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  • How to write a regular expression for "everything between X and Y" for use with preg_replace

    - by pg
    I want to take a variable called $encoded_str and and remove cd1, CD1 and anything between the first 'l' and the last blank space. So for example "lp6 id4 STRINGcd1" would return "STRING". I'm using PHP 4 for now so I can't use str_ireplace, I have this: $encoded_str=str_replace('CD1','',$encoded_str); $encoded_str=str_replace('cd1','',$encoded_str); $encoded_str=preg_replace('X','',$encoded_str); I've RTFM for preg_replace but am a bit confused. What should I replace the X with and can you suggest a decent introductory primer for writing regular expressions?

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  • Spring MVC Table selected row

    - by ich-bin-drin
    Hi, in a Spring MVC 2.5 application i'm using a spring <form:form> component and in this form a table with c:forEach is rendered. In each row a submit button is placed in. If i start a submit by clicking a button i would like to knwo, which button has processed the submit. <form:form commandName="formObject"> <table class="data-table" cellpadding="1" cellspacing="1" border="0"> <thead> <tr> </tr> </thead> <c:forEach items="${list}" var="document" varStatus="row"> <tr> <td> <input type="submit" value="${document.title}"/> <td> </tr> </c:forEach> </table> </form:form> THX.

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  • Expression parser library for Android.

    - by Malx
    What is the best way to evaluate simple conditional statements like: "a>b" ? "x-4<10+y & y>x" ? Expressions are loaded from external file. Variables are set in application. Syntax used is not essential. It may be "&" or "and" or any other supported with language/library. I need to take different action depending on result of evaluation - is it true or false. Could I use any parser already included with Andorid? Is there some way to use JS "eval" from browser component? Is it possible to use sqlite expressions to get true/false result without selecting anything? Those libraries are implemented in native code. Will it be faster and less battery expensive?

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  • Regular Expression to Match All Characters after another Regex Match

    - by Anthony Wood
    I know this may sound a little confusing, so I am open to suggestions on renaming the title. Basically I have string such as C:...\Downloads\Folder\SubFolder\SubSubFolder. and I want to return the SubFolder and SubSubFolder only. So far, my Regex looks like (?=\\Downloads\\.*?\\).* which matches Downloads\Folder\SubFolder\SubSubFolder. Does anybody have any Ideas what I am missing???? All the solutions below seem to work (except if you didn't know "Folder"). Potentially a bug with the tool I was using to test the regular expressions.

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  • Simple Search and Replace use of Regular Expression

    - by nunos
    So, I am adapting some code I found online to suit my needs. However, my set_pixel function has two more parameters. Since there are lots of calls to this function even doing a quick paste over would be very tedious. So, I thought this would be a good time for me to learn some simple regular expressions. So, I have calls of this type: set_pixel(arg1, arg2); which I want to change to something like: set_pixel(arg1, arg2, arg3, arg4); Note: arg1 and and 2 should be preserved, whereas arg3 and arg4 are most of the time the same. How can I achieve this?

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  • Java - Regular expression question

    - by Jacob
    I am new to regular expressions. I want to use java's replaceAll() function to replace any CSS comments in a string. Basically I want to use regex to search for anything that is surrounded by "/*" and "*/" and replace it with "".

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  • Cadr of a list involving assoc function

    - by user3619045
    I have looked around on the net and cant find an answer to my query. I would really appreciate if someone could provide a good answer without down rating this post. In Lisp car, cdr are used on data mode like '(whatever here) which makes sense to me. Now, in the book Land of Lisp the author is explaining how to build a text engine and suddenly he uses the following description to make a function. (defun describe-location (location nodes) (cadr (assoc location nodes))) Can I ask why is he doing a cadr on a list and how come it provides a response and not an error? shouldn't it be a data mode i.e with a quote in front of the opening bracket '(whatever here)? and also why is he using assoc as in (assoc location nodes) and not (assoc 'garden *nodes*) Isn't the second correct way to use assoc ? I may be missing the big picture and as such would really appreciate someone explaining these key points please. Many thanks!

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  • Call function based off of a string in Lisp

    - by powerj1984
    I am passing in command line arguments to my Lisp program and they are formatted like this when they hit my main function: ("1 1 1" "dot" "2 2 2") I have a dot function and would like to call it directly from the argument, but this isn't possible because something like (funcall (second args)...) receives "dot" and not dot as the function name. I tried variations of this function: (defun remove-quotes (s) (setf (aref s 0) '"")) to no avail, before realizing that the quotes were not really a part of the string. Is there a simple way to do this, or should I just check each string and then call the appropriate function? Thanks!

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  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

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  • regular expression for validation not working

    - by Camran
    I have a "description textarea" inside a form where user may enter a description for an item. This is validated with javascript before the form beeing submitted. One of the validation-steps is this: else if (!fld.value.match(desExp)){ And desExp: var desExp = /^\s*(\w[^\w]*){3}.*$/gm; Now my problem, this works fine on all cases except for descriptions where the description BEGINS with a special character of the swedish language (å, ä, ö). This wont work: åäö hello world But this will: hello world åäö Any fixes? Thanks

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • Help to write regular expression

    - by Ockonal
    Hello, I have to get any text between: Final-Recipient: RFC822; !HERE! Action I need !HERE! from this example. There could be any string. I tried something like: $Pattern = '/Final-Recipient: RFC822; (.*) Action/'; But it doesn't work. upd Here is the string I'm trying to parse: http://dpaste.com/187638/

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  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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  • Is there a way to rotate an html table?

    - by Josh
    Is there a way to rotate an html table? So, say I had a table like this: <table id="table-1" cellspacing="0" cellpadding="2"> <tr><td>1</td></tr> <tr><td>2</td></tr> <tr><td>3</td></tr> <tr><td>4</td></tr> <tr><td>5</td></tr> <tr><td>6</td></tr> </table> and wanted to some sort of button that had javascript behind it that could rotate the table any which direction. For example, clicking the right button, results in: <table id="table-1" cellspacing="0" cellpadding="2"> <tr><td>6</td><td>5</td><td>4</td><td>3</td><td>2</td><td>1</td></tr> </table> I have a drag and drop plugin that uses a table, and I am trying to do a piece that allows for a user to add to a queue (that results in the table), and then they can also rotate it around as well. Thanks.

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  • Turning logical expression around

    - by BluePrint
    I have the following code: bool s = true; for (...; ...; ...) { // code that defines A, B, C, D // and w, x, y, z if (!(A < w) && s == true) { s = false; } if (!(B < x) && s == true) { s = false; } if (!(C < y) && s == true) { s = false; } if (!(D < z) && s == true) { s = false; } } This code is working well. However, I want to, for several (unimportant) reasons, change the code so that I can initiate s = false; and set it to true inside the if-statement. It tried the following: bool s = false; for (...; ...; ...) { // code that defines A, B, C, D // and w, x, y, z if (A >= w && s == false) { s = true; } if (B >= x && s == false) { s = true; } if (C >= y && s == false) { s = true; } if (D >= z && s == false) { s = true; } } However, this is not working properly as the code above is working. I know thought wrong somewhere in the logic, but I can't figure out where. Does anbyone see my probably obvious error? EDIT: Added three more if-statemets. Missed them since they were commented away.

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  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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