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• Unable to display wap version during "Extended permission"

  - by Mickey Cheong

  Hi, Im trying to redirect to facebook to request permission to publish stream. However, it only works when i did not specify any display parameters, it shows me a web version of it. I wanted a wap version instead. What should I do? Here's the code: <form method="post" action="https://graph.facebook.com/oauth/authorize"> <input type="hidden" name="client_id" value="1XXXXXXXXXXXXXX" /> <input type="hidden" name="scope" value="publish_stream" /> <input type="hidden" name="redirect_uri" value="http://www.redirect.com/" /> <input class="button" type="submit" value="Request..." /> </form> When i submit this form, it will redirect to http://www.facebook.com/connect/prompt_ … y=page.... If I were to change the "redirected url"'s display param to "wap" it will works. However, if I were to submit to https://graph.facebook.com/oauth/authorize?display=wap. Nothing will happen and it will redirect back to the source url. Any help/hint will be grateful. Thanks a mil, Mickey

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• Nginx not responding to remote IP

  - by bucabay

  I just installed Nginx listening on 8083 I can get a HTTP response when sending a HTTP request from the local machine. eg: curl -i localhost:8083 However, when I do the same from a remote machine, it just hangs until the ssh times out, or when the browser times out if accessed from the browser. I pretty much have the default config: user apache apache; worker_processes 1; error_log logs/error.log; #error_log logs/error.log notice; #error_log logs/error.log info; pid logs/nginx.pid; events { worker_connections 1024; } http { include mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] "$request" ' '$status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for"'; access_log logs/access.log main; sendfile on; tcp_nopush on; #keepalive_timeout 0; keepalive_timeout 65; #gzip on; server { listen 8083; server_name _; charset utf-8; #access_log logs/host.access.log main; location / { root html; index index.html index.php; } #error_page 404 /404.html; # redirect server error pages to the static page /50x.html # error_page 500 502 503 504 /50x.html; location = /50x.html { root html; } location ~ /\.ht { deny all; } } } any ideas?

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• When sending headers to download a PDF, Safari appends .html

  - by alex

  Here is the request and response headers http://www.example.com/get/pdf GET /~get/pdf HTTP/1.1 Host: www.example.com User-Agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.6; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://www.example.com Cookie: etc HTTP/1.1 200 OK Date: Thu, 29 Apr 2010 02:20:43 GMT Server: Apache/2.2.14 (Unix) mod_ssl/2.2.14 OpenSSL/0.9.8i DAV/2 mod_auth_passthrough/2.1 mod_bwlimited/1.4 FrontPage/5.0.2.2635 X-Powered-By: Me Expires: Thu, 19 Nov 1981 08:52:00 GMT Pragma: no-cache Cache-Control: private Content-Disposition: attachment; filename="File #1.pdf" Content-Length: 18776 Keep-Alive: timeout=5, max=100 Connection: Keep-Alive Content-Type: text/html; charset=utf-8 ---------------------------------------------------------- Basically, the response headers are sent by DOMPDF's stream() method. In Firefox, the file is prompted as File #1.pdf. However, in Safari, the file is saved as File #1.pdf.html. Does anyone know why Safari is appending the html extension to the filename?

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• HttpWebRequest Timeouts After Ten Consecutive Requests

  - by Bob Mc

  I'm writing a web crawler for a specific site. The application is a VB.Net Windows Forms application that is not using multiple threads - each web request is consecutive. However, after ten successful page retrievals every successive request times out. I have reviewed the similar questions already posted here on SO, and have implemented the recommended techniques into my GetPage routine, shown below: Public Function GetPage(ByVal url As String) As String Dim result As String = String.Empty Dim uri As New Uri(url) Dim sp As ServicePoint = ServicePointManager.FindServicePoint(uri) sp.ConnectionLimit = 100 Dim request As HttpWebRequest = WebRequest.Create(uri) request.KeepAlive = False request.Timeout = 15000 Try Using response As HttpWebResponse = DirectCast(request.GetResponse, HttpWebResponse) Using dataStream As Stream = response.GetResponseStream() Using reader As New StreamReader(dataStream) If response.StatusCode <> HttpStatusCode.OK Then Throw New Exception("Got response status code: " + response.StatusCode) End If result = reader.ReadToEnd() End Using End Using response.Close() End Using Catch ex As Exception Dim msg As String = "Error reading page """ & url & """. " & ex.Message Logger.LogMessage(msg, LogOutputLevel.Diagnostics) End Try Return result End Function Have I missed something? Am I not closing or disposing of an object that should be? It seems strange that it always happens after ten consecutive requests. Notes: In the constructor for the class in which this method resides I have the following: ServicePointManager.DefaultConnectionLimit = 100 If I set KeepAlive to true, the timeouts begin after five requests. All the requests are for pages in the same domain. EDIT I added a delay between each web request of between two and seven seconds so that I do not appear to be "hammering" the site or attempting a DOS attack. However, the problem still occurs.

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• Execute multiple command lines with the same process using C#

  - by rima

  Hi according to my last question here I try to write a sql Editor or some thing like this,in this way I try to connect to CMD from C# and execute my command. now my problem is for example I connect to SQLPLUS after that I cant get SQLPLUS command,and the other resource I review don't satisfy me.Please help me how after I connected to Sqlplus ,I can a live my process to run my sql command? right now I use this code: //Create process System.Diagnostics.Process pProcess = new System.Diagnostics.Process(); //strCommand is path and file name of command to run pProcess.StartInfo.FileName = strCommand; //strCommandParameters are parameters to pass to program pProcess.StartInfo.Arguments = strCommandParameters; pProcess.StartInfo.UseShellExecute = false; //Set output of program to be written to process output stream pProcess.StartInfo.RedirectStandardOutput = true; //Optional pProcess.StartInfo.WorkingDirectory = strWorkingDirectory; //Start the process pProcess.Start(); //Get program output string strOutput = pProcess.StandardOutput.ReadToEnd(); //Wait for process to finish pProcess.WaitForExit(); but i customize it.I separate the initialize, i mean i just create process object one time,but I still have problem. to run the second command I use these codes for second time calling: pProcess.StartInfo.FileName = strCommand; //strCommandParameters are parameters to pass to program pProcess.StartInfo.Arguments = strCommandParameters; //Start the process pProcess.Start(); //Get program output string strOutput = pProcess.StandardOutput.ReadToEnd(); //Wait for process to finish pProcess.WaitForExit(); Thanks in advance

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• ASP.NET MVC Facebook

  - by durilai

  I am trying to do a seemingly simple thing, but having trouble accomplishing it. I am trying to automate the posting on my Facebook wall. Basically I have a ASP.NET MVC website that I post updates on, and I want to automatically submit the post to my wall. I see a lot of stuff on FB Connect and getting data, I just want to post. Thanks for any help or guidance. UPDATE: Just trying to resurrect, and be a little more clear in my description as I am not getting anywhere. I have a page that I want with a text box and a button. When I submit the form I want the message to post to my Facebook wall. I thought it was Facebook Connect, but I am getting no where as to how to automatically authenticate myself and post to my wall. I would like to use C# rather than JavaScript. private const string ApplicationKey = "XXXXXXXXXXXXXXXXXXXXXXXXXXXX"; private const string SecretKey = "XXXXXXXXXXXXXXXXXXXXXXXXXX"; private Facebook.Rest.Api _facebookAPI; private Facebook.Session.ConnectSession _connectSession; [AcceptVerbs(HttpVerbs.Post)] public ActionResult Index(FormCollection form) { _connectSession = new Facebook.Session.ConnectSession(ApplicationKey, SecretKey); if (_connectSession.IsConnected()) { _facebookAPI = new Facebook.Rest.Api(_connectSession); string response = _facebookAPI.Stream.Publish("This is a generated test"); } return View(); } } The IsConnected() is returning false. Any help is appreciated.

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• How to get "AuthSub " token in C#? For google APPS Contacts ?

  - by Pari

  Hi, I fount this code on net : HttpWebRequest update = (HttpWebRequest)WebRequest.Create(**editUrl** ); // editUrl is a string containing the contact's edit URL update.Method = "PUT"; update.ContentType = "application/atom+xml"; update.Headers.Add(HttpRequestHeader.Authorization, "GoogleLogin auth=" + **AuthToken**); update.Headers.Add(HttpRequestHeader.IfMatch, **etag**); // etag is a string containing the <entry> element's gd:etag attribute value update.Headers.Add("GData-Version", "3.0"); Stream streamRequest = update.GetRequestStream(); StreamWriter streamWriter = new StreamWriter(streamRequest, Encoding.UTF8); streamWriter.Write(entry); // entry is the string representation of the atom entry to update streamWriter.Close(); WebResponse response = update.GetResponse(); But here i am not getting what to put in " editurl" , "AuthToken" and "Etag". a) I studied abt "AuthToken" from this Link .But not getting how to create it? Can anyone help me out here? b) Also not getting " editurl" and "Etag". I am trying to use this method to Migrate my contacts to Google Apps. Thanx

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• php get, random records, and the back button

  - by Andrew Heath

  My site has a library full of games, nations, game scenarios, etc. library.php is given a type=___ & id=___ for example library.php?type=scenario&id=ABCD001 library.php saves the id to a session variable and loads an include appropriate for the type This all works just dandy. Now, I wanted to give my users the option of pulling up a random scenario. To do that, I added a special id to the logic within lib-scenario.php (the include) such that if given library.php?type=scenario&id=random the include knows to run an alternate query for a random record rather than for the actual id This also works just dandy... unless someone hits the Random Scenario button two+ times in a row, and decides that the previous random scenario was way cooler, I want to go back to that. Because the http address is always directory/library.php?type=scenario&id=random no matter how many times you click Random Scenario, as soon as you click back you'll be taken to the last page with an alternate address you visited. So, if you start at the Home page, and hit Random Scenario 35 times, then decide the 34th one was what you wanted and click BACK, you'll be put back onto the Home page. I must admit this was not a problem I had anticipated. One of my testers was the first to have the urge to back-up in the random scenario stream and here we are. How can I add back-up functionality to my script?

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• Can't get SFTP to work in PHP

  - by Chris Kloberdanz

  I am writing a simple SFTP client in PHP because we have the need to programatically retrieve files via n remote servers. I am using the PECL SSH2 extension. I have run up against a road block, though. The documentation on php.net suggests that you can do this: $stream = fopen("ssh2.sftp://$sftp/path/to/file", 'r'); However, I have an ls method that attempts to something similar public function ls($dir) { $rd = "ssh2.sftp://{$this->sftp}/$dir"; $handle = opendir($rd); if (!is_resource($handle)) { throw new SFTPException("Could not open directory."); } while (false !== ($file = readdir($handle))) { if (substr($file, 0, 1) != '.'){ print $file . "\n"; } } closedir($handle); } I get the following error: PHP Warning: opendir(): Unable to open ssh2.sftp://Resource id #5/outgoing on remote host This makes perfect sense because that's what happens when you cast a resource to string. Is the documentation wrong? I tried replacing the resource with host, username, and host and that didn't work either. I know the path is correct because I can run SFTP from the command line and it works fine. Has anyone else tried to use the SSH2 extenstion with SFTP? Am I missing something obvious here? UPDATE: I setup sftp on another machine in-house and it works just fine. So, there must be something about the server I am trying to connect to that isn't working.

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• How do I POST/GET from rails to API with Nestful?

  - by Angela

  Hi, this is a pretty basic question but I'm not entirely clear how to do this. I am trying to use a third-party service that has web-based service. The service is called Postful. But I'm not clear what exactly to do? I've looked at ActiveResource (http://api.rubyonrails.org/classes/ActiveResource/Base.html) and rest-client, but I'm still not clear exactly what steps, code, and files to create. I'm trying to use Nestful but I'm not entirely clear how to make this work. http://github.com/maccman/nestful http://www.postful.com/service/mail is one of the services (details found http://www.postful.com/developer/guide#rest ), but to upload an image I have to post the following (but I'm not sure how I actually do this?). Thanks! > http://www.postful.com/service/upload > > Be sure to include the Content-Type > and Content-Length headers and the > image itself as the body of the > request. > > POST /upload HTTP/1.0 Content-Type: > application/octet-stream > Content-Length: 301456 > > ... file content here ... > > If the upload is successful, you will > receive a response like the following: > > <?xml version="1.0" encoding="UTF-8"?> > <upload> > <id>290797321.waltershandy.2</id> > </upload>

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• even PHP has 'bugs' with IE

  - by silversky

  It's not a real bug BUT for sure it is not what you would expect. I have this sample code to upload images: <?php if($type=="image/jpg" || $type=="image/jpeg" || $type=="image/pjpeg" || $type=="image/tiff" || $type=="image/gif" || $type=="image/png") { // make upload else echo "Incorect format ...."; ?> The problem is that that if I modify the extention of an image, let's say to .jpgq or even .jpg% and i try to upload it FF and Chrome will say that the file"s type is "application/octet-stream" and normaly the condition will be false BUT since IE is 'smarter' that other brow. it will say that the file is "image/pjeg and the condition will be true and the file will be uploaded and of course latter any brow. will not be able to read / view the image. It is not a bug because on msdn.microsoft.com it says that: "If the "suggested" (server-provided) MIME type is unknown (not known and not ambiguous), FindMimeFromData immediately returns this MIME type" and "If the server-provided MIME type is either known or ambiguous, the buffer is scanned in an attempt to verify or obtain a MIME type from the actual content." plus others 'inovative solutions from Microsoft'. SO my questions are: Why is IE so 'smart' and when I upload the file to server it knows the real MIME type BUT it will fail to read it from the server ? How can i work around this issue (if the file doesn't have the right extention the condition has to be false)? Is it wise to check the extention format (and not the MIME type)? is any of the above extention not recomended to use ? Should I add others?

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• Q on Python serialization/deserialization

  - by neil

  What chances do I have to instantiate, keep and serialize/deserialize to/from binary data Python classes reflecting this pattern (adopted from RFC 2246 [TLS]): enum { apple, orange } VariantTag; struct { uint16 number; opaque string<0..10>; /* variable length */ } V1; struct { uint32 number; opaque string[10]; /* fixed length */ } V2; struct { select (VariantTag) { /* value of selector is implicit */ case apple: V1; /* VariantBody, tag = apple */ case orange: V2; /* VariantBody, tag = orange */ } variant_body; /* optional label on variant */ } VariantRecord; Basically I would have to define a (variant) class VariantRecord, which varies depending on the value of VariantTag. That's not that difficult. The challenge is to find a most generic way to build a class, which serializes/deserializes to and from a byte stream... Pickle, Google protocol buffer, marshal is all not an option. I made little success with having an explicit "def serialize" in my class, but I'm not very happy with it, because it's not generic enough. I hope I could express the problem. My current solution in case VariantTag = apple would look like this, but I don't like it too much import binascii import struct class VariantRecord(object): def __init__(self, number, opaque): self.number = number self.opaque = opaque def serialize(self): out = struct.pack('>HB%ds' % len(self.opaque), self.number, len(self.opaque), self.opaque) return out v = VariantRecord(10, 'Hello') print binascii.hexlify(v.serialize()) >> 000a0548656c6c6f Regards

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• Decoding tcp packets using python

  - by mikip

  Hello I am trying to decode data received over a tcp connection. The packets are small, no more than 100 bytes. However when there is a lot of them I receive some of the the packets joined together. Is there a way to prevent this. I am using python I have tried to separate the packets, my source is below. The packets start with STX byte and end with ETX bytes, the byte following the STX is the packet length, (packet lengths less than 5 are invalid) the checksum is the last bytes before the ETX def decode(data): while True: start = data.find(STX) if start == -1: #no stx in message pkt = '' data = '' break #stx found , next byte is the length pktlen = ord(data[1]) #check message ends in ETX (pktken -1) or checksum invalid if pktlen < 5 or data[pktlen-1] != ETX or checksum_valid(data[start:pktlen]) == False: print "Invalid Pkt" data = data[start+1:] continue else: pkt = data[start:pktlen] data = data[pktlen:] break return data , pkt I use it like this #process reports try: data = sock.recv(256) except: continue else: while data: data, pkt = decode(data) if pkt: process(pkt) Also if there are multiple packets in the data stream, is it best to return the packets as a collection of lists or just return the first packet I am not that familiar with python, only C, is this method OK. Any advice would be most appreciated. Thanks in advance Thanks

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• i want the ruby code of the php code i have given inside , please help me out

  - by Arpit Vaishnav

  <?php // amcharts.com export to image utility // set image type (gif/png/jpeg) $imgtype = 'jpeg'; // set image quality (from 0 to 100, not applicable to gif) $imgquality = 100; // get data from $_POST or $_GET ? $data = &$_POST; // get image dimensions $width = (int) $data['width']; $height = (int) $data['height']; // create image object $img = imagecreatetruecolor($width, $height); // populate image with pixels for ($y = 0; $y < $height; $y++) { // innitialize $x = 0; // get row data $row = explode(',', $data['r'.$y]); // place row pixels $cnt = sizeof($row); for ($r = 0; $r < $cnt; $r++) { // get pixel(s) data $pixel = explode(':', $row[$r]); // get color $pixel[0] = str_pad($pixel[0], 6, '0', STR_PAD_LEFT); $cr = hexdec(substr($pixel[0], 0, 2)); $cg = hexdec(substr($pixel[0], 2, 2)); $cb = hexdec(substr($pixel[0], 4, 2)); // allocate color $color = imagecolorallocate($img, $cr, $cg, $cb); // place repeating pixels $repeat = isset($pixel[1]) ? (int) $pixel[1] : 1; for ($c = 0; $c < $repeat; $c++) { // place pixel imagesetpixel($img, $x, $y, $color); // iterate column $x++; } } } // set proper content type header('Content-type: image/'.$imgtype); header('Content-Disposition: attachment; filename="chart.'.$imgtype.'"'); // stream image $function = 'image'.$imgtype; if ($imgtype == 'gif') { $function($img); } else { $function($img, null, $imgquality); } // destroy imagedestroy($img); ?

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• Uploading file with metadata

  - by Dilse Naaz

  Hi Could you help me for how to adding a file to the sharepoint document library? I found some articles in net. but i didn't get the complete concept of the same. Now i uploaded a file without metadata by using this code. if (fuDocument.PostedFile != null) { if (fuDocument.PostedFile.ContentLength > 0) { Stream fileStream = fuDocument.PostedFile.InputStream; byte[] byt = new byte[Convert.ToInt32(fuDocument.PostedFile.ContentLength)]; fileStream.Read(byt, 0, Convert.ToInt32(fuDocument.PostedFile.ContentLength)); fileStream.Close(); using (SPSite site = new SPSite(SPContext.Current.Site.Url)) { using (SPWeb webcollection = site.OpenWeb()) { SPFolder myfolder = webcollection.Folders["My Library"]; webcollection.AllowUnsafeUpdates = true; myfolder.Files.Add(System.IO.Path.GetFileName(fuDocument.PostedFile.FileName), byt); } } } } This code is working as fine. But i need to upload file with meta data. Please help me by editing this code if it possible. I created 3 columns in my Document library..

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• Django upload failing on request data read error

  - by Jake

  Hi All, I've got a Django app that accepts uploads from jQuery uploadify, a jQ plugin that uses flash to upload files and give a progress bar. Files under about 150k work, but bigger files always fail and almost always at around 192k (that's 3 chunks) completed, sometimes at around 160k. The Exception I get is below. exceptions.IOError request data read error File "/usr/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 171, in _get_post self._load_post_and_files() File "/usr/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 137, in _load_post_and_files self._post, self._files = self.parse_file_upload(self.META, self.environ[\'wsgi.input\']) File "/usr/lib/python2.4/site-packages/django/http/__init__.py", line 124, in parse_file_upload return parser.parse() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 192, in parse for chunk in field_stream: File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 314, in next output = self._producer.next() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 468, in next for bytes in stream: File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 314, in next output = self._producer.next() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 375, in next data = self.flo.read(self.chunk_size) File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 405, in read return self._file.read(num_bytes) When running locally on the Django development server, big files work. I've tried setting my FILE_UPLOAD_HANDLERS = ("django.core.files.uploadhandler.TemporaryFileUploadHandler",) in case it was the memory upload handler, but it made no difference. Does anyone know how to fix this?

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• No feedback from Socket.SendAsync

  - by BowserKingKoopa

  I'm creating a socket and I'm trying to send data through it using SendAsync. My socket isn't connected to anything so I expected to get an error of some sort. However I get nothing. I get no indication that the send didn't work. If I use the synchronous Send method instead of the asynchronous SendAsync method I get an Exception stating that the socket isn't connected to anything. That makes sense to me. When using SendAsync the completed event doesn't ever fire and I get no indication that the send didn't work. So basically my question is how can I tell when SendAsync fails? Socket socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); SocketAsyncEventArgs args = new SocketAsyncEventArgs(); args.SetBuffer(new byte[0], 0, 0); args.Completed += delegate(object sender, SocketAsyncEventArgs e) { Debug.WriteLine("async send complete"); Debug.WriteLine("SOCKET ERROR: " + e.SocketError); }; bool completedSynchronously = socket.SendAsync(args); if (completedSynchronously) { Debug.WriteLine("sync send complete"); Debug.WriteLine("socket error: " + args.SocketError); }

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• How to log in to craigslist using c#

  - by kosikiza

  i m using the following code to log in to craigslist, but haven't succeeded yet. string formParams = string.Format("inputEmailHandle={0}&inputPassword={1}", "[email protected]", "removed"); //string postData = "[email protected]&inputPassword=removed"; string uri = "https://accounts.craigslist.org/"; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri); request.KeepAlive = true; request.ProtocolVersion = HttpVersion.Version10; request.Method = "POST"; byte[] postBytes = Encoding.ASCII.GetBytes(formParams); request.ContentType = "application/x-www-form-urlencoded"; request.ContentLength = postBytes.Length; Stream requestStream = request.GetRequestStream(); requestStream.Write(postBytes, 0, postBytes.Length); requestStream.Close(); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); cookyHeader = response.Headers["Set-cookie"]; string pageSource; string getUrl = "https://post.craigslist.org/del"; WebRequest getRequest = WebRequest.Create(getUrl); getRequest.Headers.Add("Cookie", cookyHeader); WebResponse getResponse = getRequest.GetResponse(); using (StreamReader sr = new StreamReader(getResponse.GetResponseStream())) { pageSource = sr.ReadToEnd(); }

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• Database version is zero on initial install

  - by mahesh

  I have released an app (World Time) with initial database. Now i want to update the app with a database upgrade. I have put in the upgrade code in OnUpgrade() and checking for the newVersion. But it was not being called in my local testing... So i put in the debug statement to get the database version and it is zero . Any idea why it is not being versioned ? Following is the code to copy the database from my Assets folder ... InputStream myInput = myContext.getAssets().open(DB_NAME); // Path to the just created empty db String outFileName = DB_PATH + DB_NAME; //Open the empty db as the output stream OutputStream myOutput = new FileOutputStream(outFileName); //transfer bytes from the inputfile to the outputfile byte[] buffer = new byte[1024]; int length; while ((length = myInput.read(buffer))>0){ myOutput.write(buffer, 0, length); } //Close the streams myOutput.flush(); myOutput.close(); myInput.close(); -- Mahesh http://android.maheshdixit.com

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• Why is my GZipStream not writeable?

  - by Ozzah

  I have some GZ compressed resources in my program and I need to be able to write them out to temporary files for use. I wrote the following function to write the files out and return true on success or false on failure. In addition, I've put a try/catch in there which shows a MessageBox in the event of an error: private static bool extractCompressedResource(byte[] resource, string path) { try { using (MemoryStream ms = new MemoryStream(resource)) { using (FileStream fs = new FileStream(path, FileMode.Create, FileAccess.ReadWrite)) { using (GZipStream zs = new GZipStream(fs, CompressionMode.Decompress)) { ms.CopyTo(zs); // Throws exception zs.Close(); ms.Close(); } } } } catch (Exception ex) { MessageBox.Show(ex.Message); // Stream is not writeable return false; } return true; } I've put a comment on the line which throws the exception. If I put a breakpoint on that line and take a look inside the GZipStream then I can see that it's not writeable (which is what's causing the problem). Am I doing something wrong, or is this a limitation of the GZipStream class?

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• Why does std::cout convert volatile pointers to bool?

  - by Joseph Garvin

  If you try to cout a volatile pointer, even a volatile char pointer where you would normally expect cout to print the string, you will instead simply get '1' (assuming the pointer is not null I think). I assume output stream operator<< is template specialized for volatile pointers, but my question is, why? What use case motivates this behavior? Example code: #include <iostream> #include <cstring> int main() { char x[500]; std::strcpy(x, "Hello world"); int y; int *z = &y; std::cout << x << std::endl; std::cout << (char volatile*)x << std::endl; std::cout << z << std::endl; std::cout << (int volatile*)z << std::endl; return 0; } Output: Hello world 1 0x8046b6c 1

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• Facebook app getting "Warning: fopen......." - Please help!

  - by Poni

  Hello! I'm trying to establish a Facebook application. I'm getting the following PHP notice randomly: Warning: fopen(http://api.facebook.com/restserver.php? … &v=1.0) [function.fopen]: failed to open stream: HTTP request failed! HTTP/1.1 400 Bad Request in D:\projects........\facebookapi_php5_restlib.php on line 3391 As said, it happens randomly. My app configuration: IFrame Page host configuration: Windows Vista, Apache 2.2.11, PHP 5.1 No support for cURL is possible at the moment. My aim: Get the user's first name & pic_square along with two other preferences. If these two preferences are not set then I'll set them, after doing some internal job. I understand that the REST API is old. Which interface should I use then? Saw FQL, which seem to be fine, but I see no corresponding getUserPreference/setUserPreference interface. Where is it? How do I combine it with the "first name & pic_square" info that I need in one query? How do I read the results of multi-query query? Also, if I understand correctly, the FQL is also executed with the fopen() function, and as we see here it might fail. That means something went wrong, and then I want to handle it. Any suggestions how to do so efficiently? Less important than the above question though. Thank you all.

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• webcam refreshing image in iframe not working IE

  - by Nix

  I'm trying to show images from this webcam http://regacam.usz.ch/cgi-bin/guestimage.html on an html page by putting an iframe in pointing to another page that has an image tag in it. But it isn't working in IE (I just see a little cross where the image should be), Firefox is ok. Here the page with the image in: <html> <head> <meta http-euqiv="refresh" content="5"> </head> <body> <img src="http://regacam.usz.ch/cgi-bin/faststream.jpg?stream=full&fps=0.01667&rand=295543" width="200" height="150"/> </body> <html> and the iframe: <div id="rightcontainer"> <iframe id="rightframe" src="zurich.html" name="content" frameborder="0"></iframe> </div> I tried a different webcam elsewhere and that works ok in both browsers. Is there something odd about the one in my example? I got the link in src by right-clicking and copying the image location - is that the right way to go about it?

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• SEO: A whois server that work for .SE domains?

  - by Niels Bosma

  I'm developing a small domain checker and I can't get .SE to work: public string Lookup(string domain, RecordType recordType, SeoToolsSettings.Tld tld) { TcpClient tcp = new TcpClient(); tcp.Connect(tld.WhoIsServer, 43); string strDomain = recordType.ToString() + " " + domain + "\r\n"; byte[] bytDomain = Encoding.ASCII.GetBytes(strDomain.ToCharArray()); Stream s = tcp.GetStream(); s.Write(bytDomain, 0, strDomain.Length); StreamReader sr = new StreamReader(tcp.GetStream(), Encoding.ASCII); string strLine = ""; StringBuilder builder = new StringBuilder(); while (null != (strLine = sr.ReadLine())) { builder.AppendLine(strLine); } tcp.Close(); if (tld.WhoIsDelayMs > 0) System.Threading.Thread.Sleep(tld.WhoIsDelayMs); return builder.ToString(); } I've tried whois servers whois.nic-se.se and whois.iis.se put I keep getting: # Copyright (c) 1997- .SE (The Internet Infrastructure Foundation). # All rights reserved. # The information obtained through searches, or otherwise, is protected # by the Swedish Copyright Act (1960:729) and international conventions. # It is also subject to database protection according to the Swedish # Copyright Act. # Any use of this material to target advertising or # similar activities is forbidden and will be prosecuted. # If any of the information below is transferred to a third # party, it must be done in its entirety. This server must # not be used as a backend for a search engine. # Result of search for registered domain names under # the .SE top level domain. # The data is in the UTF-8 character set and the result is # printed with eight bits. "domain google.se" not found. Edit: I've tried changing to UTF8 with no other result. When I try using whois from sysinternals I get the correct result, but not with my code, not even using SE.whois-servers.net. /Niels

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• Function that prints something to std::ostream and returns std::ostream?

  - by dehmann

  I want to write a function that outputs something to a ostream that's passed in, and return the stream, like this: std::ostream& MyPrint(int val, std::ostream* out) { *out << val; return *out; } int main(int argc, char** argv){ std::cout << "Value: " << MyPrint(12, &std::cout) << std::endl; return 0; } It would be convenient to print the value like this and embed the function call in the output operator chain, like I did in main(). It doesn't work, however, and prints this: $ ./a.out 12Value: 0x6013a8 The desired output would be this: Value: 12 How can I fix this? Do I have to define an operator<< instead? UPDATE: Clarified what the desired output would be. UPDATE2: Some people didn't understand why I would print a number like that, using a function instead of printing it directly. This is a simplified example, and in reality the function prints a complex object rather than an int.

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