'csrfmiddlewaretoken')) { $(this).val(''); } if ($(this).attr('type') == 'file') { $(this).val(''); } if ($(this).attr('type') == 'checkbox') { $(this).attr('checked', false); } $(this).remove('a'); }); // Relabel or rename all the relevant bits $(row).children().children().each(function () { updateElementIndex(this, prefix, formCount) if ($(this).attr('type') == 'text') { $(this).val(''); } if ($(this).attr('type') == 'hidden' && ($(this).attr('name') != 'csrfmiddlewaretoken')) { $(this).val(''); } if ($(this).attr('type') == 'file') { $(this).val(''); } if ($(this).attr('type') == 'checkbox') { $(this).attr('checked', false); } $(this).remove('a'); });

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