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  • What would be better, (1 database + 4 tables) or (2 databases + 2 tables each) ?

    - by griseldas
    Hi there, I would like to be advised on what would be better (in regards to performance) A) 1 DATABASE with 4 tables or B) 2 DATABASES (same server), each with 2 tables. The tables size and usage are more or less similar, so the 2 tables on Database 1 would be similar usage/size to the 2 tables on database 2 The tables could have +500,000 records and the 2 tables on each database are not related (no join queries etc between them) Thanks in advance for your comments

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  • Firebird 2.1 + EXISTS = query bug?

    - by Atlas
    Using Delphi 2009 + Firebird 2.1.3. Database is ODS 11.1, default char set is UTF8. My prepared query is as follows: SELECT a.po_id, a.po_no FROM purchase_order a WHERE EXISTS (SELECT 1 FROM sales_order_item z1 JOIN purchase_order_item z2 ON z2.so_item_id = z1.so_item_id AND z2.po_id = a.po_id WHERE z1.so_id = :soid) ORDER BY a.po_no Now when I loop this say 1000 times because I have 1000 x so_id, the CPU usage get at 100% for FBSERVER.EXE Anyone encountered this problem?

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  • help with sql query - in access 2007

    - by Gold
    hi i have 2 tables table items has 144602 records table A has 27721 records code in items = BAR8 in A i want to show all records that equal i try this: SELECT Items.Code, A.BAR8 FROM Items INNER JOIN A ON Items.Code = A.BAR8; and i get 28048 records !!! i need to get 27721 , how to do it ? thank's in advance

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  • mysql extra columns with same name from two tables

    - by salmane
    Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

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  • Set the right two characters (if there are any) to capitals?

    - by Hyflex
    Below is my data: Data Here 94/452O Data more 94/4522i Data bla 94/111 Data bla 94/459es Data bla 94/444 items is automatically generated by some previous code but it could come out like: items = ["Data Here 94/452O", "Data more 94/4522i", "Data bla 94/111", "Data bla 94/459es", "Data bla 94/444"] Now currently I'm appending the following: "\n".join(items).replace("4ke", "9") with a few other .replaces however I want it to replace/change the characters on the end of the numbers with a capital letter instead of lowercase... Output: Data Here 94/452O Data more 94/4522I Data bla 94/111 Data bla 94/459ES Data bla 94/444

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  • Django. Invalid keyword argument for this function. ManyToMany

    - by sagem_tetra
    I have this error: 'people' is an invalid keyword argument for this function class Passage(models.Model): name= models.CharField(max_length = 255) who = models.ForeignKey(UserProfil) class UserPassage(models.Model): passage = models.ForeignKey(Passage) people = models.ManyToManyField(UserProfil, null=True) class UserProfil(models.Model): user = models.OneToOneField(User) name = models.CharField(max_length=50) I try: def join(request): user = request.user user_profil = UserProfil.objects.get(user=user) passage = Passage.objects.get(id=2) #line with error up = UserPassage.objects.create(people= user_profil, passage=passage) return render_to_response('thanks.html') How to do correctly? Thanks!

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  • Using Joins vs Entity associations

    - by shivesh
    I am learning Entity framework and linq-to-entities. It's possible to get cross values from multiple tables using JOINS (join keyword) or using the navigation fields ( associations) in which case the framework knows how to reference the cross data. My question is what to use when?

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  • Sql string adding problem

    - by Woland
    SELECT a.one + ' test ' +b.two from table1 a right join table1 on a.id =b.id The problem is that when one is null then it the whole string is null, is there some kind of trick to bypass this problem msSQL 2005

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  • MYSQL - Query to check against other table (hard to explain...)

    - by Sam
    I have a query that gets a list of emails who have subscribed for a newsletter trial which lasts 30 days.. $thirty = time() - 3024000; SELECT c.email FROM tbl_clients AS c JOIN tbl_clientoptions AS o ON o.client = c.id WHERE o.option = 'newsletter' AND c.datecreated $thirty What I want to do is do a check in that same query so it also returns clients OVER 30 days old if they have the tbl_clientoptions.option = 'trialoverride' (ie; a row in the client options table with the value "trialoverride") basic columns are: TBL_CLIENTS id,name,email,datecreated TBL_CLIENTOPTIONS id,client,option

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  • PHP MySQL query help

    - by user547794
    Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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  • Selecting count(*) while checking for a value in the results

    - by Rob
    SELECT COUNT(*) as Count, IF(sch.HomeTeamID = 34,true,false) AS Hawaii FROM schedule sch JOIN schools s ON s.ID = 83 WHERE (sch.HomeTeamID = 83 OR sch.AwayTeamID = 83) AND sch.SeasonID = 4 I'm trying to use count() to simplify my result but also include a field that represents wether any of the results' specific column contained a certain value. Is this possible? I'd basically like a row response with all the info I need.

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  • What is the best way to find the period of a (repeating) list in Mathematica?

    - by Arnoud Buzing
    What is the best way to find the period in a repeating list? For example: a = {4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2} has repeat {4, 5, 1, 2, 3} with the remainder {4, 5, 1, 2} matching, but being incomplete. The algorithm should be fast enough to handle longer cases, like so: b = RandomInteger[10000, {100}]; a = Join[b, b, b, b, Take[b, 27]] The algorithm should return $Failed if there is no repeating pattern like above.

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  • Get top rated item using AVG mysql

    - by user1876234
    I want to find top rated item using AVG function in mysql, right now my query looks like this: SELECT a.title, AVG(d.rating) as rating FROM in8ku_content a JOIN in8ku_content_ratings d ON a.id = d.article_id ORDER BY rating DESC Problem is that it takes AVG of all items and the result is not accurate, what should be changed here to get correct result ? Tables: in8ku_content [id, title] in8ku_content_ratings [id, article_id, rating]

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  • Website Design Templates

    - by user347834
    I am looking fr someone to make me two website templates for my site for free. Here is a quick design of what I want:(Took me 2 minutes in Paint) http:/ /i50.tinypic.com/33p9aut.jpg (You have to push backspace on the first link to join up the http:/ and the other /)and http://i50.tinypic.com/2qmogoo.jpg Email me at [email protected] or [email protected] for more information

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  • Change a link's href value based on time

    - by justSteve
    I'm coding a 'Connect to Meeting' page where i would like the link that allows attendees to join our GoToMeeting event to 'become active' 15 minutes prior to the start time. So the page users visit to see the connection info (meetingID, password) includes the start time of the meeting. I need a button ('Connect To Meeting') to change from inactive to Active when [Now() < (StartTime()-15minutes)].

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  • MySQL 'user_id' in where clause is ambiguous problem

    - by HoMe
    How can I correct the problem I keep getting from the code below which states 'user_id' in where clause is ambiguous. Thanks for the help in advance. Here is the mysql table. SELECT user.*, user_info.* FROM user INNER JOIN user_info ON user.user_id = user_info.user_id WHERE user_id='$user_id'

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  • Is there anyway that we can get a label value to a Sql

    - by Pradeep
    SELECT COUNT(*) AS Expr1 FROM Book INNER JOIN Temp_Order ON Book.Book_ID = Temp_Order.Book_ID WHERE (Temp_Order.User_ID = 25) AND (CONVERT (nvarchar, Temp_Order.OrderDate, 111) = CONVERT (nvarchar, GETDATE(), 111)) In here i want to change my User_ID to get from a label.Text this Sql Statement is in a DataView. so in the Wizard it not accepting a text box values or anything. can someone please help me to solve this

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  • delete taking really long time! mysql

    - by every_answer_gets_a_point
    i am doing this: delete calibration_2009 from calibration_2009 join batchinfo_2009 on calibration_2009.rowid = batchinfo_2009.rowid where batchinfo_2009.reporttime like '%2010%'; both tables have about 500k lines of data i suspect that 250k match the criteria to be deleted so far it has been running for 2 hours!!! is there something wrong?

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  • Return all users from group(s) specified as comma delimited value

    - by todor
    I have the following two table scenario: users id groups 1 1,2,3 2 2,3 3 1,3 4 3 and groups id 1 2 3 How do I return the IDs of all users that belong to group 2 and 1 for example? Should I look into join, a helper group_membership table or function to separate the comma delimited group IDs to get something like this: group_membership user_id group_id 1 1 1 2 1 3 2 2 2 3 ... ...

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