Search Results

Search found 17344 results on 694 pages for 'desktop clients'.

Page 142/694 | < Previous Page | 138 139 140 141 142 143 144 145 146 147 148 149  | Next Page >

  • How to bring a form in the top of desktop?

    - by Kovu
    hi, I will let popup a form in C#.net 2.0 and it should be so long in front of the desktop until the user clicks the close button. How to do? I tried the code from here: http://dotnet-snippets.de/dns/fenster-wirklich-in-den-vordergrund-des-desktops-bringen-SID1005.aspx But it didn't work. My system is Win7.

    Read the article

  • Are there any OSGi web service / SOAP clients out there?

    - by James Carr
    I'm looking for any webservice client that can be run inside an OSGi container and connect to a simple web service using SOAP, doesn't sound so hard does it? Oh, and it has to work under Java 1.5, so the JRE jax-ws wont be present. The problem is I've tried a few solutions now, and although each solution works in standard Java using it from within OSGi doesn't. the springsource JAX-WS bundles seem to have dependency issues the CXF bundles get me as far as calling the service, but then can seem to find the stub methods in the proxy Is there anyone out there who has successfully created an OSGi webservice client?

    Read the article

  • Will we be penalized for having multiple external links to the same site?

    - by merk
    There seem to be conflicting answers on this question. The most relevant ones seem to be at least a year or two old, so I thought it would be worth re-asking this question. My gut says it's ok, because there are plenty of sites out there that do this already. Every major retailer site usually has links to the manufacturer of whatever item they are selling. go to www.newegg.com and they have hundreds of links to the same site since they sell multiple items from the same brand. Our site allows people to list a specific genre of items for sale (not porn - i'm just keeping it generic since I'm not trying to advertise) and on each item listing page, we have a link back to their website if they want. Our SEO guy is saying this is really bad and google is going to treat us as a link farm. My gut says when we have to start limiting user useful features to our site to boost our ranking, then something is wrong. Or start jumping through hoops by trying to hide text using javascript etc Some clients are only selling 1 to a handful of items, while a couple of our bigger clients have hundreds of items listed so will have hundreds of pages that link back to their site. I should also mention, there will be a handful of pages with the bigger clients where it may appear they have duplicate pages, because they will be selling 2 or 3 of the same item, and the only difference in the content of the page might just be a stock #. The majority of the pages though will have unique content. So - will we be penalized in some way for having anywhere from a handful to a few hundred pages that all point to the same link? If we are penalized, what's the suggested way to handle this? We still want to give users the option to go to the clients site, and we would still like to give a link back to the clients site to help their own SE rankings.

    Read the article

  • With PHP and AJAX, Can two clients inter-exchange data without MySQL?

    - by Devyn
    Hi, Let's assume I'm developing a AJAX, PHP chess game. During the game, one movement of a player will be notified to the another but we are not saving that information. Normally, we used to store in MySQL every time a player makes movement and show update position to another player. What I want is to reduce MySQL load as much as possible and server is not interested in movements between two players. Server will only save final result like who wins. So what should I do?

    Read the article

  • launch the emulator, I only see the black window with the string 'ANDROID", and no more desktop and

    - by Jiawelin
    Dear experts, I download the Android code and "make sdk" to build out my own SDK, but the emulator from this SDK does not work well -- it only shows the black window with the "ANDROID" string, but I can't see any desktop picture or any applications. what's wrong here? anyone could please provide me a hint? Thanks a lot. I use the command: $./emulator @jiawelin -debug all and the last output message is: emulator: android_hw_control_init: hw-control qemud handler initialized

    Read the article

  • How do I make a defaultdict safe for unexpecting clients?

    - by ~miki4242
    Several times (even several in a row) I've been bitten by the defaultdict bug. d = defaultdict(list) ... try: v = d["key"] except KeyError: print "Sorry, no dice!" For those who have been bitten too, the problem is evident: when d has no key 'key', the v = d["key"] magically creates an empty list and assigns it to both d["key"] and v instead of raising an exception. Which can be quite a pain to track down if d comes from some module whose details one doesn't remember very well. I'm looking for a way to take the sting out of this bug. For me, the best solution would be to somehow disable a defaultdict's magic before returning it to the client.

    Read the article

  • Ruby Dir.glob works on laptop not on desktop?

    - by Nick Faraday
    I have a ruby shell script that works perfectly on my laptop, but Dir.glob doesn't seem to work when I try and run it on my desktop. Here is the code: sFileTemplate = File.join("**", sResolutions, "**", "*."+sType) sFiles = Dir.glob(sFileTemplate) Both machines run OSX 10.5 and are running ruby -v 1.9.1. Am I calling glob wrong? Thanks

    Read the article

  • What components have you built that you are reusing over and over again for your desktop application

    - by Jason
    We are building our internal library of components up, and was wondering what everybody has in their library of reusable components for your organization, for desktop applications. Our list currently includes only a couple of components: Logon, Security and User Group functionality System Tray / Service Framework Component for Internet Communications (to handle proxies, security, etc...) Billing What else do you have, that we should add to our list? If you have reusable web components, save your answers... I will open a different question if this one is successful.

    Read the article

  • Any suggestions on data syncronization from a server to a desktop?

    - by Jamey McElveen
    I have a web based CRM system that stores all the client data from all the clients into one database (MS Sql Server). We need to build a system that maintains a local copy of the data for each client. So basically the client database will have all tables and columns except for the ClientId that is in ever server table. I am aware that I will need to add fields to the server to support synchronization. Are there any good solutions or components already out there to help me accomplish this? We are using MS Sql Server and .NET C#

    Read the article

  • Core Data: Inverse relationship only mirrors when I edit the mutableset. Not sure why.

    - by zorn
    My model is setup so Business has many clients, Client has one business. Inverse relationship is setup in the mom file. I have a unit test like this: - (void)testNewClientFromBusiness { PTBusiness *business = [modelController newBusiness]; STAssertTrue([[business clients] count] == 0, @"is actually %d", [[business clients] count]); PTClient *client = [business newClient]; STAssertTrue([business isEqual:[client business]], nil); STAssertTrue([[business clients] count] == 1, @"is actually %d", [[business clients] count]); } I implement -newClient inside of PTBusiness like this: - (PTClient *)newClient { PTClient *client = [NSEntityDescription insertNewObjectForEntityForName:@"Client" inManagedObjectContext:[self managedObjectContext]]; [client setBusiness:self]; [client updateLocalDefaultsBasedOnBusiness]; return client; } The test fails because [[business clients] count] is still 0 after -newClient is called. If I impliment it like this: - (PTClient *)newClient { PTClient *client = [NSEntityDescription insertNewObjectForEntityForName:@"Client" inManagedObjectContext:[self managedObjectContext]]; NSMutableSet *group = [self mutableSetValueForKey:@"clients"]; [group addObject:client]; [client updateLocalDefaultsBasedOnBusiness]; return client; } The tests passes. My question(s): So am I right in thinking the inverse relationship is only updated when I interact with the mutable set? That seems to go against some other Core Data docs I've read. Is the fact that this is running in a unit test without a run loop have anything to do with it? Any other troubleshooting recommendations? I'd really like to figure out why I can't set up the relationship at the client end.

    Read the article

  • jQuery check offset

    - by Glister
    HTML: <ul class="clients"> <li> <div class="over left">Description</div> <div class="inner">Image</div> </li> </ul> CSS: .clients { margin-right: -20px; } .clients li { float: left; width: 128px; height: 120px; margin: 0 20px 20px 0; border: 1px solid #c2c2c2; } .clients .over { display: none; position: absolute; width: 250px; font-size: 11px; line-height: 16px; background: #ecf5fb; margin: 3px 0 0 3px; padding: 18px; z-index: 25; } .clients .right { margin: 3px 0 0 -161px; } .clients .inner { width: 128px; height: 120px; overflow: hidden; } So, we have a list of floated squares and a popup blocks in each, which have absolute position. JS: jQuery(function($) { $('input[title!=""]').hint(); $(".clients li").bind('mouseover mouseout',function(){$(this).find("div.over").toggle()}); }); If over - show, else - hide. Quite ok, but it must be more advanced, we should catch an offset and give a class to .over block: if offset from right (corner of browser window) less than 150px, then add class "right" for a .over block. if offset from right more than 150px - add class "left" for a .over block. How can we do it?

    Read the article

  • Getting unhandled error and connection get lost when a client tries to communicate with chat server in twisted

    - by user2433888
    from twisted.internet.protocol import Protocol,Factory from twisted.internet import reactor class ChatServer(Protocol): def connectionMade(self): print "A Client Has Connected" self.factory.clients.append(self) print"clients are ",self.factory.clients self.transport.write('Hello,Welcome to the telnet chat to sign in type aim:YOUR NAME HERE to send a messsage type msg:YOURMESSAGE '+'\n') def connectionLost(self,reason): self.factory.clients.remove(self) self.transport.write('Somebody was disconnected from the server') def dataReceived(self,data): #print "data is",data a = data.split(':') if len(a) > 1: command = a[0] content = a[1] msg="" if command =="iam": self.name + "has joined" elif command == "msg": ma=sg = self.name + ":" +content print msg for c in self.factory.clients: c.message(msg) def message(self,message): self.transport.write(message + '\n') factory = Factory() factory.protocol = ChatServer factory.clients = [] reactor.listenTCP(80,factory) print "Iphone Chat server started" reactor.run() The above code is running succesfully...but when i connect the client (by typing telnet localhost 80) to this chatserver and try to write message ,connection gets lost and following errors occurs : Iphone Chat server started A Client Has Connected clients are [<__main__.ChatServer instance at 0x024AC0A8>] Unhandled Error Traceback (most recent call last): File "C:\Python27\lib\site-packages\twisted\python\log.py", line 84, in callWithLogger return callWithContext({"system": lp}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\log.py", line 69, in callWithContext return context.call({ILogContext: newCtx}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 118, in callWithContext return self.currentContext().callWithContext(ctx, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 81, in callWithContext return func(*args,**kw) --- --- File "C:\Python27\lib\site-packages\twisted\internet\selectreactor.py", line 150, in _doReadOrWrite why = getattr(selectable, method)() File "C:\Python27\lib\site-packages\twisted\internet\tcp.py", line 199, in doRead rval = self.protocol.dataReceived(data) File "D:\chatserverultimate.py", line 21, in dataReceived content = a[1] exceptions.IndexError: list index out of range Where am I going wrong?

    Read the article

  • Is there a better way to do updates in LinqToSQL?

    - by Vaccano
    I have a list (that comes to my middleware app from the client) that I need to put in my database. Some items in the list may already be in the db (just need an update). Others are new inserts. This turns out to be much harder than I thought I would be. Here is my code to do that. I am hoping there is a better way: public void InsertClients(List<Client> clients) { var comparer = new LambdaComparer<Client>((x, y) => x.Id == y.Id); // Get a listing of all the ones we will be updating var alreadyInDB = ctx.Clients .Where(client => clients.Contains(client, comparer)); // Update the changes for those already in the db foreach (Client clientDB in alreadyInDB) { var clientDBClosure = clientDB; Client clientParam = clients.Find(x => x.Id == clientDBClosure.Id); clientDB.ArrivalTime = clientParam.ArrivalTime; clientDB.ClientId = clientParam.ClientId; clientDB.ClientName = clientParam.ClientName; clientDB.ClientEventTime = clientParam.ClientEventTime; clientDB.EmployeeCount = clientParam.EmployeeCount; clientDB.ManagerId = clientParam.ManagerId; } // Get a list of all clients that are not in my the database. var notInDB = clients.Where(x => alreadyInDB.Contains(x, comparer) == false); ctx.Clients.InsertAllOnSubmit(notInDB); ctx.SubmitChanges(); } This seems like a lot of work to do a simple update. But maybe I am just spoiled. Anyway, if there is a easier way to do this please let me know. Note: If you are curious the code to the LambdaComparer is here: http://gist.github.com/335780#file_lambda_comparer.cs

    Read the article

  • Friday Tips #3

    - by Chris Kawalek
    Even though yesterday was Thanksgiving here in the US, we still have a Friday tip for those of you around your computers today. In fact, we have two! The first one came in last week via our #AskOracleVirtualization Twitter hashtag. The tweet has disappeared into the ether now, but we remember the gist, so here it is: Question: Will there be an Oracle Virtual Desktop Client for Android? Answer by our desktop virtualization product development team: We are looking at Android as a supported platform for future releases. Question: How can I make a Sun Ray Client automatically connect to a virtual machine? Answer by Rick Butland, Principal Sales Consultant, Oracle Desktop Virtualization: Someone recently asked how they can assign VM’s to specific Sun Ray Desktop Units (“DTU’s”) without any user interfaction being required, without the “Desktop Selector” being displayed, or any User Directory.  That is, they wanted each Sun Ray to power on and immediately connect to a pre-assigned Solaris VM.   This can be achieved by using “tokens” for user assignment – that is, the tokens found on Smart Cards, DTU’s, or OVDC clients can be used in place of user credentials.  Note, however, that mixing “token-only” assignments and “User Directories” in the same VDI Center won’t work.   Much of this procedure is covered in the documentation, particularly here. But it can useful to have everything in one place, “cookbook-style”:  1. Create the “token-only” directory type: From the VDI administration interface, select:  “Settings”, “Company”, “New”, select the “None” radio button, and click “Next.” Enter a name for the new “Company”, and click “Next”, then “Finish.” 2. Create Desktop Providers, Pools, and VM’s as appropriate. 3. Access the Sun Ray administration interface at http://servername:1660 and login using “root” credentials, and access the token-id’s you wish to use for assignment.  If you’re using DTU tokens rather than Smart Card tokens, these can be found under the “Tokens” tab, and “Search-ing” using the “Currently Used Tokens” tab.  DTU’s can be identified by the prefix “psuedo.”   For example: 4. Copy/paste this token into the VDI administrative interface, by selecting “Users”, “New”, and pasting in the token ID, and click “OK” - for example: 5. Assign the token (DTU) to a desktop, that is, in the VDI Admin Gui, select “Pool”, “Desktop”, select the VM, and click "Assign" and select the token you want, for example: In addition to assigning tokens to desktops, you'll need to bypass the login screen.  To do this, you need to do two things:  1.  Disable VDI client authentication with:  /opt/SUNWvda/sbin/vda settings-setprops -p clientauthentication=Disabled 2. Disable the VDI login screen – to do this,  add a kiosk argument of "-n" to the Sun Ray kiosk arguments screen.   You set this on the Sun Ray administration page - "Advanced", "Kiosk Mode", "Edit", and add the “-n” option to the arguments screen, for example: 3.  Restart both the Sun Ray and VDI services: # /opt/SUNWut/sbin/utstart –c # /opt/SUNWvda/sbin/vda-service restart Remember, if you have a question for us, please post on Twitter with our hashtag (again, it's #AskOracleVirtualization), and we'll try to answer it if we can. See you next time!

    Read the article

  • Prevent Cisco VPN from interrupting home networking

    - by jkohlhepp
    I just got a new laptop, and for the most part have left its settings alone. Today I was trying to get some sharing going between my desktop and the laptop. Both machines are connected to the same wireless network and both machines consider that network to be a Home network. Both are running Win7 Home Premium. It seems like my laptop is aware of my desktop on the network. It can ping it by IP or by computer name. When I go to Network from the laptop, I can see the desktop in the list of computers. However, my desktop cannot ping the laptop, nor can it see it within Network. My desktop has a Homegroup set up, but my laptop says "There is currently no homegroup on the network". I do have network discovery turned on for both machines. Why can my desktop not "talk" to my laptop but it works the other way around? Update: Disabling the Windows Firewall on the laptop somewhat fixes the problem. With it disabled, my desktop can ping my laptop, but still my laptop can't see the homegroup. Also, it can ping via hostname, which resolves to IPv6, but can't ping via the IPv4 address. Obviously I'd rather not leave my firewall disabled, so I need a more specific fix. Update 2: Aha! It is the Cisco VPN software I was running to connect to work computers. Once I disconnected and exited from that, the two PCs seemed to be talking normally and the homegroup was visible to the laptop. So now my question has morphed: how can I prevent Cisco VPN from interrupting my home networking?

    Read the article

< Previous Page | 138 139 140 141 142 143 144 145 146 147 148 149  | Next Page >