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  • Is it just me? I find LINQ to XML to be sort of cumbersome, compared to XPath.

    - by Cheeso
    I am a C# programmer, so I don't get to take advantage of the cool XML syntax in VB. Dim itemList1 = From item In rss.<rss>.<channel>.<item> _ Where item.<description>.Value.Contains("LINQ") Or _ item.<title>.Value.Contains("LINQ") Using C#, I find XPath to be easier to think about, easier to code, easier to understand, than performing a multi-nested select using LINQ to XML. Look at this syntax, it looks like Greek swearing: var waypoints = from waypoint in gpxDoc.Descendants(gpx + "wpt") select new { Latitude = waypoint.Attribute("lat").Value, Longitude = waypoint.Attribute("lon").Value, Elevation = waypoint.Element(gpx + "ele") != null ? waypoint.Element(gpx + "ele").Value : null, Name = waypoint.Element(gpx + "name") != null ? waypoint.Element(gpx + "name").Value : null, Dt = waypoint.Element(gpx + "cmt") != null ? waypoint.Element(gpx + "cmt").Value : null }; All the casting, the heavy syntax, the possibility for NullPointerExceptions. None of this happens with XPath. I like LINQ in general, and I use it on object collections and databases, but my first go-round with querying XML led me right back to XPath. Is it just me? Am I missing something? EDIT: someone voted to close this as "not a real question". But it is a real question, stated clearly. The question is: Am I misunderstanding something with LINQ to XML?

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  • Best XML Parser for RSS Feeds in Objective C ?

    - by Ansari
    Hi all, I am going to develop an application which will parse the RSS feeds and display the items in my custom cell.(Cell containing the image, label, description, etc). The most popular way of parsing is using the NSXMLParser. But this is bit of a lengthy way. So is there any other way to do this. Or my question will be, which is the best xml parser for objective-c ?

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  • Is there an easy way to read an XML file in Java?

    - by user303135
    I'm fairly new to Java and am writing an app that needs an XML config file. The problem I have is that there doesn't seem to be any easy way to do this, which seems a bit strange. I've looked SAX and DOM and both seem quite complicated. Are there any other good API's out there? What's the best way to do this in Java? Thanks...

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  • How to drop null values with a native Oracle XML DB Web Service?

    - by gfjr
    I am using native Oracle XML DB Web Services (using a PL/SQL function with a web service). I want to drop null values (put nothing in the output (no XML element)). It's working with Oracle 11.2.0.1.0 but not with Oracle 11.2.0.3.0. Just to clarify... I don't want to consume a webservice with PL/SQL, I want to publish my PL/SQL packages/procedures/functions as a web service! Hope someone can help me. Thank you. In this example is the column "country" null. Oracle 11.2.0.1.0 (this is what I want): <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <GET_PERSONOutput xmlns="http://xmlns.oracle.com/orawsv/TESTSTUFF/GET_PERSON"> <RETURN> <PERSON> <PERSON_ID>3</PERSON_ID> <FIRST_NAME>Harry</FIRST_NAME> <LAST_NAME>Potter</LAST_NAME> </PERSON> </RETURN> </GET_PERSONOutput> </soap:Body> </soap:Envelope> Oracle 11.2.0.3.0: <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <GET_PERSONOutput xmlns="http://xmlns.oracle.com/orawsv/TESTSTUFF/GET_PERSON"> <RETURN> <PERSON> <PERSON_ID>3</PERSON_ID> <FIRST_NAME>Harry</FIRST_NAME> <LAST_NAME>Potter</LAST_NAME> <COUNTRY/> </PERSON> </RETURN> </GET_PERSONOutput> </soap:Body> </soap:Envelope>

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  • Parsing external XML file with C#, what's the most aesthetic way?

    - by Itay
    Hi, say there is an xml file, which not created by me, with a known schema (for example, rss). how would you parse it with C#? would you do that manually by XDocument etc, or would you use XMLSerializer and create a correspond class? or would you use Visual Studio tools to generate classes using a dtd file (that you'll write). what do you think the most aesthetic, easy, not error-prone way?

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  • Query XML file with PHP to return certain bookmarks...

    - by josh brown
    I have an XML file full of bookmarks from Google Bookmarks. (File: http://gist.github.com/324844) I want to pull the bookmark based on this path: xml_api_reply-bookmarks-bookmark-labels-label. So, my question is How can I use SimpleXML to grab the bookmarks that have the label Inspiration? Some bookmarks may have more than one bookmark.

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  • How to return this XML-RPC response in an array using PHP?

    - by mind.blank
    I'm trying to put together a WordPress plugin and I want to grab a list of all categories (of other WordPress blogs) via XML-RPC. I have the following code and it looks like it works so far: function get_categories($rpcurl,$username,$password){ $rpcurl2 = $rpcurl."/xmlrpc.php"; $params = array(0,$username,$password,true); $request = xmlrpc_encode_request('metaWeblog.getCategories',$params); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $rpcurl2); curl_setopt($ch, CURLOPT_HEADER, false); curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type: text/xml")); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt($ch, CURLOPT_POSTFIELDS, $request); $results = curl_exec($ch); $res = xmlrpc_decode($results); curl_close($ch); return $res; } If I use $res I get the following string as the response: Array If I use $results then I get: categoryId17 parentId0 descriptionTest categoryDescription categoryNameTest htmlUrlhttp://test.yoursite.com/?cat=17 rssUrlhttp://test.yoursite.com/?feed=rss2&amp;cat=17 categoryId1 parentId0 descriptionUncategorized categoryDescription categoryNameUncategorized htmlUrlhttp://test.yoursite.com/?cat=1 rssUrlhttp://test.yoursite.com/?feed=rss2&amp;cat=1 I need to pull out the names after description so Uncategorized and Test in this case. It's my first time coding in PHP. I got these results by echoing them to the page, so not sure if they get changed in that process or not... By the way I modified the above code from one that posts to a WordPress blog remotely so maybe I haven't set some of the options correctly? With var_dump($res) I get: array(2) { [0]=> array(7) { ["categoryId"]=> string(2) "17" ["parentId"]=> string(1) "0" ["description"]=> string(4) "Test" ["categoryDescription"]=> string(0) "" ["categoryName"]=> string(4) "Test" ["htmlUrl"]=> string(40) "http://test.youreventwebsite.com/?cat=17" ["rssUrl"]=> string(54) "http://test.youreventwebsite.com/?feed=rss2&cat=17" } [1]=> array(7) { ["categoryId"]=> string(1) "1" ["parentId"]=> string(1) "0" ["description"]=> string(13) "Uncategorized" ["categoryDescription"]=> string(0) "" ["categoryName"]=> string(13) "Uncategorized" ["htmlUrl"]=> string(39) "http://test.youreventwebsite.com/?cat=1" ["rssUrl"]=> string(53) "http://test.youreventwebsite.com/?feed=rss2&cat=1" } }

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