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  • UICollectionView with one static cell and N dynamic ones from a fetchresultscontroller exception

    - by nflacco
    I'm trying to make a UITableView that shows a blog post and comments for that post. My setup is a tableview in storyboard with two dynamic prototype cells. The first cell is for the post and should never change. The second cell represents the 0 to N comments. My cellForRowAtIndexPath method shows the post cell properly, but fails to get the comment at the given index path (though if I comment out the fetch I get the appropriate number of comment cells with a green background that I set as a visual debug thing). let comment = fetchedResultController.objectAtIndexPath(indexPath) as Comment I get the following exception on this line: 2014-08-24 15:06:40.712 MessagePosting[21767:3266409] *** Terminating app due to uncaught exception 'NSRangeException', reason: '*** -[__NSArrayM objectAtIndex:]: index 1 beyond bounds [0 .. 0]' *** First throw call stack: ( 0 CoreFoundation 0x0000000101aa43e5 __exceptionPreprocess + 165 1 libobjc.A.dylib 0x00000001037f9967 objc_exception_throw + 45 2 CoreFoundation 0x000000010198f4c3 -[__NSArrayM objectAtIndex:] + 227 3 CoreData 0x00000001016e4792 -[NSFetchedResultsController objectAtIndexPath:] + 162 Section and cell setup: override func tableView(tableView: UITableView!, numberOfRowsInSection section: Int) -> Int { // #warning Incomplete method implementation. // Return the number of rows in the section. switch section { case 0: return 1 default: if let realPost:Post = post { return fetchedResultController.sections[0].numberOfObjects } else { return 0 } } } override func tableView(tableView: UITableView!, cellForRowAtIndexPath indexPath: NSIndexPath!) -> UITableViewCell! { switch indexPath.section { case 0: let cell = tableView.dequeueReusableCellWithIdentifier(postViewCellIdentifier, forIndexPath: indexPath) as UITableViewCell cell.backgroundColor = lightGrey if let realPost:Post = self.post { cell.textLabel.text = realPost.text } return cell default: let cell = tableView.dequeueReusableCellWithIdentifier(commentCellIdentifier, forIndexPath: indexPath) as UITableViewCell cell.backgroundColor = UIColor.greenColor() let comment = fetchedResultController.objectAtIndexPath(indexPath) as Comment // <---------------------------- :( cell.textLabel.text = comment.text return cell } } FRC: func controllerDidChangeContent(controller: NSFetchedResultsController!) { tableView.reloadData() } func getFetchedResultController() -> NSFetchedResultsController { fetchedResultController = NSFetchedResultsController(fetchRequest: taskFetchRequest(), managedObjectContext: managedObjectContext, sectionNameKeyPath: nil, cacheName: nil) return fetchedResultController } func taskFetchRequest() -> NSFetchRequest { if let realPost:Post = self.post { let fetchRequest = NSFetchRequest(entityName: "Comment") let sortDescriptor = NSSortDescriptor(key: "date", ascending: false) fetchRequest.predicate = NSPredicate(format: "post = %@", realPost) fetchRequest.sortDescriptors = [sortDescriptor] return fetchRequest } else { return NSFetchRequest(entityName: "") } }

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  • Django: many-to-one fields and data integrity

    - by John
    Let's say that I have a Person who runs an inventory system. Each Person has some Cars, and each Car has a very large number of Parts (thousands, let's say). A Person, Bob, uses a Django form to create a Car. Now, Bob goes to create some Parts. It is only at the form level that Django knows that the Parts belong to some specific Car, and that the Parts.ForeignKey(Car) field should only have a specific Car as a choice. When creating a Part, you have to mess with the form's constructor or similar in order to limit the choice of Cars to only the cars owned by Bob. It does not seem proper that to enforce this ownership at the form level. It seems that other users' Cars must be inaccessible to anyone but the owner of the Car. What do you all think about this, and is there any way to enforce this?

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  • System.Windows.Forms.DataVisualization Namespace Fine in One Class but Not in Another

    - by jxpx777
    Hi. I'm getting this error The type or namespace name 'DataVisualization' does not exist in the namespace 'System.Windows.Forms' (are you missing an assembly reference?) Here is my using section of the class: using System; using System.Collections; using System.Collections.Generic; using System.Windows.Forms.DataVisualization.Charting; using System.Windows.Forms.DataVisualization.Charting.Borders3D; using System.Windows.Forms.DataVisualization.Charting.ChartTypes; using System.Windows.Forms.DataVisualization.Charting.Data; using System.Windows.Forms.DataVisualization.Charting.Formulas; using System.Windows.Forms.DataVisualization.Charting.Utilities; namespace myNamespace { public class myClass { // Usual class stuff } } The thing is that I am using the same DataVisualization includes in another class. The only thing that I can think that is different is that the classes that are giving this missing namespace error are Solution Items rather than specific to a project. The projects reference them by link. Anyone have thoughts on what the problem is? I've installed the chart component, .Net 3.5 SP1, and the Chart Add-in for Visual Studio 2008. UPDATE: I moved the items from Solution Items to be regular members of my project and I'm still seeing the same behavior. UPDATE 2: Removing the items from the Solution Items and placing them under my project worked. Another project was still referencing the files which is why I didn't think it worked previously. I'm still curious, though, why I couldn't use the namespace when the classes were Solution Items but moving them underneath a project (with no modifications, mind you) instantly made them recognizable. :\

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  • How can I map one to one relationship in Fluent NHibernate. I have tried everything else

    - by RM
    I have this table structure and would like to map it using Fluent Hibernate (subclass if possible). I cannot change the structure because the database has too many records and might cause major applications rework. It would be easier if the Id from Party table was a foreign key in person and organization table, but in the particular scenario the database has person and organization key as a foreign key in party table. Any help would be great. Party table Id PersonId OrganizationId Person table Id FName LName Organization table Id OrgName OrgDescription

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  • Insert rows into MySQL table while changing one value

    - by Jonathan
    Hey all- I have a MySQL table that defines values for a specific customer type. | CustomerType | Key Field 1 | Key Field 2 | Value | Each customer type has 10 values associated with it (based on the other two key fields). I am creating a new customer type (TypeB) that is exactly the same as another customer type (TypeA). I want to insert "TypeB" as the CustomerType but then just copy the values from TypeA's rows for the other three fields. Is there an SQL insert statement to make this happen? Somthing like: insert into customers(customer_type, key1, key2, value) values "TypeB" union select key1, key2, value from customers where customer_type = "TypeA" Thanks- Jonathan

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  • Moving a large number of files in one directory to multiple directories

    - by Axsuul
    I am looking to create a Windows batch script to move about 2,000 files and splitting them up so that there are 10 files per folder. I have attempted creating a batch script but the syntax really boggles my mind. Here is what I have so far @echo off :: Config parameters set /a groupsize = 10 :: initial counter, everytime counter is 1, we create new folder set /a n = 1 :: folder counter set /a nf = 1 for %%f in (*.txt) do ( :: if counter is 1, create new folder if %n% == 1 ( md folder%nf% set /a n += 1 ) :: move file into folder mv -Y %%f folder%nf%\%%f :: reset counter if larger than group size if %n% == %groupsize% ( set /a n = 1 ) else ( set /a n += 1 ) ) pause Basically what this script does is loop through each .txt file in the directory. It creates a new directory in the beginning and moves 10 files into that directory, then creates a new folder again and moves another 10 files into that directory, and so on. However, I'm having problems where the n variable is not being incremented in the loop? I'm sure there's other errors too since the CMD window closes on me even with pause. Any help or guidance is appreciated, thanks for your time!

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  • .htaccess more than one command

    - by Stefan
    Hey I have an .htaccess file with the following code: <Files ~ "item|profile|category|search"> ForceType application/x-httpd-php </Files> What I want is to add a re-write rule as well which changes any body who navigates tot he site ot use http://www.domain.com sintead of http://domain.com I have the code stored somewhere else for it however I can't seem to just place in the file as it corrupts? Or just doesn't work... I wish I knew more about .htaccess files How can I add this in? Thanks, Stefan

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  • JPA @ManyToMany on only one side?

    - by Ethan Leroy
    I am trying to refresh the @ManyToMany relation but it gets cleared instead... My Project class looks like this: @Entity public class Project { ... @ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER) @JoinTable(name = "PROJECT_USER", joinColumns = @JoinColumn(name = "PROJECT_ID", referencedColumnName = "ID"), inverseJoinColumns = @JoinColumn(name = "USER_ID", referencedColumnName = "ID")) private Collection<User> users; ... } But I don't have - and I don't want - the collection of Projects in the User entity. When I look at the generated database tables, they look good. They contain all columns and constraints (primary/foreign keys). But when I persist a Project that has a list of Users (and the users are still in the database), the mapping table doesn't get updated gets updated but when I refresh the project afterwards, the list of Users is cleared. For better understanding: Project project = ...; // new project with users that are available in the db System.out.println(project getUsers().size()); // prints 5 em.persist(project); System.out.println(project getUsers().size()); // prints 5 em.refresh(project); System.out.println(project getUsers().size()); // prints 0 So, how can I refresh the relation between User and Project?

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  • Regex with all optional parts but at least one required

    - by Alan Mendelevich
    I need to write a regex that matches strings like "abc", "ab", "ac", "bc", "a", "b", "c". Order is important and it shouldn't match multiple appearances of the same part. a?b?c? almost does the trick. Except it matches empty strings too. Is there any way to prevent it from matching empty strings or maybe a different way to write a regex for the task.

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  • emacs auctex: can one auto-fill section labels?

    - by Mica
    Hi all, I am currently using emacs and auctex to author my latex documents. This is, of course, fantastic. However, I would like to have emacs and/or auctex auto-fill the section label when using C-c C-e to make a new header. It should end up looking like this: \section{This is a section title} \label{sec:this-is-a-section-title} with the label for the header the same as the title, but with no spaces. I don't know lisp or elisp, and I'd have no idea where to start. If anyone could help that would be great!

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  • How does one set multiple cache-control directives in ASP.NET

    - by strongopinions
    I have to have several certain cache-control directives set on an ASP.NET page in order to pass a Hailstorm security scan. For example, it wants me to have Cache-control: no-cache="set-cookie" in addition to Cache-control: no-cache I have been setting the latter with the following line in my C# codebehind: Response.CacheControl = "no-cache"; Is there a special way to indicate both directives at once? Do I just separate them with a semicolon?

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  • How can I display an ASP.NET MVC html part from one application in another

    - by Frank Sessions
    We have several asp.net MVC apps in the following setup SecurityApp (root application - handles forms auth for SSO and has a profile edit page) Application1 (virtual directory) Application2 (virtual directory) Application3 (virtual directory) so that domain.com points to SecurityApp and domain.com/Application1 etc point to their associated virtual directories. All of our Single Sign On (SSO) is working properly using forms authentication. Based on the users permissions when logging in a menu that lists their available applications and a logout link will be generated and saved in the cache - this menu displays fine whenever the user is in the SecurityApp (editing their profile) but we cannot figure out how to get the Applications in the virtual directories to display the same application menu. We have tried: 1) Using JSONP to do an request that will return the html for the menu. The ajax call returns the HTML with the html; however, because User.IsAuthenticated is false the menu comes back empty. 2) We created a user control and include it along with the dll's for the SecurityApp project and this works; however, we dont want to have to include all the dlls for the SecurityApp project in every application that we create (along with all the app settings in the web.config) We would like this to be as simple as possible to implement so that anyone creating a new app can add the menu to their application in as few steps as possible... Any ideas? To Clarify - we are using ASP.NET MVC 1.0 since these apps are in production and we do not have the okay to go to ASP.NET MVC 2.0 (unfortunately)

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  • After Adding "readonly" attribute on text box not able to remove it in one event

    - by Sreedhar K
    Steps to repro USE Internet Explorer Check unlimited check box Click on text box (It will remove tick/check from check box) Try to enter text in text box We cannot enter in the text box 4. Click again on the text box. Now we will be able to enter text in the text box We tried by 1. Making attribute readOnly to flase i.e. $('#myinput').attr('readOnly', false); 2. Calling $('#myinput').click(); Below is the HTML code <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Make input read only</title> <script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.4.min.js"></script> </head> <body> <input id="myinput" type="text" /> <input id="mycheck" type="checkbox" /> <script type="text/javascript"> /*oncheck box click*/ $('#mycheck').click(function () { if ($(this).attr('checked')) { $('#myinput').attr('readOnly', 'readOnly'); } else { $('#myinput').removeAttr('readOnly'); /* also tried * $('#myinput').attr('readOnly', false); * $('#myinput').attr('readOnly', ''); */ } }); /*on text box click*/ $('#myinput').click(function () { $('#mycheck').removeAttr('checked'); $('#myinput').removeAttr('readOnly'); /* also tried * $('#myinput').attr('readOnly', false); * $('#myinput').attr('readOnly', ''); */ }); </script> </body> </html> Live copy

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  • how relate one table to another for future records

    - by Sinan
    I have a games table which holds the data about a game. Then another table which holds the data about news. So far so good. First I thought about creating a junction table for game_news so I could relate news to games. This way works as intended when the game exists. So whenever I insert a news I can relate it to a game using the junction table. However there are cases when there is news about game but the game isn't published and it doesn't exists. So my question would be; is there a way to relate these news to a particular game when the game record is created. What is the best way to do this? Any ideas?

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  • TRICKEY ONE PLEASE SOLVE

    - by jack
    Create a DTD to record the sellers of merchandise to the Second-hand shop. Each seller has the child elements sellerID (in the format KSXXXXXXX), name, address, phone and sighted_identification. ? the name element has child elements of title and firstname and surname ? the address element has child elements address_line, suburb, state and postcode ? the sighted_identification can be any of the following – passport – drivers licence – birth certificate – Medicare card. –1. Create a DTD to record the sellers of merchandise to the Second-hand shop. Each seller has the child elements sellerID (in the format KSXXXXXXX), name, address, phone and sighted_identification. ? the name element has child elements of title and firstname and surname ? the address element has child elements address_line, suburb, state and postcode ? the sighted_identification can be any of the following – passport – drivers licence – birth certificate – Medicare card. Create an XML document for five sellers including at least two with multiple sighted identifications. 3. Create an XSLT style sheet to logically display all of the seller’s details. Note 1: it may help you to create lists for both sellers and for sighted_identification. Note 2: The shops database stores the sighted identification of sellers as p, dl, bc and mc rather than by their full name, so creating an entity for each type is required. Note 3: Your XSLT should order the sellers by sellerID – for this reason don’t have them ordered correctly in the XML file – rather sort the sellerID within the XSLT. OUTPUT SHOULD BE SOMETHING LIKE THIS SELLER ID : NAME: ADDRESS : PHONE : IDENTIFICATION : IDENTIFICATION : IDENTIFICATION :

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  • MYSQL in PHPMYADMIN - create table relationship from one table

    - by Stanley DecoWood
    I want to create a table relationship with MYSQL PHPMYADMIN. I have this Create table: CREATE TABLE students(code_students int(8)not null AUTO_INCREMENT, name_students varchar(25), age_students int(3), degree_program varchar(25), code_advisor int(8)not null, primary key(code_students, code_advisor) ); and i want to make a create table named advise relationship between code_students, code_advisor.

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  • Unable to create more then one gadget in GateIn portal

    - by Genadii Ganebnyi
    Repost from: Jboss GateIn Discussion. Please refer that post for screenshots. Here what happens when I try to create 2 gadgets: I press "Create a new gadget" Leave content as is and press "Save". As the result gadget gets name "CHANGME" and there is no way to change it. Press "Create a new gadget" and change title to "hello2 ...." Press "Save". New gadget replaces previous gadget in the left menu and gets the same name "CHANGME" with no way to change it Is this a bug or I am doing something wrong?

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  • Building two executables in one project

    - by Rui Pacheco
    Hi, I've a project that must produce two executables: the main application and an executable that is called by a separate process. I've created the second file in Xcode and added a second target of type Cocoa Shell Tool. I can now build the second executable but when I try to build my project normally I get an error saying there's two executables present: ld: duplicate symbol _main in <path>/SecondExecutable.o and <path>/main.o (<path> was added by me to protect the innocent and their intelectual property). How can I configure Xcode to build both at the same time?

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  • django powering multiple shops from one code base on a single domain

    - by imanc
    Hey, I am new to django and python and am trying to figure out how to modify an existing app to run multiple shops through a single domain. Django's sites middleware seems inappropriate in this particular case because it manages different domains, not sites run through the same domain, e.g. : domain.com/uk domain.com/us domain.com/es etc. Each site will need translated content - and minor template changes. The solution needs to be flexible enough to allow for easy modification of templates. The forms will also need to vary a bit, e.g minor variances in fields and validation for each country specific shop. I am thinking along the lines of the following as a solution and would love some feedback from experienced django-ers: In short: same codebase, but separate country specific urls files, separate templates and separate database Create a middleware class that does IP localisation, determines the country based on the URL and creates a database connection, e.g. /au/ will point to the au specific database and so on. in root urls.py have routes that point to a separate country specific routing file, e..g (r'^au/',include('urls_au')), (r'^es/',include('urls_es')), use a single template directory but in that directory have a localised directory structure, e.g. /base.html and /uk/base.html and write a custom template loader that looks for local templates first. (or have a separate directory for each shop and set the template directory path in middleware) use the django internationalisation to manage translation strings throughout slight variances in forms and models (e.g. ZA has an ID field, France has 'door code' and 'floor' etc.) I am unsure how to handle these variations but I suspect the tables will contain all fields but allowing nulls and the model will have all fields but allowing nulls. The forms will to be modified slightly for each shop. Anyway, I am keen to get feedback on the best way to go about achieving this multi site solution. It seems like it would work, but feels a bit "hackish" and I wonder if there's a more elegant way of getting this solution to work. Thanks, imanc

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  • Copying one form's values to another form using JQuery

    - by rsturim
    I have a "shipping" form that I want to offer users the ability to copy their input values over to their "billing" form by simply checking a checkbox. I've coded up a solution that works -- but, I'm sort of new to jQuery and wanted some criticism on how I went about achieving this. Is this well done -- any refactorings you'd recommend? Any advice would be much appreciated! The Script <script type="text/javascript"> $(function() { $("#copy").click(function() { if($(this).is(":checked")){ var $allShippingInputs = $(":input:not(input[type=submit])", "form#shipping"); $allShippingInputs.each(function() { var billingInput = "#" + this.name.replace("ship", "bill"); $(billingInput).val($(this).val()); }) //console.log("checked"); } else { $(':input','#billing') .not(':button, :submit, :reset, :hidden') .val('') .removeAttr('checked') .removeAttr('selected'); //console.log("not checked") } }); }); </script> The Form <div> <form action="" method="get" name="shipping" id="shipping"> <fieldset> <legend>Shipping</legend> <ul> <li> <label for="ship_first_name">First Name:</label> <input type="text" name="ship_first_name" id="ship_first_name" value="John" size="" /> </li> <li> <label for="ship_last_name">Last Name:</label> <input type="text" name="ship_last_name" id="ship_last_name" value="Smith" size="" /> </li> <li> <label for="ship_state">State:</label> <select name="ship_state" id="ship_state"> <option value="RI">Rhode Island</option> <option value="VT" selected="selected">Vermont</option> <option value="CT">Connecticut</option> </select> </li> <li> <label for="ship_zip_code">Zip Code</label> <input type="text" name="ship_zip_code" id="ship_zip_code" value="05401" size="8" /> </li> <li> <input type="submit" name="" /> </li> </ul> </fieldset> </form> </div> <div> <form action="" method="get" name="billing" id="billing"> <fieldset> <legend>Billing</legend> <ul> <li> <input type="checkbox" name="copy" id="copy" /> <label for="copy">Same of my shipping</label> </li> <li> <label for="bill_first_name">First Name:</label> <input type="text" name="bill_first_name" id="bill_first_name" value="" size="" /> </li> <li> <label for="bill_last_name">Last Name:</label> <input type="text" name="bill_last_name" id="bill_last_name" value="" size="" /> </li> <li> <label for="bill_state">State:</label> <select name="bill_state" id="bill_state"> <option>-- Choose State --</option> <option value="RI">Rhode Island</option> <option value="VT">Vermont</option> <option value="CT">Connecticut</option> </select> </li> <li> <label for="bill_zip_code">Zip Code</label> <input type="text" name="bill_zip_code" id="bill_zip_code" value="" size="8" /> </li> <li> <input type="submit" name="" /> </li> </ul> </fieldset> </form> </div>

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